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  • Regexp for handling recursive arguments

    - by Matt
    Hi all, I'm a regexp novice, so I'm wondering what the regexp for the following: function {function arg1, arg2}, arg3 I'm looking to be able to just select the top-level arguments: {function arg1, arg2} & arg3 Ideally the response would be using preg_match in PHP, but almost any regexp would work fine. Thanks! Matt

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  • Jetty RewriteHandler and RewriteRegexRule

    - by Justin
    I'm trying to rewrite a URL for a servlet. The URL gets rewritten correctly, but the context doesn't match after that. Any idea how to get this to work? RewriteHandler rewriteHandler = new RewriteHandler(); rewriteHandler.setRewriteRequestURI(true); rewriteHandler.setRewritePathInfo(true); rewriteHandler.setOriginalPathAttribute("requestedPath"); RewriteRegexRule rewriteRegexRule = new RewriteRegexRule(); rewriteRegexRule.setRegex("/r/([^/]*).*"); rewriteRegexRule.setReplacement("/r?z=$1"); rewriteHandler.addRule(rewriteRegexRule); ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection(); Context servletContext = new Context(contextHandlerCollection, "/"); servletContext.addServlet(new ServletHolder(new RedirectServlet()), "/r"); So basically /r/asdf gets rewritten to /r?z=asdf. However, the rewritten /r?z=asdf is now not processed by the servlet. Also, /r?z=asdf does work if called directly.

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  • Python regex on list

    - by Peter Nielsen
    Hi there I am trying to build a parser and save the results as an xml file but i have problems.. For instance i get a TypeError: expected string or buffer when i try to run the code.. Would you experts please have a look at my code ? import urllib2, re from xml.dom.minidom import Document from BeautifulSoup import BeautifulSoup as bs osc = open('OSCTEST.html','r') oscread = osc.read() soup=bs(oscread) doc = Document() root = doc.createElement('root') doc.appendChild(root) countries = doc.createElement('countries') root.appendChild(countries) findtags1 = re.compile ('<h1 class="title metadata_title content_perceived_text(.*?)</h1>', re.DOTALL | re.IGNORECASE).findall(soup) findtags2 = re.compile ('<span class="content_text">(.*?)</span>', re.DOTALL | re.IGNORECASE).findall(soup) for header in findtags1: title_elem = doc.createElement('title') countries.appendChild(title_elem) header_elem = doc.createTextNode(header) title_elem.appendChild(header_elem) for item in findtags2: art_elem = doc.createElement('artikel') countries.appendChild(art_elem) s = item.replace('<P>','') t = s.replace('</P>','') text_elem = doc.createTextNode(t) art_elem.appendChild(text_elem) print doc.toprettyxml()

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  • Regular Expression to break row with comma separated values into distinct rows

    - by Nick
    I have a file with many rows. Each row has a column which may contain comma separated values. I need each row to be distinct (ie no comma separated values). Here is an example row: AB AB10,AB11,AB12,AB15,AB16,AB21,AB22,AB23,AB24,AB25,AB99 ABERDEEN Aberdeenshire The columns are comma separated (Postcode area, Postcode districts, Post town, Former postal county). So the above row would get turned into: AB AB10 ABERDEEN Aberdeenshire AB AB11 ABERDEEN Aberdeenshire AB AB12 ABERDEEN Aberdeenshire ... ... I tried the following but it didn't work... (.+)\t(([0-9A-Z]+),)+\t(.+)\t(.+)

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  • multi-line pattern matching in pyhon

    - by Horace Ho
    A periodic computer generated message (simplified): Hello user123, - (604)7080900 - 152 - minutes Regards Using python, how can I extract "(604)7080900", "152", "minutes" (i.e. any text following a leading "- " pattern) between the two empty lines (empty line is the \n\n after "Hello user123" and the \n\n before "Regards"). Even better if the result string list are stored in an array. Thanks!

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  • Parsing two-dimensional text

    - by alexbw
    I need to parse text files where relevant information is often spread across multiple lines in a nonlinear way. An example: 1234 1 IN THE SUPERIOR COURT OF THE STATE OF SOME STATE 2 IN AND FOR THE COUNTY OF SOME COUNTY 3 UNLIMITED JURISDICTION 4 --o0o-- 5 6 JOHN SMITH and JILL SMITH, ) ) 7 Plaintiffs, ) ) 8 vs. ) No. 12345 ) 9 ACME CO, et al., ) ) 10 Defendants. ) ___________________________________) I need to pull out Plaintiff and Defendant identities. These transcripts have a very wide variety of formattings, so I can't always count on those nice parentheses being there, or the plaintiff and defendant information being neatly boxed off, e.g.: 1 SUPREME COURT OF THE STATE OF SOME OTHER STATE COUNTY OF COUNTYVILLE 2 First Judicial District Important Litigation 3 --------------------------------------------------X THIS DOCUMENT APPLIES TO: 4 JOHN SMITH, 5 Plaintiff, Index No. 2000-123 6 DEPOSITION 7 - against - UNDER ORAL EXAMINATION 8 OF JOHN SMITH, 9 Volume I 10 ACME CO, et al, 11 Defendants. 12 --------------------------------------------------X The two constants are: "Plaintiff" will occur after the name of the plaintiff(s), but not necessarily on the same line. Plaintiffs and defendants' names will be in upper case. Any ideas?

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  • regular expression for indian vehicle number in javascript and php

    - by I Like PHP
    i need regular expression in java script as well as in PHP for Indian vehicle NUMBER here are conditions list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

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  • replacing text within quotes until next quote

    - by Jordan Trainor
    String input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; This is my current code that works but iv added some code that has to run before this which makes some '"' split onto another line thus making the code below obsolute unless under certain cirumstances the '"' is not put onto the next line. firstQuote = input.IndexOf("\""); lastQuote = input.LastIndexOf("\""); input = input.Substring(0, firstQuote) + "<span>quote" + input.Substring(firstQuote + 1, lastQuote - (firstQuote + 1) + "quote</span>" + input.Substring(lastQuote + 1, lines.Length - (lastQuote + 1); How could I change the input string from input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; to input = "helloj(<span>quoteiojgeio\r\ngsk\\"jopriquote</span>gj\r\negjoijisgoe<span>quotejoijsofeijquote</span>quote<span>quote</span>ojgsoij<span>quote</span>";

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  • How can I remove HTML span tags with a Perl one liner?

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with Perl. I would prefer to allow for any occurences of whitespace or newlines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> EDIT: It's just the <span>'s and </span>'s that are inbetween <p> and <a> from the "blockDontForget" class </div> that I want to remove (there are lots or these blockDontForget divs with spans inside anchors that I want to keep).

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  • Regular expression not working after debugging

    - by Jaison
    I have an ASP.NET website with a regular expression validator text box. I have changed the expression in the regular expression validation property "validator expression" and after compiling (rebuild) and running, the validation CHANGEs are not reflecting. The previous validation is working fine but the changed validation is not working. Please help me! edit: First code: ([a-zA-Z0-9_-.]+)\@((base.co.uk)|(base.com)|(group.com)) Second code: @"([a-zA-Z0-9_\-.]+)@((base\.co\.uk)|(base\.com)|(group\.com)|(arg\.co\.uk)|(arggroup\.com))"

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  • Match groups in Python

    - by Curd
    Is there a way in Python to access match groups without explicitely creating a match object (or another way to beautify the example below)? Here is an example to clarify my motivation for the question: Following perl code if ($statement =~ /I love (\w+)/) { print "He loves $1\n"; } elsif ($statement =~ /Ich liebe (\w+)/) { print "Er liebt $1\n"; } elsif ($statement =~ /Je t\'aime (\w+)/) { print "Il aime $1\n"; } translated into Python m = re.match("I love (\w+)", statement) if m: print "He loves",m.group(1) else: m = re.match("Ich liebe (\w+)", statement) if m: print "Er liebt",m.group(1) else: m = re.match("Je t'aime (\w+)", statement) if m: print "Il aime",m.group(1) looks very awkward (if-else-cascade, match object creation).

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  • Validating javascript decimal numbers

    - by Click Upvote
    I'm using the following regexp to validate numbers in my javascript file: var valid = (val.match(/^\d+$/)); It works fine for whole numbers like 100, 200, etc, however for things like 1.44, 4.11, etc, it returns false. How can I change it so numbers with a decimal are also accepted?

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  • bash grep finding java declarations

    - by Amarsh
    i have a huge .java file and i want to find all declared objects given the className. i think the declaration will always have the following signature: className objName; or className objName = or className objName= can someone suggest me a grep pattern which will find these signatures. I have the following (incomplete) : cat $rootFile | grep "$className "

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  • RewriteCond and Full QUERY_STRING

    - by Tim
    I'm having hard time getting my head wrapped around this one - and it should be trivial. I would like to redirect one URL with a specific query string to another URL. I want to send any requests that contain the query string in the URL http://mysite.com/index.php?option=com_user&view=register To: http://mysite.com/index.php?option=com_regme&view=form&regme=4&random=0&Itemid=6 If they add anything to the end of the first URL, it should still go to the second URL so that they cannot bypass the redirection. Nothing in the first query string needs to be preserved and passed to the second - all I want to do is change the URL completely. I'm tearing my hair out trying to get this to work yet it should be trivial. Suggestions? Thanks, -Tim

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  • PHP, what is the better choice for removing a known string?

    - by Brook Julias
    I am looking to search for and replace a known string from within another string. Should I use str_replace() or ereg_replace()? The string to be replaced would be something similar to [+qStr+], [+bqID+], or [+aID+] and it would be being searched for in a code chunk similar to this: <li> [+qStr+] <ol class="mcAlpha"> <li><input type="radio" name="[+bqID+]" id="[+bqID+]_[+aID+]" value="[+aID+]" /><label for="[+bqID+]_[+aID+]">[+aStr+]</label></li> </ol> </li> I would be replacing the strings with the results from a MySQL query, and be performing this action or similar up to 200 times at a time. Which function str_replace() or ereg_replace() would be the easiest and/or quickest method to take.

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  • Match string which doesn't start with

    - by Pinky
    I have a string that looks like this: var str = "Hello world, &nbsp;hello &gt;world, hello world!"; ... and I'd like to replace all the hellos with e.g. bye and world with earth, except the words that start with &nbsp or &gt. Those should be ignored. So the result should be: bye earth, &nbsp;hello &gt;world, bye earth! Tried to this with str.replace(/(?!\&nbsp;)hello/gi,'bye')); But it doesn't work.

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  • Match subpatterns in any order

    - by Yaroslav
    I have long regexp with two complicated subpatters inside. How i can match that subpatterns in any order? Simplified example: /(apple)?\s?(banana)?\s?(orange)?\s?(kiwi)?/ and i want to match both of apple banana orange kiwi apple orange banana kiwi It is very simplified example. In my case banana and orange is long complicated subpatterns and i don't want to do something like /(apple)?\s?((banana)?\s?(orange)?|(orange)?\s?(banana)?)\s?(kiwi)?/ Is it possible to group subpatterns like chars in character class? UPD Real data as requested: 14:24 26,37 Mb 108.53 01:19:02 06.07 24.39 19:39 46:00 my strings much longer, but it is significant part. Here you can see two lines what i need to match. First has two values: length (14 min 24 sec) and size 26.37 Mb. Second one has three values but in different order: size 108.53 Mb, length 01 h 19 m 02 s and date June, 07 Third one has two size and length Fourth has only length There are couple more variations and i need to parse all values. I have a regexp that pretty close except i can't figure out how to match patterns in different order without writing it twice. (?<size>\d{1,3}\[.,]\d{1,2}\s+(?:Mb)?)?\s? (?<length>(?:(?:01:)?\d{1,2}:\d{2}))?\s* (?<date>\d{2}\.\d{2}))? NOTE: that is only part of big regexp that forks fine already.

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  • match at the beginning of any line, including the first

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)?

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  • How to extract only part of string in PHP?

    - by shin
    I have a following string and I want to extract image123.jpg. ..here_can_be_any_length "and_here_any_length/image123.jpg" and_here_also_any_length image123 can be any length (newimage123456 etc) and with extension of jpg, jpeg, gif or png. I assume I need to use preg_match, but I am not really sure how to code it. Any help will be appreciated. Thanks in advance.

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