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  • Create Directory, 'cd' to it and download a file pipeline in Perl

    - by neversaint
    I have a file that looks like this: ftp://url1/files1.tar.gz dir1 ftp://url2/files2.txt dir2 .... many more... What I want to do are these steps: Create directory based on column 2 Unix 'cd' to that directory Download file with 'wget' based on column1 But how come this approach of mine doesn't work while(<>) { chomp; my ($url,$dir) = split(/\t/,$_); system("mkdir $dir"); system("cd $dir"); # Fail here system("wget $url"); # here too } What's the right way to do it?

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  • Java import from other directory

    - by heldopslippers
    Hi People! I am building a Enterprise Service Bus (ESB) with Java. I won't get into details But I have to build multiple servers who make use of the same classes. I have the following directory structure: /server1 -Main.java /server2 -Main.java /com -Database.java I want to import from the Main.java class for example the Database.class. But of course the following statements won't work: import com.Database; I am working with the javac compiler in the command line (so not eclipse stuff or whatever. just TextMate and the command line). And I found a (pretty stupid) solution by creating a symbolic link in the servers to the com directory. But that is not really an ideal solution. Does anybody have a better one?? THANXS in advanced!! :D

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  • Error becuase Virtual directory not being configured as an application in IIS

    - by Cipher
    Hi, I was trying to install a CMS in a folder in my website. After the installation on trying to run, it shows this error: Error 14 It is an error to use a section registered as allowDefinition='MachineToApplication' beyond application level. This error can be caused by a virtual directory not being configured as an application in IIS. E:\Users\Sarin\Documents\Visual Studio 2010\WebSites\WebAssist\blog\web.config 61 I added the webiste as a Virtual Directory and also converted that to application. On trying to browse this application, the following error occurs as shown in the screenshot: http://i.imgur.com/jcRJe.jpg How to make this work?

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  • Write file in sub-directory in Android

    - by Davide Vosti
    I'm trying to save a file in a subdirectory in Android 1.5. I can successfully create a directory using _context.GetFileStreamPath("foo").mkdir(); (_context is the Activity where I start the execution of saving the file) but then if I try to create a file in foo/ by _context.GetFileStreamPath("foo/bar.txt"); I get a exception saying I can't have directory separator in a file name ("/"). I'm missing something of working with files in Android... I thought I could use the standard Java classes but they don't seem to work... I searched the Android documentation but I couldn't fine example and google is not helping me too... I'm asking the wrong question (to google)... Can you help me out with this? Thank you!

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  • git - is there a way to get only required files in the working directory

    - by spoonboy
    I'm new to git and trying to use it with a project that has many (several hundreds) sources. The problem I have is that git is extracting all the project's sources to my working directory when doing checkout. This makes a lot of mess as I have to jump between the files and can unintentionally change/corrupt files that I wasn't even planning to change. I would prefer to extract only sources that I'm going to modify and then work with them. So, is there a way to tell git that I only going to work with specific sources, and so, that only these sources would be extracted to the working directory? Note, that this is not a partial checkout or something like this. I'm ok to checkout the whole branch. It's more about organising a working folder. Thanks.

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  • Python read files in directory and concatenate

    - by JJ Beck
    I want to write a Python script that searches all folders in the current directory, looks for all .txt files, and creates a file that is a concatenation of all those files (in any order) in the current directory. If folders have subfolders, it should not search those subfolders. An example is main_folder folder_1 sub_folder file1.txt file2.txt folder_2 file3.txt The script is placed inside main_folder. It should create a file that is a concatenation of file2.txt and file3.txt (in any order) inside main_folder. My question is: How can I tell Python to traverse through the folders, look for .txt files, without going into the subfolders?

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  • C# directory to "play with"

    - by Adam S
    Simple question here. I have a C# program which needs to stores some files onto the hard drive, but I don't need them to be anywhere useful to the end-user, only somewhere that the program can read/write from. Is there a directory that I can reference programmatically to be my "filespace playground" - that is, that I can read/write freely to and from? EDIT: Also, if I use a temp directory, how long are the files guaranteed to be there? I don't want the them to disappear while my program is still running!

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  • Rsync module path needs to be a home directory

    - by Malfist
    I'm trying to use rsync to backup windows servers to an rsync server. I'm having problems with rsync on the linux side though, it doesn't like symlinks. Currently I'm trying to use the module path of ~/backup, but rsync says that the chroot failed. I looked up what to do and saw that I needed to add the option use chroot = no and munge symlinks = no. That fixed the @ERROR: chroot failed but now it's telling me @ERROR: chdir failed and the log files say that there is no ~/backup directory. I know the user I'm authenticating with has a backup folder in his directory. How can I fix this? For reference I'm using a .NET port of rsync called NetSync and tunneling it over a port forwarded SSH connection generated with granados.

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  • Why can't I view a directory in Linux?

