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  • File Handler returning garbled files.

    - by forcripesake
    For the past 3 months my site has been using a PHP file handler in combination with htaccess. Users accessing the uploads folder of the site would be redirected to the handler as such: RewriteRule ^(.+)\.*$ downloader.php?f=%{REQUEST_FILENAME} [L] The purpose of the file handler is pseudo coded below, followed by actual code. //Check if file exists and user is downloading from uploads directory; True. //Check against a file type white list and set the mime type(); $ctype = mime type; header("Pragma: public"); // required header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Cache-Control: private",false); // required for certain browsers header("Content-Type: $ctype"); header("Content-Disposition: attachment; filename=\"".basename($filename)."\";" ); header("Content-Transfer-Encoding: binary"); header("Content-Length: ".filesize($filename)); readfile("$filename"); As of yesterday, the handler started returning garbled files, unreadable images, and had to be bypassed. I'm wondering what settings could have gone awry to cause this.

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  • Uploading to S3 using Curl

    - by Carl Crawley
    Hi All, I'm currently using cURL to upload a file from my server to S3 using AJAX to call the script. So I have the following: $fullfilepath = '/server/sitepath/files/' . $_POST['file']; $upload_url = 'https://'.$_POST['buckets'].'.s3.amazonaws.com/'; $params = array( 'key'=>$_POST['key'], 'AWSAccessKeyId'=>$_POST['AWSAccessKeyId'], 'acl'=>$_POST['acl'], 'success_action_status'=>$_POST['success_action_status'], 'policy'=>$_POST['policy'], 'signature'=>$_POST['signature'], 'Content-Type'=>$_POST['Content-Type'], 'file'=>"@$fullfilepath" ); $ch = curl_init(); curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_URL, $upload_url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $params); $response = curl_exec($ch); curl_close($ch); echo $response; However, I'm getting an S3 error as follows when it posts and I'm unsure why because I'm not passing JSON to it. <?xml version="1.0" encoding="UTF-8"?> <Error><Code>InvalidPolicyDocument</Code><Message>Invalid Policy: Invalid JSON.</Message><RequestId>B29469C6151BE0E8</RequestId><HostId>BFPk6W2kt1b6hTtx0mEq6dWdN/IhO0gNR5bct//7LAOwJxm1C3PrxS4RPv1blzJ8</HostId></Error> I've googled it for the last hour or so and can't seem to figure it out. If I change the order of the Array fields, it gives me a different error - I believe the order of the posted fields is important somehow. any help would be much appreciated! C

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  • WebService Stubs WSDL Axis2

    - by tt0686
    Good afternoon in my timezone. I have a wsdl file with the following snippet of code: <schema targetNamespace="http://util.cgd.pt" xmlns="http://www.w3.org/2001/XMLSchema"> <import namespace="http://schemas.xmlsoap.org/soap/encoding/" /> <complexType name="Attribute"> <sequence> <element name="fieldType" nillable="true" type="xsd:string" /> <element name="dataType" nillable="true" type="xsd:string" /> <element name="name" nillable="true" type="xsd:string" /> <element name="value" nillable="true" type="xsd:string" /> </sequence> </complexType> <complexType name="ArrayOffAttribute"> <complexContent> <restriction base="soapenc:Array"> <attribute ref="soapenc:arrayType" wsdl:arrayType="tns3:Attribute[]" /> </restriction> </complexContent> </complexType> When i use jax-rpc or Axis1 to generate the stubs the type Attribute is generated, but when i use Axis2 the type Attribute is not generated and a new type is created ArrayOffAttribute, this new type extends the axis2.databinding.types.soapencoding.Array and permits to add elements through the array.addObject(object), my question is, i am migrating one Java EE application from webservices using jax-rpc to start using Axis2, and the methods are using the Attribute type to fullfill attributes fields, now in Axis2 and do not have attribute type , what should i use in the ArrayOffAttribute.addObject(?) ? Could be something wrong with Axis2 ? i am stop here :( Thanks in advance Best regards

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  • Malware - Technical anlaysis

