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• How to Animate Text and Objects in PowerPoint 2010

  - by DigitalGeekery

  Are you looking for an eye catching way to keep your audience interested in your PowerPoint presentations? Today we’ll take a look at how to add animation effects to objects in PowerPoint 2010. Select the object you wish to animate and then click the More button in the Animation group of the Animation tab.   Animations are grouped into four categories. Entrance effects, Exit effects, Emphasis effects, and Motion Paths. You can get a Live Preview of how the animation will look by hovering your mouse over an animation effect.   When you select a Motion Path, your object will move along the dashed path line as shown on the screen. (This path is not displayed in the final output) Certain aspects of the Motion Path effects are editable. When you apply a Motion Path animation to an object, you can select the path and drag the end to change the length or size of the path. The green marker along the motion path marks the beginning of the  path and the red marks the end. The effects can be rotated by clicking and the bar near the center of the effect.   You can display additional effects by choosing one of the options at the bottom. This will pop up a Change Effect window. If you have Preview Effect checked at the lower left you can preview the effects by single clicking.   Apply Multiple Animations to an Object Select the object and then click the Add Animation button to display the animation effects. Just as we did with the first effect, you can hover over to get a live preview. Click to apply the effect. The animation effects will happen in the order they are applied. Animation Pane You can view a list of the animations applied to a slide by opening the Animation Pane. Select the Animation Pane button from the Advanced Animation group to display the Animation Pane on the right. You’ll see that each animation effect in the animation pane has an assigned number to the left.    Timing Animation Effects You can change when your animation starts to play. By default it is On Click. To change it, select the effect in the Animation Pane and then choose one of the options from the Start dropdown list. With Previous starts at the same time as the previous animation and After Previous starts after the last animation. You can also edit the duration that the animations plays and also set a delay.   You can change the order in which the animation effects are applied by selecting the effect in the animation pane and clicking Move Earlier or Move Later from the Timing group on the Animation tab. Effect Options If the Effect Options button is available when your animation is selected, then that particular animation has some additional effect settings that can be configured. You can access the Effect Option by right-clicking on the the animation in the Animation Pane, or by selecting Effect Options on the ribbon.   The available options will vary by effect and not all animation effects will have Effect Options settings. In the example below, you can change the amount of spinning and whether the object will spin clockwise or counterclockwise.   Under Enhancements, you can add sound effects to your animation. When you’re finished click OK.   Animating Text Animating Text works the same as animating an object. Simply select your text box and choose an animation. Text does have some different Effect Options. By selecting a sequence, you decide whether the text appears as one object, all at once, or by paragraph. As is the case with objects, there will be different available Effect Options depending on the animation you choose. Some animations, such as the Fly In animation, will have directional options.   Testing Your Animations Click on the Preview button at any time to test how your animations look. You can also select the Play button on the Animation Pane. Conclusion Animation effects are a great way to focus audience attention on important points and hold viewers interest in your PowerPoint presentations. Another cool way to spice up your PPT 2010 presentations is to add video from the web. What tips do you guys have for making your PowerPoint presentations more interesting? Similar Articles Productive Geek Tips Center Pictures and Other Objects in Office 2007 & 2010Preview Before You Paste with Live Preview in Office 2010Embed True Type Fonts in Word and PowerPoint 2007 DocumentsHow to Add Video from the Web in PowerPoint 2010Add Artistic Effects to Your Pictures in Office 2010 TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 24 Million Sites Windows Media Player Glass Icons (icons we like) How to Forecast Weather, without Gadgets Outlook Tools, one stop tweaking for any Outlook version Zoofs, find the most popular tweeted YouTube videos Video preview of new Windows Live Essentials

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• Tip #13 java.io.File Surprises

