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  • Java, JavaCC: How to check if a char (or char pair) is inside a given UTF32 range?

    - by java.is.for.desktop
    Hello, everyone! I am referring to the XML 1.1 spec. Look at the definition of NameStartChar: NameStartChar ::= ":" | [A-Z] | "_" | [a-z] | [#xC0-#xD6] | [#xD8-#xF6] | [#xF8-#x2FF] | [#x370-#x37D] | [#x37F-#x1FFF] | [#x200C-#x200D] | [#x2070-#x218F] | [#x2C00-#x2FEF] | [#x3001-#xD7FF] | [#xF900-#xFDCF] | [#xFDF0-#xFFFD] | [#x10000-#xEFFFF] If I interpret this correctly, the last range (#x10000-#xEFFFF) goes beyond the UTF16 range of Java's char type. So it must be UTF32, right? So, I need to check pairs of char against this range, instead of single chars, right? My questions are: How do I check for such character ranges using standard Java methods? How is it possible to define such ranges in JavaCC? JavaCC complains about \u10000 and \uEFFFF Thank you! NOTE: Don't worry, I am not trying to write an own XML-parser. I need those character ranges for other reasons.

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  • C++: Why does space always terminate a string when read?

    - by Nullw0rm
    Using type std::string to accept a sentence, for practise (I haven't worked with strings in C++ much) I'm checking if a character is a vowel or not. I got this: for(i = 0; i <= analyse.length(); i++) { if(analyse[i] == 'a' || analyse[i] == 'e' [..etc..]) { ...vowels++; } else { ... ...consenents++; } This works fine if the string is all one word, but the second I add a space (IE: aeio aatest) it will only count the first block and count the space as a consenent, and quit reading the sentence (exiting the for loop or something). Does a space count as no character == null? Or some oddity with std::string?, It would be helpful to know why that is happening!

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  • How to calculate the touch location with convertToWorldSpace?

    - by Paul
    i would like to convert the touch location as a world coordinate in my tile game. With this code, i clicked on the right of the screen (so that my character walks in the tiled game, and the background goes slowly to the left) : - (void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { for( UITouch *touch in touches ) { CGPoint location = [touch locationInView: [touch view]]; location = [[CCDirector sharedDirector] convertToGL: location]; CGPoint test = [self convertToWorldSpace:location]; CCLOG(@"test : %.2g", test.x); The test log gives me : 50, 72, 1e+02, 2.6e+02, 4.2e+02, (and then goes down) 3.2e+02, 9.5, -1.9e+02, etc. Does anyone know why? I would like to calculate the "real" coordinate of the touch, so that i know when the character has to keep going (click on the right of its actual position) or if he has to turn and go backwards. (click on the left of its actual position) Thanks for your help

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  • Help me with this java program

    - by aser
    The question : Input file: customer’s account number, account balance at beginning of month, transaction type (withdrawal, deposit, interest), transaction amount Output: account number, beginning balance, ending balance, total interest paid, total amount deposited, number of deposits, total amount withdrawn, number of withdrawals package sentinel; import java.io.*; import java.util.*; public class Ex7 { /** * @param args the command line arguments */ public static void main(String[] args) throws FileNotFoundException { int AccountNum; double BeginningBalance; double TransactionAmount; int TransactionType; double AmountDeposited=0; int NumberOfDeposits=0; double InterestPaid=0.0; double AmountWithdrawn=0.0; int NumberOfWithdrawals=0; boolean found= false; Scanner inFile = new Scanner(new FileReader("Account.in")); PrintWriter outFile = new PrintWriter("Account.out"); AccountNum = inFile.nextInt(); BeginningBalance= inFile.nextDouble(); while (inFile.hasNext()) { TransactionAmount=inFile.nextDouble(); TransactionType=inFile.nextInt(); outFile.printf("Account Number: %d%n", AccountNum); outFile.printf("Beginning Balance: $%.2f %n",BeginningBalance); outFile.printf("Ending Balance: $%.2f %n",BeginningBalance); outFile.println(); switch (TransactionType) { case '1': // case 1 if we have a Deposite BeginningBalance = BeginningBalance + TransactionAmount; AmountDeposited = AmountDeposited + TransactionAmount; NumberOfDeposits++; outFile.printf("Amount Deposited: $%.2f %n",AmountDeposited); outFile.printf("Number of Deposits: %d%n",NumberOfDeposits); outFile.println(); break; case '2':// case 2 if we have an Interest BeginningBalance = BeginningBalance + TransactionAmount; InterestPaid = InterestPaid + TransactionAmount; outFile.printf("Interest Paid: $%.2f %n",InterestPaid); outFile.println(); break; case '3':// case 3 if we have a Withdraw BeginningBalance = BeginningBalance - TransactionAmount; AmountWithdrawn = AmountWithdrawn + TransactionAmount; NumberOfWithdrawals++; outFile.printf("Amount Withdrawn: $%.2f %n",AmountWithdrawn); outFile.printf("Number of Withdrawals: %d%n",NumberOfWithdrawals); outFile.println(); break; default: System.out.println("Invalid transaction Tybe: " + TransactionType + TransactionAmount); } } inFile.close(); outFile.close(); } } But is gives me this : Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:840) at java.util.Scanner.next(Scanner.java:1461) at java.util.Scanner.nextInt(Scanner.java:2091) at java.util.Scanner.nextInt(Scanner.java:2050) at sentinel.Ex7.main(Ex7.java:36) Java Result: 1

