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  • Using a Button to navigate to another Page in a NavigationWindow

    - by Will
    I'm trying to use the navigation command framework in WPF to navigate between Pages within a WPF application (desktop; not XBAP or Silverlight). I believe I have everything configured correctly, yet its not working. I build and run without errors, I'm not getting any binding errors in the Output window, but my navigation button is disabled. Here's the app.xaml for a sample app: <Application x:Class="Navigation.App" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" StartupUri="First.xaml"> </Application> Note the StartupUri points to First.xaml. First.xaml is a Page. WPF automatically hosts my page in a NavigationWindow. Here's First.xaml: <Page x:Class="Navigation.First" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="First"> <Grid> <Button CommandParameter="/Second.xaml" CommandTarget="{Binding RelativeSource= {RelativeSource FindAncestor, AncestorType={x:Type NavigationWindow}}}" Command="NavigationCommands.GoToPage" Content="Go!"/> </Grid> </Page> The button's CommandTarget is set to the NavigationWindow. The command is GoToPage, and the page is /Second.xaml. I've tried setting the CommandTarget to the containing Page, the CommandParameter to "Second.xaml" (First.xaml and Second.xaml are both in the root of the solution), and I've tried leaving the CommandTarget empty. I've also tried setting the Path to the Binding to various navigational-related public properties on the NavigationWindow. Nothing has worked so far. What am I missing here? I really don't want to do my navigation in code. Clarification. If, instead of using a button, I use a Hyperlink: <Grid> <TextBlock> <Hyperlink NavigateUri="Second.xaml">Go! </Hyperlink> </TextBlock> </Grid> everything works as expected. However, my UI requirements means that using a Hyperlink is right out. I need a big fatty button for people to press. That's why I want to use the button to navigate. I just want to know how I can get the Button to provide the same ability that the Hyperlink does in this case.

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  • Twitter refresh page via API

    - by superexsl
    Hey all, I'm using the Twitter API (via TweetSharp) and was wondering if it's possible to automatically refresh the page from the API so that all users see the update? If so, is it also possible to take it one step further by only have a partial page update so only the relevant change is updated instead of the entire page? Thanks for any help

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  • how to load a page and then run a jquery function

    - by Khawar
    on master page i put this code to load page in same master page and then run jqeury function i m trying this $(document).ready(function() { $("#mainContactLink").click(function() { $(body).open("about-us.aspx", self); $(" #abtContacts").fadeIn(1000).siblings("div").fadeOut(100); $(" #abtContacts").siblings(); }); }); its not working.. any idea ?

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  • Linking directly to the Write Review page from iPhone

    - by bparanj
    I have been trying to redirect the user to the review page. I tried 3 different URL formats: {http://phobos.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=350212768&mt=8} (goes to the product page on safari) {http://itunes.apple.com/us/app/british-accent/id350212768?mt=8#} (Goes to the product page in iTunes store on the device) {http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=350212768&pageNumber=0& sortOrdering=1&type=Purple+Software&mt=8} (results in too many redirects) Could you please tell me what the URL format should be to link directly to the review page? Thanks.

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  • ASP.NET : Tracking Unique page visits/views

    - by Shyju
    I have an ASP.NET application where View.aspx page will display the details of each products in a shopping cart.The page displays dynamic data(Ex: For each product id,the content will be different).Now i want to track the unique page views of each product.What are the best solutions to approach this problem ? I am already using google analytics.But i wanna custom solution for my web ap,so that i can know how many hits came for each product

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  • Boost Netbook Speed with an SD Card & ReadyBoost

