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  • question about MySQL transaction and trigger

    - by WilliamLou
    I quickly browsed MySQL manual but didn't find the exact information about my question. Here is my question: if I have a InnoDB table A with two triggers triggered by 'AFTER INSERT ON A' and 'AFTER UPDATE ON A'. More specifically, For example: one trigger is defined as: CREATE TRIGGER test_trigger AFTER INSERT ON A FOR EACH ROW BEGIN INSERT INTO B SELECT * FROM A WHERE A.col1 = NEW.col1 END; You can ignore the query between BEGIN AND END, basically I mean this trigger will insert several rows into table B which is also a InnoDB table. Now, if I started a transaction and then insert many rows, say: 10K rows, into table A. If there is no trigger associated with table A, all these inserts are atomic, that's for sure. Now, if table A is associated with several insert/update triggers which insert/update many rows to table B and/or table C etc.. will all these inserts and/or updates are still all atomic? I think it's still atomic, but it's kind of difficult to test and I can't find any explanations in the Manual. Anyone can confirm this? Thanks a lot!

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  • AJAX filter MySQL results using checkboxes

    - by keepitnang
    I'm attempting to get to grips with displaying filterable MySQL data within a PHP page based on user checkbox selections. I have a database of domain names and the dates on which these will require renewal as per Nominet DAC information and I can get unfiltered data to display, but filtering results by domain extensions is proving tricky for me to accomplish. I should point out at this stage that I am a serious newcomer to many of the ideas I am trying to learn to work with here, so please be gentle. I have tried following some other articles on here also, but no dice. I have the following so far: HTML <input type="checkbox" class="extensions" name="extensions" value=".co.uk">.co.uk</input> <input type="checkbox" class="extensions" name="extensions" value=".org.uk">.org.uk</input> Script $('.extensions').live('click', function() { var all_boxes = $('.extensions'); var all_boxes_values = []; var i = 0; for (var i; i < all_boxes.length; i++) { if (all_boxes[i].checked) { all_boxes_values.push(all_boxes[i].value) } } var all_boxes_values_clean = all_boxes_values.join(", "); console.log(all_boxes_values_clean); $.get("sql-test.php", {q: all_boxes_values_clean}, function(result) { $("div#output").html(result); } )}); PHP $g = $_GET['q']; $extensionsql=""; $extension=1; if(isset($g)) { $extension=1; $param = "" . str_replace(",", "','", $_GET['q']) . ""; } And that's as far as I have gotten with my limited ability. What I would like to do next is search the column domainName for a string match and return the appropriate results to the user. Something to mimic something like the following but I'm not sure how to achieve it. Any help would be much appreciated: SELECT * FROM `refresh` WHERE `domainName` LIKE '%.co.uk%' AND renewalDate LIKE '%2012-06-30%' ORDER BY `domainName` ASC Thanks

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  • Convert charset in mysql query

    - by Yousf
    Hi, I have a question about converting charset from inside mysql query. I have a 2 databases. One for the website (joomla), the other for forum (IPB). I am doing query from inside joomla, which by default have "SET NAMES UTF8". I want to query a table inside the forum databases. A table called "ibf_topics". This table has latin1 encoding. I do the following to select anything from the not-utf8 table. //convert connection to handle latin1. $query = "SET NAMES latin1"; $db->setQuery($query); $db->query(); $query = "select id, title from other_database.ibf_topics"; $db->setQuery($query); $db->query(); //read result into an array. //return connection to handle UTF8. $query = "SET NAMES UTF8"; $db->setQuery($query); $db->query(); After that, when I want to use the selected tile, I use the following: echo iconv("CP1256", "UTF-8", $topic['title']) The question is, is there anyway to avoid all this hassle? For now, I can't change forum database to UTF8 and I can't change joomla database to latin1 :S

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  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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  • Use MySQL trigger to update another table when duplicate key found

