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  • Issue Querying LDAP DirectoryEntry in ASP.NET

    - by davemackey
    I have users login to my application via Active Directory and then pull from their AD information to garner information about that user like so: Dim ID as FormsIdentity = DirectCast(User.Identity, FormsIdentity) Dim ticket as FormsAuthenticationTicket = ID.Ticket Dim adDirectory as New DirectoryEntry("LDAP://DC=my,DC=domain,DC=com") Dim adTicketID as String = ticket.Name.Substring(0, 5) Session("people_id") = adDirectory.Children.Find("CN=" & adTicketID).Properties("employeeID").Value Session("person_name") = adDirectory.Children.Find("CN=" & adTicketID).Properties("displayName").Value Now, I want to be able to impersonate other users...so that I can "test" the application as them, so I added a textbox and a button to the page and when the button is clicked the text is assigned to a session variable like so: Session("impersonate_user") = TextBox1.Text When the page reloads I check to see if Session("impersonate_user") has a value other than "" and then attempt to query Active Directory using this session variable like so: If CStr(Session("impersonate_user")) <> "" Then Dim adDirectory as New DirectoryEntry(LDAP://DC=my,DC=domain,DC=com") Dim adTicketID as String = CStr(Session("impersonate_user")) Session("people_id") = adDirectory.Children.Find("CN=" & adTicketID).Properties("employeeID").Value Session("person_name")= adDirectory.Children.Find("CN=" & adTicketID).Properties("displayName").Value Else [use the actual ticket.name to get this info.] End If But this doesn't work. Instead, it throws an error on the first Session line stating, "DirectoryServicesCOMException was unhandled by user code There is no such object on the server." Why? I know I'm giving it a valid username! Is something strange happening in the casting of the session? The code is essentially the same between each method except that in one method rather than pulling from ticket.Name I pull from a session variable for the login I'll be looking up with AD.

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  • SQL SERVER – Get Latest SQL Query for Sessions – DMV

    - by pinaldave
    In recent SQL Training I was asked, how can one figure out what was the last SQL Statement executed in sessions. The query for this is very simple. It uses two DMVs and created following quick script for the same. SELECT session_id, TEXT FROM sys.dm_exec_connections CROSS APPLY sys.dm_exec_sql_text(most_recent_sql_handle) AS ST While working with DMVs if you ever find any DMV has column with name sql_handle you can right away join that DMV with another DMV sys.dm_exec_sql_text and can get the text of the SQL statement. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: DMV, SQL DMV

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  • optimizing an sql query using inner join and order by

    - by Sergio B
    I'm trying to optimize the following query without success. Any idea where it could be indexed to prevent the temporary table and the filesort? EXPLAIN SELECT SQL_NO_CACHE `groups`.* FROM `groups` INNER JOIN `memberships` ON `groups`.id = `memberships`.group_id WHERE ((`memberships`.user_id = 1) AND (`memberships`.`status_code` = 1 AND `memberships`.`manager` = 0)) ORDER BY groups.created_at DESC LIMIT 5;` +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | memberships | ref | grp_usr,grp,usr,grp_mngr | usr | 5 | const | 5 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | groups | eq_ref | PRIMARY | PRIMARY | 4 | sportspool_development.memberships.group_id | 1 | | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ 2 rows in set (0.00 sec) +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | groups | 0 | PRIMARY | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_name | 1 | name | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_privacy_setting | 1 | privacy_setting | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_created_at | 1 | created_at | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 2 | created_at | A | 6 | NULL | NULL | YES | BTREE | | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | memberships | 0 | PRIMARY | 1 | id | A | 2 | NULL | NULL | | BTREE | | | memberships | 0 | grp_usr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 0 | grp_usr | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | usr | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 2 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 3 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 4 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 2 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 3 | manager | A | 2 | NULL | NULL | YES | BTREE | | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+

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  • how to write this typical mysql query( ho to use subquery column into main query)

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, but i m not getting how to implement ...please help me. Thanks for helping me alwayz

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  • Designing complex query builders in java/jpa/hibernate

    - by Ramraj Edagutti
    I need to build complex sql queries programatically, based on large filter conditions. For example, below are few sample/hypothitical filter conditions, based on which i need to fetch users Country: india States: Andhra Pradesh(AP), Gujarat(GUJ), karnataka(KTK) Districts: All districts in AP except 3 district, 5 any districts from GUJ, all district from KTK except 1 district Cities: All cities in AP, all cities except few, include only 50 specific cities from KTK Villages: similar conditions like above with varies combinations... Currently, we have a query builder, which is very complex in nature, and not easy to modify/re-factory for improvements. So, thinking of complete re-design of it. Any suggesations on how to build this kind of complex query builders programmatically using some best practices/deisgn patterns?

