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  • What's the best way to use NHibernate for objects without ID?

    - by Khash
    I have some classes in my app that don't require an ID to be persisted. These could be things like user logs or audit records. I can add an arbitaty id to them but I would like to avoid that as they don't mean anything. The retrieval of these objects is always on another key (like UserId) which is not unique to the record.

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  • How to get all objects with their children using django orm?

    - by kender
    Hi, I got very simple hierarchical structure: every object can have 0 or 1 parent. There's no limit on how many children each object can have. So in my application I got such a model: class O(Model): name = CharField(max_length = 20) parent = ForeignKey('O', related_name = 'children') Now I would like to be able to fetch all objects who have a particular one Object1 in their parent-tree (as in their parent or parent of their parents, etc). Should I use mptt or is there a simpler approach?

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  • What types of objects should the ViewModel reference in the MVVM pattern?

    - by Blanthor
    I've seen quite a few examples of MVVM. I can see that the View should reference the ViewModel. I've seen recently an example of a ViewModel referencing a View, which seems wrong to me, as it would result in tighter coupling. Given that ViewModel is often described as an intermediary between the View and the Model, is there more to the ViewModel than a facade to domain objects? I hope I used the term "facade" correctly here.

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  • OQL - Find certain (sub)-members of a given object

    - by Pentius
    I'm analyzing heap dumps in a Portal App. With the help of OQL I found the MemorySessionData Object with its address. Now I want to find all SerializableViewState Objects, that are hold by Objects hold by this MemorySessionData object. In other words: My MemorySessionData Object holds several objects, these hold objects again and so on... I want to find all SerializableViewState Objects in this tree. How would the OQL look like? :-/

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  • How can I improve my select query for storing large versioned data sets?

    - by Jason Francis
    At work, we build large multi-page web applications, consisting mostly of radio and check boxes. The primary purpose of each application is to gather data, but as users return to a page they have previously visited, we report back to them their previous responses. Worst-case scenario, we might have up to 900 distinct variables and around 1.5 million users. For several reasons, it makes sense to use an insert-only approach to storing the data (as opposed to update-in-place) so that we can capture historical data about repeated interactions with variables. The net result is that we might have several responses per user per variable. Our table to collect the responses looks something like this: CREATE TABLE [dbo].[results]( [id] [bigint] IDENTITY(1,1) NOT NULL, [userid] [int] NULL, [variable] [varchar](8) NULL, [value] [tinyint] NULL, [submitted] [smalldatetime] NULL) Where id serves as the primary key. Virtually every request results in a series of insert statements (one per variable submitted), and then we run a select to produce previous responses for the next page (something like this): SELECT t.id, t.variable, t.value FROM results t WITH (NOLOCK) WHERE t.userid = '2111846' AND (t.variable='internat' OR t.variable='veteran' OR t.variable='athlete') AND t.id IN (SELECT MAX(id) AS id FROM results WITH (NOLOCK) WHERE userid = '2111846' AND (t.variable='internat' OR t.variable='veteran' OR t.variable='athlete') GROUP BY variable) Which, in this case, would return the most recent responses for the variables "internat", "veteran", and "athlete" for user 2111846. We have followed the advice of the database tuning tools in indexing the tables, and against our data, this is the best-performing version of the select query that we have been able to come up with. Even so, there seems to be significant performance degradation as the table approaches 1 million records (and we might have about 150x that). We have a fairly-elegant solution in place for sharding the data across multiple tables which has been working quite well, but I am open for any advice about how I might construct a better version of the select query. We use this structure frequently for storing lots of independent data points, and we like the benefits it provides. So the question is, how can I improve the performance of the select query? I assume the nested select statement is a bad idea, but I have yet to find an alternative that performs as well. Thanks in advance. NB: Since we emphasize creating over reading in this case, and since we never update in place, there doesn't seem to be any penalty (and some advantage) for using the NOLOCK directive in this case.

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  • document directory for different iphone app targets

    - by David
    I have two targets for my app which both unarchive serialized objects, however the objects made by the two apps are not compatible. these objects seem to be saved to the same document directory so that one app will try to unarchive the other's objects. how do I get the apps to create separate sandboxes so they do not have access each others' saved objects? or do I need to just have each version create differently named files?

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  • How can I link two Java serialised objects back together?