    - by nullptr
    Note: Please do not mod down or close. Im not a stupid PC user asking to fix my pc problem. I am intrigued and am having a deep technical look at whats going on. I have come across a Windows XP machine that is sending unwanted p2p traffic. I have done a 'netstat -b' command and explorer.exe is sending out the traffic. When I kill this process the traffic stops and obviously Windows Explorer dies. Here is the header of the stream from the Wireshark dump (x.x.x.x) is the machines IP. GNUTELLA CONNECT/0.6 Listen-IP: x.x.x.x:8059 Remote-IP: 76.164.224.103 User-Agent: LimeWire/5.3.6 X-Requeries: false X-Ultrapeer: True X-Degree: 32 X-Query-Routing: 0.1 X-Ultrapeer-Query-Routing: 0.1 X-Max-TTL: 3 X-Dynamic-Querying: 0.1 X-Locale-Pref: en GGEP: 0.5 Bye-Packet: 0.1 GNUTELLA/0.6 200 OK Pong-Caching: 0.1 X-Ultrapeer-Needed: false Accept-Encoding: deflate X-Requeries: false X-Locale-Pref: en X-Guess: 0.1 X-Max-TTL: 3 Vendor-Message: 0.2 X-Ultrapeer-Query-Routing: 0.1 X-Query-Routing: 0.1 Listen-IP: 76.164.224.103:15649 X-Ext-Probes: 0.1 Remote-IP: x.x.x.x GGEP: 0.5 X-Dynamic-Querying: 0.1 X-Degree: 32 User-Agent: LimeWire/4.18.7 X-Ultrapeer: True X-Try-Ultrapeers: 121.54.32.36:3279,173.19.233.80:3714,65.182.97.15:5807,115.147.231.81:9751,72.134.30.181:15810,71.59.97.180:24295,74.76.84.250:25497,96.234.62.221:32344,69.44.246.38:42254,98.199.75.23:51230 GNUTELLA/0.6 200 OK So it seems that the malware has hooked into explorer.exe and hidden its self quite well as a Norton Scan doesn't pick anything up. I have looked in Windows firewall and it shouldn't be letting this traffic through. I have had a look into the messages explorer.exe is sending in Spy++ and the only related ones I can see are socket connections etc... My question is what can I do to look into this deeper? What does malware achieve by sending p2p traffic? I know to fix the problem the easiest way is to reinstall Windows but I want to get to the bottom of it first, just out of interest.

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  • xmlEncoder not writing in netBeans

    - by Greg
    Hi, I am trying to use the xmlEncoder to write to xml file in net-beans but it doesnt work. Here is the call to the writing function: dbManipulator.writeStudents(deps); where deps = new Hashtable<String, Department>(); dbManipulator = new DataBaseManipulator(); Department is an class-object I made, and here is writeStudents method which is located in the DataBaseManipulator class: public void writeStudents(Hashtable<Integer, Student> students) { XMLEncoder encoder = null; try { encoder = new XMLEncoder(new FileOutputStream(".\\test\\Students.xml")); } catch(Exception e){} encoder.writeObject(students); encoder.close(); }//end of function writeStudents() Any ideas why it isnt working? I tried changing the hashtable to vector but still the xml file looks like that after the writing: <?xml version="1.0" encoding="UTF-8"?> <java version="1.6.0_18" class="java.beans.XMLDecoder"> <object class="java.util.Hashtable"/> </java> Thanks in advance, Greg

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  • innerHTML doesn't work correctly with xhtml in Chrome

    - by Desperadeus
    Hi! I've got a trouble with Chrome5.0.375.70, but FF 3.6.3 and Opera 10.53 are OK. Below is the line of code: document.getElementById('content').innerHTML = data.documentElement.innerHTML; The data object from the code is a document (typeof(data) == 'object') and I've got it by ajax request to chapter01.xhtml: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE html [ <!ENTITY D "&#x2014;"> <!ENTITY o "&#x2018;"> <!ENTITY c "&#x2019;"> <!ENTITY O "&#x201C;"> <!ENTITY C "&#x201D;"> ]> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Alice's Adventures in Wonderland by Lewis Carroll. Chapter I: Down the Rabbit-Hole</title> <link rel="stylesheet" type="text/css" href="style.css"/> <link rel="stylesheet" type="application/vnd.adobe-page-template+xml" href="page-template.xpgt"/> </head> <body> <div class="title_box"> <h2 class="chapnum">Chapter I</h2> <h2 class="chaptitle">Down the Rabbit-Hole</h2> <hr/> </div> The Chrome cuts all before body and as a result link to css in header is missed; user can't see formatted text and images. How can I fix it or bypass?

