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  • Django - Static content display based on URL

    - by Steven Potter
    I'm working on a Django site with a basic three column design. Left column navigation, center column content and right column URL specific content blocks. My question is about the best method of controlling the URL specific content blocks in the right column. I am thinking of something along the lines of the Flatpages app that will make the content available to the template context if the URL matches a pre-determined pattern (perhaps regex?). Does anyone know if such an app already exists? If not, I am looking for some advice about the best way to implement it. Particularly in relation to the matching of patterns to the current URL. Is there any good way to re-use parts of the Django URL dispatcher for this use?

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  • Display HttpResponse (string from Handler) in new WebView

    - by datguywhowanders
    I have the following code in a form's submit button onClickListener: String action, user, pwd, user_field, pwd_field; action = "theURL"; user_field = "id"; pwd_field = "pw"; user = "username"; pwd = "password!!"; List<NameValuePair> myList = new ArrayList<NameValuePair>(); myList.add(new BasicNameValuePair(user_field, user)); myList.add(new BasicNameValuePair(pwd_field, pwd)); HttpParams params = new BasicHttpParams(); HttpClient client = new DefaultHttpClient(params); HttpPost post = new HttpPost(action); HttpResponse end = null; String endResult = null; try { post.setEntity(new UrlEncodedFormEntity(myList)); } catch (UnsupportedEncodingException e) { // TODO Auto-generated catch block e.printStackTrace(); } try { HttpResponse response = client.execute(post); end = response; } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } BasicResponseHandler myHandler = new BasicResponseHandler(); try { endResult = myHandler.handleResponse(end); } catch (HttpResponseException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } How can I take the resulting string (endResult) and start a new activity using an intent that will open webview and load the html?

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  • Display all feeds using simplexml_load() using PHP

    - by Jean
    Hello, I want to loop to get all feeds, but displaying only one $url = "http://localhost/feeds/feeds.rss"; $xml = simplexml_load_file($url); foreach($xml->item as $result){ echo $result->description."<br>"; } RSS Feed is - <channel> <title>/</title> <link>/</link> <atom:link type="application/rss+xml" href="/" rel="self"/> <description>/</description> <language>/</language> <ttl>/</ttl> <item> <title>/</title> <description>/</description> <pubDate>/</pubDate> <guid>/</guid> <link>/</link> </item> <item> <title>/</title> <description>/</description> <pubDate>/</pubDate> <guid>/</guid> <link>/</link> </item> </channel> Thanks Jean

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  • Cant display button on specific rows of UITableView properly for iPhone

    - by varunwg
    Hi, I am trying to have a button for selected rows of my table. Here is the example code I am using: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *ControlRowIdentifier = @"ControlRowIdentifier"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:ControlRowIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:ControlRowIdentifier] autorelease]; } if ([indexPath row] > 5) { UIImage *buttonUpImage = [UIImage imageNamed:@"button_up.png"]; UIImage *buttonDownImage = [UIImage imageNamed:@"button_down.png"]; UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom]; button.frame = CGRectMake(0.0, 0.0, buttonUpImage.size.width, buttonUpImage.size.height); [button setBackgroundImage:buttonUpImage forState:UIControlStateNormal]; [button setBackgroundImage:buttonDownImage forState:UIControlStateHighlighted]; [button setTitle:@"Tap" forState:UIControlStateNormal]; [button addTarget:self action:@selector(buttonTapped:) forControlEvents:UIControlEventTouchUpInside]; cell.accessoryView = button; } NSUInteger row = [indexPath row]; NSString *rowTitle = [list objectAtIndex:row]; cell.textLabel.text = rowTitle; return cell; } This code works absolutely fine when loaded for 1st time. So, as per the logic it shows 'Tap' button for all rows greater than 5. Problem occurs when I scroll up and down. Once I do that it just starts putting that button at any random row. I dont understand why it does that and it'll be really helpful if someone can give some tips on this. Thanks.

