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  • preg_match_all problems

    - by NeoNmaN
    i use preg_match_all and need to grab all a href="" tags in my code, but i not relly understand how to its work. i have this reg. exp. ( /(<([\w]+)[^])(.?)(<\/\2)/ ) its take all html codes, i need only all a href tags. i hobe i can get help :)

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  • What is the right method for parsing a blog post?

    - by Zedwal
    Hi guys, Need a guide line .... I am trying to write a personal blog. What is the standard structure for for input for the post. I am trying the format like: This is the simple text And I am [b] bold text[/b]. This is the code part: [code lang=java] public static void main (String args[]) { System.out.println("Hello World!"); } [/code] Is this the right way to store post in the database? And What is the right method to parse this kind of post? Shall I use regular expression to parse this or there is another standard for this. If the above mentioned format is not the right way for storage, then what it could be? Thanks

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  • I am using a regex snippet query string path

    - by Shelby Poston
    Using the following to load images base on two ids one is the and bookid and the out is the client. My folder structures is this. root path = flipbooks subfolders under flipbooks are books and clients in subfolder books I have and .net page title tablet. the tablet code behind checks the bookid of client and render a the tablet page with images in a flipbook fashion. because we have over 15000 records and flipbooks already created and stored in the database. I don't move the client folder under the books subfolders. I need the code below to get to the client subfolder in the query string and help to change this would be helpful. The result now is http://www.somewebsite.com/books/client/images/someimage1.jpg[^] I need the results to be http://www.somewebsite.com/client/images/someimage1.jpg[^]. I tried moving the tablet.aspx file to the root flipbooks and it works but i have provide a user name and password each time. This need to be access by the public and my root is protected. Don't want to have to change permission. I am trying to remove the /books function getParameterByName(name) { var results = RegExp('[?&]' + name + '=([^&]*)').exec(window.location.search); return results ? decodeURIComponent(results[1].replace(/\+/g, ' ')) : null; } Thanks Mission Critical

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  • In C/C++ mode in Emacs, change face of code in #if 0...#endif block to comment face

    - by pogopop77
    I'm trying to add functionality found in some other code editors to my Emacs configuration, whereby C/C++ code within #if 0...#endif blocks is automatically set to the comment face/font. Based on my testing, cpp-highlight-mode does something like what I want, but requires user action. It seems like tying into the font-lock functionality is the correct option to make the behavior automatic. I have successfully followed examples in the GNU documentation to change the face of single-line regular expressions. For example: (add-hook 'c-mode-common-hook (lambda () (font-lock-add-keywords nil '(("\\<\\(FIXME\\|TODO\\|HACK\\|fixme\\|todo\\|hack\\)" 1 font-lock-warning-face t))))) works fine to highlight debug related keywords anywhere in a file. However, I am having problems matching #if 0...#endif as a multiline regular expression. I found some useful information in this post (How to compose region like ""), that suggested that Emacs must be told specifically to allow for multiline matches. But this code: (add-hook 'c-mode-common-hook (lambda () '(progn (setq font-lock-multiline t) (font-lock-add-keywords nil '(("#if 0\\(.\\|\n\\)*?#endif" 1 font-lock-comment-face t)))))) still does not work for me. Perhaps my regular expression is wrong (though it appears to work using M-x re-builder), I've messed up my syntax, or I'm following the wrong approach entirely. I'm using Aquamacs 2.1 (which is based on GNU Emacs 23.2.50.1) on OS X 10.6.5, if that makes a difference. Any assistance would be appreciated!

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  • Removing whitespace in Java string?

    - by waitinforatrain
    Hi guys, I'm writing a parser for some LISP files. I'm trying to get rid of leading whitespace in a string. The string contents are along the lines of: :FUNCTION (LAMBDA (DELTA PLASMA-IN-0) (IF (OR (>= #61=(+ (* 1 DELTA) PLASMA-IN-0) 100) (<= #61# 0)) PLASMA-IN-0 #61#)) The tabs are all printed as 4 spaces in the file, so I want to get rid of these leading tabs. I tried to do this: string.replaceAll("\\s{4}", " ") - but it had no effect at all on the string. Does anyone know what I'm doing wrong? Is it because it is a multi-line string? Thanks

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  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

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  • Regular Expression for username

    - by neobie
    I need help on regular expression on the condition (4) below: Begin with a-z End with a-z0-9 allow 3 special characters like ._- The characters in (3) must be followed by alphanumeric characters, and it cannot be followed by any characters in (3) themselves. Not sure how to do this. Any help is appreciated, with the sample and some explanations.

