Search Results

Search found 9244 results on 370 pages for 'django crispy forms'.

Page 15/370 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

  • Django FormWizard with dynamic forms

    - by krys
    I want to implement a simple 2 part FormWizard. Form 1 will by dynamically generated something like this: class BuyAppleForm(forms.Form): creditcard = forms.ChoiceField(widget = forms.RadioSelect) type = forms.ChoiceField(widget = forms.RadioSelect) def __init__(self,*args, **kwargs): user = kwargs['user'] del kwargs['user'] super(BuyAppleForm, self).__init__(*args, **kwargs) credit_cards = get_credit_cards(user) self.fields['creditcard'].choices = [(card.id,str(card)) for card in credit_cards] apple_types= get_types_packages() self.fields['type'].choices = [(type.id,str(type)) for type in apple_types] This will dynamically create a form with lists of available choices. My second form, I actually want no input. I just want to display a confirmation screen containing the credit card info, apple info, and money amounts (total, tax, shipping). Once user clicks OK, I want the apple purchase to commence. I was able to implement the single form way by passing in the request.user object in the kwargs. However, with the FormWizard, I cannot figure this out. Am I approaching the problem wrong and is the FormWizard not the proper way to do this? If it is, how can the Form __init__ method access the user object from the HTTP request?

    Read the article

  • Google App Engine + Form Validation

    - by Iwona
    Hi, I would like to do google app engine form validation but I dont know how to do it? I tried like this: from google.appengine.ext.db import djangoforms from django import newforms as forms class SurveyForm(forms.Form): occupations_choices = ( ('1', ""), ('2', "Undergraduate student"), ('3', "Postgraduate student (MSc)"), ('4', "Postgraduate student (PhD)"), ('5', "Lab assistant"), ('6', "Technician"), ('7', "Lecturer"), ('8', "Other" ) ) howreach_choices = ( ('1', ""), ('2', "Typed the URL directly"), ('3', "Site is bookmarked"), ('4', "A search engine"), ('5', "A link from another site"), ('6', "From a book"), ('7', "Other") ) boxes_choices = ( ("des", "Website Design"), ("svr", "Web Server Administration"), ("com", "Electronic Commerce"), ("mkt", "Web Marketing/Advertising"), ("edu", "Web-Related Education") ) name = forms.CharField(label='Name', max_length=100, required=True) email = forms.EmailField(label='Your Email Address:') occupations = forms.ChoiceField(choices=occupations_choices, label='What is your occupation?') howreach = forms.ChoiceField(choices=howreach_choices, label='How did you reach this site?') # radio buttons 1-5 rating = forms.ChoiceField(choices=range(1,6), label='What is your occupation?', widget=forms.RadioSelect) boxes = forms.ChoiceField(choices=boxes_choices, label='Are you involved in any of the following? (check all that apply):', widget=forms.CheckboxInput) comment = forms.CharField(widget=forms.Textarea, required=False) And I wanted to display it like this: template_values = { 'url' : url, 'url_linktext' : url_linktext, 'userName' : userName, 'item1' : SurveyForm() } And I have this error message: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp_init_.py", line 515, in call handler.get(*groups) File "C:\Program Files\Google\google_appengine\demos\b00213576\main.py", line 144, in get self.response.out.write(template.render(path, template_values)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 143, in render return t.render(Context(template_dict)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 183, in wrap_render return orig_render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 168, in render return self.nodelist.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template\defaulttags.py", line 209, in render return self.nodelist_true.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 768, in render return self.encode_output(output) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 757, in encode_output return str(output) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 73, in unicode return self.as_table() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 144, in as_table return self._html_output(u'%(label)s%(errors)s%(field)s%(help_text)s', u'%s', '', u'%s', False) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 129, in _html_output output.append(normal_row % {'errors': bf_errors, 'label': label, 'field': unicode(bf), 'help_text': help_text}) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 232, in unicode value = value.str() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 246, in unicode return u'\n%s\n' % u'\n'.join([u'%s' % w for w in self]) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 238, in iter yield RadioInput(self.name, self.value, self.attrs.copy(), choice, i) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 212, in init self.choice_value = smart_unicode(choice[0]) TypeError: 'int' object is unsubscriptable Do You have any idea how I can do this validation in different case? I have tried to do it using this kind of: class ItemUserAnswer(djangoforms.ModelForm): class Meta: model = UserAnswer But I dont know how to add extra labels to this form and it is displayed in one line. Do You have any suggestions? Thanks a lot as it making me crazy why it is still not working:/

