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  • Sort months ( with strings ) algorithm

    - by Oscar Reyes
    I have this months array: ["January", "March", "December" , "October" ] And I want to have it sorted like this: ["January", "March", "October", "December" ] I'm currently thinking in a "if/else" horrible cascade but I wonder if there is some other way to do this. The bad part is that I need to do this only with "string" ( that is, without using Date object or anything like that ) What would be a good approach?

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  • Simple PERL Problem

    - by Suezy
    I have an array of numbers: @numbers = 1,2,3,6,8,9,11,12,13,14,15,20 and I want to print it this way: 1-3,6,8-9,11-15,20 Any thoughts? Of course I tried using the most common "looping", but still didn't get it.

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  • Flip Vertices Array

    - by James
    Hi, I have an array of position vertices that make up a 2D polygon. Vector2[] _chassisConcaveVertices = { new Vector2(5.122f, 0.572f), new Vector2(3.518f, 0.572f), new Vector2(3.458f, 0.169f), new Vector2(2.553f, 0.169f), new Vector2(2.013f, 0.414f), new Vector2(0.992f, 0.769f), new Vector2(0.992f, 1.363f), new Vector2(5.122f, 1.363f), }; What algorithm can I use to modify the positions so the resultant polygon is flipped? I need to flip the polygon both horizontally and vertically.

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  • [Perl] Retrieve the reference

    - by Sebastian
    Hello, with the hash below, I would like the clients array's reference : my $this = { 'name' => $name, 'max_clients' => $max_clients, 'clients' => () }; I can't do "\$this{'clients'};" to retrieve the reference.

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  • Counting comma seperated values in php,how to?

    - by Jay
    Hey folks, I have a variable holding values separated by a comma (Implode), I'm trying to get the total count of the values in that variable however, count() is just returning 1. I've tried converting the comma separated values to a properly formatted array which still spits out1. So heres the quick snippet where the sarray session equals to value1,value2,value3: $schools = $_SESSION['sarray']; $result = count($schools); Any help would be appreciated.

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  • Is this the correct way to build a Perl hash that utilizes arrays?

    - by Structure
    This is the first time I have manipulated hashes and arrays in this way -- and it is working. Basically, for every key there are multiple values that I want to record and then print out in the form "key -- value -- value -- val..." My code is as follows. I am surprised that it works, so concerned that it works "by mistake". Is this the correct way to accomplish this task, or is there a more efficient or appropriate method? while ($source =~ m/(regex)/g) { #Get all key names from source $listkey = $1; #Set current list key to the current regex result. $list{$listkey} = ++$i unless $list{$listkey}; #Add the key to the hash unless it already exists. $list{$listkey} = [] unless exists $list{$listkey}; #Add an array for the hash unless the hash already exists. while ($loopcount==0) { if ($ifcount==0) { $listvalue=result_of_some_function_using_list_key; #Get the first list value from the list key. $ifcount++; #Increment so we only get the first list value once. } else { $listvalue=result_of_some_function_using_list_value; #Update the last list value. } if ($listvalue) { #If the function returned a value... push @{$list{$listkey}}, $listvalue; #...then add the value to the hash array for the key. } else { #There are no more values and we need a new key. $listkey=0; #Reset variable. $domain=0; #Reset variable. $loopcount++; #Increment loop counter to exit loop. } } $ifcount=0; #Reset count variable so the next listvalue can be generated from the new key. $loopcount=0; #Reset count variable so another loop can begin for a new key. } foreach $listkey (keys %list) { #For each key in the hash. print "$listkey --> "; #Print the key. @values = @{$list{$listkey}}; #Reference the arrays of the hash. print join ' --> ', @values; #Print the values. print "\n"; #Print new line. }

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  • Counting number of values between interval

    - by calccrypto
    Is there any efficient way in python to count the times an array of numbers is between certain intervals? the number of intervals i will be using may get quite large like: mylist = [4,4,1,18,2,15,6,14,2,16,2,17,12,3,12,4,15,5,17] some function(mylist, startpoints): # startpoints = [0,10,20] count values in range [0,9] count values in range [10-19] output = [9,10]

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  • how does array_diff work?

    - by SpawnCxy
    I just wonder how array_diff() works.And obviously it couldn't work as follows function array_diff($arraya, $arrayb) { $diffs = array(); foreach ($arraya as $keya => $valuea) { foreach ($arrayb as $valueb) { if ($valuea == $valueb) { break; } $diffs[$keya]=$valuea; } } return $diffs; } //couldn't be worse than this Hope someone can show me some better solution. Thanks.

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  • What is the best way to store anciliary data with a 2D timeseries object in R?

    - by Mike52
    I currently try to move from matlab to R. I have 2D measurements, consisting of irradiance in time and wavelength together with quality flags and uncertainty and error estimates. In Matlab I extended the timeseries object to store both the wavelength array and the auxiliary data. What is the best way in R to store this data? Ideally I would like this data to be stored together such that e.g. window(...) keeps all data synchronized.

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  • Why does my code dividing a 2D array into chunks fail?

    - by Borog
    I have a 2D-Array representing my world. I want to divide this huge thing into smaller chunks to make collision detection easier. I have a Chunk class that consists only of another 2D Array with a specific width and height and I want to iterate through the world, create new Chunks and add them to a list (or maybe a Map with Coordinates as the key; we'll see about that). world = new World(8192, 1024); Integer[][] chunkArray; for(int a = 0; a < map.getHeight() / Chunk.chunkHeight; a++) { for(int b = 0; b < map.getWidth() / Chunk.chunkWidth; b++) { Chunk chunk = new Chunk(); chunkArray = new Integer[Chunk.chunkWidth][Chunk.chunkHeight]; for(int x = Chunk.chunkHeight*a; x < Chunk.chunkHeight*(a+1); x++) { for(int y = Chunk.chunkWidth*b; y < Chunk.chunkWidth*(b+1); y++) { // Yes, the tileMap actually is [height][width] I'll have // to fix that somewhere down the line -.- chunkArray[y][x] = map.getTileMap()[x*a][y*b]; // TODO:Attach to chunk } } chunkList.add(chunk); } } System.out.println(chunkList.size()); The two outer loops get a new chunk in a specific row and column. I do that by dividing the overall size of the map by the chunkSize. The inner loops then fill a new chunkArray and attach it to the chunk. But somehow my maths is broken here. Let's assume the chunkHeight = chunkWidth = 64. For the first Array I want to start at [0][0] and go until [63][63]. For the next I want to start at [64][64] and go until [127][127] and so on. But I get an out of bounds exception and can't figure out why. Any help appreciated! Actually I think I know where the problem lies: chunkArray[y][x] can't work, because y goes from 0-63 just in the first iteration. Afterwards it goes from 64-127, so sure it is out of bounds. Still no nice solution though :/ EDIT: if(y < Chunk.chunkWidth && x < Chunk.chunkHeight) chunkArray[y][x] = map.getTileMap()[y][x]; This works for the first iteration... now I need to get the commonly accepted formula.

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  • Are there specific benefits to using XNA for 2D development if you don't plan on releasing on xbox/windows phone?

    - by ssb
    I've been using XNA for a while to tinker with 2D game development, but I can't help but feel constrained by the content pipeline when targeting PC only. Things like no vector fonts or direct use of graphics files make it a pain while other frameworks do these things with no problem. I like XNA because it's robust and has a lot of support, but what are the specific benefits that I'd get developing exclusively for PC, if there are any at all?

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  • How many views can be bound to a 2D texture at a time?

    - by Recker
    I am a newbie trying to learn on DX11.x. While reading about resources and views in MSDN, I thought this question For a given 2D Texture created with ID3D11Texture2Dinterface (or for that matter any kind of resource), how many of following views can be bound to it? 1) DepthStencilView 2) RenderTargetView 3) ShaderResourceView 4) UnorderedAccessView Thanks in advance. PS: I know the answer would be app specific, but still any insight into this would be helpful.

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  • Unity 4.5 est disponible et apporte le support d'OpenGL ES 3, un rendu plus naturel de la physique 2D et des optimisations

    Unity 4.5 est disponible : les corrections et améliorations du moteur sont très nombreuses OpenGL ES 3.0, amélioration de la physique 2D, chargement de scène amélioré, amélioration du flux de travail sur les shaders... Alors que dernièrement nous avons découvert ce que Unity 5 sera, l'équipe de développement nous apporte la version 4.5 du moteur. Celle-ci corrige près de 450 bogues mais apporte aussi de nouvelles fonctionnalités au moteur : support d'OpenGL ES 3.0 pour iOS (à partir des périphérique...

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