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  • User will input some filter criteria -- how can I turn it into a regular expression for String.match

    - by envinyater
    I have a program where the user will enter a string such as PropertyA = "abc_*" and I need to have the asterisk match any character. In my code, I'm grabbing the property value and replacing PropertyA with the actual value. For instance, it could be abc_123. I also pull out the equality symbol into a variable. It should be able to cover this type of criteria PropertyB = 'cba' PropertyC != '*-this' valueFromHeader is the lefthand side and value is the righthand side. if (equality.equals("=")) { result = valueFromHeader.matches(value); } else if (equality.equals("!=")) { result = !valueFromHeader.matches(value); } EDIT: The existing code had this type of replacement for regular expressions final String ESC = "\\$1"; final String NON_ALPHA = "([^A-Za-z0-9@])"; final String WILD = "*"; final String WILD_RE_TEMP = "@"; final String WILD_RE = ".*"; value = value.replace(WILD, WILD_RE_TEMP); value = value.replaceAll(NON_ALPHA,ESC); value = value.replace(WILD_RE_TEMP, WILD_RE); It doesn't like the underscore here... abcSite_123 != abcSite_123 (evaluates to true) abcSite_123$1.matches("abcSite$1123") It doesn't like the underscore...

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  • Help with this reg. exp. in PHP

    - by Jonathan
    Hi, i don't know about regular expressions, I asked here for one that: gets either anything up to the first parenthesis/colon or the first word inside the first parenthesis. This was the answer: preg_match('/(?:^[^(:]+|(?<=^\\()[^\\s)]+)/', $var, $match); I need an improvement, I need to get either anything up to the first parenthesis/colon/quotation marks or the first word inside the first parenthesis. So if I have something like: $var = 'story "The Town in Hell"s Backyard'; // I get this: $match = 'story'; $var = "screenplay (based on)"; // I get this: $match = 'screenplay'; $var = "(play)"; // I get this: $match = 'play'; $var = "original screen"; // I get this: $match = 'original screen'; Thanks!

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  • validation of special characters

    - by jpallavi
    I want to validate login name with special characters !@#S%^*()+_-?/<:"';. space using regular expression in ruby on rails. These special characters should not be acceptable. What is the code for that? Thanks, Pallavi

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  • Perl Strip Comments with Regex Unique Request

    - by YoDar
    Hello, I'm running a code that read files, do some parsing but need to ignore all comments. There are good explanations how to conduct it. like this link $/ = undef; $_ = <>; s#/\*[^*]*\*+([^/*][^*]*\*+)*/|("(\\.|[^"\\])*"|'(\\.|[^'\\])*'|.[^/"'\\]*)#defined $2 ? $2 : ""#gse; print; My first problem is that after run this line $/ = undef; my code doesn't work properly. Actually, I don't know what it does. But if I could turn it back after ignoring all comments it will be helpful. In general, What is the useful way to ignore all comments without changing the rest of the code ? Thanks, YoDar

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  • JavaScript Regular expressions, match and replace link

    - by Thoman
    Hello please help me <html> <body> http://domainname.com/abc/xyz.zip http://domainname2.com/abc/xyz.zip </body> </html> I want replace with link and out put like <html> <body> <a href="http://domainname.com/abc/xyz.zip">http://domainname.com/abc/xyz.zip</a> <a href="http://domainname2.com/abc/xyz.zip">http://domainname2.com/abc/xyz.zip</a> </body> </html> Great Thank

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  • Way to partialy match a Ruby string using Regexp

    - by Fabiano PS
    I'm working on 2 cases: assume I have those var: a = "hello" b = "hello-SP" b = "not_hello" 1 - Any partial matches I want to accept any string that has the var a inside, so b and c would match. 2 - Patterned match I want to match a string that has a inside, followed by '-', so b would match, c does not. I am having problem, because I always used the syntax /expression/ to define Regexp, so how dinamicaly define an RegExp on Ruby??