    - by Thread7
    I am setting up a Linux web server running apache. I uploaded and untared my web sites files. The files in the main directory are all visible when I am SSH'd into the system. However, I am blocked from all subdirectories. If I write: # cd images Then I get the error: -bash: cd: images: Permission denied I am signed in as ec2-user. I untarred the stuff as ec2-user and I doubt there was any permissions in the tar file since I created the archive on a Windows system. The weird thing is that I am the owner of this directory. Here is a snippet of the command: ls -l drw-rw-r-- 19 ec2-user ec2-user 4096 May 4 04:09 images When I do "sudo su" and then type the command cd images everything is fine. Why do I get "Permission denied" as ec2-user if I am the owner and have rw permission?

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  • No such file or directory python in linux only (coming from windows)

    - by user1804633
    I have the same exact directory structure within a folder in Windows & in Linux (Debian) - where the script is along the static + dataoutput folders How come the following code works fine in Windows, but gives a no such file or directory path error in linux? @app.route('/_getdataoutputfilelisting') def getdataoutputfilelisting(): listoffilesindataouput = getfiles('static/dataoutput') return jsonify(listoffiles = listoffilesindataouput) def getfiles(dirpath): a = [s for s in os.listdir(dirpath) if os.path.isfile(os.path.join(dirpath, s))] a.sort(key=lambda s: os.path.getmtime(os.path.join(dirpath, s))) a.reverse() return a Is there a way to make it universal such that it works in both OSs? Thanks

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  • Coupling an MFC CListCtrl and CTreeCtrl to get a view of the whole tree, not just one node at a time

    - by omatai
    Consider Windows Explorer (or regedit or similar). To the left side, there is a tree view, and to the right, a list view. In all cases I know of, the contents of the right view reflect the attributes of the selected node from the left pane. This is all well and good... but just not what I want. The nodes of the tree I want to display have a very few attributes (2-3) associated with each node - a reasonable amount to display horizontally as a row in a table. Rather than waste all that list view space on a single node with very few properties, I would like to have my list view display a table of the whole tree's properties (as the part of the tree currently expanded). So the nth line in the left view (tree) will correspond directly to the nth line in the right view (list/table), and I will get a decent overview of the properties of my tree. Does anyone know of code that does this? I am guessing that slaving a CListCtrl to a CTreeCtrl would be the way to go, and somehow overriding the vertical scrolling functions so that they are locked together. I'm just not sure that it is possible to lock the scrolls together like this... among other things! All advice gratefully welcomed :-)

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  • Sort directory listing using RecursiveDirectoryIterator

    - by Scott Saunders
    I'm using RecursiveDirectoryIterator and RecursiveIteratorIterator to build a file listing tree using code like below. I need to the list to be sorted - either directories then files alphabetically, or just alphabetically. Can anyone tell me how to sort the file list? $dir_iterator = new RecursiveDirectoryIterator($groupDirectory); $iterator = new RecursiveIteratorIterator($dir_iterator, RecursiveIteratorIterator::SELF_FIRST); foreach ($iterator as $file) { // do stuff with $file }

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  • How do we keep dependent data structures up to date?

    - by Geo
    Suppose you have a parse tree, an abstract syntax tree, and a control flow graph, each one logically derived from the one before. In principle it is easy to construct each graph given the parse tree, but how can we manage the complexity of updating the graphs when the parse tree is modified? We know exactly how the tree has been modified, but how can the change be propagated to the other trees in a way that doesn't become difficult to manage? Naturally the dependent graph can be updated by simply reconstructing it from scratch every time the first graph changes, but then there would be no way of knowing the details of the changes in the dependent graph. I currently have four ways to attempt to solve this problem, but each one has difficulties. Nodes of the dependent tree each observe the relevant nodes of the original tree, updating themselves and the observer lists of original tree nodes as necessary. The conceptual complexity of this can become daunting. Each node of the original tree has a list of the dependent tree nodes that specifically depend upon it, and when the node changes it sets a flag on the dependent nodes to mark them as dirty, including the parents of the dependent nodes all the way down to the root. After each change we run an algorithm that is much like the algorithm for constructing the dependent graph from scratch, but it skips over any clean node and reconstructs each dirty node, keeping track of whether the reconstructed node is actually different from the dirty node. This can also get tricky. We can represent the logical connection between the original graph and the dependent graph as a data structure, like a list of constraints, perhaps designed using a declarative language. When the original graph changes we need only scan the list to discover which constraints are violated and how the dependent tree needs to change to correct the violation, all encoded as data. We can reconstruct the dependent graph from scratch as though there were no existing dependent graph, and then compare the existing graph and the new graph to discover how it has changed. I'm sure this is the easiest way because I know there are algorithms available for detecting differences, but they are all quite computationally expensive and in principle it seems unnecessary so I'm deliberately avoiding this option. What is the right way to deal with these sorts of problems? Surely there must be a design pattern that makes this whole thing almost easy. It would be nice to have a good solution for every problem of this general description. Does this class of problem have a name?

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  • Unable to execute file in the temporary directory

    - by Bixal
    I am using Windows 8.1 Pro 64-bit. I see this error, almost everytime I launch an executable file (to install it) but not for all of them. I don't see the error when I use Run as Administrator. I looked around, and found a solution: I needed to give permissions to the current user for the temp file as shown in the picture below: The problem here is solved temporarily, but it goes back to give me the same problem after restarting the PC. What can I do to prevent such a thing? I don't really want to use the built in Administrator account all the time. Update: The problem is caused by the cracked version of Adobe Acrobat. And the root cause is the cracked amtlib.dll Read more here: http://www.sabernova.com/2013/12/cracked-adobe-acrobat-xi-will-revert.html#axzz2r8VSzZi9

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  • Active Directory Group Policy: Script Errors

    - by ToreTrygg
    Hello all. Anyone having issues with AD group policy script errors when enabling VMware Fusion's "Sharing" feature? I've run into this problem in version 2.0 and 3.0. I have a logon script applied on an AD OU. It works fine on all Windows client workstations and in VMware Fusion only when the "Sharing" feature is NOT enabled. Any ideas would be much appreciated. Thanks.

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  • Cannot change permissions in symlinked dropbox directory in Ubuntu 10.10

    - by Reactor5
    Title pretty much says it all, but here's what I'm doing... ls -l produces this... drwx------ 1 brian brian 4096 2010-12-28 14:19 foldername -rw------- 1 brian brian 0 2010-12-28 15:54 index.html after typing something like chmod o=rx index.html the output of ls -l is the same. This happens whether or not I'm in the original location or the symlink location. However, as a further twist, the output of chmod -v o=rx index.html is the following: mode of `index.html' changed to 0605 (rw----r-x) The location is also being symlinked to by apache. What's going on with my permissions?

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  • Apache Solr Admin on Tomcat Deployed in WebApps Directory

    - by KM01
    I am trying to get Apache Solr to work on Redhat6 and Tomcat6 (using these instructions), but get this error when browsing to the admin section, http://localhost:8080/solr-example/admin: HTTP Status 404 - missing core name in path type Status report message missing core name in path description The requested resource (missing core name in path) is not available. http://localhost:8080/solr-example loads fine, with a link to "Solr Admin." My setup is as follows: tomcat6: /etc/tomcat6 Solr: /app/solr/example I have a solr-example.xml in /etc/tomcat6/Catalina/localhost/, which reads: <?xml version="1.0" encoding="utf-8"?> <Context docBase="/app/solr/example/apache-solr-3.4.0.war" debug="0" crossContext="true"> <Environment name="solr/home" type="java.lang.String" value="/app/solr/example" override="true"/> </Context> I don't see anything in the logs (/var/log/tomcat6) ... only entires in catalina.out are regarding the starting and stopping of tomcat6. My questions are: 1.What else do I need to do to get "Solr Admin" to work under Tomcat? 2.Where are these "cores" supposed to be specified? I see an entry in /app/solr/example/solr/solr.xml ? <solr persistent="false"> adminPath: RequestHandler path to manage cores. If 'null' (or absent), cores will not be manageable via request handler <cores adminPath="/admin/cores" defaultCoreName="collection1"> <core name="collection1" instanceDir="." /> </cores> </solr> 3.How do I got about ensuring that logs are working correctly? I can't find logs that contain mention of the 404 above. Update in response to @quanta's comment: Downloaded former (apache-solr-3.4.0.tgz) dataDir was not set, now set to: <dataDir>${solr.data.dir:../solr/data}</dataDir> JAVA_OPTS: /usr/lib/jvm/java/bin/java -classpath :/usr/share/tomcat6/bin/bootstrap.jar:/usr/share/tomcat6/bin/tomcat-juli.jar:/usr/share/java/commons-daemon.jar -Dcatalina.base=/usr/share/tomcat6 -Dcatalina.home=/usr/share/tomcat6 -Djava.endorsed.dirs= -Djava.io.tmpdir=/var/cache/tomcat6/temp -Djava.util.logging.config.file=/usr/share/tomcat6/conf/logging.properties -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager org.apache.catalina.startup.Bootstrap start catalina.out contains no indication of the above error

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  • Linux / UNIX / OS X Binary Directory Structure

    - by Kevin Sylvestre
    Will Linux / UNIX / OS X binaries be stored in the same directories across different platform or distributions? I'm asking because I need to have access to uuidgen (stored in /usr/bin/uuidgen on my development computer) and noticed that my local Apache server does not include /usr/bin in the PATH. I know I could add /usr/bin to the path, but I want to make sure the software can be re-deployed on a number of different systems with ease. Thanks!

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