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  • java gui image problem : doesn't display in the background

    - by thegamer
    Hello, i have a query about why is my image not being displayed in my background of my program. I mean i did all the steps necessary and still it would'nt be displayed. The code runs perfectly but without having the image displayed. The directory is written in the good location of the image. I am using java with gui. If anyone could help me solve my problem, i would appreciate :) here is the code below: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class hehe extends JPanel{ public hehe(){ setOpaque(false); setLayout(new FlowLayout()); } public static void main (String args[]){ JFrame win = new JFrame("yooooo"); // it is automaticcally hidden JPanel mainPanel = new JPanel(new BorderLayout()); win.add(mainPanel); JLabel titleLabel = new JLabel("title boss"); titleLabel.setFont(new Font("Arial",Font.BOLD,18)); titleLabel.setForeground(Color.blue); mainPanel.add(titleLabel,BorderLayout.NORTH); win.setSize(382,269); // the dimensions of the image win.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); win.setVisible(true); } public void paint(Graphics g) { Image a = Toolkit.getDefaultToolkit().getImage("C:\\Users\\andrea\\Desktop\\Gui\\car"); // car is the name of the image file and is in JPEG g.drawImage(a,0,0,getSize().width,getSize().height,this); super.paint(g); } }

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  • Activity monitor doesnt display process name

    - by Mohsin Khawas
    Hi, I have an application, when I see that application in "Activity Monitor" the applications Process Name is displayed nothing. Only the application icon is displayed. I tried debugging this by getting processInfo of the app, I got the application name correct. Even tried with the "top" command, I got the application name correct. The target name and settings also shows the same, only the activity monitor got wrong. Is it something I missed so that activity monitor is displaying nothing. M

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  • Display values and how many times they occured using a Dictionary

    - by user1730056
    I've been told to By using a dictionary (or your solution to Part 4), write a method at_least(a, n) that takes a list, a, and an integer, n, as arguments and returns a list containing only the elements of a that occur at least n times. For complete marks, the list should contain the elements in order of their first occurrence in a. I was able to figure this without using a dictionary, with def at_least2(a, n): return [x for x in a if a.count(x) is n] I was wondering how I can write this using a dictionary? The input is: a = [-6, 8, 7, 3, 2, -9, 1, -3, 2, -4, 4, -8, 7, 8, 2, -2, -7, 0, 1, -9, -3, -7, -3, -5, 6, -3, 6, -3, -10, -8] def at_least(a, 2): and the output: [8, 7, 2, -9, 1, -3, 2, -8, 7, 8, 2, -7, 1, -9, -3, -7, -3, 6, -3, 6, -3, -8] Edit: I don't understand how a dictionary is being used, yet the output isn't in dictionary form? My understanding is that dictionaries have values for each object. I'm not sure if I'm using the right terms.

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  • Display the same prev/next usercontrol twice on a page

    - by Scott
    I haven't seen a question like this. I have a prev/next paging control on my page, one at the top and one at the bottom like this: top pager product catalog bottom pager Each pager is bound to a PagedDataSource that is exactly the same. I don't want to duplicate effort, so I am trying to figure out a way to do the processing once, but show the control twice.

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  • How to automatically display relationships in logical diagram?

    - by Cliff Chaney
    Consider a Logical Model where Entity A and Entity B are connected via Relationship Z. If I create a Logical Diagram (note: not another logical MODEL), I am able to drag Entity A and Entity B onto the diagram. Since the Logical Model already "knows" that Entity A and Entity B have a relationship, I would like to be able to easily add it to my logical diagram. I am already aware of the "Show Symbols" option whereby I can select the specific relationship that I want and have it appear. That is not a solution for me. The problem is that I have a LARGE logical model consisting of HUNDREDS of Entities and their various relationships. I then need to create application-specific diagrams consisting of a subset of those entities. I can easily identify and drag the 50+ entities onto a new diagram. But identifying and selecting all the associations is an exercise in frustration. Is there an option or some sort of feature that I'm missing - or any other trick - that would allow me to add only the relationships between selected entities or all entities on a diagram?