    - by Matthew Guay
    Looking for a way to increase the performance of your netbook?  Here’s how you can use a standard SD memory card or a USB flash drive to boost performance with ReadyBoost. Most netbooks ship with 1Gb of Ram, and many older netbooks shipped with even less.  Even if you want to add more ram, often they can only be upgraded to a max of 2GB.  With ReadyBoost in Windows 7, it’s easy to boost your system’s performance with flash memory.  If your netbook has an SD card slot, you can insert a memory card into it and just leave it there to always boost your netbook’s memory; otherwise, you can use a standard USB flash drive the same way. Also, you can use ReadyBoost on any desktop or laptop; ones with limited memory will see the most performance increase from using it. Please Note:  ReadyBoost requires at least 256Mb of free space on your flash drive, and also requires minimum read/write speeds.  Most modern memory cards or flash drives meet these requirements, but be aware that an old card may not work with it. Using ReadyBoost Insert an SD card into your card reader, or connect a USB flash drive to a USB port on your computer.  Windows will automatically see if your flash memory is ReadyBoost capable, and if so, you can directly choose to speed up your computer with ReadyBoost. The ReadyBoost settings dialog will open when you select this.  Choose “Use this device” and choose how much space you want ReadyBoost to use. Click Ok, and Windows will setup ReadyBoost and start using it to speed up your computer.  It will automatically use ReadyBoost whenever the card is connected to the computer. When you view your SD card or flash drive in Explorer, you will notice a ReadyBoost file the size you chose before.  This will be deleted when you eject your card or flash drive. If you need to remove your drive to use elsewhere, simply eject as normal. Windows will inform you that the drive is currently being used.  Make sure you have closed any programs or files you had open from the drive, and then press Continue to stop ReadyBoost and eject your drive. If you remove the drive without ejecting it, the ReadyBoost file may still remain on the drive.  You can delete this to save space on the drive, and the cache will be recreated when you use ReadyBoost next time. Conclusion Although ReadyBoost may not make your netbook feel like a Core i7 laptop with 6GB of RAM, it will still help performance and make multitasking even easier.  Also, if you have, say, a memory stick and a flash drive, you can use both of them with ReadyBoost for the maximum benefit.  We have even noticed better battery life when multitasking with ReadyBoost, as it lets you use your hard drive less.  SD cards and thumb drives are relatively cheap today, and many of us have several already, so this is a great way to improve netbook performance cheaply. Similar Articles Productive Geek Tips Speed up Your Windows Vista Computer with ReadyBoostSet the Speed Dial as the Opera Startup PageAsk the Readers: What are Your Computer’s Hardware Specs?Understanding Windows Vista Aero Glass RequirementsReplace Google Chrome’s New Tab Page with Speed Dial TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Recycle ! Find That Elusive Icon with FindIcons Looking for Good Windows Media Player 12 Plug-ins? Find Out the Celebrity You Resemble With FaceDouble Whoa ! Use Printflush to Solve Printing Problems

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  • Should page contents same all time for SEO?

    - by Ahmet Kemal
    Hi, I have a frequently updated website. That's why page contents change frequently. I mean the items that are on 1'st page become on 2'nd page a day after. Similarly 192'nd page which is my last page becomes 193'rd page a day after. So Google finds different content on a specific page than its previous visit. Is it bad for SEO? My main page is http://www.yemeklog.com/home/ and as you see below page pagination pages are like http://www.yemeklog.com/home/10 or http://www.yemeklog.com/home/192 . Website content is about food receipes at all pages. What you think about it?

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  • Remove a bad/erroneous WebPart from a SharePoint page

    - by KunaalKapoor
    If you've added a poorly written webpart to your 'default.aspx' page, the consequence of this action will be that you won't be able to load the page anymore... Don't be sad, there is still a way to remove the webpart from the page :) (Yes, even removing the webpart from the webpart gallery would not solve this issue).Steps to fix this:1. Append the following query string to your URL: ?Contents=1.Once you've added Contents=1 as a query string to the webpart page's URL it will display the Webpart Maintenance Page. Example: http://mysharepointserver/default.aspx?contents=12. On that page you can now see the webparts added to the page, delete the problematic webpart.Now try reloading the default.aspx page... Tadaaa!!! you can view your page again :)3. Leave a thank you note @ comments section :)

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  • SignalR Auto Disconnect when Page Changed in AngularJS