    - by Kidburla
    Sometimes (quite a lot, actually) we get a situation in Java where two objects are pointing to the same thing. Now if we serialise these separately it is quite appropriate that the serialised forms have separate copies of the object as it should be possible to open one without the other. However if we now deserialise them both, we find that they are still separated. Is there any way to link them back together? Example follows. public class Example { private static class ContainerClass implements java.io.Serializable { private ReferencedClass obj; public ReferencedClass get() { return obj; } public void set(ReferencedClass obj) { this.obj = obj; } } private static class ReferencedClass implements java.io.Serializable { private int i = 0; public int get() { return i; } public void set(int i) { this.i = i; } } public static void main(String[] args) throws Exception { //Initialise the classes ContainerClass test1 = new ContainerClass(); ContainerClass test2 = new ContainerClass(); ReferencedClass ref = new ReferencedClass(); //Make both container class point to the same reference test1.set(ref); test2.set(ref); //This does what we expect: setting the integer in one (way of accessing the) referenced class sets it in the other one test1.get().set(1234); System.out.println(Integer.toString(test2.get().get())); //Now serialise the container classes java.io.ObjectOutputStream os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test1.ser")); os.writeObject(test1); os.close(); os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test2.ser")); os.writeObject(test2); os.close(); //And deserialise them java.io.ObjectInputStream is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test1.ser")); ContainerClass test3 = (ContainerClass)is.readObject(); is.close(); is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test2.ser")); ContainerClass test4 = (ContainerClass)is.readObject(); is.close(); //We expect the same thing as before, and would expect a result of 4321, but this doesn't happen as the referenced objects are now separate instances test3.get().set(4321); System.out.println(Integer.toString(test4.get().get())); } }

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  • Fastest way to get array of NSRange objects for all uppercase letters in an NSString?

    - by Bama91
    I need NSRange objects for the position of each uppercase letter in a given NSString for input into a method for a custom attributed string class.  There are of course quite a few ways to accomplish this such as rangeOfString:options: with NSRegularExpressionSearch or using RegexKitLite to get each match separately while walking the string.  What would be the fastest performing approach to accomplish this task?

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  • JavaScript: How can I determine what objects are being collected by the garbage collector?

    - by shino
    I have significant garbage collection pauses. I'd like to pinpoint the objects most responsible for this collection before I try to fix the problem. I've looked at the heap snapshot on Chrome, but (correct me if I am wrong) I cannot seem to find any indicator of what is being collected, only what is taking up the most memory. Is there a way to answer this empirically, or am I limited to educated guesses?

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  • Most performant way to check how many objects are referenced by an to-many relationship in Core Data

    - by dontWatchMyProfile
    Lets say I have an employees relationship in an Company entity, and it's to-many. And they're really many. Apple in 100 years, with 1.258.500.073 employees. Could I simply do something like NSInteger numEmployees = [apple.employees count]; without firing 1.258.500.073 faults? (Well, in 100 years, the iPhone will easily handle so many objects, for sure...but anyways)

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  • How to tell if JSON object is empty in jQuery

    - by GrantU
    I have the following JSON: { "meta": { "limit": 20, "next": null, "offset": 0, "previous": null, "total_count": 0 }, "objects": [] } I'm interested in objects: I want to know if objects is empty and show an alert: something like this: success: function (data) { $.each(data.objects, function () { if data.objects == None alert(0) else :alert(1) });

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  • Find out which object being added to NSMutableArray is nil

    - by Raphael Caixeta
    I started a project using ARC, and I'm inserting a few objects into an NSMutableArray. The objects have all started out as NSStrings, and when attempting to add these objects into the array, I get the following error: Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: ' -[__NSArrayM insertObject:atIndex:]: object cannot be nil This array is holding several objects. Is there a quick way for me to find which of the objects I'm attempting to put into the array is nil?

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  • ADO program to list members of a large group.

