How does dereferencing of a function pointer happen?
- by eSKay
Why and how does dereferencing a function pointer just "do nothing"?
This is what I am talking about:
#include<stdio.h>
void hello() { printf("hello"); }
int main(void) {
(*****hello)();
}
From a comment over here:
function pointers dereference just
fine, but the resulting function
designator will be immediately
converted back to a function pointer
And from an answer here:
Dereferencing (in way you think) a
function's pointer means: accessing a
CODE memory as it would be a DATA
memory.
Function pointer isn't suppose to be
dereferenced in that way. Instead, it
is called.
I would use a name "dereference" side
by side with "call". It's OK.
Anyway: C is designed in such a way
that both function name identifier as
well as variable holding function's
pointer mean the same: address to CODE
memory. And it allows to jump to that
memory by using call () syntax either
on an identifier or variable.
How exactly does dereferencing of a function pointer work?
