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  • PHP submit problem

    - by TaG
    I'm trying to check if the username is available and display it for the user to see when they check there account settings, which I have done. BUT when the user tries to fill out another field I get the Your username is unavailable! which should not pop up because its the users username already. I want to know how can I fix this problem using PHP so that the users name is displayed every time the user views their account settings and it wont cause problems when a user submits additional info? Here is the PHP code. if (isset($_POST['submitted'])) { require_once '../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); $config->set('HTML.TidyLevel', 'heavy'); $config->set('HTML.SafeObject', true); $config->set('HTML.SafeEmbed', true); $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $first_name = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['first_name'])))); $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if($_POST['username']) { $u = "SELECT user_id FROM users WHERE username = '$username'"; $r = mysqli_query ($mysqli, $u) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); if (mysqli_num_rows($r) == TRUE) { $username = NULL; echo '<p class="error">Your username is unavailable!</p>'; } else if(mysqli_num_rows($r) == 0) { $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if ($_POST['password1'] == $_POST['password2']) { $sha512 = hash('sha512', $_POST['password1']); $password = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($sha512))); } else { $password = NULL; } if($password == NULL) { echo '<p class="error">Your password did not match the confirmed password!</p>'; } else { if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, username, password) VALUES ('$user_id', '$first_name', '$username', '$password')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', username = '$username', password = '$password' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } } } } Here is the html form. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="first_name">First Name: </label><input type="text" name="first_name" id="first_name" size="25" class="input-size" value="<?php if (isset($_POST['first_name'])) { echo stripslashes(htmlentities(strip_tags($_POST['first_name']))); } else if(!empty($first_name)) { echo stripslashes(htmlentities(strip_tags($first_name))); } ?>" /></li> <li><label for="username">UserName: </label><input type="text" name="username" id="username" size="25" class="input-size" value="<?php if (isset($_POST['username'])) { echo stripslashes(htmlentities(strip_tags($_POST['username']))); } else if(!empty($username)) { echo stripslashes(htmlentities(strip_tags($username))); } ?>" /><br /><span>(ex: CSSKing, butterball)</span></li> <li><label for="password1">Password: </label><input type="password" name="password1" id="password1" size="25" class="input-size" value="<?php if (isset($_POST['password1'])) { echo stripslashes(htmlentities(strip_tags($_POST['password1']))); } ?>" /></li> <li><label for="password2">Confirm Password: </label><input type="password" name="password2" id="password2" size="25" class="input-size" value="<?php if (isset($_POST['password2'])) { echo stripslashes(htmlentities(strip_tags($_POST['password2']))); } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Getting data back from database after an ajax post submit

    - by sslepian
    I've got a web page where the user can add a new item to a category and that item is saved to the database. However, the ID of the item is an identity value for the database table, so I don't know what the ID will be, and I need this ID so that the user can edit the item later. I'm using ajax to make a POST submit: $.ajax({ url: 'TumourGroup/CreateSub', type: "POST", data: {'pos': index, 'text': text } }); This is linked to an MVC model with three fields, ID, pos, and text. Is there a way for me to get the ID that's generated on POST submit by having CreateSub(int index, string text) return something?

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  • problem in jquery notify bar on submit form using php or zf

    - by user1400
    hi guys in my application on zend framework i use of 'jQuery Notify Bar' plugin for display messages, i'd like to show message when my form submit ,the other page is opened and notify bar be open until the other page is completely load and even some second more but the problem is that notify bar show for short Moment and when the other page begin to load , notify bar is closed, and the delay property is not effect to that $('#myForm').submit(function(){ $.notifyBar({ html: "Thank you, your settings were updated!", **delay: 20000,** animationSpeed: "normal" }); how to show notify bar in the other page too? thanks

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  • MVC 3 Remote Validation jQuery error on submit

