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  • WPF TreeView PreviewMouseDown on TreeViewItem

    - by imekon
    If I handle the PreviewMouseDown event on TreeViewItem, I get events for everything I click on that TreeViewItem include the little +/- box to the left (Windows XP). How can I distinguish that? I tried the following: // We've had a single click on a tree view item // Unfortunately this is the WHOLE tree item, including the +/- // symbol to the left. The tree doesn't do a selection, so we // have to filter this out... MouseDevice device = e.Device as MouseDevice; // This is bad. The whole point of WPF is for the code // not to know what the UI has - yet here we are testing for // it as a workaround. Sigh... // This is broken - if you click on the +/- on a item, it shouldn't // go on to be processed by OnTreeSingleClick... ho hum! if (device.DirectlyOver.GetType() != typeof(Path)) { OnTreeSingleClick(sender); } What I'm after is just single click on the tree view item excluding the extra bits it seems to include.

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  • Thinking of an Inner Join as a Cross Join and then satisfying some condition(s)?

    - by Jian Lin
    It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then satisfying some condition(s)? Because the equi-join can be obvious, but the non-equi-join can be a bit confusing. But if we always use the Cross Join, and then filter out the ones satisfying the condition, then we get the resulting table. In other words, we can always analyze it by using the first record on the left table, and then go through every single records on the right, and then repeat that for 2nd record on the left, and for the 3rd, 4th, ... etc. So in our mind, we can analyze it using this way, and it is like O(n^2), although what happens in the DBMS maybe that it is a lot faster (when an index is present). Is there another good way to think of it besides this method?

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  • Advanced SQL query with lots of joins

    - by lund.mikkel
    Hey fellow programmers Okay, first let me say that this is a hard one. I know the presentation may be a little long. But I how you'll bare with me and help me through anyway :D So I'm developing on an advanced search for bicycles. I've got a lot of tables I need to join to find all, let's say, red and brown bikes. One bike may come in more then one color! I've made this query for now: SELECT DISTINCT p.products_id, #simple product id products_name, #product name products_attributes_id, #color id pov.products_options_values_name #color name FROM products p LEFT JOIN products_description pd ON p.products_id = pd.products_id INNER JOIN products_attributes pa ON pa.products_id = p.products_id LEFT JOIN products_options_values pov ON pov.products_options_values_id = pa.options_values_id LEFT JOIN products_options_search pos ON pov.products_options_values_id = pos.products_options_values_id WHERE pos.products_options_search_id = 4 #code for red OR pos.products_options_search_id = 5 #code for brown My first concern is the many joins. The Products table mainly holds product id and it's image and the Products Description table holds more descriptive info such as name (and product ID of course). I then have the Products Options Values table which holds all the colors and their IDs. Products Options Search is containing the color IDs along with a color group ID (products_options_search_id). Red has the color group code 4 (brown is 5). The products and colors have a many-to-many relationship managed inside Products Attributes. So my question is first of all: Is it okay to make so many joins? Is i hurting the performance? Second: If a bike comes in both red and brown, it'll show up twice even though I use SELECT DISTINCT. Think this is because of the INNER JOIN. Is this possible to avoid and do I have to remove the doubles in my PHP code? Third: Bikes can be double colored (i.e. black and blue). This means that there are two rows for that bike. One where it says the color is black and one where is says its blue. (See second question). But if I replace the OR in the WHERE clause it removes both rows, because none of them fulfill the conditions - only the product. What is the workaround for that? I really hope you will and can help me. I'm a little desperate right now :D Regards Mikkel Lund

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  • OpenGL Projection matrix won't allow displaying anything