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  • How would I create a VIM or Vi command to delete all text after a certain character for every line i

    - by Jason Down
    Scenario: I have a text file that has pipe (as in the "|" character) delimited data. Each field of data in the pipe delimited fields can be of variable length, so counting characters won't work (or using some sort of substring function... if that even exists in VIM). Is it possible, using VIM / Vi to delete all data from the second pipe to the end of the line for the entire file? There are approx 150,000 lines, so doing this manually would only be appealing to a masochist... e.g. Change the following lines from: 1111|random sized text 12345|more random data la la la|1111|abcde 2222|random sized text abcdefghijk|la la la la|2222|defgh 3333|random sized text|more random data|33333|ijklmnop to: 1111|random sized text 12345 2222|random sized text abcdefghijk 3333|random sized text I'm sure this can be done somehow... I hope. TIA UPDATE: I should have mentioned that I'm running this on Windows XP, so I don't have access to some of the mentioned *nix commands (CUT is not recognized on Windows).

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  • Retain Delimiters when Splitting String

    - by JoeC
    Edit: OK, I can't read, thanks to Col. Shrapnel for the help. If anyone comes here looking for the same thing to be answered... print_r(preg_split('/([\!|\?|\.|\!\?])/', $string, null, PREG_SPLIT_DELIM_CAPTURE)); Is there any way to split a string on a set of delimiters, and retain the position and character(s) of the delimiter after the split? For example, using delimiters of ! ? . !? turning this: $string = 'Hello. A question? How strange! Maybe even surreal!? Who knows.'; into this array('Hello', '.', 'A question', '?', 'How strange', '!', 'Maybe even surreal', '!?', 'Who knows', '.'); Currently I'm trying to use print_r(preg_split('/([\!|\?|\.|\!\?])/', $string)); to capture the delimiters as a subpattern, but I'm not having much luck.

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  • How to start matching and saving matched from exact point in a text

    - by yuliya
    I have a text and I write a parser for it using regular expressions and perl. I can match what I need with two empty lines (I use regexp), because there is a pattern that allows recognize blocks of text after two empty lines. But the problem is that the whole text has Introduction part and some text in the end I do not need. Here is a code which matches text when it finds two empty lines #!/usr/bin/perl use strict; use warnings; my $file = 'first'; open(my $fh, '<', $file); my $empty = 0; my $block_num = 1; open(OUT, '>', $block_num . '.txt'); while (my $line = <$fh>) { chomp ($line); if ($line =~ /^\s*$/) { $empty++; } elsif ($empty == 2) { close(OUT); open(OUT, '>', ++$block_num . '.txt'); $empty = 0; } else { $empty = 0;} print OUT "$line\n"; } close(OUT); This is example of the text I need (it's really small :)) this is file example I think that I need to iterate over the text till the moment it will find the word LOREM IPSUM with regexps this kind "/^LOREM IPSUM/", because it is the point from which needed text starts(and save the text in one file when i reach the word). And I need to finish iterating over the text when INDEX word is fount or save the text in separate file. How could I implement it. Should I use next function to proceed with lines or what? BR, Yuliya

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  • Regular Expression - Capture and Replace Select Sequences

    - by Chad
    Take the following file... ABCD,1234,http://example.com/mpe.exthttp://example/xyz.ext EFGH,5678,http://example.com/wer.exthttp://example/ljn.ext Note that "ext" is a constant file extension throughout the file. I am looking for an expression to turn that file into something like this... ABCD,1234,http://example.com/mpe.ext ABCD,1234,http://example/xyz.ext EFGH,5678,http://example.com/wer.ext EFGH,5678,http://example/ljn.ext In a nutshell I need to capture everything up to the urls. Then I need to capture each URL and put them on their own line with the leading capture. I am working with sed to do this and I cannot figure out how to make it work correctly. Any ideas?

