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  • How can I proxy couchDB as a sub-diectory with lighttpd?

    - by indieinvader
    I have a sub-directory on my web server (lighttpd) that I want to point at a CouchDB instance running on the same machine. I tried using mod_proxy but it sends along the whole request, like a proxy should, I know! So: // What happens: Lighttpd: http://localhost/couchdb/some_request | V CouchDB: http://localhost:5984/couchdb/some_request // What I want to happen: Lighttpd: http://localhost/couchdb/some_request | V CouchDB: http://localhost:5984/some_request Is there any way to make this setup work?

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  • How to change the proxy settings for the Network Service account from the command prompt?

    - by mark
    Currently, I am only aware of the following command: C:\>bitsadmin /util /SetIEProxy NetworkService MANUAL_PROXY 1 92.168.0.200:8080 NULL But, it has the following defects: It is deprecated It does not allow to set the credentials. My question is how can I configure the proxy settings, including the credentials using a more up-to-date tool? EDIT I would like to stress that I am looking for a command line utility to do that.

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  • Is there any way to set up a malware-blocking transparent proxy on an Airport Extreme?

    - by Chris R
    I'd like to add some kind of easily-administered transparent HTTP proxy to my home network. Ideally, it would allow me to, for example, redirect web requests to blacklisted servers into nothing, block certain kinds of content, et al. My home network at the moment consists of a mac mini media server that could -- if the load wasn't huge -- fill this role as well, an Airport Extreme, and a mac laptop that is my main machine. I'm reasonably technically savvy, so don't spare the complicated answers.

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  • suggestions for fast reliable proxy IPs like codeen but with posting?

    - by barlop
    Hi, I am looking for a list like one offered by codeen http://codeen.cs.princeton.edu/ of fast reliable proxy servers.. I just want to be able to "post" on usenet or yahoo groups with them.. I think the codeen ones don't allow HTTP-POST I don't need them for downloading or for torrents, or even for any images.. they can block images to keep browsing faster. I know it's not a list, but I did try TOR once, but it was horribly slow.

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  • Script throwing unexpected operator when using mysqldump

    - by Astron
    A portion of a script I use to backup MySQL databases has stopped working correctly after upgrading a Debian box to 6.0 Squeeze. I have tested the backup code via CLI and it works fine. I believe it is in the selection of the databases before the backup occurs, possibly something to do with the $skipdb variable. If there is a better way to perform the function then I'm will to try something new. Any insight would be greatly appreciated. $ sudo ./script.sh [: 138: information_schema: unexpected operator [: 138: -1: unexpected operator [: 138: mysql: unexpected operator [: 138: -1: unexpected operator Using bash -x script here is one of the iterations: + for db in '$DBS' + skipdb=-1 + '[' test '!=' '' ']' + for i in '$IGGY' + '[' mysql == test ']' + : + '[' -1 == -1 ']' ++ /bin/date +%F + FILE=/backups/hostname.2011-03-20.mysql.mysql.tar.gz + '[' no = yes ']' + /usr/bin/mysqldump --single-transaction -u root -h localhost '-ppassword' mysql + /bin/tar -czvf /backups/hostname.2011-03-20.mysql.mysql.tar.gz mysql.sql mysql.sql + rm -f mysql.sql Here is the code. if [ $MYSQL_UP = "yes" ]; then echo "MySQL DUMP" >> /tmp/update.log echo "--------------------------------" >> /tmp/update.log DBS="$($MYSQL -u $MyUSER -h $MyHOST -p"$MyPASS" -Bse 'show databases')" for db in $DBS do skipdb=-1 if [ "$IGGY" != "" ] ; then for i in $IGGY do [ "$db" == "$i" ] && skipdb=1 || : done fi if [ "$skipdb" == "-1" ] ; then FILE="$DEST$HOST.`$DATE +"%F"`.$db.mysql.tar.gz" if [ $ENCRYPT = "yes" ]; then $MYSQLDUMP -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf - $db.sql | $OPENSSL enc -aes-256-cbc -salt -out $FILE.enc -k $ENC_PASS && rm -f $db.sql else $MYSQLDUMP --single-transaction -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf $FILE $db.sql && rm -f $db.sql fi fi done fi

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  • mod_usertrack with X-Forwarded-For (proxy) IPs, apache 2.2