    Read the article

  • How insert 2 different forms on the same page in Django

    - by xRobot
    I have to insert 2 forms in the same page: 1) Registration form 2) Login form . So if I use this in the views.py: if request.method == 'POST': form = registrationForm(request.POST) if form.is_valid(): form.save() return render_to_response('template.html', { 'form': form, }) I will get error by submitting one of two forms. How can I distinguish the 2 forms submitting in the views ?

    Read the article

  • Specifying default value for django hidden form field - bone DRY?

    - by jMyles
    So let's say at the last minute (in the view) I decide I want to specify a default for a field and make it hidden, like so: form.fields['coconut'] = forms.ModelChoiceField(label="", widget=forms.HiddenInput(), queryset=swallow.coconuts.all(), initial=some_particular_coconut) My question is this: Do I really need to specify queryset here? I mean, I already know, from initial, exactly which coconut I'm talking about. Why do I also need to specify that the universe of available coconuts is the set of coconuts which this particular swallow carried (by the husk)? Is there a way I can refrain from specifying queryset? Simply omitting causes django to raise TypeError. If indeed it is required, isn't this a bit damp?

    Read the article

  • Django, ModelForms, User and UserProfile - not hashing password

    - by IvanBernat
    I'm trying to setup a User - UserProfile relationship, display the form and save the data. When submitted, the data is saved, except the password field doesn't get hashed. Additionally, how can I remove the help_text from the username and password (inherited from the User model)? Full code is below, excuse me if it's too long. Models.py USER_IS_CHOICES = ( ('u', 'Choice A'), ('p', 'Choice B'), ('n', 'Ninja'), ) class UserProfile(models.Model): user = models.ForeignKey(User, unique=True) user_is = models.CharField(max_length=1, choices=USER_IS_CHOICES) Forms.py class UserForm(forms.ModelForm): class Meta: model = User fields = ["first_name", "last_name", "username", "email", "password"] def clean_username(self): username = self.cleaned_data['username'] if not re.search(r'^\w+$', username): raise forms.ValidationError('Username can contain only alphanumeric characters') try: User.objects.get(username=username) except ObjectDoesNotExist: return username raise forms.ValidationError('Username is already taken') class UserProfileForm(forms.ModelForm): class Meta: model = UserProfile fields = ['user_is'] Views.py if request.method == 'POST': uform = UserForm(request.POST) pform = UserProfileForm(request.POST) if uform.is_valid() and pform.is_valid(): user = uform.save() profile = pform.save(commit = False) profile.user = user profile.save() return HttpResponseRedirect('/') else: uform = UserForm() pform = UserProfileForm() variables = RequestContext(request, { 'uform':uform, 'pform':pform }) return render_to_response('registration/register.html', variables)

    Read the article

  • Setting a Forms Authentication cookie from a .NET client application

    - by Jon DellOro
    We currently have a .NET 2.0 web app that uses forms authentication via cookies. Associated with this web app is an old VB6 client application that has its own login system. Currently, the users have to login to the VB6 app, and then when they click on a link, need to authenticate themselves again with the .NET forms authentication system. I'm wondering if it's possible to create a client side .NET application, give it the username and password, and set the forms authentication cookie (without the browser being opened). Is that possible??

    Read the article

  • How to make form validation in Django dynamic?

