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  • jQuery UI DatePicker - Change Date Format

    - by tarnfeld
    I am using the UI DatePicker from jQuery UI as the stand alone picker.. i have this code <div id="datepicker"></div> And the follow JS $('#datepicker').datepicker(); When i try to return the value with this code: var date = $('#datepicker').datepicker('getDate'); I am returned this... Tue Aug 25 2009 00:00:00 GMT+0100 (BST) Which is totally the wrong format... Is there a way i can return DD-MM-YYYY ??

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  • Dynamic change of class of <TR> with Jquery

    - by Coronier
    Hi all, This is my first post, and first please forgive me for my poor english. I have a problem I really can't fix: I have a <table> of questions, the first question is visible (class:visible), the others are hidden (class:hidden) $(document).ready(function(){ $('.hidden').hide(); When people click on the first question, I want the second question to appear (and the first question to turn to grey, using a 'done' class). $('.visible:not(.done)').click(function(){ $(this).addClass('done'); $('.hidden:first').toggle(500).removeClass('hidden').addClass('visible'); }) The first question is now done (class:done) and the 2nd question should be the only one to react to a click(), and so on... But it doesn't work: the other <tr> appear only when I click on the 1st <tr>. Can someone give me a hand on this problem ? Thank you.

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  • Overlapping elements stop overlapping in IE7 on class change

    - by Gazzer
    On this page http://zenchan.com/program/ When I rollover the right box 2nd from the top suddenly the overlapping (negative margin disappears). What's happening is that a 'hover' class is being added to shift the background sprite. The two yellow boxes are debugging: if the hover class is put their in advance there is no problem. So fundamentally the CSS is not a problem for IE7 but adding the class is. Any ideas what's causing this. I've tried adding haslayout to various elements but to little effect.

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  • how to change the name dynamicaly usign jquery grid

    - by kumar
    hello friends, I am using jquery grid I have jquery grid with user data..First Coulum is ID.. here is the code $("#table").click(function(e) { var row = jQuery(e.target).parent(); Name = row.attr("id"); Friends(Name); }); Now when i click on the row I am getting Id value.. i am passing this id value to one funcation to dispaly name.. I can able to dispaly the name only frist Id.. its not changing each and every row click? Can any body help me out thanks

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  • What is the best way to store static data in C# that will never change

    - by Luke101
    I have a class that stores data in asp.net c# application that never changes. I really don't want to put this data in the database - I would like it to stay in the application. Here is my way to store data in the application: public class PostVoteTypeFunctions { private List<PostVoteType> postVotes = new List<PostVoteType>(); public PostVoteTypeFunctions() { PostVoteType upvote = new PostVoteType(); upvote.ID = 0; upvote.Name = "UpVote"; upvote.PointValue = PostVotePointValue.UpVote; postVotes.Add(upvote); PostVoteType downvote = new PostVoteType(); downvote.ID = 1; downvote.Name = "DownVote"; downvote.PointValue = PostVotePointValue.DownVote; postVotes.Add(downvote); PostVoteType selectanswer = new PostVoteType(); selectanswer.ID = 2; selectanswer.Name = "SelectAnswer"; selectanswer.PointValue = PostVotePointValue.SelectAnswer; postVotes.Add(selectanswer); PostVoteType favorite = new PostVoteType(); favorite.ID = 3; favorite.Name = "Favorite"; favorite.PointValue = PostVotePointValue.Favorite; postVotes.Add(favorite); PostVoteType offensive = new PostVoteType(); offensive.ID = 4; offensive.Name = "Offensive"; offensive.PointValue = PostVotePointValue.Offensive; postVotes.Add(offensive); PostVoteType spam = new PostVoteType(); spam.ID = 0; spam.Name = "Spam"; spam.PointValue = PostVotePointValue.Spam; postVotes.Add(spam); } } When the constructor is called the code above is ran. I have some functions that can query the data above too. But is this the best way to store information in asp.net? if not what would you recommend?

