Search Results

Search found 9989 results on 400 pages for 'grails controller'.

Page 146/400 | < Previous Page | 142 143 144 145 146 147 148 149 150 151 152 153  | Next Page >

  • Stubbing a before_filter with RSpec

    - by TheDelChop
    Guys, I'm having trouble understanding why I can't seem to stub this controller method :load_user, since all of my tests fail if I change the actual implementation of :load_user to not return and instance of @user. Can anybody see why my stub (controller.stub!(:load_user).and_return(@user)) seems to fail to actually get called when RSpec makes a request to the controller? require 'spec_helper' describe TasksController do before(:each) do @user = Factory(:user) sign_in @user @task = Factory(:task) User.stub_chain(:where, :first).and_return(@user) controller.stub!(:load_user).and_return(@user) end #GET Index describe "GET Index" do before(:each) do @tasks = 7.times{Factory(:task, :user = @user)} @user.stub!(:tasks).and_return(@tasks) end it "should should find all of the tasks owned by a user" do @user.should_receive(:tasks).and_return(@tasks) get :index, :user_id = @user.id end it "should assign all of the user's tasks to the view" do get :index, :user_id = @user.id assigns[:tasks].should be(@tasks) end end #GET New describe "GET New" do before(:each) do @user.stub_chain(:tasks, :new).and_return(@task) end it "should return a new Task" do @user.tasks.should_receive(:new).and_return(@task) get :new, :user_id = @user.id end end #POST Create describe "POST Create" do before(:each) do @user.stub_chain(:tasks, :new).and_return(@task) end it "should create a new task" do @user.tasks.should_receive(:new).and_return(@task) post :create, :user_id = @user.id, :task = @task.to_s end it "saves the task" do @task.should_receive(:save) post :create, :user_id = @user.id, :task = @task end context "when the task is saved successfully" do before(:each) do @task.stub!(:save).and_return(true) end it "should set the flash[:notice] message to 'Task Added Successfully'"do post :create, :user_id = @user.id, :task = @task flash[:notice].should == "Task Added Successfully!" end it "should redirect to the user's task page" do post :create, :user_id = @user.id, :task = @task response.should redirect_to(user_tasks_path(@user.id)) end end context "when the task isn't saved successfully" do before(:each) do @task.stub(:save).and_return(false) end it "should return to the 'Create New Task' page do" do post :create, :user_id = @user.id, :task = @task response.should render_template('new') end end end it "should attempt to authenticate and load the user who owns the tasks" do context "when the tasks belong to the currently logged in user" do it "should set the user instance variable to the currently logged in user" do pending end end context "when the tasks belong to another user" do it "should set the flash[:notice] to 'Sorry but you can't view other people's tasks.'" do pending end it "should redirect to the home page" do pending end end end end class TasksController < ApplicationController before_filter :load_user def index @tasks = @user.tasks end def new @task = @user.tasks.new end def create @task = @user.tasks.new if @task.save flash[:notice] = "Task Added Successfully!" redirect_to user_tasks_path(@user.id) else render :action => 'new' end end private def load_user if current_user.id == params[:user_id].to_i @user = User.where(:id => params[:user_id]).first else flash[:notice] = "Sorry but you can't view other people's tasks." redirect_to root_path end end end Can anybody see why my stub doesnt' work? Like I said, my tests only pass if I make sure that load_user works, if not, all my tests fail which makes my think that RSpec isn't using the stub I created. Thanks, Joe

    Read the article

  • Scaffold is ignoring class file in CakePHP

    - by JoseMarmolejos
    Hi, when using scaffolding on a controller the views render fine and the app even attempts to insert the data; the problem is that the scaffold is completely ignoring the relations I'm defining in my model class, in fact it's ignoring the class entirely as I can delete the file and the controller still scaffolds and render the crud from the table. Has this ever happened to you?

    Read the article

  • How do I Validate Email or Phone requirement in MVC?

    - by user54197
    In MVC I am using [Required(ErrorMessage="")] to validate my text. How do I utilize a validation for an "Email or Phone Contact" textboxes in my model? I now have the validation in my controller, which I would like to have in the model. CONTROLLER... if (insuredInfo.InsuredHPhone == null && insuredInfo.InsuredWPhone == null) { ModelState.AddModelError("InsuredHPhone", "Contact Number Required"); isRequired = true; }

    Read the article

  • Zend Framework Routing: .html extension

    - by smack0007
    I know I've seen this done before but I can't find the information anywhere. I need to be able to route with .html extensions in the Zend Framework. I.E. /controller/action.html should route to the appropriate controller / action. We have an idea to throw away the .html extension with our .htaccess file but I think changing the route config would be the better solution. Any advice is welcome.

