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• How can I get my div id to reload via ajax and jquery

  - by Matt Nathanson

  I'm creating a CMS using jQuery and AJAX. When I click, my "Add Campaign" buttom, it creates a unique client ID in the DB and on a hard reload, the new client shows up in its container. I am trying to use ajax to reload the container on the fly and I'm not having the exact luck i am hoping for. I can get it to reload, but it's like it's pulling in descriptions of each of the clients as well! function AddNewClient() { dataToLoad = 'clientID=' + clientID + '&addClient=yes'; $.ajax({ type: 'post', url: '/clients/controller.php', datatype: 'html', data: dataToLoad, target: ('#clientssidebar'), async: false, success: function(html){ $('#clientssidebar').html(html); }, error: function() { alert('An error occured!'); } }); };

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• Reload AJAX data every X minutes/seconds, jQuery

  - by NightMICU

  Hi everyone, I programmed a CMS that has a log of who has recently logged into the system. Presently, this data is fed into a jQuery UI tab via Ajax. I would like to put this information into a sidebar on the main page and load it via AJAX every 30 seconds (or some set period of time). How would I go about doing this? Does the PHP response need to be JSON coded? I am fairly new to AJAX and JSON data. Here is the PHP I am currently using to pull details from the users table- <?php $loginLog = $db->query("SELECT name_f, name_l, DATE_FORMAT(lastLogin, '%a, %b %D, %Y %h:%i %p') AS lastLogin FROM user_control ORDER BY lastLogin ASC LIMIT 10"); while ($recentLogin = $loginLog->fetch()) { echo $recentLogin['name_f'] . " " . $recentLogin['name_l'] . " - " . $recentLogin['lastLogin']; } ?> Thanks!

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• Paths when both including and requesting AJAX

  - by Cristian

  I was wondering if there is a way of making a relative path to the main folder (where the index.php lies) from every file that needs to be included or requested by AJAX. I want to combine both AJAX and PHP include so first time the page loads with PHP, and then to be able to refresh parts of the page with AJAX, but the files are the same and lie in subfolders. I'm having problems with the path and although I can set an absolute path, then I have to change it every time the server changes. I want a relative path to where my project is, but not DOCUMENT_ROOT, because that one doesn't work with aliases. (or do you know how to make it work with aliases? ) Thanks !

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• Can headers be sent in an AJAX request?

  - by sombe

  Can I call the server to set a new cookie with an AJAX request (that is, after the page has already loaded)? For example, when a visitor hits a link, ajax would open a php file that sets a new cookie like this: setcookie('cookiename', 'true', time()+3000, "/",'...'); But this is done after the html (the page containing the actual <a> tag pressed) was rendered. Is it nevertheless ok to set cookies in ajax? (maybe because the php file loaded is separate from the original html page).

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• Navigating by foreign keys in ADO.NET Entity Framework/MySQL

  - by Werg38

  I am using ASP.NET MVC2 on top of a MySQL database in VS2008. I am using the MySQL ADO.NET connector 6.2.3 to provide the connection for the ADO.NET Entity Data Model. This is mostly working ok, however navigating via foreign keys is causing me a real headache! Here is a simplified example.. Car (Table) CarID PK Colour Doors ManufacturerID FK Manufacturer (Table) ManufacturerID PK Name In the edmx file I can see the 1-many relationship shown as a navigation property in the both the Car and Manufacturer tables. I create a Models.CarRepository that allows me to returns a IQueryable. At the View I want to be able to display the Manufacturer.Name for each car. This is not accessible via the object I get returned. What is best way to implement this? Have I encountered a limitation of the Entity Framework/MySQL combination?

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• jquery ajax call errors in chrome onenter with no responseText

  - by wham12

  I've built a login page that uses a .ajax call to a generic c# handler (.ashx) to validate the username and password before allowing the user to log in. If you click on the login link <a href="#" class="ui-state-default ui-corner-all CustomButton" onclick="goLogin();return false"> the .ajax call returns successfully and it logs the user in. I am trying to make it so the user can also just press the "enter" key from the password box: $("#pword").keydown(function(e) { if (e.keyCode == 13) { goLogin(); } }); Using Firefox, both ways work just fine and the user is logged in. With Chrome however, pressing "enter" hits the error function of my .ajax call and will not log the user in. The parameters and responses look identical through Firefox's console, as expected. What would be causing this and/or how can I debug it in Chrome?

