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  • jQuery: How to write a function on click, hold and move?

    - by Syom
    I started learning jQuery just yesterday, and I like it very much. And now I decided to write a script where I can change the margin-left of an image when I click on it, hold the clicking and move the mouse. Depending on mouse coordinates I must change the image's margin-left. Could you give me an idea how I can do it? Thanks.

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  • [jQuery] How do I invoke custom plugin on click?

    - by Steven
    I have the following code: (function(jQuery){ jQuery.fn.timepicker = function(){ return this.each(function(){ jQuery(this).val("14:00"); }); }; })(jQuery); Currently I invoke this function by the following code: $("#event_start_time").timepicker(); Where #event_start_time is the ID of an <input> field. How can I invoke this code only when I click inside the text box?

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  • Can a problem have a relation of aggregation and composition both between two classes at same point

    - by learner
    Can a problem have a relation of aggregation and composition both between two classes at same point of time? Like any real time scenario where there can be aggregation corresponding to one method and composition related to other method. I m unable to figure out any scenario where both composition and aggregation occurs simultaneously between two classes. Any help will be appreciable.

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  • How do I send user to youtube video on ListBoxItem click?

    - by Byron Sommardahl
    I'm creating a Windows Phone 7 app and learning Silverlight in the process. I have a youtube video url and I'd like the user to be able to click a video thumbnail in my list and go to a youtube app to view the video (similar to iPhone). Is this possible? If so, can you share some code to send the user to the video? I already have a MouseLeftButtonUp event handler.

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  • how to post a form upon click on checkbox ?

    - by user281180
    I have a form (displayed as a dialog) in which I have various checkboxes. On a click on any of the checkboxes, I want to post the form values to the controller and still doesn`t want my dialog to close. How can I do that? I don`t have a submit button on the form. Ajaxpost closes the dialog after form.submit... What method can I use?

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  • How to improve Windows Aero desktop performance?

    - by Click Ok
    Sincerely I don't understand why in Windows Experience ratings, the "Game Graphics" in my pc is 5.0 and "Graphic Elements" (windows aero desktop performance) is 3.9. How it is possible? My VGA is nice for games but bad for Windows Desktop? What I can do to improve windows aero desktop performance?

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  • web services access not being reached thru the web browser

    - by Tony
    I am trying to reference my .asmx webservices in .NET but my server is not exposed to the internet. When I put on the following address I get the message mentioned below. What's the reason for not being able to see the directory? Am I missing something in my IIS configuraction? Am I missing anything in my permissions? Just as reference I have other folders with webservices and I have the same issue. When I login to the server I am doing it with my windows user and password (I am using windows authentication). It's necessary to mention that when I put the URL I am getting a popup screen to put in my userid and password but it seems that's not able to validate since keeps asking me a couple of times. Let me know if you need more information to address this issue . http://appsvr02/Inetpub/wwwroot/DevWebApi/ Internet Explorer cannot display the webpage What you can try: It appears you are connected to the Internet, but you might want to try to reconnect to the Internet. Retype the address. Go back to the previous page. Most likely causes: •You are not connected to the Internet. •The website is encountering problems. •There might be a typing error in the address. More information This problem can be caused by a variety of issues, including: •Internet connectivity has been lost. •The website is temporarily unavailable. •The Domain Name Server (DNS) is not reachable. •The Domain Name Server (DNS) does not have a listing for the website's domain. •If this is an HTTPS (secure) address, click tools, click Internet Options, click Advanced, and check to be sure the SSL and TLS protocols are enabled under the security section. For offline users You can still view subscribed feeds and some recently viewed webpages. To view subscribed feeds 1.Click the Favorites Center button , click Feeds, and then click the feed you want to view. To view recently visited webpages (might not work on all pages) 1.Click Tools , and then click Work Offline. 2.Click the Favorites Center button , click History, and then click the page you want to view.

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  • Firefox can't establish a connection to the server at www.google.com

