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  • Window's content disappears when minimized

    - by Carmen Cojocaru
    I have a simple class that draws a line when mouse dragging or a dot when mouse pressing(releasing). When I minimize the application and then restore it, the content of the window disappears except the last dot (pixel). I understand that the method super.paint(g) repaints the background every time the window changes, but the result seems to be the same whether I use it or not. The difference between the two of them is that when I don't use it there's more than a pixel painted on the window, but not all my painting. How can I fix this? Here is the class. package painting; import java.awt.*; import java.awt.event.MouseAdapter; import java.awt.event.MouseEvent; import java.awt.event.MouseMotionAdapter; import javax.swing.JFrame; import javax.swing.JPanel; class CustomCanvas extends Canvas{ Point oldLocation= new Point(10, 10); Point location= new Point(10, 10); Dimension dimension = new Dimension(2, 2); CustomCanvas(Dimension dimension){ this.dimension = dimension; this.init(); addListeners(); } private void init(){ oldLocation= new Point(0, 0); location= new Point(0, 0); } public void paintLine(){ if ((location.x!=oldLocation.x) || (location.y!=oldLocation.y)) { repaint(location.x,location.y,1,1); } } private void addListeners(){ addMouseListener(new MouseAdapter(){ @Override public void mousePressed(MouseEvent me){ oldLocation = location; location = new Point(me.getX(), me.getY()); paintLine(); } @Override public void mouseReleased(MouseEvent me){ oldLocation = location; location = new Point(me.getX(), me.getY()); paintLine(); } }); addMouseMotionListener(new MouseMotionAdapter() { @Override public void mouseDragged(MouseEvent me){ oldLocation = location; location = new Point(me.getX(), me.getY()); paintLine(); } }); } @Override public void paint(Graphics g){ super.paint(g); g.setColor(Color.red); g.drawLine(location.x, location.y, oldLocation.x, oldLocation.y); } @Override public Dimension getMinimumSize() { return dimension; } @Override public Dimension getPreferredSize() { return dimension; } } class CustomFrame extends JPanel { JPanel displayPanel = new JPanel(new BorderLayout()); CustomCanvas canvas = new CustomCanvas(new Dimension(200, 200)); public CustomFrame(String titlu) { canvas.setBackground(Color.white); displayPanel.add(canvas, BorderLayout.CENTER); this.add(displayPanel); } } public class CustomCanvasFrame { public static void main(String args[]) { CustomFrame panel = new CustomFrame("Test Paint"); JFrame f = new JFrame(); f.add(panel); f.pack(); SwingConsole.run(f, 700, 700); } }

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  • Android 1.6: "android.view.WindowManager$BadTokenException: Unable to add window -- token null is no

    - by Dan Monego
    I'm trying to open a dialog window, but every time I try to open it it throws this exception: E/AndroidRuntime( 206): Uncaught handler: thread main exiting due to uncaught exception E/AndroidRuntime( 206): android.view.WindowManager$BadTokenException: Unable to add window -- token null is not for an application E/AndroidRuntime( 206): at android.view.ViewRoot.setView(ViewRoot.java:460) E/AndroidRuntime( 206): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:177) E/AndroidRuntime( 206): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:91) E/AndroidRuntime( 206): at android.app.Dialog.show(Dialog.java:238) E/AndroidRuntime( 206): at android.app.Activity.showDialog(Activity.java:2413) I'm creating it by calling showDialog with the display's id. The onCreateDialog handler logs fine and I can step through it without an issue, but I've attached since it seems like I'm missing something in it: @Override public Dialog onCreateDialog(int id) { Dialog dialog; Context appContext = this.getApplicationContext(); switch(id) { case RENAME_DIALOG_ID: Log.i("Edit", "Creating rename dialog..."); dialog = new Dialog(appContext); dialog.setContentView(R.layout.rename); dialog.setTitle("Rename " + noteName); break; default: dialog = null; break; } return dialog; } Is there something missing from this? Some questions have talked about having this problem when creating a dialog from onCreate, which happen because the activity isn't created yet, but this is coming from a call from a menu object, and the appContext variable seems like it is correctly populated in the debugger.