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• cant find div element in ajax data find

  - by Shrey

  This is my whole Ajax page which is returned <!DOCTYPE div PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <div class="CareerAjaxData">Simple Div Content</div> The jQuery script in the Main page which calls this Ajax page is $.ajax({ type : 'POST', url : url, data : data, datatype : 'html', success : function(ajaxdata) { var $tabcontent = $(ajaxdata).find('.CareerAjaxData'); console.log($tabcontent.html()); } }); But the output of Console gives: undefined I get proper response from the server. But there some problem with js I guess. whats wrong here..??

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• AJAX form sections - how to pass url of next stage of form

  - by dan727

  Hi, I've got a multi-part form (in a PHP MVC setup) which I have working correctly without javascript enhancement. I'm starting to add the AJAX form handling code which will handle each stage of a form submission, validating/saving data etc, before using AJAX to load the next stage of the form. I'm wondering how best to pass the URL of the next stage to the current form being processed, so that my jQuery form handling code can process the current form, then load the next part via AJAX. The form "action" is different from what the url of the next stage of the form is - what do you think would be good practice here? I was thinking about either appending the url of the next stage to the form action url, via a query string - then just use javascript to extract this url when the form is successfully processed. The other option is via a hidden form element. Not sure what other client side options I have here Any thoughts?

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• how do i specify the element when loading content ajax jquery

  - by phukkie

  How can I specify an element where the content is to be retrieved from within the pageurl in the code below? $(function () { $("a[rel='sort']").click(function (e) { //e.preventDefault(); /* if uncomment the above line, html5 nonsupported browers won't change the url but will display the ajax content; if commented, html5 nonsupported browers will reload the page to the specified link. */ //get the link location that was clicked pageurl = $(this).attr('href'); //to get the ajax content and display in div with id 'content' $.ajax({ url: pageurl + '?rel=sort', success: function (data) { $('#content1').html(data); } }); //to change the browser URL to 'pageurl' if (pageurl != window.location) { window.history.pushState({ path: pageurl }, '', pageurl); } return false; }); });

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• ASP.Net MVC: Change Routes dynamically

  - by Frank

  Hi, usually, when I look at a ASP.Net MVC application, the Route table gets configured at startup and is not touched ever after. I have a couple of questions on that but they are closely related to each other: Is it possible to change the route table at runtime? How would/should I avoid threading issues? Is there maybe a better way to provide a dynamic URL? I know that IDs etc. can appear in the URL but can't see how this could be applicable in what I want to achieve. How can I avoid that, even though I have the default controller/action route defined, that default route doesn't work for a specific combination, e.g. the "Post" action on the "Comments" controller is not available through the default route? Background: Comment Spammers usually grab the posting URL from the website and then don't bother to go through the website anymore to do their automated spamming. If I regularly modify my post URL to some random one, spammers would have to go back to the site and find the correct post URL to try spamming. If that URL changes constantly I'd think that that could make the spammers' work more tedious, which should usually mean that they give up on the affected URL.

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• Ajax twice + facbook login/logout

  - by Devenv

  Hi, I have a very specific problem. The site I'm developing loads the FB connect button by ajax (it loads the box that includes FBC button). And when user logs in it loads instead of it the box with FB logout link. The problem is that FB requires to call FB.init() at the end of the body (when all the FB stuff is already on the page) and you can't do it twice as the second time is ignored. So what happens is - I do FB.init() inside the login box and FBC button works perfectly, but the logout link doesn't as FB.init() doesn't work there. The only solution I came up with is to place the login and logout buttons outside of ajax boxes and show them in the right places after ajax boxes are loaded. I'm pretty much sure this will work but I don't like the solution (which looks more like hack).

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• jQuery - now: Creating an object and storing values in it to pass to an AJAX call

  - by Josh K

  I have an array: myarr = []; I'm filling it with some values: myarray['name'] = "Me!"; Now I want to transform that array into a set of Key = Value pairs. I though jQuery would do it automatically, but it doesn't seem to. $.ajax ({ type: "POST", dataType: "text", url: "myurl", data: myarr }); Is there a way to do this or something I'm doing wrong? I get no javascript errors, and no serverside errors other then no POST information at all. I need the request to be sent as a true POST request. I need to keep the php code simple because sometimes the login won't be an AJAX call. I'm now trying the following with an error unexepected token ':' myarr: { 'name':'me' } The question has now become: How do I initialize a new javascript object as "blank", how do I set up mappings, and how do I pass it in an AJAX call?

