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  • java.lang.NoClassDefFoundError

    - by Jenny
    Everything was working just fine but now I can no longer run my application. For some reason javax.* is not being found yet in Eclipse the imports are fine... exception javax.servlet.ServletException: Error allocating a servlet instance org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:857) org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) java.lang.Thread.run(Thread.java:619) root cause java.lang.NoClassDefFoundError: javax/servlet/http/HttpServlet java.lang.ClassLoader.defineClass1(Native Method) java.lang.ClassLoader.defineClassCond(ClassLoader.java:632) java.lang.ClassLoader.defineClass(ClassLoader.java:616) java.security.SecureClassLoader.defineClass(SecureClassLoader.java:141) java.net.URLClassLoader.defineClass(URLClassLoader.java:283) java.net.URLClassLoader.access$000(URLClassLoader.java:58) java.net.URLClassLoader$1.run(URLClassLoader.java:197) java.security.AccessController.doPrivileged(Native Method) java.net.URLClassLoader.findClass(URLClassLoader.java:190) java.lang.ClassLoader.loadClass(ClassLoader.java:307) sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) java.lang.ClassLoader.loadClass(ClassLoader.java:248) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1560) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1491) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:857) org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) java.lang.Thread.run(Thread.java:619) root cause java.lang.ClassNotFoundException: javax.servlet.http.HttpServlet java.net.URLClassLoader$1.run(URLClassLoader.java:202) java.security.AccessController.doPrivileged(Native Method) java.net.URLClassLoader.findClass(URLClassLoader.java:190) java.lang.ClassLoader.loadClass(ClassLoader.java:307) sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) java.lang.ClassLoader.loadClass(ClassLoader.java:248) java.lang.ClassLoader.defineClass1(Native Method) java.lang.ClassLoader.defineClassCond(ClassLoader.java:632) java.lang.ClassLoader.defineClass(ClassLoader.java:616) java.security.SecureClassLoader.defineClass(SecureClassLoader.java:141) java.net.URLClassLoader.defineClass(URLClassLoader.java:283) java.net.URLClassLoader.access$000(URLClassLoader.java:58) java.net.URLClassLoader$1.run(URLClassLoader.java:197) java.security.AccessController.doPrivileged(Native Method) java.net.URLClassLoader.findClass(URLClassLoader.java:190) java.lang.ClassLoader.loadClass(ClassLoader.java:307) sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) java.lang.ClassLoader.loadClass(ClassLoader.java:248) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1560) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1491) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:857) org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) java.lang.Thread.run(Thread.java:619)

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  • Should I have different models and views for no user data than for some user data?

    - by Sam Holder
    I'm just starting to learn asp.net mvc and I'm not sure what the right thing to do is. I have a user and a user has a collection of (0 or more) reminders. I have a controller for the user which gets the reminders for the currently logged in user from a reminder service. It populates a model which holds some information about the user and the collection of reminders. My question is should I have 2 different views, one for when there are no reminders and one for when there are some reminders? Or should I have 1 view which checks the number of reminders and displays different things? Having one view seems wrong as then I end up with code in my view which says if (Model.Reminders.Count==0){//do something} else {do something else}, and having logic in the view feels wrong. But if I want to have 2 different views then I'd like to have some code like this in my controller: [Authorize] public ActionResult Index() { MembershipUser currentUser = m_membershipService.GetUser(); IList<Reminder> reminders = m_reminderRepository.GetReminders(currentUser); if (reminders.Count == 0) { var model = new EmptyReminderModel { Email = currentUser.Email, UserName = currentUser.UserName }; return View(model); } else { var model = new ReminderModel { Email = currentUser.Email, UserName = currentUser.UserName, Reminders = reminders }; return View(model); } but obviously this doesn't compile as the View can't take both different types. So if I'm going to do this should I return a specific named view from my controller, depending on the emptiness of the reminders, or should my Index() method redirect to other actions like so: [Authorize] public ActionResult Index() { MembershipUser currentUser = m_membershipService.GetUser(); IList<Reminder> reminders = m_reminderRepository.GetReminders(currentUser); if (reminders.Count == 0) { return RedirectToAction("ShowEmptyReminders"); } else { return RedirectToAction("ShowReminders"); } } which seems nicer but then I need to re-query the reminders for the current user in the ShowReminders action. Or should I be doing something else entirely?

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  • Django's post_save signal behaves weirdly with models using multi-table inheritance

    - by hekevintran
    Django's post_save signal behaves weirdly with models using multi-table inheritance I am noticing an odd behavior in the way Django's post_save signal works when using a model that has multi-table inheritance. I have these two models: class Animal(models.Model): category = models.CharField(max_length=20) class Dog(Animal): color = models.CharField(max_length=10) I have a post save callback called echo_category: def echo_category(sender, **kwargs): print "category: '%s'" % kwargs['instance'].category post_save.connect(echo_category, sender=Dog) I have this fixture: [ { "pk": 1, "model": "animal.animal", "fields": { "category": "omnivore" } }, { "pk": 1, "model": "animal.dog", "fields": { "color": "brown" } } ] In every part of the program except for in the post_save callback the following is true: from animal.models import Dog Dog.objects.get(pk=1).category == u'omnivore' # True When I run syncdb and the fixture is installed, the echo_category function is run. The output from syncdb is: $ python manage.py syncdb --noinput Installing json fixture 'initial_data' from '~/my_proj/animal/fixtures'. category: '' Installed 2 object(s) from 1 fixture(s) The weird thing here is that the dog object's category attribute is an empty string. Why is it not 'omnivore' like it is everywhere else? As a temporary (hopefully) workaround I reload the object from the database in the post_save callback: def echo_category(sender, **kwargs): instance = kwargs['instance'] instance = sender.objects.get(pk=instance.pk) print "category: '%s'" % instance.category post_save.connect(echo_category, sender=Dog) This works but it is not something I like because I must remember to do it when the model inherits from another model and it must hit the database again. The other weird thing is that I must do instance.pk to get the primary key. The normal 'id' attribute does not work (I cannot use instance.id). I do not know why this is. Maybe this is related to the reason why the category attribute is not doing the right thing?

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  • getting proxies of the correct type in nhibernate

    - by Nir
    I have a problem with uninitialized proxies in nhibernate The Domain Model Let's say I have two parallel class hierarchies: Animal, Dog, Cat and AnimalOwner, DogOwner, CatOwner where Dog and Cat both inherit from Animal and DogOwner and CatOwner both inherit from AnimalOwner. AnimalOwner has a reference of type Animal called OwnedAnimal. Here are the classes in the example: public abstract class Animal { // some properties } public class Dog : Animal { // some more properties } public class Cat : Animal { // some more properties } public class AnimalOwner { public virtual Animal OwnedAnimal {get;set;} // more properties... } public class DogOwner : AnimalOwner { // even more properties } public class CatOwner : AnimalOwner { // even more properties } The classes have proper nhibernate mapping, all properties are persistent and everything that can be lazy loaded is lazy loaded. The application business logic only let you to set a Dog in a DogOwner and a Cat in a CatOwner. The Problem I have code like this: public void ProcessDogOwner(DogOwner owner) { Dog dog = (Dog)owner.OwnedAnimal; .... } This method can be called by many diffrent methods, in most cases the dog is already in memory and everything is ok, but rarely the dog isn't already in memory - in this case I get an nhibernate "uninitialized proxy" but the cast throws an exception because nhibernate genrates a proxy for Animal and not for Dog. I understand that this is how nhibernate works, but I need to know the type without loading the object - or, more correctly I need the uninitialized proxy to be a proxy of Cat or Dog and not a proxy of Animal. Constraints I can't change the domain model, the model is handed to me by another department, I tried to get them to change the model and failed. The actual model is much more complicated then the example and the classes have many references between them, using eager loading or adding joins to the queries is out of the question for performance reasons. I have full control of the source code, the hbm mapping and the database schema and I can change them any way I want (as long as I don't change the relationships between the model classes). I have many methods like the one in the example and I don't want to modify all of them. Thanks, Nir

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  • Syncing data between devel/live databases in Django

    - by T. Stone
    With Django's new multi-db functionality in the development version, I've been trying to work on creating a management command that let's me synchronize the data from the live site down to a developer machine for extended testing. (Having actual data, particularly user-entered data, allows me to test a broader range of inputs.) Right now I've got a "mostly" working command. It can sync "simple" model data but the problem I'm having is that it ignores ManyToMany fields which I don't see any reason for it do so. Anyone have any ideas of either how to fix that or a better want to handle this? Should I be exporting that first query to a fixture first and then re-importing it? from django.core.management.base import LabelCommand from django.db.utils import IntegrityError from django.db import models from django.conf import settings LIVE_DATABASE_KEY = 'live' class Command(LabelCommand): help = ("Synchronizes the data between the local machine and the live server") args = "APP_NAME" label = 'application name' requires_model_validation = False can_import_settings = True def handle_label(self, label, **options): # Make sure we're running the command on a developer machine and that we've got the right settings db_settings = getattr(settings, 'DATABASES', {}) if not LIVE_DATABASE_KEY in db_settings: print 'Could not find "%s" in database settings.' % LIVE_DATABASE_KEY return if db_settings.get('default') == db_settings.get(LIVE_DATABASE_KEY): print 'Data cannot synchronize with self. This command must be run on a non-production server.' return # Fetch all models for the given app try: app = models.get_app(label) app_models = models.get_models(app) except: print "The app '%s' could not be found or models could not be loaded for it." % label for model in app_models: print 'Syncing %s.%s ...' % (model._meta.app_label, model._meta.object_name) # Query each model from the live site qs = model.objects.all().using(LIVE_DATABASE_KEY) # ...and save it to the local database for record in qs: try: record.save(using='default') except IntegrityError: # Skip as the record probably already exists pass

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  • Convert a Relative URL to an Absolute URL in Actionscript / Flex

    - by Bear
    I am working with Flex, and I need to take a relative URL source property and convert it to an absolute URL before loading it. The specific case I am working with involves tweaking SoundEffect's load method. I need to determine if a file will be loaded from the local file system or over the network from looking at the source property, and the easiest way I've found to do this is to generate the absolute URL. I'm having trouble generating the absolute URL for sound effect in particular. Here were my initial thoughts, which haven't worked. Look for the DisplayObject that the Sound Effect targets, and use its loaderInfo property. The target is null when the SoundEffect loads, so this doesn't work. Look at FlexGlobals.topLevelApplication, at the url or loaderInfo properties. Neither of these are set, however. Look at the FlexGlobals.topLevelApplication.systemManager.loaderInfo. This was also not set. The SoundEffect.as code basically boils down to var url:String = "mySound.mp3"; /*>> I'd like to convert the URL to absolute form here and tweak it as necessary <<*/ var req:URLRequest = new URLRequest(url); var loader:Loader = new Loader(); loader.load(req); Does anyone know how to do this? Any help clarifying the rules of how relative urls are resolved for URLRequests in ActionScript would also be much appreciated. edit I would also be perfectly satisfied with some way to tell whether the url will be loaded from the local file system or over the network. Looking at an absolute URL it would just be easy to look at the prefix, like file:// or http://.

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  • Flash As3.0 PHP Variables?

    - by user311421
    Is it possible to make php variables public and accessible anywhere on the timeline? The script I included works fine if I set it as the document class only (it won't work if I try importing it). The variables pass the text to dynamic text fields on the main timeline. The problem: It will pull the information and display it when the SWF first loads but if I move to my second frame and then back it erases the information. It also will not pass any variables to the second frame. The only way to see the variables after going back to the first frame is to reload the whole SWF. I'm pretty much stuck at this point trying to make the variables persistent through all frames. this is my code: package { import flash.display.MovieClip; import flash.events.*; import flash.net.*; import flash.display.Stage; public class Main extends MovieClip { public function Main() { var request:URLRequest = new URLRequest("http://localhost/mytest2/dataLayer.php"); request.method = URLRequestMethod.GET; var loader:URLLoader = new URLLoader(); loader.dataFormat = URLLoaderDataFormat.VARIABLES; loader.addEventListener(Event.COMPLETE, completeHandler); loader.load(request); function completeHandler(evt:Event) { var username = evt.target.data.username; var pclass = evt.target.data.pclass; var hpoints = evt.target.data.hpoints; var spoints = evt.target.data.spoints; username_txt.text = username; class_txt.text = pclass; hpoints_txt.text = hpoints; spoints_txt.text = spoints; } } } }

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  • Castle Active Record - Working with the cache

    - by David
    Hi All, im new to the Castle Active Record Pattern and Im trying to get my head around how to effectivley use cache. So what im trying to do (or want to do) is when calling the GetAll, find out if I have called it before and check the cache, else load it, but I also want to pass a bool paramter that will force the cache to clear and requery the db. So Im just looking for the final bits. thanks public static List<Model.Resource> GetAll(bool forceReload) { List<Model.Resource> resources = new List<Model.Resource>(); //Request to force reload if (forceReload) { //need to specify to force a reload (how?) XmlConfigurationSource source = new XmlConfigurationSource("appconfig.xml"); ActiveRecordStarter.Initialize(source, typeof(Model.Resource)); resources = Model.Resource.FindAll().ToList(); } else { //Check the cache somehow and return the cache? } return resources; } public static List<Model.Resource> GetAll() { return GetAll(false); }

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  • GRID is not properly rendered in ExtJS 4 by using Store

    - by user548543
    Here is the Src code for HTML file <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4 /strict.dtd"> <html> <head> <title>MVC Architecture</title> <link rel="stylesheet" type="text/css" href="/bh/extjs/resources/css/ext-all.css" /> <script type="text/javascript" src="extjs/ext-debug.js"></script> <script type="text/javascript" src="Main.js"></script> </head> <body> </body> </html> File path: /bh/Main.js [Main File] Ext.require('Ext.container.Viewport'); Ext.application({ name: 'App', appFolder: 'app', controllers: ['UserController'], launch: function() { Ext.create('Ext.container.Viewport', { layout: 'border', items: [ { xtype: 'userList' } ] }); } }); File path: /app/controller/UserController.js [Controller] Ext.define('App.controller.UserController',{ extend: 'Ext.app.Controller', stores: ['UserStore'], models:['UserModel'], views:['user.UserList'], init: function() { this.getUserStoreStore().load(); } }); File path: /app/store/UserStore.js Ext.define('App.store.UserStore', { extend: 'Ext.data.Store', model: 'App.model.UserModel', proxy: { type: 'ajax', url: 'app/data/contact.json' } }); File path: /app/model/UserModel.js [Model] Ext.define('App.model.UserModel',{ extends:'Ext.data.Model', fields:[ {name: 'name', type: 'string'}, {name: 'age', type: 'string'}, {name: 'phone', type: 'string'}, {name: 'email', type: 'string'} ] }); File path: /app/view/UserList.js [View] Ext.define('App.view.user.UserList' ,{ extend: 'Ext.grid.Panel', alias:'widget.userList', title:'Contacts', region:'center', resizable:true, initComponent: function() { this.store = 'UserStore'; this.columns = [ {text: 'Name',flex:1,sortable: true,dataIndex: 'name'}, {text: 'Age',flex:1,sortable: true,dataIndex: 'age'}, {text: 'Phone',flex:1,sortable: true,dataIndex: 'phone'}, {text: 'Email',flex:1,sortable: true,dataIndex: 'email'} ]; this.callParent(arguments); } }); In fire bug it shows the JSON response as follows: [{ "name": "Aswini", "age": "32", "phone": "555-555-5555", "email": "[email protected]" }] Why the Data has not been displayed although I have a valid json response. Please help!!!

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  • Django: Save data from form in DB

    - by Anry
    I have a model: class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() For the model I created a class form: class CostForm(ModelForm): class Meta: model = Cost fields = ['date', 'cost'] view.py: def cost(request, offset): if request.method == 'POST': #HOW save data in DB? return HttpResponseRedirect('/') else: form = CostForm() In the template file determined: <form action="/cost/{{ project }}/" method="post" accept-charset="utf-8"> <label for="date">Date:</label><input type="text" name="date" value={{ current_date }} id="date" /> <label for="cost">Cost:</label><input type="text" name="cost" value="0" id="cost" /> <p><input type="submit" value="Add"></p> </form> How save data from form in DB? P.S. offset = project name Model: class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) timestamp = models.DateTimeField() I tried to write: def cost(request, offset): if request.method == 'POST': form = CostForm(request.POST) if form.is_valid(): instance = form.save(commit=False) instance.project = Project.objects.filter(title=offset) instance.date = request.date instance.cost = request.cost instance.save() return HttpResponseRedirect('/') else: form = CostForm() But it does not work :(

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  • jboss Resteasy for java 5

    - by Anand
    Is there a resteasy version that runs on jdk 5 enviroment? I tried to compile my code in java 5 but it didnot work saying version problem. Is there a solution here? type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception javax.servlet.ServletException: Error instantiating servlet class org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:174) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:879) org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81) org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689) java.lang.Thread.run(Thread.java:595) root cause java.lang.UnsupportedClassVersionError: Bad version number in .class file (unable to load class javax.ws.rs.core.UriInfo) org.apache.catalina.loader.WebappClassLoader.findClassInternal(WebappClassLoader.java:1964) org.apache.catalina.loader.WebappClassLoader.findClass(WebappClassLoader.java:933) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1405) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1284) java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) java.lang.Class.getDeclaredConstructors0(Native Method) java.lang.Class.privateGetDeclaredConstructors(Class.java:2357) java.lang.Class.getConstructor0(Class.java:2671) java.lang.Class.newInstance0(Class.java:321) java.lang.Class.newInstance(Class.java:303) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:174) org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:879) org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81) org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689) java.lang.Thread.run(Thread.java:595) note The full stack trace of the root cause is available in the Apache Tomcat/5.5.31 logs.

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  • View Models (ViewData), UserControls/Partials and Global variables - best practice?

    - by elado
    Hi I'm trying to figure out a good way to have 'global' members (such as CurrentUser, Theme etc.) in all of my partials as well as in my views. I don't want to have a logic class that can return this data (like BL.CurrentUser) I do think it needs to be a part of the Model in my views So I tried inheriting from BaseViewData with these members. In my controllers, in this way or another (a filter or base method in my BaseController), I create an instance of the inheriting class and pass it as a view data. Everything's perfect till this point, cause then I have my view data available on the main View with the base members. But what about partials? If I have a simple partial that needs to display a blog post then it looks like this: <%@ Control Language="C#" AutoEventWireup="true" Inherits="ViewUserControl<Post>" %> and simple code to render this partial in my view (that its model.Posts is IEnumerable<Post>): <%foreach (Post p in this.Model.Posts) {%> <%Html.RenderPartial("Post",p); %> <%}%> Since the partial's Model isn't BaseViewData, I don't have access to those properties. Hence, I tried to make a class named PostViewData which inherits from BaseViewData, but then my containing views will have a code to actually create the PostViewData in them in order to pass it to the partial: <%Html.RenderPartial("Post",new PostViewData { Post=p,CurrentUser=Model.CurrentUser,... }); %> Or I could use a copy constructor <%Html.RenderPartial("Post",new PostViewData(Model) { Post=p }); %> I just wonder if there's any other way to implement this before I move on. Any suggestions? Thanks!

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  • How should backbone.js handle a GET request that returns no results?

    - by Nyxynyx
    I have a number of text input elements that when its values are changed, will trigger a fetch on listingListView's collection listingCollection, which then updates listingListView with the new data via the function listingListView.refreshList as shown below. I am using PHP/Codeigniter to expose a RESTful API. Problem: Everything works fine if there are results retrieved from the fetch(). However, when the filters results in no result being returned, how should the server side and the client side handle it? Currently Chrome's javascript console displays a 404 error and in the Network tab, the XHR request is highlighted in red. All I want to do in the event of zero results returned, is to blank the listingListView and show a message like (No results returned) and not throw any errors in the javascript console. Thanks! PHP Code function listings_get() { // Get filters $price_min = $this->get('price_min'); $this->load->model('app_model'); $results = $this->app_model->get_listings($price_min); if($results) $this->response($results); else $this->response(NULL); } JS Code window.ListingListView = Backbone.View.extend({ tagName: 'table', initialize: function() { this.model.bind('reset', this.refreshList, this); this.model.bind('add', function(listing) { $(this.el).append(new ListingListItemView({ model: listing }).render().el); }, this); }, render: function() { _.each(this.model.models, function(listing) { $(this.el).append(new ListingListItemView({ model: listing }).render().el); }, this); return this; }, close: function() { $(this.el).unbind(); $(this.el).empty(); }, refreshList: function() { $(this.el).empty(); this.render(); } });

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  • django: control json serialization

    - by abolotnov
    Is there a way to control json serialization in django? Simple code below will return serialized object in json: co = Collection.objects.all() c = serializers.serialize('json',co) The json will look similar to this: [ { "pk": 1, "model": "picviewer.collection", "fields": { "urlName": "architecture", "name": "\u0413\u043e\u0440\u043e\u0434 \u0438 \u0430\u0440\u0445\u0438\u0442\u0435\u043a\u0442\u0443\u0440\u0430", "sortOrder": 0 } }, { "pk": 2, "model": "picviewer.collection", "fields": { "urlName": "nature", "name": "\u041f\u0440\u0438\u0440\u043e\u0434\u0430", "sortOrder": 1 } }, { "pk": 3, "model": "picviewer.collection", "fields": { "urlName": "objects", "name": "\u041e\u0431\u044a\u0435\u043a\u0442\u044b \u0438 \u043d\u0430\u0442\u044e\u0440\u043c\u043e\u0440\u0442", "sortOrder": 2 } } ] You can see it's serializing it in a way that you are able to re-create the whole model, shall you want to do this at some point - fair enough, but not very handy for simple JS ajax in my case: I want bring the traffic to minimum and make the whole thing little clearer. What I did is I created a view that passes the object to a .json template and the template will do something like this to generate "nicer" json output: [ {% if collections %} {% for c in collections %} {"id": {{c.id}},"sortOrder": {{c.sortOrder}},"name": "{{c.name}}","urlName": "{{c.urlName}}"}{% if not forloop.last %},{% endif %} {% endfor %} {% endif %} ] This does work and the output is much (?) nicer: [ { "id": 1, "sortOrder": 0, "name": "????? ? ???????????", "urlName": "architecture" }, { "id": 2, "sortOrder": 1, "name": "???????", "urlName": "nature" }, { "id": 3, "sortOrder": 2, "name": "??????? ? ?????????", "urlName": "objects" } ] However, I'm bothered by the fast that my solution uses templates (an extra step in processing and possible performance impact) and it will take manual work to maintain shall I update the model, for example. I'm thinking json generating should be part of the model (correct me if I'm wrong) and done with either native python-json and django implementation but can't figure how to make it strip the bits that I don't want. One more thing - even when I restrict it to a set of fields to serialize, it will keep the id always outside the element container and instead present it as "pk" outside of it.

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  • Managing inverse relationships without CoreData

    - by Nathaniel Martin
    This is a question for Objective-J/Cappuccino, but I added the cocoa tag since the frameworks are so similar. One of the downsides of Cappuccino is that CoreData hasn't been ported over yet, so you have to make all your model objects manually. In CoreData, your inverse relationships get managed automatically for you... if you add an object to a to-many relationship in another object, you can traverse the graph in both directions. Without CoreData, is there any clean way to setup those inverse relationships automatically? For a more concrete example, let's take the typical Department and Employees example. To use rails terminology, a Department object has-many Employees, and an Employee belongs-to a Department. So our Department model has an NSMutableSet (or CPMutableSet ) "employees" that contains a set of Employees, and our Employee model has a variable "department" that points back to the Department model that owns it. Is there an easy way to make it so that, when I add a new Employee model into the set, the inverse relationship (employee.department) automatically gets set? Or the reverse: If I set the department model of an employee, then it automatically gets added to that department's employee set? Right know I'm making an object, "ValidatedModel" that all my models subclass, which adds a few methods that setup the inverse relationships, using KVO. But I'm afraid that I'm doing a lot of pointless work, and that there's already an easier way to do this. Can someone put my concerns to rest?

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  • GWT RPC and GoDaddy Shared Hosting

    - by Mike Apolis
    Hi, I've deployed the sample Stock Watcher app to my GoDaddy Hosting site, and I get the error below. I've tried compiling the Project in Eclipse with JRE 1.5 because my Host is using jre 1.5. I think the issue is the "gwt-servlet.jar" is not compatible with jre 1.5. Can anyone confirm this. The project runs fine on my local machine using JRE 1.6. Unfortunately GoDaddy will not upgrade my shared hosting account jre to 1.6. GoDaddy Server Setup: Tomcat Version 5.0.27 JRE 1.5_22 Error: HTTP Status 500 - type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception javax.servlet.ServletException: Error allocating a servlet instance org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java: 117) org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java: 535) org.apache.catalina.authenticator.SingleSignOn.invoke(SingleSignOn.java: 417) org.apache.coyote.tomcat5.CoyoteAdapter.service(CoyoteAdapter.java: 160) org.apache.jk.server.JkCoyoteHandler.invoke(JkCoyoteHandler.java:300) org.apache.jk.common.HandlerRequest.invoke(HandlerRequest.java:374) org.apache.jk.common.ChannelSocket.invoke(ChannelSocket.java:743) org.apache.jk.common.ChannelSocket.processConnection(ChannelSocket.java: 675) org.apache.jk.common.SocketConnection.runIt(ChannelSocket.java:866) org.apache.tomcat.util.threads.ThreadPool $ControlRunnable.run(ThreadPool.java:683) java.lang.Thread.run(Thread.java:595) root cause java.lang.UnsupportedClassVersionError: Bad version number in .class file java.lang.ClassLoader.defineClass1(Native Method) java.lang.ClassLoader.defineClass(ClassLoader.java:621) java.security.SecureClassLoader.defineClass(SecureClassLoader.java: 124) org.apache.catalina.loader.WebappClassLoader.findClassInternal(WebappClassLoader.java: 1634) org.apache.catalina.loader.WebappClassLoader.findClass(WebappClassLoader.java: 860) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java: 1307) org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java: 1189) java.security.AccessController.doPrivileged(Native Method) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java: 117) org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java: 535) org.apache.catalina.authenticator.SingleSignOn.invoke(SingleSignOn.java: 417) org.apache.coyote.tomcat5.CoyoteAdapter.service(CoyoteAdapter.java: 160) org.apache.jk.server.JkCoyoteHandler.invoke(JkCoyoteHandler.java:300) org.apache.jk.common.HandlerRequest.invoke(HandlerRequest.java:374) org.apache.jk.common.ChannelSocket.invoke(ChannelSocket.java:743) org.apache.jk.common.ChannelSocket.processConnection(ChannelSocket.java: 675) org.apache.jk.common.SocketConnection.runIt(ChannelSocket.java:866) org.apache.tomcat.util.threads.ThreadPool $ControlRunnable.run(ThreadPool.java:683) java.lang.Thread.run(Thread.java:595) note The full stack trace of the root cause is available in the Apache Tomcat/5.0.27 logs. Apache Tomcat/5.0.27

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  • Ruby on Rails Associations

    - by Eef
    Hey all, I am starting to create my sites in Ruby on Rails these days instead of PHP. I have picked up the language easily but still not 100% confident with associations :) I have this situation: User Model has_and_belongs_to_many :roles Roles Model has_and_belongs_to_many :users Journal Model has_and_belongs_to_many :roles So I have a roles_users table and a journals_roles table I can access the user roles like so: user = User.find(1) User.roles This gives me the roles assigned to the user, I can then access the journal model like so: journals = user.roles.first.journals This gets me the journals associated with the user based on the roles. I want to be able to access the journals like so user.journals In my user model I have tried this: def journals self.roles.collect { |role| role.journals }.flatten end This gets me the journals in a flatten array but unfortunately I am unable to access anything associated with journals in this case, e.g in the journals model it has: has_many :items When I try to access user.journals.items it does not work as it is a flatten array which I am trying to access the has_many association. Is it possible to get the user.journals another way other than the way I have shown above with the collect method? Hope you guys understand what I mean, if not let me know and ill try to explain it better. Cheers Eef

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  • Hashing the state of a complex object in .NET

    - by Jan
    Some background information: I am working on a C#/WPF application, which basically is about creating, editing, saving and loading some data model. The data model contains of a hierarchy of various objects. There is a "root" object of class A, which has a list of objects of class B, which each has a list of objects of class C, etc. Around 30 classes involved in total. Now my problem is that I want to prompt the user with the usual "you have unsaved changes, save?" dialog, if he tries to exit the program. But how do I know if the data in current loaded model is actually changed? There is of course ways to solve this, like e.g. reloading the model from file and compare against the one in memory value by value or make every UI control set a flag indicating the model has been changed. Now instead, I want to create a hash value based on the model state on load and generate a new value when the user tries to exit, and compare those two. Now the question: So inspired of that, I was wondering if there exist some way to generate a hash value from the (value)state of some arbitrary complex object? Preferably in a generic way, e.g. no need to apply attributes to each involved class/field. One idea could be to use some of .NET's serialization functionality (assuming it will work out-of-the-box in this case) and apply a hash function to the content of the resulting file. However, I guess there exist some more suitable approach. Thanks in advance.

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  • JSP: Refresh ComboBox options

    - by framara
    Hi, There's a class 'Car' with brand and model as properties. I have a list of items of this class List<Car> myCars. I need to represent in a JSP website 2 ComboBox, one for brand and another for model, that when you select the brand, in the model list only appear the ones from that brand. I don't know how to do this in a dynamic way. Any suggestion where to start? Thanks Update Ok, what I do now is send in the request a list with all the brand names, and a list of the items. The JSP code is like: <select name="manufacturer" id="id_manufacturer" onchange="return getManufacturer();"> <option value=""></option> <c:forEach items="${manufacturers}" var="man"> <option value="${man}" >${man}</option> </c:forEach> </select> <select name="model" id="id_model"> <c:forEach items="${mycars}" var="car"> <c:if test="${car.manufacturer eq man_selected}"> <option value="${car.id}">${car.model}</option> </c:if> </c:forEach> </select> <script> function getManufacturer() { man_selected = document.getElementById('id_manufacturer').value; } </script> How do I do to refresh the 'model' select options according to the selected 'man_selected' ?

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  • How do I fully reload my Sencha Touch App when tapping 'refresh'?

    - by torr
    My list view layout is similar to Pinterest, with absolutely positioned blocks. Unfortunately, this seems to require a full re-initialization at refresh. If reload only the store (as below) the new blocks are incorrectly positioned. How do I reload the app when the user clicks on refresh? This is my View: Ext.require(['Ext.data.Store', 'MyApp.model.StreamModel'], function() { Ext.define('MyApp.view.HomeView', { extend: 'Ext.navigation.View', xtype: 'homepanel', requires: [ 'Ext.dataview.List', ], config: { title: 'Home', iconCls: 'home', styleHtmlContent: true, navigationBar: { items: [ { xtype: 'button', iconMask: true, iconCls: 'refresh', align: 'left', action: 'refreshButton' } ] }, items: { title: 'My', xtype: 'list', itemTpl: [ '<div class="post">', ... '</div>' ].join(''), store: new Ext.data.Store({ model: 'MyApp.model.StreamModel', autoLoad: true, storeId: 'stream' }), } } }); }); Model: Ext.define('MyApp.model.StreamModel', { extend: 'Ext.data.Model', config: { fields: [ 'post_id', 'comments' ], proxy: { type: 'jsonp', url: 'http://My.com/app', reader: { type: 'json', } } } }); and my Controller: Ext.define('MyApp.controller.RefreshController', { extend: 'Ext.app.Controller', requires: [ 'Ext.navigation.View' ], config: { control: { 'button[action=refreshButton]': { tap: 'refresh' } } }, refresh: function() { // Ext.StoreMgr.get('stream').load(); // here I'd like to reload the app instead // not just the store } });

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  • Django filters - Using an AllValuesFilter (with a LinkWidget) on a ManyToManyField

    - by magnetix
    This is my first Stack Overflow question, so please let me know if I do anything wrong. I wish to create an AllValues filter on a ManyToMany field using the wonderful django-filters application. Basically, I want to create a filter that looks like it does in the Admin, so I also want to use the LinkWidget too. Unfortunately, I get an error (Invalid field name: 'operator') if I try this the standard way: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class SignFilter(LinkOrderFilterSet): operator = django_filters.AllValuesFilter(widget=django_filters.widgets.LinkWidget) class Meta: model = Sign fields = ['operator'] I got around this by creating my own filter with the many to many relationship hard coded: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class MyFilter(django_filters.ChoiceFilter): @property def field(self): cd = {} for row in self.model.objects.all(): orgs = row.operator.select_related().values() for org in orgs: cd[org['id']] = org['name'] choices = zip(cd.keys(), cd.values()) list.sort(choices, key=lambda x:(x[1], x[0])) self.extra['choices'] = choices return super(AllValuesFilter, self).field class SignFilter(LinkOrderFilterSet): operator = MyFilter(widget=django_filters.widgets.LinkWidget) I am new to Python and Django. Can someone think of a more generic/elegant way of doing this?

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  • HOWTO: implement a jQuery version of ASP.Net MVC "Strongly Typed Partial Views"

    - by Sam Carleton
    I am working on a multi-page assessment form where the questions/responses are database driven. Currently I the basic system working with Html.BeginForm via standard ASP.Net MVC. At this point in time, the key to the whole system is the 'Strongly Typed Partial Views'. When the question/response is read from the database, the response type determines which derived model is created and added to the collection. The main view it iterates through the collection and uses the 'Strongly Typed Partial Views' system of ASP.Net MVC to determine which view to render the correct type of response (radio button, drop down, or text box). I would like to change this process from a Html.BeginForm to Ajax.BeginForm. The problem is I don't have a clue as to how to implement the dynamic creation of the question/response in the JavaScript/jQuery world. Any thoughts and/or suggestions? Here is the current code to generate the dynamic form: @using (Html.BeginForm(new { mdsId = @Model.MdsId, sectionId = @Model.SectionId })) { <div class="SectionTitle"> <span>Section @Model.SectionName - @Model.SectionDescription</span> <span style="float: right">@Html.CheckBoxFor(x => x.ShowUnansweredQuestions) Show only unaswered questions</span> </div> @Html.HiddenFor(x => x.PrevSectionId) @Html.HiddenFor(x => x.NextSectionId) for (var i = 0; i < Model.answers.Count(); i++) { @Html.EditorFor(m => m.answers[i]); } }

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  • "loading" div automatically appended when using cordova (phonegap)

    - by Vlad Ioffe
    I am using cordova for mobile app development on android platform. I have this html code in www/index.html file: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <meta http-equiv="Content-Language" content="en" /> <script src="cordova-2.2.0.js" type="text/javascript"></script> <script src="jquery/jquery.js" type="text/javascript"></script> <script src="jquery.mobile/jquery.mobile-1.1.0.js" type="text/javascript"></script> <script src="JS/main.js" type="text/javascript"></script> <link rel="stylesheet" href="CSS/main.css"/> </head> <body id="body" class="body"> <div id="box" class="bodyBlack"> </div> </body> </html> I don't know why but when I am running this app (also when just opening on pc browser) i am having this div appended at the bottom of the page: <div ui-loader ui-corner-all ui-body-a ui-loader-default> <span ui-loader ui-corner-all ui-body-a ui-loader-default></span> <h1>loading</h1> Why and from where dose it getting from? how I am preventing it to do so? Thanks!!!

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  • Regarding the ViewModel

    - by mizipzor
    Im struggling to understand the ViewModel part of the MVVM pattern. My current approach is to have a class, with no logic whatsoever (important), except that it implements INotifyPropertyChanged. The class is just a collection of properties, a struct if you like, describing an as small part of the data as possible. I consider this my Model. Most of the WPF code I write are settings dialogs that configure said Model. The code-behind of the dialog exposes a property which returns an instance of the Model. In the XAML code I bind to subproperties of that property, thereby binding directly to the Model's properties. Which works quite well since it implements the INotifyPropertyChanged. I consider this settings dialog the View. However, I havent really been able to figure out what in all this is the ViewModel. The articles Ive read suggests that the ViewModel should tie the View and the Model together, providing the logic the Model lacks but is still to complex to go directly into the View. Is this correct? Would, in my example, the code-behind of the settings dialog be considered the ViewModel? I just feel a bit lost and would like my peers to debunk some of my assumptions. Am I completely off track here?

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  • how to validate the dropdownlist box values on submit

    - by kumar
    Hello friends, I have validate_excpt on Form Before Submit I am doing this.. on the View I have two dropdown listboxes I am using On Submit I need to check.. If I selet ResolutionCode I need to validat ReasonCode Dropdownlist that It should select if not Pelase select ReasonCode I should Dispaly? Do I need to do this on Submit ButtonClick? or Can I do it on Validate_excpt? Can anybody help me out? <label for="ResolutionCode"> Resolution: <span> <%=Html.DropDownListFor(model => model.ResolutionCode, new SelectList(Model.LookupCodes["C_EXCPT_RESL"], "Key", "Value"))%> </span> </label> <label for="ReasonCode"> Reason: <span><%=Html.DropDownListFor(model => model.ReasonCode, new SelectList(Model.LookupCodes["C_EXCPT_RSN"], "Key", "Value"))%></span> </label> function validate_excpt(formData, jqForm, options) { var form = jqForm[0]; return true; } // post-submit callback function showResponse(responseText, statusText, xhr, $form) { if (responseText[0].substring(0, 16) != "System.Exception") { $('#error-msg-ID span:last').html('<strong>Update successful.</strong>'); } else { $('#error-msg-ID span:last').html('<strong>Update failed.</strong> ' + responseText[0].substring(0, 48)); } $('#error-msg-ID').removeClass('hide'); } $('#exc-').ajaxForm({ target: '#error-msg-ID', beforeSubmit: validate_excpt, success: showResponse, dataType: 'json' });

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