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  • jQuery ajax response not operating correctly

    - by mmarceau
    Ok this is frustrating... The code below works "correctly" as far as sending the email address to the SaveEmail URL and it gets saved correctly each time I change the drop down. However it only outputs the "Successful" message once, no matter how many times I change the value in the drop down. The "data" that is returned is "Successful". I would like to show the message for a couple seconds, then fade it out. It works correctly the first time I change the drop down, after that the change happens and the value gets saved, but the "Successful" message doesn't display. jQuery code: $('#AgentEmails').change(function() { var NewAddress = $('#AgentEmails').val(); $.post('SaveEmail.aspx', { email: NewAddress }, function(data) { $('#SelectMsg').html("<b>" + data + "</b>").fadeOut(); }); }); HTML code: <select ID='AgentEmails' runat='server'> <option value="[email protected]">TEST</option> </select><span id='SelectMsg'></span> What needs to be changed in my code to make this operate correctly? Thanks for the help.

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  • Stop then restart submit() after ajax check

    - by jeerose
    I asked a question [here] recently and it's just not providing me with an answer. Here's what I want to do and you can see my first attempt at the link above: User submits form Stop default submit action check to see if a similar entry exists in database If it does, display a notice asking them if they want to submit anyway and give an option to let them submit anyway (enable default action and submit it). If it does not, enable the default action on the form and let it submit I'm at a loss. Any help is appreciated. Thanks gang.

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  • Pass data via ajax to dialog Jquery

    - by user342391
    I am trying to post data from my form to a jquery dialog that loads external content. I am serializing the form data which works (appears in the url) but the dialog won't open: $("#wavajax button").click(function() { $.post({url: 'player/index.php', data: $("#wavajax").serialize(), success: function (data) { $("#recordingdialog").load("player/index.php", [], function(){ $("#recordingdialog").dialog("open"); } }); return false; }); What am I doing wrong, am I going about it the right way???

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  • jquery: How to deal with 'this' in ajax callbacks

    - by Svish
    I currently have code similar to this for a form: $('#some-form') .submit(function() { // Make sure we are not already busy if($(this).data('busy')) return false; $(this).data('busy', true); // Do post $.post("some/url", $(this).serialize(), function(data) { if(data.success) // Success is a boolean I set in the result on the server { // Deal with data } else { // Display error } $('#some-form') .removeData('busy'); }); return false; }); My issue is that I would like to somehow remove the need for knowing the form id in the post callback. In the end where I remove the busy data from the form, I'd like to somehow not have that hard coded. Is there any way I can do this? Is there a way I can hand whatever is in this to the post callback function? Since I know the id right now, I can get around it by doing what I have done, but I'd like to know how to not be dependant on knowing the id, since often I don't have an id. (For example if I have a link in each row in a table and all the rows have the same click handler.

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  • ajax security ?

    - by Tony
    When I look back my codes that written earlier time, I found something terribly bad. Whenever I want to delete a record in the database, I did like this : $.post("deleteAction.do",{recordId:10}); I cannot prevent a malicious user visit my database operation url directly : deleteAction.do?recordId=10 What's the solution for this kind of problem ?

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  • how to submit using link with my current code(php+jquery+ajax)

    - by ruslyrossi
    My current Code : <script type="text/javascript"> $(document).ready(function() { $('#form').ajaxForm( { target: '#preview', success: function() { $('#success_box').addClass('success') setTimeout(function() { $('#success_box').fadeOut('slow'); }, 3100); // <-- time in milliseconds } }); }); </script> <form action="controller/product_edit_update.php" method="post" id="form" name="form" > bla..bla.. <input type="submit" value="Save" /></form> but now i want to add submit link with <a href="" id="submit_with_link" >Save</a>

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  • A brief question about JS or AJAX

    - by Luke
    I have been finding ways around this for a long time but think it's time I addressed it. If I have a page that has a dropdown menu, is there anyway I can select a value which will subsequently load other values further down. Can this be done without a page reload? I will give you an example. Say I was making some tools for an admin panel, but first of all they needed to select a member to work with. They would select the member and then below, the fields about that member would be populated based on what was selected in the first menu. As I have already asked, can this be done without a page reload? Thanks for reading.

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  • Mapping restful ajax requests to spring

    - by Diones
    I have this piece of code: @RequestMapping(value = "/test.json", method = RequestMethod.GET) @ResponseStatus(HttpStatus.OK) public @ResponseBody Object[] generateFile(@RequestParam String tipo) { Object[] variaveis = Variavel.getListVariavelByTipo(tipo); return variaveis; } As far as I know it should take a request to test.json?tipo=H and return the JSON representation of Variavel[], however when I make such request I get: HTTP Status 406 - type Status report message descriptionThe resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers () By using the following function I can get the expected json: @RequestMapping(value = "/teste.json") public void testeJson(Model model, @RequestParam String tipo) { model.addAttribute("data", Variavel.getListVariavelByTipo("H")); } What I'm doing wrong?

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  • call a Javascript function from controller more than once (in Rails)

    - by mm1
    hi. I have a multiple file upload form(html5) and want to update my view as soon one of the images is transfered to my image server. Currently I upload the files with ajax and use response_to_parent to update my upload view when all images are transfered to the image server. Is it possible to call a Javascript function from the controller more than once per action? def upload params[:images].each do |file| upload_to_image_server(file) #page << Update upload View end end Thanks, Michael

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  • posting array of text fields using jquery and ajax

    - by tabia
    i dont want to use serialize() function please help me with this. I am a beginner html <input type='button' value='Add Tier Flavor' id='Add'> <input type='button' value='Remove Tier Flavor' id='Remove'> <div id='batch'> <div id="BatchDiv1"> <h4>Batch #1 :</h4> <label>Flavor<input class="textbox" type='text' id="fl1" name="fl[]" value=""/></label></br> <label>Filling<input class="textbox" type='text' id="fi1" name="fi[]" value="" /></label></br> <label>Frosting<input class="textbox" type='text' id="fr1" name="fr[]" value=""/></label></br> </div> </div> <br> </div> this is a dynamically added fields using javascript the code is: javascript <script src="http://code.jquery.com/jquery-1.10.1.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ var counter = 2; $("#Add").click(function () { if(counter>5){ alert("Only 5 Tiers allow"); return false; } var newBatchBoxDiv = $(document.createElement('div')).attr("id", 'BatchDiv' + counter); newBatchBoxDiv.html('<h4>Batch #'+ counter + ' : </h4>' + '<label> Flavor<input type="text" name="fl[]" id="fl' + counter + '" value=""></label><br>'+ '<label> Filling<input type="text" name="fi[]" id="fi' + counter + '" value=""></label><br>'+ '<label> Frosting<input type="text" name="fr[]" id="fr' + counter + '" value=""></label><br>' ); newBatchBoxDiv.appendTo("#batch"); counter++; }); $("#Remove").click(function () { if(counter==1){ alert("No more tier to remove"); return false; } counter--; $("#BatchDiv" + counter).remove(); }); }); </script> i am trying to post the values in an array to post it onto next .php page i am using this var user_cupfl = $('input[name^="fl"]').serialize(); var user_cupfi = $('input[name^="fi"]').serialize(); var user_cupfr = $('input[name^="fr"]').serialize(); serialize is not passing the values. :( on second page i am trying to mail it using $message .= "<tr><td><strong>Cake Flavors(according to batches):</strong> </td><td><pre>" .implode("\n", $user_cupfl). "</pre></td></tr>"; $message .= "<tr><td><strong>Filling type (Inside the cake):</strong> </td><td><pre>" .implode("\n", $user_cupfi). "</pre></td></tr>"; $message .= "<tr><td><strong>Frosting type (top of the cake):</strong> </td><td><pre>" .implode("\n", $user_cupfr). "</pre></td></tr>"; i m posting array like this $user_cupfl=filter_var($_POST["userCupfl"], FILTER_SANITIZE_STRING); $user_cupfi=filter_var($_POST["userCupfi"], FILTER_SANITIZE_STRING); $user_cupfr=filter_var($_POST["userCupfr"], FILTER_SANITIZE_STRING); your replies will be highly appreciated

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  • How to get final destination URL from AJAX?

    - by Maurice Lam
    When I do an XMLHttpRequest, I always get redirected automatically to the URL (presumably by the headers of the response). For example, if I query "http://www.stackoverflow.com" I will be redirected to "http://stackoverflow.com". How can I get that final URL? (http://stackoverflow.com/ in the example) I checked in the response headers but I cannot seem to find it. (I just used the GET/POST method not HEAD).

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  • ajax + freewebhostingarea body tag replacement

    - by mandnd
    im using freewebhostingarea and he searches for the body tag and add a banner the problem is im using ipb shoutbox (3.0.x) and everytime there a tbody tag he keeps putting that banner so the shoutbox is full of banners heres the code http://pastebin.com/d4KZJqu9

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  • jquery/ajax load new content when available

    - by Tim
    I know this is quite a vague question -- sorry about that. If I have a forum, shoutbox or something similar where users enter and submit data, running on PHP and MySQL, what is the best way to have the newly submitted content automatically display on the page for all users when it is submitted? Much like a live newsfeed, if you like... The effect sort-of works here at stackoverflow, when you are answering a question you are told when new answer is submitted. I want to test for newly submitted content and then display it automatically. Any suggestions? Many thanks :)

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  • cakephp droplist/form - xml and ajax

    - by gudinne
    Hello- I'm complete noob in Cakephp - here goes... I have a website set up with Cakephp framework. I have been tasked with creating two dropdown forms to compare/show data. When the user selects an item from the dropdown from either one of the forms it is to show the content below on website. I was thinking this data would need to be stored in an xml file. How do I create and sync two dropdown forms with xml data within Cakephp? The page the form is on is the view(.ctp) file. Thanks

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  • Replacing one image with another image through ajax makes it dissappear for a split second

    - by ooo
    I have the following code (asp.net-mvc, jquery) (i have simplified the example to show the issue) where i want to click on an image and have it replaced with another image. This works fine but the first time i click it, the original image disappears (for a split second) before the other image shows up. After that it works seamlessly. Is there any way to eliminate this quirk so there is not split second where no image is shown? Here is my controller code: public ActionResult UpdateFavoriteExercise(int id, string toggle) { if (toggle == "off") { return Content("<img toggle='off' src='/images/vote-favorite-off1.png' border=0'>"); } return Content("<img toggle='on' src='/images/vote-favorite-on1.png' border=0'>"); } Here is my jquery code: $('div.favoriteExercise').live('click', function() { var id = $(this).attr("id"); var toggle = $(this).attr("toggle"); if (toggle == 'off') { onOff = 'on'; } else { onOff = 'off'; } var url = '/Tracker/UpdateFavoriteExercise/' + id + '?toggle=' + onOff; $(this).load(url); $(this).attr("toggle", onOff); });

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  • Get error with ajax get in jquery to an extern url

    - by user1394983
    I have a big problem. I want get information with an webservice in one URL. But I'mm getting this error: XMLHttpRequest cannot load ht*p://external_url_that_i_trid_to_get. Origin ht*p://localhost:8888 is not allowed by Access-Control-Allow-Origin. Im using this: $.get(url_parsed,date_get,function(data) { if (data.result == 'sucess') { alert(data.data["title"]); } },"json"); How I can resolve this? Regards

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  • jquery.ajax returns content-type "html" on iis while it returns content-type "json" on local host

    - by Sridhar
    Hi, I am using jQuery.ajax function to make an ajax call to a page method in asp.net. I specifically set the content-type to "application/json; charset=utf-8". When I looked at the response in the firebug it says the content-type is html. Following is the code to my ajax call $.ajax({ async: asyncVal, type: "POST", url: url + '/' + webMethod, data: dataPackage, contentType: "application/json; charset=UTF-8", dataType: "json", error: errorFunction, success: successFunction });

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  • Update (ajax) only part of table without affecting whole table

    - by ile
    <table width="100%" border="0" cellspacing="0" cellpadding="0" class="list"> <tr> <th><a href="#" class="sortby">Full Name</a></th> <th><a href="#" class="sortby">City</a></th> <th><a href="#" class="sortby">Country</a></th> <th><a href="#" class="sortby">Status</a></th> <th><a href="#" class="sortby">Education</a></th> <th><a href="#" class="sortby">Tasks</a></th> </tr> <div class="dynamicData"> <tr> <td>Firstname Lastname</a></td> <td>Los Angeles</td> <td>USA</td> <td>Married</td> <td>High School</td> <td>4</td> </tr> </tr> <tr> <td>Firstname Lastname</a></td> <td>Los Angeles</td> <td>USA</td> <td>Married</td> <td>High School</td> <td>4</td> </tr> </div> </table> The idea is to update table rows when clicking on link with clasl "sortby" which is part of th table tag. I tried inserting div but this doesn't work. Separating this in two tables is not good solution because witdh in both tables cell are not following each other. Any other solution? Thanks

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  • AJAX Div Retrieval every 60 seconds

    - by Sam
    Hello everyone! What I would like to do is retrieve the contents of a PHP file and insert it into a div every 60 seconds, basically refreshing the dynamic div. I've come up with the following code so far, however it doesn't seem to be working. The code is just like this, nothing extra, apart from the MYSQL login. PHP to grab: <?php $time = date("m/d/Y h:i:s a", time()); mysql_query("UPDATE djs SET requesttime='{$time}' WHERE username='{$djs['username']}'") or die(mysql_error()); $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); echo "<table style=\"border:1px solid;width:99%;margin-left:auto;margin-right:auto;\" border=\"1\">"; echo "<tr><th>Title</th><th>Artist</th><th>Dedicated To...</th></tr>"; while($request = mysql_fetch_array( $request_db )) { echo "<tr><td style=\"width:33%;padding:1px;\">"; echo $request['SongName']; echo "</td><td style=\"width:33%;\">"; echo $request['Artist']; echo "</td><td style=\"width:33%;\">"; echo $request['DedicatedTo']; echo "</td></tr>"; } echo "</table>"; ?> The original PHP code is just the same, enclosed in a div with an id attribute of 'ajax_table'. The JavaScript is: // JavaScript Document var xmlHttp_moniter function moniter() { xmlHttp_moniter = GetXmlHttpObject_parcel() if(xmlHttp_moniter == null) { alert("browser does not support HTTP Request") return } var url="ajax_table.php?random=" + Math.random() xmlHttp_moniter.onreadystatechange = stateChanged xmlHttp_moniter.open("GET",url,true) xmlHttp_moniter.send(null) } function stateChanged() { if(xmlHttp_moniter.readyState==4 || xmlHttp_moniter.readyState == "complete") { document.getElementById("ajax_table").innerHTML = xmlHttp_moniter.responseText setTimeout('ajax_table()',60000); } } function GetXmlHttpObject_parcel() { var xmlHttp_moniter=null; try { xmlHttp_moniter=new XMLHttpRequest(); } catch (e) { //Internet Explorer try { xmlHttp_moniter=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xmlHttp_moniter=new ActiveXObject("Microsoft.XMLHTTP"); } } return xmlHttp_moniter; } and that is on the page that is requesting the other php page.

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  • Respond_with not working Rails 3

    - by MDM
    As no one can help me with my UJS ajax problem I am trying "respond_with", but I am getting this error: RuntimeError (In order to use respond_with, first you need to declare the formats your controller responds to in the class level) Yet I have declared it in my controller: class HomepagesController < ApplicationController respond_to :html, :xml, :js def index @homepages = Homepage.search(params[:search]) respond_with(@homepages) end Anyone has any ideas why.

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  • Confused on the basics of AJAX

    - by Doug
    So right now, I'm just using a basic form to check a password. I want it to check the password and basically remain on page.html so I can use JavaScript to alert incorrect password or something. I'm not really sure how to do that. It seems it would bring me to check.php. I'm not too sure on the whole process, any help appreciated! Thanks! Page.html <form action="check.php" method="post"> <input type="password" name="password" /> <input type="submit" value="Submit" /> </form> check.php <?php $password = $_POST['password']; if ( $password != "testing" ) { die(); } ?>

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