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  • Make python display help screen if no action is given

    - by luckytaxi
    Let's say a user runs the script w/o giving any paramters. How can I make it so that it defaults to ./myscript.py -h so that it shows them the help info? parser = optparse.OptionParser() parser.add_option("-d", "--directory", metavar="DIR", help="Directory to scan for big files") parser.add_option("-e", "--email", metavar='EMAIL', help='email to send the list to') parser.add_option("-l", "--limit", metavar='LIMIT', help='return number of files')

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  • i want to display an item in between a for each loop

    - by atif
    i had this code <ul class="links"<?php if($this->getName()): ?> id="<?php echo $this->getName() ?>"<?php endif;?>> <?php foreach($_links as $_link): ?> <?php if ($_link instanceof Mage_Core_Block_Abstract):?> <?php echo $_link->toHtml() ?> <?php else: ?> <li<?php if($_link->getIsFirst()||$_link->getIsLast()): ?> class="<?php if($_link->getIsFirst()): ?>first<?php endif; ?><?php if($_link->getIsLast()): ?> last<?php endif; ?>"<?php endif; ?> <?php echo $_link->getLiParams() ?>><?php echo $_link->getBeforeText() ?><a href="<?php echo $_link->getUrl() ?>" title="<?php echo $_link->getTitle() ?>" <?php echo $_link->getAParams() ?>><?php echo $_link->getLabel() ?></a><?php echo $_link->getAfterText() ?></li> <?php endif;?> <?php endforeach; ?> </ul> now i know that i had four links but i want to insert "wishlist" after 1st so how could i do that?

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  • Updating display of elements on the web page without refreshing the whole page

    - by ivorossi3
    Last time I coded a web application was almost 10 years ago. I used Java/JSP/HTML/CSS etc. I've been coding non-web applications only ever since. When I look at modern sites now (like this one), I realize how my web development skills are obsolete. Maybe the most obvious "feature" that I wouldn't know how to implement now is the update of elements on the page after user input without having to refresh the whole page (e.g. the voting/downvoting here updates the vote count without reloading the whole page). What are the basic technologies behind this?

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  • how to display the grid in div tag..

    - by kumar
    <script type="text/javascript"> var showGrid = function() { $("#Grid1").load('/friends/names/fried'); }; </script> <div> <%= Html.Trirand().JQGrid(Model.OrdersGrid, "JqGrid1")%> </div> <div> </div> /////// i need to dispaly the Grid1 here? can anyone tell me? thanks

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  • Load page for validation but do not display it to user in ASP.NET

    - by Kevin
    We have a site requiring users pay $2 to view the details of a record. We occasionally get complaints because we send them to the payment page, and once they pay it turns out the record isn't valid, or it was lost, or the data couldn't be generated. So we want to add in a check to ensure the page constructs properly before the user is required to pay for it. However, we don't want the user to have access to the page until they pay for it. Is there anything in ASP.NET 3.5 or just general web design that would allow something like this? The data on the record is real time and computed on a backend server before sent to the client. Occasionally this computation fails for whatever reason. Our alternative is to call all of the loading methods and validate the data, then redirect them to the payment page. The problem is A) this will be a relatively involved process rewriting all of these methods to return validation information, and B) it still doesn't guarentee us the page will load properly. Any thoughts?

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  • Image display permissions in PHP/Apache

    - by Randy
    I have a PHP site with a login system, and am trying to make a feature where only specific usernames can view particular images. I think what I'm trying to do is more involved than merely changing the .htaccess file, because a) this won't help discern between users that are/aren't allowed to view the image, and b) if someone enters the exact URL of the image ("directory/images/photos/230ru0q0238rn230nd_asdi0nqn8.jpg") they can still view the image (since it's a physical file in the directory, and not text in a DB, etc.). Again, restricting via .htaccess would restrict the directory as a whole, or all files in it, so I can't figure out how it would work. Ideally, all images would be blocked by trying to access them directly through their direct URL, and the image would only appear between <img> tags if the user's session/username is valid, else they get an error message. I've heard the term ACL but I'm not sure this is related to what I'm trying to do.

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  • LinkedList Wrong Display(string builder)

    - by Chris
    Hello, The following program is a basic linked list divided in 3 classes. In the tester class (main) i add several numbers to the list (sorted). But insteed of getting the numbers as a result i get the result: LinkedList.LinkedList Is something wrong with the stringbuilder (the program was first in java where a string buffer was used, but that should be the same i think?) LinkedListTester.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace LinkedList { public class LinkedListTester { static void Main(string[] args) { LinkedList ll = new LinkedList(); ll.addDataSorted(5); ll.addDataSorted(7); ll.addDataSorted(13); ll.addDataSorted(1); ll.addDataSorted(17); ll.addDataSorted(8); Console.WriteLine(ll); } } }/LinkedList/ LinkedList.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace LinkedList { public class LinkedList { //toestand private LinkedListNode first; private LinkedListNode last; //gedrag public LinkedList() { first = null; last = null; } public void addDataInFront(int data) { first = new LinkedListNode(data, first); if (last == null){ last = first; } }/*addDataInFront*/ public void addDataToBack(int data) { if (first == null) { addDataInFront(data); } else { last.setNext(new LinkedListNode(data, null)); last = last.getNext(); } }/*addDataToBack*/ public void addDataSorted(int data) { if (first == null || first.getData() > data) { addDataInFront(data); } else { LinkedListNode currentNode = first; while (currentNode.getNext() != null && currentNode.getNext().getData() < data) { currentNode = currentNode.getNext(); } currentNode.setNext(new LinkedListNode(data, currentNode.getNext())); currentNode = currentNode.getNext(); if (currentNode.getNext() == null) { last = currentNode; } } }/*addDataSorted*/ public String toString() { StringBuilder Buf = new StringBuilder(); LinkedListNode currentNode = first; while (currentNode != null) { Buf.Append(currentNode.getData()); Buf.Append(' '); currentNode = currentNode.getNext(); } return Buf.ToString(); }/*toString*/ }/*LinkedList*/ }/LinkedList/ LinkedListNode: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace LinkedList { public class LinkedListNode { //toestand private int data; private LinkedListNode next; private LinkedListNode previous; //gedrag public LinkedListNode(int data, LinkedListNode next) { this.data = data; this.next = next; this.previous = null; } public LinkedListNode(int data, LinkedListNode next, LinkedListNode previous) { this.data = data; this.next = next; this.previous = previous; } public LinkedListNode getNext() { return next; } public LinkedListNode getPrevious() { return previous; } public void setNext(LinkedListNode next) { this.next = next; } public void setPrevious(LinkedListNode previous) { this.previous = previous; } public int getData() { return data; } }/*LinkedListNode*/ }/LinkedList/

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  • Unable to display google maps in a dojo layout

    - by Jens
    Dear All, I am a real newbie in programming and now I have to combine Google Maps and Dojo. Both alone are fine but when I try to implement a Google Map into a Dojo content pane which is embedded in a border-container it simply does not work. I think there is a problem with the naming of the divs but perhaps there is something else to take care of? Could someone post the simplest possible solution? many thanks

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  • Gridview display multiple tables?

    - by Shawn
    I have a gridview setup that gets its data from a SQL database stored procedure. This procedure will return one of several different tables. The gridview complains if the table is different than the one previously displayed. How do I work around this?

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  • How to display CodeRush menu item in VS ?

    - by drasto
    I just installed CodeRush to my VS and when I run VS for the first time after installation it showed me a dialog asking if I'm experienced user. While the dialog was visible I could see that there was new menu item in VS named DevExpress. There was a small check box on that dialog saying something about menu items that I probably should have checked. As I did not the menu items disappeared just after I clicked OK. I cannot make that menu item reappear. Can somebody help me with this ?

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  • jQuery - Display the value of a textbox and input the value to another

    - by user1128694
    Basically I want to get the value of a textbox which is to select a date and output the value that is selected to another textbox. These textboxes are on the same page (different steps of the same page) and the document is loaded when the page is ready on click of the next step, I've tried using: $('#TextBox1').val($('#TextBox2').val()); But this doesn't seem to be working. What is it I am doing wrong?

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