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  • Help! I'm a Haskell Newbie

    - by Darknight
    I've only just dipped my toe in the world of Haskell as part of my journey of programming enlightenment (moving on from, procedural to OOP to concurrent to now functional). I've been trying an online Haskell Evaluator. However I'm now stuck on a problem: Create a simple function that gives the total sum of an array of numbers. In a procedural language this for me is easy enough (using recursion) (c#) : private int sum(ArrayList x, int i) { if (!(x.Count < i + 1)) { int t = 0; t = x.Item(i); t = sum(x, i + 1) + t; return t; } } All very fine however my failed attempt at Haskell was thus: let sum x = x+sum in map sum [1..10] this resulted in the following error (from that above mentioned website): Occurs check: cannot construct the infinite type: a = a -> t Please bear in mind I've only used Haskell for the last 30 minutes! I'm not looking simply for an answer but a more explanation of it. Thanks in advanced.

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  • I need to simplify a MySQL sub query for performance - please help

    - by Richard
    I have the following query which is takin 3 seconds on a table of 1500 rows, does someone know how to simplify it? SELECT dealers.name, dealers.companyName, dealer_accounts.balance FROM dealers INNER JOIN dealer_accounts ON dealers.id = dealer_accounts.dealer_id WHERE dealer_accounts.id = ( SELECT id FROM dealer_accounts WHERE dealer_accounts.dealer_id = dealers.id AND dealer_accounts.date < '2010-03-30' ORDER BY dealer_accounts.date DESC, dealer_accounts.id DESC LIMIT 1 ) ORDER BY dealers.name I need the latest dealer_accounts record for each dealer by a certain date with the join on the dealer_id field on the dealer_accounts table. This really should be simple, I don't know why I am struggling to find something.

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  • jQuery JSON help

    - by kim
    okay I'm new to jQuery and JSON but I have now done so I got some information from the database in JSON format and now I want to show the results in a nice way but I don't know how ;) what I want is to show 5 newest threads on my page so will this script try to load all the time or do I need to do something else? I want it to show the 5 newest threads and when there somes a new thread i should slide down and the 6 threads at the bottom should disappear Here is my code <script type="text/javascript"> $.getJSON('ajax/forumThreads', function(data) { //$('<p>' + data[0].overskrift + '</p>').appendTo('#updateMe > .overskrift'); $('<div class="overskrift">' + data[0].overskrift + '</div>') { $(this).hide().appendTo('updateMe').slideDown(1000); } //alert(data[0].overskrift); }); </script>

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  • Need help building SQL Query (simple JOIN)

    - by Newbie
    Hello! In my database, I have a "users", a "quests" and a "questings" table. A user can solve a quest. Solving a quest will save the "user_id" and the "quest_id" in my "questings" table. Now, I want to select all quests, a user has NOT solved (meaning there is no entry for this user and quest in "questings" table)! Let's say the user has the id 14. How to write this query? After solving this query, I want to filter the results, too. A quest and a user has a city, too. What to do for writing a query which returns all quests, a user has NOT solved yet, in the users city (user city == quest city)?

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  • help implementing All Nearest Smaller Values algorithm

    - by davit-datuashvili
    http://en.wikipedia.org/wiki/All_nearest_smaller_values this is site of the problem and here is my code but i have some trouble to implement it import java.util.*; public class stack{ public static void main(String[]args){ int x[]=new int[]{ 0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15 }; Stack<Integer> st=new Stack<Integer>(); for (int a:x){ while (!st.empty() && st.pop()>=a){ System.out.println( st.pop()); if (st.empty()){ break; } else{ st.push(a); } } } } } and here is pseudo code from site S = new empty stack data structure for x in the input sequence: while S is nonempty and the top element of S is greater than or equal to x: pop S if S is empty: x has no preceding smaller value else: the nearest smaller value to x is the top element of S push x onto S

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  • Help with database design

    - by Jonny
    Hey im new to database design and having trouble trying to figure this one out. I have two tables Team and Fixtures. Team has rows of football teams and Fixture has 2 of those football teams in each row (home and away team). I want to link team id to home_team and away_team but it doesnt allow me to. Please tell me how i can solve this. Here is an image of my tables/relationships http://i49.tinypic.com/288qwpg.jpg