    - by Shaun
    Originally posted on: http://geekswithblogs.net/shaunxu/archive/2014/05/30/signalr-auto-disconnect-when-page-changed-in-angularjs.aspxIf we are using SignalR, the connection lifecycle was handled by itself very well. For example when we connect to SignalR service from browser through SignalR JavaScript Client the connection will be established. And if we refresh the page, close the tab or browser, or navigate to another URL then the connection will be closed automatically. This information had been well documented here. In a browser, SignalR client code that maintains a SignalR connection runs in the JavaScript context of a web page. That's why the SignalR connection has to end when you navigate from one page to another, and that's why you have multiple connections with multiple connection IDs if you connect from multiple browser windows or tabs. When the user closes a browser window or tab, or navigates to a new page or refreshes the page, the SignalR connection immediately ends because SignalR client code handles that browser event for you and calls the "Stop" method. But unfortunately this behavior doesn't work if we are using SignalR with AngularJS. AngularJS is a single page application (SPA) framework created by Google. It hijacks browser's address change event, based on the route table user defined, launch proper view and controller. Hence in AngularJS we address was changed but the web page still there. All changes of the page content are triggered by Ajax. So there's no page unload and load events. This is the reason why SignalR cannot handle disconnect correctly when works with AngularJS. If we dig into the source code of SignalR JavaScript Client source code we will find something below. It monitors the browser page "unload" and "beforeunload" event and send the "stop" message to server to terminate connection. But in AngularJS page change events were hijacked, so SignalR will not receive them and will not stop the connection. 1: // wire the stop handler for when the user leaves the page 2: _pageWindow.bind("unload", function () { 3: connection.log("Window unloading, stopping the connection."); 4:  5: connection.stop(asyncAbort); 6: }); 7:  8: if (isFirefox11OrGreater) { 9: // Firefox does not fire cross-domain XHRs in the normal unload handler on tab close. 10: // #2400 11: _pageWindow.bind("beforeunload", function () { 12: // If connection.stop() runs runs in beforeunload and fails, it will also fail 13: // in unload unless connection.stop() runs after a timeout. 14: window.setTimeout(function () { 15: connection.stop(asyncAbort); 16: }, 0); 17: }); 18: }   Problem Reproduce In the codes below I created a very simple example to demonstrate this issue. Here is the SignalR server side code. 1: public class GreetingHub : Hub 2: { 3: public override Task OnConnected() 4: { 5: Debug.WriteLine(string.Format("Connected: {0}", Context.ConnectionId)); 6: return base.OnConnected(); 7: } 8:  9: public override Task OnDisconnected() 10: { 11: Debug.WriteLine(string.Format("Disconnected: {0}", Context.ConnectionId)); 12: return base.OnDisconnected(); 13: } 14:  15: public void Hello(string user) 16: { 17: Clients.All.hello(string.Format("Hello, {0}!", user)); 18: } 19: } Below is the configuration code which hosts SignalR hub in an ASP.NET WebAPI project with IIS Express. 1: public class Startup 2: { 3: public void Configuration(IAppBuilder app) 4: { 5: app.Map("/signalr", map => 6: { 7: map.UseCors(CorsOptions.AllowAll); 8: map.RunSignalR(new HubConfiguration() 9: { 10: EnableJavaScriptProxies = false 11: }); 12: }); 13: } 14: } Since we will host AngularJS application in Node.js in another process and port, the SignalR connection will be cross domain. So I need to enable CORS above. In client side I have a Node.js file to host AngularJS application as a web server. You can use any web server you like such as IIS, Apache, etc.. Below is the "index.html" page which contains a navigation bar so that I can change the page/state. As you can see I added jQuery, AngularJS, SignalR JavaScript Client Library as well as my AngularJS entry source file "app.js". 