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  • Is there a way to refactor this javascript/jquery?

    - by whyzee
    switch (options.effect) { case 'h-blinds-fadein': $('.child').each(function (i) { $(this).stop().css({opacity:0}).delay(100 * i).animate({ 'opacity': 1 }, { duration: options.speed, complete: (i !== r * c - 1) || function () { $(this).parent().replaceWith(prev); options.cp.bind('click',{effect: options.effect},options.ch); } }); }); break; case 'h-blinds-fadein-reverse': $('.child').each(function (i) { $(this).stop().css({opacity:0}).delay(100 * (r * c - i)).animate({ 'opacity': 1 }, { duration: options.speed, complete: (i !== 0) || function () { $(this).parent().replaceWith(prev); options.cp.bind('click',{effect: options.effect},options.ch); } }); }); break; ....more cases } I have alot of similiar other cases. One way i could think of is to write functions ? i'm not sure i'm still fairly new to the language

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  • Errors in Layout Cant figure it out!!

    - by Wahid
    Please Help. I'm trying to create a menu that pops up if an android user clicks "menu" on his phone. and i want on the screen a button so when the user clicks it a sound starts playing for a second or two. && this error keeps popping up in my java class in the part where it says " public boolean onCreateTutorial(Menu menu) {" heres my code. package com.Tutorial; import com.Tutorial.R; import android.app.Activity; import android.os.Bundle; import android.view.Menu; import android.view.MenuInflater; import android.view.MenuItem; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.Toast; public class Tutorial extends Activity { private SoundManager mSoundManager; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); mSoundManager = new SoundManager(); mSoundManager.initSounds(getBaseContext()); mSoundManager.addSound(1, R.raw.sound); Button SoundButton = (Button)findViewById(R.id.Button); SoundButton.setOnClickListener(new OnClickListener() { public void onClick(View v) { mSoundManager.playSound(1); @Override public boolean onCreateTutorial(Menu menu) { MenuInflater inflater = getMenuInflater(); inflater.inflate(R.menu.menu, menu); return true; } } @Override public boolean onOptionsItemSelected(MenuItem item) { switch (item.getItemId()) { case R.id.icon: Toast.makeText(this, "Rate this app on Android Market!", Toast.LENGTH_LONG).show(); break; case R.id.text: Toast.makeText(this, "Name: Wahid", Toast.LENGTH_LONG).show(); break; case R.id.icontext: Toast.makeText(this, "MeSoundFx Pro on the Android Market! (Coming Soon)", Toast.LENGTH_LONG).show(); break; } return true; } }); } }

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  • BufferedReader ready method in a while loop to determine EOF?

    - by BobTurbo
    I have a large file (wikipedia english arcticles only database as xml file) I am using to read one character at a time using BufferedReader. The psuedo code is: file = BufferedReader... while (file.ready()) character = file.read() is this actually valid? Or will ready just return false when it is waiting for the HDD to return data and not actually when the EOF has been reached? I tried to use if (file.read() == -1) but seemed to run into an infinite loop that I literally could not find. I am just wondering if it is reading the whole file as my statistics say 444 380 wikipedia pages have been read but I thought there were many more articles..