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  • Power Query in Modern Corporate BI–Copenhagen, June 3, 2014–#powerquery

    - by Marco Russo (SQLBI)
    I will be in Copenhagen to deliver the SSAS Tabular Workshop on June 2-4, 2014 (few seats still available, but hurry up!). In the same week I will be a speaker in an evening community event, MsBIP møde nr. 21, delivering the Power Query in Modern Corporate BI session that I also presented at TechEd North America 2014 last week. It’s not just a session about Power Query, there is a broader scope related to Corporate BI vs. Self-Service BI, which could be open to many consideration. I think that the two worlds can (and should) collaborate, instead of fighting against each other, especially when there is an existing investment in Corporate BI. I hope to meet many of you there!

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  • How to programmatically construct textual query

    - by stibi
    Here is a query language, more specifically, it's JQL, you can use it in Jira, to search for issues, it's something like SQL, but quite simpler. My case is that, I need to construct such queries programmatically, in my application. Something like: JQLMachine jqlMachine = new JQLMachine() jqlMachine.setStatuses("Open", "In Progress") jqlMachine.setReporter("foouser", "baruser") jqlMachine.setDateRange(...) jqlMachine.getQuery() --> String with corresponding JQL query is returned You get my point I hope. I can imagine the code for this, but it's not nice, using my current knowledge how I'd do that. That's why I'm asking. What you'd advice to use to create such thing. I believe some patterns for creating something like this already exist and there is already best practices, how to do that in good way.

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  • $query returns results but not the ones i want: $query looks good to me :S

    - by Toni Michel Caubet
    I'll start again, Lets say My data is: Table element (id,name,....) 1, name element 1, .... 2, name element 2, .... 3, name element 3, .... Table tags (id,name,id_element, ....) 1, happy , 1 2, result, 1 3, very , 1 4, element, 2 5, another, 3 6, element, 1 7, happy, 2 So if search is 'very, happy,element,result': Results i would like 1) element with id = 2 because it has all tags 2) element with id = 1 because it has the tag 'element' and the tag 'happy' (only 2 less taggs) 3) .... (only 3 less taggs) So if search is 'happy,element': Results i would like 1) element with id = 1 because it has all tags (and no more) 2) element with id = 2 because it has the tag 'element' and the tag 'happy' (and two more tags) 3) .... and 3 more tags This is an echo to my query: (it doesn't fit al requirements i wrote, but its first test to find with matched tags) SELECT element.id as id_deseada,tagg.* FROM element,tagg WHERE tagg.id_element = element.id AND tagg.nombre IN ('happy','tagg','result') GROUP BY tagg.id_element ORDER BY element.votos This returns 10 duplicated elements... :S and doen't even have all taggs (and on database there are taggs with 'happy' results) if it helps, thats how i get the elements of a tag (by name and with only one tagg) $query = "SELECT element.id FROM element,tagg WHERE tagg.nombre = '$nombre_tagg' AND tagg.id_element = element.id AND lan = '$lan' GROUP BY tagg.id_element"; I hope it's a bit easier to understand now, excuse my english.. :) Thanks a lot for you possible aportation!

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  • SQL SERVER – Example of Performance Tuning for Advanced Users with DB Optimizer