    Read the article

  • External URL re direction issue IN Rails 2

    - by Rcoder
    I have a requirement where in I want to redirect to an external Url Here is my code in routes.rb map.connect "/myapp/:someparam" , :controller = "foocontroller" , :action = "redirect_to_external_url" In my foo controller i have this action def redirect_to_external_url redirect_to "http://externalurl.com/#{params[:someparam]}.html" end which will redirect to the external url The problem That I am facing is After redirecting, The browser shows "http://externalurl.com/bar.html whereas I want the browser to show "/myapp/bar" url (ex http://mydomain.com/myapp/bar) for seo purpose. Any idea on how this can be achieved in rails ? The Rails version that I am using is 2.3.4

    Read the article

  • How to check which action method rendered the current view (from within the current view) ?

    - by Richard77
    Hello, I would like to know how to check which action displayed the current View (from the current view). For instance, to check if controller myController originated the rendering (I guess) I can write: <% if(ViewContext.Controller is myApplication.Controllers.myController)%> In fact, I want to use the same View model for 2 actions methods, like this: <% If( First Action rendered this view){%> // Display this <%} else {%> //Display that <%}%> Thanks for helping

    Read the article

  • How to save Application State using NSUserDefaults in iPhone?

    - by keith
    Hello Everyone, Following is what i am doing: - (void) applicationWillTerminate: (UIApplication*) application { NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults]; [defaults setObject:navigationController.viewControllers forKey:@"diabetesstate"]; } - (void) applicationDidFinishLaunching: (UIApplication*) application { NSMutableArray *state = [[NSUserDefaults standardUserDefaults] objectForKey:@"diabetesstate"]; if (state == nil) { //Will initialize a new controller and put it as root view controller } else { [navigationController setViewControllers:state animated:NO]; } }

    Read the article

  • How to quit / terminate / stop a j2me midlet?

    - by hsmit
    Surprisingly terminating a midlet doesn't work in my application. Maybe it is because I'm using Threads, but destroyApp() and notifyDestroyed() are not sufficient. Take for example the following code: protected void destroyApp(boolean arg0) throws MIDletStateChangeException { System.out.println("destroying"); notifyDestroyed(); } protected void startApp() throws MIDletStateChangeException { try { // init modules controller.initialize(); }catch (Exception e) { viewer.showAlert("error in startApp() init controller"); destroyApp(true); } }

    Read the article

  • Calling method from view in mvc

    - by Alice in wonderland
    I'm implementing paging on an mvc view, and I want to call a method in the controller from the view view: >a href=">%= Url.Action("Search", new { page = NextPage(Request["exactPage"])).ToString()}) %" controller: public string NextPage(string currentPage) { return (int.Parse(currentPage) + 1).ToString(); } How can I call the NextPage method from the view? thanks!

    Read the article

  • asp.net mvc viewdata best practices

    - by user319353
    Hi: Am trying to understand the ASP.NET MVC ViewData with respect to its size. Since this object is passed between Controller to View, how big this could be? Say for example, if DataTable is passed from Model, and Controller is going to pass it to View. Is there any best practices OR any one had any bad experience to share here? Thanks in advance.

    Read the article

  • NSContextManagedObject - Problem Accessing it

    - by Jacob
    I have tab bar navigation application and The problem is that in my root controller I am able to set its NSContextManagedObject to the app delegates...However when I try to do the same on the other controller the application freezes... This only happens in the ViewDidLoad but thats where I need to set it so I can fetch the data

    Read the article

  • Flex: Constant strings in metadata

    - by Daniel Engmann
    I have something like public class Controller { [Observer("fetchEmployeesEvent")] public function fetchEmployees() : void { //doSomething } } and I want something like public class Controller { public static const FETCH_EMPLOYEES_EVENT : String = "fetchEmployeesEvent"; [Observer(FETCH_EMPLOYEES_EVENT)] public function fetchEmployees() : void { //doSomething } } My problem is that only the first code snippet works. Flex seems to ignore the constant FETCH_EMPLOYEES_EVENT in the metadata-tag. My question is: Is it somehow possible to use constant strings in metadata?

    Read the article

  • how can i request a variable in my home.ctp of my cakePHP application?

    - by Simon
    I created a page using the MVC structure called 'sections' ( view is located in the app/views/sections folder, model in the model folder and the controller in the controller folder) when i request the variable $test, it works fine without any errors.. When i want to request this variable in my home.ctp, it provides me with an error, saying that the variable is undefined.. Is there any way in cakePHP to request this variable on any page you want it to? Thnx in advance!

    Read the article

  • turn array into object active record can use

    - by stormdrain
    I'm running a query and then decrypting it in the controller. After it is decrypted I was putting the results into an array and sending that to the view. The problem is with this solution I need to rewrite all of my views to parse the arrays sent instead of the active record objects sent before. Is there a way to turn the decrypted array back into an object that will work with existing active record code in the view? Before Controller: $name = $this->Clients_model->getNameData('*','client_id='.$clid,''); $data['name'] = $name; $this->load->view('names/name_view',$data); View: if($name->num_rows()) > 0){ foreach($name->result() as $row){ echo $row->data; [...] Now Controller: $name = $this->Clients_model->getNameData('*','client_id='.$clid,''); $nameArray= array(); foreach ($name->result() as $row){ $x = $row; $keys = array('id','client_id'); $unenc = array(); foreach ($x as $key=>$value){ if(! in_array($key, $keys)){ $unenc[$key]=$this->encrypt->decode($value,$this->e_key); }else{ $unenc[$key]=$value; } } array_push($nameArray,$unenc); } //Creates an object with the data, but doesn't work with CI active record //foreach ($nameArray as $akey => $aval) { // $namea -> {$akey} = $aval; //} //return $data; $data['name'] = $nameArray; $this->load->view('names/name_view',$data); View: if(count($name) > 0){ foreach($name as $key=>$row){ echo $row['data']; [...] In the second (now) controller there is some commented out code that will make an object, but it doesn't behave as expected with active record. Is there a way to take the $nameArray() array and change it into an object that will work with existing view code (such as the code in the 'before:view' above)? Thanks!

    Read the article

  • Is a tab bar configuration view can be customized ?

    - by Dirty Henry
    I have an application with 8 tabbar items in the tabbar controller. Is there a way I can customize the layout of the "... (more)" view in which you can configure which tab bar items should appear in the main tab bar. It seems to be a table view controller but i'd like to use custom cell views and a background image.

    Read the article

  • Interface Builder layout ViewController with its own nib

    - by Sean Clark Hess
    I would like to be able to decide where a sub view is placed, when that view is controlled by its own view controller. This happens frequently on the iPad when you have a semi-complicated view that doesn't fill the entire screen. So, imagine that I want the sub view controller's nib to decide its own width, components, connections, etc, while the parent nib would decide where that view/nib would be placed. I'd really like to lay it out visually instead of programatically. How can I?

    Read the article

  • Is there a way to extend controllers in sails.js

    - by alarner
    Often times I will want to perform some action on every page of my web application or make some method available to all of my controllers. In the past with object oriented MVC frameworks I would have all of my controllers extend a root controller, placing everything I wanted done on every page in the constructor of that root controller. How would I accomplish something similar with sails.js / javascript?

    Read the article

  • What is the simplest way to map a folder on the file system to a url in Tomcat?

    - by Simon
    Here's my problem... I have a small prototype app (happens to be in Grails hosted on AWS) and I want to add the ability of the user to upload a few (max 10) images. I want to persist these images on disk on the server machine, in a folder location which is outside my WAR. I realise that there is probably a super-scalable solution involving more web servers and optimised static asset serving, but for the approximately 100 users I am likely to get, it's really not worth the effort and cost. So, what is the simplest way I can have a virtual folder from my url map to a physical folder on disk? I sort of want... http://myapp.com/static to map to a folder which I can configure e.g. /var/www/static so I can then have in my code... <img src="/static/user1/picture.jpg"/> I don't particularly mind whether the resulting physical folders are directly browsable. Security will eventually be an issue, but it isn't at the start. So, what are my options? I have looked at virtual hosts on the apache site, but it feels more complicated than I need. I don't want to use the Grails static rendering plugins.

    Read the article

  • modal view not showing inside didfinishpickingimage

    - by sebastien
    Hi, I have a viewcontroller, and I would like to display a modal view controller with : presentModalViewController when a user finished picking an image. The modal view controller is working fine when I call it from a button in my main view. But when I call it from didfinishpickingimage callback nothing happens. Thanks.

    Read the article

  • Is it bad to use a model directly from a view in codeigniter?

    - by jason
    I know normally the data is passed thru to the view with the controller. however, currently in my view I load my model ($this-load-model('Db_model');) so i can use it in a loop to retrieve a users profile picture path from a array of IDs that is passed from controller. Will loading the db model in the view to accomplish this make my site more vulnerable or bad form? To me it seems to be outside of MVC concept but its working atm. thanks

    Read the article

  • In Rails, how do you functional test a Javascript response format?

    - by Teflon Ted
    If your controller action looks like this: respond_to do |format| format.html { raise 'Unsupported' } format.js # index.js.erb end and your functional test looks like this: test "javascript response..." do get :index end it will execute the HTML branch of the respond_to block. If you try this: test "javascript response..." do get 'index.js' end it executes the view (index.js.erb) withOUT running the controller action!

    Read the article

  • Set a ModelState to an ActionResult in ASP.Net MVC

    - by Marco
    Hi, In a View, I've created a <form> that posts some data to another Controller, which is different from that one that redirected me to the View. In this second controller, i perform some data validations and then, if errors are found, I need to redirect the user again to the source View but with the edited ModelState (so that i can show the validation errors). Any tips?

    Read the article

  • making a password-only auth with bcrypt and mongoose

    - by user3081123
    I want to create service that let you login only with password. You type a password and if this password exists - you are logged in and if it's not - username is generated and password is encrypted. I'm having some misunderstandings and hope someone would help me to show where I'm mistaken. I guess, it would look somewhat like this in agularjs First we receive a password in login controller. $scope.signup = function() { var user = { password: $scope.password, }; $http.post('/auth/signup', user); }; Send it via http.post and get in in our node server file. We are provided with a compare password bcrypt function userSchema.methods.comparePassword = function(candidatePassword, cb) { bcrypt.compare(candidatePassword, this.password, function(err, isMatch) { if (err) return cb(err); cb(null, isMatch); }); }; So right now we are creating function to catch our http request app.post('/auth/signup', function(req, res, next) { Inside we use a compair password function to realize if such password exists or not yet. So we have to encrypt a password with bcrypt to make a comparison First we hash it same way as in .pre var encPass; bcrypt.genSalt(10, function(err, salt) { if (err) return next(err); bcrypt.hash(req.body.password, salt, function(err, hash) { if (err) return next(err); encPass=hash; )}; )}; We have encrypted password stored in encPass so now we follow to finding a user in database with this password User.findOne({ password: encPass }, function(err, user) { if (user) { //user exists, it means we should pass an ID of this user to a controller to display it in a view. I don't know how. res.send({user.name}) //like this? How should controller receive this? With $http.post? } else { and now if user doesn't exist - we should create it with user ID generated by my function var nUser = new User({ name: generId(), password: req.body.password }); nUser.save(function(err) { if (err) return next(err); )}; )}; )}; Am I doing anything right? I'm pretty new to js and angular. If so - how do I throw a username back at controller? If someone is interested - this service exists for 100+ symbol passphrases so possibility of entering same passphrase as someone else is miserable. And yeah, If someone logged in under 123 password - the other guy will log in as same user if he entered 123 password, but hey, you are warned to make a big passphrase. So I'm confident about the idea and I only need a help with understanding and realization.

    Read the article

  • When using the Auth component with CakePHP, I keep ketting this error. Why?

    - by Josh Brown
    Warning (2): Cannot modify header information - headers already sent by (output started at /Applications/MAMP/htdocs/iframeworking/iframe/app/models/frame.php:7) [COREcake/libs/controller/controller.php, line 647] here is the code from frame.php: <?php class Frame extends AppModel { var $name = 'Frame'; var $belongsTo = array('User' => array('className' => 'User', 'dependent' => true)); } ?>

    Read the article

< Previous Page | 142 143 144 145 146 147 148 149 150 151 152 153  | Next Page >