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  • Extracting a string between specified characters in python

    - by Seth
    I'm a newbie to regular expressions and I have the following string: sequence = ["{\"First\":\"Belyuen,NT,0801\",\"Second\":\"Belyuen,NT,0801\"}","{\"First\":\"Larrakeyah,NT,0801\",\"Second\":\"Larrakeyah,NT,0801\"}"] I am trying to extract the text Belyuen,NT,0801 and Larrakeyah,NT,0801 in python. I have the following code which is not working: re.search('\:\\"...\\', ''.join(sequence)) I.e. I want to get the string between characters :\ and \.

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  • Repeat String - Javascript

    - by brad
    What is the best or most concise method for returning a string repeated an arbitrary amount of times? The following is my best shot so far: function repeat(s, n){ var a = []; while(a.length < n){ a.push(s); } return a.join(''); }

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  • Retrieving multiple rows in SQL Server but distinct filtering only on one

    - by Nicklas
    I have this: SELECT Product.ProductID, Product.Name, Product.GroupID, Product.GradeID, AVG(tblReview.Grade) AS Grade FROM Product left Join tblReview ON Product.GroupID = tblReview.GroupID WHERE (Product.CategoryID = @CategoryID) GROUP BY Product.ProductID, Product.Name, Product.GroupID, Product.GradeID I would like to return only the rows where Product.Name is unique. If I make a SELECT DISTINCT the ProductID is different on every row so all the rows are unique.

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  • Problem with Django styling

    - by Brob
    Hi new to django but I'm having issues with the styling of pages. my settings.py contains MEDIA_ROOT = '' MEDIA_URL = '' TEMPLATE_DIRS = ( os.path.join(os.path.dirname(__file__), 'templates'), ) please can someone help me shed some light on what I need to do to get the styles working in my templates Thanks

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  • Pass a variable into a trigger

    - by Codesleuth
    I have a trigger which deals with some data for logging purposes like so: CREATE TRIGGER trgDataUpdated ON tblData FOR UPDATE AS BEGIN INSERT INTO tblLog ( ParentID, OldValue, NewValue, UserID ) SELECT deleted.ParentID, deleted.Value, inserted.Value, @intUserID -- how can I pass this in? FROM inserted INNER JOIN deleted ON inserted.ID = deleted.ID END How can I pass in the variable @intUserID into the above trigger, as in the following code: DECLARE @intUserID int SET @intUserID = 10 UPDATE tblData SET Value = @x PS: I know I can't literally pass in @intUserID to the trigger, it was just used for illustration purposes.

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  • How large is a "buffer" in PostgreSQL

    - by Konrad Garus
    I am using pg_buffercache module for finding hogs eating up my RAM cache. For example when I run this query: SELECT c.relname, count(*) AS buffers FROM pg_buffercache b INNER JOIN pg_class c ON b.relfilenode = c.relfilenode AND b.reldatabase IN (0, (SELECT oid FROM pg_database WHERE datname = current_database())) GROUP BY c.relname ORDER BY 2 DESC LIMIT 10; I discover that sample_table is using 120 buffers. How much is 120 buffers in bytes?

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  • Migrating from hand-written persistence layer to ORM

