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  • How to Find Intersections with Ellipses in PGF/TikZ

    - by infblnpf
    Hello, I am trying to display a sphere in PGF/TikZ to illustrate the idea of great circles. The code for my current result is: \begin{tikzpicture} \tikzfading[name=fade right, left color=transparent!20, right color=transparent!90] \tikzfading[name=fade out, inner color=transparent!100, outer color=transparent!10] \tikzfading[name=fade right gc, left color=transparent!0, right color=transparent!70] \draw [<->, dashed] (0,-5) -- (0,5); % y-axis \draw [->, dashed] (0, 0) -- (20:5); % x-axis \draw [->, dashed] (0, 0) -- (200:5); % x-axis \draw [->, dashed] (0, 0) -- (340:5); % z-axis \draw [->, dashed] (0, 0) -- (160:5); % z-axis \fill [color=cyan, opacity=0.15, path fading=fade out] (0,0) circle (4cm); % bounding circle \fill [color=cyan, opacity=0.25, path fading=fade right, fading angle=90] (0,0) ellipse (4cm and 1cm); % x-y-axis area % great circle 1 \draw [rotate=-40, color=red, path fading=fade right gc, fading angle=40] (0,0) ellipse (4cm and 1cm); % great circle 2 \draw[rotate=5, color=red, path fading=fade right gc, fading angle=5] (0,0) ellipse (1.5cm and 4cm); \end{tikzpicture} How do I find the two points of intersection of the two red ellipses (commented as great circle 1 and 2), find the point of intersection of a line (originating at the center (0,0)) with a ellipse, and place a little circle or rectangle there? Placing a little circle or rectangle there is not an issue. Thank you very much!

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  • rotate an image aroound a point

    - by Girish
    Hi all, I have an image which is of rectangular dimension, eg 30 x 60 pixels I want to rotate this image around the bottom center of the image, i.e i want to set the pivot in the above example as (15, 60 )pixel. I am using a drawble and matrix to get this done, whatever i try i always end up rotating around center of the image. Code is : Bitmap bitmapOrg = BitmapFactory.decodeFile("/sdcard/DCIM/2010-06-01_15-32-42_821.jpg"); // float angle = (angle + 10.0f)%360.0f; if(null !=bitmapOrg) { int width = bitmapOrg.getWidth(); int height = bitmapOrg.getHeight(); int newWidth = 15; int newHeight = 15; // calculate the scale - in this case = 0.4f float scaleWidth = ((float) newWidth) / width; float scaleHeight = ((float) newHeight) / height; /* Canvas c = new Canvas(bitmapOrg); float px = ; float py; c.rotate(angle, px, py)*/ // createa matrix for the manipulation Matrix matrix = new Matrix(); // resize the bit map matrix.postScale(scaleWidth, scaleHeight); // rotate the Bitmap // matrix.postRotate(45); // recreate the new Bitmap Bitmap resizedBitmap = Bitmap.createBitmap(bitmapOrg, 0, 0, width, height, matrix, true); // make a Drawable from Bitmap to allow to set the BitMap // to the ImageView, ImageButton or what ever BitmapDrawable bmd = new BitmapDrawable(resizedBitmap); ImageView imageView = new ImageView(this); // set the Drawable on the ImageView imageView.setImageDrawable(bmd); // center the Image imageView.setScaleType(ScaleType.CENTER); // imageView.layout(100, 300, 0, 0); // linLayout.addView(imageView); // add ImageView to the Layout linLayout.addView(imageView, new AbsoluteLayout.LayoutParams( LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT, 10, 30 ) ); can anyone let me know how to get this rectified?

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  • How do I locate a particular word in a text file using .NET

    - by cmrhema
    I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that?

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  • How do I locate a particular word in a text file using C#

    - by cmrhema
    Hi, I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that. Kindly do let me know. Thanks.

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  • context.Scale() with non-aspect ratio preserving parameters screws effective lineWith

    - by rrenaud
    I am trying to apply some natural transformations whereby the x axis is remapped to some very small domain, like from 0 to 1, whereas y is remapped to some small, but substantially larger domain, like 0 to 30. This way, drawing code can be nice and clean and only care about the model space. However, if I apply a scale, then lines are also scaled, which means that horizontal lines become extremely fat relative to vertical ones. Here is some sample code. When natural_height is much less than natural_height, the picture doesn't look as intended. I want the picture to look like this, which is what happens with a scale that preserves aspect ratio. rftgstats.c om/canvas_good.png However, with a non-aspect ratio preserving scale, the results look like this. rftgstats.c om/canvas_bad.png <html><head><title>Busted example</title></head> <body> <canvas id=example height=300 width=300> <script> var canvas = document.getElementById('example'); var ctx = canvas.getContext('2d'); var natural_width = 10; var natural_height = 50; ctx.scale(canvas.width / natural_width, canvas.height / natural_height); var numLines = 20; ctx.beginPath(); for (var i = 0; i < numLines; ++i) { ctx.moveTo(natural_width / 2, natural_height / 2); var angle = 2 * Math.PI * i / numLines; // yay for screen size independent draw calls. ctx.lineTo(natural_width / 2 + natural_width * Math.cos(angle), natural_height / 2 + natural_height * Math.sin(angle)); } ctx.stroke(); ctx.closePath(); </script> </body> </html>

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  • Silverlight 3 ArcSegment to always draw circle's

    - by kapaboo
    Hi everyone, Ok, my arcSegment must always draw Circle's. For this reason I calculate the Arc's Width with the following formula: arcXRadius = (4 * Math.Pow(height, 2) + Math.Pow(distanceArcPoints, 2)) / (8 * height); so Arcs.Size = (arcXRadius,height) But seems that the height is scaled down when drawn. I want to add a small Circle to the Arc's middle (highest point) so when you drag it it changes the arc Height but also changes the Width so it will remain a circle. Here's how I calculate the Circle's (highest) point: Point middlePoint = GetMiddlePoint(arcPointA,arcPointB); double arcYRadius = arcSegment.Size.Height; if (arcYRadius <= 0) return middlePoint; double angle = arcSegment.RotationAngle; Point ellinewPoint = new Point(); ellinewPoint.X = Math.Cos((angle + 90) * Math.PI / 180) * arcYRadius + middlePoint.X; ellinewPoint.Y = Math.Sin((angle + 90) * Math.PI / 180) * arcYRadius + middlePoint.Y; Until Arc's.Size.Height Property gets Closer to the Width my Circle is not at the right Point. So maybe someone can give me a hint or tell me what am I doing wrong. Cheers, kapaboo

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  • PHP : How to get specific data from array

    - by Giffary
    Hello! I try to use amazon API using PHP. If I use print_r($parsed_xml->Items->Item->ItemAttributes) it show me some result like SimpleXMLElement Object ( [Binding] = Electronics [Brand] = Canon [DisplaySize] = 2.5 [EAN] = 0013803113662 [Feature] = Array ( [0] = High-powered 20x wide-angle optical zoom with Optical Image Stabilizer [1] = Capture 720p HD movies with stereo sound; HDMI output connector for easy playback on your HDTV [2] = 2.5-inch Vari-Angle System LCD; improved Smart AUTO intelligently selects from 22 predefined shooting situations [3] = DIGIC 4 Image Processor; 12.1-megapixel resolution for poster-size, photo-quality prints [4] = Powered by AA batteries (included); capture images to SD/SDHC memory cards (not included) ) [FloppyDiskDriveDescription] = None [FormFactor] = Rotating [HasRedEyeReduction] = 1 [IsAutographed] = 0 [IsMemorabilia] = 0 [ItemDimensions] = SimpleXMLElement Object ( [Height] = 340 [Length] = 490 [Weight] = 124 [Width] = 350 ) [Label] = Canon [LensType] = Zoom lens [ListPrice] = SimpleXMLElement Object ( [Amount] = 60103 [CurrencyCode] = USD [FormattedPrice] = $601.03 ) [Manufacturer] = Canon [MaximumFocalLength] = 100 [MaximumResolution] = 12.1 [MinimumFocalLength] = 5 [Model] = SX20IS [MPN] = SX20IS [OpticalSensorResolution] = 12.1 [OpticalZoom] = 20 [PackageDimensions] = SimpleXMLElement Object ( [Height] = 460 [Length] = 900 [Weight] = 242 [Width] = 630 ) [PackageQuantity] = 1 [ProductGroup] = Photography [ProductTypeName] = CAMERA_DIGITAL [ProductTypeSubcategory] = point-and-shoot [Publisher] = Canon [Studio] = Canon [Title] = Canon PowerShot SX20IS 12.1MP Digital Camera with 20x Wide Angle Optical Image Stabilized Zoom and 2.5-inch Articulating LCD [UPC] = 013803113662 ) my goal is to get only Feature infomation and I try to use $feature = $parsed_xml->Items->Item->ItemAttributes->Feature it does'not work for me because it just show me the first feature only. How do i get all feature information? please help

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  • #include - brackets vs quotes in XCode?

    - by Chris Becke
    In MSVC++ #include files are searched for differently depending on whether the file is enclosed in "" or <. The quoted form searches first in the local folder, then in /I specified locations, The angle bracket form avoids the local folder. This means, in MSVC++, its possible to have header files with the same name as runtime and SDK headers. So, for example, I need to wrap up the windows sdk windows.h file to undefine some macro's that cause trouble. With MSVS I can just add a (optional) windows.h file to my project as long as I include it using the quoted form :- // some .cpp file #include "windows.h" // will include my local windows.h file And in my windows.h, I can pull in the real one using the angle bracket form: // my windows.h #include <windows.h> // will load the real one #undef ConflictingSymbol Trying this trick with GCC in XCode didn't work. angle bracket #includes in system header files in fact are finding my header files with similar names in my local folder structure. The MSVC system means its quite safe to have a "String.h" header file in my own folder structre. On XCode this seems to be a major no no. Is there some way to control this search path behaviour in XCode to be more like MSVC's? Or do I just have to avoid naming any of my headers anything that might possibly conflict with a system header. Writing cross platform code and using lots of frameworks means the possibility of incidental conflicts seems large.

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  • Image rotate opecv error

    - by avd
    When I use this code to rotate the image, the destination image size remains same and hence the image gets clipped. Please provide me a way/code snippet to resize accordingly (like matlab does in imrotate) so that image does not get clipped and outlier pixels gets filled with all white instead of black. void imrotate(std::string imgPath,std::string angleStr,std::string outPath) { size_t found1,found2; found1=imgPath.find_last_of('/'); found2=imgPath.size()-4; IplImage* src=cvLoadImage(imgPath.c_str(), -1);; IplImage* dst; dst = cvCloneImage( src ); int angle = atoi(angleStr.c_str()); CvMat* rot_mat = cvCreateMat(2,3,CV_32FC1); CvPoint2D32f center = cvPoint2D32f( src->width/2, src->height/2 ); double scale = 1; cv2DRotationMatrix( center, angle, scale, rot_mat ); cvWarpAffine( src, dst, rot_mat); char angStr[4]; sprintf(angStr,"%d",angle); cvSaveImage(string(outPath+imgPath.substr(found1+1,found2-found1-1)+"_"+angStr+".jpg").c_str(),dst); cvReleaseImage(&src); cvReleaseImage(&dst); cvReleaseMat( &rot_mat ); } Original Image: Rotated Image:

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  • Problem with Matlab functions

    - by appi
    HI. I got this matlab functionWhen I ran it, the following error messege showed up. Can anybody give me some hint? Thank you. The code is also shown below. [h,im_matched,theta,I,J]=im_reg_MI('keyframe1.jpg','keyframe2.jpg', 0, 1) ??? Undefined function or variable "h". Error in == im_reg_MI at 74 [a, b] = max(h(:));% finding the max of MI and indecises Below is the code. [h,im_matched, theta,I,J]=im_reg_MI(image1, image2, angle, step) [m,n]=size(image1); [p,q]=size(image2); [a,b]=size(angle); im1=round(image1); for k=1:b J = rotate_image(angle(k),image2); %rotated cropped IMAGE2 image21=round(J); [m1,n1]=size(image21); for i=1:step:(m1-m) for j=1:step:(n1-n) im2=image21(i:(i+m-1),j:(j+n-1)); % selecting part of IMAGE2 matching the size of IMAHE1 im2=round(im2); h(k,i,j)=MI2(im1,im2); % calculating MI end end end [a, b] = max(h(:));% finding the max of MI and indecises

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  • bounding a sprite in cocos2d

    - by Srinivas
    am making a canon to fire objects. back of the canon the plunger is attached. plunger acts for set speed and angle. canon rotates 0-90 degree and plunger moves front and back for adjust speed. when am rotates the canon by touches moved its working fine. when plunger is pull back by touches moved and it rotates means the plunger is bounds outside of the canon. how to control this:- my code for plunger and canon rotation on touches moved. ( para3 is the canon , para6 is my plunger):- CGPoint touchLocation = [self convertTouchToNodeSpace:touch]; CGPoint oldTouchLocation = [touch previousLocationInView:touch.view]; oldTouchLocation = [[CCDirector sharedDirector] convertToGL:oldTouchLocation]; oldTouchLocation = [self convertToNodeSpace:oldTouchLocation]; if (CGRectContainsPoint(CGRectMake(para6.position.x-para6.contentSize.width/2, para6.position.y-para6.contentSize.height/2, para6.contentSize.width, para6.contentSize.height), touchLocation) && (touchLocation.y-oldTouchLocation.y == 0)) { CGPoint diff = ccpSub(touchLocation, oldTouchLocation); CGPoint currentpos = [para6 position]; NSLog(@"%d",currentpos); CGPoint destination = ccpAdd(currentpos, diff); if (destination.x < 90 && destination.x >70) { [para6 setPosition:destination]; speed = (70 + (90-destination.x))*3.5 ; } } if(CGRectIntersectsRect((CGRectMake(para6.position.x-para6.contentSize.width/8, (para6.position.y+30)-para6.contentSize.height/10, para6.contentSize.width, para6.contentSize.height/10)),(CGRectMake(para3.position.x-para3.contentSize.width/2, para3.position.y-para3.contentSize.height/2, para3.contentSize.width, para3.contentSize.height)))) { [para3 runAction:[CCSequence actions: [CCRotateTo actionWithDuration:rotateDuration angle:rotateDiff], nil]]; CGFloat plungrot = (rotateDiff); CCRotateTo *rot = [CCRotateTo actionWithDuration:rotateDuration angle:plungrot]; [para6 runAction:rot]; } }

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  • The sign of zero with float2

    - by JackOLantern
    Consider the following code performing operations on complex numbers with C/C++'s float: float real_part = log(3.f); float imag_part = 0.f; float real_part2 = (imag_part)*(imag_part)-(real_part*real_part); float imag_part2 = (imag_part)*(real_part)+(real_part*imag_part); The result will be real_part2= -1.20695 imag_part2= 0 angle= 3.14159 where angle is the phase of the complex number and, in this case, is pi. Now consider the following code: float real_part = log(3.f); float imag_part = 0.f; float real_part2 = (-imag_part)*(-imag_part)-(real_part)*(real_part); float imag_part2 = (-imag_part)*(real_part)+(real_part)*(-imag_part); The result will be real_part2= -1.20695 imag_part2= 0 angle= -3.14159 The imaginary part of the result is -0 which makes the phase of the result be -pi. Although still accomplishing with the principal argument of a complex number and with the signed property of floating point's 0, this changes is a problem when one is defining functions of complex numbers. For example, if one is defining sqrt of a complex number by the de Moivre formula, this will change the sign of the imaginary part of the result to a wrong value. How to deal with this effect?

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  • Collision Handling in Javascript - Particles Get Stuck

    - by Conner Ruhl
    I am trying to recreate this, and I have been fairly successful. I am having issues with the collision handling though. Although the collision handling seems to work, it has very strange behavior. Here is what I have so far. This is the code that handles collisions: var dx = particle2.getX() - particle1.getX(); var dy = particle2.getY() - particle1.getY(); var angle = Math.atan2(dy, dx); var newP2X = particle1.getX() + (particle1.getRadius() + particle2.getRadius()) * Math.cos(angle); var newP2Y = particle1.getY() + (particle1.getRadius() + particle2.getRadius()) * Math.sin(angle); particle2.setX(newP2X); particle2.setY(newP2Y); var p1Vxi = particle1.getVx(); var p1Vyi = particle1.getVy(); var p1Mass = particle1.getMass(); var p2Vxi = particle2.getVx(); var p2Vyi = particle2.getVy(); var p2Mass = particle2.getMass(); var vxf = (p1Mass * p1Vxi + p2Mass * p2Vxi) / (p1Mass + p2Mass); var vyf = (p1Mass * p1Vyi + p2Mass * p2Vyi) / (p1Mass + p2Mass); particle1.setVx(vxf); particle1.setVy(vyf); particle2.setVx(vxf); particle2.setVy(vyf); EDIT: I have tried to change it to inelastic collisions like suggested, but for some reason the balls collide erratically. Check it out here. Any help is much appreciated!

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  • bounding a sprite in cocos2d

    - by Srinivas
    am making a canon to fire objects. back of the canon the plunger is attached. plunger acts for set speed and angle. canon rotates 0-90 degree and plunger moves front and back for adjust speed. when am rotates the canon by touches moved its working fine. when plunger is pull back by touches moved and it rotates means the plunger is bounds outside of the canon. how to control this:- my code for plunger and canon rotation on touches moved. ( para3 is the canon , para6 is my plunger):- CGPoint touchLocation = [self convertTouchToNodeSpace:touch]; CGPoint oldTouchLocation = [touch previousLocationInView:touch.view]; oldTouchLocation = [[CCDirector sharedDirector] convertToGL:oldTouchLocation]; oldTouchLocation = [self convertToNodeSpace:oldTouchLocation]; if (CGRectContainsPoint(CGRectMake(para6.position.x-para6.contentSize.width/2, para6.position.y-para6.contentSize.height/2, para6.contentSize.width, para6.contentSize.height), touchLocation) && (touchLocation.y-oldTouchLocation.y == 0)) { CGPoint diff = ccpSub(touchLocation, oldTouchLocation); CGPoint currentpos = [para6 position]; NSLog(@"%d",currentpos); CGPoint destination = ccpAdd(currentpos, diff); if (destination.x < 90 && destination.x >70) { [para6 setPosition:destination]; speed = (70 + (90-destination.x))*3.5 ; } } if(CGRectIntersectsRect((CGRectMake(para6.position.x-para6.contentSize.width/8, (para6.position.y+30)-para6.contentSize.height/10, para6.contentSize.width, para6.contentSize.height/10)),(CGRectMake(para3.position.x-para3.contentSize.width/2, para3.position.y-para3.contentSize.height/2, para3.contentSize.width, para3.contentSize.height)))) { [para3 runAction:[CCSequence actions: [CCRotateTo actionWithDuration:rotateDuration angle:rotateDiff], nil]]; CGFloat plungrot = (rotateDiff); CCRotateTo *rot = [CCRotateTo actionWithDuration:rotateDuration angle:plungrot]; [para6 runAction:rot]; } }

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  • Silverlight for Windows Embedded tutorial (step 6)

    - by Valter Minute
    In this tutorial step we will develop a very simple clock application that may be used as a screensaver on our devices and will allow us to discover a new feature of Silverlight for Windows Embedded (transforms) and how to use an “old” feature of Windows CE (timers) inside a Silverlight for Windows Embedded application. Let’s start with some XAML, as usual: <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Width="640" Height="480" FontSize="18" x:Name="Clock">   <Canvas x:Name="LayoutRoot" Background="#FF000000"> <Grid Height="24" Width="150" Canvas.Left="320" Canvas.Top="234" x:Name="SecondsHand" Background="#FFFF0000"> <TextBlock Text="Seconds" TextWrapping="Wrap" Width="50" HorizontalAlignment="Right" VerticalAlignment="Center" x:Name="SecondsText" Foreground="#FFFFFFFF" TextAlignment="Right" Margin="2,2,2,2"/> </Grid> <Grid Height="24" x:Name="MinutesHand" Width="100" Background="#FF00FF00" Canvas.Left="320" Canvas.Top="234"> <TextBlock HorizontalAlignment="Right" x:Name="MinutesText" VerticalAlignment="Center" Width="50" Text="Minutes" TextWrapping="Wrap" Foreground="#FFFFFFFF" TextAlignment="Right" Margin="2,2,2,2"/> </Grid> <Grid Height="24" x:Name="HoursHand" Width="50" Background="#FF0000FF" Canvas.Left="320" Canvas.Top="234"> <TextBlock HorizontalAlignment="Right" x:Name="HoursText" VerticalAlignment="Center" Width="50" Text="Hours" TextWrapping="Wrap" Foreground="#FFFFFFFF" TextAlignment="Right" Margin="2,2,2,2"/> </Grid> </Canvas> </UserControl> This XAML file defines three grid panels, one for each hand of our clock (we are implementing an analog clock using one of the most advanced technologies of the digital world… how cool is that?). Inside each hand we put a TextBlock that will be used to display the current hour, minute, second inside the dial (you can’t do that on plain old analog clocks, but it looks nice). As usual we use XAML2CPP to generate the boring part of our code. We declare a class named “Clock” and derives from the TClock template that XAML2CPP has declared for us. class Clock : public TClock<Clock> { ... }; Our WinMain function is more or less the same we used in all the previous samples. It initializes the XAML runtime, create an instance of our class, initialize it and shows it as a dialog: int WINAPI WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPTSTR lpCmdLine, int nCmdShow) { if (!XamlRuntimeInitialize()) return -1;   HRESULT retcode;   IXRApplicationPtr app; if (FAILED(retcode=GetXRApplicationInstance(&app))) return -1; Clock clock;   if (FAILED(clock.Init(hInstance,app))) return -1;     UINT exitcode;   if (FAILED(clock.GetVisualHost()->StartDialog(&exitcode))) return -1;   return exitcode; } Silverlight for Windows Embedded provides a lot of features to implement our UI, but it does not provide timers. How we can update our clock if we don’t have a timer feature? We just use plain old Windows timers, as we do in “regular” Windows CE applications! To use a timer in WinCE we should declare an id for it: #define IDT_CLOCKUPDATE 0x12341234 We also need an HWND that will be used to receive WM_TIMER messages. Our Silverlight for Windows Embedded page is “hosted” inside a GWES Window and we can retrieve its handle using the GetContainerHWND function of our VisualHost object. Let’s see how this is implemented inside our Clock class’ Init method: HRESULT Init(HINSTANCE hInstance,IXRApplication* app) { HRESULT retcode;   if (FAILED(retcode=TClock<Clock>::Init(hInstance,app))) return retcode;   // create the timer user to update the clock HWND clockhwnd;   if (FAILED(GetVisualHost()->GetContainerHWND(&clockhwnd))) return -1;   timer=SetTimer(clockhwnd,IDT_CLOCKUPDATE,1000,NULL); return 0; } We use SetTimer to create a new timer and GWES will send a WM_TIMER to our window every second, giving us a chance to update our clock. That sounds great… but how could we handle the WM_TIMER message if we didn’t implement a window procedure for our window? We have to move a step back and look how a visual host is created. This code is generated by XAML2CPP and is inside xaml2cppbase.h: virtual HRESULT CreateHost(HINSTANCE hInstance,IXRApplication* app) { HRESULT retcode; XRWindowCreateParams wp;   ZeroMemory(&wp, sizeof(XRWindowCreateParams)); InitWindowParms(&wp);   XRXamlSource xamlsrc;   SetXAMLSource(hInstance,&xamlsrc); if (FAILED(retcode=app->CreateHostFromXaml(&xamlsrc, &wp, &vhost))) return retcode;   if (FAILED(retcode=vhost->GetRootElement(&root))) return retcode; return S_OK; } As you can see the CreateHostFromXaml function of IXRApplication accepts a structure named XRWindowCreateParams that control how the “plain old” GWES Window is created by the runtime. This structure is initialized inside the InitWindowParm method: // Initializes Windows parameters, can be overridden in the user class to change its appearance virtual void InitWindowParms(XRWindowCreateParams* wp) { wp->Style = WS_OVERLAPPED; wp->pTitle = windowtitle; wp->Left = 0; wp->Top = 0; } This method set up the window style, title and position. But the XRWindowCreateParams contains also other fields and, since the function is declared as virtual, we could initialize them inside our version of InitWindowParms: // add hook procedure to the standard windows creation parms virtual void InitWindowParms(XRWindowCreateParams* wp) { TClock<Clock>::InitWindowParms(wp);   wp->pHookProc=StaticHostHookProc; wp->pvUserParam=this; } This method calls the base class implementation (useful to not having to re-write some code, did I told you that I’m quite lazy?) and then initializes the pHookProc and pvUserParam members of the XRWindowsCreateParams structure. Those members will allow us to install a “hook” procedure that will be called each time the GWES window “hosting” our Silverlight for Windows Embedded UI receives a message. We can declare a hook procedure inside our Clock class: // static hook procedure static BOOL CALLBACK StaticHostHookProc(VOID* pv,HWND hwnd,UINT Msg,WPARAM wParam,LPARAM lParam,LRESULT* pRetVal) { ... } You should notice two things here. First that the function is declared as static. This is required because a non-static function has a “hidden” parameters, that is the “this” pointer of our object. Having an extra parameter is not allowed for the type defined for the pHookProc member of the XRWindowsCreateParams struct and so we should implement our hook procedure as static. But in a static procedure we will not have a this pointer. How could we access the data member of our class? Here’s the second thing to notice. We initialized also the pvUserParam of the XRWindowsCreateParams struct. We set it to our this pointer. This value will be passed as the first parameter of the hook procedure. In this way we can retrieve our this pointer and use it to call a non-static version of our hook procedure: // static hook procedure static BOOL CALLBACK StaticHostHookProc(VOID* pv,HWND hwnd,UINT Msg,WPARAM wParam,LPARAM lParam,LRESULT* pRetVal) { return ((Clock*)pv)->HostHookProc(hwnd,Msg,wParam,lParam,pRetVal); } Inside our non-static hook procedure we will have access to our this pointer and we will be able to update our clock: // hook procedure (handles timers) BOOL HostHookProc(HWND hwnd,UINT Msg,WPARAM wParam,LPARAM lParam,LRESULT* pRetVal) { switch (Msg) { case WM_TIMER: if (wParam==IDT_CLOCKUPDATE) UpdateClock(); *pRetVal=0; return TRUE; } return FALSE; } The UpdateClock member function will update the text inside our TextBlocks and rotate the hands to reflect current time: // udates Hands positions and labels HRESULT UpdateClock() { SYSTEMTIME time; HRESULT retcode;   GetLocalTime(&time);   //updates the text fields TCHAR timebuffer[32];   _itow(time.wSecond,timebuffer,10);   SecondsText->SetText(timebuffer);   _itow(time.wMinute,timebuffer,10);   MinutesText->SetText(timebuffer);   _itow(time.wHour,timebuffer,10);   HoursText->SetText(timebuffer);   if (FAILED(retcode=RotateHand(((float)time.wSecond)*6-90,SecondsHand))) return retcode;   if (FAILED(retcode=RotateHand(((float)time.wMinute)*6-90,MinutesHand))) return retcode;   if (FAILED(retcode=RotateHand(((float)(time.wHour%12))*30-90,HoursHand))) return retcode;   return S_OK; } The function retrieves current time, convert hours, minutes and seconds to strings and display those strings inside the three TextBlocks that we put inside our clock hands. Then it rotates the hands to position them at the right angle (angles are in degrees and we have to subtract 90 degrees because 0 degrees means horizontal on Silverlight for Windows Embedded and usually a clock 0 is in the top position of the dial. The code of the RotateHand function uses transforms to rotate our clock hands on the screen: // rotates a Hand HRESULT RotateHand(float angle,IXRFrameworkElement* Hand) { HRESULT retcode; IXRRotateTransformPtr rotatetransform; IXRApplicationPtr app;   if (FAILED(retcode=GetXRApplicationInstance(&app))) return retcode;   if (FAILED(retcode=app->CreateObject(IID_IXRRotateTransform,&rotatetransform))) return retcode;     if (FAILED(retcode=rotatetransform->SetAngle(angle))) return retcode;   if (FAILED(retcode=rotatetransform->SetCenterX(0.0))) return retcode;   float height;   if (FAILED(retcode==Hand->GetActualHeight(&height))) return retcode;   if (FAILED(retcode=rotatetransform->SetCenterY(height/2))) return retcode; if (FAILED(retcode=Hand->SetRenderTransform(rotatetransform))) return retcode;   return S_OK; } It creates a IXRotateTransform object, set its rotation angle and origin (the default origin is at the top-left corner of our Grid panel, we move it in the vertical center to keep the hand rotating around a single point in a more “clock like” way. Then we can apply the transform to our UI object using SetRenderTransform. Every UI element (derived from IXRFrameworkElement) can be rotated! And using different subclasses of IXRTransform also moved, scaled, skewed and distorted in many ways. You can also concatenate multiple transforms and apply them at once suing a IXRTransformGroup object. The XAML engine uses vector graphics and object will not look “pixelated” when they are rotated or scaled. As usual you can download the code here: http://cid-9b7b0aefe3514dc5.skydrive.live.com/self.aspx/.Public/Clock.zip If you read up to (down to?) this point you seem to be interested in Silverlight for Windows Embedded. If you want me to discuss some specific topic, please feel free to point it out in the comments! Technorati Tags: Silverlight for Windows Embedded,Windows CE

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  • Alpha plugin in GStreamer not working

    - by Miguel Escriva
    Hi! I'm trying to compose two videos, and I'm using the alpha plug-in to make the white color transparent. To test the alpha plug-in I'm creating the pipeline with gst-launch. The first test I done was: gst-launch videotestsrc pattern=smpte75 \ ! alpha method=custom target-r=255 target-g=255 target-b=255 angle=10 \ ! videomixer name=mixer ! ffmpegcolorspace ! autovideosink \ videotestsrc pattern=snow ! mixer. and it works great! Then I created two videos with those lines: gst-launch videotestsrc pattern=snow ! ffmpegcolorspace ! theoraenc ! oggmux ! filesink location=snow.ogv gst-launch videotestsrc pattern=smpte75 ! ffmpegcolorspace ! theoraenc ! oggmux ! filesink location=bars75.ogv And changed the videotestsrc to a filesrc and it continues working gst-launch filesrc location=bars75.ogv ! decodebin2 \ ! alpha method=custom target-r=255 target-g=255 target-b=255 angle=10 \ ! videomixer name=mixer ! ffmpegcolorspace ! autovideosink \ filesrc location=snow.ogv ! decodebin2 ! alpha ! mixer. But, when I use the ideo I want to compose, I'm not able to make the white color transparent gst-launch filesrc location=video.ogv ! decodebin2 \ ! alpha method=custom target-r=255 target-g=255 target-b=255 angle=10 \ ! videomixer name=mixer ! ffmpegcolorspace ! autovideosink \ filesrc location=snow.ogv ! decodebin2 ! alpha ! mixer. Can you help me? Any idea what is happening? I'm using GStreamer 0.10.28 You can download the test videos from here: http://polimedia.upv.es/pub/gst/gst.zip Thanks in advance, Miguel Escriva

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  • Arbitrary Rotation about a Sphere

    - by Der
    I'm coding a mechanic which allows a user to move around the surface of a sphere. The position on the sphere is currently stored as theta and phi, where theta is the angle between the z-axis and the xz projection of the current position (i.e. rotation about the y axis), and phi is the angle from the y-axis to the position. I explained that poorly, but it is essentially theta = yaw, phi = pitch Vector3 position = new Vector3(0,0,1); position.X = (float)Math.Sin(phi) * (float)Math.Sin(theta); position.Y = (float)Math.Sin(phi) * (float)Math.Cos(theta); position.Z = (float)Math.Cos(phi); position *= r; I believe this is accurate, however I could be wrong. I need to be able to move in an arbitrary pseudo two dimensional direction around the surface of a sphere at the origin of world space with radius r. For example, holding W should move around the sphere in an upwards direction relative to the orientation of the player. I believe I should be using a Quaternion to represent the position/orientation on the sphere, but I can't think of the correct way of doing it. Spherical geometry is not my strong suit. Essentially, I need to fill the following block: public void Move(Direction dir) { switch (dir) { case Direction.Left: // update quaternion to rotate left break; case Direction.Right: // update quaternion to rotate right break; case Direction.Up: // update quaternion to rotate upward break; case Direction.Down: // update quaternion to rotate downward break; } }

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  • Learning HTML5 - Best of RSS

    - by Albers
    These are some of the best RSS feeds I've found for keeping up with HTML5. I'm doing jQuery & MVC development as well so you will find the links have a jQuery/MS angle to them. WhenCanIUse The oh-so-necessary caniuse.com, in RSS update format: http://feeds.feedburner.com/WhenCanIUse ScriptJunkie http://services.social.microsoft.com/feeds/feed/query/tag/scriptjunkieLearn/eq/ns/DiscoveryFeedTool/eq/andA good HTML, JavaScript, CSS site hosted by MS Rachel Appel's blog http://rachelappel.com/rss?containerid=13HTML5, JavaScript, and MVC links with a general MS angle Smashing Magazine http://rss1.smashingmagazine.com/feed/Really high quality articles with a focus towards the design side of the web development picture IEBlog blogs.msdn.com/b/ie/rss.aspxNo surprise - the focus is on IE10, but it is really a great resource for new browser tech. MisfitGeek http://feeds.feedburner.com/MisfitGeekJoe recently switched from MS to Mozilla. New job but he still puts out great Weekly Links summaries. The Big Web Show http://feeds.feedburner.com/bigwebshowA podcast covering web development & design topics Elijah Manor/Web Dev .NET I'm cheating on this one a little bit. Elijah is a fantastic JS & web development resource. He has a site at Web Dev .NET, but honestly these days you are better off following him on Google+ ...and you can of course sign up to follow the W3C as well, although I don't think there is an HTML5-specific RSS feed. Good luck!

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  • Resultant Vector Algorithm for 2D Collisions

    - by John
    I am making a Pong based game where a puck hits a paddle and bounces off. Both the puck and the paddles are Circles. I came up with an algorithm to calculate the resultant vector of the puck once it meets a paddle. The game seems to function correctly but I'm not entirely sure my algorithm is correct. Here are my variables for the algorithm: Given: velocity = the magnitude of the initial velocity of the puck before the collision x = the x coordinate of the puck y = the y coordinate of the puck moveX = the horizontal speed of the puck moveY = the vertical speed of the puck otherX = the x coordinate of the paddle otherY = the y coordinate of the paddle piece.horizontalMomentum = the horizontal speed of the paddle before it hits the puck piece.verticalMomentum = the vertical speed of the paddle before it hits the puck slope = the direction, in radians, of the puck's velocity distX = the horizontal distance between the center of the puck and the center of the paddle distY = the vertical distance between the center of the puck and the center of the paddle Algorithm solves for: impactAngle = the angle, in radians, of the angle of impact. newSpeedX = the speed of the resultant vector in the X direction newSpeedY = the speed of the resultant vector in the Y direction Here is the code for my algorithm: int otherX = piece.x; int otherY = piece.y; double velocity = Math.sqrt((moveX * moveX) + (moveY * moveY)); double slope = Math.atan(moveX / moveY); int distX = x - otherX; int distY = y - otherY; double impactAngle = Math.atan(distX / distY); double newAngle = impactAngle + slope; int newSpeedX = (int)(velocity * Math.sin(newAngle)) + piece.horizontalMomentum; int newSpeedY = (int)(velocity * Math.cos(newAngle)) + piece.verticalMomentum; for those who are not program savvy here is it simplified: velocity = v(moveX² + moveY²) slope = arctan(moveX / moveY) distX = x - otherX distY = y - otherY impactAngle = arctan(distX / distY) newAngle = impactAngle + slope newSpeedX = velocity * sin(newAngle) + piece.horizontalMomentum newSpeedY = velocity * cos(newAngle) + piece.verticalMomentum My Question: Is this algorithm correct? Is there an easier/simpler way to do what I'm trying to do?

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  • Animation API vs frame animation

    - by Max
    I'm pretty far down the road in my game right now, closing in on the end. And I'm adding little tweaks here and there. I used custom frame animation of a single image with many versions of my sprite on it, and controlled which part of the image to show using rectangles. But I'm starting to think that maybe I should've used the Animation API that comes with android instead. Will this effect my performance in a negative way? Can I still use rectangles to draw my bitmap? Could I add effects from the Animation API to my current frame-controlled animation? like the fadeout-effect etc? this would mean I wont have to change my current code. I want some of my animations to fade out, and just noticed that using the Animation API makes things alot easier. But needless to say, I would prefer not having to change all my animation-code. I'm bad at explaining, so Ill show a bit of how I do my animation: private static final int BMP_ROWS = 1; //I use top-view so only need my sprite to have 1 direction private static final int BMP_COLUMNS = 3; public void update(GameControls controls) { if (sprite.isMoving) { currentFrame = ++currentFrame % BMP_COLUMNS; } else { this.setFrame(1); } } public void draw(Canvas canvas, int x, int y, float angle) { this.x=x; this.y=y; canvas.save(); canvas.rotate(angle , x + width / 2, y + height / 2); int srcX = currentFrame * width; int srcY = 0 * height; Rect src = new Rect(srcX, srcY, srcX + width, srcY + height); Rect dst = new Rect(x, y, x + width, y + height); canvas.drawBitmap(bitmap, src, dst, null); canvas.restore(); }

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  • Collision with half semi-circle

    - by heitortsergent
    I am trying to port a game I made using Flash/AS3, to the Windows Phone using C#/XNA 4.0. You can see it here: http://goo.gl/gzFiE In the flash version I used a pixel-perfect collision between meteors (it's a rectangle, and usually rotated) that spawn outside the screen, and move towards the center, and a shield in the center of the screen(which is half of a semi-circle, also rotated by the player), which made the meteor bounce back in the opposite direction it came from, when they collided. My goal now is to make the meteors bounce in different angles, depending on the position it collides with the shield (much like Pong, hitting the borders causes a change in the ball's angle). So, these are the 3 options I thought of: -Pixel-perfect collision (microsoft has a sample(http://create.msdn.com/en-US/education/catalog/tutorial/collision_2d_perpixel_transformed)) , but then I wouldn't know how to change the meteor angle after the collision -3 BoundingCircle's to represent the half semi-circle shield, but then I would have to somehow move them as I rotate the shield. -Farseer Physics. I could make a shape composed of 3 lines, and use that as the collision object for the shield. Is there any other way besides those? Which would be the best way to do it(it's aimed towards mobile devices, so pixel-perfect is probably not a good choice)? Most of the time there's always a easier/better way than what we think of...

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  • Find meeting point of 2 objects in 2D, knowing (constant) speed and slope

    - by Axonn
    I have a gun which fires a projectile which has to hit an enemy. The problem is that the gun has to be automatic, i.e. - choose the angle in which it has to shoot so that the projectile hits the enemy dead in the center. It's been a looooong time since school, and my physics skills are a bit rusty, but they're there. I've been thinking to somehow apply the v = d/t formula to find the time needed for the projectile or enemy to reach a certain point. But the problem is that I can't find the common point for both the projectile and enemy. Yes, I can find a certain point for the projectile, and another for the enemy, but I would need lots of tries to find where the point coincides, which is stupid. There has to be a way to link them together but I can't figure it out. I prepared some drawings and samples: A simple version of my Flash game, dumbed down to the basics, just some shapes: http://axonnsd.org/W/P001/MathSandBox.swf - click the mouse anywhere to fire a projectile. Or, here is an image which describes my problem: So... who has any ideas about how to find x3/y3 - thus leading me to find the angle in which the weapon has to tilt in order to fire a projectile to meet the enemy? EDIT I think it would be clearer if I also mention that I know: the speed of both Enemy and Projectile and the Enemy travels on a straight vertical line.

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  • How to rotate a sprite using multi-touch with AndEngine?

    - by 786
    I am new to Android game development. I am using AndEngine GLES-2. I have created a box with a sprite. This box is now draggable by using the code below. It works fine. But I want multi-touch on this: I want to rotate the sprite with two fingers on that box, and to keep it draggable. I've no idea how do do that, which way should I go? final float centerX = (CAMERA_WIDTH - this.mBox.getWidth()) / 2; final float centerY = (CAMERA_HEIGHT - this.mBox.getHeight()) / 2; Box = new Sprite(centerX, centerY, this.mBox, this.getVertexBufferObjectManager()) { public boolean onAreaTouched(TouchEvent pSceneTouchEvent, float pTouchAreaLocalX, float pTouchAreaLocalY) { this.setPosition(pSceneTouchEvent.getX() - this.getWidth()/ 2, pSceneTouchEvent.getY() - this.getHeight() / 2); float pValueX = pSceneTouchEvent.getX(); float pValueY = CAMERA_HEIGHT-pSceneTouchEvent.getY(); float dx = pValueX - gun.getX(); float dy = pValueY - gun.getY(); double Radius = Math.atan2(dy,dx); double Angle = Radius * 360 ; Box.setRotation((float)Math.toDegrees(Angle)); return true; }

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  • "Walking" along a rotating surface in LimeJS

    - by Dave Lancea
    I'm trying to have a character walk along a plank (a long, thin rectangle) that works like a seesaw, being rotated around a central point by box2d physics (falling objects). I want the left and right arrow keys to move the player up and down the plank, regardless of it's slope, and I don't want to use real physics for the player movement. My idea for achieving this was to compute the coordinate based on the rotation of the plank and the current location "up" or "down" the board. My math is derived from here: http://math.stackexchange.com/questions/143932/calculate-point-given-x-y-angle-and-distance Here's the code I have so far: movement = 0; if(keys[37]){ // Left movement = -3; } if(keys[39]){ // Right movement = 3; } // this.plank is a LimeJS sprite. // getRotation() Should return an angle in degrees var rotation = this.plank.getRotation(); // this.current_plank_location is initialized as 0 this.current_plank_location += movement; var x_difference = this.current_plank_location * Math.cos(rotation); var y_difference = this.current_plank_location * Math.sin(rotation); this.setPosition(seesaw.PLANK_CENTER_X + x_difference, seesaw.PLANK_CENTER_Y + y_difference); This code causes the player to swing around in a circle when they are out of the center of the plank given a slight change in rotation of the plank. Any ideas on how I can get the player position to follow the board position?

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  • Create indefinitely oscillating pendulum in Farseer Physics 3.3.1/Box2d

    - by GONeale
    I am new to Farseer Physics and using version 3.3.1. I am after some help and would even be happy to receive Box2d answers just to ensure I get a response as I should then be able to convert it! -- Thanks ...After a lot of tinkering around I have managed to produce a thin vertical rectangle shape on the screen and I wish this to swing back and forth pinned at the top up to an angle I set (90 degrees would be fine for this sample). When it is approaching the top I wish it to slow down, then fall back the way it just came, increase speed then obviously slow to a stop at the top again. Almost how a swinging pirate ship would work at a theme park. This is the code I have so far which swings the shape, but it is seeming to lose speed on each swing eventually grinding to a halt: float playerWidth = ConvertUnits.ToSimUnits(5), playerHeight = ConvertUnits.ToSimUnits(68); playerPosition = ConvertUnits.ToSimUnits(-350, 0); playerBody = BodyFactory.CreateRectangle(World, playerWidth, playerHeight, 2f, playerPosition); playerBody.BodyType = BodyType.Dynamic; // create player sprite based on player body _rectangleSprite = new Sprite(ScreenManager.Assets.TextureFromShape(playerBody.FixtureList[0].Shape, MaterialType.Player, Color.Orange, 1f)); // Create swinging joint var joint = JointFactory.CreateFixedRevoluteJoint(World, playerBody, ConvertUnits.ToSimUnits(0, -34), playerBody.Position); If somebody could also provide the command I would need to pause the shape on a mouse click or keyboard command at it's current angle and then continue when I let go of the mouse click that would be super fantastic! (I actually posted this on StackOverflow as well before I realised there was a dedicated game development forum) Cheers

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