Search Results

Search found 10496 results on 420 pages for 'session bean'.

Page 153/420 | < Previous Page | 149 150 151 152 153 154 155 156 157 158 159 160  | Next Page >

  • Pass form data from block to a page view in Drupal

    - by abdesignuk
    I am using the location module and views module for a postcode search, which works fine in a page display using views. However I want the user to be able to enter their postcode into a block on the homepage and clicking submit my module sends them to the page created in views and the postcode is set as a session S_SESSION['postcode'] before sending to this page, next I want the location page to load but using the session to display the locations automatically. Any ideas I am using hook_form_submit() and inside that declaring the $form_state as a session and then using $form_state['redirect'] to sent to the views page path.

    Read the article

  • Different i18n in spring according to url

    - by Fanooos
    I have a spring web application that is required to work as following the application will be accessed from two different URLs www.domain1.com and www.domain2.com and it is required that the two URLs looks like two different applications with different CSS and I18n. for the css part is done but I am stuck with the i18n part How to make spring load different i18n properties file according to the domain name? The solution that I thought in is to implement a filter that check the request URL and according to the URL it clears the message source bean and load the required i18n file but it does not looks good for the performance by the way I am using ReloadableResourceBundleMessageSource message source Another solution is to implement two different message sources. The problem with this solution is that from the source code I can manage the bean that I use but how can I tell the fmt:message tag which data source to use ? Thanks in advance and best regards

    Read the article

  • multiple rows of a single table

    - by Amanjot Singh
    i am having a table with 3 col. viz id,profile_id,plugin_id.there can be more than 1 plugins associated with a single profile now how can i fetch from the database all the plugins associated with a profile_id which comes from the session variable defined in the login page when I try to apply the query for the same it returns the data with the plugin_id of the last record the query is as follows SqlCommand cmd1 = new SqlCommand("select plugin_id from profiles_plugins where profile_id=" + Convert.ToInt32(Session["cod"]), con); SqlDataReader dr1 = cmd1.ExecuteReader(); if (dr1.HasRows) { while (dr1.Read()) { Session["edp1"] = Convert.ToInt32(dr1[0]); } } dr1.Close(); cmd1.Dispose();

    Read the article

  • Create Custom Criterion in NHibernate?

    - by vbullinger
    I'm still a bit of a n00b when it comes to NHibernate. Let's say I have the following: var myCriteria = this.Session.CreateCriteria(typeof(SomeModel)).Add(Restrictions.Eq("SomeProperty", someValue); Then, let's say I want to add criteria in a way that's reusable. Meaning, I want to make a custom criterion. I'm seeing very, very little information online on this. Specifically, I'd like to turn the following: var myCriteria = this.Session.CreateCriteria(typeof(SomeModel)) .Add(Restrictions.Eq("SomeProperty", someValue) .CreateAlias("SomeClass", "alias", JoinType.LeftOuterJoin) .Add(Restrictions.Eq("alias.SomeOtherProperty", someOtherValue)); Into the following: var myCriteria = this.Session.CreateCriteria(typeof(SomeModel)) .Add(Restrictions.Eq("SomeProperty", someValue) .Add(this.GetAliasCriterion()); Thus extracting .CreateAlias("SomeClass", "alias", JoinType.LeftOuterJoin).Add(Restrictions.Eq("alias.SomeOtherProperty", someOtherValue)); into a method. Is this possible? How does this work?

    Read the article

  • Spring MVC JSP Parameters

    - by zpinter
    I'm looking to turn off try blocks for a specific JSP page (though turning it off globally would be OK as well). From what I've gathered, it looks something like this: <jsp-param> <param-name>noTryBlocks</param-name> <param-value>true</param-value> </jsp-param> However, everywhere I see that sample it's for a weblogic.xml file. Does anybody know how I can set this JSP parameters for a Spring MVC application? web.xml? Perhaps somewhere near here?: <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean>

    Read the article

  • Effective Entity Update In Hibernate ?

    - by Tony
    I've always wanted to know How can I update an entity effectively in hibernate just as by using SQL. For example : I have a product entity , has a field name createTime , when I use session.saveOrUpdate(product) ; I have to get this field from database and then set to product then update , actually whenever I use session.saveOrUpdate() , I updated ALL fileds , even if I just need update only one field. but most time the value object we passed to DAO layer can't contain all fileds information , like the createDate in Product , we seldom need to update this field. How to just update selected fields ? Of course I can use HQL , but that will separate save and update logic . It would be better If Hibernate has a method like this : session.updateOnlyNotNullFields(product); How can I do this in Hibernate ?

    Read the article

  • Cannot output json from MySQL - getting null value

    - by sky
    I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script>

    Read the article

  • What is the fastest way to get the persisted object after calling Hibernate's saveOrUpdate?