    - by Pinal Dave
    Performance tuning is such a subject that everyone wants to master it. In beginning everybody is at a novice level and spend lots of time learning how to master the art of performance tuning. However, as we progress further the tuning of the system keeps on getting very difficult. I have understood in my early career there should be no need of ego in the technology field. There are always better solutions and better ideas out there and we should not resist them. Instead of resisting the change and new wave I personally adopt it. Here is a similar example, as I personally progress to the master level of performance tuning, I face that it is getting harder to come up with optimal solutions. In such scenarios I rely on various tools to teach me how I can do things better. Once I learn about tools, I am often able to come up with better solutions when I face the similar situation next time. A few days ago I had received a query where the user wanted to tune it further to get the maximum out of the performance. I have re-written the similar query with the help of AdventureWorks sample database. SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID; User had similar query to above query was used in very critical report and wanted to get best out of the query. When I looked at the query – here were my initial thoughts Use only column in the select statements as much as you want in the application Let us look at the query pattern and data workload and find out the optimal index for it Before I give further solutions I was told by the user that they need all the columns from all the tables and creating index was not allowed in their system. He can only re-write queries or use hints to further tune this query. Now I was in the constraint box – I believe * was not a great idea but if they wanted all the columns, I believe we can’t do much besides using *. Additionally, if I cannot create a further index, I must come up with some creative way to write this query. I personally do not like to use hints in my application but there are cases when hints work out magically and gives optimal solutions. Finally, I decided to use Embarcadero’s DB Optimizer. It is a fantastic tool and very helpful when it is about performance tuning. I have previously explained how it works over here. First open DBOptimizer and open Tuning Job from File >> New >> Tuning Job. Once you open DBOptimizer Tuning Job follow the various steps indicates in the following diagram. Essentially we will take our original script and will paste that into Step 1: New SQL Text and right after that we will enable Step 2 for Generating Various cases, Step 3 for Detailed Analysis and Step 4 for Executing each generated case. Finally we will click on Analysis in Step 5 which will generate the report detailed analysis in the result pan. The detailed pan looks like. It generates various cases of T-SQL based on the original query. It applies various hints and available hints to the query and generate various execution plans of the query and displays them in the resultant. You can clearly notice that original query had a cost of 0.0841 and logical reads about 607 pages. Whereas various options which are just following it has different execution cost as well logical read. There are few cases where we have higher logical read and there are few cases where as we have very low logical read. If we pay attention the very next row to original query have Merge_Join_Query in description and have lowest execution cost value of 0.044 and have lowest Logical Reads of 29. This row contains the query which is the most optimal re-write of the original query. Let us double click over it. Here is the query: SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID OPTION (MERGE JOIN) If you notice above query have additional hint of Merge Join. With the help of this Merge Join query hint this query is now performing much better than before. The entire process takes less than 60 seconds. Please note that it the join hint Merge Join was optimal for this query but it is not necessary that the same hint will be helpful in all the queries. Additionally, if the workload or data pattern changes the query hint of merge join may be no more optimal join. In that case, we will have to redo the entire exercise once again. This is the reason I do not like to use hints in my queries and I discourage all of my users to use the same. However, if you look at this example, this is a great case where hints are optimizing the performance of the query. It is humanly not possible to test out various query hints and index options with the query to figure out which is the most optimal solution. Sometimes, we need to depend on the efficiency tools like DB Optimizer to guide us the way and select the best option from the suggestion provided. Let me know what you think of this article as well your experience with DB Optimizer. Please leave a comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL Intersection Conference, Las Vegas MGM Grand 10-13 November 2014

    - by Paul White
    I am very pleased to announce that I will be speaking at the SQL Intersection conference in Las Vegas again this year. This time around, I am giving a full-day workshop, "Mastering SQL Server Execution Plan Analysis" as well as a two-part session, "Parallel Query Execution" during the main conference. The workshop is a pre-conference event, held on Sunday 9 November (straight after this year's PASS Summit). Being on Sunday gives you the whole Monday off to recover and before the...(read more)

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  • sort mysql query by filtered query

    - by kalpaitch
    I have two mysql queries: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc"; and $sql = "SELECT * FROM content ORDER BY lastUpdated desc"; The end result is to have all rows returned from a particular table 'content' but have those that match the variable $filter at the top. Is there either a single query that could combine these two or should I be using a JOIN?

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  • How to apply GROUP_CONCAT in mysql Query

    - by Query Master
    How to apply GROUP_CONCAT in this Query if you guys have any idea or any alternate solution about this please share me. Helps are definitely appreciated also (see Query or result required) Query SELECT WEEK(cpd.added_date) AS week_no,COUNT(cpd.result) AS death_count FROM cron_players_data cpd WHERE cpd.player_id = 81 AND cpd.result = 2 AND cpd.status = 1 GROUP BY WEEK(cpd.added_date); Query output result screen Result Required 23,24,25 AS week_no 2,3,1 AS death_count

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  • LDAP socket keep-alive

    - by Dmitry Khalatov
    We are using OpenLDAP client library to conect to an LDAP server. The problem is that if there is no activity for some time, server (or firewall in the middle) drops TCP connection. Our current implementation of "keep-alive" just does search for baseDN from time to time - any better ideas ?

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  • Can I use Google's Protocol buffers for processing LDAP requests in my LDAP server?

    - by Naga
    Hi, I need to process the incoming predefined ASN format data(coming from verity of clients that uses BER library to build it) in my application server. This is typically an LDAP server where every request will be in a predefined ASN format. Can i use Google's protocol buffers to process the requests in the server side? Will it help any way to improve performance of my servers request handling? Is it anyway reduce the number of malloc() calls that happens while processing ASN messages? Thanks, Naga

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  • Storing LDAP Credentials

    - by Floetic
    What's the ideal way to store login and password for LDAP membership providers in the web.config? Having the login and password stored in the provider under connectionUsername/connectionPassword attributes does not go well with me because, I would want to encrypt the connection string later on. Don't have much experience with this, and was wondering if anyone had any best practices for this.