    - by AlexGomez
    Hi everyone, I'm attempting to list all the members in a Active Directory group using ADO. The problem I have is that many of these groups have over 1500 members and ADSI cannot handle more than 1500 items in a multi-valued attribute. Fortunately I came across Richard Muller's wonderful VBScript that handles more than 1500 members at http://www.rlmueller.net/DocumentLargeGroup.htm I modified his code as shown below so that I can list ALL the groups and its memberships in a certain OU. However, I'm keeping getting the exception shown below: "ADODB.Recordset: Item cannot be found in the collection corresponding to the requested name or ordinal." My program appears to get stuck at: strPath = adoRecordset.Fields("ADsPath").Value Set objGroup = GetObject(strPath) All I am doing above is issuing the query to get back a recordset consisting of the ADsPath for each group in the OU. It then walks through the recordset and grabs the ADsPath for the first group and store its in a variable named strPath; we then use the value of that variable to bind to the group account for that group. It really should work! Any idea why the code below doesn't work for me? Any pointers will be great appreciated. Thanks. Option Explicit Dim objRootDSE, strDNSDomain, adoCommand Dim adoConnection, strBase, strAttributes Dim strFilter, strQuery, adoRecordset Dim strDN, intCount, blnLast, intLowRange Dim intHighRange, intRangeStep, objField Dim objGroup, objMember, strName ' Determine DNS domain name. Set objRootDSE = GetObject("LDAP://RootDSE") 'strDNSDomain = objRootDSE.Get("DefaultNamingContext") strDNSDomain = "XXXXXXXX" ' Use ADO to search Active Directory. Set adoCommand = CreateObject("ADODB.Command") Set adoConnection = CreateObject("ADODB.Connection") adoConnection.Provider = "ADsDSOObject" adoConnection.Open = "Active Directory Provider" adoCommand.ActiveConnection = adoConnection adoCommand.Properties("Page Size") = 100 adoCommand.Properties("Timeout") = 30 adoCommand.Properties("Cache Results") = False ' Specify base of search. strBase = "<LDAP://" & strDNSDomain & ">" ' Specify the attribute values to retrieve. strAttributes = "member" ' Filter on objects of class "group" strFilter = "(&(objectClass=group)(samAccountName=*))" ' Enumerate direct group members. ' Use range limits to handle more than 1000/1500 members. ' Setup to retrieve 1000 members at a time. blnLast = False intRangeStep = 999 intLowRange = 0 IntHighRange = intLowRange + intRangeStep Do While True If (blnLast = True) Then ' If last query, retrieve remaining members. strQuery = strBase & ";" & strFilter & ";" _ & strAttributes & ";range=" & intLowRange _ & "-*;subtree" Else ' If not last query, retrieve 1000 members. strQuery = strBase & ";" & strFilter & ";" _ & strAttributes & ";range=" & intLowRange & "-" _ & intHighRange & ";subtree" End If adoCommand.CommandText = strQuery Set adoRecordset = adoCommand.Execute adoRecordset.MoveFirst intCount = 0 Do Until adoRecordset.EOF strPath = adoRecordset.Fields("ADsPath").Value Set objGroup = GetObject(strPath) For Each objField In adoRecordset.Fields If (VarType(objField) = (vbArray + vbVariant)) _ Then For Each strDN In objField.Value ' Escape any forward slash characters, "/", with the backslash ' escape character. All other characters that should be escaped are. strDN = Replace(strDN, "/", "\/") ' Check dictionary object for duplicates. 'If (objGroupList.Exists(strDN) = False) Then ' Add to dictionary object. 'objGroupList.Add strDN, True ' Bind to each group member, to find member's samAccountName Set objMember = GetObject("LDAP://" & strDN) ' Output group cn, group samaAccountName and group member's samAccountName. Wscript.Echo objMember.samAccountName intCount = intCount + 1 'End if Next End If Next adoRecordset.MoveNext Loop adoRecordset.Close ' If this is the last query, exit the Do While loop. If (blnLast = True) Then Exit Do End If ' If the previous query returned no members, then the previous ' query for the next 1000 members failed. Perform one more ' query to retrieve remaining members (less than 1000). If (intCount = 0) Then blnLast = True Else ' Setup to retrieve next 1000 members. intLowRange = intHighRange + 1 intHighRange = intLowRange + intRangeStep End If Loop

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  • Divide a large amount of text on an arbitrary number of equal parts.