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  • Objective-C(iPhone SDK) - Code for Chemical Equation Balancer help

    - by Evan
    -(IBAction) balancer: (id) sender{ double M[4][4]; M[0][0] = 6.0; M[0][1] = 0.0; M[0][2] = -1.0; M[0][3] = 0.0; M[1][0] = 12.0; M[1][1] = 0.0; M[1][2] = 0.0; M[1][3] = 2.0; M[2][0] = 6.0; M[2][1] = 2.0; M[2][2] = -2.0; M[2][3] = 1.0; M[3][0] = 0.0; M[3][1] = 0.0; M[3][2] = 0.0; M[3][3] = 0.0; int rowCount = 4; int columnCount = 4; int lead = 0; for (int r = 0; r < rowCount; r++) { if (lead = columnCount) break; int i = r; while (M[i][lead] == 0) { i++; if (i == rowCount) { i = r; lead++; if (lead == columnCount){ break; } } } double temp[4] ; temp[0] = M[r][0]; temp[1] = M[r][1]; temp[2] = M[r][2]; temp[3] = M[r][3]; M[r][0] = M[i][0]; M[r][1] = M[i][1]; M[r][2] = M[i][2]; M[r][3] = M[i][3]; M[i][0] = temp[0]; M[i][1] = temp[1]; M[i][2] = temp[2]; M[i][3] = temp[3]; double lv = M[r][lead]; for (int j = 0; j < columnCount; j++) M[r][j] = M[r][j] / lv; for (int f = 0; f < rowCount; f++) { if (f != r) { double l = M[f][lead]; for (int j = 0; j < columnCount; j++) M[f][j] = M[f][j] - l * M[r][j]; } } lead++; } NSString* myNewString = [NSString stringWithFormat:@"%g",M[0][3]]; label1.text = myNewString; } This is returning NaN, while it should be returning .16666667 for M[0][3]. Any suggestions on how to fix this?

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  • Linked lists in Java - Help with writing methods

    - by user368241
    Representation of a string in linked lists In every intersection in the list there will be 3 fields : The letter itself. The number of times it appears consecutively. A pointer to the next intersection in the list. The following class CharNode represents a intersection in the list : public class CharNode { private char _data; private int _value; private charNode _next; public CharNode (char c, int val, charNode n) { _data = c; _value = val; _next = n; } public charNode getNext() { return _next; } public void setNext (charNode node) { _next = node; } public int getValue() { return _value; } public void setValue (int v) { value = v; } public char getData() { return _data; } public void setData (char c) { _data = c; } } The class StringList represents the whole list : public class StringList { private charNode _head; public StringList() { _head = null; } public StringList (CharNode node) { _head = node; } } Add methods to the class StringList according to the details : (I will add methods gradually according to my specific questions) (Pay attention, these are methods from the class String and we want to fulfill them by the representation of a string by a list as explained above) Pay attention to all the possible error cases. Write what is the time complexity and space complexity of every method that you wrote. Make sure the methods you wrote are effective. It is NOT allowed to use ready classes of Java. It is NOT allowed to move to string and use string operations. 1) public int indexOf (int ch) - returns the index in the string it is operated on of the first appeareance of the char "ch". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex isn't in the range, returns -1. Here is my try : public int indexOf (int ch) { int count = 0; charNode pos = _head; if (pos == null ) { return -1; } for (pos = _head; pos!=null && pos.getData()!=ch; pos = pos.getNext()) { count = count + pos.getValue(); } if (pos==null) return -1; return count; } Time complexity = O(N) Space complexity = O(1) EDIT : I have a problem. I tested it in BlueJ and if the char ch doesn't appear it returns -1 but if it does, it always returns 0 and I don't understand why... I am confused. How can the compiler know that the value is the number of times the letter appears consecutively? Can I assume this because its given on the question or what? If it's true and I can assume this, then my code should be correct right? Ok I just spoke with my instructor and she said it isn't required to write it in the exercise but in order for me to test that it indeed works, I need to open a new class and write a code for making a list so that the the value of every node is the number of times the letter appears consecutively. Can someone please assist me? So I will copy+paste to BlueJ and this way I will be able to test all the methods. Meanwhile I am moving on to the next methods. 2) public int indexOf (int ch, int fromIndex) - returns the index in the string it is operated on of the first appeareance of the char "ch", as the search begins in the index "fromIndex". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex doesn't appear in the range, returns -1. Here is my try: public int indexOf (int ch, int fromIndex) { int count = 0, len=0, i; charNode pos = _head; CharNode cur = _head; for (pos = _head; pos!=null; pos = pos.getNext()) { len = len+1; } if (fromIndex<0 || fromIndex>=len) return -1; for (i=0; i<fromIndex; i++) { cur = cur.getNext(); } if (cur == null ) { return -1; } for (cur = _head; cur!=null && cur.getData()!=ch; cur = cur.getNext()) { count = count + cur.getValue(); } if (cur==null) return -1; return count; } Time complexity = O(N) ? Space complexity = O(1) 3) public StringList concat (String str) - returns a string that consists of the string that it is operated on and in its end the string "str" is concatenated. Here is my try : public StringList concat (String str) { String str = ""; charNode pos = _head; if (str == null) return -1; for (pos = _head; pos!=null; pos = pos.getNext()) { str = str + pos.getData(); } str = str + "str"; return str; } Time complexity = O(N) Space complexity = O(1)

