Search Results

Search found 17876 results on 716 pages for 'ejb jar xml'.

Page 12/716 | < Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >

  • Element Based XML Parsing

    - by demos
    I have an XML document which reads like this: <xml> <web:Web> <web:Total>4000</web:Total> <web:Offset>0</web:Offset> </web:Web> </xml> my question is how do I access them using a library like BeautifulSoup in python? xmlDom.web["Web"].Total ? does not work?

    Read the article

  • Element Based XML Parising

    - by demos
    I have an XML document which reads like this: <xml> <web:Web> <web:Total>4000</web:Total> <web:Offset>0</web:Offset> </web:Web> </xml> my question is how do I access them using a library like BeautifulSoup in python? xmlDom.web["Web"].Total ? does not work?

    Read the article

  • Getting multiple data items in an element with linq to xml

    - by Maestro1024
    Getting multiple data items in an element with linq to xml I have an xml file like this <TopLevel> <Inside> Jibba </Inside> <Inside> Jabba </Inside> </TopLevel> I was given said xml and and want to get all the elements. Here is the code I have. var q = from c in loaded.Descendants("TopLevel") select (XElement)c.Element("Inside"); I tried c.Elements but that did not work. What do I need to do to get all of the internal elements? This code just gets the first "Inside" tag.

    Read the article

  • How to modify by loading and saving the same xml file

    - by cynthia hong
    I have a problem with modifying xml file when i first load and then save it with same file path and name. Below is my code. The error is "Access to the path C:\MyApp\Web.config is denied. If i change the path of the xdoc.Save to be different from xdoc.Load, then it will be ok. What is your recommandation to solve this problem? If possible, i need to modify the existing xml file(meaning xml file for loading and saving is the same path). XmlDocument xdoc = new XmlDocument(); xdoc.Load(@"C:\\MyApp\\Web.config"); XmlNode xn = xdoc.SelectSingleNode("//configuration/MyProvider"); XmlElement el = (XmlElement)xn; el.SetAttribute("defaultProvider", "MyCustomValue"); xdoc.Save(@"C:\\MyApp\\Web.config"); Thanks in advance.

    Read the article

  • Linq to xml not able to add new elements

    - by Fore
    We save our xml in a "text" field in the database. So first I check if it exist any xml, if not I create a new xdocument, fill it with the necessary xml. else i just add the new element. Code looks like this: XDocument doc = null; if (item.xmlString == null || item.xmlString == "") { doc = new XDocument(new XDeclaration("1.0", "utf-8", "yes"), new XElement("DataTalk", new XAttribute(XNamespace.Xmlns + "xsi", "http://www.w3.org/2001/XMLSchema-instance"), new XAttribute(XNamespace.Xmlns + "xsd", "http://www.w3.org/2001/XMLSchema"), new XElement("Posts", new XElement("TalkPost")))); } else { doc = XDocument.Parse(item.xmlString); } This is working alright to create a structure, but then the problem appears, when I want to add new TalkPost. I get an error saying incorrectly structured document. The following code when adding new elements: doc.Add(new XElement("TalkPost", new XElement("PostType", newDialog.PostType), new XElement("User", newDialog.User), new XElement("Customer", newDialog.Customer), new XElement("PostedDate", newDialog.PostDate), new XElement("Message", newDialog.Message)));

    Read the article

  • Java EE6 App + EJB in Glassfish 3.0/Netbeans 6.8?

    - by egbokul
    Has anyone got this configuration working? Latest Netbeans, latest Glassfish, I created an EJB project, also an EE Application. The EJB in itself builds & deploys to Glassfish OK. Now when I want to reference the EJB, I have to add the EJB jar to the EE Application path, if I don't do this the code does not compile. But, the EJB jar gets packaged in the App jar and as a result when I try to deploy the app to Glassfish it says: "java.lang.IllegalArgumentException: Sniffers with type [ejb] and type [appclient] should not claim the archive at the same time. Please check the packaging of your archive" How do I tell Netbeans NOT TO package the EJB in the App jar? Or is the problem somewhere else? btw. if I remove the EJB manually from the JAR then the app deploys successfully (with asadmin deploy), but when I try to run it with appclient, I get a NullPointerException. Surely there must be a solution to this, I thought Netbeans was for web application development after all...

    Read the article

  • Eclipse does not recognize Classes of the jar

    - by Tom Brito
    I've included a new jar in my jre/lib/ext folder, and updated the Eclipse jre so the Eclipse see the new jar in the default JRE System Library. The trouble is that even showing the jar in the JRE System Library, the Eclipse does not see the Classes. And the worst: Eclipse see tha packages! It don't see only the classes! Here is a printscreen showing the jar withing the JRE System Library, and the Eclipse preview showing only the packages: http://picasaweb.google.com/brito.pro/Fail#5458323206632279634 Any idea how to solve this? :?