    - by Jason
    Been scratching my head on this one, hoping one of you kind people and direct me towards solving this problem. I have a mysql table of customers, it contains a lot of data, but for the purpose of this question, we only need to worry about 4 columns 'ID', 'Firstname', 'Lastname', 'Postcode' Problem is, the table contains a lot of duplicated customers. A new table is being created where each customer is unique and for us, we decide a unique customer is based on 'Firstname', 'Lastname' and 'Postcode' However, (this is the important bit) we need to ensure each new "unique" customer record also can be matched to the original multiple entries of that customer in the original table. I believe the best way to do this is to have a third table, that has 'NewUniqueID', 'OldCustomerID'. So we can search this table for 'NewUniqueID' = '123' and it would return multiple 'OldCustomerID' values where appropriate. I am hoping to make this work using a trigger and the on duplicate key syntax. So what would happen is as follows: An query is run taking the old customer table and inserting it in to the new unique table. (A standard Insert Select query) On duplicate key continue adding records, but add one entry in to the third table noting the 'NewUniqueID' that duped along with the 'OldCustomerID' of the record we were trying to insert. Hope this makes sense, my apologies if it isn't clear. I welcome and appreciate any thoughts on this one! Many thanks Jason

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  • Mysql query in drupal database - groupwise maximum with duplicate data

    - by nselikoff
    I'm working on a mysql query in a Drupal database that pulls together users and two different cck content types. I know people ask for help with groupwise maximum queries all the time... I've done my best but I need help. This is what I have so far: # the artists SELECT users.uid, users.name AS username, n1.title AS artist_name FROM users LEFT JOIN users_roles ur ON users.uid=ur.uid INNER JOIN role r ON ur.rid=r.rid AND r.name='artist' LEFT JOIN node n1 ON n1.uid = users.uid AND n1.type = 'submission' WHERE users.status = 1 ORDER BY users.name; This gives me data that looks like: uid username artist_name 1 foo Joe the Plumber 2 bar Jane Doe 3 baz The Tooth Fairy Also, I've got this query: # artwork SELECT n.nid, n.uid, a.field_order_value FROM node n LEFT JOIN content_type_artwork a ON n.nid = a.nid WHERE n.type = 'artwork' ORDER BY n.uid, a.field_order_value; Which gives me data like this: nid uid field_order_value 1 1 1 2 1 3 3 1 2 4 2 NULL 5 3 1 6 3 1 Additional relevant info: nid is the primary key for an Artwork every Artist has one or more Artworks valid data for field_order_value is NULL, 1, 2, 3, or 4 field_order_value is not necessarily unique per Artist - an Artist could have 4 Artworks all with field_order_value = 1. What I want is the row with the minimum field_order_value from my second query joined with the artist information from the first query. In cases where the field_order_value is not valuable information (either because the Artist has used duplicate values among their Artworks or left that field NULL), I would like the row with the minimum nid from the second query.

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  • Need to find number of new unique ID numbers in a MySQL table

    - by Nicholas
    I have an iPhone app out there that "calls home" to my server every time a user uses it. On my server, I create a row in a MySQL table each time with the unique ID (similar to a serial number) aka UDID for the device, IP address, and other data. Table ClientLog columns: Time, UDID, etc, etc. What I'd like to know is the number of new devices (new unique UDIDs) on a given date. I.e. how many UDIDs were added to the table on a given date that don't appear before that date? Put plainly, this is the number of new users I gained that day. This is close, I think, but I'm not 100% there and not sure it's what I want... SELECT distinct UDID FROM ClientLog a WHERE NOT EXISTS ( SELECT * FROM ClientLog b WHERE a.UDID = b.UDID AND b.Time <= '2010-04-05 00:00:00' ) I think the number of rows returned is the new unique users after the given date, but I'm not sure. And I want to add to the statement to limit it to a date range (specify an upper bound as well).

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  • How to populate html combo box with mysql data

    - by user225269
    Please help, I'm having trouble loading mysql data on the combo box. The data that I'm loading is 1 column from a table. Here is my current code, and it crashed firefox for some reason: <td colspan=”2?>Religion</TD> <td> <select name="REL" onClick="submitCboSemester();"> <?php $query_disp="SELECT * FROM Religion ORDER BY RID"; $result_disp = mysql_query($query_disp, $conn); while($query_data = mysql_fetch_array($result_disp)) { ?> <option value="<? echo $query_data["RID"]; ?>"<?php if ($query_data["RID"]==$_POST['REL']) {?>selected<? } ?>><? echo $query_data["RELIGION"]; ?></option> <? } ?> </select> </td> The column is RELIGION and it ID is RID How do I populate the combo box with all the data in the column RELIGION

