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  • The Raspberry Pi JavaFX In-Car System (Part 3)

    - by speakjava
    Ras Pi car pt3 Having established communication between a laptop and the ELM327 it's now time to bring in the Raspberry Pi. One of the nice things about the Raspberry Pi is the simplicity of it's power supply.  All we need is 5V at about 700mA, which in a car is as simple as using a USB cigarette lighter adapter (which is handily rated at 1A).  My car has two cigarette lighter sockets (despite being specified with the non-smoking package and therefore no actual cigarette lighter): one in the centre console and one in the rear load area.  This was convenient as my idea is to mount the Raspberry Pi in the back to minimise the disruption to the very clean design of the Audi interior. The first task was to get the Raspberry Pi to communicate using Wi-Fi with the ELM 327.  Initially I tried a cheap Wi-Fi dongle from Amazon, but I could not get this working with my home Wi-Fi network since it just would not handle the WPA security no matter what I did.  I upgraded to a Wi Pi from Farnell and this works very well. The ELM327 uses Ad-Hoc networking, which is point to point communication.  Rather than using a wireless router each connecting device has its own assigned IP address (which needs to be on the same subnet) and uses the same ESSID.  The settings of the ELM327 are fixed to an IP address of 192.168.0.10 and useing the ESSID, "Wifi327".  To configure Raspbian Linux to use these settings we need to modify the /etc/network/interfaces file.  After some searching of the web and a few false starts here's the settings I came up with: auto lo eth0 wlan0 iface lo inet loopback iface eth0 inet static     address 10.0.0.13     gateway 10.0.0.254     netmask 255.255.255.0 iface wlan0 inet static     address 192.168.0.1     netmask 255.255.255.0     wireless-essid Wifi327     wireless-mode ad-ho0 After rebooting, iwconfig wlan0 reported that the Wi-Fi settings were correct.  However, ifconfig showed no assigned IP address.  If I configured the IP address manually using ifconfig wlan0 192.168.0.1 netmask 255.255.255.0 then everything was fine and I was able to happily ping the IP address of the ELM327.  I tried numerous variations on the interfaces file, but nothing I did would get me an IP address on wlan0 when the machine booted.  Eventually I decided that this was a pointless thing to spend more time on and so I put a script in /etc/init.d and registered it with update-rc.d.  All the script does (currently) is execute the ifconfig line and now, having installed the telnet package I am able to telnet to the ELM327 via the Raspberry Pi.  Not nice, but it works. Here's a picture of the Raspberry Pi in the car for testing In the next part we'll look at running the Java code on the Raspberry Pi to collect data from the car systems.

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  • How to process AJAX requests more securely in PHP?

    - by animuson
    Ok, so I want to send AJAX requests to my website from my Flash games to process data, but I don't want people downloading them, decompiling them, then sending fake requests to be processed, so I'm trying to figure out the most secure way to process in the PHP files. My first idea was to use Apache's built in Authorization module to require a username and password to access the pages on a separate subdomain of my website, but then you'd have to include that username and password in the AJAX request anyway so that seems kind of pointless to even try. My current option looks pretty promising but I want to make sure it will work. Basically it just checks the IP address being sent using REMOTE_ADDR to make sure it's the IP address that my server runs on. <? $allowed = new Array("64.120.211.89", "64.120.211.90"); if (!in_array($_SERVER['REMOTE_ADDR'], $allowed)) header("HTTP/1.1 403 Forbidden"); ?> Both of those IP addresses point to my server. Things I'm worried about: 1) If I send a request from Flash/ActionScript, will that affect the IP address in any way? 2) Is it possible for malicious users to change the IP address that is being sent with REMOTE_ADDR to one of my IP addresses? Any other ways you would suggest that might be more secure?

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  • Manipulating existing XDocument (fails)

    - by Daemonfire3002nd
    Hi there, I got the following Code snippet from my Silverlight Application: var messages = from message in XcurrentMsg.Descendants("message") where DateTime.Parse(message.Attribute("timestamp").Value).CompareTo(DateTime.Parse(MessageCache.Last_Cached())) > 0 select new { ip = message.Attribute("ip").Value, timestamp = message.Attribute("timestamp").Value, text = message.Value, }; if (messages == null) throw new SystemException("No new messages recorded. Application tried to access non existing resources!"); foreach (var message in messages) { XElement temporaryElement = new XElement("message", message.text.ToString(), new XAttribute("ip", message.ip.ToString()), new XAttribute("timestamp", message.timestamp.ToString())); XcurrentMsg.Element("root").Element("messages").Add(temporaryElement); AddMessage(BuildMessage(message.ip, message.timestamp, message.text)); msgCount++; } MessageCache.CacheXML(XcurrentMsg); MessageCache.Refresh(); XcurrentMsg is a XDocument fetched from my server containing messages: Structure <root> <messages> <message ip="" timestamp=""> Text </message> </messages> </root> I want to get all "message" newer than the last time I cached the XcurrentMsg. This works fine as long as I cut out the "XElement temporaryElement" and the "XcurrentMsg.Element...." and simply use the currentMsg string as output. But I want to have "new messages" being saved in my XcurrentMsg / Cache. Now if I do not cut this part out, my Application gets awesome crazy. I think it writes infinite elements to the XcurrentMsg without stopping. I can not figure out what's the problem. regards,

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  • Website hosting from home - IIS6 [closed]