    - by kalininew
    I probably already fed up with their stupid questions, but I have one more question. I have a large piece of text <p> Sed ut perspiciatis, unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam eaque ipsa, quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt, explicabo. Nemo enim ipsam voluptatem, quia voluptas sit, </p> <p> aspernatur aut odit aut fugit, sed quia consequuntur magni dolores eos, qui ratione voluptatem sequi nesciunt, neque porro quisquam est, qui dolorem ipsum, quia dolor sit, amet, consectetur, adipisci velit, sed quia non numquam eius modi tempora incidunt, ut labore et dolore magnam aliquam quaerat voluptatem. Ut enim ad minima veniam, quis nostrum exercitationem ullam corporis suscipit laboriosam, nisi ut aliquid ex ea commodi consequatur? </p> <p> Quis autem vel eum iure reprehenderit, qui in ea voluptate velit esse, quam nihil molestiae consequatur, vel illum, qui dolorem eum fugiat, quo voluptas nulla pariatur? At vero eos et accusamus et iusto odio dignissimos ducimus, qui blanditiis praesentium voluptatum deleniti atque corrupti, quos dolores et quas molestias excepturi sint, obcaecati cupiditate non provident, similique sunt in culpa, qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum </p> <p> soluta nobis est eligendi optio, cumque nihil impedit, quo minus id, quod maxime placeat, facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Temporibus autem quibusdam et aut officiis debitis aut rerum necessitatibus saepe eveniet, ut et voluptates repudiandae sint et molestiae non recusandae. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat. </p> <p> Sed ut perspiciatis, unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam eaque ipsa, quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt, explicabo. Nemo enim ipsam voluptatem, quia voluptas sit, </p> <p> Sed ut perspiciatis, unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam eaque ipsa, quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt, explicabo. Nemo enim ipsam voluptatem, quia voluptas sit, </p> <p> aspernatur aut odit aut fugit, sed quia consequuntur magni dolores eos, qui ratione voluptatem sequi nesciunt, neque porro quisquam est, qui dolorem ipsum, quia dolor sit, amet, consectetur, adipisci velit, sed quia non numquam eius modi tempora incidunt, ut labore et dolore magnam aliquam quaerat voluptatem. Ut enim ad minima veniam, quis nostrum exercitationem ullam corporis suscipit laboriosam, nisi ut aliquid ex ea commodi consequatur? </p> <p> Quis autem vel eum iure reprehenderit, qui in ea voluptate velit esse, quam nihil molestiae consequatur, vel illum, qui dolorem eum fugiat, quo voluptas nulla pariatur? At vero eos et accusamus et iusto odio dignissimos ducimus, qui blanditiis praesentium voluptatum deleniti atque corrupti, quos dolores et quas molestias excepturi sint, obcaecati cupiditate non provident, similique sunt in culpa, qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum </p> <p> soluta nobis est eligendi optio, cumque nihil impedit, quo minus id, quod maxime placeat, facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Temporibus autem quibusdam et aut officiis debitis aut rerum necessitatibus saepe eveniet, ut et voluptates repudiandae sint et molestiae non recusandae. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat. </p> <p> Quis autem vel eum iure reprehenderit, qui in ea voluptate velit esse, quam nihil molestiae consequatur, vel illum, qui dolorem eum fugiat, quo voluptas nulla pariatur? At vero eos et accusamus et iusto odio dignissimos ducimus, qui blanditiis praesentium voluptatum deleniti atque corrupti, quos dolores et quas molestias excepturi sint, obcaecati cupiditate non provident, similique sunt in culpa, qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum </p> <p> Sed ut perspiciatis, unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam eaque ipsa, quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt, explicabo. Nemo enim ipsam voluptatem, quia voluptas sit, </p> <p> soluta nobis est eligendi optio, cumque nihil impedit, quo minus id, quod maxime placeat, facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Temporibus autem quibusdam et aut officiis debitis aut rerum necessitatibus saepe eveniet, ut et voluptates repudiandae sint et molestiae non recusandae. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat. </p> <p> Sed ut perspiciatis, unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam eaque ipsa, quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt, explicabo. Nemo enim ipsam voluptatem, quia voluptas sit, </p> At the exit I need to divide the text on the "n" equal parts, so that in these parts was about the same amount of text. Then I these part are arranged in columns and the need for these columns look about the same height. Another condition: Tags you can break (I mean that if the tag "p" contains a lot of text, it can be divided into two parts, to bring in another column). I think this is a monumental task, I shall be grateful for any help.

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