Search Results

Search found 5772 results on 231 pages for 'django exceptions'.

Page 14/231 | < Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >

  • Why use Django on Google App Engine?

    - by Travis Bradshaw
    When researching Google App Engine (GAE), it's clear that using Django is wildly popular for developing in Python on GAE. I've been scouring the web to find information on the costs and benefits of using Django, to find out why it's so popular. While I've been able to find a wide variety of sources on how to run Django on GAE and the various methods of doing so, I haven't found any comparative analysis on why Django is preferable to using the webapp framework provided by Google. To be clear, it's immediately apparent why using Django on GAE is useful for developers with an existing skillset in Django (a majority of Python web developers, no doubt) or existing code in Django (where using GAE is more of a porting exercise). My team, however, is evaluating GAE for use on an all-new project and our existing experience is with TurboGears, not Django. It's been quite difficult to determine why Django is beneficial to a development team when the BigTable libraries have replaced Django's ORM, sessions and authentication are necessarily changed, and Django's templating (if desirable) is available without using the entire Django stack. Finally, it's clear that using Django does have the advantage of providing an "exit strategy" if we later wanted to move away from GAE and need a platform to target for the exodus. I'd be extremely appreciative for help in pointing out why using Django is better than using webapp on GAE. I'm also completely inexperienced with Django, so elaboration on smaller features and/or conveniences that work on GAE are also valuable to me. Thanks in advance for your time!

    Read the article

  • Django vs GAE + Django vs GAE + other framework

    - by Ilian Iliev
    I`m looking for opinion which one is better for building web applications(web sites). I have some experience with Django, and some with Google App Engine and App-Engine-Patch for Django. And it seems to me that only Django is working faster than the GAE implementation. Is there some other frameworks that simplify the developments process, providing forms creating, user management, url resolving etc. Thanks in advance, Ilian Iliev P.S. I am also interested in GAE and webapp framework case

    Read the article

  • Google App Engine + Form Validation

    - by Iwona
    Hi, I would like to do google app engine form validation but I dont know how to do it? I tried like this: from google.appengine.ext.db import djangoforms from django import newforms as forms class SurveyForm(forms.Form): occupations_choices = ( ('1', ""), ('2', "Undergraduate student"), ('3', "Postgraduate student (MSc)"), ('4', "Postgraduate student (PhD)"), ('5', "Lab assistant"), ('6', "Technician"), ('7', "Lecturer"), ('8', "Other" ) ) howreach_choices = ( ('1', ""), ('2', "Typed the URL directly"), ('3', "Site is bookmarked"), ('4', "A search engine"), ('5', "A link from another site"), ('6', "From a book"), ('7', "Other") ) boxes_choices = ( ("des", "Website Design"), ("svr", "Web Server Administration"), ("com", "Electronic Commerce"), ("mkt", "Web Marketing/Advertising"), ("edu", "Web-Related Education") ) name = forms.CharField(label='Name', max_length=100, required=True) email = forms.EmailField(label='Your Email Address:') occupations = forms.ChoiceField(choices=occupations_choices, label='What is your occupation?') howreach = forms.ChoiceField(choices=howreach_choices, label='How did you reach this site?') # radio buttons 1-5 rating = forms.ChoiceField(choices=range(1,6), label='What is your occupation?', widget=forms.RadioSelect) boxes = forms.ChoiceField(choices=boxes_choices, label='Are you involved in any of the following? (check all that apply):', widget=forms.CheckboxInput) comment = forms.CharField(widget=forms.Textarea, required=False) And I wanted to display it like this: template_values = { 'url' : url, 'url_linktext' : url_linktext, 'userName' : userName, 'item1' : SurveyForm() } And I have this error message: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp_init_.py", line 515, in call handler.get(*groups) File "C:\Program Files\Google\google_appengine\demos\b00213576\main.py", line 144, in get self.response.out.write(template.render(path, template_values)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 143, in render return t.render(Context(template_dict)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 183, in wrap_render return orig_render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 168, in render return self.nodelist.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template\defaulttags.py", line 209, in render return self.nodelist_true.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 768, in render return self.encode_output(output) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 757, in encode_output return str(output) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 73, in unicode return self.as_table() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 144, in as_table return self._html_output(u'%(label)s%(errors)s%(field)s%(help_text)s', u'%s', '', u'%s', False) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 129, in _html_output output.append(normal_row % {'errors': bf_errors, 'label': label, 'field': unicode(bf), 'help_text': help_text}) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 232, in unicode value = value.str() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 246, in unicode return u'\n%s\n' % u'\n'.join([u'%s' % w for w in self]) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 238, in iter yield RadioInput(self.name, self.value, self.attrs.copy(), choice, i) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 212, in init self.choice_value = smart_unicode(choice[0]) TypeError: 'int' object is unsubscriptable Do You have any idea how I can do this validation in different case? I have tried to do it using this kind of: class ItemUserAnswer(djangoforms.ModelForm): class Meta: model = UserAnswer But I dont know how to add extra labels to this form and it is displayed in one line. Do You have any suggestions? Thanks a lot as it making me crazy why it is still not working:/