    - by Oli
    I'm trying to make a form that handles the checking of a domain: the form should fail based on a variable that was set earlier in another form. Basically, when a user wants to create a new domain, this form should fail if the entered domain exists. When a user wants to move a domain, this form should fail if the entered domain doesn't exist. I've tried making it dynamic overload the initbut couldn't see a way to get my passed variabele to the clean function. I've read that this dynamic validation can be accomplished using a factory method, but maybe someone can help me on my way with this? Here's a simplified version of the form so far: #OrderFormStep1 presents the user with a choice: create or move domain class OrderFormStep2(forms.Form): domain = forms.CharField() extension = forms.CharField() def clean(self): cleaned_data = self.cleaned_data domain = cleaned_data.get("domain") extension = cleaned_data.get("extension") if domain and extension: code = whoislookup(domain+extension); #Raise error based on result from OrderFormStep1 #raise forms.ValidationError('error, domain already exists') #raise forms.ValidationError('error, domain does not exist') return cleaned_data

    Read the article

  • Recordings Available - Features & Functions Forms Module

    - by MHundal
    ETPM provides robust Forms functionality that allows implementations to configure Registration & Tax Forms, configure Form Rules and process the Forms.  The Forms Definition allows for defining the Form Sections and Form Lines.  The Forms Generator uses the Forms Definition details to create the necessary Business Objects, Application Security and User Interfaces to allow interaction with the Forms.  Form Rules are used for validation of the Form Line details and creating entities in the system (creating taxpayers, accounts, financial transactions, etc...). The following recordings provide an overview of the Forms Definition Process, Form Rules and other important concepts part of the Forms Module. Forms Module Overview:  https://oracletalk.webex.com/oracletalk/ldr.php?AT=pb&SP=MC&rID=66851417&rKey=7de22df4978e7974 Forms Configuration Overview:  https://oracletalk.webex.com/oracletalk/ldr.php?AT=pb&SP=MC&rID=66964342&rKey=ea564cfd701bb32d Form Rules Overview:  https://oracletalk.webex.com/oracletalk/ldr.php?AT=pb&SP=MC&rID=66966652&rKey=2e02c1e28e058d70  

    Read the article

  • How to do custom display and auto-select in django admin multi-select field?

    - by rsp
    I'm new to django, so please feel free to tell me if I'm doing this incorrectly. I am trying to create a django ordering system. My order model: class Order(models.Model): ordered_by = models.ForeignKey(User, limit_choices_to = {'groups__name': "Managers", 'is_active': 1}) in my admin ANY user can enter an order, but ordered_by must be someone in the group "managers" (this is the behavior I want). Now, if the logged in user happens to be a manager I want it to automatically fill in the field with that logged in user. I have accomplished this by: class OrderAdmin(admin.ModelAdmin): def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == "ordered_by": if request.user in User.objects.filter(groups__name='Managers', is_active=1): kwargs["initial"] = request.user.id kwargs["empty_label"] = "-------------" return db_field.formfield(**kwargs) return super(OrderAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) This also works, but the admin puts the username as the display for the select box by default. It would be nice to have the user's real name listed. I was able to do it with this: class UserModelMultipleChoiceField(forms.ModelMultipleChoiceField): def label_from_instance(self, obj): return obj.first_name + " " + obj.last_name class OrderForm(forms.ModelForm): ordered_by = UserModelChoiceField(queryset=User.objects.all().filter(groups__name='Managers', is_active=1)) class OrderAdmin(admin.ModelAdmin): form = OrderForm My problem: I can't to both of these. If I put in the formfield_for_foreignkey function and add form = OrderForm to use my custom "UserModelChoiceField", it puts the nice name display but it won't select the currently logged in user. I'm new to this, but my guess is that when I use UserModelChoiceField it "erases" the info passed in via formfield_for_foreignkey. Do I need to use the super() function somehow to pass on this info? or something completely different?

    Read the article

  • Dynamic Forms: Pattern or AntiPattern?

    - by Segfault
    I'm sure you've seen it. The database has a bunch of tables called Forms, Controls,FormsControls, ControlSets, Actions and the program that queries these tables has a dynamically generated user interface. It will read all the forms, load a home page that has links to them all, or embed them in some tabbed or paged home page, and for each of those forms it will read the various text boxes, check boxes, radio buttons, submit buttons, combo boxes, labels and whatnot from the controls and form-to-control join tables, lay those elements out according to the database and link all the controls to logic according to other rules in the database. To me, this is an anti-pattern. It actually make the application more difficult to maintain because the design of it is now spread out into multiple different systems. Also, the database is not source controlled. Sure, it may make one or two changes go more quickly, after you've analyzed the program anyway to understand how to change the data and as long as you don't stray from the sort of changes that were anticipated and accounted for, but that's often just not sustainable. What say you?

    Read the article

  • Django simple syndication example gives: ImportError, cannot import name Feed

    - by AP257
    I'm trying to set up the simple syndication example from the Django docs, in a working project. But I'm getting an ImportError, even though I'm sure I've copied the example exactly. Here's what I have in feeds.py: from django.contrib.syndication.views import Feed class LatestEntriesFeed(Feed): # etc And here's what I have in urls.py: from election.feeds import LatestEntriesFeed #... further down, at the appropriate line... # RSS feed (r'^feed/$', LatestEntriesFeed()), But Django says it can't import the Feed class from django.contrib.syndication.views: ImportError at /feed/ cannot import name Feed ....feeds.py in <module> from django.contrib.syndication.views import Feed Any ideas? I'm baffled!

    Read the article

  • url template tag in django template

    - by user192048
    guys: I was trying to use the url template tag in django, but no lucky, I defined my urls.py like this urlpatterns = patterns('', url(r'^analyse/$', views.home, name="home"), url(r'^analyse/index.html', views.index, name="index"), url(r'^analyse/setup.html', views.setup, name="setup"), url(r'^analyse/show.html', views.show, name="show"), url(r'^analyse/generate.html', views.generate, name="generate"), I defined the url pattern in my view like this {% url 'show'%} then I got this error message Caught an exception while rendering: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. Original Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/template/debug.py", line 71, in render_node result = node.render(context) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 155, in render nodelist.append(node.render(context)) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 382, in render raise e NoReverseMatch: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. I am wondering why django failed to render? what is the right way to define it in the tempalte?

    Read the article

  • Django syncdb not making tables for my app

    - by Rosarch
    It used to work, and now it doesn't. python manage.py syncdb no longer makes tables for my app. From settings.py: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'mysite.myapp', 'django.contrib.admin', ) What could I be doing wrong? The break appeared to coincide with editing this model in models.py, but that could be total coincidence. I commented out the lines I changed, and it still doesn't work. class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(Course, through=TakingCourse, blank=True) school = models.ForeignKey(School) # minCreditsPerTerm = models.IntegerField(blank=True) # maxCreditsPerTerm = models.IntegerField(blank=True) # optimalCreditsPerTerm = models.IntegerField(blank=True) UPDATE: When I run python manage.py loadddata initial_data, it gives an error: DeserializationError: Invalid model identifier: myapp.SomeModel Loading this data had worked fine before. This error is thrown on the very first data object in the data file.

    Read the article

  • Adding links to full change forms for inline items in django admin?

    - by David Eyk
    I have a standard admin change form for an object, with the usual StackedInline forms for a ForeignKey relationship. I would like to be able to link each inline item to its corresponding full-sized change form, as the inline item has inlined items of its own, and I can't nest them. I've tried everything from custom widgets to custom templates, and can't make anything work. So far, the "solutions" I've seen in the form of snippets just plain don't seem to work for inlines. I'm getting ready to try some DOM hacking with jQuery just to get it working and move on. I hope I must be missing something very simple, as this seems like such a simple task! Using Django 1.2.

    Read the article

  • Django ORM and PostgreSQL connection limits

    - by bennylope
    I'm running a Django project on Postgresql 8.1.21 (using Django 1.1.1, Python2.5, psycopg2, Apache2 with mod_wsgi 3.2). We've recently encountered this lovely error: OperationalError: FATAL: connection limit exceeded for non-superusers I'm not the first person to run up against this. There's a lot of discussion about this error, specifically with psycopg, but much of it centers on older versions of Django and/or offer solutions involving edits to code in Django itself. I've yet to find a succinct explanation of how to solve the problem of the Django ORM (or psycopg, whichever is really responsible, in this case) leaving open Postgre connections. Will simply adding connection.close() at the end of every view solve this problem? Better yet, has anyone conclusively solved this problem and kicked this error's ass?

