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  • Sending http headers with python

    - by Niklas R
    I've set up a little script that should feed a client with html. import socket sock = socket.socket() sock.bind(('', 8080)) sock.listen(5) client, adress = sock.accept() print "Incoming:", adress print client.recv(1024) print client.send("Content-Type: text/html\n\n") client.send('<html><body></body></html>') print "Answering ..." print "Finished." import os os.system("pause") But it is shown as plain text in the browser. Can you please tell what I need to do ? I just can't find something in google that helps me.. Thanks.

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  • python sending incomplete data over socket

    - by tipu
    I have this socket server script, import SocketServer import shelve import zlib class MyTCPHandler(SocketServer.BaseRequestHandler): def handle(self): self.words = shelve.open('/home/tipu/Dropbox/dev/workspace/search/words.db', 'r'); self.tweets = shelve.open('/home/tipu/Dropbox/dev/workspace/search/tweets.db', 'r'); param = self.request.recv(1024).strip() try: result = str(self.words[param]) except KeyError: result = "set()" self.request.send(str(result)) if __name__ == "__main__": HOST, PORT = "localhost", 50007 SocketServer.TCPServer.allow_reuse_address = True server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler) server.serve_forever() And this receiver, from django.http import HttpResponse from django.template import Context, loader import shelve import zlib import socket def index(req, param = ''): HOST = 'localhost' PORT = 50007 s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((HOST, PORT)) s.send(param) data = zlib.decompress(s.recv(131072)) s.close() print 'Received', repr(data) t = loader.get_template('index.html') c = Context({ 'foo' : data }) return HttpResponse(t.render(c)) I am sending strings to the receiver that are in the hundreds of kilobytes. I end up only receiving a portion of it. Is there a way that I can fix that so that the whole string is sent?

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  • Redirect print in Python: val = print(arg) to output mixed iterable to file

    - by emcee
    So lets say I have an incredibly nested iterable of lists/dictionaries. I would like to print them to a file as easily as possible. Why can't I just redirect print to a file? val = print(arg) gets a SyntaxError. Is there a way to access stdinput? And why does print take forever with massive strings? Bad programming on my side for outputting massive strings, but quick debugging--and isn't that leveraging the strength of an interactive prompt? There's probably also an easier way than my gripe. Has the hive-mind an answer?

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  • Python evaluation order

    - by d.m
    Here's the code, I don't quite understand, how does it work. Could anyone tell, is that an expected behavior? $ipython In [1]: 1 in [1] == True Out[1]: False In [2]: (1 in [1]) == True Out[2]: True In [3]: 1 in ([1] == True) --------------------------------------------------------------------------- TypeError Traceback (most recent call last) /home/dmedvinsky/projects/condo/condo/<ipython console> in <module>() TypeError: argument of type 'bool' is not iterable In [4]: from sys import version_info In [5]: version_info Out[5]: (2, 6, 4, 'final', 0)

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  • Logical python question - handeling directories and files in them

    - by Konstantin
    Hello! I'm using this function to extract files from .zip archive and store it on the server: def unzip_file_into_dir(file, dir): import sys, zipfile, os, os.path os.makedirs(dir, 0777) zfobj = zipfile.ZipFile(file) for name in zfobj.namelist(): if name.endswith('/'): os.mkdir(os.path.join(dir, name)) else: outfile = open(os.path.join(dir, name), 'wb') outfile.write(zfobj.read(name)) outfile.close() And the usage: unzip_file_into_dir('/var/zips/somearchive.zip', '/var/www/extracted_zip') somearchive.zip have this structure: somearchive.zip 1.jpeg 2.jpeg another.jpeg or, somethimes, this one: somearchive.zip somedir/ 1.jpeg 2.jpeg another.jpeg Question is: how do I modify my function, so that my extracted_zip catalog would always contain just images, not images in another subdirectory, even if images are stored in somedir inside an archive.

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  • python fdb save huge data from database to file

    - by peter
    I have this script SELECT = """ select coalesce (p.ID,'') as id, coalesce (p.name,'') as name, from TABLE as p """ self.cur.execute(SELECT) for row in self.cur.itermap(): xml +=" <item>\n" xml +=" <id>" + id + "</id>\n" xml +=" <name>" + name + "</name>\n" xml +=" </item>\n\n" #save xml to file here f = open... and I need to save data from huge database to file. There are 10 000s (up to 40000) of items in my database and it takes very long time when script runs (1 hour and more) until finish. How can I take data I need from database and save it to file "at once"? (as quick as possible? I don't need xml output because I can process data from output on my server later. I just need to do it as quickly as possible. Any idea?) Many thanks!