1: <html data-ng-app="demo"> 2: <head> 3: <script type="text/javascript" src="jquery-2.1.0.js"></script> 1:  2: <script type="text/javascript" src="angular.js"> 1: </script> 2: <script type="text/javascript" src="angular-ui-router.js"> 1: </script> 2: <script type="text/javascript" src="jquery.signalR-2.0.3.js"> 1: </script> 2: <script type="text/javascript" src="app.js"></script> 4: </head> 5: <body> 6: <h1>SignalR Auto Disconnect with AngularJS by Shaun</h1> 7: <div> 8: <a href="javascript:void(0)" data-ui-sref="view1">View 1</a> | 9: <a href="javascript:void(0)" data-ui-sref="view2">View 2</a> 10: </div> 11: <div data-ui-view></div> 12: </body> 13: </html> Below is the "app.js". My SignalR logic was in the "View1" page and it will connect to server once the controller was executed. User can specify a user name and send to server, all clients that located in this page will receive the server side greeting message through SignalR. 1: 'use strict'; 2:  3: var app = angular.module('demo', ['ui.router']); 4:  5: app.config(['$stateProvider', '$locationProvider', function ($stateProvider, $locationProvider) { 6: $stateProvider.state('view1', { 7: url: '/view1', 8: templateUrl: 'view1.html', 9: controller: 'View1Ctrl' }); 10:  11: $stateProvider.state('view2', { 12: url: '/view2', 13: templateUrl: 'view2.html', 14: controller: 'View2Ctrl' }); 15:  16: $locationProvider.html5Mode(true); 17: }]); 18:  19: app.value('$', $); 20: app.value('endpoint', 'http://localhost:60448'); 21: app.value('hub', 'GreetingHub'); 22:  23: app.controller('View1Ctrl', function ($scope, $, endpoint, hub) { 24: $scope.user = ''; 25: $scope.response = ''; 26:  27: $scope.greeting = function () { 28: proxy.invoke('Hello', $scope.user) 29: .done(function () {}) 30: .fail(function (error) { 31: console.log(error); 32: }); 33: }; 34:  35: var connection = $.hubConnection(endpoint); 36: var proxy = connection.createHubProxy(hub); 37: proxy.on('hello', function (response) { 38: $scope.$apply(function () { 39: $scope.response = response; 40: }); 41: }); 42: connection.start() 43: .done(function () { 44: console.log('signlar connection established'); 45: }) 46: .fail(function (error) { 47: console.log(error); 48: }); 49: }); 50:  51: app.controller('View2Ctrl', function ($scope, $) { 52: }); When we went to View1 the server side "OnConnect" method will be invoked as below. And in any page we send the message to server, all clients will got the response. If we close one of the client, the server side "OnDisconnect" method will be invoked which is correct. But is we click "View 2" link in the page "OnDisconnect" method will not be invoked even though the content and browser address had been changed. This might cause many SignalR connections remain between the client and server. Below is what happened after I clicked "View 1" and "View 2" links four times. As you can see there are 4 live connections.   Solution Since the reason of this issue is because, AngularJS hijacks the page event that SignalR need to stop the connection, we can handle AngularJS route or state change event and stop SignalR connect manually. In the code below I moved the "connection" variant to global scope, added a handler to "$stateChangeStart" and invoked "stop" method of "connection" if its state was not "disconnected". 1: var connection; 2: app.run(['$rootScope', function ($rootScope) { 3: $rootScope.$on('$stateChangeStart', function () { 4: if (connection && connection.state && connection.state !== 4 /* disconnected */) { 5: console.log('signlar connection abort'); 6: connection.stop(); 7: } 8: }); 9: }]); Now if we refresh the page and navigated to View 1, the connection will be opened. At this state if we clicked "View 2" link the content will be changed and the SignalR connection will be closed automatically.   Summary In this post I demonstrated an issue when we are using SignalR with AngularJS. The connection cannot be closed automatically when we navigate to other page/state in AngularJS. And the solution I mentioned below is to move the SignalR connection as a global variant and close it manually when AngularJS route/state changed. You can download the full sample code here. Moving the SignalR connection as a global variant might not be a best solution. It's just for easy to demo here. In production code I suggest wrapping all SignalR operations into an AngularJS factory. Since AngularJS factory is a singleton object, we can safely put the connection variant in the factory function scope.   Hope this helps, Shaun All documents and related graphics, codes are provided "AS IS" without warranty of any kind. Copyright © Shaun Ziyan Xu. This work is licensed under the Creative Commons License.