    Read the article

  • Django simple syndication example gives: ImportError, cannot import name Feed

    - by AP257
    I'm trying to set up the simple syndication example from the Django docs, in a working project. But I'm getting an ImportError, even though I'm sure I've copied the example exactly. Here's what I have in feeds.py: from django.contrib.syndication.views import Feed class LatestEntriesFeed(Feed): # etc And here's what I have in urls.py: from election.feeds import LatestEntriesFeed #... further down, at the appropriate line... # RSS feed (r'^feed/$', LatestEntriesFeed()), But Django says it can't import the Feed class from django.contrib.syndication.views: ImportError at /feed/ cannot import name Feed ....feeds.py in <module> from django.contrib.syndication.views import Feed Any ideas? I'm baffled!

    Read the article

  • url template tag in django template

    - by user192048
    guys: I was trying to use the url template tag in django, but no lucky, I defined my urls.py like this urlpatterns = patterns('', url(r'^analyse/$', views.home, name="home"), url(r'^analyse/index.html', views.index, name="index"), url(r'^analyse/setup.html', views.setup, name="setup"), url(r'^analyse/show.html', views.show, name="show"), url(r'^analyse/generate.html', views.generate, name="generate"), I defined the url pattern in my view like this {% url 'show'%} then I got this error message Caught an exception while rendering: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. Original Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/template/debug.py", line 71, in render_node result = node.render(context) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 155, in render nodelist.append(node.render(context)) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 382, in render raise e NoReverseMatch: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. I am wondering why django failed to render? what is the right way to define it in the tempalte?

    Read the article

  • Django syncdb not making tables for my app

    - by Rosarch
    It used to work, and now it doesn't. python manage.py syncdb no longer makes tables for my app. From settings.py: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'mysite.myapp', 'django.contrib.admin', ) What could I be doing wrong? The break appeared to coincide with editing this model in models.py, but that could be total coincidence. I commented out the lines I changed, and it still doesn't work. class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(Course, through=TakingCourse, blank=True) school = models.ForeignKey(School) # minCreditsPerTerm = models.IntegerField(blank=True) # maxCreditsPerTerm = models.IntegerField(blank=True) # optimalCreditsPerTerm = models.IntegerField(blank=True) UPDATE: When I run python manage.py loadddata initial_data, it gives an error: DeserializationError: Invalid model identifier: myapp.SomeModel Loading this data had worked fine before. This error is thrown on the very first data object in the data file.

    Read the article

  • Django ORM and PostgreSQL connection limits

    - by bennylope
    I'm running a Django project on Postgresql 8.1.21 (using Django 1.1.1, Python2.5, psycopg2, Apache2 with mod_wsgi 3.2). We've recently encountered this lovely error: OperationalError: FATAL: connection limit exceeded for non-superusers I'm not the first person to run up against this. There's a lot of discussion about this error, specifically with psycopg, but much of it centers on older versions of Django and/or offer solutions involving edits to code in Django itself. I've yet to find a succinct explanation of how to solve the problem of the Django ORM (or psycopg, whichever is really responsible, in this case) leaving open Postgre connections. Will simply adding connection.close() at the end of every view solve this problem? Better yet, has anyone conclusively solved this problem and kicked this error's ass?

