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  • JQuery Tabbed Nav Menu and PHP Forms Question?

    - by SlAcKeR
    I'm using a JQuery Tabbed Menu which holds different types of forms and when I select a different form located under a different tab and submit the form the tab will jump to the default tab instead of the current tab the form is located in. I was wondering how would I go about fixing this so that when the form is submitted the current tab is still selected, is it the JQuery or PHP problem? Here is the JQuery. $(document).ready(function() { //When page loads... $(".form-content").hide(); //Hide all content var firstMenu = $("#home-menu ul li:first"); firstMenu.show(); firstMenu.find("a").addClass("selected-link"); //Activate first tab $(".form-content:first").show(); //Show first tab content //On Click Event $("#home-menu ul li").click(function() { $("#home-menu ul li a").removeClass("selected-link"); //Remove any "selected-link" class $(this).find("a").addClass("selected-link"); //Add "selected-link" class to selected tab $(".form-content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the selected-link tab + content $(activeTab).fadeIn(); //Fade in the selected-link ID content return false; }); });

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  • Get value from ajax-loaded form before submitting

    - by ldvldv
    Hi, I have an app that loads an ajax form when a button is clicked. I then want to check a value in that ajax loaded form called "comment_content" so that I don't send an ajax request if the comment_content is empty. I can capture the form submission using the live method, however, I can't capture the form element because it needs an element. I was looking at livequery but was wondering if there is a more efficient way by using live or if that I shouldn't even bother? Your help is very much appreciated. $("#comment_submit").live('click', function(){ var comment = $("#comment_content").html(); if(comment == ""){ $("#notice").html("").stop(true, true); $("#notice").append("<p>Are you going to write something in that comment?</p>"); $('#notice').slideDown().delay(2000).slideUp(); return false; } return true; });

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  • jQuery: submit a form when the checkbox is selected

    - by Patrick
    hi, I have a form, and I want automatically to update it when I click on a checkbox. This is my current code: $('.option img').click(function() { $("#views-exposed-form-Portfolio-page-1").submit(); }); However, the selected checkbox is not stored before the form is submitted, and so the selection has not effect. thanks

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • Success function not being called when form is submitted

    - by Tom Hartman
    Hi, I've been trying to figure out why the following script's success function isn't running. Everything in my form works perfectly, and the form contents are being emailed correctly, but the success function isn't being called. If anyone could review my code and let me know why my success function isn't being called I would very much appreciate it! Here is the HTML form with notification divs, which are hidden via css: <div id="success" class="notification"> <p>Thank you! Your message has been sent.</p> </div> <div id="failure" class="notification"> <p>Sorry, your message could not be sent.</p> </div> <form id="contact-form" method="post" action="" class="jqtransform"> <label for="name">Name:</label> <input name="name" id="name" type="text" class="validate[required] input" /> <label for="company">Company:</label> <input name="company" id="company" type="text" class="input" /> <label for="phone">Phone:</label> <input name="phone" id="phone" type="text" class="input" /> <label for="email">Email:</label> <input name="email" id="email" type="text" class="validate[required,email] input" /> <div class="sep"></div> <label for="subject">Subject:</label> <input name="subject" id="subject" type="text" class="validate[required] input" /> <div class="clear"></div> <label for="message">Message:</label> <textarea name="message" id="message" class="validate[required]"></textarea> <div id="check-services"> <input type="checkbox" name="services[]" value="Contractor Recommendation" /> <div>Contractor Recommendation</div> <input type="checkbox" name="services[]" value="Proposal Review" /> <div>Proposal Review</div> <input type="checkbox" name="services[]" value="Existing Website Review" /> <div>Existing Website Review</div> <input type="checkbox" name="services[]" value="Work Evaluation" /> <div>Work Evaluation</div> <input type="checkbox" name="services[]" value="Layman Translation" /> <div>Layman Translation</div> <input type="checkbox" name="services[]" value="Project Management" /> <div>Project Management</div> </div> <div class="sep"></div> <input name="submit" id="submit" type="submit" class="button" value="Send" /> <input name="reset" id="reset" type="reset" class="button" value="Clear" onclick="$.validationEngine.closePrompt('.formError',true)" /> </form> Here is the javascript: // CONTACT FORM VALIDATION AND SUBMISSION $(document).ready(function(){ $('#contact-form').validationEngine({ ajaxSubmit: true, ajaxSubmitFile: 'lib/mail.php', scroll: false, success: function(){ $('#success').slideDown(); }, failure: function(){ $('#failure').slideDown(); $('.formError').animate({ marginTop: '+30px' }); } }); }); And here is my PHP mailer script: <?php $name = $_POST['name']; $company = $_POST['company']; $phone = $_POST['phone']; $email = $_POST['email']; $subject = $_POST['subject']; $message = $_POST['message']; $services = $_POST['services']; $to = '[email protected]'; $subject = 'THC - Contact'; $content .= "You received a message from ".$name.".\r\n\n"; if ($company): $content .= "They work for ".$company.".\r\n\n"; endif; $content .= "Here's the message:\r\n\n".$message."\r\n\n"; $content .= "And they are interested in the services below:\r\n\n"; $content .= implode("\r\n",$services); if ($phone): $content .= "\r\n\nYou can reach them at ".$phone."."; else: $content .= "\r\n\nNo phone number was provided."; endif; $headers = "From: ".$name."\r\n"; $headers .= "Reply-To: ".$email."\r\n"; if (mail($to,$subject,$content,$headers)): return true; else: return false; endif; ?>

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  • Listen to Response on HTML Form embedded in GWT View?

    - by confile
    I have a HTML like the following: <div> <form> <input type="text" /> <button class="sendForm" value="Send form" /> </form> </div> <script> // post the form with Jquery post // register a callback that handles the response </script> I use this type of form a lot with a JavaScript/JQuery overlay that displays the form. That could be handled for example with plugins like FancyBox. I also want to use this form embedded into a GWT view. Lets assume that the for cannot be created on client side because it has some server based markup language inside to set up some model data. If I want to use this form in GWT I have to do the following. Tell GWT the form request url and use a RequestBuilder to query the html content of this form. Then I can insert it into a div generated by GWT. So far so good. Problem: When the user hits the send button the response is handled my the JQuery callback that is inside the script under the form. Is there a way to access this callback from within GWT? Is there a way to overwrite the JQuery send action? Since, the code is HTML and comes from the server I cannot place ui-binder UiFields inside to get access to these DOM elements. I need to get the response if the submitted form accessible to GWT. Is there a way how I can achieve this with JSNI?

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  • Update Input Value With jQuery, Old Value Submitted to Form

    - by Tyler DeWitt
    I've got a form with an input with id/name league_id <form accept-charset="UTF-8" action="/user" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="?"><input name="authenticity_token" type="hidden" value="bb92urX83ivxOZZJzWLJMcr5ZSuamowO9O9Sxh5gqKo="></div> <input id="league_id" name="league_id" type="text" value="11"> <select class="sport_selector" id="sport_type_id" name="sport_type_id"><option value="5" selected="selected">Football</option> <option value="25">Women's Soccer</option> <option value="30">Volleyball</option> <option value="10">Men's Soccer</option></select> <input name="commit" type="submit" value="Save changes"> </form> In another part of my page, I have a drop down that, when changed, clears the value of league_id $("#sport_type_id").change -> $("#league_id").val(null) $(this).parents('form:first').submit() If I debug this page, I can see the value get wiped from the text box, but when the form is submitted, my controller always gets the old value. I tried changing the name of the input and got the same results.

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  • JQuery add hidden element to form programmatically

    - by vanzylv
    Hi Guys This is really getting to me now.I have a form that loads when the page loads.In my jquery 'ready' function I append a hidden to that form like so : $("<input id='thehidden' type='hidden' name='thehidden' value='hiddenval'>").appendTo("#MenuForm") When I check the form content with firebug i can see the element is added. ["$(\"#MenuForm\").children()"] is [div, input#thehidden hiddenval] All good so far.When I submit this form and try and read the elemet again,i can't get the value of the new hidden val I added. alert($('#thehidden').val()) is undefined Any help would be appreciated

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  • Finding Changed Form Element With jQuery

    - by mTuran
    Hi, i have a form(id="search_options") and i tracking changes in form by: $("#search_options").change(function() { // Bla Bla Bla }); In this form i have many inputs and one of is select(id="project_category") and i want to catch if user changed project_category select or another input. How can i done this ? Thanks

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  • Jquery draggable + toggleClass problem..

    - by vrynxzent
    the problem here is that the toggleClass position top:0px; left:0px will not trigger.. only the width and height and background-color will activate.. it will work if i will not drag the div(draggable).. if i start to drag the element, the toggled class positioning will not effect.. i dont know if there's such a function in jquery to help this.. <html> <head> <title></title> <script type="text/javascript" src="jquery-1.4.2.js"></script> <script type="text/javascript" src="jquery.ui.core.js"></script> <script type="text/javascript" src="jquery.ui.widget.js"></script> <script type="text/javascript" src="jquery.ui.mouse.js"></script> <script type="text/javascript" src="jquery.ui.resizable.js"></script> <script type="text/javascript" src="jquery.ui.draggable.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("#x").draggable().dblclick(function(){ $(this).toggleClass("hi"); }); }); </script> <style> .hello { background:red; width:200px; height:200px; position:relative; top:100px; left:100px; } .hi { background:yellow; position:relative; width:300px; height:300px; top:0px; left:0px; } </style> </head> <body> <div id="x" class="hello"> </div> </body> </html>

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  • Video playback with jQuery Mobile and Phonegap

    - by aritchie
    I'm fairly new to mobile apps, so am trying to knock up a simple video player using Phonegap and jQuery Mobile. The problem is, jQuery mobile appears to be blocking the video playback for some reason. To troubleshoot I stripped it right back to the following HTML, but get the same result, ie a black rectangle where the video should be, but no video playback or controls. <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <meta name="viewport" content="width=device-width,initial-scale=1"/> <link rel="stylesheet" type="text/css" href="css/index.css" /> <link rel="stylesheet" href="css/jquery.mobile-1.2.0.min.css" /> <script type="text/javascript" src="cordova-2.2.0.js"></script> <script type="text/javascript" src="js/index.js"></script> <script src="js/jquery-1.8.3.min.js"></script> <script src="js/jquery.mobile-1.2.0.js"></script> <title></title> </head> <body> <div> <video controls autoplay> <source src="video/video1.mp4" type="video/mp4" > </video> </div> </body> </html> If I remove the link to jquery.mobile-1.2.0.js the video shows up and plays, otherwise, just the black rectangle. I don't know jQuery mobile at all, but searching in the js for a reference to the video elements doesn't show up, so I've no idea what is blocking it. The code works fine in Chrome and Firefox. There are no console messages in Xcode. I also tried hooking up to http://debug.phonegap.com/ but this gave no error messages either. Any ideas??

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  • Can jQuery perform a compound select against the top level only? (a.k.a. "How to avoid chaining chil

    - by harpo
    Basically, is there a way to write a.children('.outer').children('.inner') without the intermediate selector? I can't write $('.outer > .inner', a) because I don't want to do full-depth search against a — I know that the .outer elements are immediate children of a. It's partly a matter of "elegance", but partly because I'm trying to avoid "throwaway" element sets. Yes, jQuery may in effect do the same thing, but it has a better chance of optimizing (at least in theory), when it knows the full query's intent.

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  • Multiple forms + HAML + jQuery + Javascript submit

    - by Jay Godse
    Hi. I have a HAML page that lists some links to delete "things" that looks like this %div %a.form_submit Delete Thing 1 %form{:href=>"#", :id=>'comment_1', :method=>'post', :action=>'/thing/delete'} %input{:type=>'hidden', :name=>'thingid', :value=>'1'} %input{:type=>'submit', style='display:none'} %div %a.form_submit Delete Thing 22 %form{:href=>"#", :id=>'comment_22', :method=>'post', :action=>'/thing/delete'} %input{:type=>'hidden', :name=>'thingid', :value=>'22'} %input{:type=>'submit', style='display:none'} The intention is to have a link "Delete XX" which will delete something specific. A page could have a number of these links, and each link is for a specific "thing". I also have a piece of (unobtrusive) jQuery javascript that adds a click handler to each form as follows: $('a.form_submit').click(function(event) { $('form').submit(); event.preventDefauilt(); }); This works when there is one form on a page. However, if I have more than one form on a page, how do I ensure that clicking "Delete Thing 1" will trigger a submit() event only on the form with id='comment_1'?

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  • Display a summary of form element values before submit

    - by Dirty Bird Design
    Using jquery formtowizard.js with an ajax submit. I want the last step of the form to display a summary of all form fields that were filled out. I can get it to work in isolated test cases, but not in full use. Form <form id="Commission" method="post" action="PHP/CommissionsSubmit.php"> <fieldset id="Initial"> <legend>Enter Your Information</legend> <ul> <li> <label for="FName">First Name*</label><input type="text" name="FName" id="FName"> </li> //repeat many li's </ul> </fieldset> <fieldset> <legend>Second Step</legend> //more li's </fieldset> <fieldset> <legend>Confirmation</legend> <span id="CFName"></span> </fieldset> </form> the jquery to get "#CFName" value $('#FName').keyup(function() { $('#CFName').val($(this).val()); }); I can't get the value to appear in the span "#CFName"... Could this have to do with the "serialize" function or anything going on with my $ajax submit function? its happening before submit... Please help! I apologize, but I've gone back and forth with "#CFName" being a span and an input, using .val and .html respectively

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  • multiple form submission with one submit

    - by skylab
    I've been trying to think this through and figure out if it is possible or not. I'm using zen-cart as shopping cart software, but what I'd like to do, is hard code a page that is basically a list of 7-9 products, next to each product is a checkbox, so I'd like to figure out a way, via html,javascript or jquery to submit whichever forms(products) are checked to the cart. The typical form submission for a product looks something like this(sometimes there may be one or two additional hidden fields): <form name="cart_quantity" action="index.php?action=add_product" method="post" enctype="multipart/form-data"> <input type="hidden" name="cart_quantity" value="1"> <input type="hidden" name="products_id" value="7"> <input type="hidden" name="id[6]" value="9" id="attrib-6-9"> <input type="image" src="buy_button.png" alt="Add to Cart" title="Instructional Video Part 1: Add to Cart"> </form> There would be 7-9 of these on the page, each with a checkbox, so I'm assuming a script would need to figure out which ones where checked and submit them via the form action? Maybe there is a better way of going about this that I'm not thinking of because a)it's over my head or b)just haven't figured it out yet. Anyway is something like this possible?

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  • Jquery - Dynamically build form action on submit?

    - by Probocop
    Hi, I'm trying to have the action of a HTML form built when the user clicks the submit button. So the user fills in a form, clicks submit, then the action gets built then it actually gets submitted. The reason being is because the form has a load of options on it which will be passed to a script. How would I go about doing this with Jquery?

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  • jQuery - upgrade from version 1.6.x to 1.7

    - by Renso
    Goal: Issues to consider when upgrading from jQuery version 1.6 to 1.7. This is a short list and may help identify the real issues you need to concern yourself with in stead of reading through all the release notesSummary of issues encountered during upgrade:As you prepare for upgrade to jQuery 1.7 from 1.6.x, this is a quick glimpse of all the issues that are relevant, not sure if it covers all but may be all you need to worry about.Use this method only for checking checkboxes and radio buttons:$("input:checked")http://api.jquery.com/checked-selector/This will work regardless of the version of jQuery you are using. Note that $("input).attr("checked") returns true prior to jQuery 1.6. Only retrieve "real" attributes with "attr", in order versions it would also retrieve properties like "tagName", this no longer works with jQuery 1.6.1+Why does $("input").attr("checked") no longer (from version 1.6.1+) return TRUE or FALSE, because if you look at the HTML (as well as W3C spec) it does not contain a true/false, but the value checked="checked", which is what it should have returned in the first place. $("input").prop("checked") works, return true, because there is in fact a DOM property for "checked" with the value being "true" or "false".Furthermore, if you want to upgrade to jQuery 1.7 you should only have to worry about this for most part:1. isNumeric() is new, be careful as the older version jQuery.isNaN() has been deprecated2. jqXHR success and error have been deprecated3. When rendering content with text(), white space issue cross-browsers: http://bugs.jquery.com/ticket/3144Other than the issues above I am not aware of any deprecations you need to worry about.Hope this helps to get everyone up to version 1.7

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  • Loading scripts using jQuery

    - by Nimbuz
    $.ajax({ url: "plugin.js", dataType: 'script', cache: true, success: function() { alert('loaded'); }}); 1) I can't get the script to load, probably due to incorrect path, but how do I determine the correct path? The above code is in init.js, plugin.js is also in the same folder. 2) Can I load multiple plugins at once with the same request? eg. plugin.js, anotherplugin.js? Thanks for your help

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  • Form:has selector does not work on IE

    - by Joel
    Hey, I am trying to use "form:has" selector which works on Chrome but not on IE. http://jsbin.com/uvumu/2 Does anyone have any idea why it is not working on IE? (when pushing the Post button there should be an alert box) Edited: Here is the code: JS: $(document).ready(function() { $(".comment-link").live('click',function() { return false; }); $("#morefeeds-link").click(function () { return false; }); // Form submittion - doesnt work $("form:has(.commentBtn)").live('submit',function () { alert("a"); return false; }); return false; });? HTML <form> <a href="#" class="comment-link" style="font-size:12px;">Comment</a> <table border="0" cellpadding="0" cellspacing="0"> <tr> <td valign="middle"> <input type="hidden" name="commentkey" value="1"> <input type="text" name="commenttext" class="commentfocus" value="Express your opinion"> </td> <td valign="middle"><input type="submit" class="commentBtn" value="Post"></td> </tr> </table> </form>

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  • JQuery Autocomplete Form Submission

    - by user1658370
    I have managed to implement the jQuery autocomplete plugin on my website but was wondering if it is possible to make the form auto-submit once the user selects an item from the search. I have the following set-up: HTML Form: <form class="quick_search" action="../include/search.php" method="post"> <input type="text" name="search" id="search" value="Search..."> </form> JavaScript: $().ready(function() { $("#search").autocomplete("../include/search.php", { width: 350, selectFirst: false }); }); I have also included the jQuery and Autoplugin scripts. The search.php file contains a list of the search options. At the moment, the search works correctly and I just need it to submit the form once an item is selected from the list that appears. I tried to use the onClick and onSelect options within the search field but neither of these worked correctly. Any help would be much appreciated (I don't really understand js)! Thanks.

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  • jQuery 1.5.1 vs 1.4.4 weirdness

    - by zobgib
    I have been getting some weird errors when I upgrade jQuery from 1.4.4 to 1.5.1. Maybe you guys can explain what I need to change or why the new version is not working. In 1.4.4 I have the following code <div class="navlink home" data-link="home"> <span class="top">Home</span> </div> <div id="index-03"> </div> <div class="navlink resume" data-link="resume"> <span class="top">Resume</span> </div> <div id="index-05"> </div> <div id="index-06"> </div> <div class="navlink portfolio" data-link="portfolio"> <span class="bottom">Portfolio</span> </div> JS: $(".navlink").hover( function () { $(this).delay(100).animate({backgroundPosition: "-100% 0"}, 400); $(this).find("span").css("textDecoration","underline"); }, function () { $(this).queue("fx", []); $(this).animate({backgroundPosition: "0% 0%"}, 400); $(this).find("span").css("textDecoration","none"); } ); Which works just fine. but when I switch jQuery versions by changing this line in my header from <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script> to <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script> The above code quits animating and the background image just disappears. Here is a jsFiddle that shows what's happening just change the jQuery version on the side between 1.4.4 and 1.5.1 http://jsfiddle.net/fUXZ4/ -- 1.4.4 http://jsfiddle.net/3APCd/ -- 1.5.1 Here is a video of exactly what is happening to me: http://img.zobgib.com/2011-03-07_1905.swf

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  • submitting a form inside a modalbox with jquery

    - by birdy
    submitting form with jQuery works $('#testform').submit(); doesn't work $('#testform').submit(function () { alert('test1'); return true; }); This is just an exmaple but at times i'd like to do stuff before submission of the form. Like for example submit the form using $.POST Update: If I keep both then the $.POST has no value because the form still gets submitted the traditional way, without ajax... $("#testform").submit(function() { $.post('/myajaxcontroller', function(data) { $('#result').html(data); }); }); $("#testform").submit();

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  • form element not showing up after adding in through jquery

    - by ooo
    inside a jquery method (on a click event of a button) i have the following code: $(selector).html("<form action='/Tracker/CopyFood' method='post'><input type='hidden' name='Id' value=" + id + "><input class='very-small-input' type='text' name='Quantity' value='1' /> for <select name='Date'><option value='Today'>Today</option><option value='Yesterday'>Yesterday</option></select><select name='Meal'><option value='Breakfast'>Breakfast</option><option value='Lunch'>Lunch</option><option value='Dinner'>Dinner</option><option value='Evening Snack'>Evening Snack</option></select><input type='button' class='submitCopyFood' value='Add'> or <div style='display:inline' class='CancelCopy'>Cancel</div></form> "); it seems to work on the screen, but the button click "submitCopyFood" wasn't firing. When i click "View Selection Source" in firefox, i see the issue. All i see is this: <input name="Id" value="128" type="hidden"><input class="very-small-input" name="Quantity" value="1" type="text"> for <select name="Date"><option value="Today">Today</option><option value="Yesterday">Yesterday</option></select><select name="Meal"><option value="Breakfast">Breakfast</option><option value="Lunch">Lunch</option><option value="Dinner">Dinner</option><option value="Evening Snack">Evening Snack</option></select><input class="submitCopyFood" value="Add" type="button"> or <div style="display: inline;" class="CancelCopy">Cancel</div> Its like i never added the form anywhere. Is there any reason why i dont see the: <form action='/Tracker/CopyFood' method='post'> or the </form> in the source code inside the selected source. Is there something special that i need to do here?

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