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  • How to add "most recent emails from this user" to Gmail inbox as a sidebar

    - by Scott B
    I use and love gmail. However, since i use email for customer support, I'm always doing a cross reference lookup via the search feature to see my past conversations with the person whose email I'm reading. I'd love to have a right sidebar widget that shows me, for any email I choose to read, the list of previous conversations/emails with that person. Is this possible? I'm using Chrome Ideally, this sidebar would bump or replace the contextual ads that now display over there.

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  • jquery - deciding whether a user is "away"

    - by Phil Jackson
    hi, im doing a little test to check whether the user is "away" (unactive) or not; function away_status(){ $("#away_stat_update").everyTime(1000, function(i) { var number = Number($(this).html()); if( number == 20 ) { // set user as away alert( "user away" ); } if( number > 20 ) { $("*").mousemove(function(e){ $("#away_stat_update").html(0); var number = Number(0); // reset user to being online alert( "user back online" ); }); } $("#away_stat_update").html( number + 1 ); }); $("*").mousemove(function(e){ $("#away_stat_update").html(0); }); } away_status(); the only problem is that when the number is greater than 20 and the mouse is moved it keeps alerting "user back on line" instead of doing it just once. The number is resetting by the way.

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  • Ubuntu server 12.04 on AWS - How does the passwordless sudo work for the ubuntu user?

    - by aychedee
    I'm using Ubuntu server 12.04 on Amazon. I want to add a new user that has the same behaviour as the default ubuntu user. Specifically I want passwordless sudo for this new user. So I've added a new user and went to edit /etc/sudoers (using visudo of course). From reading that file it seemed like the default ubuntu user was getting it's passwordless sudo from being a member of the admin group. So I added my new user to that. Which didn't work. Then I tried adding the NOPASSWD directive to sudoers. Which also didn't work. Anyway, now I'm just curious. How does the ubuntu user get passwordless privileges if they aren't defined in /etc/sudoers. What is the mechanism that allows this?

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • Naming Exception when bounding to the home interface

    - by Nila
    Hi! I'm new to ejb. I'm trying to call the ejb from the servlet. But, I'm getting the NamingException. I'm directly running the servlet from the netbeans to check whether it is calling the ejb. But, it is not working. I'm getting the exception as home interface not bound. What is the solution for this?

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  • Tips on how to notify a user of new features in your game (Android)

    - by brent777
    I have noticed a problem when releasing new features for a game that I wrote for Android and published on Google Play Store. Because my game is "stage-based" - and not a game like Hay Day, for example, where users will just go into the game every day since it can't really be finished - my users are not aware of new features that I release for the game. For example, if I publish a new version of my game and it contains a couple new stages, most of their devices will just auto-update the game and they don't even notice this and think to check out what's new. So this is why an approach like popping open a dialog that showcases the new feature(s) when they open the game for the first time after the update was done is not really sufficient. I am looking for some tips on an approach that will draw my users back into the game and then they could read more detail about new features on such a dialog. I was thinking of something like a notification that tells them to check out the new features after an update is done but I am not sure if this is a good idea. Any suggestions to help me solve this problem would be awesome.

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  • Your User is Supreme Part 2

    If you want to rank your website on the basis of any two keywords on the first page of search engines, even then you are directing your search engine optimization towards disaster. You have to understand the nuances of SEO before chalking out any plan as part of your search engine marketing.

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  • Block complete network access for one local user

    - by tumchaaditya
    Well, this is quite trivial question but I could not find a satisfactory answer even after trying many search queries both here and on Google. I want to share my PC with my room-mate. And I don't want him to access ANY network(LAN included). So, I can create an account for him and block network access for the same. I would prefer avoiding any third-party tools as far as possible. It's a simple home PC hooked up to a router for internet. No domain and other stuff. (Technically, guest account can achieve this. But somehow, the guest account on my PC has network access!)

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  • Cygwin file and directory user and group

    - by dvanaria
    I use Cygwin as my main development environment on both my home and work computers. In order to share files between the two computers, I use Dropbox, which is installed in the following folder on both computers: c:\cygwin\home\dvanaria\dropbox Everything works great, except for one thing. When I'm working on my home computer and do an ls -l on any directory, all the files show up as owned by dvanaria of group Users. But when I work from my work computer, an ls -l shows all files as being owned by Administrators and of group Domain Users. I know Cygwin uses some kind of mapping between Windows users and permissions to the /etc/passwd file. But to be honest I have no idea how this file works or how it maps to Windows under Cygwin. Could anyone help figure this out? The main problem is that I can't edit any files when using my work computer, only read them.

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  • How to input data into user defined variables into MySql query

    - by user292791
    Simple Shell script echo "Enter 1 for month of March" echo "Enter 2 for month of April" echo "Enter 3 for month of May" read Month case "$Month" in 1) echo "enter establishment name" read a; mysql -u root -p $a < "March.sql";; 2) echo "enter establishment name" read b; mysql -u root -p $b < "April.sql";; 3) echo "enter establishment name" read c; mysql -u root -p $c < "May.sql";; esac done In this i have three other query files March.sql, April.sql, May.sql. i'm linking this in shell script . Example of .sql file: SELECT DISTINCT substr( a.case_no, 3, 2 ), b.case_type, b.type_name, a.case_no into outfile '/tmp/April.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\r\n' FROM Civil_t AS a, Case_type_t AS b, disposal_proc AS c WHERE substr( a.case_no, 3, 2 ) = b.case_type AND a.date_of_decision BETWEEN '2014-04-01' AND '2014-04-30' AND a.case_no = c.case_no AND a.court_no =1; I have to alter the .sql script every time. Is there any method to read the variables from shell script and use it in mysql. For example:- echo "enter date" read a #input date Now i have read a "date" and i want to use it in March.sql query in where clause. Is there is any method of using this variable in .sql query.

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  • Tapestry5 : No service implements the interface org.springframework.context.ApplicationContext

    - by Joel
    I'm using the Tapestry5 tapx template library to send an html email, as per this example. When I run the example I get the following error: Caused by: java.lang.RuntimeException: No service implements the interface org.springframework.context.ApplicationContext. at org.apache.tapestry5.ioc.internal.RegistryImpl.getService(RegistryImpl.java:560) at org.apache.tapestry5.ioc.internal.ObjectLocatorImpl.getService(ObjectLocatorImpl.java:44) All the tapestry-* jars, including tapestry-spring-5.1.05.jar are in my classpath. Any clues as to what I'm missing?

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  • .NET user interface components recommendations

    - by Parakus
    I'm looking for advice on what .NET user interface components are out there on the market. I have been developing asp.net websites and have mainly been using the Visual studio toolbox build in controls supported by the AjaxcontrolToolkit and the applications have been mainly used inhouse running on our company intranet. But now a new client wants a much more professional looking, commercial web application and they have a budget for some user components for use in the application. Any recommendations where value for money will be realised. Interested in components that will integrate well with ASP.NET 3.5 SP1 or even .NET 4.

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  • ASP.NET Scheduler: How To Implement End-User Restrictions

    Check out this 2 step approach to prevent users from editing appointments in the ASPxScheduler: Step 1: Choose Restriction First decide which action in the ASPxScheduler you want to prevent. Heres a list of the available ones: AllowAppointmentConflicts AllowAppointmentCopy AllowAppointmentCreate AllowAppointmentDelete AllowAppointmentDrag AllowAppointmentDragBetweenResources AllowAppointmentEdit AllowAppointmentMultiSelect AllowAppointmentResize AllowInplaceEditor...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • LINQ-to-SQL - Join, Count

    - by ile
    I have following query: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name }); Now, I need to modify this query... Other table I have is table Deals. I would like to count how many deals user created last month and last year. I tried something like this: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID //join dealsYear in db.Deals on date.Year equals dealsYear.DateCreated.Year join dealsYear in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Year equals dealsYear.DateCreated.Year into dYear join dealsMonth in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Month equals dealsMonth.DateCreated.Month into dMonth where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name, DealsThisYear = dYear, DealsThisMonth = dMonth }); but here is even syntax not correct. Any idea? Btw, is there any good book of LINQ to SQL with examples?

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  • Unity no longer loads in 13.04 for main user

    - by user152973
    When Ubuntu starts up, Unity fails to load (I can only see my desktop with no unity sidebar and no system bar in the top right). I tried the advice of Unity does not start in Ubuntu 13.04 which recommended the following commands: dconf reset -f /org/compiz/ unity --reset-icons &disown I ran the commands without errors an restarted the computer, but the problem persists. I am currently running Gnome. I have looked at other pages from the Google search "ubuntu unity failed to load 13.04", but the advice was similar to above and seems to be concerned with a system upgrade in April 18, 2013. I suspect my issue is something far more recent. Please give me advice on how to restore Unity on my account or at least figure out what the problem is. Thank you. Some information that might be relevant: -Unity has worked fine on 13.04 for the 6 months that I've had it until today. (November 10, 2013) -I have set up the update tool to automatically update when available. It is very possible that the system applied some updates without my knowledge. -Interestingly, Unity works fine on the Guest account. -I have made it so the system automatically logs me in at start-up. -This is a personal laptop. No one else has access to it. -I was not doing anything with the system settings or the terminal and have not installed any new software for the past 3 days. -I am running the System76 native Linux laptop Ultra Lemur. I did not contact their support yet because it seemed unlikely that this is a System76-specific error.

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  • Windows user trying install Git on Solaris

    - by nahab
    Is there simply way to install Git on Solaris as on Windows without installing any side libraries and compiling source files? And if not, why? UPD. Yes I'm looking for single package that will be easy to install. We have ~8 solaris zones using for development those we need simple way to install git fast on they. Installation should be easy because each member of team possibly will be do it and it should be fast because of big count of zones.

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  • Good books and resources on user interface testing

    - by josefx
    I am looking for good books and articles on user-interface testing. What they should contain (one or more of): different test methods/strategies examples, use cases naming pros and cons for different methods something important I might have forgotten :-) What they should not be: Only about general tests and not gui tests describing a test framework limited to a single language What are the best resources you know of? (preferably language agnostic)

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  • PHP user created function return values problem

    - by faX
    Okay I'm new here and I have been trying to figure this out all day I have two functions one calling the other but my functions only returns the last value for example 29 when it should return multiple values. As wondering how can I fix this problem so that my functions return all the values. Here is my PHP code. function parent_comments(){ if(articles_parent_comments_info($_GET['article_id']) !== false){ foreach(articles_parent_comments_info($_GET['article_id']) as $comment_info){ $comment_id = filternum($comment_info['comment_id']); reply_comment_count($comment_id); } } } function reply_comment_count($parent_id){ if(articles_reply_comments_info($_GET['article_id']) !== false){ foreach(articles_reply_comments_info($_GET['article_id']) as $reply_info){ $comment_id = filternum($reply_info['comment_id']); $reply_id = filternum($reply_info['parent_id']); if($parent_id === $reply_id){ reply_comment_count($comment_id); } } } return $comment_id; }

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