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  • change images by clicking left and right

    - by Qin
    I want to display an image in the center of the page, then 2 buttons, left, and right, when I click on left, the image changes to previous one, and move to next image by clicking right. And my question is, the code doesn't work..=.=, very obvious, can anybody tell me where the mistakes are? <table id="frontpage"> <tr> <td><input type="button" id="left" value="left"/></td> <td><img id="image" alt="Image" src="./image/guildwars2/gw2_fight.jpg"/></td> <td><input type="button" id="right" value="right"/></td> </tr> </table> $(document).ready(function(){ var image=new Array(); var current=0; image[0]=new Image(); image[0].src="./image/guildwars2/gw2_fight.jpg"; image[1]=new Image(); image[1].src="./image/diablo3/d3.jpg"; image[2]=new Image(); image[2].src="./image/dota2/catOnWater.jpg"; $("#left").click(function(){ if(current-1<0){ current=image.length-1; $("#image").attr("src")=image[current].src; } else{ --current; $("#image").attr("src")=image[current].src; } }); $("#right").click(function(){ if(current+1>image.length-1){ current=0; $("#image").attr("src")=image[current].src; } else{ ++current; $("#image").attr("src")=image[current].src; } }); })

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  • How can I change ruby log level in unit tests based on context

    - by Stuart
    I'm new to ruby so forgive me if this is simple or I get some terminology wrong. I've got a bunch of unit tests (actually they're integration tests for another project, but they use ruby test/unit) and they all include from a module that sets up an instance variable for the log object. When I run the individual tests I'd like log.level to be debug, but when I run a suite I'd like log.level to be error. Is it possible to do this with the approach I'm taking, or does the code need to be restructured? Here's a small example of what I have so far. The logging module: #!/usr/bin/env ruby require 'logger' module MyLog def setup @log = Logger.new(STDOUT) @log.level = Logger::DEBUG end end A test: #!/usr/bin/env ruby require 'test/unit' require 'mylog' class Test1 < Test::Unit::TestCase include MyLog def test_something @log.info("About to test something") # Test goes here @log.info("Done testing something") end end A test suite made up of all the tests in its directory: #!/usr/bin/env ruby Dir.foreach(".") do |path| if /it-.*\.rb/.match(File.basename(path)) require path end end

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  • Change axes of google chart without refresh?

    - by Mike Kriess
    If I was using the following: https://developers.google.com/chart/interactive/docs/gallery/annotatedtimeline Assuming I did not have the line: data.addColumn('number', 'Sold Pencils'); or anything referring to 'Sold Pencils'; How do I make it such that when the user clicks an external link 'Sold Pencils' I am able to retrieve the data and add it to the graph (without the user refreshing the page). Is there some way to redraw the graph/add the column in this way?

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  • full-text property change on column

    - by matt99
    Hello, i'm trying to modify a property of a column (in sql server 2008 r2) which is of xml data type. I want set (Is full-text indexed) to yes, but after I do this and try to save changes, i get an error: 'Abc' table - Unable to modify table. Column: B is not full-text searchable. Column B is not the column I'm modyfing, but it's content is based on the modified xml column (it takes a value from one element in xml). Weird thing is that column B is full-text indexed (in table designer). Any ideas why i cannot apply changes to the xml column?

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  • How to change data structure in mysql using mysqldump without deleting files

    - by Don Quixote
    Essentially what I'm trying to do is sync a production server with a sandbox server, but only the table structures and stored procedures. The procedures aren't any problem since they can be overriden, but the problem is the tables. I want to sync and alter their structures on the production server using mysqldump (or any other way that you can propose) without altering any existing data. If it helps, I only want to add more columns, not remove any existing ones. Also, I am using mysqlyog. Is there any way to do this?