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  • Help with getParent() downcast.

    - by Preformed Cone
    I'm learning android/java and have this example code I can't get to work: OnRatingBarChangeListener l = new OnRatingBarChangeListener() { public void onRatingChanged(RatingBar ratingBar, float rating, boolean fromTouch) { Integer myPos=(Integer)ratingBar.getTag(); RowModel model=getModel(myPos); model.rating = rating; LinearLayout p=(LinearLayout)ratingBar.getParent(); TextView l=(TextView)p.findViewById(R.id.label); l.setText(model.toString()); } }; Everything works except the LinearLayout / getParent() downcast. At runtime it creates a ClassCastException. If I comment out that block of code then everthing works fine. What am I missing?

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  • need help me in excel-vba

    - by aos
    Private Sub cmdClear_Click() Dim Confirm As Integer Confirm = MsgBox("Are you sure you want clear this Sheet?", vbYesNo, "WARNING: Date Changed") If Confirm = 6 Then Sheets("OPV").Activate 'Sheets("OPV").Activate Sheets("OPV").Range("B4:BZ1000").ClearContents Sheets("OPV").Range("B4:BZ1000").Interior.Pattern = xlNone Sheets("OPV").Activate Sheets("OPV").Range("B4").Activate MsgBox " Done .. ", vbInformation, "Clear ......" End If End Sub

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  • Error using 'send_file' for ruby/rails - help appreciated

    - by user1653279
    I am trying to create a link to download a file from the file system. For this, I define the following in the "license_helper.rb" file: def license_download_link(license, link_text = nil) if link_text.blank? link_text = image_tag("download_icon.png", :border => 0, :width => 32, :height =>32, :alt => 'Download License', :title => 'Download License') end tempLicenseFile = "tempLicense.xml" File.open("#{tempLicenseFile}", 'w') do |tf| tf.puts license.data end command = "./runLicenseEncoder.bat #{tempLicenseFile}" generateEncryptedLicenseFile = `#{command}` theLicenseFile = "license.xml" link_to link_text, "license/download" end My "view" just calls this helper class: <td><%= license_download_link(license, ' ') %></td> In the 'routes.rb' file, I have defined the following: map.licensedownload "license.xml", :controller = 'licenses', :action = 'download' map.download "/licenses/download", :controller = 'licenses', :action = 'download' In the 'controller', I have 'licenses_controller.rb' which includes the following: def download theLicense = @license licenseFileName = "license.xml" send_file "#{licenseFileName}" , :type => "application/xml", :filename => "#{licenseFileName}" end However, I am unable to obtain the '@license' attribute from the database in the controller. Could someone please let me know what I am doing wrong here and why I am unable to get the value for "@license". Thanks for your time, Regards, --- AJ

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  • Manipulating/changing adressbar link Help

