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  • C# property exactly the same, defined in two places

    - by Sarah Vessels
    I have the following classes: Defect - represents a type of data that can be found in a database FilterQuery - provides a way of querying the database by setting simple Boolean filters Both Defect and FilterQuery implement the same interface: IDefectProperties. This interface specifies particular fields that are in the database. Different classes have methods that return lists of Defect instances. With FilterQuery, you specify some filters for the particular properties implemented as part of IDefectProperties, and then you run the query and get back a list of Defect instances. My problem is that I end up implementing some properties exactly the same in FilterQuery and Defect. The two are inherently different classes, they just share some of the same properties. For example: public DateTime SubmitDateAsDate { get { return DateTime.Parse(SubmitDate); } set { SubmitDate = value.ToString(); } } This is a property required by IDefectProperties that depends on a different property, SubmitDate, which returns a string instead of a DateTime. Now SubmitDate is implemented differently in Defect and FilterQuery, but SubmitDateAsDate is exactly the same. Is there a way that I can define SubmitDateAsDate in only place, but both Defect and FilterQuery provide it as a property? FilterQuery and Defect already inherit from two different classes, and it wouldn't make sense for them to share an ancestor anyway, I think. I am open to suggestions as to my design here as well.

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  • C++ Recursive function that reverses the order of an array's indexes between two bounds

    - by CPT Kirk
    I am trying to write a recursive function that has three arguments; an array and two array indexes. The function should reverse the order of the values between the two indexes. I would like to understand what is happening instead of just being told an answer. Here is my code so far: #include <iostream> using namespace std; char switchAroo(char a[], int b1, int b2); int main() { char a[6] {'A', 'B', 'C', 'D', 'E', '\0'}; cout << a; switchAroo(a, 2, 5); return 0; } char switchAroo(char a [], int b1, int b2) { char temp; if (b1 == b2) cout << "The array after switchAroo is " << a << endl; else { temp = a[b1]; a[b1] = a[b2]; a[b2] = temp; b1++; b2--; return switchAroo(a, b1, b2); } } I am getting the following warning code: warning C4715: 'switchAroo' : not all control paths return a value Any help would be greatly appreciated.

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  • Bind two images together to be dragged

    - by Ryan Beaulieu
    I'm looking for some help with a script to drag two images together at once. I currently have a script that allows me to drag thumbnail images into a collection bin to be saved later. However, some of my thumbnails have an image positioned over the top of them to represent these thumbnail images as "unknown" plants. I was wondering if someone could point me in the right direction as to how I would go about binding these two images together to be dragged. Here is my code: $(document).ready(function() { var limit = 16; var counter = 0; $("#mainBin1, #mainBin2, #mainBin3, #mainBin4, #mainBin5, #bin_One_Hd, #bin_Two_Hd, #bin_Three_Hd, #bin_Four_Hd, #bin_Five_Hd").droppable({ accept: ".selector, .plant_Unknown", drop: function(event, ui) { counter++; if (counter == limit) { $(this).droppable("disable"); } $(this).append($(ui.draggable).clone()); $("#cbOptions").show(); $(".item").draggable({ containment: "parent", grid: [72,72], }); } }); $(".selector").draggable({ helper: "clone", revert: "invalid", revertDuration: 700, opacity: 0.75, }); $(".plant_Unknown").draggable({ helper: "clone", revert: "invalid", revertDuration: 700, opacity: 0.75, }); }); Any help would be greatly appreciated. Thanks. EDIT: Website

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  • initalizing two pointers to same value in "for" loop

    - by MCP
    I'm working with a linked list and am trying to initalize two pointers equal to the "first"/"head" pointer. I'm trying to do this cleanly in a "for" loop. The point of all this being so that I can run two pointers through the linked list, one right behind the other (so that I can modify as needed)... Something like: //listHead = main pointer to the linked list for (blockT *front, *back = listHead; front != NULL; front = front->next) //...// back = back->next; The idea being I can increment front early so that it's one ahead, doing the work, and not incrementing "back" until the bottom of the code block in case I need to backup in order to modify the linked list... Regardless as to the "why" of this, in addition to the above I've tried: for (blockT *front = *back = listHead; /.../ for (blockT *front = listHead, blockT *back = listHead; /.../ I would like to avoid pointer to a pointer. Do I just need to initialize these before the loop? As always, thanks!