    - by Paul
    I'm wanting to host a few websites from home, primarily because I'm using some BETA Microsoft software (.NET 4 and EF) and don't want to install it on my production server which is hosted at eukhost.com. Basically, I'm completely new to this sort of thing. So far, here is what I've done: Registered the domain name at namecheap.com (let's call it mydomain.com) Gone to "Nameserver Registration" in the panel and entered my IP address for the NS1 and NS2 records (let's say the IP is 0.0.0.0). Gone to "Domain Name Server Setup" and entered ns1.mydomain.com & ns2.mydomain.com Forwarded requests from port 80 to my internal IP (let's say 192.168.1.254) Created the website in IIS (I'm just testing with a single website so far, so have not created any host header values) Now, if I type in the IP address (http://0.0.0.0) I get the site as expected. However, if I enter http://www.mydomain.com I get an error saying "DNS Error - Cannot find server". I'm aware that there is a service from DynDNS that will automatically change the IP if I have a dynamic address, however my IP has remained static since I installed the ISP (since October) so I don't need this. Is there any way that I can get the DNS to work just by configuring IIS or something in Windows? I don't really want to have to pay for any 3rd party service. Thanks,

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  • General website publishing questions involving domain forwarding issue

    - by Gorgeousyousuf
    Even though I have been having a certain level of knowledge and experience about web development I have never interested in obtaining a domain and publishing a website from my own server. Since today I have been struggling with getting my own domain and configuring it utilizing web sources. I started with learning the outline of web publishing process including web server installation, deploying a website for testing purpose,router port forwarding, getting a domain and forwarding domain to my router which will also forward http requests to my web server I am confused about some parts and so far could not get the web site accessed from outside of the network. All I try to do is just for learning purpose so I do not pay much attention to security issues for now. I have Server 2008 and IIS 7.5 installed. I use a laptop and have access to the modem over wireless and my modem is Zoom x6 5590. Well I will continue explaining what I have done so far and what I think will be after each action I did, I have successfully had access to my website on any local computer entering the internal ip address and port pair of the host machine in a browser. Next, I forwarded port 80 of my host machine creating a virtual server like 10.0.0.x(internal ip(static) of the host) - tcp - start port : 80 - end port : 80 in router options. Now I suppose every request that will come to the public Ip on port 80 will be forwarded to my host machine(10.0.0.x) over port 80. So If everyhing went as desired, the website listening on port 80 will accept the request and process the issue and finally respond bla bla bla... I suppose to access my website from outside of the network by entering http://MyPublicIp:80 in a browser but I couldn't accomplish this task by now despite using godady's domain forwarding tool,I see a small view of my website when I click the "preview" button that checks whether the address(http://publicip/Index.aspx) I entered where my domain will be forwarded is available or not. I am sure that configuring domain does not play a role in solving such a problem since using public ip and port matching does not help. So here is the first question, What is the fact that I face this problem? After that, I have couple of question regarding domain forwarding using godaddy tool. Can I forward my domain to a any port for example port 8080 other than default http port 80? Additionally, can I use a sub-domain to forward to a different port of the host? What I want to design is if the client enters www.mydomain.com, website1 will respond over a specified port and after when a client enters info.mydomain.com, another website which listens on different port will respond. I tried to add a sub-domain and forward it to a address like http://www.mydomain.com:8080/Index.aspx with no success. Can I really do that? Finally, what if I have a ftp site listening on the default port 21 and I create a domain like ftp.mydomain.com that will forward to that ftp site address. Is it possible to use sub-domains for ftp site access? I know I am more than confused but no matter whatever and however you reply to me, you will help me have a more clear view on this subject. Thank you very much from now.

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  • How to Name Linked Servers

    - by Bill Graziano
    I did another SQL Server migration over the weekend that dealt with linked servers.  I’ve seen all kinds of odd naming schemes and there are a few I like and a few I suggest you avoid. Don’t name your linked server for its IP address.  At some point whatever is on the other end of that IP address will move.  You’ll probably need to point your linked server to a new IP address but not change the name of the linked server.  And then you’ve completely lost any context around this.  Bonus points if a new SQL Server eventually ends up at the old IP address further adding confusion when you’re trying to troubleshoot. Don’t name your linked server based on its instance name.  This one is less obvious.  It sounds nice to have a linked server named [VSRV1\SQLTRAN01].  You know what it is and it’s easy to use.  It’s less nice when you’ve got 200 stored procedures that all reference this linked server but the database they reference has moved to a new instance.  Now when you query this you’re actually querying a different instance. (Please note: I’m not saying it’s a good idea to have 200 stored procedures that all reference a linked server.  I’m just saying it’s not all that uncommon.) Consider naming your linked server something that you can easily search on.  See my note above.  You can also get around this by always enclosing the name in brackets.  That is harder to enforce unless you use some odd characters in it. Consider naming your linked server based on the function.  For example, I’ve had some luck having a linked server named [DW] that points to our data warehouse server.  That server can change names or physically move and all I need to do is update the linked server to point to the new destination.  The descriptive name of the linked server is still accurate.  No code needs to change and people still know what it is just by looking at it. Consider naming your linked server for the database.  I’m still thinking through this one.  It may mean you have multiple linked servers that point to the same instance.  I’ve found that database names rarely change.  It also makes it easier to move individual databases to new servers. Consider pointing your linked servers to DNS entries and not IP addresses.  I’ve done this for reporting databases and had some success.  Especially for read-only snapshots that can get created on the main database or on the mirror.  What issues have you had with linked server names?  What has worked for you?  Where are the holes in my approach?