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  • XmlSerialize a custom collection with an Attribute

    - by roomaroo
    I've got a simple class that inherits from Collection and adds a couple of properties. I need to serialize this class to XML, but the XMLSerializer ignores my additional properties. I assume this is because of the special treatment that XMLSerializer gives ICollection and IEnumerable objects. What's the best way around this? Here's some sample code: using System.Collections.ObjectModel; using System.IO; using System.Xml.Serialization; namespace SerialiseCollection { class Program { static void Main(string[] args) { var c = new MyCollection(); c.Add("Hello"); c.Add("Goodbye"); var serializer = new XmlSerializer(typeof(MyCollection)); using (var writer = new StreamWriter("test.xml")) serializer.Serialize(writer, c); } } [XmlRoot("MyCollection")] public class MyCollection : Collection<string> { [XmlAttribute()] public string MyAttribute { get; set; } public MyCollection() { this.MyAttribute = "SerializeThis"; } } } This outputs the following XML (note MyAttribute is missing in the MyCollection element): <?xml version="1.0" encoding="utf-8"?> <MyCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> What I want is <MyCollection MyAttribute="SerializeThis" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> Any ideas? The simpler the better. Thanks.

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  • hint and textview with right gravity and a singleline

    - by codeScriber
    I've opened a bug but i was wondering if anyone encountered this issue and knows a workaround. If you define a text view with a hint inside it, give it right gravity (android:gravity="right") then if you define android:singleLine=true or android:maxLines="1" or android:scrollHorizonatally="true" you don't see the hint. removing the right gravity returns the hint to the left side, removing all the tree params i mentioned above puts the hint on the right side. i want my hint on the right, but i need a single horizontal line... here's the sample layout that doesn't show the hint: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content" android:padding="5dp"> <EditText android:layout_width="fill_parent" android:layout_gravity="center_vertical|right" android:layout_height="wrap_content" android:layout_margin="6dp" android:textSize="16sp" android:paddingRight="5dp" android:id="@+id/c" android:gravity="right" android:hint="hello!!!" android:scrollHorizontally="true" android:maxLines="1" android:singleLine="true"/> </LinearLayout> i checked on 1.6 and 2.1 emulators and it reproduces 100%, i'm prettysure it's a bug, i don't see the connection between single line and the hint.... what's more the hint got it's own layout in the TextView (mLayout and mHintLayout both exists, in onDraw if the text length is 0 mHintLayout if mHint is not null is used).

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  • accessing a value of a nested hash

    - by st
    Hello! I am new to perl and I have a problem that's very simple but I cannot find the answer when consulting my perl book. When printing the result of Dumper($request); I get the following result: $VAR1 = bless( { '_protocol' => 'HTTP/1.1', '_content' => '', '_uri' => bless( do{\(my $o = 'http://myawesomeserver.org:8081/counter/')}, 'URI::http' ), '_headers' => bless( { 'user-agent' => 'Mozilla/5.0 (X11; U; Linux i686; en; rv:1.9.0.4) Gecko/20080528 Epiphany/2.22 Firefox/3.0', 'connection' => 'keep-alive', 'cache-control' => 'max-age=0', 'keep-alive' => '300', 'accept' => 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'accept-language' => 'en-us,en;q=0.5', 'accept-encoding' => 'gzip,deflate', 'host' => 'localhost:8081', 'accept-charset' => 'ISO-8859-1,utf-8;q=0.7,*;q=0.7' }, 'HTTP::Headers' ), '_method' => 'GET', '_handle' => bless( \*Symbol::GEN0, 'FileHandle' ) }, 'HTTP::Server::Simple::Dispatched::Request' ); How can I access the values of '_method' ('GET') or of 'host' ('localhost:8081'). I know that's an easy question, but perl is somewhat cryptic at the beginning. Thank you, St.

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  • java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

    - by aelshereay
    I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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  • Deploy GWT Application to Google App Engine using NetBeans

