Search Results

Search found 21888 results on 876 pages for 'django rest framework'.

Page 136/876 | < Previous Page | 132 133 134 135 136 137 138 139 140 141 142 143  | Next Page >

  • Zend Framework - Database Table Singleton

    - by Sonny
    I have found myself doing this in my code to 'cache' the work done when instantiating my Zend_Db_Table models: if (Zend_Registry::isRegistered('x_table')) { $x_table = Zend_Registry::get('x_table'); } else { $x_table = new Default_Model_DbTable_X; Zend_Registry::set('x_table', $x_table); } It bothered me that this method isn't very DRY and it dawned on me today that a singleton pattern would probably be a better way to do this. Problem is, I've never written a singleton class. When I did some web searches, I found some offhand comments about Zend_Db_Table singletons, but no real examples. I already have meta-data caching configured. How do I make my Zend_Db_Table models singletons? Are there pitfalls or downsides?

    Read the article

  • Dataflow in Controllers & Layouts in Zend Framework

    - by favo
    I use a basic setup which uses a layout.phtml for the HTML Layout and view scripts for the content part. I want to control some variables in the layout in my controllers, i.e. the title of my site. How can I access my layout to output variables from within the controller? Thanks for your feedback!

    Read the article

  • entity framework vNext wish list

    - by Fred Yang
    I have been intensively studying and use ef4 in my project. I do feel the improvement that it has over version 1. But I found that I have something I cannot get around easily. Here is a list I want it to be better in ef vNext. the model designer should allow multiple view of the same model, so that I don't need cram all my entity into a single view. respect user's manual edit of edmx. Currently, the some database view object simply can not be imported to the model because the designer "smartly" think that the view does not have a primary key, so that I have to manually edit the edmx to correct designer's behavior. But in the next "update from database" task, designer will revert my customization. For now, I simply fallback to manually edit the edmx file at all, or I have to use compare tool to keep the new update, and rollback and put the new update into my old edmx file manually. Designer should be improved to allow default behavior and user's manual control. I want control not to let the designer refresh the change of imported object. support user defined table function. linq is about Composability, stored proc dos not support composability. I wish I could use user defined table function which support this. What are you wishes for EF vNext?

    Read the article

  • Zend Framework Custom Validation Class Error Message

    - by remlabm
    The validation fails as it should but does not return the error message. $form->addElement('text', 'phone_number', array( 'required' => true, 'validators' => array( array('NotEmpty', true, array('messages' => 'Enter a valid Phone Number')), array('regex', false, array('pattern' => '/\([0-9]{3}\)\s[0-9]{3}-[0-9]{4}/', 'messages' => 'Enter a valid Phone Number' )), 'CheckPhoneNumber'), ), )); Custom Class: class Custom_Validators_CheckPhoneNumber extends Zend_Validate_Abstract{ const IN_USE = 'inUse'; protected $_messageTemplates = array( self::IN_USE => "'%value%' is currently in use" ); public function isValid($value) { $this->_setValue($value); $user_check = Users::getActive(preg_replace("/[^0-9]/", "", $value)); if($user_check->id){ $this->_error(self::IN_USE); return false; } return true; } } Just fails does not give the "IN_USE" error.

    Read the article

  • Writing a custom auth system (like the default django auth system), use it to generate tables in DB

    - by dotty
    Hay all, I've been reading up on middleware and how to use it with a context object. I want to write a simple middleware class which i can use on my own applications, it will essentially be a cut down version of the django one. The problem i seem to have is that if i have INSTALLED_APPS = ('django.contrib.my_auth') in the settings file, all is well. I've also added MIDDLEWARE_CLASSES = ('django.contrib.my_auth.middleware.MyAuthMiddleware') in it and everything is fine. My question is, how would i make my middleware automatically generate tables from a models.py module, much like how the django auth does when i run manage.py syncdb? thanks

    Read the article

  • Self Authenticating Links in Django

    - by awolf
    In my web app I would like to be able to email self-authenticating links to users. These links will contain a unique token (uuid). When they click the link the token being present in the query string will be enough to authenticate them and they won't have to enter their username and password. What's the best way to do this?

    Read the article

  • Entity Framework 4 Self Many-To-Many with Properties

    - by csharpnoob
    UPDATE: Solved by myself. Tricky but works. If you know a better solution, feel free to correct me. DESIGNER: CODE: Product product1 = new Product{key = "Product 1"}; sd.AddToProducts(product1); Product product2 = new Product{key = "Product 2"}; sd.AddToProducts(product2); Product product3 = new Product{key = "Product 3"}; ProductRelated pr = new ProductRelated(); pr.Products.Add(product1); pr.Products.Add(product2); product3.ProductRelateds.Add(pr); sd.AddToProducts(product3); CODE VIEW: foreach(var x in (from b in sd.Products select b)) { %><%=x.key %><br /> <% foreach (var y in x.ProductRelateds) { foreach (var k in y.Products) { %>- <%=k.key%><br /><%} } } OUTPUT Product1 Product2 Product3 - Product2 - Product1 QUESTION: Hi, i want to have a Self Reference for Releated Products on a Product Entity, something like here: http://my.safaribooksonline.com/9781430227038/modeling_a_many-to-many_comma_self-refer But i also want on the Many-To-Many Reference addional Properties like deleted, created etc. I tried to do it by another Entity "Related", but somehow it won't work. Does anyone had this Problem before? Is there any other Example? Thanks

    Read the article

  • How to implement table-per-concrete-type strategy using entity framework

    - by SDReyes
    Hello Guys! I'm mapping a set of tables that share a common set of fields: So as you can see I'm using a table-per-concrete-type strategy to map the inheritance. But... I have not could to relate them to an abstract type containing these common properties. It's possible to do it using EF? BONUS: The only non documented Entity Data Model Mapping Scenario is Table-per-concrete-type inheritance http://msdn.microsoft.com/en-us/library/cc716779.aspx : P

    Read the article

  • Zend Framework decorator subform add a class tag to DD wrapper tag

    - by Samuele
    I have this form: class Request_Form_Prova extends Zend_Form { public function init() { $this->setMethod('post'); $SubForm_Step = new Zend_Form_SubForm(); $SubForm_Step->setAttrib('class','Step'); $this->addSubform($SubForm_Step, 'Chicco'); $PrivacyCheck = $SubForm_Step->createElement('CheckBox', 'PrivacyCheck'); $PrivacyCheck->setLabel('I have read and I agre bla bla...') ->setRequired(true) ->setUncheckedValue(''); $PrivacyCheck->getDecorator('Label')->setOption('class', 'inline'); $SubForm_Step->addElement($PrivacyCheck); $SubForm_Step->addElement('submit', 'submit', array( 'ignore' => true, 'label' => 'OK', )); } } That generate this HTML: <form enctype="application/x-www-form-urlencoded" method="post" action=""> <dl class="zend_form"> <dt id="Chicco-label">&nbsp;</dt> <dd id="Chicco-element"> <fieldset id="fieldset-Chicco" class="Step"> <dl> <dt id="Chicco-PrivacyCheck-label"><label for="Chicco-PrivacyCheck" class="inline required">I have read and I agre bla bla...</label></dt> <dd id="Chicco-PrivacyCheck-element"> <input type="hidden" name="Chicco[PrivacyCheck]" value=""><input type="checkbox" name="Chicco[PrivacyCheck]" id="Chicco-PrivacyCheck" value="1"> </dd> <dt id="submit-label">&nbsp;</dt> <dd id="submit-element"> <input type="submit" name="Chicco[submit]" id="Chicco-submit" value="OK"> </dd> </dl> </fieldset> </dd> </dl> </form> How can I add a class="Test" to the <dd id="Chicco-element"> elemnt? In order to have it like that: <dd id="Chicco-element" class="Test"> I thought something like that but it don't work: $SubForm_Step->getDecorator('DdWrapper')->setOption('class', 'Test'); OR $SubForm_Step->getDecorator('DtDdWrapper')->setOption('class', 'Test'); How can I do it? And last question: How can I wrap that DD and DT element of a SubForm in another DL element? Like that: ( second line ) <dl class="zend_form"> <dl> <dt id="Chicco-label">&nbsp;</dt> <dd id="Chicco-element"> <fieldset id="fieldset-Chicco" class="Step"> <dl> .......

    Read the article

  • ahow can I resolve Django Error: str' object has no attribute 'autoescape'?

    - by Angelbit
    Hi have tried to create a inclusion tag on Django but don't work and return str' object has no attribute 'autoescape' this is the code of custom tag: from django import template from quotes.models import Quotes register = template.Library() def show_quote(): quote = Quotes.objects.values('quote', 'author').get(id=0) return {'quote': quote['quote']} register.inclusion_tag('quotes.html')(show_quote) EDIT: Quote class from django.db import models class Quotes(models.Model): quote = models.CharField(max_length=255) author = models.CharField(max_length=100) class Meta: db_table = 'quotes' quotes.html <blockquote id="quotes">{{ quote }}</blockquote>

    Read the article

  • Django query filter a set of data

    - by dana
    if a have a query like following = Relations.objects.filter(initiated_by = request.user) in which i'm having all the users followed by the currently logged in user, and i want to display those user's blog posts. Using a query like: blog = New.objects.filter(created_by = following) it only shows me the blog posts of the user with the id = 1 (though the currently logged in user doesn't actually follow him) in template i have : {% for object in blog %} <a href='/accounts/profile_view/{{object.created_by}}/'> {{object.created_by}}</a> <br /> {{object.post}}<br /> {% endfor %} Where am i wrong?

    Read the article

  • change the who of google calendar event with gdata framework

    - by bouth69
    $gdataCal= new Zend_gdata_calendar($client); //on retrouve l'event a partir de eventURL stocké lors de la création $event = $gdataCal->getCalendarEventEntry($id_event); $who= $gdataCal->newWho();// $who objet de type Zend_Gdata_Extension_Who //les nouvelles valeurs du who $email ="cn21lqqt8jeb9qgulpra6bj948%40group.calendar.google.com"; $rel = 'http://schemas.google.com/g/2005#event.organizer' ; $valueString ='alain developpeur'; $who->setEmail($email); $who->setRel($rel); $who->setValueString($valueString); //$who->setDom($who_old[0]->getDOM());//bizarre mais??? //méthode magic ou setteurs //$event->who= array($who); $event->setWho($who); //on affiche les propriétés du nouveau who pour voir les changements echo'<br >lemail est : '.$who->getEmail(); echo'<br >la value string est : '.$who->getValueString(); echo'<br >la rel est : '.$who->getRel(); //on sauve on spécifie le type de classe dans lequel on veut sauver // $event->save(Zend_Gdata_EventEntry);??? $event->save(Zend_Gdata_App_Entry); thank you for yours answers.

    Read the article

  • PHP Framework / Library Suggestions for a Backend

    - by frbry
    I am about to start to developing backend site of a php project. Companies and site admins will login to this site and manage their data on the project. My previous admin panel experiences were full of agony and pain. So I want to make sure that I choose correct tools for my purpose. By the way, please note, I'm not looking for scaffolding. There won't be much tables in my database. Instead, there will be complex logic between entities. I want clear seperation of markup and logic code and easy-to-use and standardized user-interface. Thank you.

    Read the article

  • Entity Framework 4 code-only reference column name

    - by Victor
    I created classes: public class Country { public long CountryId {get;set;} public string CountryName {get;set;} } public class Profile { public long ProfileId {get;set;} public string ProfileName {get;set;} public Country Country {get;set;} } and configuration for Profile: public class ProfileConfiguration : EntityConfiguration<Profile> { public IlluminatiCoreProfileConfiguration() { Relation(p => p.Country); } } Then I create context and run context.CreateDatabase(). New database contains table Profiles with column Country_CountryId. How can I write configuration for changing column name to "CountryId"? Thanks.

    Read the article

  • django getting current user id

    - by dana
    hello, i have a mini app where users can login, view their profile, and follow each other. 'Follow' is a relation like a regular 'friend' relationship in virtual communities, but it is not necessarily reciprocal, meaning that one can follow a user, without the need that the user to be following back that person who follows him. my problem is: if i am a logged in user, and i navigate to a profile X, and push the button follow, how can i take the current profile id ?(current profile meaning the profile that I, the logged in user, am viewing right now.) the view: def follow(request): if request.method == 'POST': form = FollowForm(request.POST) if form.is_valid(): new_obj = form.save(commit=False) new_obj.initiated_by = request.user u = User.objects. what here? new_obj.follow = u new_obj.save() return HttpResponseRedirect('.') else: form = FollowForm() return render_to_response('followme/follow.html', { 'form': form, }, context_instance=RequestContext(request)) thanks in advance!

    Read the article

  • htpasswd, secure specific files in zend framework

    - by AKFourSeven
    Hi I have been bashing my head against the wall with this riddle and cannot find the way to solve this. I would like to secure couple of files to restrict access to certain pages but my attempts so far are unsuccessful. I do not want to use Zend Auth as it is a very small web site doing simple stuff. Here is a sample of what I have done: AuthUserFile /path/to/my/.htpasswd AuthName "Admin Restriction" AuthType Basic <Files file.phtml> require valid-user </Files> Is there any way to achieve this ?

    Read the article

  • navigation framework in silverlight 3 skipping constructor when usercontrol is of a derived type

    - by tarren
    Hi: I am using the NavigationFramework in Silverlight 3, and am running into issues where the constructor of the UserControl in the xaml I am loading is not being called, and I believe this is because the UserControl in the xaml I am calling is actually derived from another user control. I have stepped through the debugger with specific break points and the constructor is being ignored completey. I have MyWindowBlue which is of type uctrlBaseMyWindow. The constructor for uctrlBaseMyWindow is being called when the xaml is 'navigated to' but the constructor for MyWindowBlue is being ignored. This is not the case if I add the user control via markup directly. Anyone else have this issue? The code I am using to navigate to the MyWindowBlue is this.MyContentFrame.Navigate(new Uri("/Controls/uctrlMyWindowBlue.xaml", UriKind.Relative)); Has anyone run into this or could offer any help? Thanks

    Read the article

  • how to delete findDependentRowset result in Zend Framework

    - by Behrang
    I have place model & entry model that entry is parent everything is fine but how can I delete the result row $categoryPlacements in place model: $entryModel = new Model_EntryModel(); $entryRow = $entryModel-find ( $entryId )-current (); $categoryPlacements = $entryRow-findDependentRowset($this); in this case i want to delete the $categoryPlacements result in place model I can use categoryPlacements-toarray() and then delete but is another easy way?

    Read the article

  • Google App Engine django model form does not pick up BlobProperty

    - by Wes
    I have the following model: class Image(db.Model): auction = db.ReferenceProperty(Auction) image = db.BlobProperty() thumb = db.BlobProperty() caption = db.StringProperty() item_to_tag = db.StringProperty() And the following form: class ImageForm(djangoforms.ModelForm): class Meta: model = Image When I call ImageForm(), only the non-Blob fields are created, like this: <tr><th><label for="id_auction">Auction:</label></th><td><select name="auction" id="id_auction"> <option value="" selected="selected">---------</option> <option value="ahRoYXJ0bWFuYXVjdGlvbmVlcmluZ3INCxIHQXVjdGlvbhgKDA">2010-06-19 11:00:00</option> </select></td></tr> <tr><th><label for="id_caption">Caption:</label></th><td><input type="text" name="caption" id="id_caption" /></td></tr> <tr><th><label for="id_item_to_tag">Item to tag:</label></th><td><input type="text" name="item_to_tag" id="id_item_to_tag" /></td></tr> I want the Blob fields to be included in the form as well (as file inputs). What am I doing wrong?

    Read the article

  • Django | how to append form field to the urlconf

    - by MMRUser
    I want to pass a form's field value to the next page (template) after user submit the page, the field could be user name, consider the following setup def form_submit(request): if request.method == 'POST': form = UsersForm(request.POST) if form.is_valid(): cd = form.cleaned_data try: newUser = form.save() return HttpResponseRedirect('/mysite/nextpage/') except Exception, ex: return HttpResponse("Ane apoi %s" % str(ex)) else: return HttpResponse('Error') "nextpage" is the template that renders after user submit the form, so I want to know how to append the form's field (user name) to the url and get that value from the view in order to pass it to the next page.. thanks.

    Read the article

< Previous Page | 132 133 134 135 136 137 138 139 140 141 142 143  | Next Page >