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  • two view controllers and reusability with delegate

    - by netcharmer
    Newbie question about design patterns in objC. I'm writing a functionality for my iphone app which I plan to use in other apps too. The functionality is written over two classes - Viewcontroller1 and Viewcontroller2. Viewcontroller1 is the root view of a navigation controller and it can push Viewcontroller2. Rest of the app will use only ViewController1 and will never access Viewcontroller2 directly. However, triggered by user events, Viewcontroller2 has to send a message to the rest of the app. My question is what is the best way of achieving it? Currently, I use two level of delegation to send the message out from Viewcontroller2. First send it to Viewcontroller1 and then let Viewcontroller1 send it to rest of the app or the application delegate. So my code looks like - //Viewcontroller1.h @protocol bellDelegate -(int)bellRang:(int)size; @end @interface Viewcontroller1 : UITableViewController <dummydelegate> { id <bellDelegate> delegate; @end //Viewcontroller1.m @implementation Viewcontroller1 -(void)viewDidLoad { //some stuff here Viewcontroller2 *vc2 = [[Viewcontroller2 alloc] init]; vc2.delegate = self; [self.navigationController pushViewController:vc2 animated:YES]; } -(int)dummyBell:(int)size { return([self.delegate bellRang:size]); } //Viewcontroller2.h @protocol dummyDelegate -(int)dummyBell:(int)size; @end @interface Viewcontroller2 : UITableViewController { id <dummyDelegate> delegate; @end //Viewcontroller2.m @implementation Viewcontroller2 -(int)eventFoo:(int)size { rval = [self.delegate dummyBell:size]; } @end

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  • Syncing objects between two devices with different system times

    - by Mike Weller
    Hi there. I'm syncing objects between two devices. Objects have a lastModified property. If both devices have modified an object, then during the next sync the version of the object with the most recent lastModified is chosen on both devices. So we don't do fine-grained merging, only 'most recent version' merging. The problem is this. When one device receives a list of changed objects it can't reliably compare the lastModified of received objects to its own because the system times on the two devices may be different. I considered having each device send its current date/time during the sync. Then each calculates the difference between the remote time and the local time to compare the dates properly. But if there is lag between sending a date and the remote device receiving it, this causes incorrect comparisons with objects that were modified at the same time (or very close together in time). i.e. both devices think the remote object is newer and they end up with different objects. I hope I have explained this clearly enough. There must be a common solution to this kind of problem but my brain isn't coming up with anything. Any suggestions? Thanks in advance...

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  • Why is the operation address incremented by two?

    - by Gavin Jones
    I am looking at a Javascript emulator of a NES to try and understand how it works. On this line: addr = this.load(opaddr+2); The opcode is incremented by two. However, the documentation (see appendix E) I'm reading says: Zero page addressing uses a single operand which serves as a pointer to an address in zero page ($0000-$00FF) where the data to be operated on can be found. By using zero page addressing, only one byte is needed for the operand, so the instruction is shorter and, therefore, faster to execute than with addressing modes which take two operands. An example of a zero page instruction is AND $12. So if the operand's argument is only one byte, shouldn't it appear directly after it, and be + 1 instead of + 2? Why +2? This is how I think it works, which may be incorrect. Suppose our memory looks like: ------------------------- | 0 | 1 | 2 | 3 | 4 | 5 | <- index ------------------------- | a | b | c | d | e | f | <- memory ------------------------- ^ \ PC and our PC is 0, pointing to a. For this cycle, we say that the opcode: var pc= 0; //for example's sake var opcode= memory[pc]; //a So shouldn't the first operand be the next slot, i.e. b? var first_operand = memory[pc + 1]; //b

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  • Union of two or more (hash)maps