    - by Tom
    My home page in Firefox [v4.0] and Internet Explorer [v9.0.8112.16421, Update Versions RTM (KB982861)] is currently set to Google but when I depress the quick start icon to start up either browser, I am getting the following immediate results: Unable to connect (In Firefox) Firefox can't establish a connection to the server at www.google.com. The site could be temporarily unavailable or too busy. Try again in a few moments. If you are unable to load any pages, check your computer's network connection. If your computer or network is protected by a firewall or proxy, make sure that Firefox is permitted to access the Web. Internet Explorer cannot display the webpage What you can try: Diagnose Connection Problems More information This problem can be caused by a variety of issues, including: Internet connectivity has been lost. The website is temporarily unavailable. The Domain Name Server (DNS) is not reachable. The Domain Name Server (DNS) does not have a listing for the website's domain. There might be a typing error in the address. If this is an HTTPS (secure) address, click Tools, click Internet Options, click Advanced, and check to be sure the SSL and TLS protocols are enabled under the security section. For offline users You can still view subscribed feeds and some recently viewed webpages. To view subscribed feeds: Click the Favorites button , click Feeds, and then click the feed you want to view. To view recently visited webpages (might not work on all pages): Press Alt, click File, and then click Work Offline. Click the Favorites button, click History, and then click the page you want to view. Thankfully, I am able to use one browser that I have installed on my computer (Mathon v3.0.20.5000) to search online for technical assistance in this matter. I have seen several WinSock error issues mentioned; but, they are pointing to Windows XP and I am using Windows 7 Pro and remain uncertain whether anything identified as a fix for one OS will work in another. Things I've tried: HiJackThis Complete scan with Avira AntiVirus Premium. What am I overlooking? What should I do to address this problem?

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  • web services access not being reached thru the web browser [closed]

    - by Tony
    I am trying to reference my .asmx webservices in .NET but my server is not exposed to the internet. When I put on the following address I get the message mentioned below. What's the reason for not being able to see the directory? Am I missing something in my IIS configuraction? Am I missing anything in my permissions? Just as reference I have other folders with webservices and I have the same issue. When I login to the server I am doing it with my windows user and password (I am using windows authentication). It's necessary to mention that when I put the URL I am getting a popup screen to put in my userid and password but it seems that's not able to validate since keeps asking me a couple of times. Let me know if you need more information to address this issue . http://appsvr02/Inetpub/wwwroot/DevWebApi/ Internet Explorer cannot display the webpage What you can try: It appears you are connected to the Internet, but you might want to try to reconnect to the Internet. Retype the address. Go back to the previous page. Most likely causes: •You are not connected to the Internet. •The website is encountering problems. •There might be a typing error in the address. More information This problem can be caused by a variety of issues, including: •Internet connectivity has been lost. •The website is temporarily unavailable. •The Domain Name Server (DNS) is not reachable. •The Domain Name Server (DNS) does not have a listing for the website's domain. •If this is an HTTPS (secure) address, click tools, click Internet Options, click Advanced, and check to be sure the SSL and TLS protocols are enabled under the security section. For offline users You can still view subscribed feeds and some recently viewed webpages. To view subscribed feeds 1.Click the Favorites Center button , click Feeds, and then click the feed you want to view. To view recently visited webpages (might not work on all pages) 1.Click Tools , and then click Work Offline. 2.Click the Favorites Center button , click History, and then click the page you want to view.

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  • How can I make a div expand on click with only one open at a time?

    - by imHavoc
    As shown in here: http://www.learningjquery.com/2007/03/accordion-madness. But I need help to edit it so that it will work for my circumstances. Sample HTML <div class="row even"> <div class="info"> <div class="class">CK1</div> <div class="teacher_chinese">??</div> <div class="teacher_english">Teacher Name</div> <div class="assistant_chinese">??</div> <div class="assistant_english">Assistant Name</div> <div class="room">Room 00</div> <div class="book"></div> </div> <div class="chapters"> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=1"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=2"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=3"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=4"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=5"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=6"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=7"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=8"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=9"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=10"><span class="chapter">?</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=11"><span class="chapter">??</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=12"><span class="chapter">??</span></a> <a href="../../curriculum/cantonese/textbook.php?cls=C1&amp;ch=13"><span class="chapter">??</span></a> </div> </div> JQUERY [Work In Progress] $(document).ready(function() { $('div#table_cantonese .chapters').hide(); $('div#table_cantonese .book').click(function() { var $nextDiv = $(this).next(); var $visibleSiblings = $nextDiv.siblings('div:visible'); if ($visibleSiblings.length ) { $visibleSiblings.slideUp('fast', function() { $nextDiv.slideToggle('fast'); }); } else { $nextDiv.slideToggle('fast'); } }); }); So when the end-user click on div.book, div.chapters will expand. And only one div.chapters will be shown at a time. So if a div.chapters is already open, then it will close the open one first before animating the one the user clicked on.

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  • How to find the insertion point in an array using binary search?

