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  • MySQL insert at end of table

    - by Theopile
    Hello, I am using MySQL and PHP. I am having a problem with inserting a new item at the end of my table. When I insert the new item appears after the last created item, but I want it to be entered at the bottom of the table. Suppose that I have a table id=int,Primary Key and album=string and the table is: Wrath Crack The Skye Enter Shikari What would the MySQL query be if php variable $album=myAlbum was to be inserted next, at the end of the table, and with the appropriate id? Thanks

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  • Splitting a MySQL DB in two may ease server from "Too many connetions"? I don't think so

    - by Petruza
    I was requested to split a MySQL in two, it's kind of a horizontal partition, in which some rows correspond to one site, and some other correspond to another site. But they want to split it in two DBs in the same MySQL server. I'm no DB expert but I guess keeping them in the same MySQL server with the same amount of memory and processor and the same platform won't improve things. What we're trying to avoid is the "Too many connections" problem.

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  • Unix timestamp and mysql date: birthdate

    - by Mikk
    Hi, I have a really basic question concerning unix timestamp and mysql date. I'm trying to build a small website where users can register and fill in their birthdate. Problem is that unix starts with Jan 01 1970. Now if i calculate age for users, form dates like date('m.d.Y', $unix_from_db) and so on it will fail with users older that 40 years, right? So what would be the rigth way for doing this. Sorry, for basic question like this, but I'm inexperienced with php and mysql.

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  • Using function arguments to dynamically generate a query

    - by Varun
    I am working on an issue management system, developed in PHP/MySQL. It requires search functionality, where the user will mention the search parameters and based on these parameters the system will return the result set. To solve this I am trying to write a function and all the user selected parameters are passed as arguments. Based on the arguments I will dynamically generate the query. Sample Query: select * from tickets inner join ticket_assigned_to on tickets.id=ticket_assigned_to.ticket_id where tickets.project_id= in ('') and tickets.status in ('') and ticket_assigned_to.user_id in ('') and tickets.reporter_user_id='' and tickets.operator_user_id in ('') and tickets.due_date between '' and '' and tickets.ts_created between '' and ''; I also need to handle cases where the arguments can be ORed or ANDed in the query. For example: select * from tickets inner join ticket_assigned_to on tickets.id=ticket_assigned_to.ticket_id where tickets.project_id= in ('') and tickets.status in ('') or tickets.due_date = '' or tickets.ts_created between '' and ''; I am also planning to use the same function at other places in the project also. Like to display all the tickets of a user or all tickets created between given dates and so on... How to handle this situation? Should I go with a single function which handles all this or numerous small functions? Need guidance here.

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  • Why does php show error for my SQL query

    - by ZincX
    UPDATE: My mistake - I made a typo. Nevermind this question. I'm using php to update a mysql database. The resultant query I'm using when i print it out on my webpage before executing is as follows: INSERT INTO perch2_content_items (itemOrder, regionID, pageID, itemRev, itemID, itemJSON, itemSearch ) SELECT MAX(itemOrder)+1, 105, 81, 11, 118, 'json', 'search' FROM perch2_content_items WHERE regionID=105 When I copy and paste this query directly into the phpmyadmin SQL interface, it works fine. The table gets updated. However, when I try to execute it using my php code as follows, it throws an error. $insertToPerch = "INSERT INTO perch2_content_items (itemOrder, regionID, pageID, itemRev, itemID, itemJSON, itemSearch ) SELECT MAX(itemOrder)+1, $regionID, $pageID, $regionRev, $newItemID, 'json', 'search' FROM perch2_content_items WHERE regionID=$regionID"; mysql_query(insertToPerch) or die(mysql_error()); The error I'm getting is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'insertToPerch' at line 1 Can anybody help me figure out why it is failing.