    - by javierfp
    I have two Maps that contain the same type of Objects: Map<String, TaskJSO> a = new HashMap<String, TaskJSO>(); Map<String, TaskJSO> b = new HashMap<String, TaskJSO>(); public class TaskJSO { String id; } The map keys are the "id" properties. a.put(taskJSO.getId(), taskJSO); I want to obtain a list with: all values in "Map b" + all values in "Map a" that are not in "Map b". What is the fastest way of doing this operation? Thanks EDIT: The comparaison is done by id. So, two TaskJSOs are considered as equal if they have the same id (equals method is overrided). My intention is to know which is the fastest way of doing this operation from a performance point of view. For instance, is there any difference if I do the "comparaison" in a map (as suggested by Peter): Map<String, TaskJSO> ab = new HashMap<String, TaskJSO>(a); ab.putAll(b); ab.values() or if instead I use a set (as suggested by Nishant): Set s = new Hashset(); s.addAll(a.values()); s.addAll(b.values());

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  • find the difference between two very large list

    - by user157195
    I have two large list(could be a hundred million items), the source of each list can be either from a database table or a flat file. both lists are of comparable sizes, both unsorted. I need to find the difference between them. so I have 3 scenarios: 1. List1 is a database table(assume each row simply have one item(key) that is a string), List2 is a large file. 2. Both lists are from 2 db tables. 3. both lists are from two files. in case 2, I plan to use: select a.item from MyTable a where a.item not in (select b.item form MyTable b) this clearly is inefficient, is there a better way? Another approach is: I plan to sort each list, and then walk down both of them to find the diff. If the list is from a file, I have to read it into a db table first, then use db sorting to output the list. Is the run time complexity still O(nlogn) in db sorting? either approach is a pain and seems would be very slow when the list involved has hundreds of millions of items. any suggestions?

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  • Android text layout question: two textviews, side-by-side, with different layout alignments and weights

    - by thx1200
    I'm still a bit of an Android noob, forgive me if this is simple and I'm just not seeing it. There are two portions of text in a view that spans the entire width horizontally, but is only as high as one line of text. The left side must always be displayed in full, but should take no more horizontal space than it needs. The right side should be pushed over by the left side and fill up the remainder of the screen width. If the right side text is smaller than this width, the text should be right-aligned horizontally. If the text is greater than the width, it should scroll horizontally. The text on the right side will be updated frequently and should slide up with new text when the app tells it (explaining the TextSwitcher in the layout). I have tried two different layout styles. In both situations, I can get the left side to "push" the layout, the right side to scroll, but I can't figure out how to get the right side to right align. It is always left aligned. Here is a picture showing what is happening... http://img10.imageshack.us/img10/5599/androidlayout.png In addition (but less important), in my layout code I have android:fadingEdge="none" on the TextViews, but it still has a faded edge on the left and right side when it scrolls. Why is that? Here are the two layouts I created, which yield the results shown, but not the results I want. Using a horizontal LinearLayout... <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/LinearLayoutStatusBar" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2px" android:background="#555555" > <TextView android:id="@+id/TextViewTimer" android:textSize="18px" android:textColor="#FFFFFF" android:layout_gravity="left" android:layout_weight="0" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="0px" android:layout_marginRight="3px" android:text="Left Side" > </TextView> <TextSwitcher android:id="@+id/TextSwitcherDetails" android:inAnimation="@anim/push_up_in" android:outAnimation="@anim/push_up_out" android:layout_weight="1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="right" android:layout_marginLeft="3px" android:layout_marginRight="0px" > <TextView android:id="@+id/TextViewDetails1" android:textSize="18px" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:text="Right Side 1" > </TextView> <TextView android:id="@+id/TextViewDetails2" android:textSize="18px" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:text="Right Side 2 - This is a really long text this is long and fun and fun and long" > </TextView> </TextSwitcher> </LinearLayout> And the RelativeLayout style... <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/LinearLayoutStatusBar" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2px" android:background="#555555" > <TextView android:id="@+id/TextViewTimer" android:textSize="18px" android:textColor="#FFFFFF" android:layout_gravity="left" android:layout_weight="0" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="0px" android:layout_marginRight="3px" android:layout_alignParentLeft="true" android:text="Left Side" > </TextView> <TextSwitcher android:id="@+id/TextSwitcherDetails" android:inAnimation="@anim/push_up_in" android:outAnimation="@anim/push_up_out" android:layout_weight="1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="3px" android:layout_marginRight="0px" android:layout_toRightOf="@+id/TextViewTimer" android:layout_alignParentRight="true" android:fadingEdge="none" android:fadingEdgeLength="0px" > <TextView android:id="@+id/TextViewDetails1" android:textSize="18px" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:fadingEdgeLength="0px" android:text="Right Side 1" > </TextView> <TextView android:id="@+id/TextViewDetails2" android:textSize="18px" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:fadingEdgeLength="0px" android:text="Right Side 2 - This is a really long text this is long and fun and fun and long" > </TextView> </TextSwitcher> </RelativeLayout> So how do I get that text on the right side to right-align. Thanks!