    - by Karem
    I am out of my own "ideas" going through this. I have a album viewer. When you click next I want the adressbar to hang with it, e.g if you start on ?photoid=1, and click next (next picture appends and stuff), and then i want it to say ?photoid=2. Now I cant make it say ?photoid=2 without changing/manipulating, and this you cant do without HTML5. I have made a script in HTML5 that works fine, but then I need to take care of those who dont have HTML5(only chrome, ff4 etc supports html5) Made the script from this( https://developer.mozilla.org/en/DOM/Manipulating_the_browser_history ) I thought of adding #photoid=2 so, ?photoid=1#photoid=2 and then check if theres anything in # then use that instead of the $_GET.. But apparently you cannot do that as # is client side handled and never sent to the server. So what should I then do? Any suggestions please to make a workaround this? I checked facebook, what they did to IE users, and I could hear that it "clicked" (the annoying click sound from IE) twice.. the first was to get to the next picture, the second click sound changed the adressbar?!(how?). And then I also thought hey, html5 is only supported in ff4, and I got ff3.6, and they manipulate the adress bar url when you browse through the album photos, exactly like how I wanted (and what I have written for but it only works in Chrome and ff4..?). How could they do that?

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  • Basic help needed with pointers

    - by sbsp
    Hi, i asked some time ago on an account i cant remember how to manipulate basic pointers and someone gave me a really good demo for example char *ptr = hello (hello = a char array) so now *ptr is pointing at h ptr++ = moves the ptr to point at the next element, to get its value i do *ptr and that gives me e ok so far i hope :D but now i need to manipulate a char **ptr and was wondering how i do this in a way that mimmicks the effects of a 2d array? some basic tips would be much appreciated as i need to do an assignment that has a **ptr to immitate a 2d array and without knowing how it does this first means i cant even solve it on paper (for example, how do you dereference a **ptr, how do you get [x][y] values etc) thanks

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  • help on integrating oracle BI into existing application

    - by ywang1129
    I have an existing application written in perl. Now i need to integrate this application with ocbi. The plan is having button that user can click on to open ocbi in iframe. The ocbi resides on a different server from the running application. Has anyone done this before, know what is the best practice of doing this, and what is the effort of doing this. another question is is it possible to add customize the ocbi displayed in iframe. thanks

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  • Need help with displaying the message correctly in the pole display always starting at the beginning

    - by SA
    Hi, I am using an HP RS232 pole display with the following setting: Char type: USA/Europe (default) Command mode: EPSON (default) Baud rate: 9600, n , 8, 1 (default?) Passthru None (Default) Here's the code using System.IO.Ports; private SerialPort port; port = new SerialPort("COM2", 9600, Parity.None, 8, StopBits.One); port.Handshake = Handshake.None; Port.WriteLine("Welocome to something something"); It has 2 lines consisting of 20 characters each with a total of 40 characters. I have no control how and where the characters get displayed. I would like it to always begin on line 1 position 1 but as I said earlier how would I be able to do that. The same program if I run again and again it moves a character to the left. I have set it to accept ASCII char set and so I am able to type as is visble in the Writeline message

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  • Help renaming svn repository

    - by rascher
    Here is the deal: I created an SVN repository, say, foo. It is at http://www.example.com/foo. Then I did an svn checkout. I made some updates and changes to my local copy of the code over the week. I haven't committed yet. I realized that I wanted to rename the repository. So I did this: svn copy http://example.com/foo http://example.com/bar svn delete http://example.com/foo I finish my changes (and local svn still thinks I'm working under "foo".) svn commit fails because the repo has been renamed. I try to use svn switch --relocate but it yells at me because svn is awful. I try using the script here to replace "foo" with "bar" in my billion .svn/ folders. This replace is taking a long time. I wonder if something hung? Or maybe sshfs failed? I kill it. Ctrl-C. I look and see that half my files have "foo" and the others have "bar" in the URLs in the sundry .svn/ folders. All I want to do is commit my files with the new name. I could re-checkout the branch, but then I have no way to remember which files I changed, which is why I was using version control in the first place, and svn is so godawful at moving and renaming things. What do I need to do to: Have a "clean" copy of my "bar" svn branch? and, most importantly: Commit the changes I made?