  - by ByronNevins

  There is an assumption that I've seen in code many times that is totally wrong.  And this assumption can easily bite you.  The assumption is: File.getAbsolutePath and getAbsoluteFile return paths that are not relative.  Not true!  Sort of.  At least not in the way many people would assume.  All they do is make sure that the beginning of the path is absolute.  The rest of the path can be loaded with relative path elements.  What do you think the following code will print? public class Main {    public static void main(String[] args) {        try {            File f = new File("/temp/../temp/../temp/../");            File abs  = f.getAbsoluteFile();            File parent = abs.getParentFile();            System.out.println("Exists: " + f.exists());            System.out.println("Absolute Path: " + abs);            System.out.println("FileName: " + abs.getName());            System.out.printf("The Parent Directory of %s is %s\n", abs, parent);            System.out.printf("The CANONICAL Parent Directory of CANONICAL %s is %s\n",                        abs, abs.getCanonicalFile().getParent());            System.out.printf("The CANONICAL Parent Directory of ABSOLUTE %s is %s\n",                        abs, parent.getCanonicalFile());            System.out.println("Canonical Path: " + f.getCanonicalPath());        }        catch (IOException ex) {            System.out.println("Got an exception: " + ex);        }    }} Output: Exists: trueAbsolute Path: D:\temp\..\temp\..\temp\..FileName: ..The Parent Directory of D:\temp\..\temp\..\temp\.. is D:\temp\..\temp\..\tempThe CANONICAL Parent Directory of CANONICAL D:\temp\..\temp\..\temp\.. is nullThe CANONICAL Parent Directory of ABSOLUTE D:\temp\..\temp\..\temp\.. is D:\tempCanonical Path: D:\ Notice how it says that the parent of d:\ is d:\temp !!!The file, f, is really the root directory.  The parent is supposed to be null. I learned about this the hard way! getParentXXX simply hacks off the final item in the path. You can get totally unexpected results like the above. Easily. I filed a bug on this behavior a few years ago[1].   Recommendations: (1) Use getCanonical instead of getAbsolute.  There is a 1:1 mapping of files and canonical filenames.  I.e each file has one and only one canonical filename and it will definitely not have relative path elements in it.  There are an infinite number of absolute paths for each file. (2) To get the parent file for File f do the following instead of getParentFile: File parent = new File(f, ".."); [1] http://bt2ws.central.sun.com/CrPrint?id=6687287

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• Impersonation in ASP.NET MVC

  - by eibrahim

  I have an Action that needs to read a file from a secure location, so I have to use impersonation to read the file. This code WORKS: [AcceptVerbs(HttpVerbs.Get)] public ActionResult DirectDownload(Guid id) { if (Impersonator.ImpersonateValidUser()) { try { var path = "path to file"; if (!System.IO.File.Exists(path)) { return View("filenotfound"); } var bytes = System.IO.File.ReadAllBytes(path); return File(bytes, "application/octet-stream", "FileName"); } catch (Exception e) { Log.Exception(e); }finally { Impersonator.UndoImpersonation(); } } return View("filenotfound"); } The only problem with the above code is that I have to read the entire file into memory and I am going to be dealing with VERY large files, so this is not a good solution. But if I replace these 2 lines: var bytes = System.IO.File.ReadAllBytes(path); return File(bytes, "application/octet-stream", "FileName"); with this: return File(path, "application/octet-stream", "FileName"); It does NOT work and I get the error message: Access to the path 'c:\projects\uploads\1\aa2bcbe7-ea99-499d-add8-c1fdac561b0e\Untitled 2.csv' is denied. I guess using the File results with a path, tries to open the file at a later time in the request pipeline when I have already "undone" the impersonation. Remember, the impersonation code works because I can read the file in the bytes array. What I want to do though is stream the file to the client. Any idea how I can work around this? Thanks in advance.

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• Re: How can Django/WSGI and PHP share / on Apache?

  - by Bogdan

  in response to: How can Django/WSGI and PHP share / on Apache? Hello, could you please post the complete config file from /sites-available I am having a problem seems like rewrite engine redirects all requests to django, so static and php files are not served and instead i see the django 404 page. If I get rid of rewrite rule then static files and php works. here is my apache config file from /sites-available <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/www/django <Directory /> Options +FollowSymLinks ExecCGI Indexes AllowOverride None DirectoryIndex index.php AddHandler wsgi-script .wsgi </Directory> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ /mysite.wsgi/$1 [QSA,PT,L] ~ and my .wsgi file: import site site.addsitedir('/home/user/.virtualenvs/url.com/lib/python2.6/site-packages') import os, sys path = '/home/www/django' if path not in sys.path: sys.path.append(path) os.environ['DJANGO_SETTINGS_MODULE'] = 'mysite.settings' sys.path.append(path + '/mysite') import django.core.handlers.wsgi _application = django.core.handlers.wsgi.WSGIHandler() import posixpath def application(environ, start_response): # Wrapper to set SCRIPT_NAME to actual mount point. environ['SCRIPT_NAME'] = posixpath.dirname(environ['SCRIPT_NAME']) if environ['SCRIPT_NAME'] == '/': environ['SCRIPT_NAME'] = '' return _application(environ, start_response) the document root directory on disk (/home/www/django) contains php files, images, and the mysite.wsgi file.. thanks for your help

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• Writing files in App_Data causes tempdata to be null