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  • Finding all the shortest paths between two nodes in unweighted directed graphs using BFS algorithm

    - by andra-isan
    Hi All, I am working on a problem that I need to find all the shortest path between two nodes in a given directed unweighted graph. I have used BFS algorithm to do the job, but unfortunately I can only print one shortest path not all of them, for example if they are 4 paths having lenght 3, my algorithm only prints the first one but I would like it to print all the four shortest paths. I was wondering in the following code, how should I change it so that all the shortest paths between two nodes could be printed out? class graphNode{ public: int id; string name; bool status; double weight;}; map<int, map<int,graphNode>* > graph; int Graph::BFS(graphNode &v, graphNode &w){ queue <int> q; map <int, int> map1; // this is to check if the node has been visited or not. std::string str= ""; map<int,int> inQ; // just to check that we do not insert the same iterm twice in the queue map <int, map<int, graphNode>* >::iterator pos; pos = graph.find(v.id); if(pos == graph.end()) { cout << v.id << " does not exists in the graph " <<endl; return 1; } int parents[graph.size()+1]; // this vector keeps track of the parents for the node parents[v.id] = -1; // there is a direct path between these two words, simply print that path as the shortest path if (findDirectEdge(v.id,w.id) == 1 ){ cout << " Shortest Path: " << v.id << " -> " << w.id << endl; return 1; } //if else{ int gn; map <int, map<int, graphNode>* >::iterator pos; q.push(v.id); inQ.insert(make_pair(v.id, v.id)); while (!q.empty()){ gn = q.front(); q.pop(); map<int, int>::iterator it; cout << " Popping: " << gn <<endl; map1.insert(make_pair(gn,gn)); //backtracing to print all the nodes if gn is the same as our target node such as w.id if (gn == w.id){ int current = w.id; cout << current << " - > "; while (current!=v.id){ current = parents[current]; cout << current << " -> "; } cout <<endl; } if ((pos = graph.find(gn)) == graph.end()) { cout << " pos is empty " <<endl; continue; } map<int, graphNode>* pn = pos->second; map<int, graphNode>::iterator p = pn->begin(); while(p != pn->end()) { map<int, int>::iterator it; //map1 keeps track of the visited nodes it = map1.find(p->first); graphNode gn1= p->second; if (it== map1.end()) { map<int, int>::iterator it1; //if the node already exits in the inQ, we do not insert it twice it1 = inQ.find(p->first); if (it1== inQ.end()){ parents[p->first] = gn; cout << " inserting " << p->first << " into the queue " <<endl; q.push(p->first); // add it to the queue } //if } //if p++; } //while } //while } I do appreciate all your great help Thanks, Andra

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  • How to merge two different child nodes in the same XML file

    - by user814698
    I have an XML file and I would like to merge two different CONTACT child nodes. I have checked these websites it shows how to merge two different xml files into a single file. http://www2.informatik.hu-berlin.de/~obecker/XSLT/#merge Merge XML documents In my case this is my first contact in the xml file: <CONTACT> <PDE-Identity>N65539</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Arun_niit</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> This is the second contact in the file: <PDE-Identity>N65567</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Ramanathan</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>gmail</Type> <Value>[email protected]</Value> </EMail> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACT> I know both of the contacts are belongs to the same person. How can i merge these two contacts in the same xml file. Original XML File: <?xml version="1.0" encoding="UTF-8"?> <CONTACTS> <CONTACT> <PDE-Identity>N65539</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Arun_niit</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACT> <PDE-Identity>N65567</PDE-Identity> <FirstName>Arun_niit</FirstName> <LastName>Ramanathan</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>gmail</Type> <Value>[email protected]</Value> </EMail> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACT> <PDE-Identity>N65567</PDE-Identity> <FirstName>Rangarajkarthik</FirstName> <LastName>karthik Rangaraj</LastName> <Facebook-ID/> <EMAILS> <EMail> <Type>gmail</Type> <Value>[email protected]</Value> </EMail> <EMail> <Type>yahoo</Type> <Value>[email protected]</Value> </EMail> </EMAILS> </CONTACT> <CONTACTS>

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  • WCF service with Factory attribute on .svc is not working on web server (IIS6), but is locally using

    - by Jessica
    I am working on implementing a non web.config approach of WCF services using the factory attribute on the .svc file per Rick Strahl's blog post: Factory="System.ServiceModel.Activation.WebScriptServiceHostFactory" Locally, I am running IIS7 in Visual Studio 2008 and have no problem, but when I deploy to my web server (currently running IIS6), I am getting an authentication error in the event log: Exception: System.ServiceModel.ServiceActivationException: The service '/Services/ResourcesService.svc' cannot be activated due to an exception during compilation. The exception message is: IIS specified authentication schemes 'IntegratedWindowsAuthentication, Anonymous', but the binding only supports specification of exactly one authentication scheme. Valid authentication schemes are Digest, Negotiate, NTLM, Basic, or Anonymous. Change the IIS settings so that only a single authentication scheme is used.. --- System.InvalidOperationException: IIS specified authentication schemes 'IntegratedWindowsAuthentication, Anonymous', but the binding only supports specification of exactly one authentication scheme. Valid authentication schemes are Digest, Negotiate, NTLM, Basic, or Anonymous. Change the IIS settings so that only a single authentication scheme is used. at System.ServiceModel.Web.WebServiceHost.SetBindingCredentialBasedOnHostedEnvironment(ServiceEndpoint serviceEndpoint, AuthenticationSchemes supportedSchemes) at System.ServiceModel.Web.WebServiceHost.AddAutomaticWebHttpBindingEndpoints(ServiceHost host, IDictionary`2 implementedContracts, String multipleContractsErrorMessage) at System.ServiceModel.WebScriptServiceHost.OnOpening() at System.ServiceModel.Channels.CommunicationObject.Open(TimeSpan timeout) at System.ServiceModel.Channels.CommunicationObject.Open() at System.ServiceModel.ServiceHostingEnvironment.HostingManager.ActivateService(String normalizedVirtualPath) at System.ServiceModel.ServiceHostingEnvironment.HostingManager.EnsureServiceAvailable(String normalizedVirtualPath) After doing some Googling, I changed my authentication settings on the .svc folder within my project (on the server) to only anonymous authentication, but it did not work. I still get web service failed on the calls. IIS7 by default only had anonymous. I do not have any entries in my web.config for the services (I stripped them out per this pattern). I am using a nant script to deploy the website to the server and use this also locally to verify the script was not causing the issue. Any known issue with this? IIS 6 not able to handle?

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  • Hosting WCF service in IIS 7 (WAS) with net.tcp binding on TWO tcp ports

    - by Yuri
    By default IIS 7 Web site has net.tcp binding with "808:" binding information string. If i add another net.tcp binding with "xxx:" exception occurs: This collection already contains an address with scheme net.tcp. There can be at most one address per scheme in this collection. Parameter name: item How can i solve this problem and listen my service at TWO ports?

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  • Flex 4 Slider with two thumbs

    - by 23tux
    Hi, anybody know how to make a custom hslider in Flex 4 (spark) with two thumbs? Since Flex 4 the thumbcount property of the slider component isn't longer available (at the mx component it was easily to set). I have to style the track and the thumbs. A tutorial would be nice. thx, tux.

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  • Logback to log different messages to two files

    - by Aly
    I am using logback/slf4j to do my logging. I want to parse my log file to analyze some data, so instead of parsing a great big file (mostly consisting of debug statements) I want to have two logger instances which each log to a separate file; one for analytics and one for all purpose logging. Does anyone know if this is possible with Logback, or any other logger for that matter?

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  • Fluent Nhibernate - Mapping two entities to same table

    - by Andy
    Hi, I'm trying to map two domain entities to the same table. We're doing a smart entity for our domain model, so we have the concept of an Editable Address and a readonly Address. I have both mapped using Classmaps, and everything seems to go fine until we try to export the schema using the SchemaExport class from NHibernate. It errors out saying the table already exists. I assume it's something simple that I'm just not seeing. Any ideas? Thanks

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  • Can overloading is possible with two version of function, constant member function and function with

    - by GG
    Hello, I just came across various overloading methods like type of parameter passed, varying number of parameters, return type etc. I just want to know that can I overload a function with following two version //function which can modify member String& MyClass::doSomething(); //constant member function String& MyClass::doSomething() const; Please let me know the reason behind it. Thanks, GG

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  • iPhone UISlider with two thumbs/indicators?

    - by ChrisW
    Is anyone aware of a version of the iPhone UISlider control with two thumbs? I need a control that will allow specifying a range of values. The UISlider API docs would imply this isn't possible with the standard control, so I was wondering if anyone had a solution for this (or had solved it themselves).

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  • Putting two picker control on single UIView.

    - by Amit Jain
    Hi I am having to picker controls on a single view with two outlets for each. Now when I select any of them same delegate methods are get called. How should we distinguish between which picker control has called the delegate ? Another question is can we change the frame size of the pickers to fit in one view? Thanks Amit

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  • Fluent NHibernate - How to map a non nullable foreign key that exists in two joined tables

    - by vakman
    I'm mapping a set of membership classes for my application using Fluent NHibernate. I'm mapping the classes to the asp.net membership database structure. The database schema relevant to the problem looks like this: ASPNET_USERS UserId PK ApplicationId FK NOT NULL other user columns ... ASPNET_MEMBERSHIP UserId PK,FK ApplicationID FK NOT NULL other membership columns... There is a one to one relationship between these two tables. I'm attempting to join the two tables together and map data from both tables to a single 'User' entity which looks like this: public class User { public virtual Guid Id { get; set; } public virtual Guid ApplicationId { get; set; } // other properties to be mapped from aspnetuser/membership tables ... My mapping file is as follows: public class UserMap : ClassMap<User> { public UserMap() { Table("aspnet_Users"); Id(user => user.Id).Column("UserId").GeneratedBy.GuidComb(); Map(user => user.ApplicationId); // other user mappings Join("aspnet_Membership", join => { join.KeyColumn("UserId"); join.Map(user => user.ApplicationId); // Map other things from membership to 'User' class } } } If I try to run with the code above I get a FluentConfiguration exception Tried to add property 'ApplicationId' when already added. If I remove the line "Map(user = user.ApplicationId);" or change it to "Map(user = user.ApplicationId).Not.Update().Not.Insert();" then the application runs but I get the following exception when trying to insert a new user: Cannot insert the value NULL into column 'ApplicationId', table 'ASPNETUsers_Dev.dbo.aspnet_Users'; column does not allow nulls. INSERT fails. The statement has been terminated. And if I leave the .Map(user = user.ApplicationId) as it originally was and make either of those changes to the join.Map(user = user.ApplicationId) then I get the same exception above except of course the exception is related to an insert into the aspnet_Membership table So... how do I do this kind of mapping assuming I can't change my database schema?

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