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  • List files with two dots in their names using java regular expressions

    - by Nivas
    I was trying to match files in a directory that had two dots in their name, something like theme.default.properties I thought the pattern .\\..\\.. should be the required pattern [. matches any character and \. matches a dot] but it matches both oneTwo.txt and theme.default.properties I tried the following: [resources/themes has two files oneTwo.txt and theme.default.properties] 1. public static void loadThemes() { File themeDirectory = new File("resources/themes"); if(themeDirectory.exists()) { File[] themeFiles = themeDirectory.listFiles(); for(File themeFile : themeFiles) { if(themeFile.getName().matches(".\\..\\..")); { System.out.println(themeFile.getName()); } } } } This prints nothing and the following File[] themeFiles = themeDirectory.listFiles(new FilenameFilter() { public boolean accept(File dir, String name) { return name.matches(".\\..\\.."); } }); for (File file : themeFiles) { System.out.println(file.getName()); } prints both oneTwo.txt theme.default.properties I am unable to find why these two give different results and which pattern I should be using to match two dots... Can someone help?

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  • Jakarta Regexp 1.5 Backreferences?

    - by Matt Smith
    Why does this match: String str = "099.9 102.2" + (char) 0x0D; RE re = new RE("^([0-9]{3}.[0-9]) ([0-9]{3}.[0-9])\r$"); System.out.println(re.match(str)); But this does not: String str = "099.9 102.2" + (char) 0x0D; RE re = new RE("^([0-9]{3}.[0-9]) \1\r$"); System.out.println(re.match(str)); The back references don't seem to be working... What am I missing?

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  • jquery sortable with regexp

    - by Chris Lively
    I am trying to figure out the right regexp to match on list item id's. For example: <ul id="MyList" class="connectedSortable"> <li id="id=1-32">Item 1</li> <li id="id=2_23">Item 2</li> <li id="id=3">Item 3</li> <li id="id=4">Item 4</li> <li id="id=5">Item 5</li> <li id="id=6">Item 6</li> </ul> On the serialize method, I want it to pull everything after the equal sign (=) $(function () { $("#MyList, #OtherList").sortable({ connectWith: '.connectedSortable', update: function () { $("#MyListOrder").val($("#MyList").sortable('serialize', { regexp: '/(.+)[=](.+)/)' })); } }).disableSelection(); }); I tried the above, but that didn't quite work. My regexp expression is wrong and I don't know what it should be. Ideas?

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  • Regexp look-behind to match internet speeds

    - by Sandman
    So the user may search for "10 mbit" after which I want to capture the "10" so I can use it in a speed-search rather than a string-search. This isn't a problem, the below regexp does this fine: if (preg_match("/(\d+)\smbit/", $string)){ ... } But, the user may search for something like "10/10 mbit" or "10-100 mbit". I don't want to match those with the above regexp - they should be handled in another fashion. So I would like a regexp that matches "10 mbit" if the number is all-numeric as a whole word (i.e. contained by whitespace, newline or lineend/linestart) Using lookbehind, I did this: if (preg_match("#(?<!/)(\d+)\s+mbit#i", $string)){ Just to catch those that doesn't have "/" before them, but this matched true for this string: "10/10 mbit" so I'm obviously doing something wrong here, but what?

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  • regexp for detect that the url doesn´t end with an extension

    - by devnieL
    Hello. I'm using this regular expression for detect if an url ends with a jpg : var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|]*^\.jpg)/ig; it detects the url : e.g. http://www.blabla.com/sdsd.jpg but now i want to detect that the url doesn't ends with an jpg extension, i try with this : var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|]*[^\.jpg]\b)/ig; but only get http://www.blabla.com/sdsd then i used this : var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|]*[^\.jpg]$)/ig; it works if the url is alone, but dont work if the text is e.g. : http://www.blabla.com/sdsd.jpg text

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  • How to export the matches only in a pattern search in vim?

    - by Mert Nuhoglu
    Is there a way to grab and export the match part only in a pattern search without changing the current file? For example, from a file containing: 57","0","37","","http://www.thisamericanlife.org/Radio_Episode.aspx?episode=175" 58","0","37","","http://www.thisamericanlife.org/Radio_Episode.aspx?episode=170" I want to export a new file containing: http://www.thisamericanlife.org/Radio_Episode.aspx?episode=175 http://www.thisamericanlife.org/Radio_Episode.aspx?episode=170 I can do this by using substitution like this: :s/.\{-}\(http:\/\/.\{-}\)".\{-}/\1/g :%w>>data But the substitution command changes the current file. Is there a way to do this without changing the current file?