  - by RAMX

  I have a small asp.net MVC 1 web app that can store files and create directories in the App_Data directory. When the write operation succeeds, I add a message to the tempdata and do a redirectToRoute. The problem is that the tempdata is null when the action is executed. If i write the files in a directory outside of the web applications root directory, the tempdata is not null and everything works correctly. Any ideas why writing in the app_data seems to clear the tempdata ? edit: if DRS.Logic.Repository.Manager.CreateFile(path, hpf, comment) writes in the App_Data, TempData will be null in the action being redirected to. if it is a directory out of the web app root it is fine. No exceptions are being thrown. [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create(int id, string path, FormCollection form) { ViewData["path"] = path; ViewData["id"] = id; HttpPostedFileBase hpf; string comment = form["FileComment"]; hpf = Request.Files["File"] as HttpPostedFileBase; if (hpf.ContentLength != 0) { DRS.Logic.Repository.Manager.CreateFile(path, hpf, comment); TempData["notification"] = "file was created"; return RedirectToRoute(new { controller = "File", action ="ViewDetails", id = id, path = path + Path.GetFileName(hpf.FileName) }); } else { TempData["notification"] = "No file were selected."; return View(); } }

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• Setting LD_LIBRARY_PATH in Apache PassEnv/SetEnv still cant find library

  - by DoMoreASAP

  I am trying to test the Cybersource 3d party implementation. I was able to get the test files running fine from the command line, which requires that on Linux I export the path to the payment libraries to LD_LIBRARY_PATH. to try to test this on my server I have created the apache config below <VirtualHost 127.0.0.1:12345> AddHandler cgi-script .cgi AddHandler fcgid-script .php .fcgi FCGIWrapper /my/path/to/php_fcgi/bin/php-cgi .php AddType text/html .shtml AddOutputFilter INCLUDES .shtml DocumentRoot /my/path/to/cybersource/simapi-php-5.0.1/ ProxyPreserveHost on <Directory /my/path/to/cybersource/simapi-php-5.0.1> SetEnv LD_LIBRARY_PATH /my/path/to/cybersource/LinkedLibraries/lib/ AllowOverride all Options +Indexes IndexOptions Charset=UTF-8 </Directory> </VirtualHost> I have set the env variable there with SetEnv command, which seems to be working when i run a page that prints <?php phpinfo(); ?> however the test script when called through the browser still wont work, apache says: tail /my/apache/error_log [Tue Mar 30 23:11:46 2010] [notice] mod_fcgid: call /my/path/to/cybersource/index.php with wrapper /my/path/to/cybersource/php_fcgi/bin/php-cgi PHP Warning: PHP Startup: Unable to load dynamic library '/my/path/to/cybersource/extensionsdir/php5_cybersource.so' - libspapache.so: cannot open shared object file: No such file or directory in Unknown on line 0 so it cant find the linked file libspapache.so even though it is in the LD_LIBRARY_PATH that is supposedly defined i really appreciate the help. thanks so much.

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• Why do I get completely different results when saving a BitmapSource to bmp, jpeg, and png in WPF

  - by DanM

  I wrote a little utility class that saves BitmapSource objects to image files. The image files can be either bmp, jpeg, or png. Here is the code: public class BitmapProcessor { public void SaveAsBmp(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new BmpBitmapEncoder()); } public void SaveAsJpg(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new JpegBitmapEncoder()); } public void SaveAsPng(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new PngBitmapEncoder()); } private void Save(BitmapSource bitmapSource, string path, BitmapEncoder encoder) { using (var stream = new FileStream(path, FileMode.Create)) { encoder.Frames.Add(BitmapFrame.Create(bitmapSource)); encoder.Save(stream); } } } Each of the three Save methods work, but I get unexpected results with bmp and jpeg. Png is the only format that produces an exact reproduction of what I see if I show the BitmapSource on screen using a WPF Image control. Here are the results: BMP - too dark JPEG - too saturated PNG - correct Why am I getting completely different results for different file types? I should note that the BitmapSource in my example uses an alpha value of 0.1 (which is why it appears very desaturated), but it should be possible to show the resulting colors in any image format. I know if I take a screen capture using something like HyperSnap, it will look correct regardless of what file type I save to. Here's a HyperSnap screen capture saved as a bmp: As you can see, this isn't a problem, so there's definitely something strange about WPF's image encoders. Do I have a setting wrong? Am I missing something?

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• Trying to use a authlogic-connect as a plugin in place of gem - Server doesn't start

  - by Arkid

  I am trying to use Authlogic-connect as a plugin in Rails 3 in place of a gem. I have made an entry in the gemfile as gem "authlogic-connect", :require => "authlogic-connect", :path => "localgems" Now when I run the bundle install, it runs fine. When I try to start the server i get the error Could not find gem 'authlogic-connect (>= 0, runtime)' in source at localgems. Source does not contain any versions of 'authlogic-connect (>= 0, runtime)' Try running `bundle install`. I have placed the unzipped Gem renamed as authlogic-connect in the localgems folder. what is the problem? Here is what I get on using rails plugin install arkidmitra$ rails plugin install git://github.com/viatropos/authlogic-connect.git Usage: rails new APP_PATH [options] Options: [--skip-gemfile] # Don't create a Gemfile -d, [--database=DATABASE] # Preconfigure for selected database (options: mysql/oracle/postgresql/sqlite3/frontbase/ibm_db) # Default: sqlite3 -O, [--skip-active-record] # Skip Active Record files [--dev] # Setup the application with Gemfile pointing to your Rails checkout -J, [--skip-prototype] # Skip Prototype files -T, [--skip-test-unit] # Skip Test::Unit files -G, [--skip-git] # Skip Git ignores and keeps -r, [--ruby=PATH] # Path to the Ruby binary of your choice # Default: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby -m, [--template=TEMPLATE] # Path to an application template (can be a filesystem path or URL) -b, [--builder=BUILDER] # Path to an application builder (can be a filesystem path or URL) [--edge] # Setup the application with Gemfile pointing to Rails repository Runtime options: -q, [--quiet] # Supress status output -s, [--skip] # Skip files that already exist -f, [--force] # Overwrite files that already exist -p, [--pretend] # Run but do not make any changes Rails options: -h, [--help] # Show this help message and quit -v, [--version] # Show Rails version number and quit Description: The 'rails new' command creates a new Rails application with a default directory structure and configuration at the path you specify. Example: rails new ~/Code/Ruby/weblog This generates a skeletal Rails installation in ~/Code/Ruby/weblog. See the README in the newly created application to get going.

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• Use localeURL middleware with apache prefix

  - by Olivier R.

  Good morning everyone, I Got a question about localeURL usage. Everything works great for me with url like this : www.mysite.com/ If I type www.mysite.com/ in adress bar, it turns correctly in www.mysite.com/en/ for example. If I use the view change_locale, it's also all right (ie change www.mysite.com/en/ in www.mysite.com/fr/). But my application use apache as server, and use a prefix for the site, that gives url like this : www.mysite.com/prefix/ If I type www.mysite.com/prefix/ in the adress bar, the adress turns into www.mysite.com/en/ without prefix (so 404) I change code of view to manage our settings.SERVER_PREFIX value : def change_locale(request) : """ Redirect to a given url while changing the locale in the path The url and the locale code need to be specified in the request parameters. O. Rochaix; Taken from localeURL view, and tuned to manage : - SERVER_PREFIX from settings.py """ next = request.REQUEST.get('next', None) if not next: next = request.META.get('HTTP_REFERER', None) if not next: next = settings.SERVER_PREFIX + '/' next = urlsplit(next).path prefix = False if settings.SERVER_PREFIX!="" and next.startswith(settings.SERVER_PREFIX) : prefix = True next = "/" + next.lstrip(settings.SERVER_PREFIX) _, path = utils.strip_path (next) if request.method == 'POST': locale = request.POST.get('locale', None) if locale and check_for_language(locale): path = utils.locale_path(path, locale) if prefix : path = settings.SERVER_PREFIX + path response = http.HttpResponseRedirect(path) return response with this customized view, i'm able to correctly change language, but i'm not sure that's the right way of doing stuff. Is there any option on localeURL to manage prefix of apache ?

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• Using undefined type.

  - by Knowing me knowing you

  //file list.h #include "stdafx.h" namespace st { struct My_List; typedef My_List list; list* create(const char* name); } //file list.cpp #include "stdafx.h" #include "list.h" namespace st { struct My_List { const char* name_; My_List* left_; My_List* right_; My_List(const char* name):name_(name), left_(nullptr), right_(nullptr) {} My_List(const My_List&); ~My_List() { } void insert(My_List*); void set_name(char* name) { name_ = name; } const char* get_name()const { return name_; } }; typedef My_List list; /*helper class for optor+ */ struct MyChar { const char* my_data_; MyChar(const char* c_string):my_data_(c_string){} operator const char*() { return my_data_; } operator char*() { return const_cast<char*>(my_data_); } }; char* operator+(MyChar left_, MyChar right_) { if (!left_.my_data_ || !right_.my_data_) { return 0; } size_t size = 1;//size is set to one for final '\0' char in an array char* p = "";//if both c_strings are empty this is returned bool has_left_ = false; bool has_right_ = false; if (strlen(left_)) { size += strlen(left_); has_left_ = true; } if (strlen(right_)) { size += strlen(right_); has_right_ = true; } bool both = has_left_ && has_right_ ? true : false; if (both) { p = new char[size](); const void* p_v = p;//just to keep address of beginning of p const char* tmp = left_; /*copying first c_string*/ while (*p++ = *tmp++); tmp = right_; /*one too far after last loop*/ --p; while (*p++ = *tmp++); *p = '\0'; /*go back to the beginning of an array*/ p = static_cast<char*>(const_cast<void*>(p_v)); return p; } else if (has_left_) { return left_; } else if (has_right_) { return right_; } return p;//returns "" if both c_strings were empty } My_List::My_List(const My_List& pat):left_(nullptr),right_(nullptr) { name_ = pat.name_ + MyChar("_cpy"); My_List* pattern = const_cast<My_List*>(&pat); My_List* target = this; while (pattern->right_) { target->right_ = static_cast<My_List*>(malloc(sizeof(My_List))); *target->right_ = *pattern->right_; target->right_->set_name(pattern->right_->get_name() + MyChar("_cpy")); target->right_->left_ = static_cast<My_List*>(malloc(sizeof(My_List))); *target->right_->left_ = *pattern->right_->left_; target->right_->left_->set_name(pattern->right_->left_->get_name() + MyChar("_cpy")); pattern = pattern->right_; target = target->right_; } } void My_List::insert(My_List* obj) { /*to catch first branch*/ My_List* tmp = this; if (tmp->right_) { /*go to the end of right side*/ while (tmp->right_) { tmp = tmp->right_; } tmp->right_ = obj; obj->left_ = tmp; } else { tmp->right_ = obj; obj->left_= this; } } My_List* create(const char* name) { return new My_List(name); } } //file main.cpp #include "stdafx.h" #include "list.h" using namespace st; int _tmain(int argc, _TCHAR* argv[]) { list* my = create("a"); list* b = create("b"); my->insert(b);//HERE I'M GETTING ERROR return 0; } err msg: 'Error 1 error C2027: use of undefined type 'st::My_List' 13' Why? Especially that if I comment this line it will get compiled and create() is using this type.