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  • C# WPF Show Image from Mysql

    - by user3718026
    i'm a student and i am bad at programing. I saved the images in my mysql database for each player. I created a program where I can list some soccer players from my database. When i click on a listed player in datagrid, a new window appears with the information about the player. Everything works, but now i want a picture of the selected player to be displayed on the information window from the database. Can anybody help me? My english is not the best (i'm 17) so i hope you can understand what i mean. This is what i tried to do but i don't know how to continue. PS. It's in WPF. MySqlCommand cmd = new MySqlCommand("SELECT Bilder FROM spieler WHERE Bilder='{8}'"); MySqlDataReader rdr1 = cmd.ExecuteReader(); try { conn.Open(); while (rdr1.Read()) { // image1... I don't know what to write here } } catch (Exception ex) { MessageBox.Show("Fehler: " + ex); } rdr1.Close()

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • PHP: MySQL query duplicating update for no reason

    - by ThinkingInBits
    The code below is first the client code, then the class file. For some reason the 'deductTokens()' method is calling twice, thus charging an account double. I've been programming all night, so I may just need a second pair of eyes: if ($action == 'place_order') { if ($_REQUEST['unlimited'] == 200) { $license = 'extended'; } else { $license = 'standard'; } if ($photograph->isValidPhotographSize($photograph_id, $_REQUEST['size_radio'])) { $token_cost = $photograph->getTokenCost($_REQUEST['size_radio'], $_REQUEST['unlimited']); $order = new ImageOrder($_SESSION['user']['id'], $_REQUEST['size_radio'], $license, $token_cost); $order->saveOrder(); $order->deductTokens(); header('location: account.php'); } else { die("Please go back and select a valid photograph size"); } } ######CLASS CODE####### <?php include_once('database_classes.php'); class Order { protected $account_id; protected $cost; protected $license; public function __construct($account_id, $license, $cost) { $this->account_id = $account_id; $this->cost = $cost; $this->license = $license; } } class ImageOrder extends Order { protected $size; public function __construct($account_id, $size, $license, $cost) { $this->size = $size; parent::__construct($account_id, $license, $cost); } public function saveOrder() { //$db = Connect::connect(); //$account_id = $db->real_escape_string($this->account_id); //$size = $db->real_escape_string($this->size); //$license = $db->real_escape_string($this->license); //$cost = $db->real_escape_string($this->cost); } public function deductTokens() { $db = Connect::connect(); $account_id = $db->real_escape_string($this->account_id); $cost = $db->real_escape_string($this->cost); $query = "UPDATE accounts set tokens=tokens-$cost WHERE id=$account_id"; $result = $db->query($query); } } ?> When I die("$query"); directly after the query, it's printing the proper statement, and when I run that query within MySQL it works perfectly.

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  • authorise user from mysql database

    - by Jacksta
    I suck at php, and cant find the error here. The script gets 2 variables "username" and "password" from a html from then check them against a MySQL databse. When I run this I get the follow error "Query was empty" <? if ((!$_POST[username]) || (!$_POST[password])) { header("Location: show_login.html"); exit; } $db_name = "testDB"; $table_name = "auth_users"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $slq = "SELECT * FROM $table_name WHERE username ='$_POST[username]' AND password = password('$_POST[password]')"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = mysql_num_rows($result); if ($num != 0) { $msg = "<p>Congratulations, you're authorised!</p>"; } else { header("Location: show_login.html"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Secret Area</title> </head> <body> <? echo "$msg"; ?> </body> </html>

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  • Working with PHP and MySQL - need a good and secure design with OO design