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• It ok for AJAX to take place over non-SSL?

  - by Joshua

  Say I have an https page can I make ajax calls to non SSL without getting warnings in browsers? I want to do it for non sensitive data so its faster

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• wait for ajax request then finish the rest ( jQuery )

  - by user1725155

  I have a peace of jquery code: var new = checkCP(somedata); if(new=="hi"){ alert("Welcom"); } function checkCP(jsData){ $.ajax({ type: "POST", url: "Process.php", data: jsData, dataType: "json", success: function(data){ if(data.match==1) return "hi"; else return "bye"; } }); } I don't know why the welcome alert never show up . I checked everything , even on PHP file the result is 1 but apparently before It wait for ajax respond it passes the if(new=="hi"){ alert("Welcom"); } So is there anyway to wait for ajax respond then read the rest of codes in jQuery ? Thanks.

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• return from jquery ajax call

  - by michael

  hi im tryin to use the return from a jquery ajax call in my own function, but it keeps returning undefined. function checkUser2(asdf) { $.ajax({ type: "POST", async: false, url: "check_user.php", data: { name: asdf }, success: function(data){ return data; //alert(data); } }); } $("#check").click(function(){ alert(checkUser2("muma")); }); the ajax call definately works, because when i uncomment my alert i get the correct return, and i can see it in firebug. Am i doing something stupid.

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• Jquery .$.ajax is not working

  - by Saravanan I M

  I am using $.ajax for facebook invite and calling the url (Yii framework controller). The below code is not working. $.ajax is not working. function FacebookInviteFriends() { FB.ui ( { method : 'apprequests', data: '', display: 'dialog', title : 'Invite a Friend', message: 'I just sent you an invitation to play My Game.', filters: ['app_non_users'] }, function(response) { alert("start"); if (response && response.to) { alert("inside if"); $.ajax({ url: 'http://localhost:83/invitechips/createRecord', type: 'POST', data: {id : response.to} }).done(function() { alert( "Data Saved: "); }); } else { alert("inside else"); } } ); }

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• Submit form if ajax validator returns true using jquery

  - by Anthony

  I am not sure where I'm going wrong. The idea is that before the form is submitted, one of the input fields is sent to a server-side validator via ajax. If the response is 1, the input is valid and the form should be submitted. If the response is 0, the form should not be submitted. The issue is that I can't figure out how to set a variable within the ajax request function that will prevent the form from being submitted. This is what I have: $("#form").submit(function() { var valid= false; var input = $("#input").val(); $.ajax({ type: "POST", url: "validator.php", data: "input=" + input, success: function(msg){ valid = (msg == 1) ? true : false; if(!valid) { $("#valid_input").html("Please enter valid info"); } else { $("#valid_input").html(""); } } }); return valid; });

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• File download using Java, Struts 2 and AJAX

  - by amar4kintu

  Hello Friends, I want to give file download using java,struts2 and ajax. On my html page there is a button called "export" clicking on which ajax call will be made which will execute a query and will create .xls file using code and I want to give that file for download to user without storing it on hard drive. Does any one know how to do that using struts2 and ajax in java? Is there any example available? Let me know if you need more details from me... Thanks. amar4kintu

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• Passing PHP session variable to AJAX URL

  - by user547794

  Hello, I am trying to pass a session variable into an AJAX loaded page. Here is the code I am using: jQuery(document).ready(function(){ $("#userdetail").click(function() { $.ajax({ url: "userdetail.php?id=<?php $_SESSION['uid']?>", success: function(msg){ $("#results").html(msg); } }); }); }); This is the HTML URL I had working, not sure how to get this into the AJAX call: userdetail.php?id=<?php $_SESSION['uid']?> I should also mention that if I manually pass in the userID it works fine url: "userdetail.php?id=1",

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• asp.net drop down list viewstate issue after client side Ajax update

  - by DSharper

  In my aspx page I have drop down list that initialy in page load event loads up with list of values which is shown to client(drop down list "A") and in client side, depending on client selecion of another drop down list(drop down list "B") I have written a javascript to update drop down list "A" with corresponding values with Ajax behaviour(without full page postback). But when we post page to the server, in server side page load event shows initialy sent list of values for drop down list "A" but not the values that were loaded by Ajax calls due to ViewState not being updated correctly due to Ajax call. I could fix this easily with update panel but it increased Ajax request size to 44KB which is much higher than what currently is for hand made Ajax script I have written( 0.5KB) Is there special way of fixing this rather than using update panel?