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  • how to query an embedded entity by using a query builder

    - by user577719
    I've searched quite a time for an answer to this question. Following Codesmell: @Entity public class Person { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) protected Integer id; @Column(nullable = true, length = 50) @Size(max = 50) private String name; @Embedded @Valid protected Adress adress; public void setId(Integer id) { this.id = id; } public Integer getId() { return this.id; } public void setName(String name) { this.name = name; } public void getName() { return this.name; } public void setAdress(Adress adress) { this.adress = adress; } public void getAdress() { return this.adress; } } @Embeddable public class Adress { @Column(nullable = false, length = 50) @Size(max = 50) @NotNull private String place; public void setPlace(String place) { this.place = place; } public void getPlace() { return this.place; } } public class PersonDaoJpa { public List<Ort> findByPerson(final Person person) { CriteriaBuilder builder = this.entityManager.getCriteriaBuilder(); CriteriaQuery<Person> query = builder.createQuery(Person.class); Root<Person> rootPerson = query.from(Person.class); List<Predicate> wherePredicates = new ArrayList<Predicate>(); if (person.getName() != null) { wherePredicates.add( builder.like(builder.lower(rootPerson.<String>get("name")), ort.getName().toLowerCase()) ); } Adresse adresse = ort.getAdresse(); if (adresse != null) { if(adresse.getPlace() != null) { // this won't work wherePredicates.add( builder.like(builder.lower(rootPerson.<String>get("person.adress.place")), adresse.getPlace().toLowerCase()) ); } } Predicate whereClause = builder.and(wherePredicates.toArray(new Predicate[0])); query.where(whereClause); return this.entityManager.createQuery(query).getResultList(); } } How can I access the Adress.place through rootPerson? rootPerson.get("place"), or rootPerson.get("adress.place") won't work...

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  • Question about Radio button/PHP/MySQL

    - by Marcelo
    Hi, I'm an engineering student and I'm developing a simple software based on HTML, PHP and mysql. I learned this topics on w3schools. I know only the basics. I tried to search about this in this website but I found questions about PHP, MySQL and HTML radio buttons which were much more complex than I need and that I could understand. Sorry for the English. (Q1) Ex: $email=$_REQUEST['email'] , in this case the input is text, if it where like a radio button for ex: sex: male or female, how would it be? (Q2) what would be the type of this field (for exemple sex in question 1) in the database: text, int, varchar ? Thanks for the attention

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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  • MySQL with Java: Open connection only if possible

    - by emempe
    I'm running a database-heavy Java application on a cluster, using Connector/J 5.1.14. Therefore, I have up to 150 concurrent tasks accessing the same MySQL database. I get the following error: Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLNonTransientConnectionException: Too many connections This happens because the server can't handle so many connections. I can't change anything on the database server. So my question is: Can I check if a connection is possible BEFORE I actually connect to the database? Something like this (pseudo code): check database for open connection slots if (slot is free) { Connection cn = DriverManager.getConnection(url, username, password); } else { wait ... } Cheers

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  • mysql replace matching but not changing

    - by alex
    I've used mysql's update replace function before, but even though I think I'm following the same syntax, I can't get this to work-it matches the rows, but doesn't replace. Here's what I'm trying to do: mysql> update contained_widgets set preference_values = replace(preference_values, '<li><a_href="/enewsletter"><span class="not-tc">eNewsletter</span></a></li>', '<li><a_href="/enewsletter"><span class="not-tc">eNewsletter</span></a></li> <li> <a_href="/projects"><span class="not-tc">Projects</span></a></li>'); Query OK, 0 rows affected (0.00 sec) Rows matched: 77 Changed: 0 Warnings: 0 I don't see what I'm missing. Any help is appreciated. I edited "a " to "a_" because the site thinks I'm posting spam links otherwise.

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  • mysql_connect randomly hangs up

    - by sergdev
    I install php 5 (more precisely 5.3.1) as apache module. After this one of my application becomes randomly hang up on mysql_connect - sometimes works, sometimes no, sometimes reload of page helps. How can this be fixed? I use Windows Vista, Apache/2.2.14 (Win32) PHP/5.3.1 with php module, MySql 5.0.67-community-nt.

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  • table outputs blank rows on the browser

    - by fusion
    following the answer here, altho it solved my problem, it displays a blank table. .something like this. the data does get inserted in the mysql but the table displays nothing. the codes are posted on the above link. your help would be appreciated. thanks!

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  • MySQL different versions other results.