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  • How do I process the largest match first in PHP?

    - by animuson
    Ok, so I tried searching around first but I didn't exactly know how to word this question or a search phrase. Let me explain. I have data that looks like this: <!-- data:start --> <!-- 0:start --> <!-- 0:start -->0,9<!-- 0:stop --> <!-- 1:start -->0,0<!-- 1:stop --> <!-- 2:start -->9,0<!-- 2:stop --> <!-- 3:start -->9,9<!-- 3:stop --> <!-- 4:start -->0,9<!-- 4:stop --> <!-- 0:stop --> <!-- 1:start --> <!-- 0:start -->1,5<!-- 0:stop --> <!-- 1:start -->1,6<!-- 1:stop --> <!-- 2:start -->3,6<!-- 2:stop --> <!-- 3:start -->3,8<!-- 3:stop --> <!-- 4:start -->4,8<!-- 4:stop --> <!-- 1:stop --> <!-- 2:start --> <!-- 0:start -->0,7<!-- 0:stop --> <!-- 1:start -->1,7<!-- 1:stop --> <!-- 2:stop --> <!-- data:stop --> So it's basically a bunch of points. Here is the code I'm currently using to try and parse it so that it would create an array like so: Array ( 0 => Array ( 0 => "0,9", 1 => "0,0", 2 => "9,0", 3 => "9,9", 4 => "0,9" ), 1 => Array ( 0 => "1,5", 1 => "1,6", 2 => "3,6", 3 => "3,8", 4 => "4,8" ), 2 => Array ( 0 => "0,7", 1 => "1,7" ) ) However, it is returning an array that looks like this: Array ( 0 => "0,9", 1 => "0,0", 2 => "9,0" ) Viewing the larger array that I have on my screen, you see that it's setting the first instance of that variable when matching. So how do I get it to find the widest match first and then process the insides. Here is the function I am currently using: function explosion($text) { $number = preg_match_all("/(<!-- ([\w]+):start -->)\n?(.*?)\n?(<!-- \\2:stop -->)/s", $text, $matches, PREG_SET_ORDER); if ($number == 0) return $text; else unset($item); foreach ($matches as $item) if (empty($data[$item[2]])) $data[$item[2]] = $this->explosion($item[3]); return $data; } I'm sure it will be something stupid and simple that I've overlooked, but that just makes it an easy answer for you I suppose.

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • Selectively search and replace certain lines using a regular expression

    - by eneveu
    I have a file containing a lot of SQL statements, such as: CREATE TABLE "USER" ( "ID" INTEGER PRIMARY KEY, "NAME" CHARACTER VARYING(50) NOT NULL, "AGE" INTEGER NOT NULL ); COPY "USER" (id, name, age) FROM stdin; 1 Skywalker 19 2 Kenobi 57 I want the column names in the COPY statements to be uppercased and quoted: COPY "USER" ("ID", "NAME", "AGE") FROM stdin; Using sed, I found the following regexp: sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' It does replace the column names, but it is not selective enough, and replaces other words in the file: ~/test]$sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' star_wars_example CREATE TABLE "USER" ( "ID" INTEGER PRIMARY "KEY", "NAME" CHARACTER VARYING("50")NOT "NULL", "AGE" INTEGER NOT NULL ); COPY "USER" ("ID", "NAME", "AGE") FROM stdin; 1 Skywalker 19 2 Kenobi 57 To avoid this problem, I want sed to only apply my regexp to the lines starting with COPY and ending with FROM stdin;. I have looked into lookahead / lookbehind, but they are not supported in sed. They seem to be supported in super-sed, but I am currently using Cygwin (Windows is mandatory here...) and it does not seem available in the package list. Is there a way to force sed to only consider specific line? I've considered piping my file through grep before applying sed, but other lines will then disappear from the output. Am I missing something obvious? It would be great if the answer was easily applicable on a default Cygwin install. I guess I could try installing super-sed on cygwin, but I'd like to know if there are more obvious ideas

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