    - by Dave
    I'm using Hibernate 3.2.1.ga, hibernate annotations 3.2.1.ga, and hibernate-jpa-2.0-api. I can't upgrade at this time as I'm working with legacy code. I have this generic method for saving or updating objects ... protected void saveOrUpdate(Object obj) { final Session session = sessionFactory.getCurrentSession(); session.saveOrUpdate(obj); } You can assume that every argument, "obj," will have a member field that is marked with the "@Id" annotation. I would like to change the return type to return an Object that represents the persisted object in the database (meaning if "obj" didn't contain an id before, what is returned is the database object with a populated id. What is the fastest way to do this given my versioning and generic constraints?

    Read the article

  • Spring 3.0 MVC mvc:view-controller tag

    - by gouki
    Here's a snippet of my mvc-config.xml <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/views/"/> <property name="suffix" value=".jsp"/> </bean> <mvc:view-controller path="/index" view-name="welcome"/> <mvc:view-controller path="/static/login" view-name="/static/login"/> <mvc:view-controller path="/login" view-name="/static/login"/> I have the welcome.jsp on /WEB-INF/view/ directory and login.jsp on /WEB-INF/view/static/. This work for '/index' and '/login' paths. But I'm getting 404 response for '/static/login' when invoked from the browser. I'm expecting that '/static/login/' and '/login' should behave the same. What could be wrong here? Would appreciate any help. Thanks!

    Read the article

  • PostgreSQL function to iterate through/act on many rows with state

    - by Claudiu
    I have a database with columns looking like: session | order | atype | amt --------+-------+-------+----- 1 | 0 | ADD | 10 1 | 1 | ADD | 20 1 | 2 | SET | 35 1 | 3 | ADD | 10 2 | 0 | SET | 30 2 | 1 | ADD | 20 2 | 2 | SET | 55 It represents actions happening. Each session starts at 0. ADD adds an amount, while SET sets it. I want a function to return the end value of a session, e.g. SELECT session_val(1); --returns 45 SELECT session_val(2); --returns 55 Is it possible to write such a function/query? I don't know how to do any iteration-like things with SQL, or if it's possible at all.

    Read the article

  • schedule task with spring mvc

    - by user3586352
    I want to run the following method every specific time in spring mvc project it works fine and print first output but it doesn't access the database so it doesn't display list the method public class ScheduleService { @Autowired private UserDetailService userDetailService; public void performService() throws IOException { System.out.println("first output"); List<UserDetail> list=userDetailService.getAll(); System.out.println(list); } config file <!-- Spring's scheduling support --> <task:scheduled-tasks scheduler="taskScheduler"> <task:scheduled ref="ScheduleService" method="performService" fixed-delay="2000"/> </task:scheduled-tasks> <!-- The bean that does the actual work --> <bean id="ScheduleService" class="com.ctbllc.ctb.scheduling.ScheduleService" /> <!-- Defines a ThreadPoolTaskScheduler instance with configurable pool size. --> <task:scheduler id="taskScheduler" pool-size="1"/>

    Read the article

  • Check user authentication at page load

    - by Shrewd Demon
    ok i have another question ! (god! i have so many questions) i have an application and a user must log-in before he/she can access pages. now once the user logs in i keep the user details in a session variable (say Session["CurrentUser"]). now if a user tries to jump to a page directly i will check if the Session["CurrentUser"] has a value or not...if not then the user will be directed to the login page... my problem is that i have done this or rather say written this "Checking Code" on almost all the pages. what i want is this code to stay on a particular location and i will just access that method all the time on all the pages...now where should i write this method ?? thank you.

    Read the article

  • PHP read a cookie that is on another domain

    - by pnm123
    Hello, I have two domains. One domain contains the login script. It creates a cookie when logged in. Another domain have a URL shortener. So, on the 2nd domain that have the URL Shortener script have a file called session.php. Usually I was using $_COOKIE['sessionid'] to get the session id and match it using database. How can I get the session id now? I have tried few ways but none of them have solve my problem. Thank you, pnm123

    Read the article

  • Struts2 property tag escapeHtml is not working am I missing something?

    - by user1073570
    The following code is not working correctly. I would like to take the following Java String from the bean String statusMsg = "Hello World! <br/><br/><h3>Test</h3>" And output it with the HTML tags not escaped. <s:property escapeHtml="false" value="bean.statusMsg" The result of this property Tag and String, is that the HTML tags are still being escaped, am I missing something? My goal is to eventually build a table of status data and output it on the page is this the wrong way to use the property tag? Thank you in advance for your help.

    Read the article

  • How do I conditionally assign ruby variables to javascript variables?

