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  • fastest way to copy a table in mysql

    - by Anon
    which one is the fastest way to completely copy a table on mysql ? CREATE TABLE copy LIKE original; INSERT INTO copy SELECT * FROM original; or CREATE TABLE copy SELECT * FROM original; ALTER TABLE copy ADD PRIMARY KEY (id); or theres another way ? PS. can't use command-line tools like mysqldump, must be on-the-fly.

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  • How to kill locked mysql queries

    - by jcure
    Hi, I am creating and testing a mysql join query but each time so far it causes the database tables to lockup and the site hangs. I have to then call the host and they kill the locked queries. Is this something I can do from phpmyadmin so not to bother them while I tweak the script to work? Thanks for any reply.

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  • changing mysql password via java

    - by Osama Abukmail
    I'm trying to change a user's password on mysql using java, i successfully changed it on phpmyadmin but same command doesnt work on java SET PASSWORD = PASSWORD('12345') this command will change the current logged in user, i have tried it on java like this statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD = PASSWORD('12345')"); but nothing happened i also tried this with root logged in statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD FOR 'username'@'localhost' = PASSWORD('123456')"); and nothing work,, any help please

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  • How to get the exact string within the brackets in mysql

    - by sreenath
    In my mysql table a field values are as follows: table name - "clients" field name - "accent" values are - "Eastern(Northern,Southern),Scottish(East Coast)" "Eastern(South,North,Southern),Scottish(East Coast)" If I give select accent from clients where accent like '%north%' if more than 100 records not in the same order. Strings with in the brackets are not in the same order means. It will give above two values. How should i get only second value? Please help me, thanks.

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  • Sphinx Mysql Tutorial Help

    - by Frederico
    I have just implemented the Sphinx Storage Engine, and created my first Sphinx table, I'm trying to convert from using my Fulltext MyISAM table, so I figured I would just dump all the data into a sphinx table.. obviously I was wrong. Are there any great tutorials that really take you through transforming a fulltext search on MySQL to a sphinx table? Thanks in advance.

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  • passing LIMIT as parameters to MySQL sproc

    - by Kyle
    I'm creating a paging class and need to pass in two parameters to my MySQL stored procedure for the LIMIT clause. I'm passing them in as INTs and trying something like this SELECT * FROM `MyTable` LIMIT MyFirstParamInt, MySecondParamInt it gives me an error when I try and save the sproc though. Is there a way to do this that I'm just missing? Or am I going to have to EVAL the whole query and EXECUTE it?

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  • mysql circular dependency in foreign key constraints

    - by Flavius
    Given the schema: What I need is having every user_identities.belongs_to reference an users.id. At the same time, every users has a primary_identity as shown in the picture. However when I try to add this reference with ON DELETE NO ACTION ON UPDATE NO ACTION, MySQL says #1452 - Cannot add or update a child row: a foreign key constraint fails (yap.#sql-a3b_1bf, CONSTRAINT #sql-a3b_1bf_ibfk_1 FOREIGN KEY (belongs_to) REFERENCES users (id) ON DELETE NO ACTION ON UPDATE NO ACTION) I suspect this is due to the circular dependency, but how could I solve it (and maintain referential integrity)?

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  • Using MySQL variables in a query

    - by Jon Tackabury
    I am trying to use this MySQL query: SET @a:=0; UPDATE tbl SET sortId=@a:=@a+1 ORDER BY sortId; Unfortunately I get this error: "Parameter '@a' must be defined" Is it possible to batch commands into 1 query like this, or do I need to create a stored procedure for this?

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  • PHP MySQL JavaScript or AJAX Image Slideshow

    - by medoix
    Hi all, i have searched Google and also searched Stack Overflow to no avail. I am looking for a PHP / MySQL driven dynamic image slideshow. One similar to 'lightcyclers.com', i have information stored in the DB and i just want to display random or popular content etc. I am also not interested in coding one myself as i am busy working on other features. Any links or help would be much appreciated.

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  • PHP & MySQL - saving and looping problems.

    - by R.I.P.coalMINERS
    I'm new to PHP and MySQL I want a user to be able to store multiple names and there meanings in a MySQL database tables named names using PHP I will dynamically create form fields with JQuery every time a user clicks on a link so a user can enter 1 to 1,000,000 different names and there meanings which will be stored in a table called names. Since I asked my last question I figured out how to store my values from my form using the for loop but every time I loop my values when I add one or more dynamic fields the second form field named meaning will not save the value entered also my dynamic form fields keep looping doubling, tripling and so on the entered values into the database it all depends on how many form fields are added dynamically. I was wondering how can I fix these problems? On a side note I replaced the query with echo's to see the values that are being entered. Here is the PHP code. <?php if(isset($_POST['submit'])) { $mysqli = mysqli_connect("localhost", "root", "", "site"); $dbc = mysqli_query($mysqli,"SELECT * FROM names WHERE userID='$userID'"); $name = $_POST['name']; $meaning = $_POST['meaning']; if(isset($name['0']) && mysqli_num_rows($dbc) == 0 && trim($name['0'])!=='' && trim($meaning['0'])!=='') { for($n = 0; $n < count($name); $n++) { for($m = 0; $m < count($meaning); $m++) { echo $name[$n] . '<br />'; echo $meaning[$m] . '<br /><br />'; break; } } } } ?> And here is the HTML code. <form method="post" action="index.php"> <ul> <li><label for="name">Name: </label><input type="text" name="name[]" id="name" /></li> <li><label for="meaning">Meaning: </label><input type="text" name="meaning[]" id="meaning" /></li> <li><input type="submit" name="submit" value="Save" /></li> </ul> </form> If needed I will place the JQuery code.

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  • mysql left join queries

    - by Mike79
    I have a question about the snippet below. I'm wondering, if the first query doesn't bring any results, would I still get the results for the second query? select * from ( -- first query ) as query1 left join ( -- second query ) as query2 on query1.id=query2.id left join ( -- third query ) as query3 on query1.id=query3.id; Update: what I need is a full join, however, MySQL does not support it, what would be a good way to emulate this?

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