    Read the article

  • View centric design with Django

    - by wishi_
    Hi! I'm relatively new to Django and I'm designing a website that primarily needs usability experience, speaking of optimized CSS, HTML5 and UI stuff. It's very easy to use Django for data/Model centric design. Just designing a couple of Python classes and ./manage.py syncdb - there's your Model. But I'm dealing with a significant amount of View centric challenges. (Different user classes, different tasks, different design challenges.) The official Django tutorial cursorily goes through using a "Template". Is there any Design centric guide for Django, or a set of Templates that are ready and useable? I don't want to start from scratch using JS, HTML5, Ajax and everything. From the Model layer perspective Django is very rapid and delivering a working base system. I wonder whether there's something like that for the Views.

    Read the article

  • django newbie question : cant start a new project

    - by Moayyad Yaghi
    hello . I'm totally new to django . and I'm using its documentation to get help on how to use it but seems like something is missing. i installed django using setup.py install command and i added the ( django/bin ) to system path variable but. i still cant start a new project i use the following syntax to start a project : django-admin.py startproject myNewProject but it says Type 'django-admin.py help' for usage. 1 do i miss anything ? thank u

    Read the article

  • Django Form for date range

    - by gramware
    I am trying to come up with a form that lets the user select a date range to generate a web query in Django. I am having errors getting the date to filter with in my view, I am unable to strip the date. Here is my forms.py class ReportFiltersForm(forms.Form): start_date = forms.DateField(input_formats='%Y,%m,%d',widget=SelectDateWidget()) end_date = forms.DateField(input_formats='%Y,%m,%d',widget=SelectDateWidget()) And my view if request.method == 'POST': form = ReportFiltersForm(request.POST) sdy = request.POST['start_date_year'] sdm = request.POST['start_date_month'] sdd = request.POST['start_date_day'] edy = request.POST['end_date_year'] edm = request.POST['end_date_month'] edd = request.POST['end_date_day'] start_date= datetime.date(sdy, sdm, sdd) end_date= datetime.date(edy, edm,edd) Traceback Traceback (most recent call last): File "/usr/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 651, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 134, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 154, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 92, in get_response response = callback(request, *callback_args, **callback_kwargs) File "/home/projects/acms/cms/views.py", line 470, in eventreports start_date= datetime.date(sdy, sdm, sdd) TypeError: an integer is required

    Read the article

  • Detect the language & django locale-url

    - by mamcx
    I want to deploy a website in english & spanish and detect the user browser languaje & redirect to the correct locale site. My site is www.elmalabarista.com I install django-localeurl, but I discover that the languaje is not correctly detected. This are my middlewares: MIDDLEWARE_CLASSES = ( 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.locale.LocaleMiddleware', 'multilingual.middleware.DefaultLanguageMiddleware', 'middleware.feedburner.FeedburnerMiddleware', 'lib.threadlocals.ThreadLocalsMiddleware', 'middleware.url.UrlMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'maintenancemode.middleware.MaintenanceModeMiddleware', 'middleware.redirect.RedirectMiddleware', 'openidconsumer.middleware.OpenIDMiddleware', 'django.middleware.doc.XViewMiddleware', 'middleware.ajax_errors.AjaxMiddleware', 'pingback.middleware.PingbackMiddleware', 'localeurl.middleware.LocaleURLMiddleware', 'multilingual.flatpages.middleware.FlatpageFallbackMiddleware', 'django.middleware.common.CommonMiddleware', ) But ALWAYS the site get to US despite the fact my OS & Browser setup is spanish. LANGUAGES = ( ('en', ugettext('English')), ('es', ugettext('Spanish')), ) DEFAULT_LANGUAGE = 1 Then, I hack the middleware of locale-url and do this: def process_request(self, request): locale, path = self.split_locale_from_request(request) if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path if not locale: locale = settings.LANGUAGE_CODE translation.activate(locale) request.LANGUAGE_CODE = translation.get_language() However, this detect fine the language but redirect the "en" urls to "es". So is impossible navigate in english. UPDATE: This is the final code (after the input from Carl Meyer) with a fix for the case of "/": def process_request(self, request): locale, path = self.split_locale_from_request(request) if (not locale) or (locale==''): if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) else: locale = settings.LANGUAGE_CODE locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path translation.activate(locale) request.LANGUAGE_CODE = translation.get_language()

