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• Remote interface lookup-problem in Glassfish3

  - by andersmo

  I have deployed a war-file, with actionclasses and a facade, and a jar-file with ejb-components (a stateless bean, a couple of entities and a persistence.xml) on glassfish3. My problem is that i cant find my remote interface to the stateless bean from my facade. My bean and interface looks like: @Remote public interface RecordService {... @Stateless(name="RecordServiceBean", mappedName="ejb/RecordServiceJNDI") public class RecordServiceImpl implements RecordService { @PersistenceContext(unitName="record_persistence_ctx") private EntityManager em;... and if i look in the server.log the portable jndi looks like: Portable JNDI names for EJB RecordServiceBean : [java:global/recordEjb/RecordServiceBean, java:global/recordEjb/RecordServiceBean!domain.service.RecordService]|#] and my facade: ...InitialContext ctx= new InitialContext(); try{ recordService = (RecordService) ctx.lookup("java:global/recordEjb/RecordServiceBean!domain.service.RecordService"); } catch(Throwable t){ System.out.println("ooops"); try{ recordService = (RecordService)ctx.lookup("java:global/recordEjb/RecordServiceImpl"); } catch(Throwable t2){ System.out.println("noooo!"); }... } and when the facade makes the first call this exception occur: javax.naming.NamingException: Lookup failed for 'java:global/recordEjb/RecordServiceBean!domain.service.RecordService' in SerialContext [Root exception is javax.naming.NamingException: ejb ref resolution error for remote business interfacedomain.service.RecordService [Root exception is java.lang.ClassNotFoundException: domain.service.RecordService]] and the second call: javax.naming.NamingException: Lookup failed for 'java:global/recordEjb/RecordServiceBean' in SerialContext [Root exception is javax.naming.NamingException: ejb ref resolution error for remote business interfacedomain.service.RecordService [Root exception is java.lang.ClassNotFoundException: domain.service.RecordService]] I have also tested to inject the bean with the @EJB-annotation: @EJB(name="RecordServiceBean") private RecordService recordService; But that doesnt work either. What have i missed? I tried with an ejb-jar.xml but that shouldnt be nessesary. Is there anyone who can tell me how to fix this problem?

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• Django Many-to-Many Question

  - by DZ

  My questions seems like a common problem that when I have seen any questions on it is never really asked right or not answered. So Im going to try to get the question right, and maybe someone knows how to resolve the issue, or correct my understanding. The problem: When you have a many-to-many relation ship (related_name not through) and you are trying to use the admin interface you are required to input one of the rleationships even though it does not have to exsist for you to create the first entry. Meaning you have to assign a group to an event to create the group. Wow that sounds complicated. So I can see why the question is not getting answered. Lets try the non code explanation example... First and important versions: Django 1.1.1 Phython 2.6 So I have a model where I created a many-to-many realtionship and Im using the related_name Im creating an app that is an event organizer, for simplicty lets say events although they could be anytype). For this first post Im going to stay away from the code and just try to explain. A few keys: (explaining comment) ** - many-to-many So in the model we have 1) The Main Event (this is main model) 2) Groups (link to events and their can be many events for a group) a) Events** I have simplified this example a little becuase I recognize that what does it matter. Just create the event first... But there are specific varations where that will not work. What the many-to-many related_name does it created another table with the indecies of the two other tables. Nothing says that this extra table HAS to be populated. Becuase if I look in the database and work within myPHPadmin I can create a group with out registering an event, since the connection between the two is a seperate table the DB does not care. How do I make the admin interface this realize it? Ok I know thats a lot so I hope I have explained it clearly. Thank you anyone for your comments/thoughts/advice

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• Book/topic recommendations for a programmer returning to programming.

  - by Jason Tan

  I used to be a developer in Java, PHP, perl and C/C++ (the C++ bit badly - the others not too badly, I hope). This was back in the Java 1.3/1.4 days. We used raw JDBC, swing, servlets, JSP and ant (sometimes even make). Eclipse was new. Then I joined a deployment team and became a deployment engineer and then after the deployment engineer work became a full time sys admin.You get the idea - my experience is a generation or two old in programming terms - maybe older. I'm interested in getting back into Java and perhaps Ruby development, but feel I will be waaaaay behind the technological 8 ball. Can you folks suggest some books (or sites) that would be worth reading to catch up with the last 5-10 years of the development world. I.e. what should I read to try and catch up with where development is now? I see lots of stuff on the web, but what are people in the fabled "real world" using? (are lots of people being SOA based apps? Are they using XP methodology) The sorts of things I'm interested in finding out about/catching up on are: Methodologies Design patterns APIs/Frameworks/Technologies Other stuff you deem current/interesting/relevant. So if you have any thoughts or can recommend any books (especially new classics - you know the 's equivalent to K&R C or "The mythical man month"). Thanks for any thoughts you might share.

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• Move and rename file in android

  - by Andre Fróes

  I am trying to copy a file to another folder in the android, but so far, i got no success. I manage to do so with a selected image and when taking a photo, but not with files. I've read and tried several solutions passed by the community (searched over the forum and the internet), but none of it was able to solve my problem when copying. First things first. I added the permissions to my manifest: <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" /> <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" /> after that, before copying a file, i print its filepath and the directory file path: 06-10 11:11:11.700: I/System.out(1442): /mimetype/storage/sdcard/Misc/Javascript erros for Submit and Plan buttons in IE.doc 06-10 11:11:11.710: I/System.out(1442): /storage/sdcard/mywfm/checklist-files both exists: to copy the file to the expected folder I used the FileUtils: try { FileUtils.copyFile(selectedFile, dir); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } The problem is: I get no exception and the file isn't there. I tried this solution either: How to move/rename file from internal app storage to external storage on Android? same thing, no exception, but no file either.

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• When Creating a Reference for an Object Where from where that class is Loaded?

  - by asela38

  When doing some sample codings with Java I came crosss ClassCast Exception, from where I cast the object to StaticClass. Can any explaing the what has happened here. public void test5() throws Exception { System.out.println(StaticClass.obj); Object newInstance = ClassLoader.getSystemClassLoader().loadClass("com.StaticClass").newInstance(); System.out.println(newInstance.getClass().getDeclaredField("obj").get(newInstance)); Object newInstance2 = new ILoader().loadClass("com//StaticClass.class").newInstance(); System.out.println(newInstance2.getClass().getDeclaredField("obj").get(newInstance2)); StaticClass s = (StaticClass)newInstance2; System.out.println(s.obj); System.out.println(newInstance.getClass().getClassLoader()); System.out.println(newInstance2.getClass().getClassLoader()); } package com; public class StaticClass { public static final Object obj = new Object(); } package com; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; public class ILoader extends ClassLoader { public ILoader() { super(null); } @Override protected Class<?> findClass(String name) throws ClassNotFoundException { File file = new File(name); byte[] bytes = new byte[(int)file.length()]; try { new FileInputStream(file).read(bytes); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return super.defineClass("com.StaticClass",bytes, 0, bytes.length); } } output which was given by last sysout's when the casting part of the code not existed is as belows. sun.misc.Launcher$AppClassLoader@133056f com.ILoader@1ac3c08

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• how to add data in Table of Jasper Report using Java

  - by Areeb Gillani

  i am here to ask you just a simple question that i am trying to pass data to a jasper report using java but i dont know how to to, because the table data is very dynamic thats y cannot pass sql query. any idea for this. i have a 2D array of object type, where i have all the data... so how can i pass that... Thanx in advance...!:) ConnectionManager con = new ConnectionManager(); con.establishConnection(); String fileName = "Pmc_Bill.jrxml"; String outFileName = "OutputReport.pdf"; HashMap params = new HashMap(); params.put("PName", pname); params.put("PSerial", psrl); params.put("PGender",pgen); params.put("PPhone",pph); params.put("PAge",page); params.put("PRefer",pref); params.put("PDateR",dateNow); try { JasperReport jasperReport = JasperCompileManager.compileReport(fileName); if(jasperReport != null ) System.out.println("so far so good "); // Fill the report using an empty data source JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, new JRTableModelDataSource(tbl.getModel()));//con.connection); try{ JasperExportManager.exportReportToPdfFile(jasperPrint, outFileName); System.out.printf("File exported sucessfully"); }catch(Exception e){ e.printStackTrace(); } JasperViewer.viewReport(jasperPrint); } catch (JRException e) { JOptionPane.showMessageDialog(null, e); e.printStackTrace(); System.exit(1); }

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• How would I authenticate against a local windows user on another machine in an ASP.NET application?

  - by Daniel Chambers

  In my ASP.NET application, I need to be able to authenticate/authorise against local Windows users/groups (ie. not Active Directory) on a different machine, as well as be able to change the passwords of said remote local Windows accounts. Yes, I know Active Directory is built for this sort of thing, but unfortunately the higher ups have decreed it needs to be done this way (so authentication against users in a database is out as well). I've tried using DirectoryEntry and WinNT like so: DirectoryEntry user = new DirectoryEntry(String.Format("WinNT://{0}/{1},User", serverName, username), username, password, AuthenticationTypes.Secure) but this results in an exception when you try to log in more than one user: Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again. I've tried making sure my DirectoryEntries are used inside a using block, so they're disposed properly, but this doesn't seem to fix the issue. Plus, even if that did work it is possible that two users could hit that line of code concurrently and therefore try to create multiple connections, so it would be fragile anyway. Is there a better way to authenticate against local Windows accounts on a remote machine, authorise against their groups, and change their passwords? Thanks for your help in advance.

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• What are the interets of synthetic methods?

  - by romaintaz

  Problem One friend suggested an interesting problem. Given the following code: public class OuterClass { private String message = "Hello World"; private class InnerClass { private String getMessage() { return message; } } } From an external class, how may I print the message variable content? Of course, changing the accessibility of methods or fields is not allowed. (the source here, but it is a french blog) Solution The code to solve this problem is the following: try { Method m = OuterClass.class.getDeclaredMethod("access$000", OuterClass.class); OuterClass outerClass = new OuterClass(); System.out.println(m.invoke(outerClass, outerClass)); } catch (Exception e) { e.printStackTrace(); } Note that the access$000 method name is not really standard (even if this format is the one that is strongly recommanded), and some JVM will name this method access$0. Thus, a better solution is to check for synthetic methods: Method method = null; int i = 0; while ((method == null) && (i < OuterClass.class.getDeclaredMethods().length)) { if (OuterClass.class.getDeclaredMethods()[i].isSynthetic()) { method = OuterClass.class.getDeclaredMethods()[i]; } i++; } if (method != null) { try { System.out.println(method.invoke(null, new OuterClass())); } catch (Exception e) { e.printStackTrace(); } } So the interesting point in this problem is to highlight the use of synthetic methods. With these methods, I can access a private field as it was done in the solution. Of course, I need to use reflection, and I think that the use of this kind of thing can be quite dangerous... Question What is the interest - for me, as a developer - of a synthetic method? What can be a good situation where using the synthetic can be useful?

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• Storing Result set into an array

  - by OVERTONE

  i know this should be simpel and im probably staring straight at the problem but once again im stuck and need the help of the code gurus. im trying too take one row from a column in jdbc, and put them in an array. i do this as follows: public void fillContactList() { createConnection(); try { Statement stmt = conn.createStatement(); ResultSet namesList = stmt.executeQuery("SELECT name FROM Users"); try { while (namesList.next()) { contactListNames[1] = namesList.getString(1); System.out.println("" + contactListNames[1]); } } catch(SQLException q) { } conn.commit(); stmt.close(); conn.close(); } catch(SQLException e) { } creatConnection is an already defined method that does what it obviously does. i creat my result set while theres another one, i store the string of that column into an array. then print it out for good measure. too make sure its there. the problem is that its storing the entire column into contactListNames[1] i wanted to make it store column1 row 1 into [1] then column 1 row 2 into [2] i know i could do this with a loop. but i dont know too take only one row at a time from a single column. any ideas? p.s ive read the api, i jsut cant see anything that fits.

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• Data confusion - Selecting data in one DataGridView based on selection in another

  - by Logan Young

  This probably isn't the best way to do what I want, but I can't think of anything else to try... NB: I'm using Visual Basic.NET My form has 2 DataGridView controls. One of these is bound to a DataSet, the other isn't visible - at least not until the user selects a uniqueidentifier cell in the 1st grid. When the user makes this selection, the 2nd grid will become visible and display the row from another with the same id as the one selected in the 1st grid. So, basically, I want to dynamically display data in one grid based on user selection in another grid. My code looks like this so far... Private Sub RulesGrid_CellClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles RulesGrid.CellClick Try FlagsGrid.Visible = True ''// MsgBox(RulesGrid.CurrentCell.Value.ToString()) Dim sql As String = "SELECT * FROM ctblMKA_Status_Flags " + _ "WHERE intStatusID = '" & RulesGrid.CurrentCell.Value & "'" DSFlags = GetDS(sql) DSFlags.DataSetName = "FlagsDataSet" FlagsGrid.DataSource = DSFlags ProgressBar.Visible = False Catch ex As Exception MsgBox(ex.ToString) End Try End Sub I feel like I'm missing something here... Any ideas anyone?

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• Haskell: Dealing With Types And Exceptions

  - by Douglas Brunner

  I'd like to know the "Haskell way" to catch and handle exceptions. As shown below, I understand the basic syntax, but I'm not sure how to deal with the type system in this situation. The below code attempts to return the value of the requested environment variable. Obviously if that variable isn't there I want to catch the exception and return Nothing. getEnvVar x = do { var <- getEnv x; Just var; } `catch` \ex -> do { Nothing } Here is the error: Couldn't match expected type `IO a' against inferred type `Maybe String' In the expression: Just var In the first argument of `catch', namely `do { var <- getEnv x; Just var }' In the expression: do { var <- getEnv x; Just var } `catch` \ ex -> do { Nothing } I could return string values: getRequestURI x = do { requestURI <- getEnv x; return requestURI; } `catch` \ex -> do { return "" } however, this doesn't feel like the Haskell way. What is the Haskell way?

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• In Python, how to make sure database connection will always close before leaving a code block?

  - by Cawas

  I want to prevent database connection being open as much as possible, because this code will run on an intensive used server and people here already told me database connections should always be closed as soon as possible. def do_something_that_needs_database (): dbConnection = MySQLdb.connect(host=args['database_host'], user=args['database_user'], passwd=args['database_pass'], db=args['database_tabl'], cursorclass=MySQLdb.cursors.DictCursor) dbCursor = dbConnection.cursor() dbCursor.execute('SELECT COUNT(*) total FROM table') row = dbCursor.fetchone() if row['total'] == 0: print 'error: table have no records' dbCursor.execute('UPDATE table SET field="%s"', whatever_value) return None print 'table is ok' dbCursor.execute('UPDATE table SET field="%s"', another_value) # a lot more of workflow done here dbConnection.close() # even more stuff would come below I believe that leaves a database connection open when there is no row on the table, tho I'm still really not sure how it works. Anyway, maybe that is bad design in the sense that I could open and close a DB connection after each small block of execute. And sure, I could just add a close right before the return in that case... But how could I always properly close the DB without having to worry if I have that return, or a raise, or continue, or whatever in the middle? I'm thinking in something like a code block, similar to using try, like in the following suggestion, which obviously doesn't work: def do_something_that_needs_database (): dbConnection = MySQLdb.connect(host=args['database_host'], user=args['database_user'], passwd=args['database_pass'], db=args['database_tabl'], cursorclass=MySQLdb.cursors.DictCursor) try: dbCursor = dbConnection.cursor() dbCursor.execute('SELECT COUNT(*) total FROM table') row = dbCursor.fetchone() if row['total'] == 0: print 'error: table have no records' dbCursor.execute('UPDATE table SET field="%s"', whatever_value) return None print 'table is ok' dbCursor.execute('UPDATE table SET field="%s"', another_value) # again, that same lot of line codes done here except ExitingCodeBlock: closeDb(dbConnection) # still, that "even more stuff" from before would come below I don't think there is anything similar to ExitingCodeBlock for an exception, tho I know there is the try else, but I hope Python already have a similar feature... Or maybe someone can suggest me a paradigm move and tell me this is awful and highly advise me to never do that. Maybe this is just something to not worry about and let MySQLdb handle it, or is it?

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• how do i make the app take correct input..?

  - by user1824343

  This is my windows app's one layout which converts Celsius to Fahrenheit. The problem is that when I try to input the temperature it shows some junk(for eg: if i enter '3' it displayin '3.0000009') and sometimes its even showing stack overflow exception. The output is also not shown properly : cel.text is the textbox for celsius. fahre.text is the textbox for fahrenheit. namespace PanoramaApp1 { public partial class FahretoCel : PhoneApplicationPage { public FahretoCel() { InitializeComponent(); } private void fahre_TextChanged(object sender, TextChangedEventArgs e) { if (fahre.Text != "") { try { double F = Convert.ToDouble(fahre.Text); cel.Text = "" + ((5.0/9.0) * (F - 32)) ; //this is conversion expression } catch (FormatException) { fahre.Text = ""; cel.Text = ""; } } else { cel.Text = ""; } } private void cel_TextChanged(object sender, TextChangedEventArgs e) { if (cel.Text != "") { try { Double c = Convert.ToDouble(cel.Text); fahre.Text = "" + ((c *(9.0 / 5.0 )) + 32); } catch (FormatException) { fahre.Text = ""; cel.Text = ""; } } else { fahre.Text = ""; } } } }

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• Write to PDF using PHP from android device

  - by Brent Mitchell

  I am trying to write to a pdf file on php server. I have sent variables to the server, create the pdf document, then have my phone download the document to view on device. The variables seem not to write on the php file. I have my code below public void postData() { try { Calculate calc = new Calculate(); HttpClient mClient = new DefaultHttpClient(); StringBuilder sb=new StringBuilder("myurl.com/pdf.php"); HttpPost mpost = new HttpPost(sb.toString()); String value = "1234"; List nameValuepairs = new ArrayList(1); nameValuepairs.add(new BasicNameValuePair("id",value)); mpost.setEntity(new UrlEncodedFormEntity(nameValuepairs)); } catch (UnsupportedEncodingException e) { Log.w(" error ", e.toString()); } catch (Exception e) { Log.w(" error ", e.toString()); } } And my php code to write the variable "value" onto the pdf document: //code to reverse the string if($_POST[] != null) { $reversed = strrev($_POST["value"]); $this->SetFont('Arial','u',50); $this->Text(52,68,$reversed); } I am just trying to write the variable in a random spot, but the variable the if statement is always null and I do not know why. Thanks. Sorry if it is a little sloppy.

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• send and receive in socket [closed]

  - by user3696492

  I have trouble in sending an object through socket in c#, my client can send to server but server can't send to client, i think there is something wrong with the client. Server private void Form1_Load(object sender, EventArgs e) { CheckForIllegalCrossThreadCalls = false; Thread a = new Thread(connect); a.Start(); } private void sendButton_Click(object sender, EventArgs e) { client.Send(SerializeData(ShapeList[ShapeList.Count - 1])); } void connect() { try { server = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); iep = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 5555); server.Bind(iep); server.Listen(10); client = server.Accept(); while (true) { byte[] data = new byte[1024]; client.Receive(data); PaintObject a = (PaintObject)DeserializeData(data); ShapeList.Add(a); Invalidate(); } } catch (Exception ex) { MessageBox.Show(ex.Message); } } client private void Form1_Load(object sender, EventArgs e) { CheckForIllegalCrossThreadCalls = false; Thread a = new Thread(connect); a.Start(); } private void SendButton_Click(object sender, EventArgs e) { client.Send(SerializeData(ShapeList[ShapeList.Count - 1])); } void connect() { try { client = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); iep = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 5555); client.Connect(iep); while (true) { byte[] data = new byte[1024]; client.Receive(data); PaintObject a = (PaintObject)DeserializeData(data); ShapeList.Add(a); Invalidate(); } } catch (Exception ex) { MessageBox.Show(ex.Message); } }

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• how to skip first 3 row of text file.

  - by Dilantha Chamal

  hey when i reading the text file using java, how can i skip first 3 rows of the text file. Show me how to do that. public class Reader { public static void main(String[] args) { BufferedReader reader; try { reader = new BufferedReader(new InputStreamReader( new FileInputStream("sample.txt"))); Map<String, Integer result = new LinkedHashMap<String, Integer(); Map<String, Integer result2 = new LinkedHashMap<String, Integer(); while (reader.ready()) { String line = reader.readLine(); /split a line with spaces/ String[] values = line.split("\s+"); /set a key date\tanimal/ String key = values[0] + "\t" + values[1]; int sum = 0; int count = 0; /get a last counter and sum/ if (result.containsKey(key)) { sum = result.get(key); count = result2.get(key); } else{ } /increment sum a count and save in the map with key/ result.put(key, sum + Integer.parseInt(values[2])); result2.put(key, count + 1); } /interate and print new output/ for (String key : result.keySet()) { Integer sum = result.get(key); Integer count = result2.get(key); System.out.println(key + " " + sum + "\t" + count); } reader.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } }

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• http connection timeout issues

  - by Mark

  I'm running into an issue when i try to use the HttpClient connecting to a url. The http connection is taking a longer time to timeout, even after i set a connection timeoout. int timeoutConnection = 5000; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 5000; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); It works perfect most of the time. However, every once in while, the http connection runs for ever and ignore the setconnectiontimeout, especailly when the phone is connected to wifi, and the phone was idling. So after the phone is idling, the first time i try to connect, the http connection ignores the setconnectiontimeout and runs forever, after i cancel it and try again, it works like charm everytime. But that one time that doesn't work it creates a threadtimeout error, i tried using a different thread, it works, but i know that the thread is running for long time. I understand that the wifi goes to sleep on idle, but i dont understand why its ignoring the setconnectiontimeout. Anyone can help, id really appreciated.

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• In Silverlight, what structures, aside of the ListBox, can be used for binding?

  - by Aidenn

  I need to simply provide the content of a property to a custom User Control in Silverlight. My control is something like this: <UserControl x:Class="SilverlightApplication.Header" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" mc:Ignorable="d" d:DesignWidth="300" d:DesignHeight="120"> <Grid x:Name="Header_Layout"> <StackPanel x:Name="hiHeaderContent" Width="Auto" Margin="73,8,8,8"> <TextBlock x:Name="User:" Text="{Binding name}" /> </StackPanel> </Grid> I try to use this User Control from another control where I try to pass the parameter "name" to the previous UserControl ("Header"). I don't need to create a "ListBox" as I will only have 1 header, so I try to avoid doing: <ListBox x:Name="HeaderListBox" Grid.Row="0"> <ListBox.ItemTemplate> <DataTemplate> <SilverlightApplication:Header/> </DataTemplate> </ListBox.ItemTemplate> </ListBox> in order to send the "User" account using: HeaderListBox.ItemsSource = name; Is there any other structure I can use instead of the ListBox to pass the parameter just once? It won't be a list, it's just a header... Thank you!

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• How to connect SQLite with Java?

  - by Rajapandian

  Hi, I am using one simple code to access the SQLite database from Java application . My code is import java.sql.Connection; import java.sql.DriverManager; import java.sql.ResultSet; import java.sql.Statement; public class ConnectSQLite { public static void main(String[] args) { Connection connection = null; ResultSet resultSet = null; Statement statement = null; try { Class.forName("org.sqlite.JDBC"); connection = DriverManager.getConnection("jdbc:sqlite:D:\\testdb.db"); statement = connection.createStatement(); resultSet = statement .executeQuery("SELECT EMPNAME FROM EMPLOYEEDETAILS"); while (resultSet.next()) { System.out.println("EMPLOYEE NAME:" + resultSet.getString("EMPNAME")); } } catch (Exception e) { e.printStackTrace(); } finally { try { resultSet.close(); statement.close(); connection.close(); } catch (Exception e) { e.printStackTrace(); } } } } But this code gives one exception like java.lang.ClassNotFoundException: org.sqlite.JDBC Any body knows how to slove it,please help me.

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• Handling exceptions in Prism 4 modules

  - by marcellscarlett

  I've gone through a number of threads here about this topic with no success. It seems that in the App.xaml.cs of our WPF application, handling DispatcherUnhandledExceptions and AppDomain.CurrentDomain.UnhandledException don't catch everything. In this specific instance we have 7 prism modules. My exception handling code is below (almost identical for UnhandledException): private void OnDispatcherUnhandledException(object sender, DispatcherUnhandledExceptionEventArgs e) { try { var ex = e.Exception.InnerException ?? e.Exception; var logManager = new LogManager(); logManager.Error(ex); if (!EventLog.SourceExists(ex.Source)) EventLog.CreateEventSource(ex.Source, "AppName"); EventLog.WriteEntry(ex.Source, ex.InnerException.ToString()); var emb = new ExceptionMessageBox(ex); emb.ShowDialog(); e.Handled = true; } catch (Exception) { } } The problem seems to be the unhandled exceptions occurring in the modules. They aren't caught by the code above and they cause the application to crash without logging or displaying any sort of message. Does anyone have experience with this?

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• PNG Textures not loading on HTC desire

  - by Matthew Tatum

  Hi I'm developing a game for android using OpenGL es and have hit a problem: My game loads fine in the emulator (windows xp and vista from eclipse), it also loads fine on a T-Mobile G2 (HTC Hero) however when I load it on my new HTC Desire none of the textures appear to load correctly (or at all). I'm suspecting the BitmapFactory.decode method although I have no evidence that that is the problem. All of my textures are power of 2 and JPG textures seem to load (although they don't look great quality) but anything that is GIF or PNG just doesn't load at all except for a 2x2 red square which loads fine and one texture that maps to a 3d object but seems to fill each triangle of the mesh with the nearest colour). This is my code for loading images: AssetManager am = androidContext.getAssets(); BufferedInputStream is = null; try { is = new BufferedInputStream(am.open(fileName)); Bitmap bitmap; bitmap = BitmapFactory.decodeStream(is); GLUtils.texImage2D(GL10.GL_TEXTURE_2D, 0, bitmap, 0); bitmap.recycle(); } catch(IOException e) { Logger.global.log(Level.SEVERE, e.getLocalizedMessage()); } finally { try { is.close(); } catch(Exception e) { // Ignore. } } thanks

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• Why won't the following PDO transaction won't work in PHP?

  - by jfizz

  I am using PHP version 5.4.4, and a MySQL database using InnoDB. I had been using PDO for awhile without utilizing transactions, and everything was working flawlessly. Then, I decided to try to implement transactions, and I keep getting Internal Server Error 500. The following code worked for me (doesn't contain transactions). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } Then I attempted to utilize transactions with the following code (which doesn't work). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->beginTransaction(); $dbh->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); $dbh->commit(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } When I run the previous code, I get an Internal Server Error 500. Any help would be greatly appreciated! Thanks!

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• Downloading Large JSON File to local file using Java

  - by user1279675

  I'm attempting to download a JSON from the following URL - http://api.crunchbase.com/v/1/companies.js - to a local file. I'm using Java 1.7 and the following JSON Libraries - http://www.json.org/java/ - to attempt to make it work. Here's my code: public static void download(String address, String localFileName) { OutputStream out = null; URLConnection conn = null; InputStream in = null; try { URL url = new URL(address); out = new BufferedOutputStream( new FileOutputStream(localFileName)); conn = url.openConnection(); in = conn.getInputStream(); byte[] buffer = new byte[1024]; int numRead; long numWritten = 0; while ((numRead = in.read(buffer)) != -1) { out.write(buffer, 0, numRead); numWritten += numRead; System.out.println(buffer.length); System.out.println(" " + buffer.hashCode()); } System.out.println(localFileName + "\t" + numWritten); } catch (Exception exception) { exception.printStackTrace(); } finally { try { if (in != null) { in.close(); } if (out != null) { out.close(); } } catch (IOException ioe) { } } } When I run the code everything seems to work until midway through the loop the program seems to stop and not continue reading the JSON Object. Does anyone know why this would stop reading? How could I fix the issue?

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• Elegant way to import XHTML nodes from xhr.responseXML into HTML document in IE?

  - by Weston Ruter

  While navigating through a site, I'm dynamically loading pages via Ajax and then only updating the elements of the page that are changed, such as the navigation state and main content area. This is similar to Lala. I am serving the site as XHTML in order to be able to have access to xhr.responseXML which I then traverse in parallel with the current document and copy the nodes over. This works very well in browsers other than IE. For IE, I have to iterate over all of the properties of each XML element I want to import into the HTML document to create it from scratch (using a function convertXMLElementToHTML()). Here's the code I'm currently using: try { nodeB = document.importNode(nodeB, true); } catch(e){ nodeB = nodeB.cloneNode(true); if(document.adoptNode) document.adoptNode(nodeB); } try { //This works in all browsers other than IE nodeA.parentNode.replaceChild(nodeB, nodeA); } //Manually clone the nodes into HTML; required for IE catch(e){ nodeA.parentNode.replaceChild(convertXMLElementToHTML(nodeB), nodeA); } Is there a more elegant solution to mirror-translating XML nodes into HTML?

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• Hibernate saveOrUpdate problem on char data type

  - by Yashwant Chavan

  Hi I am using Hibernate 3.0 , facing issue related to the char datatype field. I am trying to save Client pojo in the database, using following method. Problem is my client_id field is char(10) in the database. when client_id is 10 characters it works fine. but when client_id is less than ten characters it gives problem at the time of update. Rather than updating data it try to insert cleint record again and gives the unquie key exeception. i drill down the problem because of char(10) client_id field. it keeps space after client_id value upto 10 characters. Is there is any confuguration to overcome this problem. rather than modifying client_id to varchar2. public boolean saveClient(Clnt client) { boolean lReturnValue = false; SessionFactory sessionFactory = null; Session session = null; Transaction transaction = null; try { HibernateTemplate hibernateTemplate = getHibernateTemplate(); sessionFactory = hibernateTemplate.getSessionFactory(); session = sessionFactory.getCurrentSession(); transaction = session.beginTransaction(); session.saveOrUpdate(client); transaction.commit(); lReturnValue = true; } catch (HibernateException e) { lReturnValue = false; // TODO Auto-generated catch block if (transaction != null) { transaction.rollback(); } e.printStackTrace(); } return lReturnValue; }

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