Search Results

Search found 63884 results on 2556 pages for 'mysql error 1064'.

Page 120/2556 | < Previous Page | 116 117 118 119 120 121 122 123 124 125 126 127  | Next Page >

  • error in mysql syntax

    - by fusion
    while executing the following query, i get an error that there's an error in the syntax near line 9. since i'm using mysql workbench, i can't really figure out what could be wrong: CREATE TABLE IF NOT EXISTS `proquotes`.`thquotes` ( `idQuotes` INT NOT NULL AUTO_INCREMENT , `vAuthorID` VARCHAR(8) CHARACTER SET 'utf8' NOT NULL , `vAuthor` VARCHAR(45) CHARACTER SET 'utf8' NOT NULL , `cQuotes` MEDIUMTEXT CHARACTER SET 'utf8' NOT NULL , `cArabic` MEDIUMTEXT CHARACTER SET 'utf8' NOT NULL , `vReference` VARCHAR(100) CHARACTER SET 'utf8' NOT NULL , PRIMARY KEY (`idQuotes`) , INDEX `vAuthorID` () , CONSTRAINT `vAuthorID` FOREIGN KEY () REFERENCES `proquotes`.`author_info` () ON DELETE NO ACTION ON UPDATE NO ACTION) DEFAULT CHARACTER SET = utf8;

    Read the article

  • Connect MySQL database from Android

    - by Mistry Hardik
    hello people! well this is the code snippet i use to access the getUser.php to retrive user details from a MySQL database in my application: String result = ""; //the year data to send ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("uid","demo")); //http post try{ HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://192.xxx.xx.xxx/getUser.php"); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); InputStream is = entity.getContent(); }catch(Exception e){ Log.e("log_tag", "Error in http connection "+e.toString()); } //convert response to string try{ InputStream is = null; BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); result=sb.toString(); }catch(Exception e){ Log.e("log_tag", "Error converting result "+e.toString()); } //parse json data try{ JSONArray jArray = new JSONArray(result); for(int i=0;i<jArray.length();i++){ JSONObject json_data = jArray.getJSONObject(i); Log.i("log_tag","id: "+json_data.getInt("id")+ ", name: "+json_data.getString("fname")+ ", sex: "+json_data.getInt("sex")+ ", birthyear: "+json_data.getInt("dob") ); } } catch(JSONException e){ Log.e("log_tag", "Error parsing data "+e.toString()); } } This snippet is taken from http://helloandroid.com Everything is configured fine: the MySQL Db, IIS with FASTCGi, PHP tools and drivers. even the script below when called from browser with url: http://192.xxx.xx.x.xxx/getUser.php?uid=demo works fine, But returns error in android with java.lang.NullPointerException and org.json.JSONEXCEPTION: End of input at character 0 <?php mysql_connect("myhost","username","pwd"); mysql_select_db("mydb"); $q=mysql_query("SELECT * FROM userinfo WHERE uid ='".$_REQUEST['uid']."'"); while($e=mysql_fetch_assoc($q)) $output[]=$e; print(json_encode($output)); mysql_close(); ?> Can anybody help in this section? Regards, Mistry Hardik

    Read the article

  • Mysql::Error: Duplicate entry

    - by Shaliko
    Hi I have a model class Gift < ActiveRecord::Base validates_uniqueness_of :giver_id, :scope => :account_id end add_index(:gifts, [:account_id, :giver_id], :uniq => true) Action def create @gift= Gift.new(params[:gift]) if @gift.save ... else ... end end In the "production" mode, I sometimes get an error ActiveRecord::StatementInvalid: Mysql::Error: Duplicate entry '122394471958-50301499' for key 'index_gifts_on_account_id_and_user_id' What the problem?

