Implicitly invoking parent class initializer
- by Matt Joiner
class A(object):
def __init__(self, a, b, c):
#super(A, self).__init__()
super(self.__class__, self).__init__()
class B(A):
def __init__(self, b, c):
print super(B, self)
print super(self.__class__, self)
#super(B, self).__init__(1, b, c)
super(self.__class__, self).__init__(1, b, c)
class C(B):
def __init__(self, c):
#super(C, self).__init__(2, c)
super(self.__class__, self).__init__(2, c)
C(3)
In the above code, the commented out __init__ calls appear to the be the commonly accepted "smart" way to do super class initialization. However in the event that the class hierarchy is likely to change, I have been using the uncommented form, until recently.
It appears that in the call to the super constructor for B in the above hierarchy, that B.__init__ is called again, self.__class__ is actually C, not B as I had always assumed.
Is there some way in Python-2.x that I can overcome this, and maintain proper MRO when calling super constructors without actually naming the current class?