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  • Get Path of Uploaded File using Python

    - by Ali
    Is it possible to get the full path of the file on the user's computer being uploaded to my site? Using os.path.abspath(fileitem.filename) simply gets me the address of where my script is executing from on my shared hosting server. FYI: fileitem = form['file'] and form = cgi.FieldStorage()

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  • How to concat a string in Python

    - by alex
    query = "SELECT * FROM mytable WHERE time=%s", (mytime) Then, I want to add a limit %s to it. How can I do that without messing up the %s in mytime? Edit: I want to concat query2, which has "LIMIT %s, %s"

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  • A list vs. tuple situation in Python

    - by Alphonse
    Is there a situation where the use of a list leads to an error, and you must use a tuple instead? I know something about the properties of both tuples and lists, but not enough to find out the answer to this question. If the question would be the other way around, it would be that lists can be adjusted but tuples don't.

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  • Python and urllib2: how to make a GET request with parameters

    - by Infinity
    I'm building an "API API", it basically a wrapper for a in house REST web service that the web app will be making a lot of requests to. Some of the web service calls need to be GET rather than post, but passing parameters. Is there a "best practice" way to encode a dictionary into a query string? e.g.: ?foo=bar&bla=blah I'm looking at the urllib2 docs, and it looks like it decides by itself wether to use POST or GET based on if you pass params or not, but maybe someone knows how to make it transform the params dictionary into a GET request. Maybe there's a package for something like this out there? It would be great if it supported keep-alive, as the web server will be constantly requesting things from the REST service. Thanks!

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  • python conditional list creation from 2D lists

    - by dls
    Say I've got a list of lists. Say the inner list of three elements in size and looks like this: ['apple', 'fruit', 1.23] The outer list looks like this data = [['apple', 'fruit', 1.23], ['pear', 'fruit', 2.34], ['lettuce', 'vegetable', 3.45]] I want to iterate through the outer list and cull data for a temporary list only in the case that element 1 matches some keyword (aka: 'fruit'). So, if I'm matching fruit, I would end up with this: tempList = [('apple', 1.23), ('pear', 2.34)] This is one way to accomplish this: tempList = [] for i in data: if i[1] == 'fruit': tempList.append(i[0], i[2]) is there some 'Pythonic' way to do this in fewer lines?

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  • Python: Repeat elements in a list comprehension?

    - by User
    I have the following list comprehension which returns a list of coordinate objects for each location. coordinate_list = [Coordinates(location.latitude, location.longitude) for location in locations] This works. Now suppose the location object has a number_of_times member. I want a list comprehension to generate n Coordinate objects where n is the number_of_times for the particular location. So if a location has number_of_times = 5 then the coordinates for that location will be repeated 5 times in the list. (Maybe this is a case for a for-loop but I'm curious if it can be done via list comprehensions)

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  • Working with OAuth on Google with Python

    - by Dan Loewenherz
    I'm having a very frustrating time creating a valid signature for Google's OAuth implementation. I have narrowed it all down to the fact that my signature-generation code has an error of some sort; what it is I have no idea. This is the signature base string in its entirety: GET&https%3A%2F%2Fwww.google.com%2Faccounts%2FOAuthGetAccessToken&oauth_consumer_key%3Ddlosplayground.appspot.com%26oauth_nonce%3D72815d55697cb24301fab03e1f7f1d66%26oauth_signature_method%3DHMAC-SHA1%26oauth_timestamp%3D1274327867%26oauth_token%3D4%252FX2cZ54JuseQbgRwzTBzZ7lqIwqof%26oauth_verifier%3Dihf0F2Fx%252FpnCmwbVQnk2xMre%26oauth_version%3D1.0 The OAuth Playground returns an oauth_signature of gF8qAfWjpdKjKb4KR%2FvA2Gy0vhU%3D. My code gives me ikMpIKJQJ58jseg%2BKPBTecjmYPE%3D, so obviously I'm doing something wrong. Here's my signature generation code (equivalent to that of the standard oauth.py library): binascii.b2a_base64(hmac.new(CONSUMER_SECRET, BASE_STRING, hashlib.sha1).digest())[:-1] Any thoughts?

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  • Python datetime to Unix timestamp

    - by Off Rhoden
    I have to create an "Expires" value 5 minutes in the future, but I have to supply it in UNIX Timestamp format. I have this so far, but it seems like a hack. def expires(): '''return a UNIX style timestamp representing 5 minutes from now''' epoch = datetime.datetime(1970, 1, 1) seconds_in_a_day = 60 * 60 * 24 five_minutes = datetime.timedelta(seconds=5*60) five_minutes_from_now = datetime.datetime.now() + five_minutes since_epoch = five_minutes_from_now - epoch return since_epoch.days * seconds_in_a_day + since_epoch.seconds Is there a module or function that does the timestamp conversion for me?

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  • Best practice for string substition with gettext using Python

    - by Malcolm
    Looking for best practice advice on what string substitution technique to use when using gettext(). Or do all techniques apply equally? I can think of at least 3 string techniques: Classic "%" based formatting: "My name is %(name)s" % locals() .format() based formatting: "My name is {name}".format( locals() ) string.Template.safe_substitute() import string template = string.Template( "My name is ${name}" ) template.safe_substitute( locals() ) The advantage of the string.Template technique is that a translated string with with an incorrectly spelled variable reference can still yield a usable string value while the other techniques unconditionally raise an exception. The downside of the string.Template technique appears to be the inability for one to customize how a variable is formatted (padding, justification, width, etc).

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  • python popen and mysql import

    - by khelll
    I'm doing the following: from subprocess import PIPE from subprocess import Popen file = 'dump.sql.gz' p1 = Popen(["gzip", "-cd" ,file], stdout=PIPE) print "Importing temporary file %s" % file p2 = Popen(["mysql","--default-character-set=utf8", "--user=root" , "--password=something", "--host=localhost", "--port=3306" , 'my_db'],stdin=p1.stdout, stdout=PIPE,stderr=PIPE) err = p1.communicate()[1] if err: print err err = p2.communicate()[1] if err: print err But the db is not being populated. No errors are shown, also I have checked p1.stdout and it has the file contents. Any ideas?

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  • Efficient way in Python to add an element to a comma-separated string

    - by ensnare
    I'm looking for the most efficient way to add an element to a comma-separated string while maintaining alphabetical order for the words: For example: string = 'Apples, Bananas, Grapes, Oranges' addition = 'Cherries' result = 'Apples, Bananas, Cherries, Grapes, Oranges' Also, a way to do this but while maintaining IDs: string = '1:Apples, 4:Bananas, 6:Grapes, 23:Oranges' addition = '62:Cherries' result = '1:Apples, 4:Bananas, 62:Cherries, 6:Grapes, 23:Oranges' Sample code is greatly appreciated. Thank you so much.

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  • python json_encode throws KeyError exception

    - by MattM
    In a unit test case that I am running, I get a KeyError exception on the 4th json object in the json text below. I went through the sub-objects and found that it was the "cpuid" object that is the offending object, but I am completely at a loss as to what is wrong with the formatting. response = self.app.post( '/machinestats', params=dict(record=self.json_encode([ {"type": "crash", "instance_id": "xxx", "version": "0.2.0", "build_id": "unknown", "crash_text": "Gah!"}, {"type": "machine_info", "machine_info": "I'm awesome.", "version": "0.2.0", "build_id": "unknown", "instance_id": "yyy"}, {"machine_info": "Soup", "crash_text": "boom!", "version": "0.2.0", "build_id": "unknown", "instance_id": "zzz", "type": "crash"}, {"build_id" : "unknown", "cpu_brand" : "intel", "cpu_count" : 4, "cpuid": { "00000000": {"eax" :123,"ebx" :456, "ecx" :789,"edx" :321}, "00000001": {"eax" :123,"ebx" :456, "ecx" :789,"edx" :321}}, "driver_installed" : True, "instance_id" : "yyy", "version" : "0.2.0", "machine_info" : "I'm awesome.", "os_version" : "linux", "physical_memory_mib" : 1024, "product_loaded" : True, "type" : "machine_info", "virtualization_advertised" : True} ])))

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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