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  • Pass data to Child Window in Silverlight 4 using MVVM

    - by Archie
    Hello, I have a datagrid with master detail implementation as follows: <data:DataGrid x:Name="dgData" Width="600" ItemsSource="{Binding Path=ItemCollection}" HorizontalScrollBarVisibility="Hidden" CanUserSortColumns="False" RowDetailsVisibilityChanged="dgData_RowDetailsVisibilityChanged"> <data:DataGrid.Columns> <data:DataGridTextColumn Header="Item" Width="*" Binding="{Binding Item,Mode=TwoWay}"/> <data:DataGridTextColumn Header="Company" Width="*" Binding="{Binding Company,Mode=TwoWay}"/> </data:DataGrid.Columns> <data:DataGrid.RowDetailsTemplate> <DataTemplate> <data:DataGrid x:Name="dgrdRowDetail" Width="400" AutoGenerateColumns="False" HorizontalAlignment="Center" HorizontalScrollBarVisibility="Hidden" Grid.Row="1"> <data:DataGrid.Columns> <data:DataGridTextColumn Header="Date" Width="*" Binding="{Binding Date,Mode=TwoWay}"/> <data:DataGridTextColumn Header="Price" Width="*" Binding="{Binding Price, Mode=TwoWay}"/> <data:DataGridTemplateColumn> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate> <Button Content="Show More Details" Click="buttonShowDetail_Click"></Button> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> </data:DataGrid.Columns> </data:DataGrid> </DataTemplate> </data:DataGrid.RowDetailsTemplate> </data:DataGrid> I want to open a Child window in clicking the button which shows more details about the product. I'm using MVVM pattern. My Model contains a method which takes the Item name as input and retursn the Details data. My problem is how should I pass the Item to ViewModel which will get the Details data from Model? and where shoukd I open the new Child Window? In View or ViewModel? Please help.Thanks.

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  • Open excel 2007 excel files and save as 97-2003 formats in VBA

    - by ABB
    I have a weird situation where I have a set of excel files, all having the extension .xls., in a directory where I can open all of them just fine in Excel 2007. The odd thing is that I cannot open them in Excel 2003, on the same machine, without opening the file first in 2007 and going and saving the file as an "Excel 97-2003 Workbook". Before I save the file as an "Excel 97-2003 Workbook" from Excel 2007, when I open the excel files in 2003 I get the error that the file is not in a recognizable format. So my question is: if I already have the excel file opened in 2007 and I already have the file name of the open file stored in a variable, programatically how can I mimic the action of going up to the "office button" in the upper right and selecting, "save as" and then selecting "Excel 97-2003 Workbook"? I've tried something like the below but it does not save the file at all: ActiveWorkbook.SaveAs TempFilePath & TempFileName & ".xls", FileFormat:=56 Thanks for any help or guidance!

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  • Fancybox can't open partial view

    - by 1110
    I want to open partial view in fancybox like a modal view but when I click on the link it opens whole new page but it should open that in fancybox. I don't know if this is important but I have one more function that open images in fancybox (on the same page) and it works. Class names are different @Html.ActionLink("Feedback", "New", "Feedback", null, new { @class = "lightbox" }) JS $('.lightbox').fancybox(); Action method public ActionResult New() { return PartialView(); }

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  • WPF DataGrid window resize does not resize DataGridColumns

    - by skylap
    I have a WPF DataGrid (from the WPFToolkit package) like the following in my application. <Controls:DataGrid> <Controls:DataGrid.Columns> <Controls:DataGridTextColumn Width="1*" Binding="{Binding Path=Column1}" Header="Column 1" /> <Controls:DataGridTextColumn Width="1*" Binding="{Binding Path=Column2}" Header="Column 2" /> <Controls:DataGridTextColumn Width="1*" Binding="{Binding Path=Column3}" Header="Column 3" /> </Controls:DataGrid.Columns> </Controls:DataGrid> The column width should be automatically adjusted such that all three columns fill the width of the grid, so I set Width="1*" on every column. I encountered two problems with this approach. When the ItemsSource of the DataGrid is null or an empty List, the columns won't size to fit the width of the grid but have a fixed width of about 20 pixel. Please see the following picture: http://img169.imageshack.us/img169/3139/initialcolumnwidth.png When I maximize the application window, the columns won't adapt their size but keep their initial size. See the following picture: http://img88.imageshack.us/img88/9362/columnwidthaftermaximiz.png When I resize the application window with the mouse, the columns won't resize. I was able to solve problem #3 by deriving a sub class from DataGrid and override the DataGrid's OnRenderSizeChanged method as follows. protected override void OnRenderSizeChanged(SizeChangedInfo sizeInfo) { base.OnRenderSizeChanged(sizeInfo); foreach (var column in Columns) { var tmp = column.GetValue(DataGridColumn.WidthProperty); column.ClearValue(DataGridColumn.WidthProperty); column.SetValue(DataGridColumn.WidthProperty, tmp); } } Unfortunately this does not solve problems #1 and #2. How can I get rid of them?