    - by ripper234
    I'm using apache 2.2 with mod_usertrack, behind a reverse proxy (load balancer). Now, the proxy disguises the client's real IP addresses (keeps them in the X-Forwarded-For header), and forwards the request along. mod_usertrack uses the clients' IP (along with some noise) to generate a GUID for each client. However, because of the proxy, it only sees a single IP and the generated GUIDs for each client are very similar (even with some possible collisions). I would like to upgrade apache to version 2.4, but it seems to be somewhat of a project. I did manage to compile it using this post and a few others, only to discover the folder structure does not resemble the one I had before (default ubuntu). I'm weary of tweaking it myself ... and I will be making my life miserable if I want to upgrade the server later on. So ... what are my options? Is there a good unofficial repository that packages apache 2.4 for Oneiric? (please provide a short 'how to', I'm not great in installing packages) Is there an alternative route to solve this? (Upgrading just the user_track module? Another module that works with apache 2.2?)

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  • Need help to debug application using .Net and MySQL

    - by Tim Murphy
    What advice can you give me on how to track down a bug I have while inserting data into MySQL database with .Net? The error message is: MySql.Data.MySqlClient.MySqlException: Duplicate entry '26012' for key 'StockNumber_Number_UNIQUE' Reviewing of the log proves that StockNumber_Number of 26012 has not been inserted yet. Products in use. Visual Studio 2008. mysql.data.dll 6.0.4.0. Windows 7 Ultimate 64 bit and Windows 2003 32 bit. Custom built ORM framework (have source code). Importing data from Access 2003 database. The code works fine for 3000 - 5000 imports. The record being imported that causes the problem in a full run works fine if just importing by itself. I've also seen the error on other records if I sort the data to be imported a different way. Have tried import with and without transactions. Have logged the hell out of the system. The SQL command to create the table: CREATE TABLE `RareItems_RareItems` ( `RareItemKey` CHAR(36) NOT NULL PRIMARY KEY, `StockNumber_Text` VARCHAR(7) NOT NULL, `StockNumber_Number` INT NOT NULL AUTO_INCREMENT, UNIQUE INDEX `StockNumber_Number_UNIQUE` (`StockNumber_Number` ASC), `OurPercentage` NUMERIC , `SellPrice` NUMERIC(19, 2) , `Author` VARCHAR(250) , `CatchWord` VARCHAR(250) , `Title` TEXT , `Publisher` VARCHAR(250) , `InternalNote` VARCHAR(250) , `DateOfPublishing` VARCHAR(250) , `ExternalNote` LONGTEXT , `Description` LONGTEXT , `Scrap` LONGTEXT , `SuppressionKey` CHAR(36) NOT NULL, `TypeKey` CHAR(36) NOT NULL, `CatalogueStatusKey` CHAR(36) NOT NULL, `CatalogueRevisedDate` DATETIME , `CatalogueRevisedByKey` CHAR(36) NOT NULL, `CatalogueToBeRevisedByKey` CHAR(36) NOT NULL, `DontInsure` BIT NOT NULL, `ExtraCosts` NUMERIC(19, 2) , `IsWebReady` BIT NOT NULL, `LocationKey` CHAR(36) NOT NULL, `LanguageKey` CHAR(36) NOT NULL, `CatalogueDescription` VARCHAR(250) , `PlacePublished` VARCHAR(250) , `ToDo` LONGTEXT , `Headline` VARCHAR(250) , `DepartmentKey` CHAR(36) NOT NULL, `Temp1` INT , `Temp2` INT , `Temp3` VARCHAR(250) , `Temp4` VARCHAR(250) , `InternetStatusKey` CHAR(36) NOT NULL, `InternetStatusInfo` LONGTEXT , `PurchaseKey` CHAR(36) NOT NULL, `ConsignmentKey` CHAR(36) , `IsSold` BIT NOT NULL, `RowCreated` DATETIME NOT NULL, `RowModified` DATETIME NOT NULL ); The SQL command and parameters to insert the record: INSERT INTO `RareItems_RareItems` (`RareItemKey`, `StockNumber_Text`, `StockNumber_Number`, `OurPercentage`, `SellPrice`, `Author`, `CatchWord`, `Title`, `Publisher`, `InternalNote`, `DateOfPublishing`, `ExternalNote`, `Description`, `Scrap`, `SuppressionKey`, `TypeKey`, `CatalogueStatusKey`, `CatalogueRevisedDate`, `CatalogueRevisedByKey`, `CatalogueToBeRevisedByKey`, `DontInsure`, `ExtraCosts`, `IsWebReady`, `LocationKey`, `LanguageKey`, `CatalogueDescription`, `PlacePublished`, `ToDo`, `Headline`, `DepartmentKey`, `Temp1`, `Temp2`, `Temp3`, `Temp4`, `InternetStatusKey`, `InternetStatusInfo`, `PurchaseKey`, `ConsignmentKey`, `IsSold`, `RowCreated`, `RowModified`) VALUES (@RareItemKey, @StockNumber_Text, @StockNumber_Number, @OurPercentage, @SellPrice, @Author, @CatchWord, @Title, @Publisher, @InternalNote, @DateOfPublishing, @ExternalNote, @Description, @Scrap, @SuppressionKey, @TypeKey, @CatalogueStatusKey, @CatalogueRevisedDate, @CatalogueRevisedByKey, @CatalogueToBeRevisedByKey, @DontInsure, @ExtraCosts, @IsWebReady, @LocationKey, @LanguageKey, @CatalogueDescription, @PlacePublished, @ToDo, @Headline, @DepartmentKey, @Temp1, @Temp2, @Temp3, @Temp4, @InternetStatusKey, @InternetStatusInfo, @PurchaseKey, @ConsignmentKey, @IsSold, @RowCreated, @RowModified) @RareItemKey = 0b625bd6-776d-43d6-9405-e97159d172a6 @StockNumber_Text = 199305 @StockNumber_Number = 26012 @OurPercentage = 22.5 @SellPrice = 1250 @Author = SPARRMAN, Anders. @CatchWord = COOK: SECOND VOYAGE @Title = A Voyage Round the World with Captain James Cook in H.M.S. Resolution… Introduction and notes by Owen Rutter, wood engravings by Peter Barker-Mill. @Publisher = @InternalNote = @DateOfPublishing = 1944 @ExternalNote = The first English translation of Sparrman’s narrative, which had originally been published in Sweden in 1802-1818, and the only complete version of his account to appear in English. The eighteenth-century translation had appeared some time before the Swedish publication of the final sections of his account. Sparrman’s observant and well-written narrative of the second voyage contains much that appears nowhere else, emphasising naturally his interests in medicine, health, and natural history.&lt;br&gt;&lt;br&gt;One of 350 numbered copies: a handsomely produced and beautifully illustrated work. @Description = Small folio, wood-engravings in the text; original olive glazed cloth, top edges gilt, a very good copy. London, Golden Cockerel Press, 1944. @Scrap = @SuppressionKey = 00000000-0000-0000-0000-000000000000 @TypeKey = 93f58155-7471-46ad-84c5-262ab9dd37e8 @CatalogueStatusKey = 00000000-0000-0000-0000-000000000003 @CatalogueRevisedDate = @CatalogueRevisedByKey = c4f6fc06-956d-44c4-b393-0d5462cbffec @CatalogueToBeRevisedByKey = 00000000-0000-0000-0000-000000000000 @DontInsure = False @ExtraCosts = @IsWebReady = False @LocationKey = 00000000-0000-0000-0000-000000000000 @LanguageKey = 00000000-0000-0000-0000-000000000000 @CatalogueDescription = @PlacePublished = Golden Cockerel Press @ToDo = @Headline = @DepartmentKey = 529578a3-9189-40de-b656-eef9039d00b8 @Temp1 = @Temp2 = @Temp3 = @Temp4 = v @InternetStatusKey = 00000000-0000-0000-0000-000000000000 @InternetStatusInfo = @PurchaseKey = 00000000-0000-0000-0000-000000000000 @ConsignmentKey = @IsSold = True @RowCreated = 8/04/2010 8:49:16 PM @RowModified = 8/04/2010 8:49:16 PM Suggestions on what is causing the error and/or how to track down what is causing the problem?

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • Has anyone ever successfully make index merge work for MySQL?

    - by user198729
    Setup: mysql> create table t(a integer unsigned,b integer unsigned); mysql> insert into t(a,b) values (1,2),(1,3),(2,4); mysql> create index i_t_a on t(a); mysql> create index i_t_b on t(b); mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 3 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Is there something I'm missing? Update mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 1863 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Version: mysql> select version(); +----------------------+ | version() | +----------------------+ | 5.1.36-community-log | +----------------------+ Has anyone ever successfully make index merge work for MySQL? I'll be glad to see successful stories here:)

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  • PHP & MySQL database storing the name Array problem.