    - by Tony
    I have a website where I need a javascript version of the "current user" object along with the ruby version. I have been assigning these variables doing something like this... Application Controller: def get_user begin @current_user = User.find(session[:user_id]) if session[:user_id] @current_user_json = @current_user.to_json rescue session.delete(:user_id) @current_user = nil @current_user_json = {} end end Web Page: var current_user = null; current_user_json = '<%= @current_user_json %>'; if(current_user_json != ''){ current_user = current_user_json.user; } Even when there is a current user, I get the current user is undefined. Probably because I am putting the current_user_json assignment around single quotes. However, if I don't put it around single quotes, I'll always get a javascript error when no user is logged in because the syntax is invalid - current_user_json = ; I think I am just looking at this completely wrong and there must be a better way. Given that this is probably a common thing to do, I wanted to get other people's opinion on how to create an object in javascript that is a duplicate of the ruby object.

    Read the article

  • Select one column from a row in hibernate

    - by ComfortablyNumb
    I am trying to do a simple query to get a unique result back in hibernate here is my code. public String getName(Integer id) { Session session = getSessionFactory().openSession(); String name = (String)session.createSQLQuery("SELECT name FROM users WHERE user_id = :userId").setParameter("userId", id).uniqueResult(); return name; } The name that is being returned is stored as HTML text that includes html syntacx language. I think this is what is causing the problem but it doesnt make sense I just want to return it as a string. It is only happening on this one field name, I can get every other field in the row but this one it gives me the error. I am getting an exception. The exception I am getting is No Dialect mapping for JDBC type: -1; nested exception is org.hibernate.HibernateException How do you query for a specific column on a row in hibernate?

    Read the article

  • Hibernate entities stored as HttpSession attribute values

    - by njudge
    I'm dealing with a legacy Java application with a large, fairly messy codebase. There's a fairly standard 'User' object that gets stored in the HttpSession between requests, so the servlets do stuff like this at the top: HttpSession session = request.getSession(true); User user = (User)session.getAttribute("User"); The old user authentication layer (which I won't describe; suffice to say, it did not use a database) is being replaced with code mapped to the DB with Hibernate. So 'User' is now a Hibernate entity. My understanding of Hibernate object life cycles is a little fuzzy, but it seems like storing 'User' in the HttpSession now becomes a problem, because it will be retrieved in a different transaction during the next request. What is the right thing to be doing here? Can I just use the Hibernate Session object's update() method to reattach the User instance the next time around? Do I need to?

    Read the article

  • How can i keep a data table thorough out my page?

    - by Jibu P C_Adoor
    Hii, I have a data table, and this datatable will be dynamically manipulated. After certain manipulation at the end we will populate that to the database. Which state mechanism can i use for this to retain. I have tried both Session and ViewState but ViewState can't use with AJAX rich appplications. Session will be clear after the user session. i can't afford both these difficulties. Does any other mechanism to keep the datatable through out the page.

    Read the article

  • Binding a select box to a Collection (with Spring)

    - by WiPU
    i have the following problem. I have a form bean and in this bean is a list with objects. List<SomeObjectForm> toDisplay; Now i want map a html select to this list. Something like that: <form:select id="inputGroupFields" path="templateKey" multiple="true"... <form:select id="inputGroupFields" path="templateKey.id" multiple="true"... And this dosnt work of course. Now i have tryed to add different custom Converter like: myConv implements Converter<SomeObjectForm, String> myConv extends StringToObject And this also not work. I'm not sure if this is the right approach or there is a easier way to do that. Some addional Infos: --i'm using spring 3.0.5 --all this happens during a web flow regards and thanks, WiPu

    Read the article

  • Using Forms authentication with remote auth system?

    - by chobo
    I am working on a website that uses a remote websites database to check for authentication (they are both share some database tables, but are separate website...) Right now I check the username and password against the remote websites account / member table, if there is a match I create a session. Questions: Is this secure? On authenticated pages I just check if a session of a specific type exists.Is it possible for someone to create an empty session or something that could bypass this? Is it possible to use Forms authentication with this setup? Right now if a user is authenticated I just get an object back with the username, email and id.