    - by Yan Cheng CHEOK
    Hello, I try to deploy a GWT application, to Google App Engine using NetBeans. I had successful run GWT sample http://code.google.com/webtoolkit/doc/latest/tutorial/create.html using Personal GlassFish v3 Prelude Domain, by 1) Copy generated source code from StockWatcher to C:\Projects\StockWatcherNetbeans\src\java\com\google\ 2) Modify C:\Projects\StockWatcherNetbeans\nbproject\gwt.properties gwt.module=com.google.gwt.stockwatcher.StockWatcher 3) Select Personal GlassFish v3 Prelude Domain, and run. All works fine! Now, I try to select Google App Engine server, and run. However, I get the error "There is no appengine web project opened!" I check... There is file called C:\Projects\StockWatcherNetbeans\war\WEB-INF\appengine-web.xml with content <?xml version="1.0" encoding="UTF-8"?> <appengine-web-app xmlns="http://appengine.google.com/ns/1.0" xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:schemaLocation='http://kenai.com/projects/nbappengine/downloads/download/schema/appengine-web.xsd appengine-web.xsd'> <application>StockWatcherNetbeans</application> <version>1</version> </appengine-web-app> I am using NetBeans 6.7.1 GWT4NB (GWT Plugin for NetBeans) 2.6.12 Google App Engine plugin for NetBeans from http://kenai.com/downloads/nbappengine/1.0_NetBeans671/updates.xml Anything I had missed out? Even when I right click to the project, the Deploy to Google App Engine options is disabled. And yes, please do not ask me why not use Eclipse.

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  • How to parse this xml document?

    - by dfjhdfjhdf
    Get such a XML document with the help of ajax (var data = request.responseXML;), how do I parse the contacts?: <?xml version="1.0" encoding="UTF-8"?> <Alladresses xmlns="http://somedomain.org/doc/2007-08-02/"> <Owner> <ID>gut74hfowesdfj49fjsifhryh8e8rta3uyhw4</ID> <Name>Mr.Bin</Name> </Owner> <Contacts> <Person> <Name>Greg</Name> <Phone>3254566756</Phone> </Person> <Person> <Name>Smith</Name> <Phone>342446446</Phone> </Person> <Person> <Name>Yuliya</Name> <Phone>675445566867</Phone> </Person> </Contacts> </Alladresses>

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  • Reading text files line by line, with exact offset/position reporting

    - by Benjamin Podszun
    Hi. My simple requirement: Reading a huge ( a million) line test file (For this example assume it's a CSV of some sorts) and keeping a reference to the beginning of that line for faster lookup in the future (read a line, starting at X). I tried the naive and easy way first, using a StreamWriter and accessing the underlying BaseStream.Position. Unfortunately that doesn't work as I intended: Given a file containing the following Foo Bar Baz Bla Fasel and this very simple code using (var sr = new StreamReader(@"C:\Temp\LineTest.txt")) { string line; long pos = sr.BaseStream.Position; while ((line = sr.ReadLine()) != null) { Console.Write("{0:d3} ", pos); Console.WriteLine(line); pos = sr.BaseStream.Position; } } the output is: 000 Foo 025 Bar 025 Baz 025 Bla 025 Fasel I can imagine that the stream is trying to be helpful/efficient and probably reads in (big) chunks whenever new data is necessary. For me this is bad.. The question, finally: Any way to get the (byte, char) offset while reading a file line by line without using a basic Stream and messing with \r \n \r\n and string encoding etc. manually? Not a big deal, really, I just don't like to build things that might exist already..

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  • how to dispaly image in grid view reading imageUrl from xml using sax parser in android

    - by Pramod kuamr
    thanks for answer but i am able to read xml file from url but i need if in xml imageUrl is there so show in grid view ..this is my xml file and read URL <?xml version="1.0" encoding="UTF-8"?> <channels> <channel> <name>ndtv</name> <logo>http://a3.twimg.com/profile_images/670625317/aam-logo--twitter.png</logo> <description>this is a news Channel</description> <rssfeed>ndtv.com</rssfeed> </channel> <channel> <name>star news</name> <logo>http://a3.twimg.com/profile_images/740897825/AndroidCast-350_normal.png</logo> <description>this is a newsChannel</description> <rssfeed>starnews.com</rssfeed> </channel> </channels>

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  • UTF8 charset, diacritical elements, conversion problems - and Zend Framework form escaping

    - by imanc
    Hey, I am writing a webapp in ZF and am having serious issues with UTF8. It's using multi lingual content through Zend Form and it seems that ZF heavily escapes all of these characters and basically just won't show a field if there's diacritical elements 'é' and if I use the HTML entity equivalent e.g. é it gets escaped so that the user will see 'é'. Zend Form allows for having non escaped data, but trying to use this is confusing, and it seems it'd need to be used all over the place. So, I have been told that if the page and the text is in UTF8, no conversion to htmlentities is required. Is this true? And if the last question is true, then how do I convert the source text to UTF8? I am comfortable setting up apache so that it sends a default UTF8 charset heading, and also adding the charset meta tag to the html, but doing this I am still getting messed up encoding. I have also tried opening the translation csv file in TextWrangler on OSX as UTF8, but it has done nothing. Thanks! L

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  • JavaScript snippet to read and output XML file on page load?

    - by Banderdash
    Hey guys, hoping I might get some help. Have XML file here of a list of books each with unique id and numeral value for whether they are checked out or not. I need a JavaScript snippet that requests the XML file after the page loads and displays the content of the XML file. XML file looks like this: <?xml version="1.0" encoding="UTF-8" ?> <response> <library name="My Library"> <book id="1" checked-out="1"> <authors> <author>John Resig</author> </authors> <title>Pro JavaScript Techniques (Pro)</title> <isbn-10>1590597273</isbn-10> </book> <book id="2" checked-out="0"> <authors> <author>Erich Gamma</author> <author>Richard Helm</author> <author>Ralph Johnson</author> <author>John M. Vlissides</author> </authors> <title>Design Patterns: Elements of Reusable Object-Oriented Software</title> <isbn-10>0201633612</isbn-10> </book> ... </library> </response> Would LOVE any and all help!

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  • Python line file iteration and strange characters

    - by muckabout
    I have a huge gzipped text file which I need to read, line by line. I go with the following: for i, line in enumerate(codecs.getreader('utf-8')(gzip.open('file.gz'))): print i, line At some point late in the file, the python output diverges from the file. This is because lines are getting broken due to weird special characters that python thinks are newlines. When I open the file in 'vim', they are correct, but the suspect characters are formatted weirdly. Is there something I can do to fix this? I've tried other codecs including utf-16, latin-1. I've also tried with no codec. I looked at the file using 'od'. Sure enough, there are \n characters where they shouldn't be. But, the "wrong" ones are prepended by a weird character. I think there's some encoding here with some characters being 2-bytes, but the trailing byte being a \n if not viewed properly. If I replace: gzip.open('file.gz') With: os.popen('zcat file.gz') It works fine (and actually, quite faster). But, I'd like to know where I'm going wrong.

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  • Rails - CSV export: prompt for file download

    - by Pierre
    Hello, I want to give my users the ability to export a table to CSV. So in my controller, I've added on top of the file: respond_to :html, :js, :csv I'm also setting the headers if the requested format is csv: if params[:format] == 'csv' generate_csv_headers("negotiations-#{Time.now.strftime("%Y%m%d")}") end Code for generate_csv_headers(in application_controller) is: def generate_csv_headers(filename) headers.merge!({ 'Cache-Control' => 'must-revalidate, post-check=0, pre-check=0', 'Content-Type' => 'text/csv', 'Content-Disposition' => "attachment; filename=\"#{filename}\"", 'Content-Transfer-Encoding' => 'binary' }) end I've also created a view named index.csv.erb to generate my file: <%- headers = ["Id", "Name"] -%> <%= CSV.generate_line headers %> <%- @negotiations.each do |n| -%> <%- row = [ n.id, n.name ] -%> <%= CSV.generate_line row %> <%- end -%> I don't have any error, but it simply displays the content of the CSV file, while I'd expect a prompt from the browser to download the file. I've read a lot, but could not find anything that'd work. Do you have an idea? thanks, p.

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  • Data of the web services in a RSS

    - by vymz
    I only have the .wsdl and I want to put the data that the web services return in the RSS. And in a web page of SAP, I can only upload RSS, so I need put the information of the web services in the RSS For example, I put the information manually(name and total value) in the fields <title> and <descripcion>, these data are extracted from the web services. But sometimes I don´t know how much information brings the web service. Also, I know that RSS is not to store information such as web services. <?xml version="1.0" encoding="UTF-8" ?> <rss version="2.0"> <channel> <title>Test RSS</title> <link>http://solutions.com</link> <description>RSS</description> <item> <title>Luiz</title> <link>http://www.solutions.com/prueba1</link> <description>10</description> </item> <item> <title>Clodoaldo</title> <link>http://www.solutions.com/prueba2</link> <description>5</description> </item>

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  • Is the order of params important in NHibernate?

    - by Blake Blackwell
    If I have an int parameter followed by a string parameter in a sproc I get the following error: Input string was not in the correct format However, if I switch those parameters in the sproc than I get the result set I expect. Are params sorted by data type, or do I have to do anything special in my config file? I've included my code for reference: Config File <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="NHibernateDemo" namespace="NHibernateDemo.Domain"> <class name="Blake_Test" table="Blake_Test"> <id name="TestId" column="TESTID"></id> <property name="TestName" column="TESTNAME" /> <loader query-ref="GetBlakeTest"/> </class> <sql-query name="GetBlakeTest" callable="true"> <return class="Blake_Test" /> call procedure AREA51.NHIBERNATE_TEST.GetBlakeTest(:int_TestId, :vch_TestName) </sql-query> </hibernate-mapping> Sproc Code: PROCEDURE GetBlakeTest ( ret_cursor OUT SYS_REFCURSOR, int_testid integer, vch_testname varchar2 ) AS BEGIN OPEN ret_cursor FOR SELECT TestId, TestName FROM blake_test WHERE testid = int_testid ORDER BY TestName DESC; END GetBlakeTest; END NHIBERNATE_TEST; Executing Code: IQuery query1 = session.GetNamedQuery( "GetBlakeTest" ); query1.SetParameter( "int_TestId", 1 ); query1.SetParameter( "vch_TestName", "TEST" ); IList<Blake_Test> mystuff = query1.List<Blake_Test>();

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  • XSLT: need to replace document('')

    - by Daziplqa
    I've the following xslt file: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!-- USDomesticCountryList - USE UPPERCASE LETTERS ONLY --> <xsl:variable name="USDomesticCountryList"> <entry name="US"/> <entry name="UK"/> <entry name="EG"/> </xsl:variable> <!--// USDomesticCountryList --> <xsl:template name="IsUSDomesticCountry"> <xsl:param name="countryParam"/> <xsl:variable name="country" select="normalize-space($countryParam)"/> <xsl:value-of select="normalize-space(document('')//xsl:variable[@name='USDomesticCountryList']/entry[@name=$country]/@name)"/> </xsl:template> </xsl:stylesheet> I need to replace the "document('')" xpath function, what should I use instead? I've tried to remove it completely but the xsl document doesn't work for me! I need to to so because the problem is : I am using some XSLT document that uses the above file, say document a. So I have document a that includes the above file (document b). I am using doc a from java code, I am do Caching for doc a as a javax.xml.transform.Templates object to prevent multiple reads to the xsl file on every transformation request. I found that, the doc b is re-calling itself from the harddisk, I believe this is because of the document('') function above, so I wanna replace/remove it. Thanks.

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  • Reduce unwanted noise

    - by Rajeev
    In the below code sometimes when microphone is not connected some noise is generated and the system just keeps on buzzing the same sound.Whats wrong with the code below and how to reduce the unwanted noise. Should i set myMic.setLoopBack(false) in the below code <?xml version="1.0" encoding="utf-8"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" width="300" height="100" creationComplete="init()"> <mx:Script> <![CDATA[ import mx.controls.Alert; import flash.net.NetStream; private var myMic:Microphone; private var recordingState:String = "idle"; private function init():void { myMic = Microphone.getMicrophone(); myMic.setSilenceLevel(0); myMic.rate = 44; myMic.gain = 100; myMic.setUseEchoSuppression(true); micLevel.visible = true; //Security.showSettings(SecurityPanel.MICROPHONE); myMic.setLoopBack(true); if (myMic != null) { myMic.setUseEchoSuppression(true); micLevel.setProgress(myMic.activityLevel, 100); addEventListener(Event.ENTER_FRAME, showMicLevel); //micLevel.setProgress(myMic.activityLevel, 100); } } private function showMicLevel(event:Event):void{ switch (recordingState){ case "idle" : micLevel.setProgress(myMic.activityLevel, 100); break; } } ]]> </mx:Script> <mx:ProgressBar x="0" y="36" mode="manual" id="micLevel" label="" labelPlacement="bottom" width="100" fontSize="10" fontWeight="normal"/> </mx:Application>

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  • JSON Twitter List in C#.net