    - by Sergey Mikhanov
    Hi community, We are currently evaluating options for migrating from hand-written persistence layer to ORM. We have a bunch of legacy persistent objects (~200), that implement simple interface like this: interface JDBC { public long getId(); public void setId(long id); public void retrieve(); public void setDataSource(DataSource ds); } When retrieve() is called, object populates itself by issuing handwritten SQL queries to the connection provided using the ID it received in the setter (this usually is the only parameter to the query). It manages its statements, result sets, etc itself. Some of the objects have special flavors of retrive() method, like retrieveByName(), in this case a different SQL is issued. Queries could be quite complex, we often join several tables to populate the sets representing relations to other objects, sometimes join queries are issued on-demand in the specific getter (lazy loading). So basically, we have implemented most of the ORM's functionality manually. The reason for that was performance. We have very strong requirements for speed, and back in 2005 (when this code was written) performance tests has shown that none of mainstream ORMs were that fast as hand-written SQL. The problems we are facing now that make us think of ORM are: Most of the paths in this code are well-tested and are stable. However, some rarely-used code is prone to result set and connection leaks that are very hard to detect We are currently squeezing some additional performance by adding caching to our persistence layer and it's a huge pain to maintain the cached objects manually in this setup Support of this code when DB schema changes is a big problem. I am looking for an advice on what could be the best alternative for us. As far as I know, ORMs has advanced in last 5 years, so it might be that now there's one that offers an acceptable performance. As I see this issue, we need to address those points: Find some way to reuse at least some of the written SQL to express mappings Have the possibility to issue native SQL queries without the necessity to manually decompose their results (i.e. avoid manual rs.getInt(42) as they are very sensitive to schema changes) Add a non-intrusive caching layer Keep the performance figures. Is there any ORM framework you could recommend with regards to that?

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  • joining relative urls?

    - by heffaklump
    So i want to join strings with relative urls in Javascript. base url = "http://www.adress.com/more/evenmore" with relative url = "../../adress" = "http://www.adress.com/adress" relative url = "../adress" = "http://www.adress.com/more/adress" What would be the best way? I was thinking of using regexp and checking how many "../" i find, then subtracting that amount from the baseurl and adding them to what is left.

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  • Three level heirarchal data-linq

    - by user326010
    Hi I have three level heirarchal data. using the statement below i managed to display two level data. I need to extend it to one more level. Current heirachy is Modules--Documents I need to extend it as Packages--Modules--Documents var data = (from m in DataContext.SysModules join d in DataContext.SysDocuments on m.ModuleID equals d.ModuleID into tempDocs from SysDocument in tempDocs.DefaultIfEmpty() group SysDocument by m).ToList(); Regards Tassadaque

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  • ado sql update table with result of group by query

    - by brett
    I am trying to update records in an .mdb table with the number of records containing the same value The sql below does not work but I think gives an indication of what I am trying to achieve. UPDATE table1 AS A INNER JOIN (SELECT PH_BSP , Count(PH_BSP) AS PHCOUNT FROM table1 GROUP BY PH_BSP) AS B ON A.PH_BSP=B.PH_BSP SET A.PH_SORT = B.PHCOUNT; any ideas?

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  • PHP & MySQL Undefined variable problem

    - by comma
    I keep getting the following error Undefined variable: id on line 91 can some one help me correct this problem? The error is on this line. $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; MySQL database tables. CREATE TABLE tags ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill VARCHAR(255) NOT NULL, experience VARCHAR(255) NOT NULL, years VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, date_created DATETIME UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { if (isset($_POST['skill']) && trim($_POST['skill'])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill . "', '" . $experience . "', '" . $years . "')"); if (mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND years='" . $years . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; } }

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  • Enity framework not loading relationship even when using include

    - by dilbert789
    I have this code: Category selectedCategory = (from c in DB.Category.Include("SubCategory") join a in DB.Accessory on c.AccCatUID equals a.Category.AccCatUID where a.AccUID == currentAccessory.AccUID select c).FirstOrDefault(); It works fine, selectedCategory gets populated as expected. BUT selectedCategory has a child table 'SubCategory' which does not get loaded even though there is the include there. It is not loaded until I do this: selectedCategory.SubCategory.Load(); Why do I have to call load explicitly in order to load the child table?

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  • the shema return by the new query differ from the base query

    - by sochandara
    I am working on class project which required to work with Windows Application and this issue occurred to me that i don understand how to solved it can anybody help please? I want to show the NATIONALITYNAME instead of showing NATIONALITYID in the grid view SELECT COACH.COACHID , COACH.COACHFIRSTNAME , COACH.COACHLASTNAME , NATIONALITY.NATIONALITY FROM COACH INNER JOIN NATIONALITY ON COACH.NATIONALITYID = NATIONALITY.NATIONALITYID Error Message: "The Schema returned by the new query differ from the base query"

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  • SQL Count in View as column

    - by alex
    I'm trying to get the result of a COUNT as a column in my view. Please see the below query for a demo of the kind of thing I want (this is just for demo purposes) SELECT ProductID, Name, Description, Price, (SELECT COUNT(*) FROM ord WHERE ord.ProductID = prod.ProductID) AS TotalNumberOfOrders FROM tblProducts prod LEFT JOIN tblOrders ord ON prod.ProductID = ord.ProductID This obviously isn't working... but I was wondering what the correct way of doing this would be?

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  • MySQL Sub-query.. Doesn't provide proper information after 3 entries into table.

    - by Chris Keefer
    After I get 3 rows in my forum_threads table this no longer does it's job; to organize a list of active forum threads and put the most recently responded-to thread at the top of the list, followed by second most recent posted-to thread, followed by third, fourth, etc. Like I said, the query works wonders up until there is a fourth row added to forum_threads. SELECT forum_threads.*, forum_posts.thread_id FROM forum_threads INNER JOIN (SELECT MAX(id) AS id, thread_id as thread_id FROM forum_posts group by thread_id order by id DESC) forum_posts ON forum_threads.id = forum_posts.thread_id

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  • MySQL error problem

    - by comma
    I keep getting the error listed below but it only says line 1 what does this mean and how do I fix it? Here is the error I keep getting? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 here is the code. if (isset($_POST['info_submitted'])) { $user_id = '5'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); $skill = $_POST['skill']; $experience = $_POST['experience']; $year = $_POST['year']; if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, year) VALUES ('" . $skill . "', '" . $experience . "', '" . $year . "')"); } if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND year='" . $year . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE learned_skills JOIN users_skills ON (users_skills.skill_id = learned_skills.id) SET skill = '$skill', experience = '$experience', year = '$year'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } }

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  • Does this introduce security vulnerabilities?

    - by mcmt
    I don't think I'm missing anything. Then again I'm kind of a newbie. def GET(self, filename): name = urllib.unquote(filename) full = path.abspath(path.join(STATIC_PATH, filename)) #Make sure request is not tricksy and tries to get out of #the directory, e.g. filename = "../.ssh/id_rsa". GET OUTTA HERE assert full[:len(STATIC_PATH)] == STATIC_PATH, "bad path" return open(full).read()

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  • Django template can't see CSS files

    - by Technical Bard
    I'm building a django app and I can't get the templates to see the CSS files... My settings.py file looks like: MEDIA_ROOT = os.path.join(os.path.abspath(os.path.dirname(__file__)), 'media') MEDIA_URL = '/media/' I've got the CSS files in /mysite/media/css/ and the template code contains: <link rel="stylesheet" type="text/css" href="/media/css/site_base.css" />` then, in the url.py file I have: # DEVELOPMENT ONLY (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/media'}), but the development server serves the plain html (without styles). What am I doing wrong?

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  • cakePHP and GROUP BY

    - by Lizard
    I am trying to solve a hopefully simple problem here is the query I am trying produce: SELECT `categories`.*, COUNT(`entities`.id) FROM `categories` LEFT JOIN `entities` ON (`categories`.`id` = `entities`.`category_id`) GROUP BY `categories`.`id` I am really struggling to do this is in cakePHP 1.2 How would/should I go about doing this... (I am using 'Containable' if that helps) Thanks in advance

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  • How would I change this Query builder from Kohana 2.4 to Kohana 3?

    - by Thorpe Obazee
    I have had this website built for a few months and I am just getting on Kohana 3. I'd just like to convert this K2.4 query builder to K3 query builder. return DB::select(array('posts.id', 'posts.created', 'posts.uri', 'posts.price', 'posts.description', 'posts.title', 'image_count' => db::expr('COUNT(images.id)'))) ->from('posts') ->join('images')->on('images.post_id', '=', 'posts.id') ->group_by(array('posts.id')) ->order_by('posts.id', 'DESC') ->limit($limit) ->offset($offset) ->execute();

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  • how do i get the sum of the 4th column

    - by every_answer_gets_a_point
    this statement will generate a 4 column table: SELECT shipped.badguy AS badguy, shipped.sdate AS LineDate, 'Delivery' AS Legend, -price*quantity AS amount FROM product JOIN shipped ON (product.id = shipped.product) UNION SELECT receipt.badguy, receipt.rdate,notes, amount FROM how do i get the total sum of the 4th of column of what the above generates?

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  • How to list all duplicated rows which may include NULL columns?

    - by Yousui
    Hi guys, I have a problem of listing duplicated rows that include NULL columns. Lemme show my problem first. USE [tempdb]; GO IF OBJECT_ID(N'dbo.t') IS NOT NULL BEGIN DROP TABLE dbo.t END GO CREATE TABLE dbo.t ( a NVARCHAR(8), b NVARCHAR(8) ); GO INSERT t VALUES ('a', 'b'); INSERT t VALUES ('a', 'b'); INSERT t VALUES ('a', 'b'); INSERT t VALUES ('c', 'd'); INSERT t VALUES ('c', 'd'); INSERT t VALUES ('c', 'd'); INSERT t VALUES ('c', 'd'); INSERT t VALUES ('e', NULL); INSERT t VALUES (NULL, NULL); INSERT t VALUES (NULL, NULL); INSERT t VALUES (NULL, NULL); INSERT t VALUES (NULL, NULL); GO Now I want to show all rows that have other rows duplicated with them, I use the following query. SELECT a, b FROM dbo.t GROUP BY a, b HAVING count(*) > 1 which will give us the result: a b -------- -------- NULL NULL a b c d Now if I want to list all rows that make contribution to duplication, I use this query: WITH duplicate (a, b) AS ( SELECT a, b FROM dbo.t GROUP BY a, b HAVING count(*) > 1 ) SELECT dbo.t.a, dbo.t.b FROM dbo.t INNER JOIN duplicate ON (dbo.t.a = duplicate.a AND dbo.t.b = duplicate.b) Which will give me the result: a b -------- -------- a b a b a b c d c d c d c d As you can see, all rows include NULLs are filtered. The reason I thought is that I use equal sign to test the condition(dbo.t.a = duplicate.a AND dbo.t.b = duplicate.b), and NULLs cannot be compared use equal sign. So, in order to include rows that include NULLs in it in the last result, I have change the aforementioned query to WITH duplicate (a, b) AS ( SELECT a, b FROM dbo.t GROUP BY a, b HAVING count(*) > 1 ) SELECT dbo.t.a, dbo.t.b FROM dbo.t INNER JOIN duplicate ON (dbo.t.a = duplicate.a AND dbo.t.b = duplicate.b) OR (dbo.t.a IS NULL AND duplicate.a IS NULL AND dbo.t.b = duplicate.b) OR (dbo.t.b IS NULL AND duplicate.b IS NULL AND dbo.t.a = duplicate.a) OR (dbo.t.a IS NULL AND duplicate.a IS NULL AND dbo.t.b IS NULL AND duplicate.b IS NULL) And this query will give me the answer as I wanted: a b -------- -------- NULL NULL NULL NULL NULL NULL NULL NULL a b a b a b c d c d c d c d Now my question is, as you can see, this query just include two columns, in order to include NULLs in the last result, you have to use many condition testing statements in the query. As the column number increasing, the condition testing statements you need in your query is increasing astonishingly. How can I solve this problem? Great thanks.

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  • How can i resolve the N+1 Selects problem ?

    - by Maxime ARNSTAMM
    Hello everyone, I have trouble understanding how to avoid the n+1 select in jpa or hibernate. From what i read, there's the 'left join fetch', but i'm not sure if it still works with more than one list (oneToMany).. Could someone explain it to me, or give me a link with a clear complete explanation please ? I'm sorry if this is a noob question, but i can't find a real clear article or doc on this issue. Thanks

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