    - by ????
    The basic idea of binary search in an array is simple, but it might return an "approximate" index if the search fails to find the exact item. (we might sometimes get back an index for which the value is larger or smaller than the searched value). For looking for the exact insertion point, it seems that after we got the approximate location, we might need to "scan" to left or right for the exact insertion location, so that, say, in Ruby, we can do arr.insert(exact_index, value) I have the following solution, but the handling for the part when begin_index >= end_index is a bit messy. I wonder if a more elegant solution can be used? (this solution doesn't care to scan for multiple matches if an exact match is found, so the index returned for an exact match may point to any index that correspond to the value... but I think if they are all integers, we can always search for a - 1 after we know an exact match is found, to find the left boundary, or search for a + 1 for the right boundary.) My solution: DEBUGGING = true def binary_search_helper(arr, a, begin_index, end_index) middle_index = (begin_index + end_index) / 2 puts "a = #{a}, arr[middle_index] = #{arr[middle_index]}, " + "begin_index = #{begin_index}, end_index = #{end_index}, " + "middle_index = #{middle_index}" if DEBUGGING if arr[middle_index] == a return middle_index elsif begin_index >= end_index index = [begin_index, end_index].min return index if a < arr[index] && index >= 0 #careful because -1 means end of array index = [begin_index, end_index].max return index if a < arr[index] && index >= 0 return index + 1 elsif a > arr[middle_index] return binary_search_helper(arr, a, middle_index + 1, end_index) else return binary_search_helper(arr, a, begin_index, middle_index - 1) end end # for [1,3,5,7,9], searching for 6 will return index for 7 for insertion # if exact match is found, then return that index def binary_search(arr, a) puts "\nSearching for #{a} in #{arr}" if DEBUGGING return 0 if arr.empty? result = binary_search_helper(arr, a, 0, arr.length - 1) puts "the result is #{result}, the index for value #{arr[result].inspect}" if DEBUGGING return result end arr = [1,3,5,7,9] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [] b = 60 arr.insert(binary_search(arr, b), b) p arr and result: Searching for 6 in [1, 3, 5, 7, 9] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 6, arr[middle_index] = 5, begin_index = 3, end_index = 2, middle_index = 2 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9] Searching for 6 in [1, 3, 5, 7, 9, 11] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 6, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 3, middle_index = 3 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9, 11] Searching for 60 in [1, 3, 5, 7, 9] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 60, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 60, arr[middle_index] = 9, begin_index = 4, end_index = 4, middle_index = 4 the result is 5, the index for value nil [1, 3, 5, 7, 9, 60] Searching for 60 in [1, 3, 5, 7, 9, 11] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 60, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 60, arr[middle_index] = 11, begin_index = 5, end_index = 5, middle_index = 5 the result is 6, the index for value nil [1, 3, 5, 7, 9, 11, 60] Searching for -60 in [1, 3, 5, 7, 9] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 9, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9] Searching for -60 in [1, 3, 5, 7, 9, 11] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 11, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9, 11] Searching for -60 in [1] a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 0, the index for value 1 [-60, 1] Searching for 60 in [1] a = 60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 1, the index for value nil [1, 60] Searching for 60 in [] [60]

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  • What is the best way to deal with 404s that are all trying to point to the same page that are from an external site?

    - by Lee
    I started getting 404s showing up in my Google Webmaster's Tools from a site linking to a specific category but with odd characters at the end of the url. So Something like this: http://example.com/category/puppies%EF%BC%9A.textwidget%E8%A6%81%E7%B4%A0%E7%B7%A8%E9%9B%86 Google Webmaster says that there are about 120 of these links and I can imagine there will be more to come. What is the best way to handle these links from an seo point-of-view? I have heard 301 redirecting too many links at one time can cause Google to ding the site but I don't want this site to continue posting broken links. Any help on this would be appreciated.

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  • Domain Name from 123-reg, VPS from Linode. How to point to Google Mail for Business?

    - by Ashutosh Jindal
    I have bought a domain from 123-reg.co.uk and have successfully pointed it to the IP Address of my Linode VPS so that going to the domain serves up the pages from the Apache server running on the VPS. The instructions I followed to do this are : Now, I am trying to get the domain's mail handled by Google Apps for Business. I have tried updating the MX records at Linode following this tutorial : http://library.linode.com/email/google-mail And also followed the instructions to update the MX Records in 123-reg's control panel : I am slightly confused now. Where should I be adding the MX records? In my domain registrar's control panel or in Linode's VPS? Both have options to update the MX records.

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  • In DNS can an IN NS point to a CNAME?

    - by Mark Wagner
    Is it allowed to have an NS record be a CNAME? E.g.: subdomain.example.com. IN NS ns1.example.com. ns1.example.com. CNAME foo.example.com. foo.example.com. IN A 10.1.1.1 This doesn't seem to work in bind though this (of course) does: subdomain.example.com. IN NS foo.example.com. foo.example.com. IN A 10.1.1.1 Any pointers to RFCs prohibiting this setup would be appreciated.

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