    - by Richard Reddy
    I seem to have a weird issue with remote validation on my project. I am doing a simple validation check on an email field to ensure that it is unique. I've noticed that unless I put the cursor into the textbox and then remove it to trigger the validation at least once before submitting my form I will get a javascript error. e[h] is not a function jquery.min.js line 3 If I try to resubmit the form after the above error is returned everything works as expected. It's almost like the form tried to submit before waiting for the validation to return or something. Am I required to silently fire off a remote validation request on submit before submitting my form? Below is a snapshot of the code I'm using: (I've also tried GET instead of POST but I get the same result). As mentioned above, the code works fine but the form returns a jquery error unless the validation is triggered at least once. Model: public class RegisterModel { [Required] [Remote("DoesUserNameExist", "Account", HttpMethod = "POST", ErrorMessage = "User name taken.")] [Display(Name = "User name")] public string UserName { get; set; } [Required] [Display(Name = "Firstname")] public string Firstname { get; set; } [Display(Name = "Surname")] public string Surname { get; set; } [Required] [Remote("DoesEmailExist", "Account", HttpMethod = "POST", ErrorMessage = "Email taken.", AdditionalFields = "UserName")] [Display(Name = "Email address")] public string Email { get; set; } [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 8)] [DataType(DataType.Password)] [Display(Name = "Password")] public string Password { get; set; } [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 8)] [DataType(DataType.Password)] [Display(Name = "Confirm password")] public string ConfirmPassword { get; set; } [Display(Name = "Approved?")] public bool IsApproved { get; set; } } public class UserRoleModel { [Display(Name = "Assign Roles")] public IEnumerable<RoleViewModel> AllRoles { get; set; } public RegisterModel RegisterUser { get; set; } } Controller: // POST: /Account/DoesEmailExist // passing in username so that I can ignore the same email address for the same user on edit page [HttpPost] public JsonResult DoesEmailExist([Bind(Prefix = "RegisterUser.Email")]string Email, [Bind(Prefix = "RegisterUser.UserName")]string UserName) { var user = Membership.GetUserNameByEmail(Email); if (!String.IsNullOrEmpty(UserName)) { if (user == UserName) return Json(true); } return Json(user == null); } View: <script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.17/jquery-ui.min.js" type="text/javascript"></script> <script type="text/javascript" src="/Content/web/js/jquery.unobtrusive-ajax.min.js"></script> <script type="text/javascript" src="/Content/web/js/jquery.validate.min.js"></script> <script type="text/javascript" src="/Content/web/js/jquery.validate.unobtrusive.min.js"></script> ...... @using (Html.BeginForm()) { @Html.AntiForgeryToken() <div class="titleh"> <h3>Edit a user account</h3> </div> <div class="body"> @Html.HiddenFor(model => model.RegisterUser.UserName) @Html.Partial("_CreateOrEdit", Model) <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(model => model.RegisterUser.IsApproved)</span> @Html.RadioButtonFor(model => model.RegisterUser.IsApproved, true, new { @class = "uniform" }) Active @Html.RadioButtonFor(model => model.RegisterUser.IsApproved, false, new { @class = "uniform" }) Disabled <div class="clear"></div> </div> <div class="button-box"> <input type="submit" name="submit" value="Save" class="st-button"/> @Html.ActionLink("Back to List", "Index", null, new { @class = "st-clear" }) </div> </div> } CreateEdit Partial View @model Project.Domain.Entities.UserRoleModel <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(m => m.RegisterUser.Firstname)</span> @Html.TextBoxFor(m => m.RegisterUser.Firstname, new { @class = "st-forminput", @style = "width:300px" }) @Html.ValidationMessageFor(m => m.RegisterUser.Firstname) <div class="clear"></div> </div> <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(m => m.RegisterUser.Surname)</span> @Html.TextBoxFor(m => m.RegisterUser.Surname, new { @class = "st-forminput", @style = "width:300px" }) @Html.ValidationMessageFor(m => m.RegisterUser.Surname) <div class="clear"></div> </div> <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(m => m.RegisterUser.Email)</span> @Html.TextBoxFor(m => m.RegisterUser.Email, new { @class = "st-forminput", @style = "width:300px" }) @Html.ValidationMessageFor(m => m.RegisterUser.Email) <div class="clear"></div> </div> Thanks, Rich

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  • Styling HTML Submit Button (CSS, Different Browsers)

    - by jiewmeng
    i want to style a submit button which seems to be rendered abit differently in different browsers. <p id="lineInput"> <label for="task">Add a Task</label> <input type="text" name="task" id="task" /> <input type="submit" id="btnSubmit" value="Add" /> </p> #lineInput { ... position: relative; margin: 0px; } #btnSubmit { ... padding: 6px 8px; margin: 0; font: 1em/1em Hetilica; position: absolute; right: 2px; top: 3px; } notice the add button is too low on chrome when #btnSubmit has bottom: 3px. the issue if fixed in chrome with bottom: 5px but in Firefox will be too high