    Read the article

  • UnicodeDecodeError on attempt to save file through django default filebased backend

    - by Ivan Kuznetsov
    When i attempt to add a file with russian symbols in name to the model instance through default instance.file_field.save method, i get an UnicodeDecodeError (ascii decoding error, not in range (128) from the storage backend (stacktrace ended on os.exist). If i write this file through default python file open/write all goes right. All filenames in utf-8. I get this error only on testing Gentoo, on my Ubuntu workstation all works fine. class Article(models.Model): file = models.FileField(null=True, blank=True, max_length = 300, upload_to='articles_files/%Y/%m/%d/') Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/auth/decorators.py" in _wrapped_view 24. return view_func(request, *args, **kwargs) File "/var/www/localhost/help/wiki/views.py" in edit_article 338. new_article.file.save(fp, fi, save=True) File "/usr/lib/python2.6/site-packages/django/db/models/fields/files.py" in save 92. self.name = self.storage.save(name, content) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in save 47. name = self.get_available_name(name) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in get_available_name 73. while self.exists(name): File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in exists 196. return os.path.exists(self.path(name)) File "/usr/lib/python2.6/genericpath.py" in exists 18. st = os.stat(path) Exception Type: UnicodeEncodeError at /edit/ Exception Value: ('ascii', u'/var/www/localhost/help/i/articles_files/2010/03/17/\u041f\u0440\u0438\u0432\u0435\u0442', 52, 58, 'ordinal not in range(128)')

    Read the article

  • What's the reason exceptions are heavily used in managed (C# and Java) languages but not in C++? [on hold]

    - by ZijingWu
    AFAIK, a lot of C++ projects don't allow exceptions and deny them in coding guidelines. I have a lot of reasons, for example, exception is hard to handle correctly if your binary needs to be compiled by separate and different compilers. But it doesn't fully convince me, there is a lot of projects which are just using one compiler. Compared to C++, exceptions are heavily used in C# and Java and the reason can only be that exception are not bringing enough benefit. One point is debugbility in practice. Exception can not get the call stack in C++ code, but in C# and Java you can get the call stack from exception, it is significant and makes debugging easier. No-callstack is not the fault of the exception, it is the language difference, but it impacts the exception usage. So what's the reason that exceptions are frowned upon in c++ programs?

    Read the article

  • Django facebook integration error

    - by Gaurav
    I'm trying to integrate facebook into my application so that users can use their FB login to login to my site. I've got everything up and running and there are no issues when I run my site using the command line python manage.py runserver But this same code refuses to run when I try and run it through Apache. I get the following error: Environment: Request Method: GET Request URL: http://helvetica/foodfolio/login Django Version: 1.1.1 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'foodfolio.app', 'foodfolio.facebookconnect'] Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'facebook.djangofb.FacebookMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebookconnect.middleware.FacebookConnectMiddleware') Template error: In template /home/swat/website-apps/foodfolio/facebookconnect/templates/facebook/js.html, error at line 2 Caught an exception while rendering: No module named app.models 1 : <script type="text/javascript"> 2 : FB_RequireFeatures(["XFBML"], function() {FB.Facebook.init("{{ facebook_api_key }}", " {% url facebook_xd_receiver %} ")}); 3 : 4 : function facebookConnect(loginForm) { 5 : FB.Connect.requireSession(); 6 : FB.Facebook.get_sessionState().waitUntilReady(function(){loginForm.submit();}); 7 : } 8 : function pushToFacebookFeed(data){ 9 : if(data['success']){ 10 : var template_data = data['template_data']; 11 : var template_bundle_id = data['template_bundle_id']; 12 : feedTheFacebook(template_data,template_bundle_id,function(){}); Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/swat/website-apps/foodfolio/app/controller.py" in __showLogin__ 238. context_instance = RequestContext(request)) File "/usr/lib/pymodules/python2.6/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/usr/lib/pymodules/python2.6/django/template/loader.py" in render_to_string 108. return t.render(context_instance) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 178. return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 71. result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 946. autoescape=context.autoescape)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 81. raise wrapped Exception Type: TemplateSyntaxError at /foodfolio/login Exception Value: Caught an exception while rendering: No module named app.models

    Read the article

  • Javascript error when integrating django-tinymce and django-filebrowser

    - by jwesonga
    I've set up django-filebrowser in my app without any bugs, I already had django-tinymce set up and it loads the editor in the admin forms. I now want to use django-filebrowser with django-tinymce, but I keep getting a weird javascript error when I click on "Image URL" in the Image popup: r is undefined the error is js/tiny_mce/tiny_mce.js My settings.py file has the following configuration: TINYMCE_JS_URL=MEDIA_URL + 'js/tiny_mce/tiny_mce.js' TINYMCE_DEFAULT_CONFIG = { 'mode': "textareas", 'theme': "advanced", 'language': "en", 'skin': "o2k7", 'dialog_type': "modal", 'object_resizing': True, 'cleanup_on_startup': True, 'forced_root_block': "p", 'remove_trailing_nbsp': True, 'theme_advanced_toolbar_location': "top", 'theme_advanced_toolbar_align': "left", 'theme_advanced_statusbar_location': "none", 'theme_advanced_buttons1': "formatselect,styleselect,bold,italic,underline,bullist,numlist,undo,redo,link,unlink,image,code,template,visualchars,fullscreen,pasteword,media,search,replace,charmap", 'theme_advanced_buttons2': "", 'theme_advanced_buttons3': "", 'theme_advanced_path': False, 'theme_advanced_blockformats': "p,h2,h3,h4,div,code,pre", 'width': '700', 'height': '300', 'plugins': "advimage,advlink,fullscreen,visualchars,paste,media,template,searchreplace", 'advimage_update_dimensions_onchange': True, 'file_browser_callback': "CustomFileBrowser", 'relative_urls': False, 'valid_elements' : "" + "-p," + "a[href|target=_blank|class]," + "-strong/-b," + "-em/-i," + "-u," + "-ol," + "-ul," + "-li," + "br," + "img[class|src|alt=|width|height]," + "-h2,-h3,-h4," + "-pre," + "-code," + "-div", 'extended_valid_elements': "" + "a[name|class|href|target|title|onclick]," + "img[class|src|border=0|alt|title|hspace|vspace|width|height|align|onmouseover|onmouseout|name]," + "br[clearfix]," + "-p[class<clearfix?summary?code]," + "h2[class<clearfix],h3[class<clearfix],h4[class<clearfix]," + "ul[class<clearfix],ol[class<clearfix]," + "div[class]," } TINYMCE_FILEBROWSER = False TINYMCE_COMPRESSOR = False i've tried switching back to older versions of tinyMCE Javascript but nothing seems to work. Would appreciate some help

    Read the article

  • While trying to set up Django on Windows: AttributeError: 'Settings' object has no attribute 'DATABA

    - by user326370
    I'm following these instructions in order to set up Django on Windows. I have installed Python 2.6, PostgreSQL 8.4, Psycopg 2.0.14 for Python 2.6 and the latest version of Django from SVN. I'm now following these instructions to run a test project (copied from the page linked to above): C:\Documents and Settings\John>cd C:\ C:\>mkdir django C:\>cd django C:\django>django-admin.py startproject testproject C:\django>cd testproject C:\django\testproject>python manage.py runserver When I run the last line, this is the output: Validating models... Unhandled exception in thread started by <function inner_run at 0x01ECB930> Traceback (most recent call last): File "J:\Python26\lib\site-packages\django\core\management\commands\runserver.py", line 48, in inn er_run self.validate(display_num_errors=True) File "J:\Python26\lib\site-packages\django\core\management\base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "J:\Python26\lib\site-packages\django\core\management\validation.py", line 22, in get_validat ion_errors from django.db import models, connection File "J:\Python26\lib\site-packages\django\db\__init__.py", line 14, in <module> if not settings.DATABASES: File "J:\Python26\lib\site-packages\django\utils\functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'DATABASES' Did I forget to do something with the database? Any help will be appreciated. Thank you!

    Read the article

  • How to do custom display and auto-select in django admin multi-select field?

    - by rsp
    I'm new to django, so please feel free to tell me if I'm doing this incorrectly. I am trying to create a django ordering system. My order model: class Order(models.Model): ordered_by = models.ForeignKey(User, limit_choices_to = {'groups__name': "Managers", 'is_active': 1}) in my admin ANY user can enter an order, but ordered_by must be someone in the group "managers" (this is the behavior I want). Now, if the logged in user happens to be a manager I want it to automatically fill in the field with that logged in user. I have accomplished this by: class OrderAdmin(admin.ModelAdmin): def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == "ordered_by": if request.user in User.objects.filter(groups__name='Managers', is_active=1): kwargs["initial"] = request.user.id kwargs["empty_label"] = "-------------" return db_field.formfield(**kwargs) return super(OrderAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) This also works, but the admin puts the username as the display for the select box by default. It would be nice to have the user's real name listed. I was able to do it with this: class UserModelMultipleChoiceField(forms.ModelMultipleChoiceField): def label_from_instance(self, obj): return obj.first_name + " " + obj.last_name class OrderForm(forms.ModelForm): ordered_by = UserModelChoiceField(queryset=User.objects.all().filter(groups__name='Managers', is_active=1)) class OrderAdmin(admin.ModelAdmin): form = OrderForm My problem: I can't to both of these. If I put in the formfield_for_foreignkey function and add form = OrderForm to use my custom "UserModelChoiceField", it puts the nice name display but it won't select the currently logged in user. I'm new to this, but my guess is that when I use UserModelChoiceField it "erases" the info passed in via formfield_for_foreignkey. Do I need to use the super() function somehow to pass on this info? or something completely different?

    Read the article

  • Django: Filtering datetime field by *only* the year value?

    - by unclaimedbaggage
    Hi folks, I'm trying to spit out a django page which lists all entries by the year they were created. So, for example: 2010: Note 4 Note 5 Note 6 2009: Note 1 Note 2 Note 3 It's proving more difficult than I would have expected. The model from which the data comes is below: class Note(models.Model): business = models.ForeignKey(Business) note = models.TextField() created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) class Meta: db_table = 'client_note' @property def note_year(self): return self.created.strftime('%Y') def __unicode__(self): return '%s' % self.note I've tried a few different ways, but seem to run into hurdles down every path. I'm guessing an effective 'group by' method would do the trick (PostGres DB Backend), but I can't seem to find any Django functionality that supports it. I tried getting individual years from the database but I struggled to find a way of filtering datetime fields by just the year value. Finally, I tried adding the note_year @property but because it's derived, I can't filter those values. Any suggestions for an elegant way to do this? I figure it should be pretty straightforward, but I'm having a heckuva time with it. Any ideas much appreciated.