    Read the article

  • View centric design with Django

    - by wishi_
    Hi! I'm relatively new to Django and I'm designing a website that primarily needs usability experience, speaking of optimized CSS, HTML5 and UI stuff. It's very easy to use Django for data/Model centric design. Just designing a couple of Python classes and ./manage.py syncdb - there's your Model. But I'm dealing with a significant amount of View centric challenges. (Different user classes, different tasks, different design challenges.) The official Django tutorial cursorily goes through using a "Template". Is there any Design centric guide for Django, or a set of Templates that are ready and useable? I don't want to start from scratch using JS, HTML5, Ajax and everything. From the Model layer perspective Django is very rapid and delivering a working base system. I wonder whether there's something like that for the Views.

    Read the article

  • django newbie question : cant start a new project

    - by Moayyad Yaghi
    hello . I'm totally new to django . and I'm using its documentation to get help on how to use it but seems like something is missing. i installed django using setup.py install command and i added the ( django/bin ) to system path variable but. i still cant start a new project i use the following syntax to start a project : django-admin.py startproject myNewProject but it says Type 'django-admin.py help' for usage. 1 do i miss anything ? thank u

    Read the article

  • Modify Django Forms

    - by Ninefingers
    Hi All, I've recently been developing on the django platform and have stumbled upon Django Forms (forms.Form/forms.ModelForm) as ways of creating <form> html. Now, this is brilliant for quick stuff but what I'm trying to do is a little bit more complicated. Consider a DateField - my current form has fields for day, month and year and constructs a python date object from that. However, a django form creates a single textbox in which the correct format (say 2010-06-15) must be entered. As another example, for large fields I need to replace <input> with <textarea>. I'd like to take advantage of Django's forms for simple validation but I need something simpler for my users. So my question is: can I intercept the rendering of one of these objects to write out the html as I like? If so, do I have to do all the writing myself or can I only do those objects I wish to re-write? Thanks in advance.

    Read the article

  • Cannot get MEDIA_URL from Django widget's template

    - by Eric
    Hi folks, I am a new Djangoer, and figuring out how to build custom widget, my problem is cannot get the MEDIA_URL in my widget's template, while the form use MySelectWidget able to get the MEDIA_URL itself. # #plus_sign.html # <a href="" class="" id="id_{{ field }}"> <img src="{{ MEDIA_URL }}images/plus_sign.gif" width="10" height="10" alt="Add"/> </a> *^ cannot load the {{ MEDIA_URL}} to this widget's template, and therefore I can't load the .gif image properly. :(* # #custom_widgets.py # from django import forms class MySelectMultiple(forms.SelectMultiple): def render(self, name, *args, **kwargs): html = super(MySelectMultiple, self).render(name, *args, **kwargs) plus = render_to_string("plus_sign.html", {'field': name}) return html+plus # #forms.py # from django import forms from myapp.custom_widgets.py import MySelectMultiple class MyForm(forms.ModelForm): contacts = forms.ModelMultipleChoiceField(Contact.objects, required=False, widget=MySelectMultiple) # #views.py # def AddContacts(request): if request.method == 'POST': form = MyForm(request.POST) if form.is_valid(): cd = form.cleaned_data new = form.save() return HttpResponseRedirect('/addedContact/') else: form = MyForm() return render_to_response('shop/my_form.html', {'form': form}, context_instance=RequestContext(request)) # #my_form.html # {% extends "base.html" %} {% block content %} {{ form.contacts }} {% endblock %} Please let me know how can I load the widget's image properly. Thank you so much for all responses.

    Read the article

  • In Django Combobox choices, how do you lookup description from short value?

    - by MikeN
    In Django models/forms the choices for a combobox often look like this: food_choices = (("",""), ("1", "Falafel"), ("2", "Hummus"), ("3", "Eggplant Stuff, Babaganoush???"), So the value to be stored in the database will be 1/2/3, but the displayed value on the form will be the long description. When we are working in code outside a form, how can we quickly lookup the long description given the short value stored in the model? So I want to map short values to long values: print foo("1") "Falafel"

    Read the article

  • Detect the language & django locale-url

    - by mamcx
    I want to deploy a website in english & spanish and detect the user browser languaje & redirect to the correct locale site. My site is www.elmalabarista.com I install django-localeurl, but I discover that the languaje is not correctly detected. This are my middlewares: MIDDLEWARE_CLASSES = ( 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.locale.LocaleMiddleware', 'multilingual.middleware.DefaultLanguageMiddleware', 'middleware.feedburner.FeedburnerMiddleware', 'lib.threadlocals.ThreadLocalsMiddleware', 'middleware.url.UrlMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'maintenancemode.middleware.MaintenanceModeMiddleware', 'middleware.redirect.RedirectMiddleware', 'openidconsumer.middleware.OpenIDMiddleware', 'django.middleware.doc.XViewMiddleware', 'middleware.ajax_errors.AjaxMiddleware', 'pingback.middleware.PingbackMiddleware', 'localeurl.middleware.LocaleURLMiddleware', 'multilingual.flatpages.middleware.FlatpageFallbackMiddleware', 'django.middleware.common.CommonMiddleware', ) But ALWAYS the site get to US despite the fact my OS & Browser setup is spanish. LANGUAGES = ( ('en', ugettext('English')), ('es', ugettext('Spanish')), ) DEFAULT_LANGUAGE = 1 Then, I hack the middleware of locale-url and do this: def process_request(self, request): locale, path = self.split_locale_from_request(request) if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path if not locale: locale = settings.LANGUAGE_CODE translation.activate(locale) request.LANGUAGE_CODE = translation.get_language() However, this detect fine the language but redirect the "en" urls to "es". So is impossible navigate in english. UPDATE: This is the final code (after the input from Carl Meyer) with a fix for the case of "/": def process_request(self, request): locale, path = self.split_locale_from_request(request) if (not locale) or (locale==''): if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) else: locale = settings.LANGUAGE_CODE locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path translation.activate(locale) request.LANGUAGE_CODE = translation.get_language()

    Read the article

  • UnicodeDecodeError on attempt to save file through django default filebased backend

    - by Ivan Kuznetsov
    When i attempt to add a file with russian symbols in name to the model instance through default instance.file_field.save method, i get an UnicodeDecodeError (ascii decoding error, not in range (128) from the storage backend (stacktrace ended on os.exist). If i write this file through default python file open/write all goes right. All filenames in utf-8. I get this error only on testing Gentoo, on my Ubuntu workstation all works fine. class Article(models.Model): file = models.FileField(null=True, blank=True, max_length = 300, upload_to='articles_files/%Y/%m/%d/') Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/auth/decorators.py" in _wrapped_view 24. return view_func(request, *args, **kwargs) File "/var/www/localhost/help/wiki/views.py" in edit_article 338. new_article.file.save(fp, fi, save=True) File "/usr/lib/python2.6/site-packages/django/db/models/fields/files.py" in save 92. self.name = self.storage.save(name, content) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in save 47. name = self.get_available_name(name) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in get_available_name 73. while self.exists(name): File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in exists 196. return os.path.exists(self.path(name)) File "/usr/lib/python2.6/genericpath.py" in exists 18. st = os.stat(path) Exception Type: UnicodeEncodeError at /edit/ Exception Value: ('ascii', u'/var/www/localhost/help/i/articles_files/2010/03/17/\u041f\u0440\u0438\u0432\u0435\u0442', 52, 58, 'ordinal not in range(128)')

    Read the article

  • Audiencing with Forms-Based Authentication (FBA)

    - by PeterBrunone
    This really is no different from when you create an audience with regular old NTLM (Windows Authentication).  The difference is that while the AD provider is set up by default in all environments, the extra membership provider (that you use for Forms Authentication) isn't included anywhere except in the web application where you install it.  To be able to find your FBA users in the audience creation tool, you'll need to add the extra membership provider(s) to the web.config for your SSP site in IIS.  At that point, the People Picker should start recognizing your Forms Auth users, and you can create your audience as needed.

    Read the article

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >