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  • sorting a list of objects by value php

    - by Mike
    I have a list of objects: class Beer { var $name; var $id; var $style; var $brewery; var $rate; function getName() { return $this->name; } function getID() { return $this->id; } function getStyle() { return $this->style; } function getBrewery() { return $this->brewery; } function getRate() { return $this->rate; } } After doing some research online on how to accomplish this, this is my code: usort($localBeersList, "cmp"); function cmp($a, $b) { if ($a->getRate() == $b->getRate()) { return 0; } return ($a->getRate() < $b->getRate()) ? -1 : 1; } If I try and output my list after this I do not get anything.

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  • Java threads not working correctly with linkedlist

    - by user69514
    Hi I am working on the sleeping barber problem. with the addition of having priority customer when they arrive they go in the front of the line and they are the next ones to get a haircut. I'm using a linkedlist and if I see a priority customer I put him in the beginning of the list, if the customer is not priority he goes to the end of the list. then I call the wantHaircut method getting the first element of the list. my problem is that the customer are being processed in the order they arrive, and the priority customer have to wait. here is the code where it all happens. any ideas what I am doing wrong? thanks public void arrivedBarbershop(Customer c){ if(waiting < numChairs && c.isPriority()){ System.out.println("Customer " + c.getID() + ": is a priority customer - SITTING -"); mutex.up(); customer_list.addFirst(c); } else if(waiting >= numChairs && c.isPriority()){ System.out.println("Customer " + c.getID() + ": is a priority customer - STANDING -"); mutex.up(); customer_list.addFirst(c); } else if(waiting < numChairs && !c.isPriority()){ waiting++; System.out.println("Customer " + c.getID() + ": arrived, sitting in the waiting room"); customer_list.addLast(c); customers.up(); // increment waiting customers } else if(waiting >= numChairs && !c.isPriority()) { System.out.println("Customer " + c.getID() + ": went to another barber because waiting room was full - " + waiting + " waiting"); mutex.up(); } if(!customer_list.isEmpty()){ this.wantHairCut(customer_list.removeFirst()); } } public void wantHairCut(Customer c) { mutex.up(); barber.down(); // waits for being allowed in barber chair System.out.println("Customer " + c.getID() + ": getting haircut"); try { /** haircut takes between 1 and 2 seconds **/ Thread.sleep(Barbershop.randomInt(1, 2) * 1000); } catch (InterruptedException e) { } System.out.println("Barber: finished cutting customer " + c.getID() + "'s hair"); c.gotHaircut = true; cutting.up(); // signals cutting has finished /** customer must pay now **/ this.wantToCashout(c); }

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  • Swapping two jQuery draggable list items not working properly (with jsFiddle example)

    - by Tony_Henrich
    The minimalist working example below swaps the two boxes when box 'one' is dragged and dropped on box 'two'. The problem is that when box 'one' is dropped, its style has 'top' & 'left' values causing it to be placed away from where it should drop. Its class includes 'ui-draggable-dragging'. It seems the top & left values are related to the amount the elements were dragged before the drop. And the dragging was 'interrupted' hence the residual 'ui-draggable-dragging' class? What am I missing to make the swap work seamlessly? full jsfiddle example here <html> <head> <script type="text/javascript" src="includes/jquery-1.4.2.min.js"></script> <script type="text/javascript" src="includes/jquery-ui-1.8.2.custom.min.js"></script> <script type="text/javascript"> jQuery.fn.swapWith = function(to) { return this.each(function() { var copy_to = $(to).clone(true); var copy_from = $(this).clone(true); $(to).replaceWith(copy_from); $(this).replaceWith(copy_to); }); }; $(document).ready(function() { options = {revert: true}; $("li").draggable(options) $('#wrapper').droppable({ drop: function(event, ui) { $(ui.draggable).swapWith($('#two')); } }); }); </script> </head> <body> <form> <ul id="wrapper"> <li id='one'> <div style="width: 100px; height: 100px; border: 1px solid green"> one<br /></div> </li> <li id='two'> <div style="width: 110px; height: 110px; border: 1px solid red"> two<br /></div> </li> </ul> <br /> </form> </body> </html>

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  • Python 3.1 - Memory Error during sampling of a large list

    - by jimy
    The input list can be more than 1 million numbers. When I run the following code with smaller 'repeats', its fine; def sample(x): length = 1000000 new_array = random.sample((list(x)),length) return (new_array) def repeat_sample(x): i = 0 repeats = 100 list_of_samples = [] for i in range(repeats): list_of_samples.append(sample(x)) return(list_of_samples) repeat_sample(large_array) However, using high repeats such as the 100 above, results in MemoryError. Traceback is as follows; Traceback (most recent call last): File "C:\Python31\rnd.py", line 221, in <module> STORED_REPEAT_SAMPLE = repeat_sample(STORED_ARRAY) File "C:\Python31\rnd.py", line 129, in repeat_sample list_of_samples.append(sample(x)) File "C:\Python31\rnd.py", line 121, in sample new_array = random.sample((list(x)),length) File "C:\Python31\lib\random.py", line 309, in sample result = [None] * k MemoryError I am assuming I'm running out of memory. I do not know how to get around this problem. Thank you for your time!

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  • List of drugs to parse in application

    - by Skoder
    Hey, Not sure if that has been asked before, but semantics causes difficulty in searching. Are there any sites which have a list of items for developers to use in applications? For example, you can download Dictionaries in specific formats (e.g. XML) for use in word games. In particular, I was hoping that there might be a list of common medical drugs so that I can use display a list in an application I'm working on as researching and typing 150+ drug names would be quite inefficient. Thanks

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  • Search row with highest number of cells in a row with colspan

    - by user593029
    What is the efficient way to search highest number of cells in big table with numerous colspan (merge cells ** colspan should be ignored so in below example highest number of cells is 4 in first row). Is it js/jquery with reg expression or just the loop with bubble sorting. I got one link as below explainig use of regex is it ideal way ... can someone suggest pseudo code for this. High cpu consumption due to a jquery regex patch <table width="156" height="84" border="0" > <tbody> <tr style="height:10px"> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px"/> </tr> <tr style="height:10px"> <td width="10" style="width:10px; height:10px" colspan="2"/> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px"/> </tr> <tr style="height:10px"> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px" colspan="2"/> </tr> <tr style="height:10px"> <td width="10" style="width:10px; height:10px" colspan="2"/> <td width="10" style="width:10px; height:10px"/> <td width="10" style="width:10px; height:10px"/> </tr> </tbody> </table>

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  • Jquery getting list of values of hidden inputs within a div

    - by RandyMarsh
    I am trying to get a list of values within a div that I will format later using the .each() method. They are input values which are hidden my html and jquery call looks like this. <div id="container_0"> <input type="hidden" id="check_data" value=10> <input type="hidden" id="check_data" value=20> </div> Jquery: var list = $('#container_0 input#check_data'); $(list).each( function() { alert($(this).val()); } ); This however is not returning any values. Any help would be greatly appreciated.

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  • iPhone programming guideline : List / detail / modify

    - by Oliver
    Hello, I have a program that displays a list (a TableView). When the user clicks an item, it's detail is shown. On the detail view, the user can ask to modify it so a modify window is shown. Here, the user can ask to delete the item. I would like at this time return to the list with the item deleted from the list and from the data source. There may be thousands of methods to do this, but I wonder which is the best / good one. Could you help me, and/or give me a good reference to read about this ? Thank you.

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  • emacs list-buffers behavior

    - by Stephen
    In GNU emacs, every time I hit Ctrl-x Ctrl-b to see all of my buffers, the window is split to show the buffer list, or if I have my window already split in 2 (for instance, I will have a shell running in the lower window), the buffer list appears in the other window. My desired behavior is for the buffer list to appear in my active window so that I can select the buffer I want and continue to working in the same window, rather than having to Ctrl-x Ctrl-o to the other buffer, selecting the buffer (with enter) and editing that buffer in the other window... I've googled for it but it doesn't seem to be a common desire? I wonder if anyone has an elispy (or other) solution?