    Read the article

  • Java WebApp: Loading resource from .jar located in WEB-INF

    - by shaman.sir
    There are a lot of similar questions, but, probably, mine is a little bit different: What is the right way to load resource from inside of .jar file located in WEB-INF/lib folder (if I know the jar file name and the name of the class it resource belongs to), while Web Application is running? Should I use getServletContext().getResourceAsStream(?) for this purpose or the <name-of-known-class>.getResourseAsStream(?), and what path do I need to specify there? So, the structure is: /WEB-INF /classes /some/package/name ?.class #some Java code or Servlet that tries to read 'required-file.xml' /lib /<jar-with-known-name>.jar /another/package/with/known/name SomeKnownClass.class required-file.xml

    Read the article

  • Packaging reference documentation with jar file

    - by soren.enemaerke
    We are porting our .NET library to a java equivalent and is now looking at how to distribute this port. Packaging the classes into a jar-file seems like best practice and we would then ship this jar file in a zip along with some license terms. But what about the documentation? In .NET land it seems like best practice to distribute the xml file that can be consumed by tooling (Visual Studio) but we can't seem to find such best practices for java. We have javadoc comments on our public classes and interfaces, so we are just looking for a way to generate and distribute these comments in a way that is developer friendly (we're thinking easily consumed from various IDEs). What are developers expecting and how do you best deliver this? We would really prefer to bundle the documentation along with the jar file and not have to host the documentation on our website EDIT: We would like for our documentation to appear inside the java IDEs so we want to provide the documentation in a way that integrates into the IDEs as gracefully as possible. In .NET land this is as an xml file placed next to the .dll file, but is there a similar concept for jar files that enables the integration into tooling? PS: We are developing in Eclipse and have an ant task doing the building and jar-file packaing in our automated build.

    Read the article

  • How to search Jar files using Windows Search?

    - by Marcus
    I believe back when we were on Win2K, Windows Search would search through Jar files to locate specific classes but this doesn't appear to work in XP. Does anyone know how to enable this in XP? Note, to do the search in Win2K we just entered *.jar for the files and "ClassABC" for the search text string and the search would return any jar files containing class files where the title contained "ClassABC".

    Read the article

  • How do I add a .jar file to the compilation of .java files

    - by Christopher Schroeder
    My makefile is below Also, I would appreciate it if you told me how to move my .class files to ../bin/ JFLAGS = -cp JAR = "RSBot*.jar" JC = javac .SUFFIXES: .java .class .java.class: $(JC) $(JFLAGS) $(JAR) $*.java CLASSES = \ src/Banker.java \ src/Eater.java \ src/Fighter.java \ src/grotgui.java \ src/InventTab.java \ src/Looter.java \ src/Potter.java \ src/W8babyGrotworm.java \ src/Walker.java default: classes classes: $(CLASSES:.java=.class) clean: $(RM) *.class

    Read the article

  • Automatically copy new Jar file to Tomcat project WEB-INF/lib folder

    - by The D Williams
    I am developing a Tomcat app (actually it's a Red5 app, but this is effectively the same). This contains the usual /WebContent/WEB-INF/lib folder, which is where I locate the various jars it uses. Recently, I pulled a package out of my app project, and converted into a separate Jar project which was then released as open source (this resides in the same workspace). What I want, is that when I build my Tomcat app, that Eclipse automatically pulls the latest version of the Jar I have built into its /WebContent/WEB-INF/lib folder. This is the behaviour you get with .NET when you reference one project from another, and I guess this is why I was expecting to find some way of doing it. At the moment, I have to manually copy/paste the Jar across each time I build it. Of course, ideally when I build my Tomcat app it would automatically detect if the Jar project was up-to-date too, and build it if not. Any suggestions most gratefully received.

    Read the article

  • my .jar file won't do anything.

    - by David
    I created a program that more or less holds an array of strings as an object and randomly prints one. so basicaly class Happy { string[] namestrings = new string[#] constructor() { fill with some strings} public static void main (String[]arg) { create instance of class do some junk with it method that prints it } method that prints it {} another method } when i compile and run it on the command line it works fine but when on the comand line i type in jar -cf Happy.jar Fun.class i get a .jar file called Happy and when i click on it i get an error message that reads "the java Jar file happy could not be launched read the consol for possible error messages" I have a mac i'm running lepord if that makes a diference. Whats going on?

    Read the article

  • JAR file folder for eclipse projects

    - by Daff
    I'm trying to create a centralized folder (in some kind of a "meta project" in my eclipse workspace) for commonly used JAR files for referenced projects in this workspace. It should work similar to the WEB-INF/lib folder for web projects but also apply to non web projects, and automatically scan and add all jar files in this folder. I tried to create a user library with these jar files and reference them in the project but I still have to add every new jar manually to the user library (and don't know if it is referenced relative of absoulute) and Tomcat (WTP) doesn't seem to take these files (Run As - Run on Server) into its classpath (and I don't want to duplicate the jars and put them into WEB-INF/lib). Any ideas?