    Read the article

  • Problem with ColdFusion communicating with MySQL database

    - by Greg
    Hi, I have been working to migrate a non-profit website from a local server (running Windows XP) to a GoDaddy hosting account (running Linux). Most of the pages are written in ColdFusion. Things have gone smoothly, up until this point. There is a flash form within the site (see this page: http://www.preservenet.cornell.edu/employ/submitjob.cfm) which, when completed, takes the visitor to this page: submitjobaction.cfm . I'm not quite sure what to make of this error, since I copied exactly what had been in the old MySQL database, and the .cfm files are exactly as they had been when they worked on the old server. Am I missing something? Below is the code from the database that the error seems to be referring to. When I change "Positionlat" to some default value in the database as it suggests in the error, it says that another field needs a default value, and it's a neverending chain of errors as I try to correct it. This is probably a stupid error that I'm missing, but I've been working at it for days and can't find what I'm missing. I would really appreciate any help. Thanks! -Greg DROP TABLE IF EXISTS employopp; CREATE TABLE employopp ( POSTID int(10) NOT NULL auto_increment, USERID varchar(10) collate latin1_general_ci default NULL, STATUS varchar(10) collate latin1_general_ci NOT NULL default 'ACTIVE', TYPE varchar(50) collate latin1_general_ci default 'professional', JOBTITLE varchar(70) collate latin1_general_ci default NULL, NUMBER varchar(30) collate latin1_general_ci default NULL, SALARY varchar(40) collate latin1_general_ci default NULL, ORGNAME varchar(70) collate latin1_general_ci default NULL, DEPTNAME varchar(70) collate latin1_general_ci default NULL, ORGDETAILS mediumtext character set utf8 collate utf8_unicode_ci, ORGWEBSITE varchar(200) collate latin1_general_ci default NULL, ADDRESS varchar(60) collate latin1_general_ci default 'none given', ADDRESS2 varchar(60) collate latin1_general_ci default NULL, CITY varchar(30) collate latin1_general_ci default NULL, STATE varchar(30) collate latin1_general_ci default NULL, COUNTRY varchar(3) collate latin1_general_ci default 'USA', POSTALCODE varchar(10) collate latin1_general_ci default NULL, EMAIL varchar(75) collate latin1_general_ci default NULL, NOMAIL varchar(5) collate latin1_general_ci default NULL, PHONE varchar(20) collate latin1_general_ci default NULL, FAX varchar(20) collate latin1_general_ci default NULL, WEBSITE varchar(200) collate latin1_general_ci default NULL, POSTDATE varchar(10) collate latin1_general_ci default NULL, POSTUNTIL varchar(20) collate latin1_general_ci default 'select date', POSTUNTILFILLED varchar(20) collate latin1_general_ci NOT NULL default 'until filled', texteHTML mediumtext character set utf8 collate utf8_unicode_ci, HOWTOAPPLY mediumtext character set utf8 collate utf8_unicode_ci, CONFIRSTNM varchar(30) collate latin1_general_ci default NULL, CONLASTNM varchar(60) collate latin1_general_ci default NULL, POSITIONCITY varchar(30) collate latin1_general_ci default NULL, POSITIONSTATE varchar(30) collate latin1_general_ci default NULL, POSITIONCOUNTRY varchar(3) collate latin1_general_ci default 'USA', POSITIONLAT varchar(50) collate latin1_general_ci NOT NULL, POSITIONLNG varchar(50) collate latin1_general_ci NOT NULL, PRIMARY KEY (POSTID) ) ENGINE=MyISAM AUTO_INCREMENT=2007 DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;

    Read the article

  • NHibernate mapping in Asp.Net using MySql

    - by Siva
    Hi, I'm new to NHibernate. Actually I'm trying to save the values ffrom two text boxes into MySql Database in asp.Net page. I that I got "Resource not found: WebApplication1.Sample.hbm.xml" error. But I can't fix this error. Can anyone help me to fix this one?

    Read the article

  • Selecting a column that is also a keyword in MySQL

    - by randall123
    For some reason, the developers at a new company I'm working for decided to name their columns "ignore" and "exists". Now when I run MySQL queries with those words in the where clause, I get a syntax error; however, I can't seem to figure out how to reference those columns without running into an error. I tried setting them as strings, but that doesn't make any sense. Help? Also, is there a term for this kind of mismatch?

    Read the article

  • mysql multiple insert - what happens on error?

    - by aviv
    What happens in mysql multiple records insert during an error. I have a table: id | value 2 | 100 UNIQUE(id) Now i try to execute the query: INSERT INTO table(id, value) VALUES (1,10),(2,20),(3,30) I will get a duplicate-key error for the (2,20) BUT... Will the (1,10) get into the database? Will the (3,30) get into the database?

    Read the article

  • mysql error #1452 appearing when trying to add a constraint

    - by user1701484
    I am trying to alter a table so That I can add a foreign key constraint in mysql database: ALTER TABLE `Question` ADD CONSTRAINT `FK_question` FOREIGN KEY (`QuestionId`) REFERENCES `Image_Question` (`QuestionId`) ON DELETE CASCADE ; Problem is that it is giving me this error: 1452 - Cannot add or update a child row: a foreign key constraint fails (mobile_app. '#sql-4517_15241', CONSTRAINT FK_question FOREIGN KEY (QuestionId) REFERENCES Image_Question (QuestionId) ON DELETE CASCADE) What does this error actually mean and what are the possible solutions I might have to undertake in order to fix this?

    Read the article

  • Beginner MYSQL Error - Access Denied

    - by WANNABE
    ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: N O) I've tried EVERYTHING, I've read through pages of answers and no-one seems to know the right one. When i try to log into my DB i just get the above error, I havent set a password or anything. Can't log into MySQL at all now, don't understand. Thanks for your help in advance

    Read the article

  • MYSQL LIMIT not working as expected - Java

    - by Sirish
    I have this weird problem in java when trying to fetch records from MYSql database by using the limit function in the query. Not sure what went wrong or did wrong, this query is giving me a hard time. Issue - When I run this query through my java program it returns all the records and not limiting the records to 10 as given in the limit. The same query when ran in MYSql command line, it execute very well and fetches me only 10 recrods. Below is the java code and query. Any help or support is appreciated.! Java code - public UserVO getApplUserDetailsList(UserVO userVO) throws CAPDAOException { List<UserVO> returnList = null; String methodName = "getApplUserDetails()"; Session session = null; String queryString = null; Transaction transaction = null; PreparedStatement ps = null; ResultSet rs = null; if(userVO == null) { logger.writeToTivoliAlertLog(className, CAPConstants.ERROR, methodName, null, "userVO returned null. Busines validation error.!", null); throw new CAPDAOException("userVO returned null. Busines validation error.!",CAPException.BUSINESS_VALIDATION_ERROR_SECURITY); } try { returnList = new ArrayList<UserVO>(); System.out.println(""); String appusr = userVO.getAppUsrNm(); session = getSession(); transaction = session.beginTransaction(); if(userVO.getAppUsrRoleCd()!=null && !userVO.getAppUsrRoleCd().trim().equalsIgnoreCase(CAPConstants.DEFAULT_DROPDOWN_VALUE)){ queryString = "SELECT " + "APPL_USR_ID,APPL_USR_NM,APPL_USR_FRST_NM, " + "APPL_USR_LST_NM,ACCESS_ROLE_CD " + "FROM APPL_USR " + "WHERE " + "APPL_USR_NM LIKE ?"+ " AND APPL_USR_FRST_NM LIKE ?"+ " AND APPL_USR_LST_NM LIKE ?"+ " AND ACCESS_ROLE_CD = ?"+ " AND APPL_USR_ID != ?"; ps = session.connection().prepareStatement(queryString); ps.setString(1,userVO.getAppUsrNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(2,userVO.getAppUsrFirstNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(3,userVO.getAppUsrLastNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(4,userVO.getAppUsrRoleCd()); ps.setInt(5, 1); } else { queryString = "SELECT " + "APPL_USR_ID,APPL_USR_NM,APPL_USR_FRST_NM, " + "APPL_USR_LST_NM,ACCESS_ROLE_CD " + "FROM APPL_USR " + "WHERE " + "APPL_USR_NM LIKE ?"+ " AND APPL_USR_FRST_NM LIKE ?"+ " AND APPL_USR_LST_NM LIKE ?"+ " AND APPL_USR_ID != ?"; ps = session.connection().prepareStatement(queryString); ps.setString(1,userVO.getAppUsrNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(2,userVO.getAppUsrFirstNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setString(3,userVO.getAppUsrLastNm()+CAPConstants.PERCENTILE_SYMBOL); ps.setInt(4, 1); } if(userVO.getQueryAction()!=null && userVO.getQueryAction().equals(CAPConstants.GET_DATA)) queryString += " ORDER BY APPL_USR_ID LIMIT " + userVO.getPAGE_MIN_LIMIT() + ", " + userVO.getPAGE_MAX_LIMIT(); else queryString += " ORDER BY APPL_USR_ID"; rs = ps.executeQuery(); if(userVO.getQueryAction()!=null && userVO.getQueryAction().equals(CAPConstants.GET_DATA)) { int tempCOunt = 0; while(rs!=null && rs.next()) { tempCOunt ++; UserVO returnVO = new UserVO(); returnVO.setAppUsrId(rs.getInt("APPL_USR_ID")); returnVO.setAppUsrNm(rs.getString("APPL_USR_NM")); returnVO.setAppUsrFirstNm(rs.getString("APPL_USR_FRST_NM")); returnVO.setAppUsrLastNm(rs.getString("APPL_USR_LST_NM")); if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.ADMINISTRATOR_ROLE_CD)) returnVO.setApplicationLevelRole("Administrator"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.MAINTAINER_ROLE_CD)) returnVO.setApplicationLevelRole("Maintainer"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.VIEWER_ROLE_CD)) returnVO.setApplicationLevelRole("Viewer"); else returnVO.setApplicationLevelRole("None"); returnList.add(returnVO); } System.out.println("Count >>>>>>>>>>>>>>>>>>> "+tempCOunt); userVO.setReturnListFromDB(returnList); } else { int rowcount = 0; if (rs.last()) { rowcount = rs.getRow(); rs.beforeFirst(); // not rs.first() because the rs.next() below will move on, missing the first element } userVO.setTotalRecordCount(rowcount); System.out.println("Total count of the records to be used for pagination >> "+rowcount); rowcount = 0; while(rs!=null && rs.next()) { rowcount ++; UserVO returnVO = new UserVO(); returnVO.setAppUsrId(rs.getInt("APPL_USR_ID")); returnVO.setAppUsrNm(rs.getString("APPL_USR_NM")); returnVO.setAppUsrFirstNm(rs.getString("APPL_USR_FRST_NM")); returnVO.setAppUsrLastNm(rs.getString("APPL_USR_LST_NM")); if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.ADMINISTRATOR_ROLE_CD)) returnVO.setApplicationLevelRole("Administrator"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.MAINTAINER_ROLE_CD)) returnVO.setApplicationLevelRole("Maintainer"); else if (rs.getString("ACCESS_ROLE_CD")!=null && rs.getString("ACCESS_ROLE_CD").trim().equalsIgnoreCase(CAPConstants.VIEWER_ROLE_CD)) returnVO.setApplicationLevelRole("Viewer"); else returnVO.setApplicationLevelRole("None"); returnList.add(returnVO); System.out.println("Row count >>"+rowcount); if(rowcount == CAPConstants.PAGINATION_MAX_VALUE) break; } rowcount = 0; userVO.setReturnListFromDB(returnList); } System.out.println("returnList >>"+returnList); return userVO; } catch (Throwable e) { e.printStackTrace(); logger.writeToTivoliAlertLog(className, CAPConstants.ERROR, methodName, userVO.getAppUsrNm(), "Error occured while trying to fetch application user details. Printing stack trace to the log for analysis..", e); throw new CAPDAOException("Error occured while trying to fetch application user details.",CAPException.SPEXECUTION_ERROR_CODE); } finally{ closeTransactionAndSession(session,transaction); } } MYSQL Query - SELECT APPL_USR_ID,APPL_USR_NM,APPL_USR_FRST_NM, APPL_USR_LST_NM,ACCESS_ROLE_CD FROM APPL_USR WHERE APPL_USR_NM LIKE '%' AND APPL_USR_FRST_NM LIKE '%' AND APPL_USR_LST_NM LIKE '%' AND APPL_USR_ID != 1 ORDER BY APPL_USR_ID LIMIT 10, 10