    - by James
    Hi, My code is below. I am not able to extract the 'name' and 'query' lists from the JSON via a DataContracted Class (below) I have spent a long time trying to work this one out, and could really do with some help... My Json string: {"as_of":1266853488,"trends":{"2010-02-22 15:44:48":[{"name":"#nowplaying","query":"#nowplaying"},{"name":"#musicmonday","query":"#musicmonday"},{"name":"#WeGoTogetherLike","query":"#WeGoTogetherLike"},{"name":"#imcurious","query":"#imcurious"},{"name":"#mm","query":"#mm"},{"name":"#HumanoidCityTour","query":"#HumanoidCityTour"},{"name":"#awesomeindianthings","query":"#awesomeindianthings"},{"name":"#officeformac","query":"#officeformac"},{"name":"Justin Bieber","query":"\"Justin Bieber\""},{"name":"National Margarita","query":"\"National Margarita\""}]}} My code: WebClient wc = new WebClient(); wc.Credentials = new NetworkCredential(this.Auth.UserName, this.Auth.Password); string res = wc.DownloadString(new Uri(link)); //the download string gives me the above JSON string - no problems Trends trends = new Trends(); Trends obj = Deserialise<Trends>(res); private T Deserialise<T>(string json) { T obj = Activator.CreateInstance<T>(); using (MemoryStream ms = new MemoryStream(Encoding.Unicode.GetBytes(json))) { DataContractJsonSerializer serialiser = new DataContractJsonSerializer(obj.GetType()); obj = (T)serialiser.ReadObject(ms); ms.Close(); return obj; } } [DataContract] public class Trends { [DataMember(Name = "as_of")] public string AsOf { get; set; } //The As_OF value is returned - But how do I get the //multidimensional array of Names and Queries from the JSON here? }

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  • populate textboxs with xml node attributes

    - by Doug
    I have Data.xml: <?xml version="1.0" encoding="utf-8" ?> <data> <album> <slide title="Autum Leaves" description="Leaves from the fall of 1986" source="images/Autumn Leaves.jpg" thumbnail="images/Autumn Leaves_thumb.jpg" /> <slide title="Creek" description="Creek in Alaska" source="images/Creek.jpg" thumbnail="images/Creek_thumb.jpg" /> </album> </data> I'd like to be able to edit the attributes of each Slide node via GridView (that has a "Select" column added.) And so far I have: protected void GridView1_SelectedIndexChanged(object sender, EventArgs e) { int selectedIndex = GridView1.SelectedIndex; LoadXmlData(selectedIndex); } private void LoadXmlData(int selectedIndex) { XmlDocument xmldoc = new XmlDocument(); xmldoc.Load(MapPath(@"..\photo_gallery\Data.xml")); XmlNodeList nodelist = xmldoc.DocumentElement.ChildNodes; XmlNode xmlnode = nodelist.Item(selectedIndex); titleTextBox.Text = xmlnode.Attributes["title"].InnerText; descriptionTextBox.Text = xmlnode.Attributes["description"].InnerText; sourceTextBox.Text = xmlnode.Attributes["source"].InnerText; thumbTextBox.Text = xmlnode.Attributes["thumbnail"].InnerText; The code for LoadXmlData is just a guess on my part - I'm new to working with xml in this way. I'd like have the user to slected the row from the gridview, then populate a set of text boxes with each slide attributed for updating back to the Data.xml file. The error I'm getting is "Object reference not set to an instance of an object" at the line: titleTextBox.Text = xmlnode.Attributes["@title"].InnerText; - so I'm not reaching the attribute "title" of the slide node. Thanks for any ideas you may have.

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  • smartGWT: retrieve data from server to populate a listGrid

    - by Gabriele
    I'm searching a way to populate a ListGrid with an XML response from a server. This is an example of my server response: <?xml version="1.0" encoding="UTF-8"?> <tbody id="tbody"> <tr> <word>The</word> <frequence>12</frequence> </tr> <tr> <word>best</word> <frequence>3</frequence> </tr> ... And this is how I can populate the ListGrid using a file (item.xml) where I have saved the xml result: public class Frequenze extends DataSource { private static Frequenze instance = null; public static Frequenze getInstance() { if (instance == null) { instance = new Frequenze("frequence"); } return instance; } public Frequenze(String id) { setID(id); setRecordXPath("//tr"); DataSourceTextField wordField = new DataSourceTextField("word", "Word"); wordField.setRequired(true); DataSourceIntegerField frequenceField = new DataSourceIntegerField("frequence", "Frequence"); frequenceField.setRequired(true); setFields(wordField, frequenceField); setDataURL("ds/item.xml"); setClientOnly(true); } } Now I want not to use the file, but I'm searching a way to retrieve the data directly from the server. Anyone know how I get this?

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