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  • Visual Studio 2010 Beta start without debugging Console wont stay open

    - by CousinVinny
    I want to keep the console (output) window open to view the output of the project I am working on. I have enabled the start without debugging option and added the button to the debugging toolbar, but alas it fails to keep it open nicely like in visual studio 2008. I have to add cin.getline() etc etc etc to get it to stay open, but I don't want to type it. Any suggestions as to alter it Visual Studio 2010 to keep it open, or any debugging tricks to make it easier to view output for longer than a flash. Visual Studio used to have a "Press any key to continue prompt" I want it back...

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  • Try to use Window.FEATURU_CUSTOM_TITLE but got Exception:You cannot combine custom titles with other

    - by xueru
    I am trying to use a custom title to include an image button to the title bar. I got a lot of help form this post: http://stackoverflow.com/questions/2569753/android-adding-button-to-the-title-of-the-app, but could not get it work for my ListActivity. In a nutshell, following is what I have: I hide the titlebar in the AndroidManifest.xml The specify a relative layout for the custom title (workorder_list_titlebar.xml) My Activity Class looks like the following: public class WorkOrderListActivity extends ListActivity { String[] orders={"WO-12022009", "WO-12302009", "WO-02122010", "02152010"}; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); requestWindowFeature(Window.FEATURE_CUSTOM_TITLE); this.getWindow().setFeatureInt(Window.FEATURE_CUSTOM_TITLE, R.layout.workorder_list_titlebar); setContentView(R.layout.workorder_list); setListAdapter(new ArrayAdapter(this,R.layout.workorder_list, R.id.label,orders)); } } When I ran the app, I got AndroidRuntimeException: You cannot combine custom titles with other title features. Base on the stack trace, the exception was thrown by com.android.internal.policy.impl.PhoneWindow.requestFeature(PhoneWindow.java:183), that was triggered by setlistAdapter call. Does anyone have the same problem with ListActivity? Also once I manage to get this work, how do I attach listeners to the image button for it to do something? Thanks in advance.

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  • On Windows, how does console window ownership work?

    - by shroudednight
    When a console application is started from another console application, how does console ownership work? I see four possibilities: The second application inherits the console from the first application for its lifetime, with the console returning to the original owner on exit. Each application has its own console. Windows then somehow merges the content of the two into what the "console" visible to the user The second application get a handle to the console that belongs to the first application. The console is placed into shared memory and both applications have equal "ownership" It's quite possible that I missed something and none of these four options adequately describe what Windows does with its consoles. If the answer is close to option 4. My follow-up question is which of the two processes is responsible for managing the window? (Handling graphical updates when the screen needs to be refreshed / redrawn, etc) A concrete example: Run CMD. Then, using CMD, run [console application]. The [console application] will write to what appears to be the same console window that CMD was using.

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  • Eliminate horizontal scrolling in div in favor of horizontal scrolling in browser window

    - by Casey Flynn
    I have a div, set to 800px wide, that will automatically scroll horizontally if the browser window is resized to < 800px. The behavior I would like, is to have the browser window scroll instead of the div. It would seem simple but for some reason I'm getting hung up on it. Any ideas? The page in question: http://www.caseyflynn.com/game/ The div CSS: div#main_container { border: 1px solid #FFF; width:800px; margin-left:auto; margin-right:auto; padding:0px; background-color:#FFF; overflow:hidden; } The BODY CSS: html, body { background-color:#000; border:0px; margin:0px; padding:0px; font-family : Arial, Helvetica, sans-serif; font-size : 62.5%; overflow:auto; } I'm assuming anyone looking at this will have the ability to see the HTML and the CSS. Thanks!

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  • Qt: Force QWebView to click on a web element, even one not visible on the window

    - by Pirate for Profit
    So let's say I'm trying to click a link in the QWebView, here is what I have: // extending QWebView void MyWebView::click(const QString &selectorQuery) { QWebElement el = this->page()->mainFrame()->findFirstElement(selectorQuery); if (!el) return; el.setFocus(); QMouseEvent pressEvent(QMouseEvent::MouseButtonPress, el.geometry().center(), Qt::MouseButton::LeftButton, Qt::LeftButton, Qt::NoModifier); QCoreApplication::sendEvent(this, &pressEvent); QMouseEvent releaseEvent(QMouseEvent::MouseButtonRelease, el.geometry().center(), Qt::MouseButton::LeftButton, Qt::LeftButton, Qt::NoModifier); QCoreApplication::sendEvent(this, &releaseEvent); } And you call it as so: myWebView->click("a[href]"); // will click first link on page myWebView->click("input[type=submit]"); // submits a form THE ONLY PROBLEM IS: if the element is not visible in the window, it is impossible to click. What I mean is if you have to scroll down to see it, you can't click it. I imagine this has to do with the geometry, since the element doesn't show up on the screen it can't do the math to click it right. Any ideas to get around this? Maybe some way to make the window behave like a billion x billion pixels but still look 200x200?

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  • Photo gallery not open in titanium 1.0

    - by user291247
    Hello, I am developing new app. using titanium 1.0 In that I am opening phtogallery in new window but I am not able to open it why this was happened? Code to open photogallery in app.js Titanium.App.addEventListener('recordvideo', function(e) { win1.close(); var w = Titanium.UI.createWindow({ backgroundColor:'#336699', title:'Modal Window', barColor:'black', url:'xhr_testfileupload.js' }); w.open({animated:true}); }); xhr_testfileupload.js code: var win = Titanium.UI.currentWindow; var ind=Titanium.UI.createProgressBar({ width:200, height:50, min:0, max:1, value:0, style:Titanium.UI.iPhone.ProgressBarStyle.PLAIN, top:10, message:'Uploading Image', font:{fontSize:12, fontWeight:'bold'}, color:'#888' }); win.add(ind); ind.show(); Titanium.Media.openPhotoGallery({ success:function(event) { Ti.API.info("success! event: " + JSON.stringify(event)); var image = event.media; var xhr = Titanium.Network.createHTTPClient(); xhr.onerror = function(e) { Ti.API.info('IN ERROR ' + e.error); }; xhr.onload = function() { Ti.API.info('IN ONLOAD ' + this.status + ' readyState ' + this.readyState); }; xhr.onsendstream = function(e) { ind.value = e.progress ; Ti.API.info('ONSENDSTREAM - PROGRESS: ' + e.progress); } // open the client xhr.open('POST','https://twitpic.com/api/uploadAndPost'); // send the data xhr.send({media:image,username:'fgsandford1000',password:'sanford1000',message:'check me out'}); }, cancel:function() { }, error:function(error) { }, allowImageEditing:true, });

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  • Delphi - Message loop for Form created in DirectShow filter goes dead

    - by Robert Oschler
    I have a DirectShow filter created with Delphi Pro 6 and the DSPACK direct show library. I'm running under windows XP. I've tried creating the form dynamically when the container class for the DirectFilter has its constructor called, passing NIL into the constructor as the AOwner parameter (TMyForm.Create(nil) and then calling the Form's Show() method. The form does show but then appears to stop receiving windows messages because it never repaints and does not respond to input. As a test I then tried creating my own WndProc() and overriding the Form's WndProc(). My WndProc() did get called once but never again. I'm guessing it's because I'm a DLL and the context that I am running in is not "friendly" to the window message handler for the form; perhaps something to do with the thread that calls it or whatever. If someone could give me a tip on how to solve this or what the proper way to create a persistent window is from the context of a DirectShow filter I'd appreciate it. Note, as I said the window needs to be persistent so I can't create it as a Filter property page. Thanks, Robert

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  • Ajax call to parent window after form submission

    - by David
    Hi all, Pardon the complicated title. Here's my situation: I'm working on a Grails app, and using jQuery for some of the more complex UI stuff. The way the system is set up, I have an item, which can have various files (user-supplied) associated with it. On my Item/show view, there is a link to add a file. This link pops up a jQuery modal dialog, which displays my file upload form (a remote .gsp). So, the user selects the file and enters a comment, and when the form is submitted, the dialog gets closed, and the list of files on the Item/show view is refreshed. I was initially accomplishing this by adding onclick="javascript:window.parent.$('#myDialog').dialog('close');" to my submit button. This worked fine, but when submitting some larger files, I end up with a race condition where the dialog closes and the file list is refreshed before the new file is saved, and so the list of files is out of date (the file still gets saved properly). So my question is, what is the best way to ensure that the dialog is not closed until after the form submit operation completes? I've tried using the <g:formRemote tag in Grails, and closing the dialog in the "after" attribute (according to the Grails docs, the script is called after form submission), but I receive an error (taken from FireBug) stating that window.parent.$('#myDialog').dialog is not a function Is this a simple JavaScript/Grails syntax issue that I'm missing here, or am I going about this entirely wrong? Thanks so much for your time and assistance!

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  • Open pdf in flash player 10

    - by Jordan
    I need to open a PDF in flash player 10. The swf will not be running in a browser and there will not be an adobe reader program on the system. I need to know if its possible to open a PDF without converting it in any way, in the flash player. I've searched google for countless hours and nothing has come up, only conversion software and code to open it in a browser. Thanks, Jordan

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  • Handling multiple sessions for same user credentials and avoiding new browser window opening in my w

    - by Kabeer
    Hello. I want to handle following scenarios in my new web application. If multiple users log into the application with same credentials, the application should deny access. Since I have out of process session store, I would be able to make out when this situation happens. So I can deny all requests after first successful attempt. This will however not work if the user instead of logging out of the application, closes the browser. The session will continue to reflect in the store for the period of timeout value. If a user attempts to open a new browser windows (Ctrl+N), the application should defeat this attempt. Every new page can potentially fiddle with cookies. I want to therefore deny the users the ability to open new window.

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  • Custom title with image

    - by Alex Volovoy
    Hi all, i'm creating custom title for activity by disabling standard one and managing everything myself. I wonder if it's possible to replace/theme standart title to my needs. I can customize size, background image, and text via themes by changing windowXYZStyle items. The only thing i couldn't find - how i can add image instead of text. I've tried requestWindowFeature(Window.FEATURE_CUSTOM_TITLE) and assign custom layout - but it doesn't seems to work. EDIT : Here is a report of testing suggestions, code is below - result - image view is not showing up. Activity public class SettingsActivity extends PreferenceActivity { @Override protected void onCreate(Bundle savedInstanceState) { requestWindowFeature(Window.FEATURE_CUSTOM_TITLE); getWindow().setFeatureInt(Window.FEATURE_CUSTOM_TITLE, R.layout.custom_title); super.onCreate(savedInstanceState); addPreferencesFromResource(R.xml.settings); } } XML : <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/title" android:layout_width="fill_parent" android:layout_height="26dip" android:paddingLeft="5dip" android:background="@drawable/titlebar_bg" android:layout_gravity="left|center" > <ImageView android:id="@+id/logo" android:src="@drawable/title_logo" android:layout_width="wrap_content" android:layout_height="wrap_content" /> </LinearLayout>

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  • How to show only border of winforms window when resizing?

    - by MartyIX
    I would like to disable displaying of the content of the window when resizing, is it possible? The problem is that when I'm resizing my window the controls redraw on correct positions but it doesn't look good because it's not done fluently. EDIT: I would like a code that would manage the following scenario: I click on the corner of window Now only the border of window is visible - the middle part is transparent I set the size of the window by mouse I release the mouse button and the middle part of the window will appear

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  • Android application transparency and window sizing at root level

    - by ajoburg
    Is it possible to create an application with a transparent background on the root task such that you can see the task running beneath it when it is part of a separate stack? Alternatively, is it possible to run an application so the window of the root task is only a portion of the screen instead of the whole screen? I understand how the transparency and window sizing is done with activities that are not the root task and this works fine. However, the root task of an activity seems to always fill the whole screen and be black even when a transparent theme is applied to the application object in the manifest file. ApplicationManifest.xml: <application android:icon="@drawable/icon" android:label="@string/app_name" android:debuggable="true" android:theme="@style/Theme.Transparent"> Styles.xml <resources> <style name="Theme.Transparent"> <item name="android:windowIsTranslucent">true</item> <item name="android:windowNoTitle">true</item> <item name="android:windowBackground">@drawable/ transparent_background</item> <item name="android:windowAnimationStyle">@android:style/ Animation.Translucent</item> <item name="android:colorForeground">#fff</item> <item name="android:windowIsFloating">true</item> <item name="android:gravity">bottom</item> </style> </resources> Colors.xml <resources> <drawable name="transparent_background">#00000000</drawable> </resources>

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  • Why are my attempts to open a file using open for writing failing? Ada 95

    - by mat_geek
    When I attempt to open a file to write to I get an Ada.IO_Exceptions.Name_Error. The procedure call is Ada.Text_IO.Open The file name is "C:\CC_TEST_LOG.TXT". This file does not exist. This is on Windows XP on an NTFS partition. The user has permissions to create and write to the directory. The filename is well under the WIN32 max path length. name_2 : String := "C:\CC_TEST_LOG.TXT" if name_2'last > name_2'first then begin Ada.Text_IO.Open(file, Ada.Text_IO.Out_File, name_2); Ada.Text_IO.Put_Line( "CC_Test_Utils: LogFile: ERROR: Open, File " & name_2); return; exception when The_Error : others => Ada.Text_IO.Put_Line( "CC_Test_Utils: LogFile: ERROR: Open Failed; " & Ada.Exceptions.Exception_Name(The_Error) & ", File " & name_2); end; end if;

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  • git difftool, open all diff files immediately, not in serial

    - by Seba Illingworth
    The default git diff behavior is to open each diff file in serial (wait for previous file to be closed before opening next file). I'm looking for a way to open all the files at once - in BeyondCompare for example this would open all the files in tabs within the same BC window. This would make it easier to review a complex set of changes; flick back and forwards between the diff files and ignore unimportant files.

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  • Trying to access a specific option value to generate a popup window

    - by Isaac
    I am trying to use a click event to generate a popup window based off of the specific value chosen. I am having trouble with the if statement and trying to access each specific option value. Can any of you give me some hints? <select id="offices"> <option value="Choose an Office">Choose an Office</option> <option value="Residential Education (ResEd)" >Residential Education (ResEd)</option> <option value="Dean of Students">Dean of Students</option> <option value="Office of Student Affairs">Office of Student Affairs</option> <option value="Vice-Provost of Student Affairs">Vice-Provost of Student Affairs</option> </select> </div> function display(){ var officearray = [{ Office: "Residential Education (ResEd)", ID: "725-2800", Description: "The Office of Residential Education is responsible for developing the policies, programs, and staffing which support the intellectual, educational, and community-building activities in student residences. Second Floor. " }, { Office: "Dean of Students", ID: "723-7833", Description: "The Dean of Students office is composed of 13 individual administrative units that are concerned with the general welfare of both undergraduate and graduate students, in and out of the classroom. Second floor." }, { Office: "Office of Student Activities (OSA)", ID: "723-2733", Description: "Services for student organizations, student-initiated major events and programs, and fraternities and sororities. Second floor." }, { Office: "Vice-Provost of Student Affairs", ID: "725-0911", Description: "The Vice Provost for Student Affairs is responsible to the Provost for providing services and programs to undergraduate and graduate students in support of the academic mission of the University. Second floor." }] for(var i = 0; i < officearray.length; i++) { var o = document.getElementById("offices") var oString = o.options[o.selectedIndex].value; newwindow2 = window.open('', 'name', 'height=200, width=150') var tmp = newwindow2.document if (oString == officearray[i].Office) { tmp.writeln(officearray[i].Description) } } } document.getElementsByTagName('option').addEventListener("click",display,false)

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  • Python 2.5.2: trying to open files recursively

    - by user248959
    Hi, the script below should open all the files inside the folder 'pruebaba' recursively but i get this error: Traceback (most recent call last): File "/home/tirengarfio/Desktop/prueba.py", line 8, in f = open(file,'r') IOError: [Errno 21] Is a directory This is the hierarchy: pruebaba folder1 folder11 test1.php folder12 test1.php test2.php folder2 test1.php The script: import re,fileinput,os path="/home/tirengarfio/Desktop/pruebaba" os.chdir(path) for file in os.listdir("."): f = open(file,'r') data = f.read() data = re.sub(r'(\s*function\s+.*\s*{\s*)', r'\1echo "The function starts here."', data) f.close() f = open(file, 'w') f.write(data) f.close() Any idea? Regards Javi

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