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  • help with $(this).val() toUpperCase()

    - by rod
    Hi All, Given: <script type="text/javascript"> $(document).ready(function () { var str = 'Test'; //alert(str.toUpperCase()); $('#stringFinder').keyup(function (e) { alert($(this).val()==str.toUpperCase()); }); }); </script> How do I make $(this).val() all upper case to get a like comparison? Thanks, rodchar

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  • help me to choose between two designs

    - by alex
    // stupid title, but I could not think anything smarter I have a code (see below, sorry for long code but it's very-very simple): namespace Option1 { class AuxClass1 { string _field1; public string Field1 { get { return _field1; } set { _field1 = value; } } // another fields. maybe many fields maybe several properties public void Method1() { // some action } public void Method2() { // some action 2 } } class MainClass { AuxClass1 _auxClass; public AuxClass1 AuxClass { get { return _auxClass; } set { _auxClass = value; } } public MainClass() { _auxClass = new AuxClass1(); } } } namespace Option2 { class AuxClass1 { string _field1; public string Field1 { get { return _field1; } set { _field1 = value; } } // another fields. maybe many fields maybe several properties public void Method1() { // some action } public void Method2() { // some action 2 } } class MainClass { AuxClass1 _auxClass; public string Field1 { get { return _auxClass.Field1; } set { _auxClass.Field1 = value; } } public void Method1() { _auxClass.Method1(); } public void Method2() { _auxClass.Method2(); } public MainClass() { _auxClass = new AuxClass1(); } } } class Program { static void Main(string[] args) { // Option1 Option1.MainClass mainClass1 = new Option1.MainClass(); mainClass1.AuxClass.Field1 = "string1"; mainClass1.AuxClass.Method1(); mainClass1.AuxClass.Method2(); // Option2 Option2.MainClass mainClass2 = new Option2.MainClass(); mainClass2.Field1 = "string2"; mainClass2.Method1(); mainClass2.Method2(); Console.ReadKey(); } } What option (option1 or option2) do you prefer ? In which cases should I use option1 or option2 ? Is there any special name for option1 or option2 (composition, aggregation) ?

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  • Syntax error. Help with one small JS snippet :(

    - by Bogdan
    Hey guys. I don't know much JS, but I wanted to do some quick work with jQuery. But I've been staring at this for about an hour and I don't understand what I missed: <script type="text/javascript"> $('#qty_6035').change(function () { var substractedQty, stockQty, remQty; substractedQty = (int) $('#qty_6035').val(); // missing ; before statement stockQty = (int) $('#orig_qty_6035').val(); $('#rem_qty_6035').html(stockQty-substractedQty); }); </script> jQuery library is included at the beggining of the document. Thanks.

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  • Help with a query

    - by stackoverflowuser
    Hi Based on the following table ID Effort Name ------------------------- 1 1 A 2 1 A 3 8 A 4 10 B 5 4 B 6 1 B 7 10 C 8 3 C 9 30 C I want to check if the total effort against a name is less than 40 then add a row with effort = 40 - (Total Effort) for the name. The ID of the new row can be anything. If the total effort is greater than 40 then trucate the data for one of the rows to make it 40. So after applying the logic above table will be ID Effort Name ------------------------- 1 1 A 2 1 A 3 8 A 10 30 A 4 10 B 5 4 B 6 1 B 11 25 B 7 10 C 8 3 C 9 27 C I was thinking of opening a cursor, keeping a counter of the total effort, and based on the logic insert existing and new rows in another temporary table. I am not sure if this is an efficient way to deal with this. I would like to learn if there is a better way.

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  • Little (Employee - Shift) SQL Database help

    - by latinunit-net
    Hi Guys, Im creating a little database that has employee, emp_shift, shift, tables now im suppose to be able to calculate at the end of the month which employee has done the most number of shifts. Ive created the SQL creation, insert statements for the tables, and a little diagram to explain what im trying to acomplish, im a beginner and this is a homework ive been trying to do for the last 4 days. Diagram: http://latinunit.net/emp_shift.jpg SQL: latinunit.net/emp_shift.txt can you please guys check it, deadline is 2 days and this is just a part of the whole database

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