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  • jQuery: Check whether val() has a specific value or not upon form submit

    - by Staffan Estberg
    Hi, I'm trying to check whether val() has a specific value or not inside a form, if so deleting the contents / preventing the form being submitted depending on if both fields are filled in (stringOne and stringTwo). There's a default text for each input field, the first being "Namn, telefonnr, sökord" and the second "Område, plats, ort". If a user only fills in the first field the second must be cleared before the form string is passed on and vice versa. Like so - // "This" refers to the form's submit button if (($(this).siblings('input.stringOne').val("Namn, telefonnr, sökord")) && ($(this).siblings('input.stringTwo').val("Område, plats, ort"))) { return false; // If nothing's filled in, then do not submit } else { // If either field is not filled in, clear it if ($(this).siblings('input.stringOne').val("Namn, telefonnr, sökord")) { $(this).siblings('input.stringOne').val() == ''; } if ($(this).siblings('input.stringTwo').val("Område, plats, ort")) { $(this).siblings('input.stringTwo').val() == ''; } } jQuery version 1.2.6.

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  • PHP form validation submit problem

    - by TaG
    Every time I try to submit the form and I have not entered nothing in the year field I get Incorrect year! how can I still submit the form without having to enter a year. In other words leaving the year field blank and not getting a warning? Here is the PHP code. if(preg_match('/^\d{4,}$/', $_POST['year'])) { $year = mysqli_real_escape_string($mysqli, $_POST['year']); } else { $year = NULL; } if($year == NULL) { echo '<p class="error">Incorrect year!</p>'; } else { //do something }

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  • jQuery .submit() woes with IE8

    - by Jitesh
    I am trying to submit a delete link click via a http post to my asp.net mvc controller. While my code below works for chrome it does not work in IE8. Any pointer will be very useful. Setup:- Browser: IE8 jQuery: 1.4.1 MVC: 2.0 The delete link is:- <a title="Delete contact" href="/Contacts/Delete/<%= Model.Contact.Id %>" class="delete" rel="Are you sure you want to delete <%= Html.Encode(Model.Contact.Name) %>?">Delete</a> and the jqeury handler for the click of delete is $("a.delete").click(function() { if (confirm($(this).attr("rel"))) { var form = "<form method='POST' action='" + $(this).attr("href") + '" style='display:none;'></form>"; $(form).submit(); } return false; });

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  • POST from a submit button in C#

    - by Marlon
    I'm not familiar with http stuff, but how would I be able to submit data to a website? There is a submit button that I would like to "press" from a console app. This is not my own website. This is part of the page source, not sure if it has any relevance: <form action="rate.php" method="post"> I looked at the HttpWebRequest class but I am unfamiliar with what properties I need to fill in. Sorry I'm so vague but I'm not familiar with http.

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  • PHP getting blank pages after submit a form + signal Segmentation fault (11)

    - by Ole Media
    I few days ago I update my macbook pro to snow leopard, and since then some php files are not showing. This is what happens: I created a php form, when going to 'http://localhost/webform.php' I can see the form just fine. Then, once I submit the form, I just get a blank page. I enable error and warnings reporting under php.ini to make sure I'm not missing something, but still I'm not getting anything, just the blank page. Then I checked under apache log files, and what I notice is that every time I submit the form I see the following line coming up under the apache logs: [Wed Apr 07 21:40:28 2010] [notice] child pid 70223 exit signal Segmentation fault (11) I'm clueless on this one. Any ideas on how to fix it?

