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  • second time auto login to twitter using oauth php

    - by JAMES
    Any can tell me how to second time auto connect with twitter from my site. I did... the following CODE if(empty($outh_key_db)){ $token=$_SESSION['oauth_token'] ; $outh_secr_db=$_SESSION['oauth_token_secret']; $con = mysql_connect("localhost","rathin","xxxxxxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_twtbook", $con); mysql_query("UPDATE register SET outh_key = '".$token."', outh_secr='".$outh_secr_db."' WHERE userid='".$loguser_email."'"); mysql_close($con); This code save the outh_token and outh_tk_secret to my DB. But on second time log in to my site I passed the 'outh_token and outh_tk_secret' in session with username. The oauth not authenticate that.... Kindly suggest me.... to make aouth connect to twitter using oauth...if user once(1st time made the) connect twitter

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  • How do I make replies to comments? (PHP)

    - by jpjp
    I want to create something like reddit where they have comments, then replies to the comment, then reply to the reply. What type of database structure do they use so: 1. they keep track of all the comments to a posting 2. a reply to a comment 3. a reply to a reply All I have right are is just a posting and a bunch of comments relating to it like.. POSTING TABLE posting_id | title | author COMMENTS TABLE comment_id | posting_id | comment REPLIES TABLE ???? How do I relate the comments to the replies? What type of css do they use to give replies that indented space?

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  • [PHP] Local/Dev/Live deployment - best workflow

    - by Adam Kiss
    Hello, situation We our little company with 3 people, each has a localhost webserver and most projects (previous and current) are on one PC network shared disk. We have virtual server, where some of our clients' sites and our site. Our standard workflow is: Coder PC ? Programmer localhost ? dev domain (client.company.com) ? live version (client.com) It often happens, that there are two or three guys working on same projects at the same time - one is on dev version, two are on localhost. When finished, we try to synchronize the files on dev version and ideally not to mess up any files, which *knock knock * doesn't happen often. And then one of us deploys dev version on live webserver. question we are looking for a way to simplify this workflow while updating websites - ideally some sort of diff uploader or VCS probably (Git/SVN/VCS/...), but we are not completely sure where to begin or what way would be ideal, therefore I ask you, fellow stackoverflowers for your experience with website / application deployment and recommended workflow. We probably will also need to use Mac in process, so if it won't be a problem, that would be even better. Thank you

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • login/logout problem in PHP

    - by user356170
    i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

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  • PHP - Class Inherit problem

    - by TatMing
    I have A.php and B.php A.php <?php error_reporting(E_ALL); ini_set("display_errors",1); class myClass { function hello() { return 'hello'; } } ?> B.php <?php error_reporting(E_ALL); ini_set("display_errors",1); require_once('/A.php'); $a = new myClass(); testing(); function testing() { echo $a ->hello(); } ?> B.php inherits A.php , if i run B.php,but it show "Fatal error: Call to a member function hello() on a non-object." So the question is simple, how can i correct this ,but "$a = new myClass();" is not inside the function, since in .NET world can do this, i believe PHP also possible. And one more question is, what is the modify of function in A.php ,if i have not state private/public/protected???

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  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

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  • num_rows is 0 when it should be >0 for php mysqli code

    - by jpporterVA
    My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

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  • PHP - Setting Database Info

    - by user1710648
    First off, I'm sorry if this shows no code which is not what Stack Overflow is about..But I have no clue where to go on this. I have a basic CMS I made, and I am trying to distribute it. I want to make it so that upon going to /cms/install for example, they set the database info, and different info to integrate into the CMS. Now my issue is, what would be the best method to allow the user to store that database info? A cookie seems to not be the right way..Could I store database info inside of a database? Not too sure where to go on this. More or less. What is the best way to temporarily store the database information the user gave before arrival of the full CMS.

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  • php and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • Error during data INSERT in php

    - by nectar
    here my code- $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES "; for($i=0; $i0) { $sql .= ", "; } $sql .= "('$pin[$i]', '$ownerid', 'Free', '1')"; } $sql .= ";"; echo $sql; mysql_query($sql); if(mysql_affected_rows() 0) { echo "done"; } else { echo "Fail"; } output: ** INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES ('13837927', 'admin', 'Free', '1'), ('59576082', 'admin', 'Free', '1'); Fail why it is not inserting values when $sql query is right?

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • PHP, MySQL - can you distinguish between rows matched and rows affected?

    - by Renesis
    I am trying to write a PHP-MySQL database processor that is somewhat intelligent. When this processor decides it needs to make an update, I want to report if it was really successful or not. I thought I could use mysql_affected_rows... // Example: // After running query "UPDATE mytable SET name='Test' WHERE ID=1" $result = mysql_affected_rows(); if ($result >= 1) { /* Success */ } If, for example, there was no row with ID=1, then $result would be 0. However, it turns out that PHP's mysql_affected_rows is the actual affected rows, and may be still be 0 if the row exists but name was already "Test". (The PHP docs even say this is the case). If I run this in the command line, I get the following meta information about the query: Query OK, 0 rows affected (0.01 sec) Rows matched: 1 Changed: 0 Warnings: 0 Is there any way for me to get that "Rows matched" value in PHP instead of the affected rows?

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  • php pconnect vs connect

    - by user192344
    if i have a script which insert a data then exit the script will be opened by 100 user at same time or within 2 mins actually im doing email tracking so pconnect is bettwe or connect is better to reduce the resource i have close when after insert

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  • php for-loop issue

    - by rajesh1984
    Heya, I have a loop which generates a table code for a specific number of times. What I'm having problems with is to echo a variable inside the loop. The loop runs 10 times, and there are 10 text messages sent to the page, so my problem is how do I get each of the looped tables to echo one of the text messages each time?

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  • Removing part of a string in PHP

    - by Nik
    I'm trying to take a query: SHOW TABLES; which will display a bunch of tables with the chat_ prefix. I want to remove the chat_ prefix from the string, format the variable (with a link), and display it. How is this accomplished?

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  • PHP: reusing database class

    - by citricsquid
    Hi, I built a class that allows me to do: $db->query($query); and it works perfectly, although if I want to do: $db->query($query); while($row = $db->fetch_assoc()){ $db->query($anotherquery); echo $db->result(); } it "breaks" the class. I don't want to constantly have to redeclare my class (eg: $seconddb = new database()), is there a way to get around this? I want to be able to reuse $db within $db, without overwriting the "outside" db. currently I'm create an array of data (from db-fetch_assoc() then doing a foreach and then doing the db call inside that: $db->query('SELECT * FROM table'); while($row = $db->fetch_assoc()){ $arr[] = $row; } foreach($arr as $a){ $db->query(); // query and processing here } Is this the best method or am I missing the obvious? Should I consider passing a connection link ID with the database connection?

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  • Thumbnailing and then Saving as a Blob with PHP in Wordpress

    - by Parris
    The below code seems like it should work; however, the blob in the database only contains 0 after the function is run. Does the below code look accurate? If not how can I fix it? $tmpName = $_FILES['picture']['tmp_name']; $fp = fopen($tmpName, 'r'); $binary = fread($fp, filesize($tmpName)); fclose($fp); $originalImage = imagecreatefromstring($binary); $tempImage = imagecreate(100,100); imagecopyresized($tempImage,$originalImage,0,0,0,0,100,100); ob_start(); imageJPEG($tempImage); $thumbnail = ob_get_contents(); ob_end_clean(); $wpdb->query("UPDATE ".$wpdb->prefix."items SET picture = $thumbnail WHERE id=$id'"); Thank :)!

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  • How can I Display an extract from MySQL database entry?

    - by ThatMacLad
    I'm after creating a webpage that includes a blog section and it currently displays the whole post on the homepage. I'd like to set it so that it only displays a certain part of the entry i.e 50 words. I'd then like to be able to set it so that I have a read more button below the post that links to the post id. I currently use post.php?=# (# = whatever the post id is). Here is the homepage: <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>Blog Name</title> <link rel="stylesheet" href="css/style.css" type="text/css" /> <body> <div id="upper-bar"> <div id="bar-content"> <a href="#">Home</a> <a href="#">Archives</a> <a href="#">Contact</a> <a href="#">About</a> <a href="#"><img src="images/twitter.png" id="tweet"></a><a href="#"><img src="images/feed.png" id="feed"></a> </div> </div> <div id="clear"> </div> <div class="main"> <h1>Blog Name</h1> <div class="post-col"> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $id = $row['id']; ?> <div id='post-info'><?php echo "<p id='title'><strong><a href=\"post.php?id=". $id . "\">" . $title . "</a></strong></p>"; ?><br /></div> <div id="post"> <?php echo $entry; ?> <!--<br /><br /> Posted on <?php echo $date; ?> !--> </p> </div> </p> </div> <?php } ?> </div> </div> </body> </html>

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  • iptables not allowing mysql connections to aliased ips?

    - by Curtis
    I have a fairly simple iptables firewall on a server that provides MySQL services, but iptables seems to be giving me very inconsistent results. The default policy on the script is as follows: iptables -P INPUT DROP I can then make MySQL public with the following rule: iptables -A INPUT -p tcp --dport 3306 -j ACCEPT With this rule in place, I can connect to MySQL from any source IP to any destination IP on the server without a problem. However, when I try to restrict access to just three IPs by replacing the above line with the following, I run into trouble (xxx=masked octect): iptables -A INPUT -p tcp --dport 3306 -m state --state NEW -s 208.XXX.XXX.184 -j ACCEPT iptables -A INPUT -p tcp --dport 3306 -m state --state NEW -s 208.XXX.XXX.196 -j ACCEPT iptables -A INPUT -p tcp --dport 3306 -m state --state NEW -s 208.XXX.XXX.251 -j ACCEPT Once the above rules are in place, the following happens: I can connect to the MySQL server from the .184, .196 and .251 hosts just fine as long as am connecting to the MySQL server using it's default IP address or an IP alias in the same subnet as the default IP address. I am unable to connect to MySQL using IP aliases that are assigned to the server from a different subnet than the server's default IP when I'm coming from the .184 or .196 hosts, but .251 works just fine. From the .184 or .196 hosts, a telnet attempt just hangs... # telnet 209.xxx.xxx.22 3306 Trying 209.xxx.xxx.22... If I remove the .251 line (making .196 the last rule added), the .196 host still can not connect to MySQL using IP aliases (so it's not the order of the rules that is causing the inconsistent behavior). I know, this particular test was silly as it shouldn't matter what order these three rules are added in, but I figured someone might ask. If I switch back to the "public" rule, all hosts can connect to the MySQL server using either the default or aliased IPs (in either subnet): iptables -A INPUT -p tcp --dport 3306 -j ACCEPT The server is running in a CentOS 5.4 OpenVZ/Proxmox container (2.6.32-4-pve). And, just in case you prefer to see the problem rules in the context of the iptables script, here it is (xxx=masked octect): # Flush old rules, old custom tables /sbin/iptables --flush /sbin/iptables --delete-chain # Set default policies for all three default chains /sbin/iptables -P INPUT DROP /sbin/iptables -P FORWARD DROP /sbin/iptables -P OUTPUT ACCEPT # Enable free use of loopback interfaces /sbin/iptables -A INPUT -i lo -j ACCEPT /sbin/iptables -A OUTPUT -o lo -j ACCEPT # All TCP sessions should begin with SYN /sbin/iptables -A INPUT -p tcp ! --syn -m state --state NEW -j DROP # Accept inbound TCP packets (Do this *before* adding the 'blocked' chain) /sbin/iptables -A INPUT -m state --state ESTABLISHED,RELATED -j ACCEPT # Allow the server's own IP to connect to itself /sbin/iptables -A INPUT -i eth0 -s 208.xxx.xxx.178 -j ACCEPT # Add the 'blocked' chain *after* we've accepted established/related connections # so we remain efficient and only evaluate new/inbound connections /sbin/iptables -N BLOCKED /sbin/iptables -A INPUT -j BLOCKED # Accept inbound ICMP messages /sbin/iptables -A INPUT -p ICMP --icmp-type 8 -j ACCEPT /sbin/iptables -A INPUT -p ICMP --icmp-type 11 -j ACCEPT # ssh (private) /sbin/iptables -A INPUT -p tcp --dport 22 -m state --state NEW -s xxx.xxx.xxx.xxx -j ACCEPT # ftp (private) /sbin/iptables -A INPUT -p tcp --dport 21 -m state --state NEW -s xxx.xxx.xxx.xxx -j ACCEPT # www (public) /sbin/iptables -A INPUT -p tcp --dport 80 -j ACCEPT /sbin/iptables -A INPUT -p tcp --dport 443 -j ACCEPT # smtp (public) /sbin/iptables -A INPUT -p tcp --dport 25 -j ACCEPT /sbin/iptables -A INPUT -p tcp --dport 2525 -j ACCEPT # pop (public) /sbin/iptables -A INPUT -p tcp --dport 110 -j ACCEPT # mysql (private) /sbin/iptables -A INPUT -p tcp --dport 3306 -m state --state NEW -s 208.xxx.xxx.184 -j ACCEPT /sbin/iptables -A INPUT -p tcp --dport 3306 -m state --state NEW -s 208.xxx.xxx.196 -j ACCEPT /sbin/iptables -A INPUT -p tcp --dport 3306 -m state --state NEW -s 208.xxx.xxx.251 -j ACCEPT Any ideas? Thanks in advance. :-)

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