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  • Google search question, front page not showing...

    - by Catelyn
    I know this is probably a dumb question but I hope someone can give me some insight; I was ranked on Google first page of search results for "funny st patricks day shirts" but I was third from the bottom and not familiar enough with SEO, so I signed up for "Attracta" to rank higher. Big mistake. Since using Attracta, I've lost the first page and I'm now on the fourth page in that search. What I noticed is that Google is now just showing a sub-page or side page, (a link from my front page, to a page which has only a few designs in it) this is not where I would want customers to land first... but my front page is not showing in that search anymore. Obviously, the title of this side page is not geared toward that search result, so I know that's why I have the pr drop. Why is my front page not ranking over that page, though? Why is it apparently gone from that search, or so far back no one will ever find it? I need to know how to fix this quick if anyone has any advice at all for me. It's the busiest season for my website and the people who were stealing design ideas from me are all ranked higher than my site now. (I can prove this, lol) So, I'm very frustrated by that. I would be very grateful to have any advice at all as to what I can do to fix this. THANKS in advance for any advice you can offer. Catelyn

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  • Page.ClientScript Register a pair of javascript code

    - by blgnklc
    How can I register a javascript code a page? I want to put th javascript function to the aspx.page; I thing it might be like that; string strJS= "<script language = javascript> (function(images, elements) { var fetchImages = function() { if(images.length > 0) { var numImages = 10; while(images.length > 0 && numImages-- > 0) { // assuming your elements are <img> document.getElementById(elements.shift()).src = images.shift(); // if not you could also set the background (or backgroundImage) css property // document.getElementById(elements.shift()).style.background = "url(" + images.shift() + ")"; } setTimeout(fetchImages, 5000); } } // bind to window onload window.onload = fetchImages; // if you're going to use something like jquery then do something like this instead //$(fetchImages); }(['url1', 'url2', 'url3'], ['img1', 'img2', 'img3'])) </script>"; Page.ClientScript.RegisterClientScriptBlock(typeof(ui_SUBMVGInfo), "SmartPenCheck", strJS); The second Questin is; ... ... g(ctrlIDBirthPlaceCode).onchange(); }} </script> <script language = javascript> var url1 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Adiniz'; var url2 ='http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Soyadiniz'; var url3 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_tarih'; var url4 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Adiniz'; var url5 ='http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Soyadiniz'; var url6 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_tarih'; var url7 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Adiniz'; var url8 ='http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Soyadiniz'; var url9 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_tarih'; var url10 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Adiniz'; var url11 ='http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_Soyadiniz'; var url12 = 'http://localhost:3645/ImageHandler.ashx?FormId=XXX.11&FieldId=s1_tarih'; function(images, elements) {var fetchImages = function() {if(images.length > 0) {var numImages = 5; while(images.length > 0 && numImages-- > 0) { document.getElementById(elements.shift()).src = images.shift(); }setTimeout(fetchImages, 5000); }}window.onload = fetchImages; }(['+url1+', '+url2+', '+url3+','+url4+', '+url5+', '+url6+','+url7+', '+url8+', '+url9+','+url10+', '+url11+', '+url12+'], ['ui_taskFormControl$ctl03$ctl00$ctl03$ui_CustomerNameImage', 'ui_taskFormControl$ctl03$ctl00$ctl03$ui_CustomerSurNameImage', 'ui_taskFormControl$ctl03$ctl00$ctl03$ui_MaritalStatusImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_SexImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_BirthDateImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_BirthPlaceCodeImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_BirthPlaceImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_IdNationalityImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_MotherOldSurNameImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_TaxNoImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_CitizenshipNoImage','ui_taskFormControl$ctl03$ctl00$ctl03$ui_HomePhoneImage'])); </script> <script> var ui_BirthPlaceCode_a='Intertech.Utility'; var ui_BirthPlaceCode_c='Intertech.Utility.Common'; var ui_BirthPlaceCode_sbn=''; ... .. What do you think is it allright or how can I do that? And according to second question above; the use of the code is correct? ref:** PS: To see my purpose please continue reading below; There is a web site page which is coded on asp.net with using c# and ajax is enabled too. I want a very fast loading web page; which is going to happen with the following architecture; 1- First all data is shown by the text boxes (There are 50 text boxes, it is an application form.) 2- When the web Page is requested and loaded, then I want all the photos are shown near the each text boxes 10 by 10 from top of the page till the end of it. (Each photo is between 5 kb - 20 kb; ) I know ImageHandler's the question is how can I put all these idea into real life? some examples and ideas will be great ! thanks This issue has been answered and you may have a look - here Regards Bk

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  • Google search question, front page not showing

    - by user5746
    I know this is probably a dumb question but I hope someone can give me some insight; I was ranked on Google first page of search results for "funny st patricks day shirts" but I was third from the bottom and not familiar enough with SEO, so I signed up for "Attracta" to rank higher. Big mistake. Since using Attracta, I've lost the first page and I'm now on the fourth page in that search. What I noticed is that Google is now just showing a sub-page or side page, (a link from my front page, to a page which has only a few designs in it) this is not where I would want customers to land first... but my front page is not showing in that search anymore. Obviously, the title of this side page is not geared toward that search result, so I know that's why I have the pr drop. Why is my front page not ranking over that page, though? Why is it apparently gone from that search, or so far back no one will ever find it? I need to know how to fix this quick if anyone has any advice at all for me. It's the busiest season for my website and the people who were stealing design ideas from me are all ranked higher than my site now. (I can prove this, lol) So, I'm very frustrated by that. I would be very grateful to have any advice at all as to what I can do to fix this. THANKS in advance for any advice you can offer. Catelyn

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  • Accidently system timer speed up

    - by Grind Core
    Laptop: Acer 5750zg I've found this issue in latest Ubuntu versions (13.04, 14.04) in all desktop environment. When I'm typing something in text field, randomly I get ~5..20 same symbols and everything speed up. It's happen few times per one minute and start from normal speed, slowly rising to super boost animation and other processes like CPU monitor, clock, window animation, etc. I think something wrong with system clock. Please help to figure out how to fix it.

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  • SEO Software Reviews - Page Speed

    Well they finally went and did it, at last Google has made the announcement that they are now going to count site speed as one of their official page ranking factors. There are hundreds of site rank factors that Google uses and now your page speed will be one of them.