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  • hover buttons background image change not working

    - by Brae
    Background I'm trying to make a menu, you hover over the button and the background image shifts its Y position to give you the 'over' effect for each button. CSS .menu {float: left;} .menu span {display: none;} .menu a {display: block; margin: 10px; width: 200px; height: 50px;} #itemA {background: url('images/btnA.png') no-repeat 0 0;} #itemB {background: url('images/btnB.png') no-repeat 0 0;} #itemC {background: url('images/btnC.png') no-repeat 0 0;} #itemD {background: url('images/btnD.png') no-repeat 0 0;} HTML <div class="menu"> <a id="itemA" href="#"><span>AAAAA</span></a> <a id="itemB" href="#"><span>BBBBB</span></a> <a id="itemC" href="#"><span>CCCCC</span></a> <a id="itemD" href="#"><span>DDDDD</span></a> </div> Problem why do none of these work? /*** - test A a.menu:link {background-position: 0 -51px;} a.menu:visited {display: block; margin: 10px; width: 200px; height: 32px;} ***/ /*** - test B a.menu:hover {background-position: 0 -51px;} ***/ /*** - test C .menu a:hover {background-position: 0 -51px;} ***/ /*** - test D .menu:hover a {background-position: 0 -51px;} ***/ /*** - test E a:hover .menu {background-position: 0 -51px;} ***/ Notes images are 200x101px (50px high with a 1px seperator) Question why do none of these work, should any of them work, is there a solution im missing? thanks in advance!

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  • Use jQuery to change a CSS value

    - by justSteve
    If i have a background image defined as: #header { width: 100%; background: url(/Content/images/header.jpg) -0 0 no-repeat; } and i want to overwrite that after the page loads. Shouldn't this code work? $("#header").css('background-image', '/Content/images/aff/header_<%=affiliateID%>.jpg')

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  • a minimal change to my code is breaking it

    - by Delirium tremens
    Works (it sets lasturi): var domainnameuri; var generaldomainnameuri; domainnameuri = sc.domainnameuri; generaldomainnameuri = sc.generaldomainnameuri; sc.redirectinggeneral = false; $.ajax({ type: "GET", url: generaldomainnameuri, success: function(data, textStatus) { if (data.redirect == domainnameuri) { sc.redirectinggeneral = true; } sc.setlasturi(); } }); Doesn't work (it doesn't set lasturi): this.setredirectinggeneral = function(c) { var domainnameuri; var generaldomainnameuri; domainnameuri = sc.domainnameuri; generaldomainnameuri = sc.generaldomainnameuri; sc.redirectinggeneral = false; $.ajax({ type: "GET", url: generaldomainnameuri, success: function(data, textStatus) { if (data.redirect == domainnameuri) { sc.redirectinggeneral = true; } c(); } }); } sc.setredirectinggeneral(sc.setlasturi); Why?

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  • Change Interval Of CADisplayLink

    - by user3679109
    I have replaced an NSTimer with a CADisplayLink. I have it working properly but it is running too slowly. How could I go about speeding this up? This is the code that I'm using: ViewController.h (In {} with @interface: CADisplayLink *displayLink; ViewController.m (viewDidLoad): displayLink = [CADisplayLink displayLinkWithTarget:self selector:@selector(onTimer)]; [displayLink addToRunLoop:[NSRunLoop currentRunLoop] forMode:NSRunLoopCommonModes]; onTimer is the method that it is calling. So my question is how do I speed up how often this is being called? Thanks

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  • XSLT: change node inner text.

    - by nabo
    I need to transform the following xml doc: <a> <b/> <c/> myText </a> into this: <a> <b/> <c/> differentText </a> So, i wrote this XSLT document <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" version="1.0" omit-xml-declaration="no" /> <xsl:template match="/a/text()"> <a> <b/> <c/> differentText </a> </xsl:template> </xsl:stylesheet> This way, i get the following result: <?xml version="1.0" encoding="utf-8"?> <a> <b /><c /> differentText </a> <a> <b /><c /> differentText </a> <a> <b /><c /> differentText </a> The result appears repeated 3 times because 3 matches are being done.. Why? I could i fix it? Thanks

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  • How do I dynamically change the path_to()?