    - by comma
    I'm new to PHP & MySQL and I keep getting the word Array stored in my MySQL tables fields $skill, $experience, $yearsI was wondering how can I fix this problem? And I know I need to add mysqli_real_escape_string which I left out to make code more easier to read Hopefully. Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; if (isset($_POST['skill'][0]) && trim($_POST['skill'][0])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { for ($s = 0; $s < count($skill); $s++){ for ($x = 0; $x < count($experience); $x++){ for ($g = 0; $g < count($years); $g++){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $s . "', '" . $x . "', '" . $g . "')"); $id = mysqli_insert_id($mysqli); if ($query1 == TRUE) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query2 = mysqli_query($mysqli,"INSERT INTO users_skills (skill_id, user_id) VALUES ('$id', '$user_id')"); } } } } } } } Here is the XHTML code. <li><label for="skill">Skill: </label><input type="text" name="skill[0]" id="skill[0]" /> <label for="experience">Experience: </label> <?php echo '<select id="experience[0]" name="experience[0]">' . "\n"; foreach($experience_options as $option) { if ($option == $experience) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> <label for="years">Years: </label> <?php echo '<select id="years[0]" name="years[0]">' . "\n"; foreach($grade_options as $option) { if ($option == $years) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

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  • SQL SELECT: "Give me all documents where all of the documents procedures are 'work in progress'"

    - by prestonmarshall
    This one really has me stumped. I have a documents table which hold info about the documents, and a procedures table, which is kind of like a revisions table for each document. What I need to do is write a select statement which gives me all of the documents where all of the procedures have the status "work_in_progress". Here's an example procedures table: document_id | status 1 | 'wip' 1 | 'wip' 1 | 'wip' 1 | 'approved' 2 | 'wip' 2 | 'wip' 2 | 'wip' Here, I would want my query to only return document id 2, because all of its statuses are work_in_progress. I DO NOT want document_id 1 since one of its statuses is 'approved'. I believe this is relational division I want, but I'm not sure where to start. This is MySQL 5.0 FYI.

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  • I need to calculate the date / time difference between one date time column

    - by Stringz
    Details. I have the notes table having the following columns. ID - INT(3) Date - DateTime Note - VARCHAR(100) Tile - Varchar(100) UserName - Varchar(100) Now this table will be having NOTES along with the Titles entered by UserName on the specified date / time. I need to calculate the DateTimeDifference between the TWO ROWS in the SAME COLUMN For example the above table has this peice of information in the table. 64, '2010-03-26 18:16:13', 'Action History', 'sending to Level 2.', 'Salman Khwaja' 65, '2010-03-26 18:19:48', 'Assigned By', 'This is note one for the assignment of RF.', 'Salman Khwaja' 66, '2010-03-27 19:19:48', 'Assigned By', 'This is note one for the assignment of CRF.', 'Salman Khwaja' Now I need to have the following resultset in query reports using MYSQL. TASK - TIME Taken ACTION History - 2010-03-26 18:16:13 Assigned By - 00:03:35 Assigned By - 25:00:00 More smarter approach would be TASK - TIME Taken ACTION History - 2010-03-26 18:16:13 Assigned By - 3 minutes 35 seconds Assigned By - 1 day, 1 hour. I would appreciate if one could give me the PLAIN QUERY along with PHP code to embed it too.

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  • How to merge two tables based on common column and sort the results by date

    - by techiepark
    Hello friends, I have two mysql tables and i want to merge the results of these two tables based on the common column rev_id. The merged results should be sorted by the date of two tables. Please help me. CREATE TABLE `reply` ( `id` int(3) NOT NULL auto_increment, `name` varchar(25) NOT NULL default '', `member_id` varchar(45) NOT NULL, `rev_id` int(3) NOT NULL default '0', `description` text, `post_date` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, `flag` char(2) NOT NULL default 'N', PRIMARY KEY (`id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM; CREATE TABLE `comment` ( `com_id` int(8) NOT NULL auto_increment, `rev_id` int(5) NOT NULL default '0', `member_id` varchar(50) NOT NULL, `comm_desc` text NOT NULL, `date_created` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, PRIMARY KEY (`com_id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM;

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  • free sql script to get a list of countries, provinces/states and their cities.