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  • POST and multiple submit buttons on form (iphone)

    - by Jonathan
    NSString *reqURL = [NSString stringWithFormat:@"%@/login",SERVER_URL]; NSMutableURLRequest *req = [[NSMutableURLRequest alloc]initWithURL:[NSURL URLWithString:reqURL]]; [req setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"]; NSData *myRequestData = [NSData dataWithBytes:[@"username=whatever&password=whatever" UTF8String] length: [@"username=whatever&password=whatever" length]]; [req setHTTPMethod: @"POST"]; [req setHTTPBody: myRequestData]; NSData *returnData = [NSURLConnection sendSynchronousRequest:req returningResponse: nil error: nil]; NSString *html = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; I got this code from another question I asked. But what happens if there is more than one submit button. I really have no idea how to ask this question. An example of such situation is on the logout page for this site. There are no fields to enter data into, but there are 2 submit buttons. How can I "simulate clicking" on one of those buttons using code like the above (so not using a UIWebView)

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  • click and submit button id with jquery

    - by user836910
    my aim is to submit a button id using jquery into a database im only interested in the button not its value. $("#button").click(function(){ var p = $(this).attr("id"); $.ajax({ type: "POST", url: subpage.php", data: 'b='+p, cache: false, success: function(html) { //process live } }); return false; }); subpage.php $item = $_POST['b']; $query = mysql_query("SELECT * FROM table WHERE id = '25' AND bttnid = '$item'"); if(count($query)==0){ mysql_query("INSERT INTO table VALUES ('','25','$item') "); } it doesn't submit. please assit

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  • in jqgrid, how can i have the editform disappear after submit

    - by leora
    right now, when i click submit it sends a message to the server and updates the databased and refreshes the screen but it keeps the edit form popup on the screen. Is there anyway to have it disappear once the submit is complete. its kind of annoying because its a little unclear that you are done because the form just sits there (even through the grid has refreshed) i have closeAfterEdit and closeAfterAdd set to true but it doesn't seem to do anything. jQuery("#grid").navGrid("#pager", { }, { height: 380, width: 500, reloadAfterSubmit: true, closeAfterEdit: true, url: siteRoot + controller + "/Update" }, { height: 380, width: 500, reloadAfterSubmit: true, closeAfterAdd: true, url: siteRoot + controller + "/Add" }, { reloadAfterSubmit: true, url: siteRoot + controller + "/Delete" }, { multipleSearch: true }

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  • how to show jquery notify bar on submit form using php or zf

    - by user1400
    hi guys in my application on zend framework i use of 'jQuery Notify Bar' plugin for display messages, i'd like to show message when my form submit ,the other page is opened and notify bar be open until the other page is completely load and even some second more but the problem is that notify bar show for short Moment and when the other page begin to load , notify bar is closed, and the delay property is not effect to that $('#myForm').submit(function(){ $.notifyBar({ html: "Thank you, your settings were updated!", **delay: 20000,** animationSpeed: "normal" }); how to show notify bar in the other page too? thanks

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  • Confused about technique to use to submit form

    - by user281180
    I have created a view in which i`m using clientsidevalidation. The jquery has a textbox , a table and a submit button. The table is empty at the beginning. Using jquery I populate the table with 2 columns ID and Name. I send the values to the controller using the submit button. My question are as follows: How do I send the values of the texbox and the table to the controller? Any guide please.

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  • Can I submit iPhone applications with same Icon.png but differnt bundle name

    - by AJ
    Can some one tell me if it is possible to submit two different iphone applications which has same Icon.png but have a different bundle name? I am working on a travel guide app that is targeted for different cities. I want the users of different cities to download the app as per their cities. So I want to submit different apps for different cities(3 in my case). User can also purchase any of these cities through in-app purchase. In that case the new purchased city would be unlocked in the app. Here is my thing. I want the same icon for all the three apps. I can do away with different names for app store and bundle(home screen icon name). But I am not sure if apple would approve/reject this app. Can someone enhance this blur picture I have?

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  • how to submit using link with my current code(php+jquery+ajax)

    - by ruslyrossi
    My current Code : <script type="text/javascript"> $(document).ready(function() { $('#form').ajaxForm( { target: '#preview', success: function() { $('#success_box').addClass('success') setTimeout(function() { $('#success_box').fadeOut('slow'); }, 3100); // <-- time in milliseconds } }); }); </script> <form action="controller/product_edit_update.php" method="post" id="form" name="form" > bla..bla.. <input type="submit" value="Save" /></form> but now i want to add submit link with <a href="" id="submit_with_link" >Save</a>

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  • submit button on html to output result on same page

    - by amateur
    Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

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  • Easiest way to submit data via PHP?