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  • sharepoint custom aspx page with database connection

    - by Megini
    hi there i have created a custom aspx page whithin my sharepoint site with a sql server connection to a database on that server to select data when i view the page it works but when another user tries to view it it gives the following error : Server Error in '/' Application. Login failed for user 'GRINCOR\GuguK'. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Data.SqlClient.SqlException: Login failed for user 'GRINCOR\GuguK'. Source Error: The source code that generated this unhandled exception can only be shown when compiled in debug mode. To enable this, please follow one of the below steps, then request the URL: Add a "Debug=true" directive at the top of the file that generated the error. Example: <%@ Page Language="C#" Debug="true" % or: 2) Add the following section to the configuration file of your application: Note that this second technique will cause all files within a given application to be compiled in debug mode. The first technique will cause only that particular file to be compiled in debug mode. Important: Running applications in debug mode does incur a memory/performance overhead. You should make sure that an application has debugging disabled before deploying into production scenario. Stack Trace: [SqlException (0x80131904): Login failed for user 'GRINCOR\GuguK'.] System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection) +248 System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj) +245 System.Data.SqlClient.TdsParser.Run(RunBehavior runBehavior, SqlCommand cmdHandler, SqlDataReader dataStream, BulkCopySimpleResultSet bulkCopyHandler, TdsParserStateObject stateObj) +2811 System.Data.SqlClient.SqlInternalConnectionTds.CompleteLogin(Boolean enlistOK) +53 System.Data.SqlClient.SqlInternalConnectionTds.AttemptOneLogin(ServerInfo serverInfo, String newPassword, Boolean ignoreSniOpenTimeout, Int64 timerExpire, SqlConnection owningObject) +327 System.Data.SqlClient.SqlInternalConnectionTds.LoginNoFailover(String host, String newPassword, Boolean redirectedUserInstance, SqlConnection owningObject, SqlConnectionString connectionOptions, Int64 timerStart) +2445370 System.Data.SqlClient.SqlInternalConnectionTds.OpenLoginEnlist(SqlConnection owningObject, SqlConnectionString connectionOptions, String newPassword, Boolean redirectedUserInstance) +2445224 System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, Object providerInfo, String newPassword, SqlConnection owningObject, Boolean redirectedUserInstance) +354 System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection) +703 System.Data.ProviderBase.DbConnectionFactory.CreatePooledConnection(DbConnection owningConnection, DbConnectionPool pool, DbConnectionOptions options) +54 System.Data.ProviderBase.DbConnectionPool.CreateObject(DbConnection owningObject) +2414776 System.Data.ProviderBase.DbConnectionPool.UserCreateRequest(DbConnection owningObject) +92 System.Data.ProviderBase.DbConnectionPool.GetConnection(DbConnection owningObject) +1657 System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) +84 System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) +1645767 System.Data.SqlClient.SqlConnection.Open() +258 ASP.d7922f0d_ac20_4f87_91a2_a99a52c2b2fa__233736835.DisplayData() in C:\inetpub\wwwroot\wss\VirtualDirectories\80\sites\hrportal2\tester.aspx:151 ASP.d7922f0d_ac20_4f87_91a2_a99a52c2b2fa_233736835._RenderMain(HtmlTextWriter __w, Control parameterContainer) in C:\inetpub\wwwroot\wss\VirtualDirectories\80\sites\hrportal2\tester.aspx:346 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +115 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +240 System.Web.UI.HtmlControls.HtmlContainerControl.Render(HtmlTextWriter writer) +42 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +240 System.Web.UI.HtmlControls.HtmlForm.RenderChildren(HtmlTextWriter writer) +253 System.Web.UI.HtmlControls.HtmlForm.Render(HtmlTextWriter output) +87 System.Web.UI.HtmlControls.HtmlForm.RenderControl(HtmlTextWriter writer) +53 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +240 System.Web.UI.HtmlControls.HtmlContainerControl.Render(HtmlTextWriter writer) +42 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +240 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +240 System.Web.UI.Page.Render(HtmlTextWriter writer) +38 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +4240 Version Information: Microsoft .NET Framework Version:2.0.50727.3603; ASP.NET Version:2.0.50727.3601 can someone give me a solution to this problem ? i am using sharepoint services 3.0

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  • Page output caching for dynamic web applications

