Define a positive number to be isolated if none of the digits in its square are in its cube [closed]
- by proglaxmi
Define a positive number to be isolated if none of the digits in its square are in its cube. For example 163 is n isolated number because 69*69 = 26569 and 69*69*69 = 4330747 and the square does not contain any of the digits 0, 3, 4 and 7 which are the digits used in the cube. On the other hand 162 is not an isolated number because 162*162=26244 and 162*162*162 = 4251528 and the digits 2 and 4 which appear in the square are also in the cube.
Write a function named isIsolated that returns 1 if its argument is an isolated number, it returns 0 if its not an isolated number and it returns -1 if it cannot determine whether it is isolated or not (see the note below). The function signature is:
int isIsolated(long n)
Note that the type of the input parameter is long. The maximum positive number that can be represented as a long is 63 bits long. This allows us to test numbers up to 2,097,151 because the cube of 2,097,151 can be represented as a long. However, the cube of 2,097,152 requires more than 63 bits to represent it and hence cannot be computed without extra effort. Therefore, your function should test if n is larger than 2,097,151 and return -1 if it is. If n is less than 1 your function should also return -1.
Hint: n % 10 is the rightmost digit of n, n = n/10 shifts the digits of n one place to the right.
The first 10 isolated numbers are
N n*n n*n*n
2 4 8
3 9 27
8 64 512
9 81 729
14 196 2744
24 576 13824
28 784 21952
34 1156 39304
58 3364 195112
63 3969 250047