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  • python - from matrix to dictionary in single line

    - by Sanich
    matrix is a list of lists. I've to return a dictionary of the form {i:(l1[i],l2[i],...,lm[i])} Where the key i is matched with a tuple the i'th elements from each list. Say matrix=[[1,2,3,4],[9,8,7,6],[4,8,2,6]] so the line: >>> dict([(i,tuple(matrix[k][i] for k in xrange(len(matrix)))) for i in xrange(len(matrix[0]))]) does the job pretty well and outputs: {0: (1, 9, 4), 1: (2, 8, 8), 2: (3, 7, 2), 3: (4, 6, 6)} but fails if the matrix is empty: matrix=[]. The output should be: {} How can i deal with this?

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  • Selecting an item in an HTML SELECT list using keyboard doesnt trigger the CLICK event

    - by Jimbo
    I have an HTML select list which, when an item is selected, must show different information beneath it. The onclick or JQuery change events are triggered when a select list item is selected by being clicked on (mouse), but not when the user uses key presses (keyboard). Any idea what event to watch in order to determine when the selected list item has changed? Here is a BASIC test example: <select id="mylist" name="mylist"> <option value="">(none)</option> <option value="1">Test 1</option> <option value="2">Test 2</option> <option value="3">Test 3</option> </select> <span id="myspan"></span> <script type="text/javascript"> $("#mylist").change(function() { $("#myspan").html($("#mylist").attr("selectedIndex")); }); </script>

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  • Removing Redundant Data from a List<T>

    - by Mark
    I have a List of objects which are ordered. I would like to remove redundant objects where redundant does not necessarily mean duplicate. Here is an example: List<Point> points = new List<Point> { new Point(0, 10), new Point(1, 12), new Point(2, 16), new Point(3, 16), new Point(4, 16), new Point(5, 13), new Point(6, 16), }; I am interested in removing the new Point(3, 16) entry because it doesn't provide useful information; I already know that the element at 2=16 and the element at 4=16. The information that 3=16 doesn't do me any good in my application (because I already have the bounds {2,4}=16), so I would like to remove that entry. I'd also like to not that I want to keep the 5th and 6th entry because there are not consecutive entries where Y=16. Is there a slick way to do this with linq?

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  • Why does VerticalScrollBarVisibility not work in a style in Silverlight?

    - by Edward Tanguay
    VerticalScrollBarVisibility works when I define it inline like this: <UserControl x:Class="TestScrollBar.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <UserControl.Resources> <Style TargetType="TextBox" x:Key="EditListContainerContentMultiLineTwoColumn"> <Setter Property="AcceptsReturn" Value="True"/> <Setter Property="Width" Value="400"/> <Setter Property="Height" Value="300"/> <Setter Property="IsReadOnly" Value="False"/> <Setter Property="Margin" Value="0 0 0 20"/> <Setter Property="HorizontalAlignment" Value="Left"/> <Setter Property="TextWrapping" Value="Wrap" /> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White" Margin="10"> <StackPanel HorizontalAlignment="Left"> <TextBox Text="this is a test" Style="{StaticResource EditListContainerContentMultiLineTwoColumn}" VerticalScrollBarVisibility="Auto" /> </StackPanel> </Grid> </UserControl> But when I put VerticalScrollBarVisibility in a style, it shows me a blank screen: <UserControl x:Class="TestScrollBar.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <UserControl.Resources> <Style TargetType="TextBox" x:Key="EditListContainerContentMultiLineTwoColumn"> <Setter Property="VerticalScrollBarVisibility" Value="Auto"/> <Setter Property="AcceptsReturn" Value="True"/> <Setter Property="Width" Value="400"/> <Setter Property="Height" Value="300"/> <Setter Property="IsReadOnly" Value="False"/> <Setter Property="Margin" Value="0 0 0 20"/> <Setter Property="HorizontalAlignment" Value="Left"/> <Setter Property="TextWrapping" Value="Wrap" /> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White" Margin="10"> <StackPanel HorizontalAlignment="Left"> <TextBox Text="this is a test" Style="{StaticResource EditListContainerContentMultiLineTwoColumn}" /> </StackPanel> </Grid> </UserControl> In WPF it works works fine. How can I get VerticalScrollBarVisibility to work in a style?