    Read the article

  • How much knowledge do I need to begin a project in Django

    - by Smock
    I started learning django about a month ago. I have an intermediate C, Java programming experience. I read the first 8 chapters of the django book . Afterwards, I picked up Practical Django Projects by James Bennett and did the first two projects: CMS & Web Blog. Although, I started getting lost when he got to the generic views part. I know that's important but I'm not sure how important that is when trying to implement a project. Anyway, I have a project in mind that I'd like to start; however, I'm nervous as to where to begin. I'm overwhelmed with the number of things that I'd like my project to do but no knowledge or minimal knowledge as to how e.g. how do i implement css and javascript in my project. Moreover, I am aware that some django packages exists to ease development but I don't know if I should use them or not. Anyway, I apologize for my length message. I just want some advice/encouragement. I have a project in mind but do you think I need to read more materials/tutorials or is it smart to just start working on my project based on the minimal knowledge i've gained from those books? Any information that can be provided is much appreciated. I really want to get good at this but I just need some direction.

    Read the article

  • Single django instance with subdomains for each app in the django project

    - by jwesonga
    I have a django project (django+apache+mod_wsgi+nginx) with multiple apps, I'd like to map each app as a subdomain: project/ app1 (domain.com) app2 (sub1.domain.com) app3 (sub3.domain.com) I have a single .wsgi script serving the project, which is stored in a folder /apache. Below is my vhost file. I'm using a single vhost file instead of separate ones for each sub-domain: <VirtualHost *:8080> ServerAdmin [email protected] ServerName www.domain.com ServerAlias domain.com DocumentRoot /home/path/to/app/ Alias /admin_media/ /usr/local/lib/python2.6/dist-packages/django/contrib/admin/media <Directory /home/path/to/wsgi/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/path/to/logs/apache_error.log CustomLog /home/path/to/logs/apache_access.log combined WSGIDaemonProcess domain.com user=www-data group=www-data threads=25 WSGIProcessGroup domain.com WSGIScriptAlias / /home/path/to/apache/kcdf.wsgi </VirtualHost> <VirtualHost *:8081> ServerAdmin [email protected] ServerName sub1.domain.com ServerAlias sub1.domain.com DocumentRoot /home/path/to/app Alias /admin_media/ /usr/local/lib/python2.6/dist-packages/django/contrib/admin/media <Directory /home/path/to/wsgi/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/path/to/logs/apache_error.log CustomLog /home/path/to/logs/apache_access.log combined WSGIDaemonProcess sub1.domain.com user=www-data group=www-data threads=25 WSGIProcessGroup sub1.domain.com WSGIScriptAlias / /home/path/to/apache/kcdf.wsgi </VirtualHost> My Nginx configuration for the domain.com: server { listen 80; server_name domain.com; access_log off; error_log off; # proxy to Apache 2 and mod_wsgi location / { proxy_pass http://127.0.0.1:8080/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_max_temp_file_size 0; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } } Configuration for the sub.domain.com: server { listen 80; server_name sub.domain.com; access_log off; error_log off; # proxy to Apache 2 and mod_wsgi location / { proxy_pass http://127.0.0.1:8081/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_max_temp_file_size 0; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } } This set up doesn't seem to work, everything seems to point to the main domain. I've tried http://effbot.org/zone/django-multihost.htm which kind of worked but seems to have issues with loading my css,images,js files.

    Read the article

  • In Django Combobox choices, how do you lookup description from short value?

    - by MikeN
    In Django models/forms the choices for a combobox often look like this: food_choices = (("",""), ("1", "Falafel"), ("2", "Hummus"), ("3", "Eggplant Stuff, Babaganoush???"), So the value to be stored in the database will be 1/2/3, but the displayed value on the form will be the long description. When we are working in code outside a form, how can we quickly lookup the long description given the short value stored in the model? So I want to map short values to long values: print foo("1") "Falafel"

    Read the article

  • Do Django Models inherit managers? (Mine seem not to)

    - by Zach
    I have 2 models: class A(Model): #Some Fields objects = ClassAManager() class B(A): #Some B-specific fields I would expect B.objects to give me access to an instance of ClassAManager, but this is not the case.... >>> A.objects <app.managers.ClassAManager object at 0x103f8f290> >>> B.objects <django.db.models.manager.Manager object at 0x103f94790> Why doesn't B inherit the objects attribute from A?

    Read the article

< Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >