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  • Preserving indentation when inserting HTML from MySQL

    - by Benjamin
    I am using MySQL and PHP to populate parts of a site, often with HTML stored in a TEXT field. I like to keep my HTML indented so that the source is neat and easy to read, for example: <body> <div> <p>Blahblah</p> </div> </body> However, when the HTML is pulled from MySQL, I end up with: <body> <div> <p>Blahblahblah</p> </div> </body> This is quite ugly when there is a large amount of HTML being inserted into a DIV that is significantly indented. How can I stop this from happening? FYI, I use wordwrap() to keep each line from being too long.

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  • Combining Cocoa and MySQL

    - by BryCry
    Hey guys, i was searching SO for help on this, but i can't seem to find a concrete solution. Is, or isn't it possible to connect to a mysql database with Cocoa? Because i'm working on a program that i'd like to extend to a database, but i sure as hell don't know how! I mean, that cocoa-mysql package is heavily outdated, and i dont even know what a C wrapper is! Can someone please tell me how to do this, or atleast burst my bubble to tell me that it can't be done? Thanks!

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  • How to get number of rows deleted from mysql in schell script

    - by simonlord
    Hi all I can't work out how to get the mysql client to return the number of rows deleted to the shell when running a delete. Does anyone know what option will enable this? Or ways around it? Here's what i'm trying, but i get no output: #!/bin/bash deleted=`mysql mydb -e "delete from mytable where insertedtime < '2010-04-01 00:00:00'"|tail -n 1` I was expecting something like this as the output from mysql: deleted 999999 Which is why i have the tail -n 1 so i only pick up the count and not the column name. Any help would be most appreciated.

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  • Using indexes on/through a MySQL view

    - by Peeja
    We've got a MySQL table in which rows are never updated, but instead new rows are added and the old ones marked obsolete. Think Rails' acts_as_paranoid, but for every update. To make working with Rails sane, we've got a view which selects only the rows which are "current". That makes a much better "table" for our ActiveRecord model. The snag: our indexes aren't being used anymore. Queries on the view don't use the underlying tables' indexes. You can't add an index to a view. Without indexes, the app is unbearably slow. The only solution we've come up with is to build a materialized view, but that's a pain in MySQL because they're not natively supported. Is there a better way to do this?

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  • Heavy Mysql operation & Time Constraints [closed]

    - by Rahul Jha
    There is a performance issue where that I have stuck with my application which is based on PHP & MySql. The application is for Data Migration where data has to be uploaded and after various processes (Cleaning from foreign characters, duplicate check, id generation) it has to be inserted into one central table and then to 5 different tables. There, an id is generated and that id has to be updated to central table. There are different sets of records and validation rules. The problem I am facing is that when I insert say(4K) rows file (containing 20 columns) it is working fine within 15 min it gets inserted everywhere. But, when I insert the same records again then at this time it is taking one hour to insert (ideally it should get inserted by marking earlier inserted data as duplicate). After going through the log file, I noticed is that there is a Mysql select statement where I am checking the duplicates and getting ID which are duplicates. Then I am calling a function inside for loop which is basically inserting records into 5 tables and updates id to central table. This Calling function is major time of whole process. P.S. The records has to be inserted record by record.. Kindly Suggest some solution.. //This is that sample code $query=mysql_query("SELECT DISTINCT p1.ID FROM table1 p1, table2 p2, table3 a WHERE p2.datatype =0 AND (p1.datatype =1 || p1.datatype=2) AND p2.ID =0 AND p1.ID = a.ID AND p1.coulmn1 = p2.column1 AND p1.coulmn2 = p2.coulmn2 AND a.coulmn3 = p2.column3"); $num=mysql_num_rows($query); for($i=0;$i<$num;$i++) { $f=mysql_result($query,$i,"ID"); //calling function RecordInsert($f); }

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  • Integrating TFS and MySQL

    - by user294043
    We are developing an application with Visual Studio 2008 and TFS. Our database is a MySQL DB. As we develop we keep the new queries that need to be applied to the database of our new release as the New Version Update Queries. Right now I'm keeping them in a simple text file (which is a painful task!). I know that TFS integrates with MSSQL and makes this job very easy. I've already asked our consultant from Microsoft if there is any way to integrate TFS and MySQL, and his answer was "NO". So I was wondering if anyone knows any smart way of handling this issue?

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  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

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  • SubSonic isn't generating MySql foreign key tables

    - by keith
    I two tables within a MySql 5.1.34 database. When using SubSonic to generate the DAL, the foreign-key relationship doesn't get scripted, ie; I have no Parent.ChildCollection object. Looking inside the generated DAL Parent class shows the following; //no foreign key tables defined (0) I have tried SubSonic 2.1 and 2.2, and various MySql 5 versions. I must be doing something wrong procedurally - any help would be greatly appreciated. This has always just worked 'out-the-box' when using MS-SQL. TABLE `parent` ( `ParentId` INT(11) NOT NULL AUTO_INCREMENT, `SomeData` VARCHAR(25) DEFAULT NULL, PRIMARY KEY (`ParentId`) ) ENGINE=INNODB DEFAULT CHARSET=latin1; TABLE `child` ( `ChildId` INT(11) NOT NULL AUTO_INCREMENT, `ParentId` INT(11) NOT NULL, `SomeData` VARCHAR(25) DEFAULT NULL, PRIMARY KEY (`ChildId`), KEY `FK_child` (`ParentId`), CONSTRAINT `FK_child` FOREIGN KEY (`ParentId`) REFERENCES `parent` (`ParentId`) ) ENGINE=INNODB DEFAULT CHARSET=latin1;

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  • MySQL insert at end of table

    - by Theopile
    Hello, I am using MySQL and PHP. I am having a problem with inserting a new item at the end of my table. When I insert the new item appears after the last created item, but I want it to be entered at the bottom of the table. Suppose that I have a table id=int,Primary Key and album=string and the table is: Wrath Crack The Skye Enter Shikari What would the MySQL query be if php variable $album=myAlbum was to be inserted next, at the end of the table, and with the appropriate id? Thanks

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  • Splitting a MySQL DB in two may ease server from "Too many connetions"? I don't think so

    - by Petruza
    I was requested to split a MySQL in two, it's kind of a horizontal partition, in which some rows correspond to one site, and some other correspond to another site. But they want to split it in two DBs in the same MySQL server. I'm no DB expert but I guess keeping them in the same MySQL server with the same amount of memory and processor and the same platform won't improve things. What we're trying to avoid is the "Too many connections" problem.

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  • Using function arguments to dynamically generate a query

    - by Varun
    I am working on an issue management system, developed in PHP/MySQL. It requires search functionality, where the user will mention the search parameters and based on these parameters the system will return the result set. To solve this I am trying to write a function and all the user selected parameters are passed as arguments. Based on the arguments I will dynamically generate the query. Sample Query: select * from tickets inner join ticket_assigned_to on tickets.id=ticket_assigned_to.ticket_id where tickets.project_id= in ('') and tickets.status in ('') and ticket_assigned_to.user_id in ('') and tickets.reporter_user_id='' and tickets.operator_user_id in ('') and tickets.due_date between '' and '' and tickets.ts_created between '' and ''; I also need to handle cases where the arguments can be ORed or ANDed in the query. For example: select * from tickets inner join ticket_assigned_to on tickets.id=ticket_assigned_to.ticket_id where tickets.project_id= in ('') and tickets.status in ('') or tickets.due_date = '' or tickets.ts_created between '' and ''; I am also planning to use the same function at other places in the project also. Like to display all the tickets of a user or all tickets created between given dates and so on... How to handle this situation? Should I go with a single function which handles all this or numerous small functions? Need guidance here.

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  • how to query an embedded entity by using a query builder

    - by user577719
    I've searched quite a time for an answer to this question. Following Codesmell: @Entity public class Person { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) protected Integer id; @Column(nullable = true, length = 50) @Size(max = 50) private String name; @Embedded @Valid protected Adress adress; public void setId(Integer id) { this.id = id; } public Integer getId() { return this.id; } public void setName(String name) { this.name = name; } public void getName() { return this.name; } public void setAdress(Adress adress) { this.adress = adress; } public void getAdress() { return this.adress; } } @Embeddable public class Adress { @Column(nullable = false, length = 50) @Size(max = 50) @NotNull private String place; public void setPlace(String place) { this.place = place; } public void getPlace() { return this.place; } } public class PersonDaoJpa { public List<Ort> findByPerson(final Person person) { CriteriaBuilder builder = this.entityManager.getCriteriaBuilder(); CriteriaQuery<Person> query = builder.createQuery(Person.class); Root<Person> rootPerson = query.from(Person.class); List<Predicate> wherePredicates = new ArrayList<Predicate>(); if (person.getName() != null) { wherePredicates.add( builder.like(builder.lower(rootPerson.<String>get("name")), ort.getName().toLowerCase()) ); } Adresse adresse = ort.getAdresse(); if (adresse != null) { if(adresse.getPlace() != null) { // this won't work wherePredicates.add( builder.like(builder.lower(rootPerson.<String>get("person.adress.place")), adresse.getPlace().toLowerCase()) ); } } Predicate whereClause = builder.and(wherePredicates.toArray(new Predicate[0])); query.where(whereClause); return this.entityManager.createQuery(query).getResultList(); } } How can I access the Adress.place through rootPerson? rootPerson.get("place"), or rootPerson.get("adress.place") won't work...

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  • Unix timestamp and mysql date: birthdate

    - by Mikk
    Hi, I have a really basic question concerning unix timestamp and mysql date. I'm trying to build a small website where users can register and fill in their birthdate. Problem is that unix starts with Jan 01 1970. Now if i calculate age for users, form dates like date('m.d.Y', $unix_from_db) and so on it will fail with users older that 40 years, right? So what would be the rigth way for doing this. Sorry, for basic question like this, but I'm inexperienced with php and mysql.

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  • Why does php show error for my SQL query

    - by ZincX
    UPDATE: My mistake - I made a typo. Nevermind this question. I'm using php to update a mysql database. The resultant query I'm using when i print it out on my webpage before executing is as follows: INSERT INTO perch2_content_items (itemOrder, regionID, pageID, itemRev, itemID, itemJSON, itemSearch ) SELECT MAX(itemOrder)+1, 105, 81, 11, 118, 'json', 'search' FROM perch2_content_items WHERE regionID=105 When I copy and paste this query directly into the phpmyadmin SQL interface, it works fine. The table gets updated. However, when I try to execute it using my php code as follows, it throws an error. $insertToPerch = "INSERT INTO perch2_content_items (itemOrder, regionID, pageID, itemRev, itemID, itemJSON, itemSearch ) SELECT MAX(itemOrder)+1, $regionID, $pageID, $regionRev, $newItemID, 'json', 'search' FROM perch2_content_items WHERE regionID=$regionID"; mysql_query(insertToPerch) or die(mysql_error()); The error I'm getting is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'insertToPerch' at line 1 Can anybody help me figure out why it is failing.

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • Question about Radio button/PHP/MySQL

    - by Marcelo
    Hi, I'm an engineering student and I'm developing a simple software based on HTML, PHP and mysql. I learned this topics on w3schools. I know only the basics. I tried to search about this in this website but I found questions about PHP, MySQL and HTML radio buttons which were much more complex than I need and that I could understand. Sorry for the English. (Q1) Ex: $email=$_REQUEST['email'] , in this case the input is text, if it where like a radio button for ex: sex: male or female, how would it be? (Q2) what would be the type of this field (for exemple sex in question 1) in the database: text, int, varchar ? Thanks for the attention

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  • MySQL with Java: Open connection only if possible

    - by emempe
    I'm running a database-heavy Java application on a cluster, using Connector/J 5.1.14. Therefore, I have up to 150 concurrent tasks accessing the same MySQL database. I get the following error: Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLNonTransientConnectionException: Too many connections This happens because the server can't handle so many connections. I can't change anything on the database server. So my question is: Can I check if a connection is possible BEFORE I actually connect to the database? Something like this (pseudo code): check database for open connection slots if (slot is free) { Connection cn = DriverManager.getConnection(url, username, password); } else { wait ... } Cheers

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  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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