    Read the article

  • Connect to MySQL in Ruby using NetBeans

    - by Varun
    I've downloaded the "dbd-mysql-0.4.4.zip" and linked it to my project. While I try to run a demo code from NetBeans the very first line require "dbi" gives me an error. Is there a different way to do it? I also tried jruby setup.rb config --with=dbi,dbd_mysql from the command prompt and it gave me the following error: config: unknown option --with=dbi,dbd_mysql Try 'ruby setup.rb --help' for detailed usage. Any suggestions please?

    Read the article

  • Creating temporary tables in MySQL Stored Procedure

    - by burntblark
    The following procedure gives me an error when I invoke it using the CALL statement: CREATE DEFINER=`user`@`localhost` PROCEDURE `emp_performance`(id VARCHAR(10)) BEGIN DROP TABLE IF EXISTS performance; CREATE TABLE performance AS SELECT time_in, time_out, day FROM attendance WHERE employee_id = id; END The error says "Unknown table 'performance' ". This is my first time actually using stored procedures and I got my sources from Google. I just cant figure out what I am doing wrong.

    Read the article

  • Is this possible to join tables in doctrine ORM without using relations?

    - by piemesons
    Suppose there are two tables. Table X-- Columns: id x_value Table Y-- Columns: id x_id y_value Now I dont want to define relationship in doctrine classes and i want to retrieve some records using these two tables using a query like this: Select x_value from x, y where y.id="variable_z" and x.id=y.x_id; I m not able to figure out how to write query like this in doctrine orm EDIT: Table structures: Table 1: CREATE TABLE IF NOT EXISTS `image` ( `id` int(11) NOT NULL AUTO_INCREMENT, `random_name` varchar(255) NOT NULL, `user_id` int(11) NOT NULL, `community_id` int(11) NOT NULL, `published` varchar(1) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=259 ; Table 2: CREATE TABLE IF NOT EXISTS `users` ( `id` int(11) NOT NULL AUTO_INCREMENT, `city` varchar(20) DEFAULT NULL, `state` varchar(20) DEFAULT NULL, `school` varchar(50) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; Query I am using: $q = new Doctrine_RawSql(); $q ->select('{u.*}, {img.*}') ->from('users u LEFT JOIN image img ON u.id = img.user_id') ->addComponent('u', 'Users u') ->addComponent('img', 'u.Image img') ->where("img.community_id='$community_id' AND img.published='y' AND u.state='$state' AND u.city='$city ->orderBy('img.id DESC') ->limit($count+12) ->execute(); Error I am getting: Fatal error: Uncaught exception 'Doctrine_Exception' with message 'Couldn't find class u' in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php:290 Stack trace: #0 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php(240): Doctrine_Table- >initDefinition() #1 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Connection.php(1127): Doctrine_Table->__construct('u', Object(Doctrine_Connection_Mysql), true) #2 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\RawSql.php(425): Doctrine_Connection- >getTable('u') #3 C:\xampp\htdocs\fanyer\doctrine\models\Image.php(33): Doctrine_RawSql- >addComponent('img', 'u.Image imga') #4 C:\xampp\htdocs\fanyer\community_images.php(31): Image->get_community_images_gallery_filter(4, 0, 'AL', 'ALBERTVILLE') #5 {main} thrown in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php on line 290

    Read the article

  • Need help to debug application using .Net and MySQL

    - by Tim Murphy
    What advice can you give me on how to track down a bug I have while inserting data into MySQL database with .Net? The error message is: MySql.Data.MySqlClient.MySqlException: Duplicate entry '26012' for key 'StockNumber_Number_UNIQUE' Reviewing of the log proves that StockNumber_Number of 26012 has not been inserted yet. Products in use. Visual Studio 2008. mysql.data.dll 6.0.4.0. Windows 7 Ultimate 64 bit and Windows 2003 32 bit. Custom built ORM framework (have source code). Importing data from Access 2003 database. The code works fine for 3000 - 5000 imports. The record being imported that causes the problem in a full run works fine if just importing by itself. I've also seen the error on other records if I sort the data to be imported a different way. Have tried import with and without transactions. Have logged the hell out of the system. The SQL command to create the table: CREATE TABLE `RareItems_RareItems` ( `RareItemKey` CHAR(36) NOT NULL PRIMARY KEY, `StockNumber_Text` VARCHAR(7) NOT NULL, `StockNumber_Number` INT NOT NULL AUTO_INCREMENT, UNIQUE INDEX `StockNumber_Number_UNIQUE` (`StockNumber_Number` ASC), `OurPercentage` NUMERIC , `SellPrice` NUMERIC(19, 2) , `Author` VARCHAR(250) , `CatchWord` VARCHAR(250) , `Title` TEXT , `Publisher` VARCHAR(250) , `InternalNote` VARCHAR(250) , `DateOfPublishing` VARCHAR(250) , `ExternalNote` LONGTEXT , `Description` LONGTEXT , `Scrap` LONGTEXT , `SuppressionKey` CHAR(36) NOT NULL, `TypeKey` CHAR(36) NOT NULL, `CatalogueStatusKey` CHAR(36) NOT NULL, `CatalogueRevisedDate` DATETIME , `CatalogueRevisedByKey` CHAR(36) NOT NULL, `CatalogueToBeRevisedByKey` CHAR(36) NOT NULL, `DontInsure` BIT NOT NULL, `ExtraCosts` NUMERIC(19, 2) , `IsWebReady` BIT NOT NULL, `LocationKey` CHAR(36) NOT NULL, `LanguageKey` CHAR(36) NOT NULL, `CatalogueDescription` VARCHAR(250) , `PlacePublished` VARCHAR(250) , `ToDo` LONGTEXT , `Headline` VARCHAR(250) , `DepartmentKey` CHAR(36) NOT NULL, `Temp1` INT , `Temp2` INT , `Temp3` VARCHAR(250) , `Temp4` VARCHAR(250) , `InternetStatusKey` CHAR(36) NOT NULL, `InternetStatusInfo` LONGTEXT , `PurchaseKey` CHAR(36) NOT NULL, `ConsignmentKey` CHAR(36) , `IsSold` BIT NOT NULL, `RowCreated` DATETIME NOT NULL, `RowModified` DATETIME NOT NULL ); The SQL command and parameters to insert the record: INSERT INTO `RareItems_RareItems` (`RareItemKey`, `StockNumber_Text`, `StockNumber_Number`, `OurPercentage`, `SellPrice`, `Author`, `CatchWord`, `Title`, `Publisher`, `InternalNote`, `DateOfPublishing`, `ExternalNote`, `Description`, `Scrap`, `SuppressionKey`, `TypeKey`, `CatalogueStatusKey`, `CatalogueRevisedDate`, `CatalogueRevisedByKey`, `CatalogueToBeRevisedByKey`, `DontInsure`, `ExtraCosts`, `IsWebReady`, `LocationKey`, `LanguageKey`, `CatalogueDescription`, `PlacePublished`, `ToDo`, `Headline`, `DepartmentKey`, `Temp1`, `Temp2`, `Temp3`, `Temp4`, `InternetStatusKey`, `InternetStatusInfo`, `PurchaseKey`, `ConsignmentKey`, `IsSold`, `RowCreated`, `RowModified`) VALUES (@RareItemKey, @StockNumber_Text, @StockNumber_Number, @OurPercentage, @SellPrice, @Author, @CatchWord, @Title, @Publisher, @InternalNote, @DateOfPublishing, @ExternalNote, @Description, @Scrap, @SuppressionKey, @TypeKey, @CatalogueStatusKey, @CatalogueRevisedDate, @CatalogueRevisedByKey, @CatalogueToBeRevisedByKey, @DontInsure, @ExtraCosts, @IsWebReady, @LocationKey, @LanguageKey, @CatalogueDescription, @PlacePublished, @ToDo, @Headline, @DepartmentKey, @Temp1, @Temp2, @Temp3, @Temp4, @InternetStatusKey, @InternetStatusInfo, @PurchaseKey, @ConsignmentKey, @IsSold, @RowCreated, @RowModified) @RareItemKey = 0b625bd6-776d-43d6-9405-e97159d172a6 @StockNumber_Text = 199305 @StockNumber_Number = 26012 @OurPercentage = 22.5 @SellPrice = 1250 @Author = SPARRMAN, Anders. @CatchWord = COOK: SECOND VOYAGE @Title = A Voyage Round the World with Captain James Cook in H.M.S. Resolution… Introduction and notes by Owen Rutter, wood engravings by Peter Barker-Mill. @Publisher = @InternalNote = @DateOfPublishing = 1944 @ExternalNote = The first English translation of Sparrman’s narrative, which had originally been published in Sweden in 1802-1818, and the only complete version of his account to appear in English. The eighteenth-century translation had appeared some time before the Swedish publication of the final sections of his account. Sparrman’s observant and well-written narrative of the second voyage contains much that appears nowhere else, emphasising naturally his interests in medicine, health, and natural history.&lt;br&gt;&lt;br&gt;One of 350 numbered copies: a handsomely produced and beautifully illustrated work. @Description = Small folio, wood-engravings in the text; original olive glazed cloth, top edges gilt, a very good copy. London, Golden Cockerel Press, 1944. @Scrap = @SuppressionKey = 00000000-0000-0000-0000-000000000000 @TypeKey = 93f58155-7471-46ad-84c5-262ab9dd37e8 @CatalogueStatusKey = 00000000-0000-0000-0000-000000000003 @CatalogueRevisedDate = @CatalogueRevisedByKey = c4f6fc06-956d-44c4-b393-0d5462cbffec @CatalogueToBeRevisedByKey = 00000000-0000-0000-0000-000000000000 @DontInsure = False @ExtraCosts = @IsWebReady = False @LocationKey = 00000000-0000-0000-0000-000000000000 @LanguageKey = 00000000-0000-0000-0000-000000000000 @CatalogueDescription = @PlacePublished = Golden Cockerel Press @ToDo = @Headline = @DepartmentKey = 529578a3-9189-40de-b656-eef9039d00b8 @Temp1 = @Temp2 = @Temp3 = @Temp4 = v @InternetStatusKey = 00000000-0000-0000-0000-000000000000 @InternetStatusInfo = @PurchaseKey = 00000000-0000-0000-0000-000000000000 @ConsignmentKey = @IsSold = True @RowCreated = 8/04/2010 8:49:16 PM @RowModified = 8/04/2010 8:49:16 PM Suggestions on what is causing the error and/or how to track down what is causing the problem?

    Read the article

  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

    Read the article

  • Has anyone ever successfully make index merge work for MySQL?

    - by user198729
    Setup: mysql> create table t(a integer unsigned,b integer unsigned); mysql> insert into t(a,b) values (1,2),(1,3),(2,4); mysql> create index i_t_a on t(a); mysql> create index i_t_b on t(b); mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 3 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Is there something I'm missing? Update mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 1863 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Version: mysql> select version(); +----------------------+ | version() | +----------------------+ | 5.1.36-community-log | +----------------------+ Has anyone ever successfully make index merge work for MySQL? I'll be glad to see successful stories here:)

    Read the article

  • PHP & MySQL database storing the name Array problem.

    - by comma
    I'm new to PHP & MySQL and I keep getting the word Array stored in my MySQL tables fields $skill, $experience, $yearsI was wondering how can I fix this problem? And I know I need to add mysqli_real_escape_string which I left out to make code more easier to read Hopefully. Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; if (isset($_POST['skill'][0]) && trim($_POST['skill'][0])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { for ($s = 0; $s < count($skill); $s++){ for ($x = 0; $x < count($experience); $x++){ for ($g = 0; $g < count($years); $g++){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $s . "', '" . $x . "', '" . $g . "')"); $id = mysqli_insert_id($mysqli); if ($query1 == TRUE) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query2 = mysqli_query($mysqli,"INSERT INTO users_skills (skill_id, user_id) VALUES ('$id', '$user_id')"); } } } } } } } Here is the XHTML code. <li><label for="skill">Skill: </label><input type="text" name="skill[0]" id="skill[0]" /> <label for="experience">Experience: </label> <?php echo '<select id="experience[0]" name="experience[0]">' . "\n"; foreach($experience_options as $option) { if ($option == $experience) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> <label for="years">Years: </label> <?php echo '<select id="years[0]" name="years[0]">' . "\n"; foreach($grade_options as $option) { if ($option == $years) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

    Read the article

  • error executing aapt, all of the sudden

    - by pjv
    I know there are a lot of these topics around but none seem to help in my case, nor describe it exactly. The best similar one is aapt not found under the right path. My problem is that I can be using Eclipse for a whole evening programming, compiling and using my device, and then suddenly I get "error executing aapt" for my current project and ofcourse R.java isn't (properly) generated anymore. I then restart Eclipse and everything goes away. I'm seeing this once a day on average however. I've recently switched to amd64 and installed the latest Android-2.3 SDK and matching tools. I know that there is now a platform-tools folder that has an aapt version that should work SDK version independently. At first I had added this directory to my PATH, as instructed on the SDK website. I've also tried not adding it to my path and making a link platforms/android-9/tools so that every SDK version might use it's own old copy. Needless to say, platform-tools/aapt is there and has the right permissions, and I have been able to execute it on the command-line at any time. When I do write a faulty xml file or sorts, and appropriately get an error, I see an extra line that says "aapt: /lib32/libz.so.1: no version information available". I'm running a recent Gentoo linux system. I have everything installed to support x86 on amd64, but have re-emerged emul-linux-x86-baselibs and zlib just to be sure. The problem persists. I do see some pages that spell horror over some zlib bugs, but I'm not sure if that's related. I realize I'm not on the reference Ubuntu platform, but surely the difference cannot be that great? It might very well be a bug in aapt or the tools itself. Why would it suddenly stop working? I also experience that the ids in R.java were incorrect, namely that simple findViewById() code would give ClassCastExceptions because of mixed ids the one time, and then work perfectly without any changes bu only a "clean project", in the aftermath of a failing aapt. Finally, I've run a few commands on aapt, that don't seem to add any extra information: #ldd aapt ./aapt: /lib32/libz.so.1: no version information available (required by ./aapt) linux-gate.so.1 => (0xffffe000) librt.so.1 => /lib32/librt.so.1 (0x4f864000) libpthread.so.0 => /lib32/libpthread.so.0 (0x4f849000) libz.so.1 => /lib32/libz.so.1 (0xf7707000) libstdc++.so.6 => /usr/lib/gcc/x86_64-pc-linux-gnu/4.4.4/32/libstdc++.so.6 (0x415e9000) libm.so.6 => /lib32/libm.so.6 (0x4f876000) libgcc_s.so.1 => /lib32/libgcc_s.so.1 (0x4fac6000) libc.so.6 => /lib32/libc.so.6 (0x4f5ed000) /lib/ld-linux.so.2 (0x4f5ca000) #file aapt aapt: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.15, not stripped Can anybody tell anything wrong with my configuration? Does it smell like a bug perhaps (otherwise let's report it (again))? Update 2010-01-06: I've gained some more knowledge. When I recently was trying to export a signed apk, I ran into another error message (full details from the Eclipse error view) regarding aapt I hadn't seen before. Note here too, that I can just restart Eclipse and can export apks again without problems, at least for a little while. I'm starting to think it is related to lack of memory on my system. The message "onvoldoende geheugen beschikbaar" means "insufficient memory available". I have also been seeing insufficient memory errors in DDMS when I'm dumping HPROF files. Here is the error log (shortened): !ENTRY com.android.ide.eclipse.adt 4 0 2011-01-05 23:11:16.097 !MESSAGE Export Wizard Error !STACK 1 org.eclipse.core.runtime.CoreException: Failed to export application at com.android.ide.eclipse.adt.internal.project.ExportHelper.exportReleaseApk(Unknown Source) at com.android.ide.eclipse.adt.internal.wizards.export.ExportWizard.doExport(Unknown Source) at com.android.ide.eclipse.adt.internal.wizards.export.ExportWizard.access$0(Unknown Source) at com.android.ide.eclipse.adt.internal.wizards.export.ExportWizard$1.run(Unknown Source) at org.eclipse.jface.operation.ModalContext$ModalContextThread.run(ModalContext.java:121) Caused by: com.android.ide.eclipse.adt.internal.build.AaptExecException: Error executing aapt. Please check aapt is present at /opt/android-sdk/android-sdk-linux_x86-1.6_r1/platform-tools/aapt at com.android.ide.eclipse.adt.internal.build.BuildHelper.executeAapt(Unknown Source) at com.android.ide.eclipse.adt.internal.build.BuildHelper.packageResources(Unknown Source) ... 5 more Caused by: java.io.IOException: Cannot run program "/opt/android-sdk/android-sdk-linux_x86-1.6_r1/platform-tools/aapt": java.io.IOException: error=12, Onvoldoende geheugen beschikbaar ... Caused by: java.io.IOException: java.io.IOException: error=12, Onvoldoende geheugen beschikbaar ... !SUBENTRY 1 com.android.ide.eclipse.adt 4 0 2011-01-05 23:11:16.098 !MESSAGE Failed to export application !STACK 0 com.android.ide.eclipse.adt.internal.build.AaptExecException: Error executing aapt. Please check aapt is present at /opt/android-sdk/android-sdk-linux_x86-1.6_r1/platform-tools/aapt at com.android.ide.eclipse.adt.internal.build.BuildHelper.executeAapt(Unknown Source) at com.android.ide.eclipse.adt.internal.build.BuildHelper.packageResources(Unknown Source) at com.android.ide.eclipse.adt.internal.project.ExportHelper.exportReleaseApk(Unknown Source) at com.android.ide.eclipse.adt.internal.wizards.export.ExportWizard.doExport(Unknown Source) at com.android.ide.eclipse.adt.internal.wizards.export.ExportWizard.access$0(Unknown Source) at com.android.ide.eclipse.adt.internal.wizards.export.ExportWizard$1.run(Unknown Source) at org.eclipse.jface.operation.ModalContext$ModalContextThread.run(ModalContext.java:121) Caused by: java.io.IOException: Cannot run program "/opt/android-sdk/android-sdk-linux_x86-1.6_r1/platform-tools/aapt": java.io.IOException: error=12, Onvoldoende geheugen beschikbaar ... Caused by: java.io.IOException: java.io.IOException: error=12, Onvoldoende geheugen beschikbaar