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• Spring Custom Filter Problem?

  - by mr.lost

  greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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• Matching Regular Expression in Javascript and PHP problem...

  - by Frankie

  I can't figure out how to get the same result from my Javscript as I do from my PHP. In particular, Javascript always leaves out the backslashes. Please ignore the random forward and backslashes; I put them there so that I can cover my basis on a windows system or any other system. Output: Input String: "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:" /root\wp-content\image6.jpg (PHP Output) /rootwp-contentimage6.jpg (Javscript Output) I would appreciate any help! PHP: <?php $path ="/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; $path = preg_replace("/[^a-zA-Z0-9\\\\\/\.-]/", "", $path); echo $path; ?> Javascript: <script type="text/javascript"> var path = "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; //exact same string as PHP var regx = /[^a-zA-Z0-9\.\/-]/g; path = path.replace(regx,""); document.write("<br>"+path); </script>

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• Custom Filter Problem?

  - by mr.lost

  greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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• django+mod_wsgi on virtualenv not working

  - by jwesonga

  I've just finished setting up a django app on virtualenv, deployment went smoothly using a fabric script, but now the .wsgi is not working, I've tried every variation on the internet but no luck. My .wsgi file is: import os import sys import django.core.handlers.wsgi # put the Django project on sys.path root_path = os.path.abspath(os.path.dirname(__file__) + '../') sys.path.insert(0, os.path.join(root_path, 'kcdf')) sys.path.insert(0, root_path) os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings' application = django.core.handlers.wsgi.WSGIHandler() I keep getting the same error: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'. [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last): [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self.load_middleware() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] for middleware_path in settings.MIDDLEWARE_CLASSES: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._setup() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._wrapped = Settings(settings_module) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings my virtual environment is on /home/user/webapps/kcdfweb my app is /home/user/webapps/kcdf.web/releases/current/project_name my wsgi file home/user/webapps/kcdf.web/releases/current/project_name/apache/project_name.wsgi

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• django inner redirects

  - by Zayatzz

  Hello I have one project that in my own development computer (uses mod_wsgi to serve the project) caused no problems. In live server (uses mod_fastcgi) it generates 500 though. my url conf is like this: # -*- coding: utf-8 -*- from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^admin/', include(admin.site.urls)), url(r'^', include('jalka.game.urls')), ) and # -*- coding: utf-8 -*- from django.conf.urls.defaults import * from django.contrib.auth import views as auth_views urlpatterns = patterns('jalka.game.views', url(r'^$', view = 'front', name = 'front',), url(r'^ennusta/(?P<game_id>\d+)/$', view = 'ennusta', name = 'ennusta',), url(r'^login/$', auth_views.login, {'template_name': 'game/login.html'}, name='auth_login'), url(r'^logout/$', auth_views.logout, {'template_name': 'game/logout.html'}, name='auth_logout'), url(r'^arvuta/$', view = 'arvuta', name = 'arvuta',), ) and .htaccess is like that: Options +FollowSymLinks RewriteEngine on RewriteOptions MaxRedirects=10 # RewriteCond %{HTTP_HOST} . RewriteCond %{HTTP_HOST} ^www\.domain\.com RewriteRule (.*) http://domain.com/$1 [R=301,L] AddHandler fastcgi-script .fcgi RewriteCond %{HTTP_HOST} ^jalka\.domain\.com$ [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*) cgi-bin/fifa2010.fcgi/$1 [QSA,L] RewriteCond %{HTTP_HOST} ^subdomain\.otherdomain\.eu$ [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*) cgi-bin/django.fcgi/$1 [QSA,L] Notice, that i have also other project set up with same .htaccess and that one is running just fine with more complex urls and views fifa2010.fcgi: #!/usr/local/bin/python # -*- coding: utf-8 -*- import sys, os DOMAIN = "domain.com" APPNAME = "jalka" PREFIX = "/www/apache/domains/www.%s" % (DOMAIN,) # Add a custom Python path. sys.path.insert(0, os.path.join(PREFIX, "htdocs/django/Django-1.2.1")) sys.path.insert(0, os.path.join(PREFIX, "htdocs")) sys.path.insert(0, os.path.join(PREFIX, "htdocs/jalka")) # Switch to the directory of your project. (Optional.) os.chdir(os.path.join(PREFIX, "htdocs", APPNAME)) # Set the DJANGO_SETTINGS_MODULE environment variable. os.environ['DJANGO_SETTINGS_MODULE'] = "%s.settings" % (APPNAME,) from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") Alan

