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  • Regular Expression With Mask

    - by Kumar
    I have a regular expression for phone numbers as follows: ^[01]?[- .]?(\([2-9]\d{2}\)|[2-9]\d{2})[- .]?\d{3}[- .]?\d{4}$ I have a mask on the phone number textbox in the following format: (___)___-____ How can I modify the regular expression so that it accommodates the mask?

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  • UPDATE REGEX MYSQL

    - by Simon
    I have a table of contacts and a table of postcode data. I need to match the first part of the postcode and the join that with the postcode table... and then perform an update... I want to do something like this... UPDATE `contacts` LEFT JOIN `postcodes` ON PREG_GREP("/^[A-Z]{1,2}[0-9][0-9A-Z]{0,1}/", `contacts`.`postcode`) = `postcodes`.`postcode` SET `contacts`.`lat` = `postcode`.`lat`, `contacts`.`lng` = `postcode`.`lng` Is it possible?? Or do I need to use an external script? Many thanks.

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  • Tikz: horizontal centering of group of nodes

    - by mindhex
    Hi, I need to align each row of the graph to the center. I am trying to do it with xshift. Here the code: \begin{tikzpicture}[node distance=1.5cm, auto, text centered] \tikzstyle{every node}=[draw,ball,align=center]; \begin{scope}[xshift=1.5cm] \node (A) {A}; \node [right of=A] (B) {B}; \node [right of=B] (C) {C}; \node [right of=C] (D) {D}; \end{scope} \begin{scope}[yshift=-1.5cm] \node (AB) {AB}; \node [right of=AB] (AC) {AC}; \node [right of=AC] (AD) {AD}; \node [right of=AD] (BC) {BC}; \node [right of=BC] (BD) {BD}; \node [right of=BD] (CD) {CD}; \end{scope} \begin{scope}[yshift=-3cm,node distance=2cm,xshift=1cm] \node (ABC) {ABC}; \node [right of=ABC] (ABD) {ABD}; \node [right of=ABD] (ACD) {ACD}; \node [right of=ACD] (BCD) {BCD}; \end{scope} \begin{scope}[xshift=4cm, yshift=-4.5cm, node distance=2cm] \node (ABCD) {ABCD}; \end{scope} \end{tikzpicture} Is there any other way to do it? Do not like to change xshift values every time.

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  • Can't find my bug: Group flat data in Advanced Datagrid w'ont work

    - by Werner
    Hi, i've got an ArrayCollection which is properly displayed in this Advanced Datagrid: <mx:AdvancedDataGrid id="drawingDataDG" editable="true" sortableColumns="true" headerWordWrap="true" sortExpertMode="true" rowCount="8" y="10" right="10" left="10" dataProvider="{model.drawingsData}"> <mx:columns> <mx:AdvancedDataGridColumn headerText="Approved in Week" dataField="ApprovedInWeek" editable="false" visible="true" /> <mx:AdvancedDataGridColumn headerText="DRAWING_PK" dataField="DRAWING_PK" editable="false" visible="false" /> <mx:AdvancedDataGridColumn headerText="Drawing No" dataField="DRAWING_NO" editable="false" visible="true"/> <mx:AdvancedDataGridColumn headerText="Drawing Index" dataField="DRAWING_INDEX" editable="false" visible="true"/> </mx:columns> ` According to this explanation link text I've implemented a GroupingCollection. But it just don't work??? <mx:AdvancedDataGrid id="drawingDataDG" editable="true" sortableColumns="true" headerWordWrap="true" sortExpertMode="true" rowCount="8" y="10" right="10" left="10" initialize="gc.refresh();"> <mx:dataProvider> <mx:GroupingCollection id="gc" source="{model.drawingsData}"> <mx:Grouping> <mx:GroupingField name="ApprovedInWeek"/> </mx:Grouping> </mx:GroupingCollection> </mx:dataProvider> <mx:columns> <mx:AdvancedDataGridColumn headerText="Approved in Week" dataField="ApprovedInWeek" editable="false" visible="true" /> <mx:AdvancedDataGridColumn headerText="DRAWING_PK" dataField="DRAWING_PK" editable="false" visible="false" /> <mx:AdvancedDataGridColumn headerText="Drawing No" dataField="DRAWING_NO" editable="false" visible="true"/> <mx:AdvancedDataGridColumn headerText="Drawing Index" dataField="DRAWING_INDEX" editable="false" visible="true"/> </mx:columns> </mx:AdvancedDataGrid> Please let me know what additional details you may need? Werner

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  • JavaScript: Given an offset and substring length in an HTML string, what is the parent node?