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  • jQuery autosuggest example

    - by RUtt
    I need to implement an "autosuggest" feature on our site but it needs to re-query the on every keystroke after a certain number of keys (like every character after 2 it would need to query again). So the result isn't a limiting search. For example, the autocomplete plugins I've seen work like the following: [looking for a county] 1. customer types 'CA' and the first result would return 'Canada', 'Cambodia', and 'Camaroon' 2. customer continues to type and hits 'M' the new results would query within the only the existing 3 results (producing results of just 'Cambodia' and 'Camaroon') I need a solution that would be the equivalent of querying my datasource on each keystroke. I already have the ajax call that will return my results based on the "typed" params. For example (in the above example), it would need to make an ajax call passing 'ca' first and if the customer kept typing passing 'can' on the 3 character and so forth. Thanks.

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  • html - problem with word wrapping

    - by pakita883
    Hello! I have some text in div, and I want it to wrap to fit document width (without any scrolls!). I don't want to have word-break, like div {word-wrap: break-word;} For example (this is what I want to get): hello world! today is a good day. But not: hello world! today is a good day. or: hello world! today is a go od day.

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  • Explicit or implicit execution control statement use

    - by Andrei Rinea
    I sometimes use if (this._currentToolForeColor.HasValue) return this._currentToolForeColor.Value; else throw new InvalidOperationException(); other times I use if (this._currentToolForeColor.HasValue) return this._currentToolForeColor.Value; throw new InvalidOperationException(); The two are equivalent, I know, but I am not sure which is the best and why. This goes even further as you can use other execution-control statements such as brake or continue : while(something) { if(condition) { DoThis(); continue; } else break; } versus while(something) { if(condition) { DoThis(); continue; } break; } EDIT 1 : Yes the loop example(s) suck because they are synthetic (i.e.: made up for this question) unlike the first which is practical.

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  • RODBC string getting truncated

    - by sayan dasgupta
    Hi all, I am fetching data from MySql Server into R using RODBC. So in one column of the database is a character vector SELECT MAX(CHAR_LENGTH(column)) FROM reqtable; RETURNS 26566 Now I will show you an example how I am running into the problem `library(RODBC) con <- odbcConnect("mysqlcon") rslts <- as.numeric(sqlQuery(con, "SELECT CHAR_LENGTH(column) FROM reqtable LIMIT 10", as.is=TRUE)[,1]) ` returns > rslts [1] 62 31 17 103 30 741 28 73 25 357 where as rslts <- nchar(as.character(sqlQuery(con, "SELECT column FROM reqtable LIMIT 10", as.is=TRUE)[,1])) returns > rslts [1] 62 31 17 103 30 255 28 73 25 255 So strings with length 255 is getting truncated at 255. Is there a way I can get the full string. Thanks

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  • Servlets response.sendRedirect(String url) doesn't seems to send the encoding, why?

    - by Daziplqa
    Hi folks, I have some Servlet that explicity sets the character encoding and redirect to some servlet class Servlet1 extends HttpServle{ void doGet(..... ){ // ... request.setCharacterEncoding("UTF-8"); response.setCharacterEncoding("UTF-8"): //...... response.redirect(servlet2); } } class Servlet2 extends HttpServle{ void doGet(..... ){ // ... request.getCharacterEncoding(); // prints null ?? why??? //...... } } So, why the character encoding not being send with the request?

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  • Vibration after regular intervals

    - by umar
    I have a beep system which gives you four beeps. One beep after a second for one second. However If its silent mode i want the vibrator to do the same, vibrate for 1 second 4 times after 1 second. This is the code I am using long[] pattern = new long[2]; pattern[0] = 10; pattern [1] = 30; switch (am.getRingerMode()) { case AudioManager.RINGER_MODE_VIBRATE: vibe.vibrate(pattern, 0); break; case AudioManager.RINGER_MODE_NORMAL: soundsOn(mp); break; Kindly how can i do what i want to do Best Regards

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  • rendering a new line in a string (\n) with drawRect

    - by Mrwolfy
    I am trying to render a string with a new line (line break \n), using drawRect. The code below renders the my string as a single line, with no line break, even though I am using the \n character. See the second to last line. UIFont *font = [UIFont fontWithName:@"HelveticaNeue-CondensedBlack" size:fontSize]; CGPoint point = CGPointMake(0,0); CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSetRGBFillColor(context, 1.0, 1.0, 1.0, 1.0); CGContextSetRGBStrokeColor(context, 0.0, 0.0, 0.0, 1.0); CGContextSetLineWidth(context, 4.0); CGContextSetTextDrawingMode(context, kCGTextFillStroke); CGContextSaveGState(context); [@"test \n test" drawAtPoint:point withFont:font]; CGContextRestoreGState(context);

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  • Excel file reading with 2007 office connection string.

    - by p-vasuu
    Actually in my system having 2007 office then i am reading the 2003 .xls file with using the 2007 connection string string ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + Filename + ";Extended Properties=\"Excel 8.0;HDR=YES;\""; data is not reading. But if the first row first column data length is lessthen 255 then the following first columns data is cutting up to 255 character. If the First row first column is morethan the 255 character then the following first columns data is reading fine. Is there any back word computability is there?

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  • How to use switch statement with Enumerations C#

    - by Maximus Decimus
    I want to use a switch statement in order to avoid many if's. So I did this: public enum Protocol { Http, Ftp } string strProtocolType = GetProtocolTypeFromDB(); switch (strProtocolType) { case Protocol.Http: { break; } case Protocol.Ftp: { break; } } but I have a problem of comparing an Enum and a String. So if I added Protocol.Http.ToString() there is another error because it allows only CONSTANT evaluation. If I change it to this switch (Enum.Parse(typeof(Protocol), strProtocolType)) It's not possible also. So, it's possible to use in my case a switch statement or not?

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  • Tilde not recognised in XML public identifier

    - by phantom-99w
    Hi everyone I found an interesting bug and wanted to know you think. Brief background: I've written a custom DTD and an example XML file (both UTF-8). I have now implemented a SAX parser in Java which I want to test. I got a SAXException complaining "An invalid XML character (Unicode: 0x7e) was found in the public identifier". Now, the URL of my DTD does contain a tilde character (unicode 0x7e). If I move the DTD file to another URL which does not contain a tilde, then my example XML file parses without causing a SAXException. So I have a work-around for this problem, but I am interested to know: why does this happen? Is this a bug? If so, is it with UTF-8, Java (1.6.0_18 x86), Windows (Server 2008 R2 x86_64) or what? Or is this one of those little obscure nuances of the XML 1.0 specification?

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  • I need help understanding what Exercise 5-12 is asking for in the C Programming Language book.

    - by marsol0x
    K&R C Programming Language: pg. 105 Extend entab and detab to accept the shorthand entab -m +n to mean tab stops every n columns, starting at column m. entab replaces a number of spaces with a tab character and detab does the opposite. The question I have concerns the tab stops and entab. I figure that for detab it's pretty easy to determine the number of spaces needed to reach the next tab stop, so no worries there. With entab, replacing spaces with tabs is slightly more difficult since I cannot for sure know how large the tab character goes to its own tab stop (unless there is a way to know for sure). Am I even thinking about this thing properly?

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  • Javascript data parsing in IE vs other browsers... It seems kinda screwed up. What's the deal?

    - by Carter
    Firstly, when I say other browsers I really only mean Firefox because that's all I tested in. Internet Explorer can parse a date followed by a single character as a proper date. Whereas Firefox behaves as I'd expect. For example... var dateString = new Date("1/1/2010f"); alert(dateString); In IE it will alert... Thu Dec 31 21:00:00 UTC-0900 2009 Whereas in FF is will spit out... "Invalid Date" I first noticed this using the jquery validation plug in. http://docs.jquery.com/Plugins/Validation/Methods/date It seems like it just subtracts some amount of hours off the actual date in IE when a character is appended. I've tested in IE6 and IE8. Am I missing something?

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  • Python breaks for a certain amount

    - by Brian Cox
    All, I am not very good at explaining so i will let my comments do it! #this script is to calculate some of the times table up to 24X24 and also miss some out #Range of numbers to be calculated numbers=range(1,25) for i in numbers: for w in numbers: print(str(i)+"X"+str(w)+"="+str(i*w)) #here i want to break randomly (skip some out) e.g. i could be doing the 12X1,12X2 and then 12X5 i have no limit of skips. Update Sorry if this is not clear i want it to break from the inner loop for a random amount of times

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  • Is concatenating with an empty string to do a string conversion really that bad?

    - by polygenelubricants
    Let's say I have two char variables, and later on I want to concatenate them into a string. This is how I would do it: char c1, c2; // ... String s = "" + c1 + c2; I've seen people who say that the "" + "trick" is "ugly", etc, and that you should use String.valueOf or Character.toString instead. I prefer this construct because: I prefer using language feature instead of API call if possible In general, isn't the language usually more stable than the API? If language feature only hides API call, then even stronger reason to prefer it! More abstract! Hiding is good! I like that the c1 and c2 are visually on the same level String.valueOf(c1) + c2 suggests something is special about c1 It's shorter. Is there really a good argument why String.valueOf or Character.toString is preferrable to "" +? Trivia: in java.lang.AssertionError, the following line appears 7 times, each with a different type: this("" + detailMessage);

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  • how to put a value to an array when a checkbox is checked? c#?

    - by Jan Darren Noroña
    I am making a random character generator, i have 2 forms, form1 and form2, on my form2 i have the checkboxes there, so if the user checked checkbox1, on my form1 it will only display 1 character, now if the user check all 5 checkboxes, my form1 will generate 5 characters. i have a button on form1 that will trigger an event on generating random characters. characters: '+','-','*','/','%' how will my code be? I am using WINDOWS FORMS APPLICATION. pics here: form1: http://i49.tinypic.com/30bzos8.png form2: http://i50.tinypic.com/k00ndt.png char[] select = new char[] { '+' , '-' , '*' , '/', '%' }; var rand = new Random(); char num = select[rand.Next(5)];

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  • Using images in QListWidget, is this possible?

    - by Neko
    Hi, again. :) As with the last few times I posted here, I have a question about QT, which I am using to create a chat messenger client. To display the list of online users, I'm using a QListWidget, as created like this: listWidget = new QListWidget(horizontalLayoutWidget); listWidget->setObjectName("userList"); QSizePolicy sizePolicy1(QSizePolicy::Preferred, QSizePolicy::Expanding); sizePolicy1.setHorizontalStretch(0); sizePolicy1.setVerticalStretch(0); sizePolicy1.setHeightForWidth(listWidget->sizePolicy().hasHeightForWidth()); listWidget->setSizePolicy(sizePolicy1); listWidget->setMinimumSize(QSize(30, 0)); listWidget->setMaximumSize(QSize(150, 16777215)); listWidget->setBaseSize(QSize(100, 0)); listWidget->setContextMenuPolicy(Qt::CustomContextMenu); Users are shown by constantly refreshing the list, like this: (Note: There are different channels, with different userlists, so refreshing it is the most efficient thing to do, as far as I know.) void FMessenger::refreshUserlist() { if (currentPanel == 0) return; listWidget = this->findChild<QListWidget *>(QString("userList")); listWidget->clear(); QList<FCharacter*> charList = currentPanel->charList(); QListWidgetItem* charitem = 0; FCharacter* character; foreach(character, charList) { charitem = new QListWidgetItem(character->name()); // charitem->setIcon(QIcon(":/Images/status.png")); listWidget->addItem(charitem); } } This has always worked perfectly. The line that I commented out is the one I have problems with: my current goal is to be able to display a user's online status with an image, which represents whether they are busy, away, available, etc. Using setIcon() does absolutely nothing though, apparently; the items still show up as they used to, without icons. I'm aware that this is probably not the way this function needs to be used, but I have found little documentation about it online, and absolutely no useful examples of implementations. My question is, can anybody help me with fixing this problem? Any help would be appreciated terrifically, like always!

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  • timer_getoverrun() doesn't behave as expected when using sleep()

    - by dlp
    Here is a program that uses a POSIX per-process timer alongside the sleep subroutine. The signal used by the timer has been set to SIGUSR1 rather than SIGALRM, since SIGALRM may be used internally by sleep, but it still doesn't seem to work. I have run the program using the command line timer-overruns -d 1 -n 10000000 (1 cs interval) so, in theory, we should expect 100 overruns between calls to sigwaitinfo. However, timer_getoverrun returns 0. I have also tried a version using a time-consuming for loop to introduce the delay. In this case, overruns are recorded. Does anyone know why this happens? I am running a 3.4 Linux kernel. Program source /* * timer-overruns.c */ #include <unistd.h> #include <stdlib.h> #include <stdio.h> #include <signal.h> #include <time.h> // Signal to be used for timer expirations #define TIMER_SIGNAL SIGUSR1 int main(int argc, char **argv) { int opt; int d = 0; int r = 0; // Repeat indefinitely struct itimerspec its; its.it_interval.tv_sec = 0; its.it_interval.tv_nsec = 0; // Parse arguments while ((opt = getopt(argc, argv, "d:r:s:n:")) != -1) { switch (opt) { case 'd': // Delay before calling sigwaitinfo() d = atoi(optarg); break; case 'r': // Number of times to call sigwaitinfo() r = atoi(optarg); break; case 's': // Timer interval (seconds) its.it_interval.tv_sec = its.it_value.tv_sec = atoi(optarg); break; case 'n': // Timer interval (nanoseconds) its.it_interval.tv_nsec = its.it_value.tv_nsec = atoi(optarg); break; default: /* '?' */ fprintf(stderr, "Usage: %s [-d signal_accept_delay] [-r repetitions] [-s interval_seconds] [-n interval_nanoseconds]\n", argv[0]); exit(EXIT_FAILURE); } } // Check sanity of command line arguments short e = 0; if (d < 0) { fprintf(stderr, "Delay (-d) cannot be negative!\n"); e++; } if (r < 0) { fprintf(stderr, "Number of repetitions (-r) cannot be negative!\n"); e++; } if (its.it_interval.tv_sec < 0) { fprintf(stderr, "Interval seconds value (-s) cannot be negative!\n"); e++; } if (its.it_interval.tv_nsec < 0) { fprintf(stderr, "Interval nanoseconds value (-n) cannot be negative!\n"); e++; } if (its.it_interval.tv_nsec > 999999999) { fprintf(stderr, "Interval nanoseconds value (-n) must be < 1 second.\n"); e++; } if (e > 0) exit(EXIT_FAILURE); // Set default values if not specified if (its.it_interval.tv_sec == 0 && its.it_interval.tv_nsec == 0) { its.it_interval.tv_sec = its.it_value.tv_sec = 1; its.it_value.tv_nsec = 0; } printf("Running with timer delay %d.%09d seconds\n", (int) its.it_interval.tv_sec, (int) its.it_interval.tv_nsec); // Will be waiting for signals synchronously, so block the one in use. sigset_t sigset; sigemptyset(&sigset); sigaddset(&sigset, TIMER_SIGNAL); sigprocmask(SIG_BLOCK, &sigset, NULL ); // Create and arm the timer struct sigevent sev; timer_t timer; sev.sigev_notify = SIGEV_SIGNAL; sev.sigev_signo = TIMER_SIGNAL; sev.sigev_value.sival_ptr = timer; timer_create(CLOCK_REALTIME, &sev, &timer); timer_settime(timer, TIMER_ABSTIME, &its, NULL ); // Signal handling loop int overruns; siginfo_t si; // Make the loop infinite if r = 0 if (r == 0) r = -1; while (r != 0) { // Sleeping should cause overruns if (d > 0) sleep(d); sigwaitinfo(&sigset, &si); // Check that the signal is from the timer if (si.si_code != SI_TIMER) continue; overruns = timer_getoverrun(timer); if (overruns > 0) { printf("Timer overrun occurred for %d expirations.\n", overruns); } // Decrement r if not repeating indefinitely if (r > 0) r--; } return EXIT_SUCCESS; }

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  • reverse a linked list?

    - by sil3nt
    Hi there, Im trying to reverse the order of the following linked list, I've done so, But the reversed list does not seem to print out. Where have I gone wrong? //reverse the linked list #include <iostream> using namespace std; struct node{ int number; node *next; }; node *A; void addNode(node *&listpointer, int num){ node *temp; temp = new node; temp->number = num; temp->next = listpointer; listpointer = temp; } void reverseNode(node *&listpointer){ node *temp,*current; current = listpointer; temp = new node; while (true){ if (current == NULL){ temp = NULL; break; } temp->number = current->number; current = current->next; temp = temp->next; } listpointer = temp; } int main(){ A = NULL; addNode(A,1); addNode(A,2); addNode(A,3); while (true){ if (A == NULL){break;} cout<< A->number << endl; A = A->next; } cout<< "****" << endl; reverseNode(A); while (true){ if (A == NULL){break;} cout<< A->number << endl; A = A->next; } cout<< "****"<< endl; return 0; }

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