    - by kuba
    hey, i have 2 version of mysql on windows 5.1.39-community and on linux 5.1.39-log i execute a query: SELECT `o`.`idOffer`, `o`.`offer_date`, `p`.`factory`, `c`.`short` AS `company`, `s`.`name` AS `subcategory`, `ct`.`name` AS `category`, count( (select count(1) from product where idProduct=idOffer group by idOffer) ) as b FROM `Offer` AS `o` LEFT JOIN `Product` AS `p` ON o.idOffer = p.idOffer LEFT JOIN `company` AS `c` ON o.company = c.id LEFT JOIN `Subcategory` AS `s` ON s.idSubcategory = o.idSubcategory LEFT JOIN `Category` AS `ct` ON ct.idCategory = s.idCategory WHERE (o.idOffer = p.idOffer) GROUP BY `o`.`idOffer` on windows it works as it suppose, but on linux it says: ERROR 1242 (21000): Subquery returns more than 1 row is it any way to get it worked on linux without any mysql updates/downgrades ?

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  • Finding shared list IDs in a MySQL table using bitwise operands

    - by landons
    I want to find items in common from the "following_list" column in a table of users: +----+--------------------+-------------------------------------+ | id | name | following_list | +----+--------------------+-------------------------------------+ | 9 | User 1 | 26,6,12,10,21,24,19,16 | | 10 | User 2 | 21,24 | | 12 | User 3 | 9,20,21,26,30 | | 16 | User 4 | 6,52,9,10 | | 19 | User 5 | 9,10,6,24 | | 21 | User 6 | 9,10,6,12 | | 24 | User 7 | 9,10,6 | | 46 | User 8 | 45 | | 52 | User 9 | 10,12,16,21,19,20,18,17,23,25,24,22 | +----+--------------------+-------------------------------------+ I was hoping to be able to sort by the number of matches for a given user id. For example, I want to match all users except #9 against #9 to see which of the IDs in the "following_list" column they have in common. I found a way of doing this through the "SET" datatype and some bit trickery: http://dev.mysql.com/tech-resources/articles/mysql-set-datatype.html#bits However, I need to do this on an arbitrary list of IDs. I was hoping this could be done entirely through the database, but this is a little out of my league. Any bit gurus out there? Thanks, Landon

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  • Insert record into mysql db with Entity Framework

    - by sanfra1983
    Hi, the problem is that it will insert a new record in a mysql table, I have already done the mapping of the mysql db and I have already done tests returning data and everything works. Now I read from a file, where there are queries written, I have them run me back and the result of true or false based on the final outcome of single query written to the file. Txt; I did this: using (var w = new demotestEntities ()) ( foreach (var l listaqueri) ( var p = we.CreateQuery <category> (l); we.SaveChanges (); result = true; ) ) but it does not work, I sense that it returns no errors, but neither the result given written in the query. txt file is as follows: INSERT INTO category (id, name) VALUES (null, 'test2') anyone can help me?

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  • Selecting two field in MySQL with PHP

    - by Crays
    Hi guys, i'm relatively new to php and mysql and would like to know how to select two value in mysql with php. What i have is $query = sprintf("SELECT COUNT(id) FROM table WHERE UPPER(username) = UPPER('%s') AND password='%s'"... in this case, i'm only selecting and count if the id exist and i use list($count) = mysql_fetch_row($result); if($count == 1) and by using cookies, i would like to retrieve two value from the database, namely user (the user's name) and power (which has value of 1,2 or 3, indicating the menu they would be able to see) basically it is to differentiate if you're admin or normal user, but i wonder if i could do SELECT COUNT(id) AND power FROM table WHERE ... is this possible? or is there any other way? Please guide me, thanks.

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  • Emulating a transaction-safe SEQUENCE in MySQL

    - by Michael Pliskin
    We're using MySQL with InnoDB storage engine and transactions a lot, and we've run into a problem: we need a nice way to emulate Oracle's SEQUENCEs in MySQL. The requirements are: - concurrency support - transaction safety - max performance (meaning minimizing locks and deadlocks) We don't care if some of the values won't be used, i.e. gaps in sequence are ok. There is an easy way to archieve that by creating a separate InnoDB table with a counter, however this means it will take part in transaction and will introduce locks and waiting. I am thinking to try a MyISAM table with manual locks, any other ideas or best practices?

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  • Ubuntu 8.04 LTS MySQL port remote access

    - by Stig Christian
    Hi! I have tried everything I know, but still no solution to this problem. MySQL works perfectly on localhost, but it seems port 3306 is blocked from the outside... I have commented out "bind-address" in /etc/mysql/my.cnf, and there is no iptables rules that deny this port. (I have even opened the port in iptables just to be sure) Still I can`t connect to the server from a remote connection (telnet or portscan returns negative results). Where is the problem?

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