    - by Bungle
    My current project requires locating an array of strings within an element's text content, then wrapping those matching strings in <a> elements using JavaScript (requirements simplified here for clarity). I need to avoid jQuery if at all possible - at least including the full library. For example, given this block of HTML: <div> <p>This is a paragraph of text used as an example in this Stack Overflow question.</p> </div> and this array of strings to match: ['paragraph', 'example'] I would need to arrive at this: <div> <p>This is a <a href="http://www.example.com/">paragraph</a> of text used as an <a href="http://www.example.com/">example</a> in this Stack Overflow question.</p> </div> I've arrived at a solution to this by using the innerHTML() method and some string manipulation - basically using the offsets (via indexOf()) and lengths of the strings in the array to break the HTML string apart at the appropriate character offsets and insert <a href="http://www.example.com/"> and </a> tags where needed. However, an additional requirement has me stumped. I'm not allowed to wrap any matched strings in <a> elements if they're already in one, or if they're a descendant of a heading element (<h1> to <h6>). So, given the same array of strings above and this block of HTML (the term matching has to be case-insensitive, by the way): <div> <h1>Example</a> <p>This is a <a href="http://www.example.com/">paragraph of text</a> used as an example in this Stack Overflow question.</p> </div> I would need to disregard both the occurrence of "Example" in the <h1> element, and the "paragraph" in <a href="http://www.example.com/">paragraph of text</a>. This suggests to me that I have to determine which node each matched string is in, and then traverse its ancestors until I hit <body>, checking to see if I encounter a <a> or <h_> node along the way. Firstly, does this sound reasonable? Is there a simpler or more obvious approach that I've failed to consider? It doesn't seem like regular expressions or another string-based comparison to find bounding tags would be robust - I'm thinking of issues like self-closing elements, irregularly nested tags, etc. There's also this... Secondly, is this possible, and if so, how would I approach it?

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  • strange behavior in vim with negative look-behind

    - by João Portela
    So, I am doing this search in vim: /\(\(unum\)\|\(player\)=\)\@<!\"1\" and as expected it does not match lines that have: player="1" but matches lines that have: unum="1" what am i doing wrong? isn't the atom to be negated all of this: \(\(unum\)\|\(player\)=\) naturally just doing: /\(\(unum\)\|\(player\)=\) matches unum= or player=.

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  • Building a Hashtag in Javascript without matching Anchor Names, BBCode or Escaped Characters

    - by Martindale
    I would like to convert any instances of a hashtag in a String into a linked URL: #hashtag - should have "#hashtag" linked. This is a #hashtag - should have "#hashtag" linked. This is a [url=http://www.mysite.com/#name]named anchor[/url] - should not be linked. This isn&#39;t a pretty way to use quotes - should not be linked. Here is my current code: String.prototype.parseHashtag = function() { return this.replace(/[^&][#]+[A-Za-z0-9-_]+(?!])/, function(t) { var tag = t.replace("#","") return t.link("http://www.mysite.com/tag/"+tag); }); }; Currently, this appears to fix escaped characters (by excluding matches with the amperstand), handles named anchors, but it doesn't link the #hashtag if it's the first thing in the message, and it seems to grab include the 1-2 characters prior to the "#" in the link. Halp!

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  • sql query to return items based on text and group ID

    - by mattgcon
    I am not sure how to best describe what I am trying to do (or search for it for that matter) but I am going to try. I have a pre-existing query (stored procedure) that returns items based on 3 specific ID's. What I want to do is to be able to reduce the results even further based upon a column within the results having the exact same string. For some reason I am confused about how to do this, I am drawing a complete blank about this. Please help

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  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

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  • In Python BeautifulSoup How to move tags

    - by JJ
    I have a partially converted XML document in soup coming from HTML. After some replacement and editing in the soup, the body is essentially - <Text...></Text> # This replaces <a href..> tags but automatically creates the </Text> <p class=norm ...</p> <p class=norm ...</p> <Text...></Text> <p class=norm ...</p> and so forth. I need to "move" the <p> tags to be children to <Text> or know how to suppress the </Text>. I want - <Text...> <p class=norm ...</p> <p class=norm ...</p> </Text> <Text...> <p class=norm ...</p> </Text> I've tried using item.insert and item.append but I'm thinking there must be a more elegant solution. for item in soup.findAll(['p','span']): if item.name == 'span' and item.has_key('class') and item['class'] == 'section': xBCV = short_2_long(item._getAttrMap().get('value','')) if currentnode: pass currentnode = Tag(soup,'Text', attrs=[('TypeOf', 'Section'),... ]) item.replaceWith(currentnode) # works but creates end tag elif item.name == 'p' and item.has_key('class') and item['class'] == 'norm': childcdatanode = None for ahref in item.findAll('a'): if childcdatanode: pass newlink = filter_hrefs(str(ahref)) childcdatanode = Tag(soup, newlink) ahref.replaceWith(childcdatanode) Thanks

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  • Transforming a string to a valid PDO_MYSQL DSN

    - by Alix Axel
    What is the most concise way to transform a string in the following format: mysql:[/[/]][user[:pass]@]host[:port]/db[/] Into a usuable PDO connection/instance (using the PDO_MYSQL DSN), some possible examples: $conn = new PDO('mysql:host=host;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user', 'pass'); I've been trying some regular expressions (preg_[match|split|replace]) but they either don't work or are too complex, my gut tells me this is not the way to go but nothing else comes to my mind. Any suggestions?

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  • Group keywords by site

    - by Skudd
    I am finding a lot of useful help here today, and I really appreciate it. This should be the last one for the day: I have a list of the top 10 keywords per site, sorted by visits, by date. The records need to be sorted as follows (excuse the formatting): 2010-05 2010-04 site1.com keyword1 apples wine keyword1 visits 100 12 keyword2 oranges water keyword2 visits 99 10 site2.com keyword1 blueberry cornbread keyword1 visits 90 100 keyword2 squares biscuits keyword2 visits 80 99 Basically what I need to accomplish involves grouping, but I can't seem to figure it out. Am I heading down the right path, or is there another way to achieve this, or is it just impossible?

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  • How do I locate a particular word in a text file using .NET

    - by cmrhema
    I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that?

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  • Convert regular expression to CFG

    - by user242581
    How can I convert some regular language to its equivalent Context Free Grammar(CFG)? Whether the DFA corresponding to that regular expression is required to be constructed or is there some rule for the above conversion? For example, considering the following regular expression 01+10(11)* How can I describe the grammar corresponding to the above RE?

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  • Not-quite-JSON string deserialization in Python

    - by cpharmston
    I get the following text as a string from an XML-based REST API 'd':4 'ca':5 'sen':1 'diann':2,6,8 'feinstein':3,7,9 that I'm looking to deserialize into a pretty little Python dictionary: { 'd': [4], 'ca': [5], 'sen': [1], 'diann': [2, 6, 8], 'feinstein': [3, 7, 9] } I'm hoping to avoid using regular expressions or heavy string manipulation, as this format isn't documented and may change. The best I've been able to come up with: members = {} for m in elem.text.split(' '): m = m.split(':') members[m[0].replace("'", '')] = map(int, m[1].split(',')) return members Obviously a terrible approach, but it works, and that's better than anything else I've got right now. Any suggestions on better approaches?

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  • Cleaning strings in R: add punctuation w/o overwriting last character

    - by spearmint
    I'm new to R and unable to find other threads with a similar issue. I'm cleaning data that requires punctuation at the end of each line. I am unable to add, say, a period without overwriting the final character of the line preceding the carriage return + line feed. Sample code: Data1 <- "%trn: dads sheep\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Data2 <- gsub("[^[:punct:]]\r\n\\*", ".\r\n\\*", Data1) The contents of Data2: [1] "%trn: dads shee.\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Notice the "p" of sheep was overwritten with the period. Any thoughts on how I could avoid this?

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  • Invert regexp in vim

    - by Chris J
    There's a few "how do I invert a regexp" questions here on stackoverflow, but I can't find one for vim (if it does exist, by goggle-fu is lacking today). In essence I want to match all non-printable characters and delete them. I could write a short script, or drop to a shell and use tr or something similar to delete, but a vim solution would be dandy :-) Vim has the atom \p to match printable characters, however trying to do this :s/[^\p]//g to match the inverse failed and just left me with every 'p' in the file. I've seen the (?!xxx) sequence in other questions, and vim seems to not recognise this sequence. I've not found seen an atom for non-printable chars. In the interim, I'm going to drop to external tools, but if anyone's got any trick up their sleeve to do this, it'd be welcome :-) Ta!

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