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  • Can't access local network when connect to pppoe

    - by shantanu
    I am using DSL(PPPOE) connection in ubuntu. It has two part (I am not sure), when I just connect the cable, system automatically get an IP address started with 172.x.x.x(DHCP). When I connect using username/password (PPPOE) I get another IP started with 10.x.x.x and can access internet but can't access some local IP (in my LAN), which are some FTP, media server provided by my ISP. I complained about that to my ISP but they reply Windows is working It's true, Windows 7 is working fine with this settings. I can access internet and local server at the same time. Also I use a WIFI router (TP-link TL-WR340G/TL-WR340GD) which result the same problem. So when I connect cable directly to system and use Windows 7 than everything is fine. Otherwise problem. Similar problem discussed here. Edit before connect. route -n Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 0.0.0.0 172.100.0.1 0.0.0.0 UG 0 0 0 eth0 172.100.0.0 0.0.0.0 255.255.0.0 U 1 0 0 eth0 after connect. Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 0.0.0.0 10.12.44.91 0.0.0.0 UG 0 0 0 ppp0 10.12.44.91 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0 ifconfig after connect eth0 Link encap:Ethernet HWaddr 74:d0:2b:d5:b3:6c inet6 addr: fe80::76d0:2bff:fed5:b36c/64 Scope:Link inet6 addr: 2002:ac64:154:c:76d0:2bff:fed5:b36c/64 Scope:Global inet6 addr: fec0::c:76d0:2bff:fed5:b36c/64 Scope:Site UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:26582 errors:0 dropped:18 overruns:0 frame:0 TX packets:2340 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:2542063 (2.5 MB) TX bytes:244938 (244.9 KB) lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:65536 Metric:1 RX packets:4118 errors:0 dropped:0 overruns:0 frame:0 TX packets:4118 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:336759 (336.7 KB) TX bytes:336759 (336.7 KB) ppp0 Link encap:Point-to-Point Protocol inet addr:10.12.44.95 P-t-P:10.12.44.91 Mask:255.255.255.255 inet6 addr: fe80::a536:c7ae:e079:d88d/10 Scope:Link UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1492 Metric:1 RX packets:689 errors:0 dropped:0 overruns:0 frame:0 TX packets:744 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:3 RX bytes:385746 (385.7 KB) TX bytes:75296 (75.2 KB) I used network manager to create network(DSL connection)

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  • Objective-C @class / import best practice

    - by Winder
    I've noticed that a lot of Objective-C examples will forward declare classes with @class, then actually import the class in the .m file with an import. I understand that this is considered a best practice, as explained in answers to question: http://stackoverflow.com/questions/322597/objective-c-class-vs-import Coming from C++ this feels backwards. I would normally include all needed .h files in the new classes header file. This seems useful since it would make the compiler generate a warning when two classes include each other, at which point I can decide whether this is a bad thing or not then use the same Objective-C style and forward declare the class in the header and include it in the .cpp file. What is the benefit of forward declaring @class and importing in the implementation file? Should it be a best practice in C++ to forward declare classes rather than including the header file? Or is it wrong to think of Objective-C and C++ in these similar terms to begin with?

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  • Detecting Acceleration in a car (iPhone Accelerometer)

    - by TheGazzardian
    Hello, I am working on an iPhone app where we are trying to calculate the acceleration of a moving car. Similar apps have accomplished this (Dynolicious), but the difference is that this app is designed to be used during general city driving, not on a drag strip. This leads us to one big concern that Dynolicious was luckily able to avoid: hills. Yes, hills. There are two important stages to this: calibration, and actual driving. Our initial run was simple and suffered the consequences. During the calibration stage, I took the average force on the phone, and during running, I just subtracted the average force from the current force to get the current acceleration this frame. The problem with this is that the typical car receives much more force than just the forward force - everything from turning to potholes was causing the values to go out of sync with what was really happening. The next run was to add the condition that the iPhone must be oriented in such a way that the screen was facing toward the back of the car. Using this method, I attempted to follow only force on the z-axis, but this obviously lead to problems unless the iPhone was oriented directly upright, because of gravity. Some trigonometry later, and I had managed to work gravity out of the equation, so that the car was actually being read very, very well by the iPhone. Until I hit a slope. As soon as the angle of the car changed, suddenly I was receiving accelerations and decelerations that didn't make sense, and we were once again going out of sync. Talking with someone a lot smarter than me at math lead to a solution that I have been trying to implement for longer than I would like to admit. It's steps are as follows: 1) During calibration, measure gravity as a vector instead of a size. Store that vector. 2) When the car initially moves forward, take the vector of motion and subtract gravity. Use this as the forward momentum. (Ignore, for now, the user cases where this will be difficult and let's concentrate on the math :) 3) From the forward vector and the gravity vector, construct a plane. 4) Whenever a force is received, project it onto said plane to get rid of sideways force/etc. 5) Then, use that force, the known magnitude of gravity, and the known direction of forward motion to essentially solve a triangle to get the forward vector. The problem that is causing the most difficulty in this new system is not step 5, which I have gotten to the point where all the numbers look as they should. The difficult part is actually the detection of the forward vector. I am selecting vectors whose magnitude exceeds gravity, and from there, averaging them and subtracting gravity. (I am doing some error checking to make sure that I am not using a force just because the iPhone accelerometer was off by a bit, which happens more frequently than I would like). But if I plot these vectors that I am using, they actually vary by an angle of about 20-30 degrees, which can lead to some strong inaccuracies. The end result is that the app is even more inaccurate now than before. So basically - all you math and iPhone brains out there - any glaring errors? Any potentially better solutions? Any experience that could be useful at all? Award: offering a bounty of $250 to the first answer that leads to a solution.

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  • How do I get the next token in a Cstring if I want to use it as an int? (c++)

    - by Van
    My objective is to take directions from a user and eventually a text file to move a robot. The catch is that I must use Cstrings(such as char word[];) rather than the std::string and tokenize them for use. the code looks like this: void Navigator::manualDrive() { char uinput[1]; char delim[] = " "; char *token; cout << "Enter your directions below: \n"; cin.ignore(); cin.getline (uinput, 256); token=strtok(uinput, delim); if(token == "forward") { int inches; inches=token+1; travel(inches); } } I've never used Cstrings I've never tokenized anything before, and I don't know how to write this. Our T.A.'s expect us to google and find all the answers because they are aware we've never been taught these methods. Everyone in my lab is having much more trouble than usual. I don't know the code to write but I know what I want my program to do. I want it to execute like this: 1) Ask for directions. 2) cin.getline the users input 3) tokenize the inputed string 4) if the first word token == "forward" move to the next token and find out how many inches to move forward then move forward 5) else if the first token == "turn" move to the next token. if the next token == "left" move to the next token and find out how many degrees to turn left I will have to do this for forward x, backward x, turn left x, turn right x, and stop(where x is in inches or degrees). I already wrote functions that tell the robot how to move forward an inch and turn in degrees. I just need to know how to convert the inputted strings to all lowercase letters and move from token to token and convert or extract the numbers from the string to use them as integers. If all is not clear you can read my lab write up at this link: http://www.cs.utk.edu/~cs102/robot_labs/Lab9.html If anything is unclear please let me know, and I will clarify as best I can.

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  • Any socket programmers out there? How can I obtain the IPv4 address of the client?

    - by Dr Dork
    Hello! I'm prepping for a simple work project and am trying to familiarize myself with the basics of socket programming in a Unix dev environment. At this point, I have some basic server side code setup to listen for incoming TCP connection requests from clients after the parent socket has been created and is set to listen... int sockfd, newfd; unsigned int len; socklen_t sin_size; char msg[]="Test message sent"; char buf[MAXLEN]; int st, rv; struct addrinfo hints, *serverinfo, *p; struct sockaddr_storage client; char ip[INET6_ADDRSTRLEN]; . . //parent socket creation and listen code omitted for simplicity . //wait for connection requests from clients while(1) { //Returns the socketID and address of client connecting to socket if( ( newfd = accept(sockfd, (struct sockaddr *)&client, &len) ) == -1 ){ perror("Accept"); exit(-1); } if( (rv = recv(newfd, buf, MAXLEN-1, 0 )) == -1) { perror("Recv"); exit(-1); } struct sockaddr_in *clientAddr = ( struct sockaddr_in *) get_in_addr((struct sockaddr *)&client); inet_ntop(client.ss_family, clientAddr, ip, sizeof ip); printf("Receive from %s: query type is %s\n", ip, buf); if( ( st = send(newfd, msg, strlen(msg), 0)) == -1 ) { perror("Send"); exit(-1); } //ntohs is used to avoid big-endian and little endian compatibility issues printf("Send %d byte to port %d\n", ntohs(clientAddr->sin_port) ); close(newfd); } } I found the get_in_addr function online and placed it at the top of my code and use it to obtain the IP address of the client connecting... // get sockaddr, IPv4 or IPv6: void *get_in_addr(struct sockaddr *sa) { if (sa->sa_family == AF_INET) { return &(((struct sockaddr_in*)sa)->sin_addr); } return &(((struct sockaddr_in6*)sa)->sin6_addr); } but the function always returns the IPv6 IP address since thats what the sa_family property is set as. My question is, is the IPv4 IP address stored anywhere in the data I'm using and, if so, how can I access it? Thanks so much in advance for all your help!

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  • OpenVPN IPv6 over IPv4 tunnel

    - by user66779
    Today I installed OpenVPN 2.3rc2 on both my windows 7 client machine and centos 6 server. This new version of OpenVPN provides full compatibility for IPv6. The Problem: I am currently able to connect to the server (through the IPv4 tunnel) and ping the IPv6 address which is assigned to my client and I can also ping the tun0 interface on the server. However, I cannot browse to any IPv6 websites. My vps provider has given me this: 2607:f840:0044:0022:0000:0000:0000:0000/64 is routed to this server (2607:f840:0:3f:0:0:0:eda). This is ifconfig after setup with OpenVPN running: eth0 Link encap:Ethernet HWaddr 00:16:3E:12:77:54 inet addr:208.111.39.160 Bcast:208.111.39.255 Mask:255.255.255.0 inet6 addr: 2607:f740:0:3f::eda/64 Scope:Global inet6 addr: fe80::216:3eff:fe12:7754/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:2317253 errors:0 dropped:7263 overruns:0 frame:0 TX packets:1977414 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:1696120096 (1.5 GiB) TX bytes:1735352992 (1.6 GiB) Interrupt:29 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:0 (0.0 b) TX bytes:0 (0.0 b) tun0 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:10.8.0.1 P-t-P:10.8.0.2 Mask:255.255.255.255 inet6 addr: 2607:f740:44:22::1/64 Scope:Global UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1500 Metric:1 RX packets:739567 errors:0 dropped:0 overruns:0 frame:0 TX packets:1218240 errors:0 dropped:1542 overruns:0 carrier:0 collisions:0 txqueuelen:100 RX bytes:46512557 (44.3 MiB) TX bytes:1559930874 (1.4 GiB) So OpenVPN is sucessfully creating a tun0 interface and assigning clients IPv6 addresses using 2607:f840:44:22::/64. The first client to connect is getting 2607:f840:44:22::1000 and the second 2607:f840:44:22::1001, and so on... plus 1 each time. After connecting as the first client, I can ping from my windows client machine 2607:f740:44:22::1 and 2607:f740:44:22::1000. However, I have no access to IPv6 websites. I believe the problem is that the tun0 IPv6 addressees are not being forwarded to the eth0 interface. This is the firewall running on the server: #!/bin/sh # # iptables configuration script # # Flush all current rules from iptables # iptables -F iptables -t nat -F # # Allow SSH connections on tcp port 22 # iptables -A INPUT -i eth0 -p tcp --dport 22 -j ACCEPT iptables -A OUTPUT -o eth0 -p tcp --sport 22 -j ACCEPT # # Set access for localhost # iptables -A INPUT -i lo -j ACCEPT # # Accept connections on 1195 for vpn access from client # iptables -A INPUT -i eth0 -p udp --dport 1195 -m state --state NEW,ESTABLISHED -j ACCEPT iptables -A OUTPUT -o eth0 -p udp --sport 1195 -m state --state ESTABLISHED -j ACCEPT # # Apply forwarding for OpenVPN Tunneling # iptables -A FORWARD -m state --state RELATED,ESTABLISHED -j ACCEPT iptables -A FORWARD -s 10.8.0.0/24 -j ACCEPT iptables -t nat -A POSTROUTING -o eth0 -j SNAT --to 209.111.39.160 iptables -A FORWARD -j REJECT # # Enable forwarding # echo 1 > /proc/sys/net/ipv4/ip_forward # # Set default policies for INPUT, FORWARD and OUTPUT chains # iptables -P INPUT ACCEPT iptables -P FORWARD ACCEPT iptables -P OUTPUT ACCEPT # # IPv6 # IP6TABLES=/sbin/ip6tables $IP6TABLES -F INPUT $IP6TABLES -F FORWARD $IP6TABLES -F OUTPUT echo -n "1" >/proc/sys/net/ipv6/conf/all/forwarding echo -n "1" >/proc/sys/net/ipv6/conf/all/proxy_ndp echo -n "0" >/proc/sys/net/ipv6/conf/all/autoconf echo -n "0" >/proc/sys/net/ipv6/conf/all/accept_ra $IP6TABLES -A INPUT -i eth0 -m state --state ESTABLISHED,RELATED -j ACCEPT $IP6TABLES -A INPUT -i eth0 -p tcp --dport 22 -j ACCEPT $IP6TABLES -A INPUT -i eth0 -p icmpv6 -j ACCEPT $IP6TABLES -P INPUT ACCEPT $IP6TABLES -P FORWARD ACCEPT $IP6TABLES -P OUTPUT ACCEPT Server.conf: server-ipv6 2607:f840:44:22::/64 server 10.8.0.0 255.255.255.0 port 1195 proto udp dev tun ca ca.crt cert server.crt key server.key dh dh2048.pem ifconfig-pool-persist ipp.txt push "redirect-gateway def1 bypass-dhcp" push "dhcp-option DNS 208.67.222.222" push "dhcp-option DNS 208.67.220.220" keepalive 10 60 tls-auth ta.key 0 cipher AES-256-CBC comp-lzo user nobody group nobody persist-key persist-tun status openvpn-status.log log-append openvpn.log verb 5 Client.conf: client dev tun nobind keepalive 10 60 hand-window 15 remote 209.111.39.160 1195 udp persist-key persist-tun ca ca.crt key client1.key cert client1.crt remote-cert-tls server tls-auth ta.key 1 comp-lzo verb 3 cipher AES-256-CBC I'm not sure where I am going wrong, it could be the firewall, or something missing from server or client.conf. This version of OpenVPN was only released yesterday, and there's little info on the internet about how to setup an IPv6 over IPv4 vpn tunnel. I've read the manual for this new version of OpenVPN (parts pertaining to IPv6) and it provides very little info too. Thanks for any help.

