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  • std::map for storing static const Objects

    - by Sean M.
    I am making a game similar to Minecraft, and I am trying to fine a way to keep a map of Block objects sorted by their id. This is almost identical to the way that Minecraft does it, in that they declare a bunch of static final Block objects and initialize them, and then the constructor of each block puts a reference of that block into whatever the Java equivalent of a std::map is, so there is a central place to get ids and the Blocks with those ids. The problem is, that I am making my game in C++, and trying to do the exact same thing. In Block.h, I am declaring the Blocks like so: //Block.h public: static const Block Vacuum; static const Block Test; And in Block.cpp I am initializing them like so: //Block.cpp const Block Block::Vacuum = Block("Vacuum", 0, 0); const Block Block::Test = Block("Test", 1, 0); The block constructor looks like this: Block::Block(std::string name, uint16 id, uint8 tex) { //Check for repeat ids if (IdInUse(id)) { fprintf(stderr, "Block id %u is already in use!", (uint32)id); throw std::runtime_error("You cannot reuse block ids!"); } _id = id; //Check for repeat names if (NameInUse(name)) { fprintf(stderr, "Block name %s is already in use!", name); throw std::runtime_error("You cannot reuse block names!"); } _name = name; _tex = tex; //fprintf(stdout, "Using texture %u\n", _tex); _transparent = false; _solidity = 1.0f; idMap[id] = this; nameMap[name] = this; } And finally, the maps that I'm using to store references of Blocks in relation to their names and ids are declared as such: std::map<uint16, Block*> Block::idMap = std::map<uint16, Block*>(); //The map of block ids std::map<std::string, Block*> Block::nameMap = std::map<std::string, Block*>(); //The map of block names The problem comes when I try to get the Blocks in the maps using a method called const Block* GetBlock(uint16 id), where the last line is return idMap.at(id);. This line returns a Block with completely random values like _visibility = 0xcccc and such like that, found out through debugging. So my question is, is there something wrong with the blocks being declared as const obejcts, and then stored at pointers and accessed later on? The reason I cant store them as Block& is because that makes a copy of the Block when it is entered, so the block wouldn't have any of the attributes that could be set afterwards in the constructor of any child class, so I think I need to store them as a pointer. Any help is greatly appreciated, as I don't fully understand pointers yet. Just ask if you need to see any other parts of the code.

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  • IIS and PAE

    - by Latest Microsoft Blogs
    I recently got a question by one of my customers about PAE and IIS that I thought I’d share the answer to. Their environment looked something like this: 32bit OS (Windows 2003) IIS 6 with multiple application pools, where each app pool hosts a number Read More......(read more)

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  • Is my computer slow due to lack of swap

    - by Kristian Jensen
    A few months ago, I installed Ubuntu 12.04 alongside with Windows 7 on my Asus EEE-PC 1015bx. It has a tendency of freezing and when trying to investigate I found that a swap partition of only 256 MB had been created. The Asus EEE-PC 1015bx is born with 1 GByte RAM only and it is not possible to add further or exchange the existing 1 GByte with a larger card. When looking at the system monitor, it looks like all swap is being utilized along with 70-75% of the RAM, even with very few applications running. Can the lack of much swap space be the reason for my computer running slowly and at times freezing? How can I add a swap partition? Or should I add a swap file instead? At the moment, I see two partitions when viewing the system monitor: one 28.6 GByte ext4 partition which must be the one containing Ubuntu and one 100 GByte fuseblk partition which I assume is the one holding Windows. It shows that I have 18.6 GByte free space on the ext4 partition. Can I "take a bite" from the ext4 partition and convert this into a swap partition? I was thinking something like 3 GBytes for swap considering my limited RAM. I hope that someone can guide me through. Thank you. 20th Oct 2012 - Further details Thank you for below answer which I find very useful. I am certainly considering switching to one of your suggested shells as I can see from the Internet that many have posted that these require much fewer resources than ubuntu. It seems to me that lubuntu is the perfect match for my very limited computer. I will have to wait a few days, though, as I am presently limited by a very slow and restricted Internet connection via satellite. But will lubuntu install as simply another shell replacing unity or will it replace ubuntu all together? Will the software that I have installed under ubuntu still be accessible in lubuntu? And can I return to ubuntu if required? Regarding the actual question of swap: When I run gparted, it shows me that there is one ntfs partition of 100 GBytes from where it boots and the before mentioned ext4 partition of 28.6 GBytes is not mentioned. Could it be that my ubuntu installation resides inside this 100 GBytes ntfs partiotion? And if so, can I take a bite of this for my swap partition? Realising that gparted is shown in Danish, I hope that you can make out what I mean. System monitoring shows below details: Once again I sincerely hope that you can help. Thank you.

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  • Did You Know? What PreCon would I take if I were attending TechEd?

    - by Kalen Delaney
    TechEd starts in 3 weeks, and I'm not going to make it this year. I had very much wanted to visit New Orleans post-Katrina and see the recovery for myself. I attended a couple of TechEd's there many years ago, but my primary reason for visiting that fabulous city was because my daughter went to school there. She graduated from Tulane University in 1999, but it just so happened that every time TechEd was there, it was after school was over for the year, so I never got to combine my conference trip...(read more)

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  • How should I monitor memory usage/performance in SunOS/Solaris?

    - by exhuma
    Last week we decided to add some SunOS (uname -a = SunOS bbs-sam-belair 5.10 Generic_127128-11 i86pc i386 i86pc) machines into our running munin instance. First off, the machines are pre-configured appliances, so, I want to avoid touching the system too much without supervision of the service provider. But adding it to munin was fairly easy by writing a small socket-service (if anyone is interested, I put it up on github: https://github.com/munin-monitoring/contrib/tree/master/tools/pypmmn) Yesterday, I implemented/adapted the required plugins for our machines. And here the questions start: First, I have not found a way to determine detailed memory usage values. I get the total memory by running prtconf | grep Memory, and the free memory using vmstat. Fiddling together a munin-plugin, gives me the following graph: This is pretty much uninformative. Compare this to the default plugin for linux nodes which has a lot more detail: Most importantly, this shows me how much memory is actually used by applications. So, first question: Is it possible to get detailed memory information on SunOS with the default system tools (i.e. not using top)? Onto the next puzzle: Seeing the graphs, I noticed activity in the "Paging in/out" graphs, even though the memory graph still has unused memory: Upon further investigation, I found out that df reports that /tmp is mounted on swap. Drilling around on the web, I understood that df will display swap, but in fact, it's mounted as a tmpfs. Now I don't know if this explains the swap activity. The default munin-plugin for solaris uses kstat -p -c misc -m cpu_stat to get these values. I find it already strange that this is using the cpu_stat module. So maybe I simply misinterpret the "paging" graphs? Second question: Do the paging graphs indicate that parts of the memory are paged to disk? Or is the activity caused by file operations in /tmp?

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  • C++ difference between "char *" and "char * = new char[]"

    - by nashmaniac
    So, if I want to declare an array of characters I can go this way char a[2]; char * a ; char * a = new char[2]; Ignoring the first declaration, the other two use pointers. As far as I know the third declaration is stored in heap and is freed using the delete operator . does the second declaration also hold the array in heap ? Does it mean that if something is stored in heap and not freed can be used anywhere in a file like a variable with file linkage ? I tried both third and second declaration in one function and then using the variable in another but it didn't work, why ? Are there any other differences between the second and third declarations ?

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  • C++ simple arrays and pointers question

    - by nashmaniac
    So here's the confusion, let's say I declare an array of characters char name[3] = "Sam"; and then I declare another array but this time using pointers char * name = "Sam"; What's the difference between the two? I mean they work the same way in a program. Also how does the latter store the size of the stuff that someone puts in it, in this case 3 characters? Also how is it different from char * name = new char[3]; If those three are different where should they be used I mean in what circumstances?

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  • Swap and hibernation

    - by maaartinus
    I saw a lot of recommendations claiming that for hibernation the swap partition/file must be at least as large as the main memory. This makes no sense to me. Lets assume I have 8 GB of main memory and 8 GB swap area and want to hibernate: case 1: I'm using 4 GB of virtual memory - 8 GB of swap is unnecessarily large. case 2: I'm using 8 GB of virtual memory - 8 GB of swap is just right. case 3: I'm using 12 GB of virtual memory - 8 GB of swap is too small. The outcome is: A swap area of size equal to the memory size is sufficient for hibernate IFF it doesn't get used for swapping at all. So what is the reason behind the claim that you need at least as much swap area as main memory for hibernate to work? I know that virtual memory gets used for caching too, and that the cache may be simply discarded, but what happens to hibernation if a program allocates 12 GB of virtual memory (given the above memory and swap sizes)?

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  • SQLbits London 2012 - Demos

    - by Adam Machanic
    Thanks to everyone who attended my sessions last Friday and Saturday at SQLbits! It was great to meet many new people, not to mention spending some time exploring one of my favorite cities, London. Attached are the demos for each of the two talks I delivered: Query Tuning Mastery: The Art of and Science of Manhandling Parallelism As a database developer, your job boils down to one word: performance. And in today's multi-core-driven world, query performance is very much determined by how well you're...(read more)

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  • Automatically kill a process if it exceeds a given amount of RAM

    - by chrisamiller
    I work on large-scale datasets. When testing new software, a script will sometimes sneak up on me, quickly grab all available RAM, and render my desktop unusable. I'd like a way to set a RAM limit for a process so that if it exceeds that amount, it will be killed automatically. A language-specific solution probably won't work, as I use all sorts of different tools (R, Perl, Python, Bash, etc). So is there some sort of process-monitor that will let me set a threshold amount of RAM and automatically kill a process if it uses more?

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  • xen domUs crashes or unavailability

    - by Rush
    I've xen server with 8 domU. Server is Xeon E31270 with 16gb ram. I think it is enough for 8 machines. Sometimes domU's crashes and i can't figure out the reason. After crash i can connect to console and there is somthing like this: Oct 8 22:20:49 server kernel: [30892.320780] lowmem_reserve[]: 0 0 0 0 Oct 8 22:20:49 server kernel: [30892.320790] Node 0 DMA: 10*4kB 3*8kB 13*16kB 10*32kB 7*64kB 3*128kB 2*256kB 2*512kB 1*1024kB 2*2048kB 0*4096kB = 8080kB Oct 8 22:20:49 server kernel: [30892.320817] Node 0 DMA32: 648*4kB 2*8kB 1*16kB 0*32kB 1*64kB 0*128kB 0*256kB 0*512kB 1*1024kB 1*2048kB 0*4096kB = 5760kB Oct 8 22:20:49 server kernel: [30892.320842] 1491 total pagecache pages Oct 8 22:20:49 server kernel: [30892.320847] 0 pages in swap cache Oct 8 22:20:49 server kernel: [30892.320852] Swap cache stats: add 0, delete 0, find 0/0 Oct 8 22:20:49 server kernel: [30892.320858] Free swap = 0kB Oct 8 22:20:49 server kernel: [30892.320862] Total swap = 0kB Oct 8 22:20:49 server kernel: [30892.324024] 524288 pages RAM Oct 8 22:20:49 server kernel: [30892.324024] 11010 pages reserved Oct 8 22:20:49 server kernel: [30892.324024] 424467 pages shared Oct 8 22:20:49 server kernel: [30892.324024] 503538 pages non-shared Oct 8 22:20:49 server kernel: [30892.330308] apache2 invoked oom-killer: gfp_mask=0x200da, order=0, oom_adj=0 Oct 8 22:20:49 server kernel: [30892.330322] apache2 cpuset=/ mems_allowed=0 Oct 8 22:20:49 server kernel: [30892.330330] Pid: 23938, comm: apache2 Not tainted 2.6.32-5-xen-amd64 #1 Oct 8 22:20:49 server kernel: [30892.330337] Call Trace: Oct 8 22:20:49 server kernel: [30892.330349] [<ffffffff810b7180>] ? oom_kill_process+0x7f/0x23f Oct 8 22:20:49 server kernel: [30892.330358] [<ffffffff810b76a4>] ? __out_of_memory+0x12a/0x141 Oct 8 22:20:49 server kernel: [30892.330367] [<ffffffff810b77fb>] ? out_of_memory+0x140/0x172 Oct 8 22:20:49 server kernel: [30892.330376] [<ffffffff810bb59c>] ? __alloc_pages_nodemask+0x4e5/0x5f5 Oct 8 22:20:49 server kernel: [30892.330385] [<ffffffff810cc224>] ? do_wp_page+0x386/0x707 Oct 8 22:20:49 server kernel: [30892.330395] [<ffffffff8100c3a5>] ? __raw_callee_save_xen_pud_val+0x11/0x1e Oct 8 22:20:49 server kernel: [30892.330404] [<ffffffff8100c369>] ? __raw_callee_save_xen_pmd_val+0x11/0x1e Oct 8 22:20:49 server kernel: [30892.330412] [<ffffffff810cdfc7>] ? handle_mm_fault+0x7aa/0x80f Oct 8 22:20:49 server kernel: [30892.330422] [<ffffffff8130f906>] ? do_page_fault+0x2e0/0x2fc Oct 8 22:20:49 server kernel: [30892.330433] [<ffffffff8130d7a5>] ? page_fault+0x25/0x30 Oct 8 22:20:49 server kernel: [30892.330439] Mem-Info: Oct 8 22:20:49 server kernel: [30892.330443] Node 0 DMA per-cpu: Oct 8 22:20:49 server kernel: [30892.330450] CPU 0: hi: 0, btch: 1 usd: 0 Oct 8 22:20:49 server kernel: [30892.330463] CPU 1: hi: 0, btch: 1 usd: 0 Oct 8 22:20:49 server kernel: [30892.330466] Node 0 DMA32 per-cpu: Oct 8 22:20:49 server kernel: [30892.330469] CPU 0: hi: 186, btch: 31 usd: 0 Oct 8 22:20:49 server kernel: [30892.330472] CPU 1: hi: 186, btch: 31 usd: 60 Oct 8 22:20:49 server kernel: [30892.330476] active_anon:342076 inactive_anon:115398 isolated_anon:0 Oct 8 22:20:49 server kernel: [30892.330477] active_file:268 inactive_file:481 isolated_file:0 Oct 8 22:20:49 server kernel: [30892.330477] unevictable:1125 dirty:2 writeback:13 unstable:0 Oct 8 22:20:49 server kernel: [30892.330478] free:3410 slab_reclaimable:1718 slab_unreclaimable:6946 Oct 8 22:20:49 server kernel: [30892.330478] mapped:899 shmem:113 pagetables:35697 bounce:0 Oct 8 22:20:49 server kernel: [30892.330502] Node 0 DMA free:8036kB min:32kB low:40kB high:48kB active_anon:1144kB inactive_anon:1268kB active_file:8kB inactive_file:8kB unevictable:0kB isolated(anon):0kB isolated(file):0kB present:11792kB mlocked:0kB dirty:0kB writeback:0kB mapped:0kB shmem:0kB slab_reclaimable:0kB slab_unreclaimable:224kB kernel_stack:16kB pagetables:1228kB unstable:0kB bounce:0kB writeback_tmp:0kB pages_scanned:0 all_unreclaimable? no Oct 8 22:20:49 server kernel: [30892.330518] lowmem_reserve[]: 0 2004 2004 2004 Oct 8 22:20:49 server kernel: [30892.330523] Node 0 DMA32 free:5604kB min:5708kB low:7132kB high:8560kB active_anon:1367160kB inactive_anon:460324kB active_file:1064kB inactive_file:1916kB unevictable:4500kB isolated(anon):0kB isolated(file):0kB present:2052320kB mlocked:4500kB dirty:8kB writeback:52kB mapped:3600kB shmem:452kB slab_reclaimable:6872kB slab_unreclaimable:27560kB kernel_stack:3528kB pagetables:141560kB unstable:0kB bounce:0kB writeback_tmp:0kB pages_scanned:992 all_unreclaimable? no Oct 8 22:20:49 server kernel: [30892.330539] lowmem_reserve[]: 0 0 0 0 Oct 8 22:20:49 server kernel: [30892.330544] Node 0 DMA: 1*4kB 2*8kB 13*16kB 10*32kB 7*64kB 3*128kB 2*256kB 2*512kB 1*1024kB 2*2048kB 0*4096kB = 8036kB Oct 8 22:20:49 server kernel: [30892.330579] Node 0 DMA32: 609*4kB 2*8kB 1*16kB 0*32kB 1*64kB 0*128kB 0*256kB 0*512kB 1*1024kB 1*2048kB 0*4096kB = 5604kB Oct 8 22:20:49 server kernel: [30892.330605] 1522 total pagecache pages Oct 8 22:20:49 server kernel: [30892.330610] 0 pages in swap cache Oct 8 22:20:49 server kernel: [30892.330615] Swap cache stats: add 0, delete 0, find 0/0 Oct 8 22:20:49 server kernel: [30892.330621] Free swap = 0kB Oct 8 22:20:49 server kernel: [30892.330625] Total swap = 0kB Oct 8 22:20:49 server kernel: [30892.333018] 524288 pages RAM Oct 8 22:20:49 server kernel: [30892.333018] 11010 pages reserved Oct 8 22:20:49 server kernel: [30892.333018] 424367 pages shared Oct 8 22:20:49 server kernel: [30892.333018] 503658 pages non-shared Seems like there isn't enough memory for this domU. But there is no any memory problems reported in munin monitoring: As you see system uses around 0.2G and 1G is available. So my question is: Is it xen specific problem, that real memory usage and memory usage that shows munin are different (I've never seen such problems oh real hardware machines)? Or maybe it is just monitoring problem, that can't catch moment when there is unusual high load and domU go down? And how I can to defeat this problem? it is really annoying to catch messages in e-mail that domU went down. Btw, such situation was when domU had 2G memory.

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  • Why the overhead when allocating objects/arrays in Java?

    - by Gnijuohz
    How many bytes an array occupies in Java? Assume It's a 64bit machine and also assume there are N elements in an array, so all these elements would take up 2*N, 4*N or 8*N bytes for different types of array. And a lecture in Coursera says that it would occupy 2*N+24, 4*N+24 or 8*N+24 bytes for a N element array and the 24 bytes is called overhead, but didn't explain why the overhead is needed. Also objects have overheads, which is 16 bytes. What exactly are these overheads? What are these 24/16 bytes composed of? Also, do these overheads only exist in Java? How about C, C++ and Python?

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  • kernel mem parameter

    - by Ashfame
    As a last resort to my question, I am yet to try the mem parameter of kernel to force it to use the specified amount of RAM. Short Summary - I can only see 3.2GB RAM on a 64bit OS and am not sure ifs a hardware limitation, so wants to try as I found a post on Ubuntuforums. My question is if its ok to play with my resident Ubuntu install or should I be using a live bootable usb? What values do I try (I have 6GB with only 3.2GB being usable) and how to keep it safe? I don't want to burn any of my hardware component at this point of time or make the system unbootable. Running Ubuntu 11.10 with kernel 3.0.0-13-generic

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  • Help me i can't format my usb? i have already tried with mkdosfs and gparted

    - by Mauri Olivares
    I have a MicroSD card in a USB adapter (which plugs into a USB port on my machine, and acts like a USB flash drive). I was using Unetbootin to make this a bootable USB flash drive with Kubuntu. But I needed to cancel while it was working. So I killed the Unetbootin process from the console. Since then, I can't format the MicroSD or delete the folder that Kubuntu made. I have also tried mkdosfs, with no success. I can't mount the drive anymore either? What can I do, to make this drive usable again? Trying to create a new partition table in GParted, as described in Eliah Kagan's answer, does not work. It fails with the error message "imposible crear tabla de particiones" ("unable to create a partition table").

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  • Tension between the dependency inversion principle and avoiding "new" in C++?

    - by Kazark
    I have seen a lot of advice that it is better to do Type object; than Type* object = new Type(); in C++ whenever possible. I understand the rational behind this and appreciate it. But according to my understanding, to practice dependency inversion requires pointers, e.g.: Type* object = new Implementation();. (Or am I wrong about that?) Is there an inherent tension between the DIP and avoiding new when using C++? If so, what patterns/principles/practices can be used to mitigate this tension?

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  • Browser support for internal corporate tools

    - by adam
    We are on the verge of a conversion. For years, our company supported only IE for its internal (intranet) home-built tools. Since a few of our users are still on XP, which means IE only goes up to 8... a heavily JS / jQuery site wont even load! We have been in the process of converting to use Chrome instead, to make use of its javascript performance. But, it has now been suggested that we support all common browsers... internally for these tools. Which means more development time to scale-back some of these new applications, more time to test in all browsers, and we are already under staffed. Are there any good informational sites/posts out there, that already make this argument?

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  • Ubuntu swappiness

    - by Viswanath Kuchibhotla
    I have a laptop with 4 GB RAM and i3 processor. It runs very fast when I use windows, but it keeps slowing down on my Ubuntu when I use it continuously. I noticed that 500mb+ swap is getting used even if only 20% of RAM is only used, and I have a doubt that this is the reason for the slowness. I have already set the swappiness value to 10. Then how else can I change it? I spend most of my time in Ubuntu so this is very important for me.

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  • what's the overhead when allocating objects/arrays in Java?

    - by Gnijuohz
    How many bytes an array occupies in Java? Assume It's a 64bit machine and also assume there are N elements in an array, so all these elements would take up 2*N, 4*N or 8*N bytes for different types of array. And a lecture in Coursera says that it would occupy 2*N+24, 4*N+24 or 8*N+24 bytes for a N element array and the 24 byte is called overhead, but didn't explain it. Also objects have overheads, which is 16 bytes. What exactly are these overheads? Also, do these overheads only exist in Java? How about C, C++ and Python?

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  • When I have 6 GB of RAM installed, why is just 3 GB available on Ubuntu?

    - by user842225
    I'm using a laptop with 32-bit Ubuntu 10.04. I used to have only 2 GB of RAM. Today, our IT-support upgraded my laptop to a total of 6 GB of RAM. They told me "Though you do now have 6 GB, when you use your current Ubuntu, you'll only have 3 GB available. You have to install the latest version of 64-bit Ubuntu to enable all of the 6 GB." He was in a hurry to leave without explaining more. I turned on my laptop, used gnome-system-monitor to check, and as he said, it shows I only have 3 GB of RAM. Could someone explain me why? Why do I have just 3 GB available, and why installing a 64-bit version makes all of the 6 GB available?

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  • WinRAR extracting file before checking password? [closed]

    - by opatachibueze
    I tried extracting an encrypted rar file today, and I discovered that I had to wait the same amount of time I'll wait before a file is extracted (extraction reaches 99% completion) for WinRAR to conclude it's the wrong password (winrar message: "CRC failed wrong password or corrupt file?") . My guess is that this file is somewhere on the Computer just before the detection, - it has to be and then gets deleted after it's verified that the password is not the same? Is there anyway I can forcefully get this file from the PC? Thanks.

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  • large tmpfs /run partition - must it be so big?

    - by Stevod
    I am running Ubuntu 11.10 desktop on a couple of 8G RAM Wintel boxes. Both have been created automatically by the default installer with a 1.6GB tmpfs /run partition, where I suspect this amount of RAM could be more usefully used elsewhere in the system. I suspect that the installer takes 20% as the default, which is probably OK for boxes with lots less RAM, but seems overkill for an 8GB system. My question is - can I change its size, if so, how, and what are the risks in doing so? The /run partition does not appear in the /etc/fstab file so it must be set up elsewhere.

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  • C++ function returning pointer, why does this work ? [migrated]

    - by nashmaniac
    So heres a simple c++ function what it does it take an array of characters as its argument and a integer n and then creates a new character array with only n elements of the array. char * cutString(char * ch , int n){ char * p = new char[n]; int i ; for(i = 0 ; i < n ; i++) p[i] = ch[i]; while(i <= n ){ p[i++] = '\0'; } return p ; } this works just fine but if I change char * p = new char[n]; to char p[n]; I see funny characters what happens ? What difference does the former make also p is a temporary variable then how does the function returns it alright ?

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  • Trying to calculate the 10001st prime number in Java.

    - by user247679
    Greetings. I am doing Problem 7 from Project Euler. What I am supposed to do is calculate the 10001st prime number. (A prime number being a number that is only divisible by itself and one.) Here is my current program: public class Problem7 { public static void main(String args []){ long numberOfPrimes = 0; long number = 2; while (numberOfPrimes < 10001){ if(isPrime(number)){ numberOfPrimes++; } number++; } System.out.println("10001st prime: "+ number); } public static boolean isPrime(long N) { if (N <= 1) return false; else return Prime(N,N-1); } public static boolean Prime(long X,long Y) { if (Y == 1) return true; else if (X % Y == 0) return false; else return Prime(X, Y-1); } } It works okay with finding, say the 100th prime number, but when I enter very large numbers such as 10001 it causes a stack overflow. Does anyone know of a way to fix this? Thanks for reading my problem!

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  • Processing command-line arguments in prefix notation in Python

    - by ejm
    I'm trying to parse a command-line in Python which looks like the following: $ ./command -o option1 arg1 -o option2 arg2 arg3 In other words, the command takes an unlimited number of arguments, and each argument may optionally be preceded with an -o option, which relates specifically to that argument. I think this is called a "prefix notation". In the Bourne shell I would do something like the following: while test -n "$1" do if test "$1" = '-o' then option="$2" shift 2 fi # Work with $1 (the argument) and $option (the option) # ... shift done Looking around at the Bash tutorials, etc. this seems to be the accepted idiom, so I'm guessing Bash is optimized to work with command-line arguments this way. Trying to implement this pattern in Python, my first guess was to use pop(), as this is basically a stack operation. But I'm guessing this won't work as well on Python because the list of arguments in sys.argv is in the wrong order and would have to be processed like a queue (i.e. pop from the left). I've read that lists are not optimized for use as queues in Python. So, my ideas are: convert argv to a collections.deque and use popleft(), reverse argv using reverse() and use pop(), or maybe just work with the int list indices themselves. Does anyone know of a better way to do this, otherwise which of my ideas would be best-practise in Python?

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  • Dojo StackContainer children are not resizing on browser maximise/restore

    - by Andy
    Hi. I have the following nested layout in a dojo 1.4 app: BorderContainer 1 -- Stack Container 1 ----BorderContainer 2 ----BorderContainer 3 The StackContainer is sized with width and height 100%. When I resize the browser window using maximise/restore, the StackContainer correctly resizes to the center region of it's parent BorderContainer. The problem I have is that the StackContainer children (BorderContainer 2 and 3) do not get resized to the StackContainer's contentBox. Is there something special you have to do to force a resize of StackContainer children? I have tried calling StackContainer1.resize() but this makes no difference. Thanks in advance. Additional information: Thanks for the reply peller. The widget hierachy that contains the StackContainer is actually a custom widget, so the StackContainer is not actually in a BorderContainer directly, but has its height and width explicitly set to 100%. This works and the StackContainer is resized correctly on browser maximise. The direct children of the stackcontainer are BorderContainers and it is these BorderContainers that do not get resized when the StackContainer is resized. One point to note is that when the StackContainer is created in markup, the stackcontainer children are empty divs. These divs are then used as placeholders for custom widget creation, e.g. var widget = new com.company.widget(params, placeholderDiv); where placeholderDiv is a direct child of the StackContainer in markup. Should I be adding the programatically created 'widget' to the stackcontainer using addChild instead?

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