    - by Abijah
    I'm new to PHP, and have spent 10 hours trying to figure this problem out. The goal is to take all data entered into this order form, and send it to my email via PHP. I have 2 questions: 1. I can get PHP to send data from a single menu item (example: Mexican Tortas), but how do I get PHP to send data from multiple items (example: Mexican Tortas, Fish Sandwich and Hamburger)? 2. How do I tell PHP to not send data from menu items that don't have the "How Many?" or "Customize It?" text fields filled out? If you could provide a super simple example (or a link to a learning resource) I would really appreciate it. Thank you, Abijah PHP <?php if(isset($_POST['submit'])) { $to = "[email protected]"; $subject = "New Order"; $name_field = $_POST['name']; $phone_field = $_POST['phone']; $item = $_POST['item']; $quantity = $_POST['quantity']; $customize = $_POST['customize']; } $body = "Name: $name_field\nPhone: $phone_field\n\nItem: $item\nQuantity: $quantity\nCustomize: $customize"; echo "Data has been submitted to $to!"; mail($to, $subject, $body); ?> HTML <form action="neworder.php" method="POST"> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/mexicantortas.jpg"> <h1>Mexican Torta - $8.50</h1> <input name="item" type="hidden" value="Mexican Torta"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/fishsandwich.jpg"> <h1>Fish Sandwich - $8.50</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/hamburgers.jpg"> <h1>Hamburger w/ Fries - $7.00</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class="horizontal_form"> <div class="form"> <h2>Place Your Order Now: <font size="3"><font color="#037B41">Fill in the form below, and we'll call you when your food is ready to be picked up...</font></font></h2> <p class="name"> <input type="text" name="name" id="name" style="text-align:center;" onClick="this.value='';" value="Enter your name"/> </p> <p class="phone"> <input type="text" name="phone" id="phone" style="text-align:center;" onClick="this.value='';" value="Enter your phone #"/> </p> <p class="submit"> <input type="submit" value="Place Order" name="submit"/> </p> </div><!-- FORM --> </div><!-- HORIZONTAL_FORM --> </form>

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  • problem in jquery with showing pop message on submit form

    - by user1400
    hi guys in my application on php i use of 'jQuery Notify Bar' plugin for display messages, i'd like to show message when my form submit(in edit page) ,the other page(index page) is opened and notify bar be open until the other page(index page) is completely load and even some second more but the problem is that notify bar show for short Moment and when the index page begin to load , notify bar is closed, and the delay property is not effect to that $('#myForm').submit(function(){ $.notifyBar({ html: "Thank you, your settings were updated!", **delay: 20000,** animationSpeed: "normal" }); how to show notify bar in the other page too? thanks

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  • Javascript Function wont submit form..

    - by Josh K
    Here is my function: function processCheck() { var numberClicked = 0; var frm = document.getElementById('form'); for (var i=0; i<form.elements.length; i++) { if (frm.elements[i].checked) numberClicked++; } if(numberClicked != 8) alert('Must choose 8 Teams'); else frm.submit(); } My forms name is 'form', here is my input: echo "<input type='button' name='submit' value='Update' onclick='processCheck()' />"; When i click the button and there is anything but 8 boxes selected it displays the alert, if there is 8 boxes it does nothing (<-- The problem). I have the form action set to another page.

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  • Cannot submit form when disabling JSF page

    - by Steve
    Simple submit button. <h:commandButton actionListener="#{regBean.findReg}" action="#{regBean.navigate}" value="Search" /> The form tag is displayed like so: <h:form onsubmit="this.disabled=true;busyProcess();return true;"> This is so if the submit button is pressed, the page shows a "busy" icon until request is processed. The problem is, the request is never submitted and it never reaches the backend. However, if I instead take out the "disabled" call like so: <h:form onsubmit="busyProcess();return true;"> Everything works. Any ideas?

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  • Submit POST form from url

    - by Martijn Van Mierloo
    Website: www.example.com <form method="POSt" action="" > <input type="hidden" name="test1" value="test11" /> <input type="hidden" name="test2" value="" /> <input type="hidden" name="test3" value="test33" /> <input type="submit" value="Submit"> </form> I want to sumbit this form with adding the correct parameters in the URL. With GET, I can simply use : http://ww.example.com/?test1=test11&test2=&test3=test33 and the form will be sumbitted. Can I do the same for a POST? If so, how? Thanks

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