    - by Andrew
    I am new to PHP- first time developer. I am working on my web application and it is nearly done; nevertheless, most of my sql was done directly via code using direct mysql requests. This is the way I approached it: In classes_db.php I declared the db settings and created methods that I use to open and close DB connections. I declare those objects on my regular pages: class classes_db { public $dbserver = 'server; public $dbusername = 'user'; public $dbpassword = 'pass'; public $dbname = 'db'; function openDb() { $dbhandle = mysql_connect($this->dbserver, $this->dbusername, $this->dbpassword); if (!$dbhandle) { die('Could not connect: ' . mysql_error()); } $selected = mysql_select_db($this->dbname, $dbhandle) or die("Could not select the database"); return $dbhandle; } function closeDb($con) { mysql_close($con); } } On my regular page, I do this: <?php require 'classes_db.php'; session_start(); //create instance of the DB class $db = new classes_db(); //get dbhandle $dbhandle = $db->openDb(); //process query $result = mysql_query("update user set username = '" . $usernameFromForm . "' where iduser= " . $_SESSION['user']->iduser); //close the connection if (isset($dbhandle)) { $db->closeDb($dbhandle); } ?> My questions is: how to do it right and make it OO and secure? I know that I need incorporate prepared queries- how to do it the best way? Please provide some code

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  • Mysql count and sum from two diferent tables

    - by Agent_x
    Hi all, i have a problem with some querys in php and mysql: I have 2 diferent tables with one field in common: table 1 id | hits | num_g | cats | usr_id |active 1 | 10 | 11 | 1 | 53 | 1 2 | 13 | 16 | 3 | 53 | 1 1 | 10 | 22 | 1 | 22 | 1 1 | 10 | 21 | 3 | 22 | 1 1 | 2 | 6 | 2 | 11 | 1 1 | 11 | 1 | 1 | 11 | 1 table 2 id | usr_id | points 1 | 53 | 300 Now i use this statement to sum just the total from the table 1 every id count + 1 too SELECT usr_id, COUNT( id ) + SUM( num_g + hits ) AS tot_h FROM table1 WHERE usr_id!='0' GROUP BY usr_id ASC LIMIT 0 , 15 and i get the total for each usr_id usr_id| tot_h | 53 | 50 22 | 63 11 | 20 until here all is ok, now i have a second table with extra points (table2) I try this: SELECT usr_id, COUNT( id ) + SUM( num_g + hits ) + (SELECT points FROM table2 WHERE usr_id != '0' ) AS tot_h FROM table1 WHERE usr_id != '0' GROUP BY usr_id ASC LIMIT 0 , 15 but it seems to sum the 300 extra points to all users: usr_id| tot_h | 53 | 350 22 | 363 11 | 320 Now how i can get the total like the first try but + the secon table in one statement? because now i have just one entry in the second table but i can be more there. thanks for all the help. =============================================================================== hi thomas thanks for your reply, i think is in the right direction, but im getting weirds results, like usr_id | tot_h 22 | NULL <== i think the null its because that usr_id as no value in the table2 53 | 1033 Its like the second user is getting all the the values. then i try this one: SELECT table1.usr_id, COUNT( table1.id ) + SUM( table1.num_g + table1.hits + table2.points ) AS tot_h FROM table1 LEFT JOIN table2 ON table2.usr_id = table1.usr_id WHERE table1.usr_id != '0' AND table2.usr_id = table1.usr_id GROUP BY table1.usr_id ASC Same result i just get the sum of all values and not by each user, i need something like this result: usr_id | tot_h 53 | 53 <==== plus 300 points on table1 22 | 56 <==== plus 100 points on table2 /////////the result i need //////////// usr_id | tot_h 53 | 353 <==== plus 300 points on table2 22 | 156 <==== plus 100 points on table2 I think the structure need to be something like this Pseudo statements ;) from table1 count all id to get the number of record where the usr_id are then sum hits + num_g and from table2 select the extra points where the usr_id are the same as table1 and get teh result: usr_id | tot_h 53 | 353 22 | 156

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  • Refining Search Results [PHP/MySQL]

    - by Dae
    I'm creating a set of search panes that allow users to tweak their results set after submitting a query. We pull commonly occurring values in certain fields from the results and display them in order of their popularity - you've all seen this sort of thing on eBay. So, if a lot of rows in our results were created in 2009, we'll be able to click "2009" and see only rows created in that year. What in your opinion is the most efficient way of applying these filters? My working solution was to discard entries from the results that didn't match the extra arguments, like: while($row = mysql_fetch_assoc($query)) { foreach($_GET as $key => $val) { if($val !== $row[$key]) { continue 2; } } // Output... } This method should hopefully only query the database once in effect, as adding filters doesn't change the query - MySQL can cache and reuse one data set. On the downside it makes pagination a bit of a headache. The obvious alternative would be to build any additional criteria into the initial query, something like: $sql = "SELECT * FROM tbl MATCH (title, description) AGAINST ('$search_term')"; foreach($_GET as $key => $var) { $sql .= " AND ".$key." = ".$var; } Are there good reasons to do this instead? Or are there better options altogether? Maybe a temporary table? Any thoughts much appreciated!

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  • hibernate: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException

    - by user121196
    when saving an object to database using hibernate, sometimes it fails because certain fields of the object exceed the maximum varchar length defined in the database. There force I am using the following approach: 1. attempt to save 2. if getting an DataException, then I truncate the fields in the object to the max length specified in the db definition, then try to save again. However, in the second save after truncation. I'm getting the following exception: hibernate: com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Cannot add or update a child row: a foreign key constraint fails here's the relevant code, what's wrong? public static void saveLenientObject(Object obj){ try { save2(rec); } catch (org.hibernate.exception.DataException e) { // TODO Auto-generated catch block e.printStackTrace(); saveLenientObject(rec, e); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } } private static void saveLenientObject(Object rec, DataException e) { Util.truncateObject(rec); System.out.println("after truncation "); save2(rec); } public static void save2(Object obj) throws Exception{ try{ beginTransaction(); getSession().save(obj); commitTransaction(); }catch(Exception e){ e.printStackTrace(); rollbackTransaction(); //closeSession(); throw e; }finally{ closeSession(); } }

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  • Beginner PHP: I can't insert data into MYSQL database

    - by Victor
    I'm learning PHP right now and I'm trying to insert data into a MySQL database called "pumpl2" The table is set up like this. create table product ( productid int unsigned not null auto_increment primary key, price int(9) not null, value int(9) not null, description text ); I have a form and want to insert the fields from the form in the database. Here is what the php file looks like. <?php // create short variable names $price = $_POST['price']; $value = $_POST['value']; $description = $_POST['description']; if (!$price || !$value || !$description) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } @ $db = new mysqli('localhost', 'pumpl', '********', 'pumpl2'); if (mysqli_connect_errno()) { echo "Error: Could not connect to database. Please try again later."; exit; } $query = "insert into pumpl2 values ('".$price."', '".$value."', '".$description."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." product inserted into database."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> When I submit the form, I get an error message "An error has occurred. The item was not added." Does anyone know what the problem is? Thank you!

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  • Inexplicably slow query in MySQL

    - by Brandon M.
    Given this result-set: mysql> EXPLAIN SELECT c.cust_name, SUM(l.line_subtotal) FROM customer c -> JOIN slip s ON s.cust_id = c.cust_id -> JOIN line l ON l.slip_id = s.slip_id -> JOIN vendor v ON v.vend_id = l.vend_id WHERE v.vend_name = 'blahblah' -> GROUP BY c.cust_name -> HAVING SUM(l.line_subtotal) > 49999 -> ORDER BY c.cust_name; +----+-------------+-------+--------+---------------------------------+---------------+---------+----------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+--------+---------------------------------+---------------+---------+----------------------+------+----------------------------------------------+ | 1 | SIMPLE | v | ref | PRIMARY,idx_vend_name | idx_vend_name | 12 | const | 1 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | l | ref | idx_vend_id | idx_vend_id | 4 | csv_import.v.vend_id | 446 | | | 1 | SIMPLE | s | eq_ref | PRIMARY,idx_cust_id,idx_slip_id | PRIMARY | 4 | csv_import.l.slip_id | 1 | | | 1 | SIMPLE | c | eq_ref | PRIMARY,cIndex | PRIMARY | 4 | csv_import.s.cust_id | 1 | | +----+-------------+-------+--------+---------------------------------+---------------+---------+----------------------+------+----------------------------------------------+ 4 rows in set (0.04 sec) I'm a bit baffled as to why the query referenced by this EXPLAIN statement is still taking about a minute to execute. Isn't it true that this query only has to search through 449 rows? Anyone have any idea as to what could be slowing it down so much?

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  • Determining Best Table Structure for MySQL Performance

    - by Joe Majewski
    I'm working on a browser-based RPG for one of my websites, and right now I'm trying to determine the best way to organize my SQL tables for performance and maintenance. Here's my question: Does the number of columns in an SQL table affect the speed in which it can be queried? I am not a newbie when it comes to PHP or MySQL. I used to develop things with the common goal of getting them to work, but I've recently advanced to the stage where a functional program is not good enough unless it's fast and reliable. Anyways, right now I have a members table that has around 15 columns. It contains information such as the player's username, password, email, logins, page views, etcetera. It doesn't contain any information on the player's progress in the game, however. If I added columns for things such as army size, gold, turns, and whatnot, then it could easily rise to around 40 or 50 total columns. Oh, and my database structure IS normalized. Will a table with 50 columns that gets constantly queried be a bad idea? Should I split it into two tables; one for the user's general information and one for the user's game statistics? I know I could check the query time myself, but I haven't actually created the tables yet and I think I'd be better off with some professional advice on this important decision for my game. Thank you for your time! :)

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  • Complex sorting on MySQL database

    - by ChrisR
    I'm facing the following situation. We've got an CMS with an entity with translations. These translations are stored in a different table with a one-to-many relationship. For example newsarticles and newsarticle_translations. The amount of available languages is dynamically determined by the same CMS. When entering a new newsarticle the editor is required to enter at least one translation, which one of the available languages he chooses is up to him. In the newsarticle overview in our CMS we would like to show a column with the (translated) article title, but since none of the languages are mandatory (one of them is mandatory but i don't know which one) i don't really know how to construct my mysql query to select a title for each newsarticle, regardless of the entered language. And to make it all a little harder, our manager asked for the possibilty to also be able to sort on title, so fetching the translations in a separate query is ruled out as far as i know. Anyone has an idea on how to solve this in the most efficient way? Here are my table schema's it it might help > desc news; +-----------------+----------------+------+-----+-------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+----------------+------+-----+-------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | category_id | int(1) | YES | | NULL | | | created | timestamp | NO | | CURRENT_TIMESTAMP | | | user_id | int(10) | YES | | NULL | | +-----------------+----------------+------+-----+-------------------+----------------+ > desc news_translations; +-----------------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | enabled | tinyint(1) | NO | | 0 | | | news_id | int(1) unsigned | NO | | NULL | | | title | varchar(255) | NO | | | | | summary | text | YES | | NULL | | | body | text | NO | | NULL | | | language | varchar(2) | NO | | NULL | | +-----------------+------------------+------+-----+---------+----------------+ PS: i've though about subqueries and coalesce() solutions but those seem rather dirty tricks, wondering if something better is know that i'm not thinking of?

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  • MYSQL/PHP: Inserting data via HTML form, same "input name"

    - by Camen
    I'm new to MySQL and as a learning project I'd like to make a recipe database. I'd like to the user to be able to enter ingredients through a simple HTML form but I'm stuck in how to label the form so that I can enter several ingredients into the database at once. I'd like to do something like this: <form method="post" action="insert.php"> Ingredient 1: <input type="text" name="ingredient"><br /> Ingredient 2: <input type="text" name="ingredient"><br /> Ingredient 3: <input type="text" name="ingredient"><br /> <input type="submit" value="Submit"> </form> When I do this, I add rows to the table but they're all empty. I know it's got something to do with me using "ingredient" (the table value where I want to add the ingredient name) several times in the form, but I just don't know how to solve it. I would absolutely love some input on how to make it work.

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  • Run multiple MySQL queries based on a series of ifs

    - by OldWest
    I am just getting started on this complex query I need to write and was hoping for any suggestions or feedback regarding table structure and the actual query itself.. I've already created my tables and populated test data, and now just trying to sort out how and what is possible within MySQL. Here is an outline of the problem: End result: Listing of rates based on specific queried criteria (see below): Age: [ 27 ] Spouse Age: [ 25 ] Num of Children: [ 3 ] Zip Code: [ 97128 ] The problem I am running into is each company that provides rates has a unique way of dealing with the rate. And I am looking for the best approach for multiple queries based on the company (one query with results for each company more or less all combined into one result set). Here are some facts: - Each company deals with zip code ranges which assist in the query result. - Each company has a different method of calculating the rate based on the Applicant, Spouse, Num of Children: Example, a) Company A determines rate by: Applicant + Spouse + Child(ren) = rate (age is pertinent to the applicant within a range). b) Company B determines the rate by total number of applicants like: 1, 2, 3, 4, 5, 6+ = rate (and age is ignored). First off, what would I call this type of query? Multiple nested query? And should I intertwine php within it to determine the If()s ... I apologize if this thread lacks sufficient data, so please tell me anything you would like to see.

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  • Increase and decrease row value by 1 in MySQL

    - by Elliott
    Hi I have a MySQL database table "points" the user can click a button and a point should be removed from their account, the button they pressed has an ID of another user, therefore their account must increase by one. I have it working in jQuery and checked the varibles/posts in Firebug, and it does send the correct data, such as: userid= 1 posterid = 4 I think the problem is with my PHP page: <?php include ('../functions.php'); $userid=mysql_real_escape_string($_POST['user_id']); $posterid=mysql_real_escape_string($_POST['poster_id']); if (loggedin()) { include ('../connection.php'); $query1 = "UPDATE `points` SET `points` = `points` - 1 WHERE `userID` = '$userid'"; $result1=mysql_query($query1); $query2 = "UPDATE `points` SET `points` = `points` + 1 WHERE `userID` = '$posterid'"; $result2=mysql_query($query2); if ($result1 && result2) { echo "Successful"; return 1; } else { echo mysql_error(); return 0; } } ?> Any ideas? Thanks :)

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  • Error No 150 mySQL

    - by buddhamagnet
    Hi all. This is making me sweat - I am getting error 150 when I try and create a table in mySQL. I've scoured the forums to no avail. The statement uses foreign key constraints - both tables are InnoDB, all relevant columns have the same data type and both tables have the same charset and collation. Here's the CREATE TABLE and the original CREATE TABLE statement for the table that's being referenced. Any ideas? New table: CREATE TABLE `approval` ( `rev_id` int(10) UNSIGNED NOT NULL, `rev_page` int(10) UNSIGNED NOT NULL, `user_id` int(10) UNSIGNED NOT NULL, `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`rev_id`,`rev_page`,`user_id`), KEY `FK_approval_user` (`user_id`), CONSTRAINT `FK_approval_revision` FOREIGN KEY (`rev_id`, `rev_page`) REFERENCES `revision` (`rev_id`, `rev_page`), CONSTRAINT `FK_approval_user` FOREIGN KEY (`user_id`) REFERENCES `user` (`user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Referenced table: CREATE TABLE `revision` ( `rev_id` int(10) unsigned NOT NULL auto_increment, `rev_page` int(10) unsigned NOT NULL, `rev_text_id` int(10) unsigned NOT NULL, `rev_comment` tinyblob NOT NULL, `rev_user` int(10) unsigned NOT NULL default '0', `rev_user_text` varbinary(255) NOT NULL default '', `rev_timestamp` binary(14) NOT NULL default '\0\0\0\0\0\0\0\0\0\0\0\0\0\0', `rev_minor_edit` tinyint(3) unsigned NOT NULL default '0', `rev_deleted` tinyint(3) unsigned NOT NULL default '0', `rev_len` int(10) unsigned default NULL, `rev_parent_id` int(10) unsigned default NULL, PRIMARY KEY (`rev_id`), UNIQUE KEY `rev_page_id` (`rev_page`,`rev_id`), KEY `rev_timestamp` (`rev_timestamp`), KEY `page_timestamp` (`rev_page`,`rev_timestamp`), KEY `user_timestamp` (`rev_user`,`rev_timestamp`), KEY `usertext_timestamp` (`rev_user_text`,`rev_timestamp`) ) ENGINE=InnoDB AUTO_INCREMENT=4904 DEFAULT CHARSET=binary MAX_ROWS=10000000 AVG_ROW_LENGTH=1024;

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  • mysql to excel genration using php

    - by pmms
    <?php // DB Connection here mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $select = "SELECT * FROM jos_users "; $export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; ? the above code is used for genrating mysql to excel sheet but we are getting following error the file youare trying to open, 'users.xls',is in a different format than specified by the file extension. verify that the file is not corrupted and is from a trusted source before opening the file. do you want to open the file now?

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