    - by reggie
    I am working on a registration page for a php website as mysql as the backend database. I need a sql script to insert the list of countries with their associated provinces and the provinces with their associated cities. I need all the countries, provinces and cities all over the world which are related to each other. I can get the individual list of countries, provinces and cities but there is no list that relates them together.. any help appreciated.. thanks in advance.

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  • PDO update with conditional?

    - by dmontain
    I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. But hopefully there is a way to accomplish this in 1 query?

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  • select random value from each type

    - by Joseph Mastey
    I have two tables, rating: +-----------+-----------+-------------+----------+ | rating_id | entity_id | rating_code | position | +-----------+-----------+-------------+----------+ | 1 | 1 | Quality | 0 | | 2 | 1 | Value | 0 | | 3 | 1 | Price | 0 | +-----------+-----------+-------------+----------+ And rating_option +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 2 | 1 | 2 | 2 | 2 | | 3 | 1 | 3 | 3 | 3 | | 4 | 1 | 4 | 4 | 4 | | 5 | 1 | 5 | 5 | 5 | | 6 | 2 | 1 | 1 | 1 | | 7 | 2 | 2 | 2 | 2 | | 8 | 2 | 3 | 3 | 3 | | 9 | 2 | 4 | 4 | 4 | | 10 | 2 | 5 | 5 | 5 | | 11 | 3 | 1 | 1 | 1 | | 12 | 3 | 2 | 2 | 2 | | 13 | 3 | 3 | 3 | 3 | | 14 | 3 | 4 | 4 | 4 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I need a SQL query (not application level, must stay in the database) which will select a set of ratings randomly. A sample result would look like this, but would pick a random value for each rating_id on subsequent calls: +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 8 | 2 | 3 | 3 | 3 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I'm totally stuck on the random part, and grouping by rating_id has been a crap shoot so far. Any MySQL ninjas want to take a stab? Thanks, Joe

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  • Identifying which value of a multi-row inserts fails foreign key constraint

    - by Jonathan
    I have a multi-row insert that looks something like: insert into table VALUES (1, 2, 3), (4, 5, 6), (7, 8, 9); Assume the first attribute (1, 4, 7) is a foreign key to another table and assume that this referenced table does not have the value '4'. A MySQLExeption is thrown with error code 1452. EXCEPTION: Cannot add or update a child row: a foreign key constraint fails (dbName/tableName, CONSTRAINT id FOREIGN KEY (customer_id) REFERENCES referencedTable (customer_id)) Is there a way to identify which value caused the error? I would love to give my user an error message that said something like: Error: '4' does not exist in the referenced table. I am using the .NET mysql connector to execute the insert. Thanks- Jonathan

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  • Force 'Replace Into' to use a certain index

    - by Bobby
    I have a MySQL (5.0) table with 3 rows which are considered a combined Unique Index: CREATE TABLE `test`.`table_a` ( `Id` int(11) NOT NULL AUTO_INCREMENT, `field1` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field2` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field3` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', PRIMARY KEY (`Id`), INDEX `IdxUnqiue` (`field1`(5),`field2`(5),`field3`(5)) ) ENGINE=MyISAM; This table should be filled with a REPLACE INTO query: REPLACE INTO table_a ( Field1, Field2, Field3 ) VALUES ( "Test1", "Test2", "Test3" ) The behavior I'd like to see is that this query always overrides the previous inserted row, because IdxUnique is...ahm, triggered. But unfortunately, there's still the primary index which seems to kick in and always inserts a new row. What I get: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 1 | Test1 | Test2 | Test2 | | 2 | Test1 | Test2 | Test2 | | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ What I want: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ So, can I tell REPLACE INTO to use just a certain Index or to consider one 'more inportant' then another?

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  • Is it possible to call a procedure within an SQL statement?

    - by darren
    Hi everyone I thought I would use a stored routine to clean up some of my more complex SQL statements. From what I've read, it seems impossible to use a stored procedure within an sql statement, and a stored function only returns a single value when what I need is a result set. I am using mySQL v5.0 SELECT p.`id`, gi.`id` FROM `sport`.`players` AS p JOIN `sport`.`gameinstances` AS gi ON p.`id` = gi.`playerid` WHERE (p.`playerid` IN (CALL findPlayers`("Canada", "2002"))) AND (gi.`instanceid` NOT IN (CALL findGameInstances`("Canada", "2002"))); For example, the procedures 'findPlayers' and 'findGameInstances' are are stored routines that execute some SQL and return a result set. I would prefer not to include their code directly within the statement above.

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