    - by user272973
    I'm trying to get some basic OpenGL-ES with Shaders to run on the iPhone, based on some examples. For some reason my projection matrix refuses to result in something on the screen. It feels like a clipping plane is set very near but that contradicts with the values I supply. If I render the same scene with an Orthogonal projection matrix I see my object just no perspective obviously. Here's the code that generates the projection matrix: esPerspective(&proj, 45.f, 768.0/1024.0, 1.f, 10000.f); void esPerspective(ESMatrix *result, float fovy, float aspect, float nearZ, float farZ) { float frustumW, frustumH; frustumH = tanf( fovy / 360.0f * PI ) * nearZ; frustumW = frustumH * aspect; esFrustum( result, -frustumW, frustumW, -frustumH, frustumH, nearZ, farZ ); } void esFrustum(ESMatrix *result, float left, float right, float bottom, float top, float nearZ, float farZ) { float deltaX = right - left; float deltaY = top - bottom; float deltaZ = farZ - nearZ; ESMatrix frust; if ( (nearZ <= 0.0f) || (farZ <= 0.0f) || (deltaX <= 0.0f) || (deltaY <= 0.0f) || (deltaZ <= 0.0f) ) return; frust.m[0][0] = 2.0f * nearZ / deltaX; frust.m[0][1] = frust.m[0][2] = frust.m[0][3] = 0.0f; frust.m[1][1] = 2.0f * nearZ / deltaY; frust.m[1][0] = frust.m[1][2] = frust.m[1][3] = 0.0f; frust.m[2][0] = (right + left) / deltaX; frust.m[2][1] = (top + bottom) / deltaY; frust.m[2][2] = -(nearZ + farZ) / deltaZ; frust.m[2][3] = -1.0f; frust.m[3][2] = -2.0f * nearZ * farZ / deltaZ; frust.m[3][0] = frust.m[3][1] = frust.m[3][3] = 0.0f; esMatrixMultiply(result, &frust, result); } My projection matrix comes out as: [3.21, 0, 0, 0] [0, 2.41, 0, 0] [0, 0, -1, -1] [0, 0, -2, 0] Even if I manually set the [3][3] cell to 1 I still don't see anything. Any ideas?

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  • Random directions, with no repeat.. (Bad Description)

    - by Neurofluxation
    Hey there, So I'm knocking together a random pattern generation thing. My code so far: int permutes = 100; int y = 31; int x = 63; while (permutes > 0) { int rndTurn = random(1, 4); if (rndTurn == 1) { y = y - 1; } //go up if (rndTurn == 2) { y = y + 1; } //go down if (rndTurn == 3) { x = x - 1; } //go right if (rndTurn == 4) { x = x + 1; } //go left setP(x, y, 1); delay(250); } My question is, how would I go about getting the code to not go back on itself? e.g. The code says "Go Left" but the next loop through it says "Go Right", how can I stop this? NOTE: setP turns a specific pixel on. Cheers peoples!

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  • Binary Tree operator overloading and recursion

    - by furious.snail
    I was wondering how to overload the == operator for a binary tree to compare if two trees have identical data at same nodes. So far this is what I have: bool TreeType::operator==(const TreeType& otherTree) const { if((root == NULL) && (otherTree.root == NULL)) return true; //two null trees are equal else if((root != NULL) && (otherTree.root != NULL)) { return((root-info == otherTree.root-info) && //this part doesn't actually do anything recursively... //(root-left == otherTree.root-left) && //(root-right == otherTree.root-right)) } else return false; //one tree is null the other is not } I have a similar function that takes two TreeNode pointers as parameters but I've been stuck on how to convert it to this function.

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  • CSS float column extending over footer

    - by JD
    Hi, I am having a problem with my CSS whereby the right hand column in a 2 column layout is extending beyond the footer. I have tried playing with the clear: both; property but I cannot get it to work.. the second column has the id column2 both columns use the class column. The footer html has the id footerWrapper Both columns and footer are div tags. My CSS (abridged): .column { width: 49%; } #column2 { width: 50%; position: absolute; top: 0px; margin-left: 50%; float: left; } #footerWrapper { background-color: #333333; border-top: 2px #FF6600 solid; color: #666; }

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  • Optimize MySQL query (ngrams, COUNT(), GROUP BY, ORDER BY)

    - by Gerardo
    I have a database with thousands of companies and their locations. I have implemented n-grams to optimize search. I am making one query to retrieve all the companies that match with the search query and another one to get a list with their locations and the number of companies in each location. The query I am trying to optimize is the latter. Maybe the problem is this: Every company ('anunciante') has a field ('estado') to make logical deletes. So, if 'estado' equals 1, the company should be retrieved. When I run the EXPLAIN command, it shows that it goes through almost 40k rows, when the actual result (the reality matching companies) are 80. How can I optimize this? This is my query (XXX represent the n-grams for the search query): SELECT provincias.provincia AS provincia, provincias.id, COUNT(*) AS cantidad FROM anunciantes JOIN anunciante_invertido AS a_i0 ON anunciantes.id = a_i0.id_anunciante JOIN indice_invertido AS indice0 ON a_i0.id_invertido = indice0.id LEFT OUTER JOIN domicilios ON anunciantes.id = domicilios.id_anunciante LEFT OUTER JOIN localidades ON domicilios.id_localidad = localidades.id LEFT OUTER JOIN provincias ON provincias.id = localidades.id_provincia WHERE anunciantes.estado = 1 AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') GROUP BY provincias.id ORDER BY cantidad DESC And this is the query explained (hope it can be read in this format): id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY anunciantes ref PRIMARY,estado estado 1 const 36669 Using index; Using temporary; Using filesort 1 PRIMARY domicilios ref id_anunciante id_anunciante 4 db84771_viaempresas.anunciantes.id 1 1 PRIMARY localidades eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.domicilios.id_localidad 1 1 PRIMARY provincias eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.localidades.id_provincia 1 1 PRIMARY a_i0 ref PRIMARY,id_anunciante,id_invertido PRIMARY 4 db84771_viaempresas.anunciantes.id 1 Using where; Using index 1 PRIMARY indice0 eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.a_i0.id_invertido 1 Using index 6 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 6 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 5 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 5 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 4 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 4 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 3 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 3 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 2 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 2 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index

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  • SQL Server: query database user roles for all databases in server

    - by atricapilla
    I would like to make a query for database user roles for all databases in my sql server instance. I modified a query from sp_helpuser: select u.name ,case when (r.principal_id is null) then 'public' else r.name end ,l.default_database_name ,u.default_schema_name ,u.principal_id from sys.database_principals u left join (sys.database_role_members m join sys.database_principals r on m.role_principal_id = r.principal_id) on m.member_principal_id = u.principal_id left join sys.server_principals l on u.sid = l.sid where u.type <> 'R' How can I modify this to query from all databases? What is the link between sys.databases and sys.database_principals?

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  • Measure width() with jQuery after DOM refresh

    - by o_O Tync
    My script dynamically creates a <ul> width left-floating <li>s inside: it's a paginator. Afterwards, the script measures width of all <li>s and summs them up. The problem is that after the nodes are injected into the document — the browser refreshed DOM and applies CSS styles which takes a while. It has a negative effect on my script: when these operations are not complete before I measure the width — my script gets a wrong value. If I perform the measure in a second — everything is ok. The thing I'm looking for is a way to detect the moment when the <ul> is fully drawn, styles applied and the width has stabilizes. Or at least a way to detect every dimensions changes. Of course I can use setTimeout(..., 100) but it's ugly and I guess — not a solution at all. If there's a way to detect width stabilization — I would do the measuring right after it to get the correct values. HTML code generated by the DOM <div> <ul> <li><a href="...">1</a></li> <li><a href="...">2</a></li> .... </ul> </div> P.S. Why I need this. My paginator's left-floating <li> items tend to move to the next line when the <ul> tries to become wider than the page itself. Even though most of <li>s are invisible because of parent <div>'s width restriction: div { width: 500px; overflow: hidden; } div ul { width: 100%; white-space: nowrap; } div ul li { display: block; float: left; } they still go down unless I specify the actual summed width of the <ul> with the script.

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  • Cannot position Google +1 button with CSS?

    - by Bogdan Protsenko
    I'm having some trouble positioning the Google +1 button on my website. The div is as follows: <div class="g-plusone"></div> The CSS I'm using is pretty simple: .g-plusone { position: absolute; top:95px; left:715px; } I know for a fact that the div in question is being accessed. What's strange is that other social sharing buttons, such as the FB like below follow the same syntax and are positioned perfectly. .fb-like { position: absolute; top:62px; left:715px; } Any ideas?

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • how to drag a 'div' element to the google maps ,that be changed to a 'marker'..use jquery

    - by zjm1126
    this is my code : <!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width,minimum-scale=1.0,maximum-scale=1.0,user-scalable=no"> </head> <body onload="initialize()" onunload="GUnload()"> <style type="text/css"> </style> <div id="map_canvas" style="width: 500px; height: 300px;float:left;"></div> <div id=b style="width: 50px; height: 50px;background:red;float:left;margin-left:300px;"></div> <script src="jquery-1.4.2.js" type="text/javascript"></script> <script src="jquery-ui-1.8rc3.custom.min.js" type="text/javascript"></script> <script src="http://ditu.google.cn/maps?file=api&amp;v=2&amp;key=ABQIAAAA-7cuV3vqp7w6zUNiN_F4uBRi_j0U6kJrkFvY4-OX2XYmEAa76BSNz0ifabgugotzJgrxyodPDmheRA&sensor=false"type="text/javascript"></script> <script type="text/javascript"> //********** function initialize() { if (GBrowserIsCompatible()) { // function createMarker(point, number) { var marker = new GMarker(point); var message = ["?","?","?","??","??"]; marker.value = number; GEvent.addListener(marker, "click", function() { var myHtml = "<b>#" + number + "</b><br/>" + message[number -1]; map.openInfoWindowHtml(point, myHtml); }); return marker; } // var map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(39.9493, 116.3975), 13); // Add 5 markers to the map at random locations var bounds = map.getBounds(); var southWest = bounds.getSouthWest(); var northEast = bounds.getNorthEast(); var lngSpan = northEast.lng() - southWest.lng(); var latSpan = northEast.lat() - southWest.lat(); for (var i = 0; i < 5; i++) { var point = new GLatLng(southWest.lat() + latSpan * Math.random(), southWest.lng() + lngSpan * Math.random()); map.addOverlay(createMarker(point, i + 1)); } } } //************* $("#b").draggable(); </script> </body> </html>

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  • Query joining in sql server 2005

    - by Domnic
    I have two queries like: SELECT PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO ACCOUNT, COUNT(PC_CHEQUE_NO) CHQS, SUM(CONVERT(FLOAT, PC_AMOUNT)) CHQ_AMT FROM GLAS_PDC_CHEQUES WHERE PC_COMP_CODE = '1' AND PC_DISCD IS NULL GROUP BY PC_SL_LDGR_CODE, PC_SL_ACNO ,PC_COMP_CODE ORDER BY PC_SL_ACNO -------------------------------------------------- SELECT COAD_PTY_FULL_NAME,PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO, PC_DEPT_NO, PC_DOC_TYPE, PC_CHEQUE_NO, PC_BANK_AC_NO FROM GLAS_PTY_ADDRESS,GLAS_SBLGR_MASTERS,GLAS_PDC_CHEQUES WHERE COAD_COMP_CODE = '1' AND SLMA_COMP_CODE = COAD_COMP_CODE AND SLMA_ADDR_ID = COAD_ADDR_ID AND SLMA_LDGRCTL_CODE = PC_SL_LDGR_CODE AND PC_COMP_CODE=SLMA_COMP_CODE AND SLMA_ACNO = PC_SL_ACNO AND SLMA_LDGRCTL_YEAR = DBO.GLAS_VALIDATIONS_GET_OPEN_YEAR(PC_COMP_CODE) If I execute first query alone I get 5 records... If I join the above two query like: SELECT PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO ACCOUNT, COUNT(PC_CHEQUE_NO) CHQS, SUM(CONVERT(FLOAT, PC_AMOUNT)) CHQ_AMT, COAD_PTY_FULL_NAME FROM GLAS_PDC_CHEQUES LEFT OUTER JOIN GLAS_SBLGR_MASTERS ON( SLMA_COMP_CODE=PC_COMP_CODE AND SLMA_LDGRCTL_CODE = PC_SL_LDGR_CODE AND SLMA_ACNO = PC_SL_ACNO ) LEFT OUTER JOIN GLAS_PTY_ADDRESS ON( SLMA_COMP_CODE = COAD_COMP_CODE AND SLMA_ADDR_ID = COAD_ADDR_ID) WHERE PC_COMP_CODE = '1' AND PC_DISCD IS NULL AND SLMA_LDGRCTL_YEAR = DBO.GLAS_VALIDATIONS_GET_OPEN_YEAR(PC_COMP_CODE) GROUP BY PC_SL_LDGR_CODE, PC_SL_ACNO ,PC_COMP_CODE,COAD_PTY_FULL_NAME ORDER BY PC_SL_ACNO then I just get 2 records.... I need that 5 records to display after join..... How can I do it?

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  • Font-awesome, input type 'submit'

    - by denis.peplin
    It seems no class for input type 'submit' in font-awesome. Is it possible to use some class from font-awesome for button input? I've added icons to all buttons (which actually links with class 'btn' from twitter-bootstrap) in my applications, but can't add icons on 'input type submit'. Or, how to use this code: input#image-button{ background: #ccc url('icon.png') no-repeat top left; padding-left: 16px; height: 16px; } html: <input type="submit" id="image-button">Text</input> (which I took from HTML: How to make a submit button with text + image in it?) with font-awesome?

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  • Class not overwriting with addClass

    - by scatteredbomb
    I'm using jQuery's addClass to add a class to an tab so when clicked it'll change the class so it's obvious the tab is highlighted. My HTML <div id="mainNav"> <ul> <li id="LinktheBand" onclick="nav('theBand')">The Band</li> <li id="linkTheMusic" onclick="nav('theMusic')">The Music</li> My CSS #mainNav li { float:left; margin-right:5px; color:white; font-family:Tahoma; font-weight:bold; padding: 10px 8px 0px 8px; background:url('../images/transparent-65.png'); height:40px; height: 25px !important; border:1px solid #000; } #mainNav li:hover { float:left; margin-right:5px; color:white; font-family:Tahoma; font-weight:bold; padding: 10px 8px 0px 8px; background: #660000; height:40px; height: 25px !important; border:1px solid #660000; } .mainNavSelected { float:left; margin-right:5px; color:white; font-family:Tahoma; font-weight:bold; padding: 10px 8px 0px 8px; background: #660000; height:40px; height: 25px !important; border:1px solid #660000; } My Javascript function nav(a) { $('#'+a).show(); $('#Link'+a).addClass('mainNavSelected'); } This works properly, I check firebug and can see the class="mainNavSelected" is added, but the list element doesn't take any properties of the new class. Firebug lists all the class items for mainNavSelected, but has them all crossed out. What am i missing to replace the class of this element?

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  • Scroll to a text position in Javascript

    - by Andy
    I have a real-time HTML editor, with a textarea on the left for code entry, and a 'preview' DIV on the right to contain the preview of the code entered. At the moment, when editing the code in the left pane, the preview just sits where it is, so often the part of the code you're editing is not in the visible area of the preview (especially when images are involved). My question is how do I make the preview scroll to show the part of the code that's currently being edited? Here is the page I have so far: http://www.caerphoto.com/rtedit.html You'll notice in the source I have a (currently unused) matchPreview() function that tries to match the scroll position of the preview based on the scroll position of the textarea, but obviously if images or large text are involved the two panes no longer match.

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  • Removing elements from heap

    - by user193138
    I made a heap. I am curious if there's something subtley wrong with my remove function: int Heap::remove() { if (n == 0) exit(1); int temp = arr[0]; arr[0] = arr[--n]; heapDown(0); arr[n] = 0; return temp; } void Heap::heapDown(int i) { int l = left(i); int r = right(i); // comparing parent to left/right child // each has an inner if to handle if the first swap causes a second swap // ie 1 -> 3 -> 5 // 3 5 1 5 1 3 if (l < n && arr[i] < arr[l]) { swap(arr[i], arr[l]); heapDown(l); if (r < n && arr[i] < arr[r]) { swap(arr[i], arr[r]); heapDown(r); } } else if (r < n && arr[i] < arr[r]) { swap(arr[i], arr[r]); heapDown(r); if (l < n && arr[i] < arr[l]) { swap(arr[i], arr[l]); heapDown(l); } } } Here's my output i1i2i3i4i5i6i7 p Active heap: 7 4 6 1 3 2 5 r Removed 7 r Removed 6 p Active heap: 5 3 4 1 2 Here's my teacher's sample output: p Active heap : 7 4 6 1 3 2 5 r Removed 7 r Removed 6 p Active heap : 5 4 2 1 3 s Heapsorted : 1 2 3 4 5 While our outputs are completely different, I do seem to hold maxheap principle of having everything left oriented and for all nodes parent child(in every case I tried). I try to do algs like this from scratch, so maybe I'm just doing something really weird and wrong (I would only consider it "wrong" if it's O(lg n), as removes are intended to be for heaps). Is there anything in particular "wrong" about my remove? Thanks, http://ideone.com/PPh4eQ

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  • Using jQuery's animate(), if the clicked on element is "<a href="#" ...> </a>", the fucntion should

    - by Jian Lin
    I was reading jQuery's page for animate() http://api.jquery.com/animate/ Its examples don't mention about if using <a href="#" id="clickme">click me</a> ... $('#clickme').click(function() { $('#someDiv').animate({left: "+=60"}); }) we actually still have to return false like in the old days? $('#clickme').click(function() { $('#someDiv').animate({left: "+=60"}); return false; }) (but then, those examples didn't use a <a> for the "click me"... but used something else. Otherwise the page will jump back to the beginning of the page? Does jQuery have a more elegant or magical way of doing it?

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  • jQuery appendTo (switching back and forth)

    - by Starboy
    So what I'm trying to accomplish is a simple appendTo a certain element. The issue I'm having is after execute is run, it appends to the location but then proceed to go back to the ul it resides in. <script type="text/javascript"> function execute() { $('#desCopy').appendTo('#description') $('#imgPlace').appendTo('#IMGbox') } </script> <div id="content" style="background:#000; width:989px;"> <div style="float:left; left:18px; margin:0; width:337px; position:relative; padding:15px 0 0 0; color:#FFF;"> <div id="description"> </div> </div> <div id="IMGbox" style="float:left; position:relative; display:block; background:#F00; width:652px; height:258px; background:#0FF; overflow:hidden;"> </div> <div style="float:right; background:#CCC; height:25px; width:652px;"> <ul> <li><a href="" onclick="execute()">Slide 1</a> <ul style=""> <li><span id="desCopy">Test description, Test description</span></li> <li><img src="images/test.jpg" id="imgPlace"></li> </ul> </li> </ul> </div> </div>

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  • CSS background image ?

    - by BillyD
    I have a div that is 200px by 200px. If I want to place a 30x30px no-repeat background image at the top left corner position of 120px from the left and 50px from the top ... while also allowing the text inside that div to be displayed on top of the background image ... how would I do that? I tried the following, but it doesnt appear to work. background:url(http://example.com/background-image.png) no-repeat 120px 50px; Any ideas how to perform what I want to accomplish?

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  • It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then sa

    - by Jian Lin
    It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then satisfying some condition(s)? Because the equi-join can be obvious, but the non-equi-join can be a bit confusing. But if we always use the Cross Join, and then filter out the ones satisfying the condition, then we get the resulting table. In other words, we can always analyze it by using the first record on the left table, and then go through every single records on the right, and then repeat that for 2nd record on the left, and for the 3rd, 4th, ... etc. So in our mind, we can analyze it using this way, and it is like O(n^2), although what happens in the DBMS maybe that it is a lot faster (when an index is present). Is there another good way to think of it besides this method?

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  • Extract images link from html text string

    - by Jaj
    I want to extract all images link to so I can utilize all images freely. how to do in asp.net c# <div> <img src="/upload/Tom_Cruise-242x300.jpg" alt="Tom_Cruise-242x300.jpg" align="left" border="0" height="300" width="242"> sample text sample text sample text sample text <img src="http://www.sharicons.com/images/rss_icon.jpg" alt="Icon" align="left" border="0" height="100" width="100"> sample text sample text sample text sample text sample text sample text sample text sample text</div>

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  • Making a window pop in and out of the edge of the screen

    - by Brad
    I'm trying to re-write an application I have for Windows in Objective-C for my Mac, and I want to be able to do something like Mac's hot corners. If I move my mouse to the left side of the screen it will make a window visible, if I move it outside of the window location the window will hide again. (window would be pushed up to the left side of screen). Does anyone know where I can find some demo code (or reference) on how to do this, or at least how to tell where the mouse is at, even if the current application is not on top. (not sure how to word this, too used to Windows world). Thank you -Brad

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