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  • Is it possible to match with decomposed sequences in F#?

    - by Ball
    I seem to remember an older version of F# allowing structural decomposition when matching sequences just like lists. Is there a way to use the list syntax while keeping the sequence lazy? I'm hoping to avoid a lot of calls to Seq.head and Seq.skip 1. I'm hoping for something like: let decomposable (xs:seq<'a>) = match xs with | h :: t -> true | _ -> false seq{ 1..100 } |> decomposable But this only handles lists and gives a type error when using sequences. When using List.of_seq, it seems to evaluate all the elements in the sequence, even if it is infinite.

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  • error string list handle in C#

    - by Chelsea_cole
    Same namespace: 2 forms. public class Account //frm1 { public string Username; public string Password; } public class ListAcc { public static List<Account> UserList; } private void button1_Click(object sender, EventArgs e) { List<Account> UserList = new List<Account>(); Account acc = new Account(); acc.Username = textBox1.Text; acc.Password = textBox2.Text; UserList.Add(acc); } private void button2_Click(object sender, EventArgs e) //frm2 { string p = frmDangky.ListAcc.UserList[0].Username; // null ->error string p = frmDangky.ListAcc.UserList[0].Password; // null ->error } Someone help me? :( why my string is NULL???????? The textBox is not empty... Thanks!

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  • Groovy: Sorting Columns in a view: list

    - by Luixv
    I have a Groovy application. I am rendering the view list using the following statement: render (view: 'list', model:[reportingInstanceList: reportingInstanceList, reportingInstanceTotal: i, params: params]) The list.gsp is as follows: The view is rendered but the default sorting is not working. <g:sortableColumn class="tabtitle" property="id" title="Id" titleKey="reporting.id" /> <g:sortableColumn class="tabtitle" property="company" title="Company" titleKey="reporting.company" /> Unfortunately the default sorting (by id, by company, etc) are not working. Any hint why? Thanks a lot in advance. Luis

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  • Multiple (variant) arguments overloading in Java: What's the purpose?

    - by fortran
    Browsing google's guava collect library code, I've found the following: // Casting to any type is safe because the list will never hold any elements. @SuppressWarnings("unchecked") public static <E> ImmutableList<E> of() { return (ImmutableList<E>) EmptyImmutableList.INSTANCE; } public static <E> ImmutableList<E> of(E element) { return new SingletonImmutableList<E>(element); } public static <E> ImmutableList<E> of(E e1, E e2) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2)); } public static <E> ImmutableList<E> of(E e1, E e2, E e3) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3)); } public static <E> ImmutableList<E> of(E e1, E e2, E e3, E e4) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3, e4)); } public static <E> ImmutableList<E> of(E e1, E e2, E e3, E e4, E e5) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3, e4, e5)); } public static <E> ImmutableList<E> of(E e1, E e2, E e3, E e4, E e5, E e6) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3, e4, e5, e6)); } public static <E> ImmutableList<E> of( E e1, E e2, E e3, E e4, E e5, E e6, E e7) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3, e4, e5, e6, e7)); } public static <E> ImmutableList<E> of( E e1, E e2, E e3, E e4, E e5, E e6, E e7, E e8) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3, e4, e5, e6, e7, e8)); } public static <E> ImmutableList<E> of( E e1, E e2, E e3, E e4, E e5, E e6, E e7, E e8, E e9) { return new RegularImmutableList<E>( ImmutableList.<E>nullCheckedList(e1, e2, e3, e4, e5, e6, e7, e8, e9)); } public static <E> ImmutableList<E> of( E e1, E e2, E e3, E e4, E e5, E e6, E e7, E e8, E e9, E e10) { return new RegularImmutableList<E>(ImmutableList.<E>nullCheckedList( e1, e2, e3, e4, e5, e6, e7, e8, e9, e10)); } public static <E> ImmutableList<E> of( E e1, E e2, E e3, E e4, E e5, E e6, E e7, E e8, E e9, E e10, E e11) { return new RegularImmutableList<E>(ImmutableList.<E>nullCheckedList( e1, e2, e3, e4, e5, e6, e7, e8, e9, e10, e11)); } public static <E> ImmutableList<E> of( E e1, E e2, E e3, E e4, E e5, E e6, E e7, E e8, E e9, E e10, E e11, E e12, E... others) { final int paramCount = 12; Object[] array = new Object[paramCount + others.length]; arrayCopy(array, 0, e1, e2, e3, e4, e5, e6, e7, e8, e9, e10, e11, e12); arrayCopy(array, paramCount, others); return new RegularImmutableList<E>(ImmutableList.<E>nullCheckedList(array)); } And although it seems reasonable to have overloads for empty and single arguments (as they are going to use special instances), I cannot see the reason behind having all the others, when just the last one (with two fixed arguments plus the variable argument instead the dozen) seems to be enough. As I'm writing, one explanation that pops into my head is that the API pre-dates Java 1.5; and although the signatures would be source-level compatible, the binary interface would differ. Isn't it?

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  • Can my tortoise vs. hare race be improved?

    - by FredOverflow
    Here is my code for detecting cycles in a linked list: do { hare = hare.next(); if (hare == back) return; hare = hare.next(); if (hare == back) return; tortoise = tortoise.next(); } while (tortoise != hare); throw new AssertionError("cyclic linkage"); Is there a way to get rid of the code duplication inside the loop? Am I right in assuming that I don't need a check after making the tortoise take a step forward? As I see it, the tortoise can never reach the end of the list before the hare (contrary to the fable). Any other ways to simplify/beautify this code?

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  • removing the single quote from a list of

    - by tanky
    I need to append/format a url with a list of ids for an api call however, when i put the list at the end of the api https://api.twitter.com/1.1/users/lookup.json?user_id=%s'%a i just get an empty string as a response. i have tried turning the list into a string and removing the square brackets doing a = str(followers['ids'])[1:-1] but i still get the same problem. and im assuming that its being caused by the single quote at the start. i have tried removing the apostrophe from the string doing a.replace("'", "") and now i have run out of ideas thanks

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  • KnockoutJS showing a sorted list by item category

    - by Darksbane
    I just started learning knockout this week and everything has gone well except for this one issue. I have a list of items that I sort multiple ways but one of the ways I want to sort needs to have a different display than the standard list. As an example lets say I have this code var BetterListModel = function () { var self = this; food = [ { "name":"Apple", "quantity":"3", "category":"Fruit", "cost":"$1", },{ "name":"Ice Cream", "quantity":"1", "category":"Dairy", "cost":"$6", },{ "name":"Pear", "quantity":"2", "category":"Fruit", "cost":"$2", },{ "name":"Beef", "quantity":"1", "category":"Meat", "cost":"$3", },{ "name":"Milk", "quantity":"5", "category":"Dairy", "cost":"$4", }]; self.allItems = ko.observableArray(food); // Initial items // Initial sort self.sortMe = ko.observable("name"); ko.utils.compareItems = function (l, r) { if (self.sortMe() =="cost"){ return l.cost > r.cost ? 1 : -1 } else if (self.sortMe() =="category"){ return l.category > r.category ? 1 : -1 } else if (self.sortMe() =="quantity"){ return l.quantity > r.quantity ? 1 : -1 }else { return l.name > r.name ? 1 : -1 } }; }; ko.applyBindings(new BetterListModel()); and the HTML <p>Your values:</p> <ul class="deckContents" data-bind="foreach:allItems().sort(ko.utils.compareItems)"> <li><div style="width:100%"><div class="left" style="width:30px" data-bind="text:quantity"></div><div class="left fixedWidth" data-bind="text:name"></div> <div class="left fixedWidth" data-bind="text:cost"></div> <div class="left fixedWidth" data-bind="text:category"></div><div style="clear:both"></div></div></li> </ul> <select data-bind="value:sortMe"> <option selected="selected" value="name">Name</option> <option value="cost">Cost</option> <option value="category">Category</option> <option value="quantity">Quantity</option> </select> </div> So I can sort these just fine by any field I might sort them by name and it will display something like this 3 Apple $1 Fruit 1 Beef $3 Meat 1 Ice Cream $6 Dairy 5 Milk $4 Dairy 2 Pear $2 Fruit Here is a fiddle of what I have so far http://jsfiddle.net/Darksbane/X7KvB/ This display is fine for all the sorts except the category sort. What I want is when I sort them by category to display it like this Fruit 3 Apple $1 Fruit 2 Pear $2 Fruit Meat 1 Beef $3 Meat Dairy 1 Ice Cream $6 Dairy 5 Milk $4 Dairy Does anyone have any idea how I might be able to display this so differently for that one sort?

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  • Relationships via Email Rather Than User List

    - by Bob Lerner
    I'm new at Drupal, so I may have missed a solution despite a lot of research: I want users to be able to invite non-users and other users into a named relationship they've set up (using e.g. the Friendlist or User Relationships module) using only email addresses and not the user list. I believe that invitations from both of those modules are done only after the inviter selects the invitee after selecting the invitee from a list of all users. Frankly, I would be surprised if no email solution exists since a large site's user list would be daunting. Does anyone know if this is possible using Organic Groups? Thanks very much.

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  • converting result set to list

    - by akshay
    how can i conver result set to list? i am using following code but its not working properly private List<User> convertToList(ResultSet rs) { List<User> userList = new ArrayList(); User user = new User(); try { while (rs.next()) { user.setId(rs.getInt("id")); user.setUsername(rs.getString("username")); user.setFname(rs.getString("fname")); user.setLname(rs.getString("lname")); user.setUsertype(rs.getInt("usertype")); user.setPasswd(rs.getString("passwd")); user.setEmail(rs.getString("email")); userList.add(user); } } catch (SQLException ex) { Logger.getLogger(UserDAO.class.getName()).log(Level.SEVERE, null, ex); } finally { closeConnection(); } return userList; }

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  • How can I use STL sort in c++ to sort some values in the class?

    - by Morteza M.
    I have a class named Graph, in this class I have a member named V, it is a vector. I have a struct named Edge, and a list of Edges. like below: struct Edge{ int u; int v; Edge(int u,int v){ this-u=u; this-v=v; } }; class Graph{ vector < Vertex > V; . . . int edgeCmp(Edge* x,Edge* y){ return (V[x-v].dv].d)?1:0; } void someFunction(){ list backEdges; backEdges.sort(&Graph::edgeCmp); } } But it doesn't work!! may someone help me to do such a thing?

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  • How do I change the list using mutable lists in Racket or Scheme?

    - by exOne
    I need your help Can anyone help me? first question This procedure should modify each element which’s index in the list is even. The value of the element should be equal to the new-element. For example: (define number-list (1 56 8 1 43 9 78)) (modify-even-indices number-list 10) The new list: 1 10 8 10 43 10 78 second question This problem is the extended version of Question 1. (modify-even-odd-indices my-list new-element modification-type) This procedure should modify each element according to the modification-type. The modification-type can be even or odd. For example: (define number-list (1 56 8 1 43 9 78)) (modify-even-odd-indices number-list 10 ‘even’) The new list: 1 10 8 10 43 10 78 (modify-even-odd-indices number-list 10 ‘odd’) The new list: 10 56 10 1 10 9 10

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  • CSS3: Top align of list item

    - by Irishgirl
    CSS3: Top align of list item. See image as below. How can I align a blue arrow to align on top of a senetence of each list. I'm using jQuery 1.7 and it is for iOS (iPhone). ul.lists{ padding:0 0 15px 0;} ul.lists li{ line-height:18px; border-bottom:1px #bfeaf0 solid; padding:6px 12px; background:url(../images/arrow_cyan.svg) no-repeat left; } /* no-repeat left top; */ I've tried to include a js as offset $("li:last").offset({ top: -15 }); but it did not work properly because I don't know how to move all blue arrows to align each list even the sentence might might run into more than one line.

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