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  • If a Matlab function returns a variable number of values, how can I get all of them as a cellarray,

    - by kaleidomedallion
    I am writing a function to remove some values from a cellarray, like so: function left = remove(cells, item); left = cells{cellfun(@(i) ~isequal(item, i), cells)}; But when I run this, left has only the first value, as the call to cells{} with a logical array returns all of the matching cells as separate values. How do I group these separate return values into a single cellarray? Also, perhaps there is already a way to remove a given item from a cellarray? I could not find it in the documentation.

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  • [C#] How to share a variable between two classes?

    - by Altefquatre
    Hello, How would you share the same object between two other objects? For instance, I'd like something in that flavor: class A { private string foo_; // It could be any other class/struct too (Vector3, Matrix...) public A (string shared) { this.foo_ = shared; } public void Bar() { this.foo_ = "changed"; } } ... // inside main string str = "test"; A a = new A(str); Console.WriteLine(str); // "test" a.Bar(); Console.WriteLine(str); // I get "test" instead of "changed"... :( I read there is some ref/out stuff, but I couldn't get what I'm asking here. I could only apply some changes in the methods scope where I was using ref/out arguments... I also read we could use pointers, but is there no other way to do it? Thanks Altefquatre

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  • Class definition thinks setting a variable is a Unit?

    - by DeLongey
    Writing out a Scala class and problem here is that the compiler thinks that the code is a unit not returning the proper value. It's a method used to set a property in the class: def setObject(`object`:StripeObject):StripeObject = { this.`object` = `object` } The error is: type mismatch; found : Unit required: com.stripe.StripeObject The full class is: case class EventData(var previousAttributes: HashMap[String,Object], var `object`:StripeObject) extends StripeObject { def getPreviousAttributes = { previousAttributes } def setPreviousAttributes(previousAttributes: HashMap[String, Object]) = { this.previousAttributes = previousAttributes } def getObject = { `object` } def setObject(`object`:StripeObject):StripeObject = { this.`object` = `object` } } How do I make sure it doesn't return a Unit?

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  • Do I have to call release on an objective-c retain class variable when setting it to a new object?

    - by Andrew Arrow
    Say I have: @property (nonatomic,retain) NSString *foo; in some class. And I call: myclass.foo = [NSString stringWithString:@"string1"]; myclass.foo = [NSString stringWithString:@"string2"]; Should I have called [myclass.foo release] before setting it to "string2" to avoid a memory leak? Or the fact that nothing is pointing to the first "string1" object anymore is good enough? And in the dealloc method [foo release] will be called.

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  • How to set Minimum and Maximum Character limitation to EditText in Android?

    - by nishitpatel
    I am new to android here i have very silly problem i want to set my Edit text box minimum and maximum input value. Here I am creating one Simple validation for Edit text it only take A-Z and 0-9 value with minimum 5 and Maximum 8 character. I set the Maximum and other validation as follow. <EditText android:id="@+id/edittextKode_Listing" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_marginRight="5dp" android:layout_marginLeft="5dp" android:layout_alignTop="@+id/textKode_listing" android:layout_toRightOf="@+id/textKode_listing" android:maxLength="8" android:inputType="textCapCharacters" android:digits="0,1,2,3,4,5,6,7,8,9,ABCDEFGHIJKLMNOPQRSTVUWXYZ" /> but not able to set Minimum requirement. My Edit text is in alert dialog and i also apply the following code to solve this problem ` private void openInboxDialog() { LayoutInflater inflater = this.getLayoutInflater(); // declare dialog view final View dialogView = inflater.inflate(R.layout.kirim_layout, null); final EditText edittextKode = (EditText) dialogView.findViewById(R.id.edittextKode_Listing); final EditText edittextalamat = (EditText) dialogView.findViewById(R.id.edittextAlamat); edittextKode.setOnFocusChangeListener(new OnFocusChangeListener() { @Override public void onFocusChange(View v, boolean hasFocus) { // TODO Auto-generated method stub if(edittextKode.getText().toString().length() > 0){ if(edittextKode.getText().toString().length() < 5) { edittextKode.setError("Error"); Toast.makeText(GPSActivity.this, "Kode listing value not be less than 5", Toast.LENGTH_SHORT).show(); edittextKode.requestFocus(); } } } }); final AlertDialog.Builder builder = new AlertDialog.Builder(GPSActivity.this); builder.setTitle("Kirim").setView(dialogView) .setNeutralButton("OK", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { // TODO Auto-generated method stub gpsCoordinates = (TextView) findViewById(R.id.text_GPS_Coordinates); kode = edittextKode.getText().toString(); alamat = edittextalamat.getText().toString(); catatan = edittextcatatan.getText().toString(); pengirim = edittextPengirim.getText().toString(); if (kode.length() > 0 && alamat.length() > 0 && catatan.length() > 0 && pengirim.length() > 0) { message = "Kode listing : " + kode + "\nAlamat : " + alamat + " \nCatatan : " + catatan + " \n Pengirim : " + pengirim + "\nKoordinat GPS : " + gpsCoordinates.getText().toString(); sendByGmail(); } else { Toast.makeText( getApplicationContext(), "Please fill all three fields to send mail", Toast.LENGTH_LONG).show(); } } }); builder.create(); builder.show(); }` in this alert dialog i have two edittext i want to apply my validation on first edittext i called the setOnFocusChangeListener to check its minimum length on focus change and if length is less than 5 request for focus but it still type in second edittext. please help me out.

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  • Prolog Beginner: How to make unique values for each Variable in a predicate.

    - by sixtyfootersdude
    I have a prolog predicate: DoStuff( [A|B] ) :- <Stuff that I do> ... </Stuff that I do> It is all done except it needs to do return unique values. Ie if you do: ?- DoStuff(A,B,C,D). it should return: A=1; B=2; C=3; D=4. (Or something similar, the key point is that all of the values are unique). However you should be able to do this too: ?- DoStuff(A,A,B,B). And still get a valid answer. Ie: A=1; B=2. How can I do this? What I was planning on doing was something like this: DoStuff( [A|B] ) :- <Stuff that I do> ... </Stuff that I do> unique([A|B]). unique([]). unique([A|B]) :- A is not B. However I think that will make DoStuff([A,A,B]) not work because not all values will be unique.

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  • How can I qualify an autowired property with a variable from a config file using annotations?

    - by jiggy
    My specific problem is that I have configured two beans that implement the same interface and I have a third bean that has a property of that interface's type. I inject the property using a config property. So, assuming RemoteDataSource and LocalDataSource implement IDataSource and dao1 has a property of type IDataSource, my XML config might look like this: <bean id="datasource1" class="com.foo.RemoteDataSource"> <property name="url">${url}</property> </bean> <bean id="datasource2" class="com.foo.LocalDataSource"> <property name="path">${filepath}</property> </bean> <bean id="dao1" class="com.foo.MyDAO"> <property name="dataSource">${datasource}</property> </bean> With url, filepath and datasource being defined in an included properties file. We are now making a push for annotation-driven configuration and I'm not sure how to annotate my dao to put the data source configured in the property file. I want to do something like this, but it is evidently not allowed: @Autowired @Qualifier("${datasource}") public void setDataSource(IDataSource datasource) {...}

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  • Can I have two names for the same variable?

    - by Roman
    The short version of the question: I do: x = y. Then I change x, and y is unchanged. What I want is to "bind" x and y in such a way that I change y whenever I change x. The extended version (with some details): I wrote a class ("first" class) which generates objects of another class ("second" class). In more details, every object of the second class has a name as a unique identifier. I call a static method of the first class with a name of the object from the second class. The first class checks if such an object was already generated (if it is present in the static HashMap of the first class). If it is already there, it is returned. If it is not yet there, it is created, added to the HashMap and returned. And then I have the following problem. At some stage of my program, I take an object with a specific name from the HashMap of the first class. I do something with this object (for example change values of some fields). But the object in the HashMap does not see these changes! So, in fact, I do not "take" an object from the HashMap, I "create a copy" of this object and this is what I would like to avoid.

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  • Shared/Static Variable Should Be Nothing but Isn't - what gives?

    - by Denis
    I have the following code: Public Class TestClass Public Sub Test() If theGlobal IsNot Nothing Then Throw New Exception("What gives!") End Sub Private Shared theGlobal As Object = Nothing Private Shared ReadOnly Property Global Get If theGlobal Is Nothing Then theGlobal = New Object() End If Return theGlobal End Get End Property End Class Am stumped... Why is theGlobal object NOT Nothing?

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  • SELECT SQL Variable - should i avoid using this syntax and always use SET?

    - by Sholom
    Hi All, This may look like a duplicate to here, but it's not. I am trying to get a best practice, not a technical answer (which i already (think) i know). New to SQL Server and trying to form good habits. I found a great explanation of the functional differences between SET @var = and SELECT @var = here: http://vyaskn.tripod.com/differences_between_set_and_select.htm To summarize what each has that the other hasn't (see source for examples): SET: ANSI and portable, recommended by Microsoft. SET @var = (SELECT column_name FROM table_name) fails when the select returns more then one value, eliminating the possibility of unpredictable results. SET @var = (SELECT column_name FROM table_name) will set @var to NULL if that's what SELECT column_name FROM table_name returned, thus never leaving @var at it's prior value. SELECT: Multiple variables can be set in one statement Can return multiple system variables set by the prior DML statement SELECT @var = column_name FROM table_name would set @var to (according to my testing) the last value returned by the select. This could be a feature or a bug. Behavior can be changed with SELECT @j = (SELECT column_name FROM table_name) syntax. Speed. Setting multiple variables with a single SELECT statement as opposed to multiple SET/SELECT statements is much quicker. He has a sample test to prove his point. If you could design a test to prove the otherwise, bring it on! So, what do i do? (Almost) always use SET @var =, using SELECT @var = is messy coding and not standard. OR Use SELECT @var = freely, it could accomplish more for me, unless the code is likely to be ported to another environment. Thanks

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  • Cam you insert the results of a dynamic sql call into a SQL Server 2005 table variable

    - by codingguy3000
    Is there anyway to do this in SQL Server 2005? declare @tv_tablelist table (recnum int identity(1,1) primary key, newvar varchar(500)) declare @mysql nvarchar(4000) set @mysql = 'insert into @tv_tablelist(newvar) values (''test test test'')' Exec sp_executesql @mysql, N'@tv_tablelist table (recnum int identity(1,1) primary key, newvar varchar(500)) OUTPUT', @tv_tablelist OUTPUT select * from @tv_tablelist

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  • How to intialize a variable from another script in bash?

    - by Zombies
    How can I set my intial variables in a re-usable way? I tried to do this by invoking something like this in my child script: ./init.bash And inside init.bash: prod="false" if [ "$prod" == "prod" ] then RUN_DIR=/home/windsor/.scripts/websites JAVA_DIR=/home/windsor/prog/websitechecker OUT_DIR=/tmp/ DB="prod" else if [ ! -a /tmp/test ] then mkdir /tmp/test fi DB="mydb" OUT_DIR=/tmp/test/ RUN_DIR=/home/windsor/workspaces/bash/websites JAVA_DIR=/home/windsor/workspaces/java/testrun fi cd $RUN_DIR

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  • Is it possible to open a pipe-based filehandle which prints to a variable in perl?

    - by blackkettle
    Hi, I know I can do this, ------ open(F,"",\$var); print F "something cool"; close(F); print $var; ------ or this, open(F, "| ./prog1 | ./prog2 tmp.file"); print F "something cool"; close(F); but is it possible to combine these? The semantics of what I'd like to do should be clear from the following, open(F,"|./prog1 | ./prog2", \$var); print F "something cool"; close(F); print $var; however the above clearly won't work. A few minutes of experimenting and googling seems to indicate that this is not possible, but I'd like to know if I'm stuck with using the `` to capture the output.

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  • Why "constructor-way" of declaring variable in "for-loop" allowed but in "if-statement" not allowed?

    - by PiotrNycz
    Consider this simple example: /*1*/ int main() { /*2*/ for (int i(7); i;){break;} /*3*/ if (int i(7)) {} /*4*/ } Why line-2 compiles just fine, whilst line-3 gives the error? This is little strange to me why if-statement is in this aspect treated worse than for-loop? If this is compiler specific - I tested with gcc-4.5.1: prog.cpp: In function 'int main()': prog.cpp:3:7: error: expected primary-expression before 'int' prog.cpp:3:7: error: expected ')' before 'int' I was inspired by this question [UPDATE] I know this compiles just fine: /*1*/ int main() { /*2*/ for (int i = 7; i;){break;} /*3*/ if (int i = 7) {} /*4*/ }

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  • Why can't my function access a variable in an enclosing function?

    - by nailer
    I know about the LEGB rule. But a simple test of whether a function has read access to variables defined in an enclosing function doesn't seem to actually work. Ie: #!/usr/bin/env python2.4 '''Simple test of Python scoping rules''' def myfunction(): print 'Hope this works: '+myvariable def enclosing(): myvariable = 'ooh this worked' myfunction() if __name__ == '__main__': enclosing() Returns: NameError: global name 'myvariable' is not defined Am I doing something wrong? Is there more to it than the LEGB resolution order?

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  • C++ Variable declarable in function body, but not class member?

    - by anon
    I want to create a C++ class with the following type: It can be declared inside of a function. It can be declared inside of a member function. It can not be declared as a class member. The use of this: think "Root" objects for a GC. Is this possible in C++? In particular, I'm using g++. Willing to switch to clang. Either templates or macro solution fine. Thanks!

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  • Can I execute a "variable statements" within a function and without defines.

    - by René Nyffenegger
    I am facing a problem that I cannot see how it is solvable without #defines or incuring a performance impact although I am sure that someone can point me to a solution. I have an algorithm that sort of produces a (large) series of values. For simplicity's sake, in the following I pretend it's a for loop in a for loop, although in my code it's more complex than that. In the core of the loop I need to do calculations with the values being produced. Although the algorithm for the values stays the same, the calculations vary. So basically, what I have is: void normal() { // "Algorithm" producing numbers (x and y): for (int x=0 ; x<1000 ; x++) { for (int y=0 ; y<1000 ; y++) { // Calculation with numbers being produced: if ( x+y == 800 && y > 790) { std::cout << x << ", " << y << std::endl; } // end of calculation }} } So, the only part I need to change is if ( x+y == 800 && y > 790) { std::cout << x << ", " << y << std::endl; } So, in order to solve that, I could construct an abstract base class: class inner_0 { public: virtual void call(int x, int y) = 0; }; and derive a "callable" class from it: class inner : public inner_0 { public: virtual void call(int x, int y) { if ( x+y == 800 && y > 790) { std::cout << x << ", " << y << std::endl; } } }; I can then pass an instance of the class to the "algorithm" like so: void O(inner i) { for (int x=0 ; x<1000 ; x++) { for (int y=0 ; y<1000 ; y++) { i.call(x,y); }} } // somewhere else.... inner I; O(I); In my case, I incur a performance hit because there is an indirect call via virtual function table. So I was thinking about a way around it. It's possible with two #defines: #define OUTER \ for (int x=0 ; x<1000 ; x++) { \ for (int y=0 ; y<1000 ; y++) { \ INNER \ }} // later... #define INNER \ if (x + y == 800 && y > 790) \ std::cout << x << ", " << y << std::endl; OUTER While this certainly works, I am not 100% happy with it because I don't necessarly like #defines. So, my question: is there a better way for what I want to achieve?

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  • get an id of child element and store in a variable using jquery?

    - by Simpson88Keys
    I'm basically trying to do exactly what the subject suggests, but I'm getting "undefined" in my alert, and I'm not entirely sure why. I am fairly new to jquery, so, I probably have the syntax wrong, but not sure where to go from here. I'll post both of my attempts, which both yield "undefined" in the alert... //In my first attempt, I'm trying to get the id of the inner a tag <ul> <li id="l1" class="active"><a href="#c1">Samp 1</a></li> <li id="l2" class=""><a href="#c2">Samp 2</a></li> <li id="l3" class=""><a href="#c3">Samp 3</a></li> </ul> var selected = $(".active).children("a").attr("id"); alert(selected); //In my second attempt, I'm trying to get the id of the currently selected li var selected = $(".active").attr("id"); alert(selected);

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  • How to pass an integer to create new variable name?

    - by Joe
    I have 50 svg animations named animation0, animation1, animation2 etc. and I want to load them when the integer 0 to 49 is passed to this function: function loadAnimation(value){ var whichswiffy = "animation" + value; var stage = new swiffy.Stage(document.getElementById('swiffycontainer'), whichswiffy); stage.start(); } It doesn't work at the moment, maybe it's passing 'whichswiffy' rather than 'animation10'? Any ideas?

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  • How do I write a writer method for a class variable in Ruby?

    - by tepidsam
    I'm studying Ruby and my brain just froze. In the following code, how would I write the class writer method for 'self.total_people'? I'm trying to 'count' the number of instances of the class 'Person'. class Person attr_accessor :name, :age @@nationalities = ['French', 'American', 'Colombian', 'Japanese', 'Russian', 'Peruvian'] @@current_people = [] @@total_people = 0 def self.nationalities #reader @@nationalities end def self.nationalities=(array=[]) #writer @@nationalities = array end def self.current_people #reader @@current_people end def self.total_people #reader @@total_people end def self.total_people #writer #-----????? end def self.create_with_attributes(name, age) person = self.new(name) person.age = age person.name = name return person end def initialize(name="Bob", age=0) @name = name @age = age puts "A new person has been instantiated." @@total_people =+ 1 @@current_people << self end

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