    - by Mike Ellis
    I am currently working on a web application where the user steps (forward or back) through a series of pages with "Next" and "Previous" buttons, entering data until they reach a page with the "Finish" button. Until finished, all data is stored in Session state, then sent to the mainframe database via web services at the end of the process. Some of the pages display data from previous pages in order to collect additional information. These pages can never be cached because they are different for every user. For pages that don't display this dynamic data, they can be cached, but only the first time they load. After that, the data that was previously entered needs to be displayed. This requires Page_Load to fire, which means the page can't be cached at that point. A couple of weeks ago, I knew almost nothing about implementing page caching. Now I still don't know much, but I know a little bit, and here is the solution that I developed with the help of others on my team and a lot of reading and trial-and-error. We have a base page class defined from which all pages inherit. In this class I have defined a method that sets the caching settings programmatically. For pages that can be cached, they call this base page method in their Page_Load event within a if(!IsPostBack) block, which ensures that only the page itself gets cached, not the data on the page. if(!IsPostBack) {     ...     SetCacheSettings();     ... } protected void SetCacheSettings() {     Response.Cache.AddValidationCallback(new HttpCacheValidateHandler(Validate), null);     Response.Cache.SetExpires(DateTime.Now.AddHours(1));     Response.Cache.SetSlidingExpiration(true);     Response.Cache.SetValidUntilExpires(true);     Response.Cache.SetCacheability(HttpCacheability.ServerAndNoCache); } The AddValidationCallback sets up an HttpCacheValidateHandler method called Validate which runs logic when a cached page is requested. The Validate method signature is standard for this method type. public static void Validate(HttpContext context, Object data, ref HttpValidationStatus status) {     string visited = context.Request.QueryString["v"];     if (visited != null && "1".Equals(visited))     {         status = HttpValidationStatus.IgnoreThisRequest; //force a page load     }     else     {         status = HttpValidationStatus.Valid; //load from cache     } } I am using the HttpValidationStatus values IgnoreThisRequest or Valid which forces the Page_Load event method to run or allows the page to load from cache, respectively. Which one is set depends on the value in the querystring. The value in the querystring is set up on each page in the "Next" and "Previous" button click event methods based on whether the page that the button click is taking the user to has any data on it or not. bool hasData = HasPageBeenVisited(url); if (hasData) {     url += VISITED; } Response.Redirect(url); The HasPageBeenVisited method determines whether the destination page has any data on it by checking one of its required data fields. (I won't include it here because it is very system-dependent.) VISITED is a string constant containing "?v=1" and gets appended to the url if the destination page has been visited. The reason this logic is within the "Next" and "Previous" button click event methods is because 1) the Validate method is static which doesn't allow it to access non-static data such as the data fields for a particular page, and 2) at the time at which the Validate method runs, either the data has not yet been deserialized from Session state or is not available (different AppDomain?) because anytime I accessed the Session state information from the Validate method, it was always empty.

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  • Single page not appearing in Google Search

    - by Dan
    Description I have a static franchise website which has various sub pages each dedicated to an individual franchisee. For each franchisee the page, the only thing slightly similar between all of them are the page titles, they follow this structure: <title> Welcome to THE_COMPANY - PRODUCT_DESCRIPTION Services, THE_LOCATION </title> THE_COMPANY and PRODUCT_DESCRIPTION are the same across all franchisees, however THE_LOCATION changes depeding on where they are located in the UK. Each franchisee page has the following <meta /> tags: <meta name="DC.creator" content="user"/> <meta name="DC.format" content="text/html"/> <meta name="DC.language" content="en"/> <meta name="DC.date.modified" content="2014-01-23T11:22:31+00:00"/> <meta name="DC.date.created" content="2014-01-23T11:22:09+00:00"/> <meta name="DC.type" content="Page"/> <meta name="DC.distribution" content="Global"/> <meta name="robots" content="ALL"/> <meta name="distribution" content="Global"/> The main content on each franchisee page is completely different. The Problem There is one particular franchisee page, located in Area A.. Which will not appear in Google Search results at all. However every single other franchisee (if you Google Search for "THE_COMPANY, THE_LOCATION" is number 1). And if I do the same search on Bing, Yahoo or DuckDuckGo, the Area A franchisee is the first result on all of them. Has Google for some reason black listed one page on the site? What I Have Tried Ensuring the page is referenced in my sitemap.xml file 'Fetching as Google Bot' the link www.the_company.co.uk/areaa When that came back as OK I would submit to index Resubmitting the sitemap.xml file in Webmaster Tools Linking to the Area A page from another pages content For this I also waited about 3 weeks before checking again to give Google time to re-index Making a change to the page content and waiting another 2 / 3 weeks Removing the page completely and recreating it with an alternative URL The closest thing I have found to this issue is this StackOverflow question but this particular franchisee has existed for almost a year, it used to appear on Google searches however no longer does. I'm guessing the Panda update wasn't too happy with something on the page, but it hasn't effected anything else on the site and I am at a loss for things to try. I would greatly appreciate any information or thoughts as to what could have caused this Thanks. Update In line with Daniel Fukudas answer below, I have followed some of his steps but everything seems to check out alright: HTTP Headers HTTP/1.1 200 OK => Date => Tue, 25 Feb 2014 16:31:29 GMT Server => Zope/(2.12.16, python 2.6.6, linux2) ZServer/1.1 Content-Length => 40078 Expires => Sat, 01 Jan 2000 00:00:00 GMT Content-Type => text/html;charset=utf-8 Content-Language => en Vary => Accept-Encoding Connection => close Robots <meta /> tag: <meta name="robots" content="ALL"/> I have updated this <meta /> tag to read content="INDEX" instead now. robots.txt: User-agent: * Disallow: User-Agent: Googlebot Disallow: /*sendto_form$ Disallow: /*folder_factories$ Using site:THE_COMPANY.co.uk: Searching for 'AREA A site:THE_COMPANY.co.uk' does not return the page, but regardless of that searching just for site:THE_COMPANY.co.uk will not necessarily return every indexed page, or so I understand... Update It appears Google likes to drop pages every now and then from the index, despite my steps above, I left the site alone and the page appeared back in the SERPs by itself.