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• WCF done broke.

  - by SteveCav

  WCF is completely fouled up on my machine. I start a new sln in VS2008. Add a project (WCF Service Lib).Build the project (builds ok). debug the project -- it gets halfway through the progress bar and bombs out with the error below (real path changed to "my mex path" so codeproject doesn't think its spam). I'm assuming it's file permissions but don't know where to start. Any ideas?: Error: Cannot obtain Metadata from my mex path If this is a Windows (R) Communication Foundation service to which you have access, please check that you have enabled metadata publishing at the specified address. For help enabling metadata publishing, please refer to the MSDN documentation at somewhere unhelpful Exchange Error URI: my mex path Metadata contains a reference that cannot be resolved: 'my mex path'. Could not connect to my mex path. TCP error code 10061: No connection could be made because the target machine actively refused it 127.0.0.1:8731. Unable to connect to the remote server No connection could be made because the target machine actively refused it 127.0.0.1:8731HTTP GET Error URI: my mex path There was an error downloading 'my mex path'. Unable to connect to the remote server No connection could be made because the target machine actively refused it 127.0.0.1:8731

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• More efficient approach to XSLT for-each

  - by Paul

  I have an XSLT which takes a . delimted string and splits it into two fields for a SQL statement: <xsl:for-each select="tokenize(Path,'\.')"> <xsl:choose> <xsl:when test="position() = 1 and position() = last()">SITE = '<xsl:value-of select="."/>' AND PATH = ''</xsl:when> <xsl:when test="position() = 1 and position() != last()">SITE = '<xsl:value-of select="."/>' </xsl:when> <xsl:when test="position() = 2 and position() = last()">AND PATH = '<xsl:value-of select="."/>' </xsl:when> <xsl:when test="position() = 2">AND PATH = '<xsl:value-of select="."/></xsl:when> <xsl:when test="position() > 2 and position() != last()">.<xsl:value-of select="."/></xsl:when> <xsl:when test="position() > 2 and position() = last()">.<xsl:value-of select="."/>' </xsl:when> <xsl:otherwise>zxyarglfaux</xsl:otherwise> </xsl:choose> </xsl:for-each> The results are as follows: INPUT: North OUTPUT: SITE = 'North' AND PATH = '' INPUT: North.A OUTPUT: SITE = 'North' AND PATH = 'A' INPUT: North.A.B OUTPUT: SITE = 'North' AND PATH = 'A.B' INPUT: North.A.B.C OUTPUT: SITE = 'North' AND PATH = 'A.B.C' This works, but is very lengthy. Can anyone see a more efficient approach? Thanks!

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• Have an unprivileged non-account user ssh into another box?

  - by Daniel Quinn

  I know how to get a user to ssh into another box with a key: ssh -l targetuser -i path/to/key targethost But what about non-account users like apache? As this user doesn't have a home directory to which it can write a .ssh directory, the whole thing keeps failing with: $ sudo -u apache ssh -o StrictHostKeyChecking=no -l targetuser -i path/to/key targethost Could not create directory '/var/www/.ssh'. Warning: Permanently added '<hostname>' (RSA) to the list of known hosts. Permission denied (publickey). I've tried variations using -o UserKnownHostsFile=/dev/null and setting $HOME to /dev/null and none of these have done the trick. I understand that sudo could probably fix this for me, but I'm trying to avoid having to require a manual server config since this code will be deployed on a number of different environments. Any ideas? Here's a few examples of what I've tried that don't work: $ sudo -u apache export HOME=path/to/apache/writable/dir/ ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=path/to/apache/writable/dir/.ssh/known_hosts -l deploy -i path/to/key targethost $ sudo -u apache ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=path/to/apache/writable/dir/.ssh/known_hosts -l deploy -i path/to/key targethost $ sudo -u apache ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=/dev/null -l deploy -i path/to/key targethost Eventually, I'll be using this solution to run rsync as the apache user.