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  • Find and Replace with Notepad++

    - by Levi
    I have a document that was converted from PDF to HTML for use on a company website to be referenced and indexed for search. I'm attempting to format the converted document to meet my needs and in doing so I am attempting to clean up some of the junk that was pulled over from when it was a PDF such as page numbers, headers, and footers. luckily all of these lines that need to be removed are in blocks of 4 lines unfortunately they are not exactly the same therefore cannot be removed with a simple literal replace. The lines contain numbers which are incremental as they correlate with the pages. How can I remove the following example from my html file. Title<br> 10<br> <hr> <A name=11></a>Footer<br> I've tried many different regular expression attempts but as my skill in that area is limited I can't find the proper syntax. I'm sure i'm missing something fairly easy as it would seem all I need is a wildcard replace for the two numbers in the code and the rest is literal. any help is apprciated

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  • Matching several items inside one string with preg_match_all() and end characters

    - by nefo_x
    I have the following code: preg_match_all('/(.*) \((\d+)\) - ([\d\.\d]+)[,?]/U', "E-Book What I Didn't Learn At School... (2) - 3525.01, FREE Intro DVD/Vid (1) - 0.15", $match); var_dump($string, $match); and get the following ouput: array(4) { [0]=> array(1) { [0]=> string(54) "E-Book What I Didn't Learn At School... (2) - 3525.01," } [1]=> array(1) { [0]=> string(39) "E-Book What I Didn't Learn At School..." } [2]=> array(1) { [0]=> string(1) "2" } [3]=> array(1) { [0]=> string(7) "3525.01" } } which matches only one items... what i need is to get all items from such strings. when i've added "," sign to the end of the string - it worked fine. but that is non-sense in adding comma to each string. Any advice?

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  • How do I write this URL in Django?

    - by alex
    (r'^/(?P<the_param>[a-zA-z0-9_-]+)/$','myproject.myapp.views.myview'), How can I change this so that "the_param" accepts a URL(encoded) as a parameter? So, I want to pass a URL to it. mydomain.com/http%3A//google.com

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  • Confusion in RegExp Reluctant quantifier? Java

    - by Dusk
    Hi, Could anyone please tell me the reason of getting an output as: ab for the following RegExp code using Relcutant quantifier? Pattern p = Pattern.compile("abc*?"); Matcher m = p.matcher("abcfoo"); while(m.find()) System.out.println(m.group()); // ab and getting empty indices for the following code? Pattern p = Pattern.compile(".*?"); Matcher m = p.matcher("abcfoo"); while(m.find()) System.out.println(m.group());

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  • sed - trying to replace first occurrence after a match

    - by wakkaluba
    I am facing a situation that drives me nuts. I am setting up an update server which uses a json file. Don't ask why or how, it sucks and is my only possibility to achieve it. I have been trying and researching for HOURS (many) because I went ballistic and wanted to crack this on my own. But I have to realize I got stuck and need help. So sorry for this chunk but I think it is somewhat important to see... The file is a one liner and repeating the following sequence with changing values (of course). "plugin_name_foo_bar": {"buildDate": "bla", "dependencies": [{"name": "bla", "optional": true, "version": "1.00"}], "developers": [{"developerId": "bla", "email": "[email protected]", "name": "Bla bla2nd"}], "excerpt": "some text {excerpt} !bla.png|thumbnail,border=1! ", "gav": "bla", "labels": ["report", "scm-related"], "name": "plugin_name_foo_bar", "previousTimestamp": "bla", "previousVersion": "1.0", "releaseTimestamp": "bla", "requiredCore": "1", "scm": "github.com", "sha1": "ynnBM2jWo25ZLDdP3ybBOnV/Pio=", "title": "bla", "url": "http://bla.org", "version": "1.0", "wiki": "https://bla.org"}, "Exclusion": {"buildDate": "bla", "dependencies": [], and the next plugin block is glued straight afterwards. What I now want to do is to search for "plugin_foo_bar": {" as this is the unique identifier for a new plugin description block. I want to replace the first sha1 value occuring afterwards. That's where I keep failing. I always grab the first,last or any occurrence in the entire file and not the block :( "title" is the unique identifier after the sha1 value. So I tried to make the .* less greedy but it ain't working out. last attempt was heading towards: sed -i 's/("name": "plugin_name_foo_bar.*sha1": ")([a-zA-Z0-9!@#\$%^&*()\[\]]*)(", "title"\)/\1blablabla\2/1' default.json to find the sha1 value of that plugin but still no joy. I hope someone knows - preferably a simpler approach - before I now continue with trial and error until I have to puke and freakout. I am working with SED on Windows, so Unix approach might help me to figure out how to achieve this in batch but please make it as one-liner if possible. Scripts are a real pain to convert. And I just need SED and no other solution with other tools like AWK. That is absolutely out of discussion. Any help is appreciated :) Cheers Jan