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  • Troubleshoot Page Loading Issue (ActiveX control)

    - by Spence
    Apologies for cryptic title, I'm hoping most people will read this BEFORE trying to move it to server fault. I might try and discourage the "too hard basket, move it to server fault anyway" crowd as well :). I have a page which will open cleanly when it's opened in it's own browser window/tab. The exact same URL, when loaded as part of a frame in a page in the same (local intranet) security zone shows the error: Your security settins do not allow websites to use ActiveX controls installed on your computer. This page may not display correctly. Click Here for options. How do I troubleshoot IE to work out which ActiveX control won't load in the frame but does load if the page is opened directly? Please note that I have dropped the security fully AND I've also moved EVERY setting in IE to enable or allow and restarted the browser but I STILL get the same issue. The two sites are on different machines in the same domain. I can't access website source code but I can ask for it to be fixed, so I'd really appreciate some help on this.

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  • Rails' page caching vs. HTTP reverse proxy caches

    - by John Topley
    I've been catching up with the Scaling Rails screencasts. In episode 11 which covers advanced HTTP caching (using reverse proxy caches such as Varnish and Squid etc.), they recommend only considering using a reverse proxy cache once you've already exhausted the possibilities of page, action and fragment caching within your Rails application (as well as memcached etc. but that's not relevant to this question). What I can't quite understand is how using an HTTP reverse proxy cache can provide a performance boost for an application that already uses page caching. To simplify matters, let's assume that I'm talking about a single host here. This is my understanding of how both techniques work (maybe I'm wrong): With page caching the Rails process is hit initially and then generates a static HTML file that is served directly by the Web server for subsequent requests, for as long as the cache for that request is valid. If the cache has expired then Rails is hit again and the static file is regenerated with the updated content ready for the next request With an HTTP reverse proxy cache the Rails process is hit when the proxy needs to determine whether the content is stale or not. This is done using various HTTP headers such as ETag, Last-Modified etc. If the content is fresh then Rails responds to the proxy with an HTTP 304 Not Modified and the proxy serves its cached content to the browser, or even better, responds with its own HTTP 304. If the content is stale then Rails serves the updated content to the proxy which caches it and then serves it to the browser If my understanding is correct, then doesn't page caching result in less hits to the Rails process? There isn't all that back and forth to determine if the content is stale, meaning better performance than reverse proxy caching. Why might you use both techniques in conjunction?

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  • Facebook Connect application page Errors while loading page from application

    - by Lily
    Hi I am getting this error from my Facebook Application profile page Errors while loading page from application The URL is not valid. Please try again later. We appreciate your patience as the developers of SocialAnalysis and Facebook resolve this issue. Thanks! The application page is http://www.facebook.com/apps/application.php?id=333786146530 and when I try to go to the application, it gives me that error

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  • Ruby on Rails - Static page as start page

    - by meetraghu28
    Hello! I am developing an app in RoR which has static and dynamic parts. The static portion is placed in the public/ folder of the app. Now if i have an index.html in my public folder then i will not be able to use the routes configured in my routes.rb The default configurations like map.connect /:controller/:action will not be usable if i have an index.html. So i removed the index html. Now i have a static page startpage.html in my public/ folder which has to be the starting page of the app. And the i have links in it for other static/dynamic pages. The RoR app is hosted in apache and i tried to configure the Virtual Host configuration by adding the DirectoryIndex param so that when ever a request comes for the site it will direct it to the startpage.html but still it takes me to the default controller that i have specified in routes.rb with map.root I dont want to add a dummy controller and action and create a view which has the startpage and configure routes.rb to use it as the root. What i am looking to do here is Basically startpage.html should be my first page in the app served as a static page from the public/ folder. This will then have links to other pages and controllers/actions Here i am not able to apache to redirect to the html page instead of passing on the control to rails application. Directory listing is also enabled by using Options Indexes but still no change. Any pointers anyone?

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