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  • Java Netscape LDAP Remove One Attribute

    - by spex
    Hi, I have LDAP schema where are users. I need remove one attribute named "notify" which have values: phone number or mail or remove attribute from user. I found method LDAPConnection myCon = new LDAPConnection("localhost",389); myCon.delete("uid=test1, ou=People, o=domain.com, o=isp"); but this remove whole user and i need remove only one attribute "notifyTo" of this user. I need remove whole attribute not only its value. Thanks for reply

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  • Recommendation for advanced CMS with LDAP support

    - by Miko
    I'm developing and designing a site for a customer. I would like to give him some control over content but also allow myself control over the outputted code/graphic. Normally for simple sites, I am using toko cms (content editor), but for this site i need something more advanced with database and user sync (LDAP). Any recommendations ? Maybe a robust but productive framework?

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  • LDAP c++ API choice

    - by ypnos
    I would like to write my own LDAP client under Linux, specific to our local environment. Most probably I will use QT4 to provide a shiny frontend without much hassle. I found that there seems to be no standard C++ library for this. OpenLDAP provides a C API and there should also be a C++ API (experimental?) somewhere.. Do I need to use the C stuff or is there a C++ API out there worth of recommendation?

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  • SQL SERVER – Query Hint – Contest Win Joes 2 Pros Combo (USD 198) – Day 1 of 5

    - by pinaldave
    August 2011 we ran a contest where every day we give away one book for an entire month. The contest had extreme success. Lots of people participated and lots of give away. I have received lots of questions if we are doing something similar this month. Absolutely, instead of running a contest a month long we are doing something more interesting. We are giving away USD 198 worth gift every day for this week. We are giving away Joes 2 Pros 5 Volumes (BOOK) SQL 2008 Development Certification Training Kit every day. One copy in India and One in USA. Total 2 of the giveaway (worth USD 198). All the gifts are sponsored from the Koenig Training Solution and Joes 2 Pros. The books are available here Amazon | Flipkart | Indiaplaza How to Win: Read the Question Read the Hints Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India residents only) 2 Winners will be randomly selected announced on August 20th. Question of the Day: Which of the following queries will return dirty data? a) SELECT * FROM Table1 (READUNCOMMITED) b) SELECT * FROM Table1 (NOLOCK) c) SELECT * FROM Table1 (DIRTYREAD) d) SELECT * FROM Table1 (MYLOCK) Query Hints: BIG HINT POST Most SQL people know what a “Dirty Record” is. You might also call that an “Intermediate record”. In case this is new to you here is a very quick explanation. The simplest way to describe the steps of a transaction is to use an example of updating an existing record into a table. When the insert runs, SQL Server gets the data from storage, such as a hard drive, and loads it into memory and your CPU. The data in memory is changed and then saved to the storage device. Finally, a message is sent confirming the rows that were affected. For a very short period of time the update takes the data and puts it into memory (an intermediate state), not a permanent state. For every data change to a table there is a brief moment where the change is made in the intermediate state, but is not committed. During this time, any other DML statement needing that data waits until the lock is released. This is a safety feature so that SQL Server evaluates only official data. For every data change to a table there is a brief moment where the change is made in this intermediate state, but is not committed. During this time, any other DML statement (SELECT, INSERT, DELETE, UPDATE) needing that data must wait until the lock is released. This is a safety feature put in place so that SQL Server evaluates only official data. Additional Hints: I have previously discussed various concepts from SQL Server Joes 2 Pros Volume 1. SQL Joes 2 Pros Development Series – Dirty Records and Table Hints SQL Joes 2 Pros Development Series – Row Constructors SQL Joes 2 Pros Development Series – Finding un-matching Records SQL Joes 2 Pros Development Series – Efficient Query Writing Strategy SQL Joes 2 Pros Development Series – Finding Apostrophes in String and Text SQL Joes 2 Pros Development Series – Wildcard – Querying Special Characters SQL Joes 2 Pros Development Series – Wildcard Basics Recap Next Step: Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India) Bonus Winner Leave a comment with your favorite article from the “additional hints” section and you may be eligible for surprise gift. There is no country restriction for this Bonus Contest. Do mention why you liked it any particular blog post and I will announce the winner of the same along with the main contest. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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