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• Problem with outputting html via AJAX

  - by Marek

  Hello I am new to JS and AJAX, but I have to do my homework. I choose jQuery, so it little easy now. I want to get a html via AJAX request, but in result it looks, ex: <fieldset id=\"item4\" class=\"item\"><legend>Odno\u015bnik 4<\/legend> I set response content-type to text/html. When I outputting result on server everything is ok. jQuery code: enter code here $.ajax({ dataType : 'html', data : 'add_sz='+changeSize+'&next_id='+nextId, url : '/kohana/admin/menus/ajax_items_refresh', error : function(err, xhr, status) { msgOutput.text('error msg'); }, success : function(data, xhr, textStatus) { msgOutput.text('success msg'); var tabs = $('#items-list'); $('#items-wrap').html($('#items-wrap').html() + data); Could somebody help me? What I am doing wrong? Kind Regards.

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• Zend and Jquery (Ajax Post)

  - by Zend_Newbie_Dev

  I'm using zend framework, i would like to get POST data using Jquery ajax post on a to save without refreshing the page. //submit.js $(function() { $('#buttonSaveDetails').click(function (){ var details = $('textarea#details').val(); var id = $('#task_id').val(); $.ajax({ type: 'POST', url: 'http://localhost/myproject/public/module/save', async: false, data: 'id=' + id + '&details=' + details, success: function(responseText) { //alert(responseText) console.log(responseText); } }); }); }); On my controller, I just don't know how to retrieve the POST data from ajax. public function saveAction() { $data = $this->_request->getPost(); echo $id = $data['id']; echo $details = $data['details']; //this wont work; } Thanks in advance.

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• Simple Sinatra Ajax Not Working

  - by proteantech

  I was trying make an AJAX call from a static file on my computer to a simple sinatra service. The ajax call was returning with an error and no details. The server logged no errors either. Another strange symptom was that the Origin in the request header was null. I turns out that you can't make cross domain ajax calls without a little extra effort. You can set the Access-Control-Allow-Origin header on your sinatra response to expose your service to external domains using a snippet like this: get '/hi' do response['Access-Control-Allow-Origin'] = '*' content_type 'text/plain' "Hello World" end There's also another header you can set to allow other HTTP Methods besides gets, Access-Control-Request-Method. You can find more information by searching around for CORS: Cross Origin Resource Sharing and the previously mentioned headers. Oh, and in case you want to do this in Rails as well you can do something like this in your controller: after_filter :set_access_control_headers def set_access_control_headers headers['Access-Control-Allow-Origin'] = '*' headers['Access-Control-Request-Method'] = '*' end

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• AJAX with jQuery not returning data

  - by James P

  This is my Javascript: $(document).ready(function() { $('#like').bind('keydown', function(e) { if(e.keyCode == 13) { var likeMsg = $('#like').val(); if(likeMsg) { // Send the AJAX request to like.php $.ajax({ url: 'like.php', success: function(data) { alert('Content: ' + data); } }); } } }); }); And this is my like.php file: <?php echo "It works! :)"; ?> When I press enter on the #like input, it seems the AJAX request is sent and an alert box comes up saying: Content:, but there's no data being sent back from like.php... I have checked if the file exists and if it's in the same directory and whatever and it is, so I'm pretty much clueless atm. Does anyone know what could be wrong here? Cheers.

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• why i got : ReferenceError: $ is not defined $.ajax({

  - by user2922621

  i need to call phpfile through ajax.. i tried \::; <html> <script type="text/javascript"> setInterval(function(){ test(); },3000); function test(){ $.ajax({ type: "POST", url: "GetMachineDetail.php", data: "{}", success: function(response){ alert("suceccess");} }); } Its simple javascript jquery calling.. but we got ajax not found eror, any solution please.

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