    Read the article

  • how to stop the showing error message in visual studio for jscript in visual studio 2010

    - by steven spielberg
    i am using IE 8 for testing the javascript i write for my web-application. i use something who are not unknown for IE 8 so they give me error each time "Microsoft JScript runtime error: Object doesn't support this property or method". are their any way to stop this error showing in visual studio when i debug the javascript. when i refresh the page they give me error in visual studio. well i not want to see anything like showing error in visual studio. so how i can disable the showing error for javascript in visual studio even i need to work with javascript breakpoint and trackpoint.

    Read the article

  • SQL SELECT: "Give me all documents where all of the documents procedures are 'work in progress'"

    - by prestonmarshall
    This one really has me stumped. I have a documents table which hold info about the documents, and a procedures table, which is kind of like a revisions table for each document. What I need to do is write a select statement which gives me all of the documents where all of the procedures have the status "work_in_progress". Here's an example procedures table: document_id | status 1 | 'wip' 1 | 'wip' 1 | 'wip' 1 | 'approved' 2 | 'wip' 2 | 'wip' 2 | 'wip' Here, I would want my query to only return document id 2, because all of its statuses are work_in_progress. I DO NOT want document_id 1 since one of its statuses is 'approved'. I believe this is relational division I want, but I'm not sure where to start. This is MySQL 5.0 FYI.

    Read the article

  • I need to calculate the date / time difference between one date time column

    - by Stringz
    Details. I have the notes table having the following columns. ID - INT(3) Date - DateTime Note - VARCHAR(100) Tile - Varchar(100) UserName - Varchar(100) Now this table will be having NOTES along with the Titles entered by UserName on the specified date / time. I need to calculate the DateTimeDifference between the TWO ROWS in the SAME COLUMN For example the above table has this peice of information in the table. 64, '2010-03-26 18:16:13', 'Action History', 'sending to Level 2.', 'Salman Khwaja' 65, '2010-03-26 18:19:48', 'Assigned By', 'This is note one for the assignment of RF.', 'Salman Khwaja' 66, '2010-03-27 19:19:48', 'Assigned By', 'This is note one for the assignment of CRF.', 'Salman Khwaja' Now I need to have the following resultset in query reports using MYSQL. TASK - TIME Taken ACTION History - 2010-03-26 18:16:13 Assigned By - 00:03:35 Assigned By - 25:00:00 More smarter approach would be TASK - TIME Taken ACTION History - 2010-03-26 18:16:13 Assigned By - 3 minutes 35 seconds Assigned By - 1 day, 1 hour. I would appreciate if one could give me the PLAIN QUERY along with PHP code to embed it too.

    Read the article

  • How to merge two tables based on common column and sort the results by date

    - by techiepark
    Hello friends, I have two mysql tables and i want to merge the results of these two tables based on the common column rev_id. The merged results should be sorted by the date of two tables. Please help me. CREATE TABLE `reply` ( `id` int(3) NOT NULL auto_increment, `name` varchar(25) NOT NULL default '', `member_id` varchar(45) NOT NULL, `rev_id` int(3) NOT NULL default '0', `description` text, `post_date` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, `flag` char(2) NOT NULL default 'N', PRIMARY KEY (`id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM; CREATE TABLE `comment` ( `com_id` int(8) NOT NULL auto_increment, `rev_id` int(5) NOT NULL default '0', `member_id` varchar(50) NOT NULL, `comm_desc` text NOT NULL, `date_created` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, PRIMARY KEY (`com_id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM;

    Read the article

< Previous Page | 116 117 118 119 120 121 122 123 124 125 126 127  | Next Page >