    Read the article

  • Resources access problem from JAR

    - by aeter
    I have the following directory structure of a project: Folder "project" in Eclipse: --folder "src" --folder "resources" ----trayicon2.png --folder "db" ----test.db --folder "bin" I'm accessing the image with: Image image = Toolkit.getDefaultToolkit().getImage("resources/trayicon2.png"); and from Eclipse that is not a problem. Then I generate an "executable jar file", and add the dirs, making a directory structure of: Folder "project" --folder "db" ----test.db --folder "resources" ----trayicon2.png --project.jar And now the image is no more accessible. Also, the database is no more accessible; while in Eclipse I used to access it with: Connection conn = DriverManager.getConnection("jdbc:sqlite:db/test.db"); How can I access the resources (images and db) after generating the jar file "project.jar"?

    Read the article

  • Run Jar in Background on Linux

    - by Benny
    I have a jar that runs forever (infinite loop with socket listening thread) and need it to run in the background at all times. An example would be: "java -jar test.jar" How do I do this? Thanks in advance!

    Read the article

  • NullPointerException when accessing image files in a .jar file

    - by user548240
    Hi, I have pretty much tried everything but still have this same problem. I have the following setup: I have a images.jar containing a folder called 'images' in which there are multiple image files. I add images.jar to the java build path of the project in eclipse, and i've been trying to use the following code to access the individual images in the jar: URL url = this.getClass().getResource("images/a.png"); ImageIcon icon = new ImageIcon (url); Unfortunately, the URL object is always NULL. I don't think this has anything to do with where I put images.jar file as it is added to the classpath in eclipse. I have also tried using the path '/images/a.png', but still the same problem. Any suggestion would be extremely welcome! Thanks.

    Read the article

  • Standard way of allowing general XML data

    - by Greg Jackson
    I'm writing a data gathering and reporting application that takes XML files as input, which will then be read, processed, and stored in a strongly-typed database. For example, an XML file for a "Job" might look like this: <Data type="Job"> <ID>12345</ID> <JobName>MyJob</JobName> <StartDate>04/07/2012 10:45:00 AM</StartDate> <Files> <File name="a.jpeg" path="images\" /> <File name="b.mp3" path="music\mp3\" /> </Files> </Data> I'd like to use a schema to have a standard format for these input files (depending on what type of data is being used, for example "Job", "User", "View"), but I'd also like to not fail validation if there is extra data provided. For example, perhaps a Job has additional properties such as "IsAutomated", "Requester", "EndDate", and so on. I don't particularly care about these extra properties. If they are included in the XML, I'll simply ignore them when I'm processing the XML file, and I'd like validation to do the same, without having to include in the schema every single possible property that a customer might provide me with. Is there a standard way of providing such a schema, or of allowing such a general XML file that can still be validated without resorting to something as naïve (and potentially difficult to deal with) as the below? <Data type="Job"> <Data name="ID">12345</Data> . . . <Data name="Files"> <Data name="File"> <Data name="Filename">a.jpeg</Data> <Data name="path">images</Data> . . . </Data> </Data>

    Read the article

  • Serializing a list of Key/Value pairs to XML

    - by Slauma
    I have a list of key/value pairs I'd like to store in and retrieve from a XML file. So this task is similar as described here. I am trying to follow the advice in the marked answer (using a KeyValuePair and a XmlSerializer) but I don't get it working. What I have so far is a "Settings" class ... public class Settings { public int simpleValue; public List<KeyValuePair<string, int>> list; } ... an instance of this class ... Settings aSettings = new Settings(); aSettings.simpleValue = 2; aSettings.list = new List<KeyValuePair<string, int>>(); aSettings.list.Add(new KeyValuePair<string, int>("m1", 1)); aSettings.list.Add(new KeyValuePair<string, int>("m2", 2)); ... and the following code to write that instance to a XML file: XmlSerializer serializer = new XmlSerializer(typeof(Settings)); TextWriter writer = new StreamWriter("c:\\testfile.xml"); serializer.Serialize(writer, aSettings); writer.Close(); The resulting file is: <?xml version="1.0" encoding="utf-8"?> <Settings xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <simpleValue>2</simpleValue> <list> <KeyValuePairOfStringInt32 /> <KeyValuePairOfStringInt32 /> </list> </Settings> So neither key nor value of the pairs in my list are stored though the number of elements is correct. Obviously I am doing something basically wrong. My questions are: How can I store the key/value pairs of the list in the file? How can I change the default generated name "KeyValuePairOfStringInt32" of the elements in the list to some other name like "listElement" I'd like to have?

    Read the article

  • PHP Object as XML Document

    - by Sam McAfee
    What is the best way to take a given PHP object and serialize it as XML? I am looking at simple_xml and I have used it to parse XML into objects, but it isn't clear to me how it works the other way around.

    Read the article

< Previous Page | 8 9 10 11 12 13 14 15 16 17 18 19  | Next Page >