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  • Bind Config section to DataTable using c#

    - by srk
    I have the following config section in my app.config file and the code to iterate through config section to retrieve the values. But i want to save the values of config section to a datatable in a proper structure. How ? I want to show all the values in datagridview with appropriate columns. <configSections> <section name="ServerInfo" type="System.Configuration.IConfigurationSectionHandler" /> </configSections> <ServerInfo> <Server id="1"> <Name>SRUAV1</Name> <key> 1 </key> <IP>10.1.150.110</IP> <Port>7901</Port> </Server> <Server id="2"> <Name>SRUAV2</Name> <key> 4 </key> <IP>10.1.150.110</IP> <Port>7902</Port> </Server> <Server id="3"> <Name>SRUAV3</Name> <key> 6 </key> <IP>10.1.150.110</IP> <Port>7904</Port> </Server> </ServerInfo> Code : public void GetServerValues(string strSelectedServer) { Configuration config = ConfigurationManager.OpenExeConfiguration(ConfigurationUserLevel.None); ConfigurationSection section = config.GetSection("ServerInfo"); XmlDocument xml = new XmlDocument(); xml.LoadXml(section.SectionInformation.GetRawXml()); string temp = ""; XmlNodeList applicationList = xml.DocumentElement.SelectNodes("Server"); for (int i = 0; i < applicationList.Count; i++) { object objAppId = applicationList[i].Attributes["id"]; int iAppId = 0; if (objAppId != null) { iAppId = Convert.ToInt32(applicationList[i].Attributes["id"].Value); } temp = BuildServerValues(applicationList[i]); } } public string BuildServerValues(XmlNode applicationNode) { for (int i = 0; i < applicationNode.ChildNodes.Count; i++) { if (applicationNode.ChildNodes.Item(i).Name.ToString().Equals("Name")) { strServerName = applicationNode.ChildNodes.Item(i).InnerXml.ToString(); } if (applicationNode.ChildNodes.Item(i).Name.ToString().Equals("IP")) { strIP = applicationNode.ChildNodes.Item(i).InnerXml.ToString(); } if (applicationNode.ChildNodes.Item(i).Name.ToString().Equals("Port")) { strPort = applicationNode.ChildNodes.Item(i).InnerXml.ToString(); } } return strServerName; }

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  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

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  • How can I obtain the IPv4 address of the client?

    - by Dr Dork
    Hello! I'm prepping for a simple work project and am trying to familiarize myself with the basics of socket programming in a Unix dev environment. At this point, I have some basic server side code setup to listen for incoming TCP connection requests from clients after the parent socket has been created and is set to listen... int sockfd, newfd; unsigned int len; socklen_t sin_size; char msg[]="Test message sent"; char buf[MAXLEN]; int st, rv; struct addrinfo hints, *serverinfo, *p; struct sockaddr_storage client; char ip[INET6_ADDRSTRLEN]; . . //parent socket creation and listen code omitted for simplicity . //wait for connection requests from clients while(1) { //Returns the socketID and address of client connecting to socket if( ( newfd = accept(sockfd, (struct sockaddr *)&client, &len) ) == -1 ){ perror("Accept"); exit(-1); } if( (rv = recv(newfd, buf, MAXLEN-1, 0 )) == -1) { perror("Recv"); exit(-1); } struct sockaddr_in *clientAddr = ( struct sockaddr_in *) get_in_addr((struct sockaddr *)&client); inet_ntop(client.ss_family, clientAddr, ip, sizeof ip); printf("Receive from %s: query type is %s\n", ip, buf); if( ( st = send(newfd, msg, strlen(msg), 0)) == -1 ) { perror("Send"); exit(-1); } //ntohs is used to avoid big-endian and little endian compatibility issues printf("Send %d byte to port %d\n", ntohs(clientAddr->sin_port) ); close(newfd); } } I found the get_in_addr function online and placed it at the top of my code and use it to obtain the IP address of the client connecting... // get sockaddr, IPv4 or IPv6: void *get_in_addr(struct sockaddr *sa) { if (sa->sa_family == AF_INET) { return &(((struct sockaddr_in*)sa)->sin_addr); } return &(((struct sockaddr_in6*)sa)->sin6_addr); } but the function always returns the IPv6 IP address since thats what the sa_family property is set as. My question is, is the IPv4 IP address stored anywhere in the data I'm using and, if so, how can I access it? Thanks so much in advance for all your help!

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  • Cannot determine ethernet address for proxy ARP on PPTP

    - by Linux Intel
    I installed pptp server on a centos 6 64bit server PPTP Server ip : 55.66.77.10 PPTP Local ip : 10.0.0.1 Client1 IP : 10.0.0.60 centos 5 64bit Client2 IP : 10.0.0.61 centos5 64bit PPTP Server can ping Client1 And client 1 can ping PPTP Server PPTP Server can ping Client2 And client 2 can ping PPTP Server The problem is client 1 can not ping Client 2 and i get this error also on PPTP server error log Cannot determine ethernet address for proxy ARP Ping from Client2 to Client1 PING 10.0.0.60 (10.0.0.60) 56(84) bytes of data. --- 10.0.0.60 ping statistics --- 6 packets transmitted, 0 received, 100% packet loss, time 5000ms route -n on PPTP Server Destination Gateway Genmask Flags Metric Ref Use Iface 10.0.0.60 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0 10.0.0.61 0.0.0.0 255.255.255.255 UH 0 0 0 ppp1 55.66.77.10 0.0.0.0 255.255.255.248 U 0 0 0 eth0 10.0.0.0 0.0.0.0 255.0.0.0 U 0 0 0 eth0 0.0.0.0 55.66.77.19 0.0.0.0 UG 0 0 0 eth0 route -n On Client 1 Destination Gateway Genmask Flags Metric Ref Use Iface 10.0.0.1 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0 55.66.77.10 70.14.13.19 255.255.255.255 UGH 0 0 0 eth0 10.0.0.0 0.0.0.0 255.0.0.0 U 0 0 0 eth1 0.0.0.0 70.14.13.19 0.0.0.0 UG 0 0 0 eth0 route -n On Client 2 Destination Gateway Genmask Flags Metric Ref Use Iface 10.0.0.1 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0 55.66.77.10 84.56.120.60 255.255.255.255 UGH 0 0 0 eth1 10.0.0.0 0.0.0.0 255.0.0.0 U 0 0 0 eth0 0.0.0.0 84.56.120.60 0.0.0.0 UG 0 0 0 eth1 cat /etc/ppp/options.pptpd on PPTP server ############################################################################### # $Id: options.pptpd,v 1.11 2005/12/29 01:21:09 quozl Exp $ # # Sample Poptop PPP options file /etc/ppp/options.pptpd # Options used by PPP when a connection arrives from a client. # This file is pointed to by /etc/pptpd.conf option keyword. # Changes are effective on the next connection. See "man pppd". # # You are expected to change this file to suit your system. As # packaged, it requires PPP 2.4.2 and the kernel MPPE module. ############################################################################### # Authentication # Name of the local system for authentication purposes # (must match the second field in /etc/ppp/chap-secrets entries) name pptpd # Strip the domain prefix from the username before authentication. # (applies if you use pppd with chapms-strip-domain patch) #chapms-strip-domain # Encryption # (There have been multiple versions of PPP with encryption support, # choose with of the following sections you will use.) # BSD licensed ppp-2.4.2 upstream with MPPE only, kernel module ppp_mppe.o # {{{ refuse-pap refuse-chap refuse-mschap # Require the peer to authenticate itself using MS-CHAPv2 [Microsoft # Challenge Handshake Authentication Protocol, Version 2] authentication. require-mschap-v2 # Require MPPE 128-bit encryption # (note that MPPE requires the use of MSCHAP-V2 during authentication) require-mppe-128 # }}} # OpenSSL licensed ppp-2.4.1 fork with MPPE only, kernel module mppe.o # {{{ #-chap #-chapms # Require the peer to authenticate itself using MS-CHAPv2 [Microsoft # Challenge Handshake Authentication Protocol, Version 2] authentication. #+chapms-v2 # Require MPPE encryption # (note that MPPE requires the use of MSCHAP-V2 during authentication) #mppe-40 # enable either 40-bit or 128-bit, not both #mppe-128 #mppe-stateless # }}} # Network and Routing # If pppd is acting as a server for Microsoft Windows clients, this # option allows pppd to supply one or two DNS (Domain Name Server) # addresses to the clients. The first instance of this option # specifies the primary DNS address; the second instance (if given) # specifies the secondary DNS address. #ms-dns 10.0.0.1 #ms-dns 10.0.0.2 # If pppd is acting as a server for Microsoft Windows or "Samba" # clients, this option allows pppd to supply one or two WINS (Windows # Internet Name Services) server addresses to the clients. The first # instance of this option specifies the primary WINS address; the # second instance (if given) specifies the secondary WINS address. #ms-wins 10.0.0.3 #ms-wins 10.0.0.4 # Add an entry to this system's ARP [Address Resolution Protocol] # table with the IP address of the peer and the Ethernet address of this # system. This will have the effect of making the peer appear to other # systems to be on the local ethernet. # (you do not need this if your PPTP server is responsible for routing # packets to the clients -- James Cameron) proxyarp # Normally pptpd passes the IP address to pppd, but if pptpd has been # given the delegate option in pptpd.conf or the --delegate command line # option, then pppd will use chap-secrets or radius to allocate the # client IP address. The default local IP address used at the server # end is often the same as the address of the server. To override this, # specify the local IP address here. # (you must not use this unless you have used the delegate option) #10.8.0.100 # Logging # Enable connection debugging facilities. # (see your syslog configuration for where pppd sends to) debug # Print out all the option values which have been set. # (often requested by mailing list to verify options) #dump # Miscellaneous # Create a UUCP-style lock file for the pseudo-tty to ensure exclusive # access. lock # Disable BSD-Compress compression nobsdcomp # Disable Van Jacobson compression # (needed on some networks with Windows 9x/ME/XP clients, see posting to # poptop-server on 14th April 2005 by Pawel Pokrywka and followups, # http://marc.theaimsgroup.com/?t=111343175400006&r=1&w=2 ) novj novjccomp # turn off logging to stderr, since this may be redirected to pptpd, # which may trigger a loopback nologfd # put plugins here # (putting them higher up may cause them to sent messages to the pty) cat /etc/ppp/options.pptp on Client1 and Client2 ############################################################################### # $Id: options.pptp,v 1.3 2006/03/26 23:11:05 quozl Exp $ # # Sample PPTP PPP options file /etc/ppp/options.pptp # Options used by PPP when a connection is made by a PPTP client. # This file can be referred to by an /etc/ppp/peers file for the tunnel. # Changes are effective on the next connection. See "man pppd". # # You are expected to change this file to suit your system. As # packaged, it requires PPP 2.4.2 or later from http://ppp.samba.org/ # and the kernel MPPE module available from the CVS repository also on # http://ppp.samba.org/, which is packaged for DKMS as kernel_ppp_mppe. ############################################################################### # Lock the port lock # Authentication # We don't need the tunnel server to authenticate itself noauth # We won't do PAP, EAP, CHAP, or MSCHAP, but we will accept MSCHAP-V2 # (you may need to remove these refusals if the server is not using MPPE) refuse-pap refuse-eap refuse-chap refuse-mschap # Compression # Turn off compression protocols we know won't be used nobsdcomp nodeflate # Encryption # (There have been multiple versions of PPP with encryption support, # choose which of the following sections you will use. Note that MPPE # requires the use of MSCHAP-V2 during authentication) # # Note that using PPTP with MPPE and MSCHAP-V2 should be considered # insecure: # http://marc.info/?l=pptpclient-devel&m=134372640219039&w=2 # https://github.com/moxie0/chapcrack/blob/master/README.md # http://technet.microsoft.com/en-us/security/advisory/2743314 # http://ppp.samba.org/ the PPP project version of PPP by Paul Mackarras # ppp-2.4.2 or later with MPPE only, kernel module ppp_mppe.o # If the kernel is booted in FIPS mode (fips=1), the ppp_mppe.ko module # is not allowed and PPTP-MPPE is not available. # {{{ # Require MPPE 128-bit encryption #require-mppe-128 # }}} # http://mppe-mppc.alphacron.de/ fork from PPP project by Jan Dubiec # ppp-2.4.2 or later with MPPE and MPPC, kernel module ppp_mppe_mppc.o # {{{ # Require MPPE 128-bit encryption #mppe required,stateless # }}} IPtables is stopped on clients and server, Also net.ipv4.ip_forward = 1 is enabled on PPTP Server. How can i solve this problem .?

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  • Port forwarding on Fortigate 50B

    - by sindre j
    I have serious problems setting up port forwarding on a Fortigate 50B. The unit is basically running as factory default, the wan1 interface is connected to my fibre optic internet modem, and my lan is connected to the internal switch of the Fortigate. The factory default firewall policy allowing traffic from the internal interface to wan1 is kept and I'm able to access the interet as normal. Then I added a virtual ip and a firewall policy for allowing access from the internet to my local servers (ip 192.168.9.51) webserver (standard port 80). The settings I made are as follows. Edit Virtual IP Mapping Name : Server VIP External interface : wan1 Type : Static NAT Extermal IP Address/Range : 0.0.0.0 Mapped IP Address/Range : 192.168.9.51 Port Forwading : not checked Firewall policy Source interface/Zone : wan1 Source address : all Destination interface/Zone : internal Destination address : Server VIP Schedule : always Service : HTTP Action : ACCEPT no other settings checked What happens now is that I'm unable to access internet from my server, I'm not getting through to the webserver from internet either. I'm able to ping a site on the outside, but all web traffic is blocked, both ways. I've checked the documentation, but as far as I can tell I have set this up correctly. Anyone here with knowledge of Fortigate port forwading/NAT?

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  • Standard Protection:Prevent IRC communication

    - by awe
    I have McAffee virusscan on my work computer, and every time I start up, I get 2 log entries like this: Blocked by port blocking rule C:\Program Files\Skype\Phone\Skype.exe Anti-virus Standard Protection:Prevent IRC communication The difference between the two, is that at the end there are 2 different IP addresses (which I don't recognise as belongs to us) with port :6667 on one and :6669 on the other. Although this is logged, Skype seems to work as expected; including talking, chatting and screen sharing (new feature in Skype 4.1). Anyone knows anything about what this is? EDIT: I also have a Skype certified plugin in Skype called Cucku Backup. I did not find anything in the documentation that Cucku is trying to access these ports through Skype, but it could be...? EDIT2: I did a search on the IP addresses in question on www.webyield.net, and resulted in the following: IP 71.251.72.173 (this one used port :6667): Host name: pool-71-251-72-173.tampfl.fios.verizon.net IP 79.87.54.165 (this one used port :6669): Host name: 165.54.87-79.rev.gaoland.net

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  • PSExec on Windows 2008 R2 Failing "Network name cannot be found"

    - by Adam Frisby
    Hi, We've got a bunch of remote admin scripts which rely on psexec and they do not appear to be working over the network on our new 2008 hosts. An error dump is below: C:\Users\<user>\Desktop\PsTools> psexec \\<host IP> -u Administrator -p <pass> <cmd> PsExec v1.97 - Execute processes remotely Copyright (C) 2001-2009 Mark Russinovich Sysinternals - www.sysinternals.com Couldn't access <host IP>: The network name cannot be found. Make sure that the default admin$ share is enabled on <host IP>. We've tried both the machine name and the IP address in with the same results. The same command has worked previously with our Win2K3 hosts - so we're presuming it is some form of security change between the 2003 and 2008R2. Anyone have any clues?

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  • Why isn't ICMP routing with iptables nat routing

    - by Scott Forsyth - MVP
    I'm using iptables on Ubuntu server to route a public IP to a private IP. I want to nat all traffic, including 80, 443 and ICMP. However, it appears that ICMP isn't routing. I have a steady ping going to the public IP and it never stops, even with NAT pointing to a bogus IP. Here are the rules that I'm using: iptables -t nat -I PREROUTING -d 206.72.119.76 -j DNAT --to-destination 10.240.5.5 iptables -t nat -I POSTROUTING -s 10.240.5.5 -j SNAT --to-source 206.72.119.76 I tried with rules for ICMP specifically, but no such luck: iptables -t nat -I PREROUTING -d 206.72.119.76 - icmp --icmp-type echo-request -j DNAT --to-destination 10.240.5.5 Any ideas?

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  • .htaccess allow from hostname?

    - by Mikey B
    Ubuntu 9.10 Apache2 Hi Guys, Long story short, I need to restrict access to a certain part of my web site based on a dynamic IP source address that changes every now and then. Historically, I've just added the following to htaccess... order deny,allow deny from all # allow my dynamic IP address allow from <dynamic ip> But the problem is that I'll have to manually make this change every time the IP changes. Ideally I'd like to specify a hostname instead... something like: order deny,allow deny from all # allow my host allow from hostname.whatever.local That doesn't seemed to have worked though. I get an error 403 - access forbidden. Does .htaccess not support hostnames?

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  • Subversion Apache Ubuntu - Remote Access?

    - by Hollowsteps
    Okay, a couple days ago I built a bare bones kit into a machine. I've been running through tutorials to get it to work and right now I've gotten as far as making it available in my lan, hooray! However, I cannot access the repositories remotely. Any machine on the lan can easily access it through the hostname or, using 'outbound ip/hostname' or 'outbound ip/machine ip'. The machine can be pinged from a remote, non-lan machine and responds. I just can't get anyone into it outside of my lan. I've been trying to figure it out but I'm lost. I'm breaking a few rules and if any of these would be my problem, please indicate. I don't think I have a static IP (However I check my outbound IP whenever I do testing, is that not enough? It has stayed the same for 5+ days) I have not discussed this set-up with my service provider (Does Optimum Online block port 80? If so, can I just switch apache to listen on a different port?) I am in the DMZ of my router. This is what allowed it to be pinged remotely. For security reasons the machine that is in that zone is turned off most of the time until I can get it locked down. Any help would be appreciated, even if it's just a couple of words I could google to understand what I'm doing wrong. Tortoise SVN does not allow access remotely, but it does within the LAN as well.

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  • QoS basics on a Cisco ASA

    - by qbn
    Could someone briefly explain how to use QoS on Cisco ASA 5505? I have the basics of policing down, but what about shaping and priorities? Basically what I'm trying to do is carve out some bandwidth for my VPN subnets (in an object-group called priority-traffic). I've seen this Cisco QoS document, however configuring shaping and priority-queue don't seem to have any effects in my test. A full download of the linux kernel from kernel.org will boost a ping to a server via VPN sky high. Policing has been successful in passing this test, although it doesn't seem as efficient (I cap non-vpn traffic at 3 of my 4.5 megabits of bandwidth). Am I misunderstanding the results of the test? I think there is some simple concept I'm not grasping here. EDIT: Here is my config thus far (I have 4.5 megabits of bandwidth): access-list priority-traffic extended permit ip object-group priority-traffic any access-list priority-traffic extended permit ip any object-group priority-traffic access-list priority-traffic extended permit icmp object-group priority-traffic any access-list priority-traffic extended permit icmp any object-group priority-traffic access-list non-priority-traffic extended deny ip object-group priority-traffic any access-list non-priority-traffic extended deny ip any object-group priority-traffic access-list non-priority-traffic extended permit ip any any priority-queue outside queue-limit 440 class-map non-priority-traffic match access-list non-priority-traffic class-map priority-traffic match access-list priority-traffic class-map inspection_default match default-inspection-traffic policy-map type inspect dns preset_dns_map parameters message-length maximum 512 policy-map global_policy class inspection_default inspect dns preset_dns_map inspect ftp inspect h323 h225 inspect h323 ras inspect rsh inspect rtsp inspect sqlnet inspect skinny inspect sunrpc inspect xdmcp inspect sip inspect netbios inspect tftp policy-map outbound-qos-policy class non-priority-traffic police input 2500000 police output 2500000 class priority-traffic priority service-policy global_policy global service-policy outbound-qos-policy interface outside

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  • Finding all domains registered in a nameserver

    - by Florian
    Up until now, I was pretty confident that it was pretty much impossible to list all the domains handled by a nameserver. But apparently, there exists a couple of websites on the Internet that are able to list all the domains registered in a namerserver. For example: http://www.gwebtools.com/ns-spy/udns1.ultradns.net Or all domains pointing to a specific IP : http://www.robtex.com/ip/190.7.200.92.html (These DNS/IP were picked at random) Do you know how it's done ?

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