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• VBA: How go I get the total width from all controls in an MS-Access form?

  - by Stefan Åstrand

  Hi, This is probably very basic stuff, but please bear in mind I am completely new to these things. I am working on a procedure for my Access datasheet forms that will: Adjust the width of each column to fit content Sum the total width of all columns and subtract it from the size of the window's width Adjust the width of one of the columns to fit the remaining space This is the code that adjusts the width of each column to fit content (which works fine): Dim Ctrl As Control Dim Path As String Dim ClmWidth As Integer 'Adjust column width to fit content For Each Ctrl In Me.Controls If TypeOf Ctrl Is TextBox Then Path = Ctrl.Name Me(Path).ColumnWidth = -2 End If Next Ctrl How should I write the code so I get the total width of all columns? Thanks a lot! Stefan Solution This is the code that makes an Access datasheet go from this: To this: Sub AdjustColumnWidth(frm As Form, clm As String) On Error GoTo HandleError Dim intWindowWidth As Integer ' Window width property Dim ctrl As Control ' Control Dim intCtrlWidth As Integer ' Control width property Dim intCtrlSum As Integer ' Control width property sum Dim intCtrlAdj As Integer ' Control width property remaining after substracted intCtrSum 'Adjust column width to standard width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name frm(Path).ColumnWidth = 1500 End If Next ctrl 'Get total column width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name intCtrlWidth = frm(Path).ColumnWidth If Path <> clm Then intCtrlSum = intCtrlSum + intCtrlWidth End If End If Next ctrl 'Adjust column to fit window intWindowWidth = frm.WindowWidth - 270 intCtrlAdj = intWindowWidth - intCtrlSum frm.Width = intWindowWidth frm(clm).ColumnWidth = intCtrlAdj Debug.Print "Totalt (Ctrl): " & intCtrlSum Debug.Print "Totalt (Window): " & intWindowWidth Debug.Print "Totalt (Remaining): " & intCtrlAdj Debug.Print "clm : " & clm HandleError: GeneralErrorHandler Err.Number, Err.Description Exit Sub End Sub Code to call procedure: Private Sub Form_Load() Call AdjustColumnWidth(Me, "txtDescription") End Sub

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• How to create a semi transparent window in WPF that allows mouse events to pass through

  - by RMK

  I am trying to create an effect similar to the Lights out /lights dim feature in Adobe Lightroom (http://www.youtube.com/watch?v=87hNd3vaENE) except in WPF. What I tried was to create another window over-top of my existing window, make it transparent and put a semi transparent Path geometry on it. But I want mouse events to be able to pass through this semi transparent window (on to windows below). This is a simplified version of what I have: <Window x:Class="LightsOut.MaskWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" AllowsTransparency="True" WindowStyle="None" ShowInTaskbar="False" Topmost="True" Background="Transparent"> <Grid> <Button HorizontalAlignment="Left" Height="20" Width="60">click</Button> <Path IsHitTestVisible="False" Stroke="Black" Fill="Black" Opacity="0.3"> <Path.Data> <RectangleGeometry Rect="0,0,1000,1000 "/> </Path.Data> </Path> </Grid> The window is fully transparent, so on places where the Path doesn't cover, mouse events pass right through. So far so good. The IsHitTestvisible is set to false on the path object. So mouse events will pass through it to other controls on the same form (ie you can click on the Button, because it is on the same form). But mouse events wont pass through the Path object onto windows that are below it. Any ideas? Or better ways to solve this problem? Thanks.

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• Baffled by differences between WPF BitmapEncoders

  - by DanM

  I wrote a little utility class that saves BitmapSource objects to image files. The image files can be either bmp, jpeg, or png. Here is the code: public class BitmapProcessor { public void SaveAsBmp(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new BmpBitmapEncoder()); } public void SaveAsJpg(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new JpegBitmapEncoder()); } public void SaveAsPng(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new PngBitmapEncoder()); } private void Save(BitmapSource bitmapSource, string path, BitmapEncoder encoder) { using (var stream = new FileStream(path, FileMode.Create)) { encoder.Frames.Add(BitmapFrame.Create(bitmapSource)); encoder.Save(stream); } } } Each of the three Save methods work, but I get unexpected results with bmp and jpeg. Png is the only format that produces an exact reproduction of what I see if I show the BitmapSource on screen using a WPF Image control. Here are the results: BMP - too dark JPEG - too saturated PNG - correct Why am I getting completely different results for different file types? I should note that the BitmapSource in my example uses an alpha value of 0.1 (which is why it appears very desaturated), but it should be possible to show the resulting colors in any image format. I know if I take a screen capture using something like HyperSnap, it will look correct regardless of what file type I save to. Here's a HyperSnap screen capture saved as a bmp: As you can see, this isn't a problem, so there's definitely something strange about WPF's image encoders. Do I have a setting wrong? Am I missing something?

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• Segmentation fault

  - by darkie15

  #include<stdio.h> #include<zlib.h> #include<unistd.h> #include<string.h> int main(int argc, char *argv[]) { char *path=NULL; size_t size; int index ; printf("\nArgument count is = %d", argc); printf ("\nThe 0th argument to the file is %s", argv[0]); path = getcwd(path, size); printf("\nThe current working directory is = %s", path); if (argc <= 1) { printf("\nUsage: ./output filename1 filename2 ..."); } else if (argc > 1) { for (index = 1; index <= argc;index++) { printf("\n File name entered is = %s", argv[index]); strcat(path,argv[index]); printf("\n The complete path of the file name is = %s", path); } } return 0; } In the above code, here is the output that I get while running the code: $ ./output test.txt Argument count is = 2 The 0th argument to the file is ./output The current working directory is = /home/welcomeuser File name entered is = test.txt The complete path of the file name is = /home/welcomeusertest.txt Segmentation fault (core dumped) Can anyone please me understand why I am getting a core dumped error? Regards, darkie

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• HttpPostedFile.SaveAs() throws UnauthorizedAccessException even though the file is saved?

  - by jrummell

  I have an aspx page with multiple FileUpload controls and one Upload button. In the click handler I save the files like this: string path = "..."; for (int i = 0; i < Request.Files.Count - 1; i++) { HttpPostedFile file = Request.Files[i]; string fileName = Path.GetFileName(file.FileName); string saveAsPath = Path.Combine(path, fileName); file.SaveAs(saveAsPath); } When file.SaveAs() is called, it throws: System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. --- System.UnauthorizedAccessException: Access to the path '...' is denied. at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode) at System.Web.HttpPostedFile.SaveAs(String filename) at Belden.Web.Intranet.Iso.Complaints.AttachmentUploader.btnUpload_Click(Object sender, EventArgs e) at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) --- End of inner exception stack trace --- at System.Web.UI.Page.HandleError(Exception e) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest() at System.Web.UI.Page.ProcessRequest(HttpContext context) at ASP.departments_iso_complaints_uploadfiles_aspx.ProcessRequest(HttpContext context) at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) Now here's the fun part. The file is saved correctly! So why is it throwing this exception?

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• Failure to connect to admin share pops up dialog

  - by Jan

  I'm having an issue with a curious error message when accessing the administrative share on a remote machine. Specifically, the client is logged in as the domain administrator on the machine A, and runs some code that tries to access the admin share on B (a domain member). The access is done in .NET, along these lines (though I am not sure if the method of access makes a difference): string path = @"\\B\admin$"; if (Directory.Exists(path)) { try { path += @"\temp\"; if (!Directory.Exists(path)) { Directory.CreateDirectory(path); } path += "myfile_remote"; File.Copy("myfile", path); Now, on some machines this fails. That is not a big problem as we have a fallback. I'd like to know why but it is not the real issue. The problem is that running this piece of code causes a dialog box to pop up for the logged-in user on B, saying "network error trying to access \\B\admin$\temp\myfile_remote. Contact the network administrator and ask for the correct permissions". Unfortunately, it is a foreign language Windows so I'll spare you all posting a screenshot. It is skinned like a standard Windows dialog box. Why exactly is that dialog box popping up for the user and is there anything I can do about it? Edit to add: B is a Windows 7 Enterprise installation. The client is not aware of any GPO policies being installed. There is AV from Trend Micro installed.

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• Python function correctly/incorrectly?

  - by Anthony Kernan

  I'm just starting too use python, learning experience. I know the basics logic of programming. I have a function in python that is running everytime, even when it's not supposed to. I use an if statement in the beginning of the function. I don't know why this if statement is not working, confused. I have another function that is similar and works correctly. Am I missing something simple? Here's the function that is not working... def check_artist_art(): if os.path.exists("/tmp/artistinfo") and open("/tmp/artistinfo").read() != title: #if artist == "": if os.path.exists(home + "/.artist"): os.remove(home + "/.artist") if os.path.exists("/tmp/artistinfo"): os.remove("/tmp/artistinfo") print artist return False else: os.path.exists("/tmp/artistinfo") and open("/tmp/artistinfo").read() == artist return False return True And this is the similar function that is working correctly.. def check_album(): if os.path.exists("/tmp/albuminfo") and open("/tmp/albuminfo").read() != album: if os.path.exists(home + "/.album"): os.remove(home + "/.album") if os.path.exists("/tmp/albuminfo"): os.remove("/tmp/albuminfo") return False elif os.path.exists("/tmp/trackinfo") and open("/tmp/trackinfo").read() == artist + album: return False return True Any help is greatly appreciated.

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