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  • How to find which delimiter was used during string split (VB.NET)

    - by typoknig
    Hi all, lets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question? Dim linePunctuation as Integer = 0 Dim myString As String = "some text. with punctuation! in it?" For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "." Then linePunctuation += 1 Next For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "!" Then linePunctuation += 1 Next For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "?" Then linePunctuation += 1 Next Dim delimiters(3) As Char delimiters(0) = "." delimiters(1) = "!" delimiters(2) = "?" currentLineSplit = myString.Split(delimiters) Dim sentenceArray(linePunctuation) As String Dim count As Integer = 0 While linePunctuation > 0 sentenceArray(count) = currentLineSplit(count)'Here I want to add what ever delimiter was used to make the split back onto the string before it is stored in the array.' count += 1 linePunctuation -= 1 End While

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  • PHP & Regular expression: keyword just occurs once

    - by lauthiamkok
    Hi, how can I make sure a certain keyword just occurs once in the input with regular expression? I think there is some mistakes in the expression below as I can repeat the same keywords, if (!preg_match('/\b(.php?){1}\b/', $cfg_path)) { $error = true; echo '<error elementid="cfg_path" message="PATH - make sure you have a \'.php?\' in the path."/>'; } I just want this to be true, form.php?category=something or form.php? but not this, form.php?.php?category=something or form.php?.php? please let me know how to fix it. thanks.

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  • Is there a way to get the PREMATCH ($`) and POSTMATCH ($') from pcrecpp?

    - by Eric Peers
    Is there a way to obtain the C++ equivalent of Perl's PREMATCH ($`) and POSTMATCH ($') from pcrecpp? I would be happy with a string, a char *, or pairs indices/startpos+length that point at this. StringPiece seems like it might accomplish part of this, but I'm not certain how to get it. in perl: $_ = "Hello world"; if (/lo\s/) { $pre = $`; #should be "Hel" $post = $'; #should be "world" } in C++ I would have something like: string mystr = "Hello world"; //do I need to map this in a StringPiece? if (pcrecpp::RE("lo\s").PartialMatch(mystr)) { //should I use Consume or FindAndConsume? //What should I do here to get pre+post matches??? } pcre plainjane c seems to have the ability to return the vector with the matches including the "end" portion of the string, so I could theoretically extract such a pre/post variable, but that seems like a lot of work. I like the simplicty of the pcrecpp interface. Suggestions? Thanks! --Eric

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  • Help with Regular Expression

    - by shivesh
    Hello I need help with Regular Expression, I want to match each section (number and it's text - 2 groups), the text can be multi line, each section ends when another section starts (another number) or when .END is reached or EOF. Demo Expression: \(\d{1,3}\) ([\s\S]*?)(\.END|\(\d{1,3}\)) Input text: (1) some text some text some text some text some text some text (2) some text some textsome text (3) some textsome text some textsome textsome text (4) some text .END first group should match number (with brackets) and second group should match corresponded text.

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  • Regular expressions in python unicode

    - by Remy
    I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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  • regular expression and escaping

    - by pstanton
    Sorry if this has been asked, my search brought up many off topic posts. I'm trying to convert wildcards from a user defined search string (wildcard is "*") to postgresql like wildcard "%". I'd like to handle escaping so that "%" => "\%" and "\*" => "*" I know i could replace \* with something else prior to replacing * and then swap it back, but i'd prefer not to and instead only convert * using a pattern that selects it when not proceeded by \. String convertWildcard(String like) { like = like.replaceAll("%", "\\%"); like = like.replaceAll("\\*", "%"); return like; } Assert.assertEquals("%", convertWildcard("*")); Assert.assertEquals("\%", convertWildcard("%")); Assert.assertEquals("*", convertWildcard("\*")); // FAIL Assert.assertEquals("a%b", convertWildcard("a*b")); Assert.assertEquals("a\%b", convertWildcard("a%b")); Assert.assertEquals("a*b", convertWildcard("a\*b")); // FAIL ideas welcome.

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  • Weird error using preg_match and unicode

    - by Thorpe Obazee
    if (preg_match('(\p{Nd}{4}/\p{Nd}{2}/\p{Nd}{2}/\p{L}+)', '2010/02/14/this-is-something')) { // do stuff } The above code works. However this one doesn't. if (preg_match('/\p{Nd}{4}/\p{Nd}{2}/\p{Nd}{2}/\p{L}+/u', '2010/02/14/this-is-something')) { // do stuff } Maybe someone could shed some light as to why the one below doesn't work. This is the error that is being produced: A PHP Error was encountered Severity: Warning Message: preg_match() [function.preg-match]: Unknown modifier '\'

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  • C# regular expression

    - by vert
    How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following: a-z A-Z Æ æ Å å Ø ø - ' Thanks!

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