    - by Angela
    I currently have three methods which I want to collapse into one: def send_email(contact,email) end def make_call(contact, call) return link_to "Call", new_contact_call_path(:contact => contact, :call => call, :status => 'called') end def make_letter(contact, letter) return link_to "Letter", new_contact_letter_path(:contact => contact, :letter => letter, :status => 'mailed') end I want to collapse the three into one so that I can just pass the Model as one of the parameters and it will still correctly create the path_to. I am trying to do this with the following, but stuck: def do_event(contact, call_or_email_or_letter) model_name = call_or_email_or_letter.class.name.tableize.singularize link_to "#{model_name.camelize}", new_contact_#{model_name}_path(contact, call_or_email_or_letter)" end

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  • Delay in the implementation of text change in Statusbar control

    - by ehsan zeynali
    I have a function a time consuming operation that is done I want to start and end operations appear to be user (By statusbar control) But when performed function, both text executed at the end of function. (user can not sees "Start Operation ...") What solution do you recommend to me? private void btnUpdateDataBase_Click(object sender, RoutedEventArgs e) { TextBlockStatus.Text = "Start Operation ..."; //Time consuming operation TextBlockStatus.Text = "End Operation ..."; }

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  • Reloading Rails Directories on Change for Development, Not in Lib

    - by yar
    I have checked out several questions on this, including all of those you see next to the question. Unfortunately, I'm not working with a plugin, and I don't want to work in lib. I have a directory called File.join(Rails.root, 'classes') and I'd like the classes in this directory to reload automatically in dev. In my environment.rb I have this line config.load_paths << File.join(Rails.root, 'classes') which works fine and blows up if the path isn't there. The reloading line in my development.rb also works fine require_dependency File.join(Rails.root, 'classes', 'blah.rb') which blows up if the file is not there (a good sign). However, the file doesn't reload. This all works if the file is in the root of lib and I use the require_dependency line, but my whole point is to get stuff out of lib as suggested here.

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  • Change object on client side or on server side

    - by Polina Feterman
    I'm not sure what is the best practice. I have some big and complex objects (NOT flat). In that object I have many related objects - for example Invoice is the main class and one of it's properties is invoiceSupervisor - a big class by it's own called User. User can also be not flat and have department property - also an object called Department. For example I want create new Invoice. First way: I can present to client several fields to fill in. Some of them will be combos that I will need to fill with available values. For example available invoiceSupervisors. Then all the chosen values I can send to server and on server I can create new Invoice and assign all chosen values to that new Invoice. Then I will need to assign new supervisor I will pull the chosen User by id that user picked up on server from combobox. I might do some verification on the User such as does the user applicable to be invoice supervisor. Then I will assign the User object to invoiceSupervisor. Then after filling all properties I will save the new invoice. Second way: In the beginning I can call to server to get a new Invoice. Then on client I can fill all chosen values , for example I can call to server to get new User object and then fill it's id from combobox and assign the User as invoiceSupervisor. After filling the Invoice object on client I can send it to server and then the server will save the new invoice. Before saving server can run some validations as well. So what is the best approach - to make the object on client and send it to server or to collect all values from client and to make a new object on server using those values ?

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  • Why does the app signature change in Android after a classpath change?

    - by espinchi
    I have an Android project that branched into three different applications, app-1, app-2 and app-3, that apply some customizations. Currently there is a lot of code duplication, making maintenance a nightmare: do the changes in one of the branches, and then merge the other two. So we create a library project, named app-core, that factors out most of the duplicated code. So far so good. When I launch this into an emulator where the application was already loaded (before the refactoring), I get this exception: Re-installation failed due to different application signatures A different signature? But I just added a line in the .classpath to link to the app-core Java project! The main question is: are the existing users going to be bothered by this too? And the side question: Why is it a different signature?

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