    Read the article

  • Hibernate/Spring: getHibernateTemplate().save(...) Freezes/Hangs

    - by ashes999
    I'm using Hibernate and Spring with the DAO pattern (all Hibernate dependencies in a *DAO.java class). I have nine unit tests (JUnit) which create some business objects, save them, and perform operations on them; the objects are in a hash (so I'm reusing the same objects all the time). My JUnit setup method calls my DAO.deleteAllObjects() method which calls getSession().createSQLQuery("DELETE FROM <tablename>").executeUpdate() for my business object table (just one). One of my unit tests (#8/9) freezes. I presumed it was a database deadlock, because the Hibernate log file shows my delete statement last. However, debugging showed that it's simply HibernateTemplate.save(someObject) that's freezing. (Eclipse shows that it's freezing on HibernateTemplate.save(Object), line 694.) Also interesting to note is that running this test by itself (not in the suite of 9 tests) doesn't cause any problems. How on earth do I troubleshoot and fix this? Also, I'm using @Entity annotations, if that matters. Edit: I removed reuse of my business objects (use unique objects in every method) -- didn't make a difference (still freezes). Edit: This started trickling into other tests, too (can't run more than one test class without getting something freezing) Transaction configuration: <bean id="txManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager"> <property name="dataSource" ref="dataSource" /> </bean> <tx:advice id="txAdvice" transaction-manager="txManager"> <!-- the transactional semantics... --> <tx:attributes> <!-- all methods starting with 'get' are read-only --> <tx:method name="get*" read-only="true" /> <tx:method name="find*" read-only="true" /> <!-- other methods use the default transaction settings (see below) --> <tx:method name="*" /> </tx:attributes> </tx:advice> <!-- my bean which is exhibiting the hanging behavior --> <aop:config> <aop:pointcut id="beanNameHere" expression="execution(* com.blah.blah.IMyDAO.*(..))" /> <aop:advisor advice-ref="txAdvice" pointcut-ref="beanNameHere" /> </aop:config>

    Read the article

  • Instantiating custom PropertySourcesPlaceholderConfigurer from spring context

    - by mmona
    I want to define a custom PropertySourcesPlaceholderConfigurer in spring context xml. I want to use there multiple PropertySources, so that I can load part of the configuration from several property files and provide other part dynamically by my custom PropertySource implementation. The advantage is that it should be then easy to adjust the order of loading these property sources just by making modifications to the xml spring configuration. And here I run into a problem: how to define an arbitrary list of PropertySources and inject it into PropertySourcesPlaceholderConfigurer, so that it uses the sources defined by me? Seems to be a basic thing that should be provided by spring, but since yesterday I cannot find a way to do it. Using namespace would enable me to load several property files, but I also need to define the id of the PropertySourcesPlaceholderConfigurer (as other projects refer to it), and also I want to use my custom implementation. That is why I am defining the bean explicitly and not using the namespace. The most intuitive way would be to inject a list of PropertySources into PropertySourcesPlaceholderConfigurer like this: <bean id="applicationPropertyPlaceholderConfigurer" class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer"> <property name="ignoreUnresolvablePlaceholders" value="true" /> <property name="ignoreResourceNotFound" value="true" /> <property name="order" value="0"/> <property name="propertySources"> <list> <!-- my PropertySource objects --> </list> </property> </bean> but unfortunately propertySources is of type PropertySources and does not accept a list. The PropertySources interface has one and only implementor which is MutablePropertySources, which indeed stores list of PropertySource objects, but has no constructor nor setter through which I can inject this list. It only has add*(PropertySource) methods. The only workaround I see now is to implement my own PropertySources class, extending MutablePropertySources, which would accept list of PropertySource objects on creation and manually add it via using add*(PropertySource) method. But why so much workaround would be needed to provide something that I thought was supposed to be the main reason of introducing the PropertySources (having flexible configuration manageable from spring configuration level). Please clarify what am I getting wrong :)

    Read the article

  • JSF navigation on commandbutton

    - by Nitesh Panchal
    Hello, I want to conditionally navigate to some page. If some condition is true i want to navigate to some other page else i want to remain on the same page. I have something like :- <h:commandButton action="#{bean.navigate}"/> in bean.navigate i have something like :- public String navigate(){ if(value <= 0) return "helloWorld"; else return ""; } But if i return "", error is thrown and in h:messages message is appended that page not found etc. How do i avoid this error?

    Read the article

  • display format for gridview

    - by peter
    I have a grid named 'GridView1' contains two columns 'Date' and 'Session Deatils' i am displaying like this way only <asp:GridView ID="GridView1" OnRowCommand="ScheduleGridView_RowCommand" runat="server" AutoGenerateColumns="False" Height="60px" Style="text-align: center" Width="869px" EnableViewState="False"> <Columns> <asp:BoundField HeaderText="Date" DataField="Date"><HeaderStyle Width="80px" /></asp:BoundField> <asp:BoundField DataField="" HeaderText="Session Detais" /> </Columns> But here i need to display 3 column sections downside Session details without any column borders for each dates,,how can i achive like this wasy Date SessionDetails 06-04-2010 Time-(value from database) Topic-(value from database) Head-(value from database) ------- ------------------ ------------------- ----------------------

    Read the article

< Previous Page | 149 150 151 152 153 154 155 156 157 158 159 160  | Next Page >